332354 + Interview Questions in Secondary School in Math

1.	If y = 1 is a zero of the polynomial q(y) =4y³+ky²-y-1 then find the value of k.
Answer» ANSWER: Given, 4y³+ky²-y-1 -1 is zero Of polynomial so, 4(-1)³+k(-1)²-(-1)-1=0 4(-1)+k+1-1=0 -4+k=0 k=4 Step-by-step EXPLANATION: PLEASE mark me as BRAINLIEST

1.

If y = 1 is a zero of the polynomial q(y) =4y³+ky²-y-1 then find the value of k.

Answer»

ANSWER:

Given,

4y³+ky²-y-1

-1 is zero Of polynomial

so,

4(-1)³+k(-1)²-(-1)-1=0

4(-1)+k+1-1=0

-4+k=0

k=4

Step-by-step EXPLANATION:

PLEASE mark me as BRAINLIEST

Discussion

2.	Find the HCF of 500 and 360
Answer» Answer: 20 Step-by-step explanation: 500=5×5×5×2×2 360=3×3×2×2×2×5 so,HCF=5×2×2=20

2.

Find the HCF of 500 and 360

Answer»

Answer:

20

Step-by-step explanation:

500=5×5×5×2×2

360=3×3×2×2×2×5

so,HCF=5×2×2=20

Discussion

3.	Factorisation+श्री ए क्यू प्लस 4 माइनस 3
Answer» ANSWER: YH QUESTION PLZZ no. m LIKHO....

3.

Factorisation+श्री ए क्यू प्लस 4 माइनस 3

Answer»

ANSWER:

YH QUESTION PLZZ no. m LIKHO....

Discussion

4.	Given a number x = 2^48-1 then between 5 and 10, x hasguys pls help I have exam in a few hours ,I need to know this don't spam !!!! answer with steps or dint answer
Answer» ANSWER: let N = 248−1 . N is odd. So check all odd numbers between 5 and 10 i.e., 5,7,9. Here a%b represents modulus operation i.e., value of remainder when a divided by b (a/b). 1) For 5 : 21=2,22=4,23=8,24=16, 25=32,26=64,27=128,28=256... and so on. If power%4 = 0, unit digit will be 6.(eg. for 28 unit digit is 256) So for 248 number unit digit = 6, and 248−1 number unit digit = 5. So N is divisible by 5. 2) For 7 : 7 is factor, iff N%7=0 . N=248−1≡0 (MOD 7) 248≡1 (mod 7) If 248%7=1 then 7 is a factor of N. See fast exponentiation modulo algorithm for finding (ab)%m . express 48 in binary = 110000 0 → 21%7=2 0 → 22%7=2∗2%7=4 0 → 24%7=4∗4%7=2 0 → 28%7=2∗2%7=4 1 → 216%7=4∗4%7=2 1 → 232%7=2∗2%7=4 MULTIPLY all 1 terms (that are bold above) 248%7=2∗4%7=1 So 7 is a factor. 3) For 9 : (explanation is same as above) 0 → 21%9=2 0 → 22%9=2∗2%9=4 0 → 24%9=4∗4%9=7 0 → 28%9=7∗7%9=4 1 → 216%9=4∗4%9=7 1 → 232%9=7∗7%9=4 Multiply all 1 terms (that are bold above) 248%9=7∗4%9=1 So 9 is a factor. So 5,7,9 are factors of N. Edit 1: for checking 5 as factor, you can also use same method as shown above for 7. If 248%5=1 then 5 is factor of N. 0 → 21%5=2 0 → 22%5=2∗2%5=4 0 → 24%5=4∗4%5=1 0 → 28%5=1∗1%5=1 1 → 216%5=1∗1%5=1 1 → 232%5=1∗1%5=1 Multiply all 1 terms (that are bold above) 248%5=1∗1%5=1 So 5 is a factor.

4.

Given a number x = 2^48-1 then between 5 and 10, x hasguys pls help I have exam in a few hours ,I need to know this don't spam !!!! answer with steps or dint answer

Answer»

ANSWER:

let N = 248−1 .

N is odd. So check all odd numbers between 5 and 10 i.e., 5,7,9.

Here a%b represents modulus operation i.e., value of remainder when a divided by b (a/b).

1) For 5 :

21=2,22=4,23=8,24=16,

25=32,26=64,27=128,28=256... and so on.

If power%4 = 0, unit digit will be 6.(eg. for 28 unit digit is 256)

So for 248 number unit digit = 6, and 248−1 number unit digit = 5.

So N is divisible by 5.

2) For 7 :

7 is factor, iff N%7=0 .

N=248−1≡0 (MOD 7)

248≡1 (mod 7)

If 248%7=1 then 7 is a factor of N.

See fast exponentiation modulo algorithm for finding (ab)%m .

express 48 in binary = 110000

0 → 21%7=2

0 → 22%7=2∗2%7=4

0 → 24%7=4∗4%7=2

0 → 28%7=2∗2%7=4

1 → 216%7=4∗4%7=2

1 → 232%7=2∗2%7=4

MULTIPLY all 1 terms (that are bold above)

248%7=2∗4%7=1

So 7 is a factor.

3) For 9 :

(explanation is same as above)

0 → 21%9=2

0 → 22%9=2∗2%9=4

0 → 24%9=4∗4%9=7

0 → 28%9=7∗7%9=4

1 → 216%9=4∗4%9=7

1 → 232%9=7∗7%9=4

Multiply all 1 terms (that are bold above)

248%9=7∗4%9=1

So 9 is a factor.

So 5,7,9 are factors of N.

Edit 1:

for checking 5 as factor, you can also use same method as shown above for 7.

If 248%5=1 then 5 is factor of N.

0 → 21%5=2

0 → 22%5=2∗2%5=4

0 → 24%5=4∗4%5=1

0 → 28%5=1∗1%5=1

1 → 216%5=1∗1%5=1

1 → 232%5=1∗1%5=1

Multiply all 1 terms (that are bold above)

248%5=1∗1%5=1

So 5 is a factor.

Discussion

5.	Find the value of Cos^2 24 - Cos^2 6
Answer» Step-by-step EXPLANATION: Cos^2 24 - Cos^2 6 = Cos^2 24 + Sin^2 24 = 1

5.

Find the value of Cos^2 24 - Cos^2 6

Answer»

Step-by-step EXPLANATION:

Cos^2 24 - Cos^2 6

= Cos^2 24 + Sin^2 24

= 1

Discussion

6.	In given figures find the value of x
Answer» ANSWER: X = 42° 3x-8 = 118° x+20 = 62°

6.

In given figures find the value of x

Answer»

ANSWER:

X = 42°

3x-8 = 118°

x+20 = 62°

Discussion

7.	(1x2x3 x 4)+1=5,(2x3 x4 x 5) + 1 = 11,(3x4 x5 x 6) +1 = 19etc., then the value of(50 x 51 x 52 x 53) + 1 =
Answer» Answer: In the given question, (1×2×3×4)+1=5 ⇒You will observe that the multiplication of the given terms is 24 and when you ADD 1 it becomes 25 which is the SQUARE of 5. Also,when you add only the multiplication PART i.e (1+2+3+4)=5 which is given in RHS. Same happens with the rest of the equations, i.e (2×3×4×5)+1=11 In which the multiplication part gives the result 120 and after adding 1 it becomes 121 which is the square of 11 given in RHS. And,(2+3+4+5)=11 from which you will get the RHS part. So, by seeing above equations and their relations we can CONCLUDE that, ⇒(50×51×52×53)+1=(50+51+52+53)=206. Hope It helps you.

7.

(1x2x3 x 4)+1=5,(2x3 x4 x 5) + 1 = 11,(3x4 x5 x 6) +1 = 19etc., then the value of(50 x 51 x 52 x 53) + 1 =

Answer»

Answer:

In the given question,

(1×2×3×4)+1=5

⇒You will observe that the multiplication of the given terms is 24 and when you ADD 1 it becomes 25 which is the SQUARE of 5.

Also,when you add only the multiplication PART i.e (1+2+3+4)=5 which is given in RHS.

Same happens with the rest of the equations,

i.e (2×3×4×5)+1=11

In which the multiplication part gives the result 120 and after adding 1 it becomes 121 which is the square of 11 given in RHS.

And,(2+3+4+5)=11 from which you will get the RHS part.

So, by seeing above equations and their relations we can CONCLUDE that,

⇒(50×51×52×53)+1=(50+51+52+53)=206.

Hope It helps you.

Discussion

8.	We can write 016 as 0.161616... true or false
Answer» Answer: no it is false hope it HELPS you plz FOLLOW me plz mark as brainliest

8.

We can write 016 as 0.161616... true or false

Answer»

Answer:

no it is false

hope it HELPS you

plz FOLLOW me

plz mark as brainliest

Discussion

9.	If A=[1 0 02 1 0 the reduce it to I3 3 3 1] by using columntransformations.
Answer» ANSWER: i m not U derstand you QUESTION

9.

If A=[1 0 02 1 0 the reduce it to I3 3 3 1] by using columntransformations.

Answer»

ANSWER:

i m not U derstand you QUESTION

Discussion

10.	Le in the figure, ABC is an isosceles right-angledtriangle and PQRS is a rectangle3 cm3 cm3 cm3 cm
Answer» ANSWER: Where is the FIGURE???

10.

Le in the figure, ABC is an isosceles right-angledtriangle and PQRS is a rectangle3 cm3 cm3 cm3 cm

Answer»

ANSWER:

Where is the FIGURE???

Discussion

11.	The highest degree of polynomial of 2x^2+3x^4+9x+2
Answer» 4 PLS MARK as BRAINLIEST ANSWER

Discussion

12.	(1)(2) à- ас(3)If a, B and y are the zeros of the polynomialf(x) = ax3 - bx2 + cx - d, then a2 +d, then a2 + B2 + y2b2(1)62 + Zac(2)622ac(4)attakenaz262 - Zac(3)2a
Answer» ANSWER: TELL CLEARLY my FRIEND.....

12.

(1)(2) à- ас(3)If a, B and y are the zeros of the polynomialf(x) = ax3 - bx2 + cx - d, then a2 +d, then a2 + B2 + y2b2(1)62 + Zac(2)622ac(4)attakenaz262 - Zac(3)2a

Answer»

ANSWER:

TELL CLEARLY my FRIEND.....

Discussion

13.	A ABC લઘુકોણ ત્રિકોણ છે અને AM વેધ છે. સાબિત કરોકે, AC^2 = AB^2 + BC^2—2 ×BC × BM
Answer» Answer: I can't understand your question please write the question CAPITAL and upload again for BETTER EXPLANATION have a nice day BYE

13.

A ABC લઘુકોણ ત્રિકોણ છે અને AM વેધ છે. સાબિત કરોકે, AC^2 = AB^2 + BC^2—2 ×BC × BM

Answer»

Answer:

I can't understand your question please write the question CAPITAL and upload again for BETTER EXPLANATION have a nice day BYE

Discussion

14.	Write down the decimal expansion of the rational number of above which haveterminating decimal expansion. (i) 19/250 (ii) 23/2048 (iv)35/800 (vi) 52/2^3×5^4
Answer» ANSWER: Step-by-step explanation: 19/250 = 0.076 = TERMINATING and NON REPEATING 23/2048 = 0.011.... non terminating and repeating 35/800 = 0.04375 = terminating and non repeating 52/2^3 * 5^4 = 52/8*625 = 52/5000 = 0.0104 = terminating and non repeating

14.

Write down the decimal expansion of the rational number of above which haveterminating decimal expansion. (i) 19/250 (ii) 23/2048 (iv)35/800 (vi) 52/2^3×5^4

Answer»

ANSWER:

Step-by-step explanation:

19/250 = 0.076 = TERMINATING and NON REPEATING

23/2048 = 0.011.... non terminating and repeating

35/800 = 0.04375 = terminating and non repeating

52/2^3 * 5^4 = 52/8*625 = 52/5000 = 0.0104 = terminating and non repeating

Discussion

15.	Prove log the base b b=1
Answer» ANSWER: log B b=1 →b^1 = b (Anything raised to the EXPONENT 1 is equal to itself) Hence, Proved.

15.

Prove log the base b b=1

Answer»

ANSWER:

log B b=1

→b^1 = b

(Anything raised to the EXPONENT 1 is equal to itself)

Hence, Proved.

Discussion

16.	Please help me with this as early as possible
Answer» ANSWER: a SQUARE MINUS a B + b square

16.

Please help me with this as early as possible

Answer»

ANSWER:

a SQUARE MINUS a B + b square

Discussion

17.	Please answer this question correctly please
Answer» so the ANSWER is 2 hope it HELPS! PLS MARK as BRAINLIEST!!!

17.

Please answer this question correctly please

Answer»

so the ANSWER is 2

hope it HELPS!

PLS MARK as BRAINLIEST!!!

Discussion

18.	9. A number which when divided by 35 gives thequotient 26 and remainder 17 is
Answer» ANSWER: Step-by-step explanation: a=bq+r =35×26+17 =927 927 is the required number Don't FORGET to MARK me as BRAINLIEST

18.

9. A number which when divided by 35 gives thequotient 26 and remainder 17 is

Answer»

ANSWER:

Step-by-step explanation:

a=bq+r

=35×26+17

=927

927 is the required number

Don't FORGET to MARK me as BRAINLIEST

Discussion

19.	Find the difference between given number 4501 and 3720
Answer» Answer: the DIFFERENCE between the given NUMBERS for 4501 and 3720 is 880

19.

Find the difference between given number 4501 and 3720

Answer»

Answer:

the DIFFERENCE between the given NUMBERS for 4501 and 3720 is 880

Discussion

20.	Mathematical logic plz explain in case of statement, state it's truth value. 1.close the door2.zero is a complex number
Answer» Step-by-step EXPLANATION: OK COOL THANKS for your

20.

Mathematical logic plz explain in case of statement, state it's truth value. 1.close the door2.zero is a complex number

Answer»

Step-by-step EXPLANATION:

OK COOL THANKS for your

Discussion

21.	Is x-1+2 a polynomial?
Answer» Answer: yes, it this is a X ia a power of WHOLE NUMBER, fraction or not root. Step-by-step explanation: I hope it is HELP full to you and plz mark me in BRAINLY.

21.

Is x-1+2 a polynomial?

Answer»

Answer:

yes, it this is a X ia a power of WHOLE NUMBER, fraction or not root.

Step-by-step explanation:

I hope it is HELP full to you and plz mark me in BRAINLY.

Discussion

22.	Find the compound interest on ®5000 at 4% per annum for 3 years compounded annually .Answer is 624.32
Answer» ANSWER: SORRY GUY i am WEAK in MATHS

22.

Find the compound interest on ®5000 at 4% per annum for 3 years compounded annually .Answer is 624.32

Answer»

ANSWER:

SORRY GUY i am WEAK in MATHS

Discussion

23.	What will be the number of zeros of a linear polynomial px if it's graph cuts the x-axis at 5 points and touches it at 3 places.
Answer» ANSWER: The answer is 0 Step-by-step EXPLANATION: Because it MEETS at a POINT (5,3)

23.

What will be the number of zeros of a linear polynomial px if it's graph cuts the x-axis at 5 points and touches it at 3 places.

Answer»

ANSWER:

The answer is 0

Step-by-step EXPLANATION:

Because it MEETS at a POINT (5,3)

Discussion

24.	B) What must be added to the polynomial (99 x3 - 33 x2 -13 x -41) toget (-4x3 - 13 x2 + 5 x + 8)
Answer» Answer: DIVIDE 1st POLYNOMIAL by 2ND Step-by-step EXPLANATION: hope it helps

24.

B) What must be added to the polynomial (99 x3 - 33 x2 -13 x -41) toget (-4x3 - 13 x2 + 5 x + 8)

Answer»

Answer:

DIVIDE 1st POLYNOMIAL by 2ND

Step-by-step EXPLANATION:

hope it helps

Discussion

25.	I am sharinga few questionswhich you might like to us
Answer» ANSWER: what is your question PLZ TELL then I will SURELY answer thankyou

25.

I am sharinga few questionswhich you might like to us

Answer»

ANSWER:

what is your question PLZ TELL then I will SURELY answer

thankyou

Discussion

26.	If the solutions of the equation x² + 3x – 18 = 0 are –6, 3, then the roots of the equation 2(x² + 3x – 18) = 0 are __________.
Answer» ANSWER: -6 and 3 are the ROOTS. Step-by-step EXPLANATION: $Hope it helps you...Please mark this answer as the brainliest and follow me.$

26.

If the solutions of the equation x² + 3x – 18 = 0 are –6, 3, then the roots of the equation 2(x² + 3x – 18) = 0 are __________.

Answer»

ANSWER:

-6 and 3 are the ROOTS.

Step-by-step EXPLANATION:

$Hope it helps you...Please mark this answer as the brainliest and follow me.$

Discussion

27.	Integrate with respect to x : (a)1/(9-8x-x^2) (b)1/(3x^2-9)
Answer» Answer (a) 1/10{log\|(X + 9)/(1 - x)\|} + C (B) 1/6√3{log\|(x - √3)/(x + √3)\| + C Solution $\sf (a) \: \dfrac{1}{9 - 8x - {x}^{2} }$ $\sf \underline{Integrating \: with \: respect \: to \: \bf{x} }$ $\sf \longrightarrow \int\dfrac{dx}{9 - 8x - {x}^{2} } \\ \\ \sf \longrightarrow \int \dfrac{dx}{25 - 16 - 8x - {x}^{2} } \\ \\ \sf \longrightarrow \int \dfrac{dx}{25 - (x {}^{2} + 4 {}^{2} + 2 \times 4 \times x )} \\ \\ \sf \longrightarrow \int \dfrac{dx}{5 {}^{2} - (x + 4) {}^{2} }$ Now let US CONSIDER $\sf x + 4 = t \\ \\ \sf Differentiating \: with \: respect \: to \: x \\ \\ \implies \sf \dfrac{d}{dx} (x + 4) = \frac{dt}{dx} \\ \\ \sf\implies 1 = \frac{dt}{dx} \\ \\ \sf\implies dx = dt$ THUS , the required integration becomes : $\sf \longrightarrow \int \dfrac{dt}{5^{2} - t^{2}} \\\\ \sf\longrightarrow \dfrac{1}{2\times 5 } \log \| \dfrac{t + 5}{t - 5 } \\\\ \sf\longrightarrow \dfrac{1}{10} \log\|\dfrac{ 5+x + 4 }{5 - ( x + 4) } \| + C \\\\ \sf\longrightarrow \dfrac{1}{10} \log \| \dfrac{x+9}{1-x}\| + C$ ___________________ $\sf (b) \dfrac{1}{3x^{2} - 9}$ $\sf \underline{Integrating \: we \: have : }$ $\sf\longrightarrow \int \dfrac{1}{3x^{2} - 9 } \\\\ \sf\longrightarrow \int \dfrac{1}{3(x^{2} - 3)} \\\\$ $\sf \longrightarrow \dfrac{1}{3} \int \dfrac{dx}{x^{2} - (\sqrt{3})^{2}} \\\\$ $\sf\longrightarrow \dfrac{1}{6\sqrt{3}} \log \|\dfrac{x-\sqrt{3}}{x+\sqrt{3}} \| + C$ $\bf \large\underline{Formula \: used }$ ✪ $\sf \int \dfrac{dx}{x^{2} - a^{2} } = \dfrac{1}{2a}\log \|\dfrac{x-a}{x + a} \| + C$ ✪ $\sf \int \dfrac{dx}{a^{2} - x^{2} } = \dfrac{1}{2a} \log\|\dfrac{a + x}{a - x} \| + C$

27.

Integrate with respect to x : (a)1/(9-8x-x^2) (b)1/(3x^2-9)

Answer»

Answer

(a) 1/10{log|(X + 9)/(1 - x)|} + C

(B) 1/6√3{log|(x - √3)/(x + √3)| + C

Solution

$\sf (a) \: \dfrac{1}{9 - 8x - {x}^{2} }$

$\sf \underline{Integrating \: with \: respect \: to \: \bf{x} }$

$\sf \longrightarrow \int\dfrac{dx}{9 - 8x - {x}^{2} } \\ \\ \sf \longrightarrow \int \dfrac{dx}{25 - 16 - 8x - {x}^{2} } \\ \\ \sf \longrightarrow \int \dfrac{dx}{25 - (x {}^{2} + 4 {}^{2} + 2 \times 4 \times x )} \\ \\ \sf \longrightarrow \int \dfrac{dx}{5 {}^{2} - (x + 4) {}^{2} }$

Now let US CONSIDER

$\sf x + 4 = t \\ \\ \sf Differentiating \: with \: respect \: to \: x \\ \\ \implies \sf \dfrac{d}{dx} (x + 4) = \frac{dt}{dx} \\ \\ \sf\implies 1 = \frac{dt}{dx} \\ \\ \sf\implies dx = dt$

THUS , the required integration becomes :

$\sf \longrightarrow \int \dfrac{dt}{5^{2} - t^{2}} \\\\ \sf\longrightarrow \dfrac{1}{2\times 5 } \log | \dfrac{t + 5}{t - 5 } \\\\ \sf\longrightarrow \dfrac{1}{10} \log|\dfrac{ 5+x + 4 }{5 - ( x + 4) } | + C \\\\ \sf\longrightarrow \dfrac{1}{10} \log | \dfrac{x+9}{1-x}| + C$

___________________

$\sf (b) \dfrac{1}{3x^{2} - 9}$

$\sf \underline{Integrating \: we \: have : }$

$\sf\longrightarrow \int \dfrac{1}{3x^{2} - 9 } \\\\ \sf\longrightarrow \int \dfrac{1}{3(x^{2} - 3)} \\\\$

$\sf \longrightarrow \dfrac{1}{3} \int \dfrac{dx}{x^{2} - (\sqrt{3})^{2}} \\\\$

$\sf\longrightarrow \dfrac{1}{6\sqrt{3}} \log |\dfrac{x-\sqrt{3}}{x+\sqrt{3}} | + C$

$\bf \large\underline{Formula \: used }$

✪ $\sf \int \dfrac{dx}{x^{2} - a^{2} } = \dfrac{1}{2a}\log |\dfrac{x-a}{x + a} | + C$

✪ $\sf \int \dfrac{dx}{a^{2} - x^{2} } = \dfrac{1}{2a} \log|\dfrac{a + x}{a - x} | + C$

Discussion

28.	Q.15If the length of the transverse tangent is 8 cm, thencalculate the centre distance (in cm) of the twocircles with radii 7 cm and 3 cm.(A) 1100(B) V120(C) W164 (D) V180
Answer» ANSWER: D) V180 is answer of QUESTION DEAR

28.

Q.15If the length of the transverse tangent is 8 cm, thencalculate the centre distance (in cm) of the twocircles with radii 7 cm and 3 cm.(A) 1100(B) V120(C) W164 (D) V180

Answer»

ANSWER:

D) V180 is answer of QUESTION DEAR

Discussion

29.	(-2/3) to the power of -4 * (-3/5) to the power of 2
Answer» Answer: 1.8225 Step-by-step EXPLANATION: => 81/16 X 9/25 => 729/400 => 1.8225 Hope this HELPS.....

29.

(-2/3) to the power of -4 * (-3/5) to the power of 2

Answer»

Answer:

1.8225

Step-by-step EXPLANATION:

=> 81/16 X 9/25

=> 729/400

=> 1.8225

Hope this HELPS.....

Discussion

30.	Show 3,425 by drawing pictures of place value blocks and notes/coins.
Answer» ANSWER: idk idk Step-by-step EXPLANATION: MESSAGE me on DISCORD and I will SEND you the answer

30.

Show 3,425 by drawing pictures of place value blocks and notes/coins.

Answer»

ANSWER:

idk

Step-by-step EXPLANATION:

MESSAGE me on DISCORD and I will SEND you the answer

Discussion

31.	Sin (45° + θ) – cos (45° – θ) is equal to2 cos θ02 sin θ1
Answer» QUESTION : Find the VALUE of: sin(45° + θ) – cos (45°-θ) Formula's USED : $\sf1)\sin(a+b)=\sin\:a\cos\:b+\sin\:b\cos\:a$ $\sf2)\sin(a-b)=\sin\:a\cos\:b-\sin\:b\cos\:a$ $\sf3)\cos(a+b)=\cos\:a\cos\:b-\sin\:b\sin\:a$ $\sf4)\cos(a-b)=\cos\:a\cos\:b+\sin\:b\sin\:a$ Solution : We have , sin(45° + θ) – cos (45°-θ) USE formula of sin(a+b) and cos(a-b) ,then sin(45° + θ) – cos (45°-θ) =sin45°cosθ+sinθcos45°-(cosθcos45°-sinθsin45°) =sin45°cosθ+sinθcos45°-cosθcos45°+sinθsin45° We know that cos45°=sin45° =sin45°cosθ+sinθcos45°-cosθsin45°+sinθcos45° =0 Therefore,sin(45° + θ) – cos (45°-θ)=0 Another WAY to solve : We know that sin(90-x)=cosx and cos(90-x)=sinx Then, sin(45° + θ) – cos (45°-θ) =sin(45° + θ) – sin[90-(45°-θ)] =sin(45° + θ) – sin(45°+θ) =0

31.

Sin (45° + θ) – cos (45° – θ) is equal to2 cos θ02 sin θ1

Answer»

QUESTION :

Find the VALUE of:

sin(45° + θ) – cos (45°-θ)

Formula's USED :

$\sf1)\sin(a+b)=\sin\:a\cos\:b+\sin\:b\cos\:a$

$\sf2)\sin(a-b)=\sin\:a\cos\:b-\sin\:b\cos\:a$

$\sf3)\cos(a+b)=\cos\:a\cos\:b-\sin\:b\sin\:a$

$\sf4)\cos(a-b)=\cos\:a\cos\:b+\sin\:b\sin\:a$

Solution :

We have ,

sin(45° + θ) – cos (45°-θ)

USE formula of sin(a+b) and cos(a-b) ,then

sin(45° + θ) – cos (45°-θ)

=sin45°cosθ+sinθcos45°-(cosθcos45°-sinθsin45°)

=sin45°cosθ+sinθcos45°-cosθcos45°+sinθsin45°

We know that cos45°=sin45°

=sin45°cosθ+sinθcos45°-cosθsin45°+sinθcos45°

=0

Therefore,sin(45° + θ) – cos (45°-θ)=0

Another WAY to solve :

We know that sin(90-x)=cosx and cos(90-x)=sinx

Then,

sin(45° + θ) – cos (45°-θ)

=sin(45° + θ) – sin[90-(45°-θ)]

=sin(45° + θ) – sin(45°+θ)

=0

Discussion

32.	Find the square of 3 - 2 under root5
Answer» Step-by-step EXPLANATION: Prove that 3 + 2 root 5 whole SQUARE is irrational. Answer: To Prove : (3 + 2√5)² is irrational No. (3 + 2√5)² = 3² + (2√5)² + 2×3×2√5. = 29 + 12√5. we USE the result that √5 is an irrational no. we know that PRODUCT of rational and irrational no is and irrational no. ⇒ 12 × √5 = 12√5 is an irrational no.

32.

Find the square of 3 - 2 under root5

Answer»

Step-by-step EXPLANATION: Prove that 3 + 2 root 5 whole SQUARE is irrational. Answer: To Prove : (3 + 2√5)² is irrational No. (3 + 2√5)² = 3² + (2√5)² + 2×3×2√5. = 29 + 12√5. we USE the result that √5 is an irrational no. we know that PRODUCT of rational and irrational no is and irrational no. ⇒ 12 × √5 = 12√5 is an irrational no.

Discussion

33.	If (2x-(1/x) = 2 then (8 x^3 - (1/x^3))= ?*
Answer» ANSWER: gwiw6wyhwgwbwh2i2i2828. w929292. 28ei2b3

33.

If (2x-(1/x) = 2 then (8 x^3 - (1/x^3))= ?*

Answer»

ANSWER:

gwiw6wyhwgwbwh2i2i2828. w929292. 28ei2b3

Discussion

34.	15.2 marksHow many multiples of 5 lie between 31and 151?Subjective
Answer» There are 60 MULTIPLES of 5 LYING between 31 & 151. Hope it HELPS you!

34.

15.2 marksHow many multiples of 5 lie between 31and 151?Subjective

Answer»

There are 60 MULTIPLES of 5 LYING between 31 & 151.

Hope it HELPS you!

Discussion

35.	plz answer this question it's very urgent....plz give me the correct answer plz... I will mark it as brain list answer plz plz plz
Answer» ANSWER: HOPE it will HELP you. if you like it then PLS MARK me as brainliest.

35.

plz answer this question it's very urgent....plz give me the correct answer plz... I will mark it as brain list answer plz plz plz

Answer»

ANSWER:

HOPE it will HELP you.

if you like it then PLS MARK me as brainliest.

Discussion

36.	the value of y for which the expression (y - 15) and (2 y + 1) became equal is . whose so ever will answer I will mark him brainliest these questions is from simpal equations .
Answer» ANSWER: CORRECT answer is 4 OK bye and follow me

36.

the value of y for which the expression (y - 15) and (2 y + 1) became equal is . whose so ever will answer I will mark him brainliest these questions is from simpal equations .

Answer»

ANSWER:

CORRECT answer is 4 OK bye and follow me

Discussion

37.	Which two theorem would you use to find PQ?
Answer» Answer: PQ is 90 degree and I don't have IDEA about THEOREM

37.

Which two theorem would you use to find PQ?

Answer»

Answer:

PQ is 90 degree and I don't have IDEA about THEOREM

Discussion

38.	solved the following simultaneously equation
Answer» Answer: 12682828865949646646

38.

solved the following simultaneously equation

Answer»

Answer:

12682828865949646646

Discussion

39.	2/5 × (-3/7) - 1/6 × 3/2 + 1/14 × 2/5
Answer» ANSWER: is the answer Step-by-step EXPLANATION: -11÷28? it is your answer. am a RIGHT

39.

2/5 × (-3/7) - 1/6 × 3/2 + 1/14 × 2/5

Answer»

ANSWER:

is the answer

Step-by-step EXPLANATION:

-11÷28? it is your answer.

am a RIGHT

Discussion

40.	Solve the following questions on the number line 3/2 , 5/2 , -3/2
Answer» Step-by-step explanation: convert into mixed fraction plot on NUMBER LINE as shown

40.

Solve the following questions on the number line 3/2 , 5/2 , -3/2

Answer»

Step-by-step explanation:

convert into mixed fraction

plot on NUMBER LINE as shown

Discussion

41.	If Sin^2 28°+sin^2B= 1 then B=?plz answer
Answer» ANSWER : here your answer Step-by-step EXPLANATION: hope it HELPS you thank you so much for seeing my answer

41.

If Sin^2 28°+sin^2B= 1 then B=?plz answer

Answer»

ANSWER :

here your answer

Step-by-step EXPLANATION:

hope it HELPS you

thank you so much

for seeing my answer

Discussion

42.	Show that 5-root3 is irrational
Answer» ANSWER:WRITE in p/q FORM

Discussion

43.	मूल bindu ka bhuj kya hota hai
Answer» Step-by-step EXPLANATION: (0,0) I hope this is HELPFUL for you if you like this *answer* then FOLLOW me

43.

मूल bindu ka bhuj kya hota hai

Answer»

Step-by-step EXPLANATION:

(0,0)

I hope this is HELPFUL for you if you like this answer then FOLLOW me

Discussion

44.	Find the positive value of K for which the equation x^2+10 kx+16=0 has no real roots.
Answer» Step-by-step EXPLANATION: PLEASE MARK has BRAINLIEST ANSWER (❁´◡`❁)(♥_♥)(❁´◡`❁)(♥_♥)

44.

Find the positive value of K for which the equation x^2+10 kx+16=0 has no real roots.

Answer»

Step-by-step EXPLANATION:

PLEASE MARK has BRAINLIEST ANSWER (❁´◡`❁)(♥_♥)(❁´◡`❁)(♥_♥)

Discussion

45.	2. There are some girls in twoclass-rooms A and B. If 12 girls aresent from room A to room B, thenumber of girls in both the roomswill become equal. If 11 girls are sentfrom room B to room A. The numberof girls in Room A will became doubleRoom B. How many girls are there ineach class-room?ha
Answer» Answer: Step-by-step EXPLANATION: Let the no. of girls in class room A be x Let the no. of girls in classroom B be y 1st condition: If 12 girls are sent from classroom A to B then the equation will be Now the no. girls in class A is = x-12 and the no. of girls in class B is = y+12(SINCE class B will gain 12 more girls) Given that if 12 girls are sent from A to B then the no. of girls will become equal: x-12=y+12 x-y=12+12 x-y=24 ----- (equation 1) In 2nd condition it's given that if 11 girls are sent from class B to A then class A will be double of class B Total no. of girls in class B=y If 11 girls are REMOVED = y-11 Total no. of girls in class A=x Hence class A will gain 11 girls = x+11 x+11=2(y-11) x+11=2y-22 x-2y=-11-22 x-2y=-33 -----(equation 2) By subtract equation 2 from equation 1 we get x-y= 24 x-2y=-33 -__+__+______(symbols get changed) y=57 __________ By SUBSTITUTING y value to equation 1, we get: x-y = 24 x-57=24 x = 24+57 x = 81 Therefore, class A CONTAINS 81 girls and class B contains 57 girls

45.

2. There are some girls in twoclass-rooms A and B. If 12 girls aresent from room A to room B, thenumber of girls in both the roomswill become equal. If 11 girls are sentfrom room B to room A. The numberof girls in Room A will became doubleRoom B. How many girls are there ineach class-room?ha

Answer»

Answer:

Step-by-step EXPLANATION:

Let the no. of girls in class room A be x

Let the no. of girls in classroom B be y

1st condition: If 12 girls are sent from classroom A to B then the equation will be

Now the no. girls in class A is = x-12

and the no. of girls in class B is = y+12(SINCE class B will gain 12 more girls)

Given that if 12 girls are sent from A to B then the no. of girls will become equal:

x-12=y+12

x-y=12+12

x-y=24 ----- (equation 1)

In 2nd condition it's given that if 11 girls are sent from class B to A then class A will be double of class B

Total no. of girls in class B=y

If 11 girls are REMOVED = y-11

Total no. of girls in class A=x

Hence class A will gain 11 girls = x+11

x+11=2(y-11)

x+11=2y-22

x-2y=-11-22

x-2y=-33 -----(equation 2)

By subtract equation 2 from equation 1 we get

x-y= 24

x-2y=-33

-__+__+______(symbols get changed)

y=57

__________

By SUBSTITUTING y value to equation 1, we get:

x-y = 24

x-57=24

x = 24+57

x = 81

Therefore, class A CONTAINS 81 girls and class B contains 57 girls

Discussion

46.	Diagnol of a cube When a=2
Answer» ANSWER: HEY MATE 8 is your answer

46.

Diagnol of a cube When a=2

Answer»

ANSWER:

HEY MATE 8 is your answer

Discussion

47.	What is the additive inverse of the following--1. -7÷122. 21÷122right answerer will get follow back and brainliest. wrong answerer will get reported.
Answer» Answer: 1.7/12 2.-21/122 are the ADDITIVE INVERSES

47.

What is the additive inverse of the following--1. -7÷122. 21÷122right answerer will get follow back and brainliest. wrong answerer will get reported.

Answer»

Answer:

1.7/12

2.-21/122 are the ADDITIVE INVERSES

Discussion

48.	(4/2x²)(1/3y²zx)(-6xyz²)
Answer» I don't UNDERSTAND CLEARLY this QUESTION. . . ? . ? , fggggghhhyhhhhhh .

48.

(4/2x²)(1/3y²zx)(-6xyz²)

Answer»

I don't UNDERSTAND CLEARLY this QUESTION. . . ? . ? , fggggghhhyhhhhhh .

Discussion

49.	If 4^a=14^b=8^c=7^d then the value of ab/cd is
Answer» Step-by-step explanation: a+b=10—(1) b+c=20—(2) c+a=24—(3) (1)+(2)+(3)=>2(a+b+c)=10+20+24=54 =>a+b+c=27—(4) (4)−(1)=>c=27–10=17 (4)−(2)=>a=27–20=7 (4)−(3)=>b=27–24=3 ANS: a=7, b = 3, c = 17

49.

If 4^a=14^b=8^c=7^d then the value of ab/cd is

Answer»

Step-by-step explanation:

a+b=10—(1)

b+c=20—(2)

c+a=24—(3)

(1)+(2)+(3)=>2(a+b+c)=10+20+24=54

=>a+b+c=27—(4)

(4)−(1)=>c=27–10=17

(4)−(2)=>a=27–20=7

(4)−(3)=>b=27–24=3

ANS: a=7, b = 3, c = 17

Discussion

50.	If E and F are the midpoints of equal sides AB and AC of a triangle ABC. Then
Answer» ANSWER: Then TRIANGLE ABC is ISOSCELES triangle Then , AE=EB AF=FC

50.

If E and F are the midpoints of equal sides AB and AC of a triangle ABC. Then

Answer»

ANSWER:

Then TRIANGLE ABC is ISOSCELES triangle

Then ,

AE=EB

AF=FC

Discussion

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