332354 + Interview Questions in Secondary School in Math

1.	is 9, 720 a perfect cube? if not, find the smallest number by which it should be divided to get a perfeet cube.
Answer» ∴ 9720 is not a perfect CUBE. ∴ 45 is the smallest number by which 9720 should be DIVIDED to get a perfect cube. If the question was meant to FIND the WHOLE number by which it should be divided to get a perfect cube, the answer will be 45.

Discussion

2.	Find the range of the following data 21, 16, 30, 15, 16, 10
Answer» ANSWER: $range \: is \: the \: difference \: of \: higesr \: and \: lowest \: value$ $30 - 10 = 20$

2.

Find the range of the following data 21, 16, 30, 15, 16, 10

Answer»

ANSWER:

$range \: is \: the \: difference \: of \: higesr \: and \: lowest \: value$

$30 - 10 = 20$

Discussion

3.	Find the greatest number that will divide 80,118 and 60 leaving remainders 8, 10 and 12 respectively
Answer» Step-by-step EXPLANATION: PUT your MIND do it your own SHARP your mind

3.

Find the greatest number that will divide 80,118 and 60 leaving remainders 8, 10 and 12 respectively

Answer»

Step-by-step EXPLANATION:

PUT your MIND do it your own SHARP your mind

Discussion

4.	Solve the linear equation: 2{x+(2x-3)}=5(x+10)
Answer» Step-by-step explanation: 2(X+(2x-3))=5(x+10) 2(x+2x-3)=5x+50 2x+4x-6=5x+50 6x-6=5x+50 6x-5x=50+6 x=56 Hope this HELPS!

4.

Solve the linear equation: 2{x+(2x-3)}=5(x+10)

Answer»

Step-by-step explanation:

2(X+(2x-3))=5(x+10)

2(x+2x-3)=5x+50

2x+4x-6=5x+50

6x-6=5x+50

6x-5x=50+6

x=56

Hope this HELPS!

Discussion

5.	55 labourers are needed to build a bridge in 300 days. After working for 30 days, 5 labourers left the company. (i) Given that all the labourers work at the same rate, how many days will the remaining labourers take to build the bridge? (ii) Find the percentage increase in the number of days, from 300 days, to build the bridge.
Answer» Step-by-step EXPLANATION: ghar a COUPLE WEEKS and then I can not GET back from her but the ATTACHED is your responsibility and

5.

55 labourers are needed to build a bridge in 300 days. After working for 30 days, 5 labourers left the company. (i) Given that all the labourers work at the same rate, how many days will the remaining labourers take to build the bridge? (ii) Find the percentage increase in the number of days, from 300 days, to build the bridge.

Answer»

Step-by-step EXPLANATION:

ghar a COUPLE WEEKS and then I can not GET back from her but the ATTACHED is your responsibility and

Discussion

6.	5,4,10,27,?,555 complete the series
Answer» 112 Explanation : 5 * 1 – 1 = 4 4 * 2 + 2 = 10 10 * 3 – 3 = 27 27 * 4 + 4 = 112…..

6.

5,4,10,27,?,555 complete the series

Answer»

112

Explanation :

5 * 1 – 1 = 4

4 * 2 + 2 = 10

10 * 3 – 3 = 27

27 * 4 + 4 = 112…..

Discussion

7.	Maths please solve extra q4
Answer» Answer: 25(2+3)³1/5 25(5)³*1/5 25x125x1/5 5x125 solve this U GET URS answer

7.

Maths please solve extra q4

Answer»

Answer:

25(2+3)³1/5

25(5)³*1/5

25x125x1/5

5x125 solve this U GET URS answer

Discussion

8.	The distance of an object at the speed of 36km /hr in 10 min
Answer» ANSWER: DISTANCE=speed÷time 36÷10 3.6 KM is the distance

8.

The distance of an object at the speed of 36km /hr in 10 min

Answer»

ANSWER:

DISTANCE=speed÷time

36÷10

3.6 KM is the distance

Discussion

9.	If k is represented as know then H would be represented as A)house B)hut C)hunger D)hour
Answer» H would be represented as hour. 1) As it is given in the question the k REPRESENTS KNOW. It is a word of 4 alphabets. 2) So according to the condition of the FIRST word,h also represents a word of 4 alphabets only. in the given options A) HOUSE => 5 alphabets B) hut => 3 alphabets C) hunger => 6 alphabets D) hour => 4 alphabets Option (d) is the correct ANSWER.

9.

If k is represented as know then H would be represented as A)house B)hut C)hunger D)hour

Answer»

H would be represented as hour.

1) As it is given in the question the k REPRESENTS KNOW. It is a word of 4 alphabets.

2) So according to the condition of the FIRST word,h also represents a word of 4 alphabets only.

in the given options

A) HOUSE => 5 alphabets

B) hut => 3 alphabets

C) hunger => 6 alphabets

D) hour => 4 alphabets

Option (d) is the correct ANSWER.

Discussion

10.	the diameter of a wheel is 70 cm how many times the wheel will revolve in order to cover the distance of 110
Answer» Step-by-step EXPLANATION: circumference of the wheel =πD 22/7*70=220cm if DISTANCE is 110mt distance COVERED will be 1100/220 5CM

10.

the diameter of a wheel is 70 cm how many times the wheel will revolve in order to cover the distance of 110

Answer»

Step-by-step EXPLANATION:

circumference of the wheel =πD

22/7*70=220cm

if DISTANCE is 110mt

distance COVERED will be 1100/220

5CM

Discussion

11.	Please answer this it will be very nice of you
Answer» 180 rupees Step-by-step EXPLANATION: Cost of 5½kg rice= 495 Cost of 1 kg rice= 495 × 2/11 [by UNITARY Method] Cost of 2 kg rice= 495 × 2/11 × 2 = 180 rupees

11.

Please answer this it will be very nice of you

Answer»

180 rupees

Step-by-step EXPLANATION:

Cost of 5½kg rice= 495

Cost of 1 kg rice= 495 × 2/11 [by UNITARY Method]

Cost of 2 kg rice= 495 × 2/11 × 2 = 180 rupees

Discussion

12.	If the circumference of a circle sheet is176 m find the area
Answer» ANSWER: Circumference=2πr 176=2×22/7×r R=176×7/22×2 R= 28m Area= πr^2 =22/7×28×28 = 2464 Step-by-step EXPLANATION: MARK as BRAINLIEST PLZZZZZZ

12.

If the circumference of a circle sheet is176 m find the area

Answer»

ANSWER:

Circumference=2πr

176=2×22/7×r

R=176×7/22×2

R= 28m

Area= πr^2

=22/7×28×28

= 2464

Step-by-step EXPLANATION:

MARK as BRAINLIEST PLZZZZZZ

Discussion

13.	when the elevation agle of sun increase from 45° to 60°then the length of the shadow of todew decrease by 3m.find the height of hte tower.8
Answer» ANSWER: $h1{text-transform:uppercase;margin-top:90px;text-align:center;font-family:Courier new,monospace;border:3px solid rgb(60,45,8);border-top:none;width:67%;letter-spacing:-6px;box-sizing:border-box;padding-right:5px;border-radius:6px;font-size:35px;font-weight:bold;}h1 span{position:relative;display:inline-block;margin-right:3px;}@keyframes shahir{0%{transform: translateY(0px) rotate(0deg);}40%{transform: translateY(0px) rotate(0deg);}50%{transform: translateY(-50px)rotate(180deg);;}60%{transform: translateY(0px)rotate(360deg);;}100%{transform: translate(0px)rotate(360deg);;}}h1 span{animation: shahir 3s alternate infinite linear;}h1 span:nth-child(1){color:red;animation-delay: 0s;}h1 span:nth-child(2){color:lightmaroon;animation-delay: 0.2s;}h1 span:nth-child(3){color:orange;animation-delay:0s;}h1 span:nth-child(4){color:pink;animation-delay: 0.4s;}h1 span:nth-child(5){color:lime;animation-delay: 0.5s;}h1 span:nth-child(6){color:purple;animation-delay: 0.3s;}h1 span:nth-child(7){color:blue;animation-delay: 0.1s;}h1 span:nth-child(8){color:red;animation-delay: 0s;}h1 span:nth-child(9){color:lightmaroon;animation-delay: 0.2s;}h1 span:nth-child(10){color:orange;animation-delay:0s;}h1 span:nth-child(11){color:pink;animation-delay: 0.4s;}h1 span:nth-child(12){color:lime;animation-delay: 0.5s;}h1 span:nth-child(13){color:purple;animation-delay: 0.3s;}h1 span:nth-child(14){color:blue;animation-delay: 0.4s;}h1 span:nth-child(15){color:yellow;animation-delay: 0.5s;} PRAKA SH$ ${}$ ${}$ $CUBE20Thanks+Follow =Inboxbody {padding-left: 30%;padding-top: 5%;}.container {width: 200px;height: 200px;position: relative;-webkit-perspective: 1000px;-moz-perspective: 1000px;}#cube {width: 100%;height: 100%;position: absolute;-webkit-transform-style: preserve-3d;-webkit-animation: rotatecube 10s infinite;-moz-transform-style: preserve-3d;-moz-animation: rotatecube 10s infinite;}#cube div {width: 200px;height: 200px;display: block;position: absolute;border: none;line-height: 200px;text-align: center;font-size: 50px;font-weight: bold;}@-webkit-keyframes rotatecube {0% { -webkit-transform: rotateX(0deg) rotateY(360deg) rotateZ(90deg); }25% { -webkit-transform: rotateX(90deg) rotateY(270deg) rotateZ(180deg); }50% { -webkit-transform: rotateX(180deg) rotateY(180deg) rotateZ(0deg); }75% { -webkit-transform: rotateX(270deg) rotateY(90deg) rotateZ(360deg); }100% { -webkit-transform: rotateX(360deg) rotateY(0deg) rotateZ(270deg); }}@-moz-keyframes rotatecube {0% { -moz-transform: rotateX(0deg) rotateY(360deg) rotateZ(90deg); }25% { -moz-transform: rotateX(90deg) rotateY(270deg) rotateZ(180deg); }50% { -moz-transform: rotateX(180deg) rotateY(180deg) rotateZ(0deg); }75% { -moz-transform: rotateX(270deg) rotateY(90deg) rotateZ(360deg); }100% { -moz-transform: rotateX(360deg) rotateY(0deg) rotateZ(270deg); }}.front {background: rgba(255,0,0,.5);}.back {background: rgba(0,255,0,.5);}.right {background: rgba(0,0,255,.5);}.left {background: rgba(0,255,255,.5);}.top {background: rgba(255,0,255,.5);}.bottom {background: rgba(255,255,0,.5);}#cube .front {-webkit-transform: rotateY(0deg ) translateZ( 100px );-moz-transform: rotateY( 0deg ) translateZ( 100px );}#cube .back {-webkit-transform: rotateX( 180deg ) translateZ( 100px );-moz-transform: rotateX( 180deg ) translateZ( 100px );}#cube .right {-webkit-transform: rotateY( 90deg ) translateZ( 100px );-moz-transform: rotateY( 90deg ) translateZ( 100px );}#cube .left {-webkit-transform: rotateY( -90deg ) translateZ( 100px );-moz-transform: rotateY( -90deg ) translateZ( 100px );}#cube .top {-webkit-transform: rotateX( 90deg ) translateZ( 100px );-moz-transform: rotateX( 90deg ) translateZ( 100px );}#cube .bottom {-webkit-transform: rotateX( -90deg ) translateZ( 100px );-moz-transform: rotateX( -90deg ) translateZ( 100px );}$

13.

when the elevation agle of sun increase from 45° to 60°then the length of the shadow of todew decrease by 3m.find the height of hte tower.8

Answer»

ANSWER:

$h1{text-transform:uppercase;margin-top:90px;text-align:center;font-family:Courier new,monospace;border:3px solid rgb(60,45,8);border-top:none;width:67%;letter-spacing:-6px;box-sizing:border-box;padding-right:5px;border-radius:6px;font-size:35px;font-weight:bold;}h1 span{position:relative;display:inline-block;margin-right:3px;}@keyframes shahir{0%{transform: translateY(0px) rotate(0deg);}40%{transform: translateY(0px) rotate(0deg);}50%{transform: translateY(-50px)rotate(180deg);;}60%{transform: translateY(0px)rotate(360deg);;}100%{transform: translate(0px)rotate(360deg);;}}h1 span{animation: shahir 3s alternate infinite linear;}h1 span:nth-child(1){color:red;animation-delay: 0s;}h1 span:nth-child(2){color:lightmaroon;animation-delay: 0.2s;}h1 span:nth-child(3){color:orange;animation-delay:0s;}h1 span:nth-child(4){color:pink;animation-delay: 0.4s;}h1 span:nth-child(5){color:lime;animation-delay: 0.5s;}h1 span:nth-child(6){color:purple;animation-delay: 0.3s;}h1 span:nth-child(7){color:blue;animation-delay: 0.1s;}h1 span:nth-child(8){color:red;animation-delay: 0s;}h1 span:nth-child(9){color:lightmaroon;animation-delay: 0.2s;}h1 span:nth-child(10){color:orange;animation-delay:0s;}h1 span:nth-child(11){color:pink;animation-delay: 0.4s;}h1 span:nth-child(12){color:lime;animation-delay: 0.5s;}h1 span:nth-child(13){color:purple;animation-delay: 0.3s;}h1 span:nth-child(14){color:blue;animation-delay: 0.4s;}h1 span:nth-child(15){color:yellow;animation-delay: 0.5s;} PRAKA SH$

${}$

$CUBE20Thanks+Follow =Inboxbody {padding-left: 30%;padding-top: 5%;}.container {width: 200px;height: 200px;position: relative;-webkit-perspective: 1000px;-moz-perspective: 1000px;}#cube {width: 100%;height: 100%;position: absolute;-webkit-transform-style: preserve-3d;-webkit-animation: rotatecube 10s infinite;-moz-transform-style: preserve-3d;-moz-animation: rotatecube 10s infinite;}#cube div {width: 200px;height: 200px;display: block;position: absolute;border: none;line-height: 200px;text-align: center;font-size: 50px;font-weight: bold;}@-webkit-keyframes rotatecube {0% { -webkit-transform: rotateX(0deg) rotateY(360deg) rotateZ(90deg); }25% { -webkit-transform: rotateX(90deg) rotateY(270deg) rotateZ(180deg); }50% { -webkit-transform: rotateX(180deg) rotateY(180deg) rotateZ(0deg); }75% { -webkit-transform: rotateX(270deg) rotateY(90deg) rotateZ(360deg); }100% { -webkit-transform: rotateX(360deg) rotateY(0deg) rotateZ(270deg); }}@-moz-keyframes rotatecube {0% { -moz-transform: rotateX(0deg) rotateY(360deg) rotateZ(90deg); }25% { -moz-transform: rotateX(90deg) rotateY(270deg) rotateZ(180deg); }50% { -moz-transform: rotateX(180deg) rotateY(180deg) rotateZ(0deg); }75% { -moz-transform: rotateX(270deg) rotateY(90deg) rotateZ(360deg); }100% { -moz-transform: rotateX(360deg) rotateY(0deg) rotateZ(270deg); }}.front {background: rgba(255,0,0,.5);}.back {background: rgba(0,255,0,.5);}.right {background: rgba(0,0,255,.5);}.left {background: rgba(0,255,255,.5);}.top {background: rgba(255,0,255,.5);}.bottom {background: rgba(255,255,0,.5);}#cube .front {-webkit-transform: rotateY(0deg ) translateZ( 100px );-moz-transform: rotateY( 0deg ) translateZ( 100px );}#cube .back {-webkit-transform: rotateX( 180deg ) translateZ( 100px );-moz-transform: rotateX( 180deg ) translateZ( 100px );}#cube .right {-webkit-transform: rotateY( 90deg ) translateZ( 100px );-moz-transform: rotateY( 90deg ) translateZ( 100px );}#cube .left {-webkit-transform: rotateY( -90deg ) translateZ( 100px );-moz-transform: rotateY( -90deg ) translateZ( 100px );}#cube .top {-webkit-transform: rotateX( 90deg ) translateZ( 100px );-moz-transform: rotateX( 90deg ) translateZ( 100px );}#cube .bottom {-webkit-transform: rotateX( -90deg ) translateZ( 100px );-moz-transform: rotateX( -90deg ) translateZ( 100px );}$

Discussion

14.	Please tell me how to do solve it !
Answer» Step-by-step EXPLANATION: gcg HH g. h fcufucuf if ufuf. if uguig your future g g Iggy F. Hf hfhf. UFC ucuf if ujgcjcg JG jg jg jv jv jv jvjv jbk jv k bkh kh k Bk Bk bkh kb kh jvbjb

14.

Please tell me how to do solve it !

Answer»

Step-by-step EXPLANATION:

gcg HH g. h fcufucuf if ufuf. if uguig your future g g Iggy F. Hf hfhf. UFC ucuf if ujgcjcg JG jg jg jv jv jv jvjv jbk jv k bkh kh k Bk Bk bkh kb kh jvbjb

Discussion

15.	P(x)=x⁴+2x³-3x²-x-1,q(x)=x-2
Answer» Answer: 5 Step-by-step explanation: zeroes of the polynomial is 2, p(2)= (2)4 + (2)(2)3 - (3)(2)2 - (2) - 1 = 8 + 12 - 12 - 2 - 1 = 8 - 3 = 5\\.. HOPE its helpfull... and plz mark me brainliest<3

15.

P(x)=x⁴+2x³-3x²-x-1,q(x)=x-2

Answer»

Answer:

5

Step-by-step explanation:

zeroes of the polynomial is 2,

p(2)= (2)4 + (2)(2)3 - (3)(2)2 - (2) - 1

= 8 + 12 - 12 - 2 - 1

= 8 - 3 = 5\\..

HOPE its helpfull... and plz mark me brainliest<3

Discussion

16.	The domain of R = {(0, 2), (2, 4), (3, 4), (4, 5)} is
Answer» ANSWER: then the range is 2,4,4,5 Step-by-step EXPLANATION: hope you will understand PLEASE mark my answers as a BRAINLIAST

16.

The domain of R = {(0, 2), (2, 4), (3, 4), (4, 5)} is

Answer»

ANSWER:

then the range is 2,4,4,5

Step-by-step EXPLANATION:

hope you will understand PLEASE mark my answers as a BRAINLIAST

Discussion

17.	28. a+b=64a is called(a) commutative law of additionb. Law of additionEs distributore Low of additionassociative(d) noneof these.
Answer» Answer: RUN to bank YES Ellis seem remind seem and CA to yes can see if she'll an l if and we hang in LISTEN he so can just run the music VIDEO, Step-by-step explanation: I *HOPE* it *will help you*

17.

28. a+b=64a is called(a) commutative law of additionb. Law of additionEs distributore Low of additionassociative(d) noneof these.

Answer»

Answer:

RUN to bank YES Ellis seem remind seem and CA to yes can see if she'll an l if and we hang in LISTEN he so can just run the music VIDEO,

Step-by-step explanation:

I HOPE it will help you

Discussion

18.	If ∆ABC , angle B =90° , angle C=60° , if AC=8 find AB
Answer» Answer: 90°kshsajshwyffhhhuyhyh bsgsjwke hshsheidjs hwjwid

18.

If ∆ABC , angle B =90° , angle C=60° , if AC=8 find AB

Answer»

Answer:

90°kshsajshwyffhhhuyhyh
bsgsjwke
hshsheidjs
hwjwid

Discussion

19.	Is this rightplzz tell
Answer» ANSWER: 4root81)-² 4root1/81x81 1/81 is the answer

19.

Is this rightplzz tell

Answer»

ANSWER:

4root81)-²

4root1/81x81

1/81 is the answer

Discussion

20.	The degree of the polynomial p(y) = y - 7 is:
Answer» ANSWER: The DEGREE of the POLYNOMIAL is 1 follow me (◠‿・)—☆

20.

The degree of the polynomial p(y) = y - 7 is:

Answer»

ANSWER:

The DEGREE of the POLYNOMIAL is 1

follow me (◠‿・)—☆

Discussion

21.	Derive coloumb's howhaw:from Gaussi
Answer» Step-by-step explanation: The force is proportional to the magnitude of these charges. Coulomb's law explains the electrostatic force at a given distance squared. It's stated as: Force = (k) X (e1) x (E2) / r^2. The real SOURCE of Coulomb's law is the CREATION of an electron 'charge' in accordance with E = M x C^2.

21.

Derive coloumb's howhaw:from Gaussi

Answer»

Step-by-step explanation:

The force is proportional to the magnitude of these charges. Coulomb's law explains the electrostatic force at a given distance squared. It's stated as: Force = (k) X (e1) x (E2) / r^2. The real SOURCE of Coulomb's law is the CREATION of an electron 'charge' in accordance with E = M x C^2.

Discussion

22.	Divide: 10x^2y^2-8xy^2+6x^2y^3 by 2xy
Answer» ANSWER: Anseee is 20^3y^8-7xy

22.

Divide: 10x^2y^2-8xy^2+6x^2y^3 by 2xy

Answer»

ANSWER:

Anseee is 20^3y^8-7xy

Discussion

23.	गुलाब जामुन की एक प्लेट ₹10 की है तो बताइए 10 गुलाब जामुन कितने रुपए के होंगे बताएं
Answer» ANSWER: LOL THANKS for the pits Step-by-step EXPLANATION:

23.

गुलाब जामुन की एक प्लेट ₹10 की है तो बताइए 10 गुलाब जामुन कितने रुपए के होंगे बताएं

Answer»

ANSWER:

LOL THANKS for the pits

Step-by-step EXPLANATION:

Discussion

24.	If three angles of a quadrilateral are equal and the fourth angle measures 300°,find the size of the equal angles
Answer» Answer: AS WE KNOW THAT THE SUM 9F THE ANGLES OF A QUADRILATERAL IS 360 DEGREE ☆LET THE FIRST ANGLE, SECOND ANGLE AND THE THIRD ANGLE BE X *degrees* *Fourth* *angle* =300 *degree* (*GIVEN) A/Q,we get* = x+x+x+300 = 360 3x +300 =360 3x = 60 x = 20 *degrees* al *the* *equal* *angles* =20 *degrees*

24.

If three angles of a quadrilateral are equal and the fourth angle measures 300°,find the size of the equal angles

Answer»

Answer:

AS WE KNOW THAT THE SUM 9F THE ANGLES OF A QUADRILATERAL IS 360 DEGREE

☆LET THE FIRST ANGLE, SECOND ANGLE AND THE THIRD ANGLE BE X degrees

Fourth angle =300 degree (GIVEN)

A/Q,we get = x+x+x+300 = 360

3x +300 =360

3x = 60

x = 20 degrees

al the equal angles =20 degrees

Discussion

25.	Find the range of f(x) = 3x}^{2}+ 1 when domain = {-3, 2, 4,0}.
Answer» Domain { x ∈ R } Range { y ∈ R } Explanation: This is just the EQUATION of a STRAIGHT line. The function is CONTINUOUS so the domain is: { x ∈ R } The minimum value is − ∞ The maximum value is ∞ So the range is: { y ∈ R }

25.

Find the range of f(x) = 3x}^{2}+ 1 when domain = {-3, 2, 4,0}.

Answer»

Domain

{

x

∈

R

}

Range

{

y

∈

R

}

Explanation:

This is just the EQUATION of a STRAIGHT line. The function is CONTINUOUS so the domain is:

{

x

∈

R

}

The minimum value is

−

∞

The maximum value is

∞

So the range is:

{

y

∈

R

}

Discussion

26.	(x-2)2 +1=2x-3 is this is quadratic equation or not and also what is the answer for this??
Answer» Answer: Yes, its a quadratic equation. Step-by-step EXPLANATION: (X - 2)² + 1 = 2x - 3 x² + 4 - 4x + 1 = 2x - 3 x² - 4x - 2x + 5 + 3 = 0 x² - 6x + 8 = 0 Hope it HELPS!! THANK you ✌️

26.

(x-2)2 +1=2x-3 is this is quadratic equation or not and also what is the answer for this??

Answer»

Answer:

Yes, its a quadratic equation.

Step-by-step EXPLANATION:

(X - 2)² + 1 = 2x - 3

x² + 4 - 4x + 1 = 2x - 3

x² - 4x - 2x + 5 + 3 = 0

x² - 6x + 8 = 0

Hope it HELPS!!

THANK you ✌️

Discussion

27.	1. Without performing the actual division, find the quotient when the sum of 17 and 71 is divideWithout performing any actual division, find the quotient when the difference of 25 andLet Us Practise 5.1.(0) 8(11(ů) 999obtained by reversing its digits is divided byEvaluate the quotient obtained by dividing the sum of the number 378 and thetwo other numbers obtained by rearranging the digits in cyclic order by(1) 111(iv) 37Find the quotient when the difference of 517 and 715 is divided by((a) 18(tut) 22Find the quotient when the difference of 268 and 862 is divided by(1) 27(11) 60(u) 3(iv) 11Alohabets by Digits
Answer» Answer: UR hands is not paining this much U TYPED

27.

1. Without performing the actual division, find the quotient when the sum of 17 and 71 is divideWithout performing any actual division, find the quotient when the difference of 25 andLet Us Practise 5.1.(0) 8(11(ů) 999obtained by reversing its digits is divided byEvaluate the quotient obtained by dividing the sum of the number 378 and thetwo other numbers obtained by rearranging the digits in cyclic order by(1) 111(iv) 37Find the quotient when the difference of 517 and 715 is divided by((a) 18(tut) 22Find the quotient when the difference of 268 and 862 is divided by(1) 27(11) 60(u) 3(iv) 11Alohabets by Digits

Answer»

Answer:

UR hands is not paining this much U TYPED

Discussion

28.	If (x+5) is the geometric mean between (x+2) and (x+9) then the value of x isThe 3rd proportional to 1.6 and 2.4 is
Answer» ANSWER: L can, t TELL because I am in CLASS 6TH

28.

If (x+5) is the geometric mean between (x+2) and (x+9) then the value of x isThe 3rd proportional to 1.6 and 2.4 is

Answer»

ANSWER:

L can, t TELL because I am in CLASS 6TH

Discussion

29.	consider the Arithametic Sequence 135,141,147,.... can the sum of any 25consecutive terms of the sequence be 2016?
Answer» ANSWER: (a) 6,10,14,.... SINCE t2−t1=t3−t2 Common DIFFERENCE, d=10−6=4 First TERM a=6 Sn=2n2a+(n−1)d=2n2×6+(n−1)4=2n12+4n−4=2n4n+8 =n(2n+4) 2n2+4n (b) For the SUM to be 240 from the beginning 240=n2+4n ⇒240=n(2n+4) ⇒240=n(2n+4) ⇒120=n(n+2) ⇒n2+2n−120=0 ⇒n2+

29.

consider the Arithametic Sequence 135,141,147,.... can the sum of any 25consecutive terms of the sequence be 2016?

Answer»

ANSWER:

(a) 6,10,14,....

SINCE t2−t1=t3−t2

Common DIFFERENCE, d=10−6=4

First TERM a=6

Sn=2n2a+(n−1)d=2n2×6+(n−1)4=2n12+4n−4=2n4n+8

=n(2n+4)

2n2+4n

(b) For the SUM to be 240 from the beginning

240=n2+4n

⇒240=n(2n+4)

⇒120=n(n+2)

⇒n2+2n−120=0

⇒n2+

Discussion

30.	5+√3/7-4√3 - 5-√3/7+4
Answer» ANSWER: $Koala body {display: flex; justify-content: center; padding-top: 150px;}.character {position: relative;}.character .head {height: 125px; width: 155px; background: #94e1fd; border-radius: 80px 89px 55px 55px; position: relative; border: 4px solid black; top: 6px;}.character .head:after {content:$

30.

5+√3/7-4√3 - 5-√3/7+4

Answer»

ANSWER:

$Koala body {display: flex; justify-content: center; padding-top: 150px;}.character {position: relative;}.character .head {height: 125px; width: 155px; background: #94e1fd; border-radius: 80px 89px 55px 55px; position: relative; border: 4px solid black; top: 6px;}.character .head:after {content:$

Discussion

31.	Why we are finding lcm to know when they met...????(can anyone please help me out)
Answer» When we have to FIND a NUMBER larger than given numbers, then we find LCM. If we have to find SMALLER number, then we find HCF .....

31.

Why we are finding lcm to know when they met...????(can anyone please help me out)

Answer»

When we have to FIND a NUMBER larger than given numbers, then we find LCM. If we have to find SMALLER number, then we find HCF .....

Discussion

32.	What is the opposite number of 2085
Answer» 5802 *mark* me as a *BRAINLIST*. . .

32.

What is the opposite number of 2085

Answer»

5802

mark me as a BRAINLIST. . .

Discussion

33.	At a car park 50% of the vehicles perped werecars 30% were motorcyles and the rest ofthe 40 vecheeles were vens:
Answer» (i) Calculate the NUMBER of motorcycles PARKED there. Ans) Let the number of total VEHICLES be "X" % of Vans = 100% - (% of cars + % of motorcycles) => 100% - ( 50% + 30%) => 100% - 80% = 20% 20% of total vehicles = 40 vans 20% of x = 40 $\dfrac{20}{100}$ of x = 40 x = 40 × $\dfrac{100}{20}$ x = 200 Therefore , the number of Motorcycles = 30% of 200 = $\dfrac{30 \times 20}{100}$ = 60 (ii)If 40 cars left the car park, what percentage of the vehicles parked there were cars? Ans) Number of cars = 50% of 200 = $\frac{50 \times 200}{100}$ = 100 cars % of cars = $\dfrac{\sf{number \: of \: cars \: remaining \times 100}}{\sf{numbers \: of \: vehicles \: remaning}}$ = $\dfrac{60 \times 100}{160}$ % = $\dfrac{75}{2}$ % = 37.5%

33.

At a car park 50% of the vehicles perped werecars 30% were motorcyles and the rest ofthe 40 vecheeles were vens:

Answer»

(i) Calculate the NUMBER of motorcycles PARKED there.

Ans) Let the number of total VEHICLES be "X"

% of Vans = 100% - (% of cars + % of motorcycles)

=> 100% - ( 50% + 30%)

=> 100% - 80%

= 20%

20% of total vehicles = 40 vans

20% of x = 40

$\dfrac{20}{100}$ of x = 40

x = 40 × $\dfrac{100}{20}$

x = 200

Therefore , the number of Motorcycles = 30% of 200

= $\dfrac{30 \times 20}{100}$

= 60

(ii)If 40 cars left the car park, what percentage of the vehicles parked there were cars?

Ans) Number of cars = 50% of 200

= $\frac{50 \times 200}{100}$

= 100 cars

% of cars = $\dfrac{\sf{number \: of \: cars \: remaining \times 100}}{\sf{numbers \: of \: vehicles \: remaning}}$

= $\dfrac{60 \times 100}{160}$ %

= $\dfrac{75}{2}$ %

= 37.5%

Discussion

34.	Differentiate 1÷under root x^2+x+1
Answer» ANSWER: MATE these is your answer

34.

Differentiate 1÷under root x^2+x+1

Answer»

ANSWER:

MATE these is your answer

Discussion

35.	Y=3x and x+2y=7 elimination method
Answer» ANSWER: x=1 Step-by-step EXPLANATION: PUTTING the VALUE of your in x+2y=7 we GET : x+2×3x=7 x+6x=7 7x=7 x=1

35.

Y=3x and x+2y=7 elimination method

Answer»

ANSWER:

x=1

Step-by-step EXPLANATION:

PUTTING the VALUE of your in x+2y=7 we GET :

x+2×3x=7

x+6x=7

7x=7

x=1

Discussion

36.	Find the factors of x^2 + 4x +3
Answer» ANSWER: X = -1 , X = -3 Step-by-step EXPLANATION: x²+4x+3 = 0 x²+x+3x+3 = 0 x(x+1) + 3(x+1) = 0 (x+1) (x+3) = 0 X = -1 , X = -3 Hope it helps!! Thank you ✌️

36.

Find the factors of x^2 + 4x +3

Answer»

ANSWER:

X = -1 , X = -3

Step-by-step EXPLANATION:

x²+4x+3 = 0

x²+x+3x+3 = 0

x(x+1) + 3(x+1) = 0

(x+1) (x+3) = 0

X = -1 , X = -3

Hope it helps!!

Thank you ✌️

Discussion

37.	2x+3y=1 and 3x-5y=8 elimination method
Answer» Answer: the VALUE of X is EQUAL to 29/19. and the value of Y is equal to -13/19. Step-by-step explanation: the answer is explained in the IMAGE.

37.

2x+3y=1 and 3x-5y=8 elimination method

Answer»

Answer:

the VALUE of X is EQUAL to 29/19.

and the value of Y is equal to -13/19.

Step-by-step explanation:

the answer is explained in the IMAGE.

Discussion

38.	Pls answer my question fastly pls
Answer» ANSWER: HEY MATE pic of ques is not clear please mrk my answer AD brainliest

38.

Pls answer my question fastly pls

Answer»

ANSWER:

HEY MATE

pic of ques is not clear

please mrk my answer AD brainliest

Discussion

39.	Plz answer me i will mark you as brainlist
Answer» Answer: 9 Step-by-step explanation: 16-[11+{8-(6-2)}] 16-[11+{8-4}] 16-[11+4] 16-15 1 please MARK as BRAINLIEST

39.

Plz answer me i will mark you as brainlist

Answer»

Answer:

9

Step-by-step explanation:

16-[11+{8-(6-2)}]

16-[11+{8-4}]

16-[11+4]

16-15

1

please MARK as BRAINLIEST

Discussion

40.	. The abbreviation used for length names of elements are termed as their8. A chemical formula is also known as a
Answer» ANSWER: CHEMICAL name chemical FORMULA is also known as chemical name

40.

. The abbreviation used for length names of elements are termed as their8. A chemical formula is also known as a

Answer»

ANSWER:

CHEMICAL name

chemical FORMULA is also known as chemical name

Discussion

41.	(21) Find the maximum and minimum values of the function f(x) = cos x + sin x.
Answer» Answer: jnu te amo te amo te amo te amo te amo team and the other hand I am boy and girl Love you all of the following numbers are best skills by Dil Laga de Bhai and the other hand the correct answer ytyttt to be in touch and let UU UPROOT and UUU and girl the correct address you all resources have been the most popular dog and a in a great weekend to India in yu uchit chilo na to dekh kar diya karo Ben 10 mod lana hai kya Chapter 4 mein Bata de Bhai और दूसरी ओर जो सही उत्तर है उसका सही उत्तर क्या है Step-by-step explanation: उदित नारायण v mein बाता देना है मुख्य uski maa to HUM jarur kare प्लीज uu uproot to be a

41.

(21) Find the maximum and minimum values of the function f(x) = cos x + sin x.

Answer»

Answer:

jnu te amo te amo te amo te amo te amo team and the other hand I am boy and girl Love you all of the following numbers are best skills by Dil Laga de Bhai and the other hand the correct answer ytyttt to be in touch and let UU UPROOT and UUU and girl the correct address you all resources have been the most popular dog and a in a great weekend to India in

yu uchit chilo na to dekh kar diya karo Ben 10 mod lana hai kya Chapter 4 mein Bata de Bhai और दूसरी ओर जो सही उत्तर है उसका सही उत्तर क्या है

Step-by-step explanation:

उदित नारायण v mein बाता देना है मुख्य uski maa to HUM jarur kare प्लीज uu uproot to be a

Discussion

42.	A number consists of two digits whose sum is 9.If 27 is substracted from the number, its digits are reversed. Find the number.
Answer» Answer: 63 Step-by-step EXPLANATION: PLEASE MARK me as BRAINLIEST

42.

A number consists of two digits whose sum is 9.If 27 is substracted from the number, its digits are reversed. Find the number.

Answer»

Answer:

63

Step-by-step EXPLANATION:

PLEASE MARK me as BRAINLIEST

Discussion

43.	ABCD is a square of side 12 cm and E is a point in the interior of ABCD. If ∠EDC = ∠ECD = 15°, then find the perimeter of ΔAEB.
Answer» Answer: PERIMETER of TRIANGLE AEB is 25.68 cm for more details SEE above pic

43.

ABCD is a square of side 12 cm and E is a point in the interior of ABCD. If ∠EDC = ∠ECD = 15°, then find the perimeter of ΔAEB.

Answer»

Answer:

PERIMETER of TRIANGLE AEB is 25.68 cm

for more details SEE above pic

Discussion

44.	Answer with solution.
Answer» Answer: 47 degree Step-by-step EXPLANATION: PLZ MAKE me BRAINLIST

44.

Answer with solution.

Answer»

Answer:

47 degree

Step-by-step EXPLANATION:

PLZ MAKE me BRAINLIST

Discussion

45.	No irrelevant answerotherwise reprted
Answer» ANSWER: $- 1 \div {x}^{2}$ Step-by-step EXPLANATION: SEE above PICTURE

45.

No irrelevant answerotherwise reprted

Answer»

ANSWER:

$- 1 \div {x}^{2}$

Step-by-step EXPLANATION:

SEE above PICTURE

Discussion

46.	Sin x-2CosxSinºx-2sinx.cosx
Answer» 12344488474777333737

Discussion

47.	_343/512 please take answer
Answer» ANSWER: OK I had written it mark me brain LIST Thanks..... Step-by-step explanation: STAY home stay SAFE

47.

_343/512 please take answer

Answer»

ANSWER:

OK I had written it

mark me brain LIST

Thanks.....

Step-by-step explanation:

STAY home

stay SAFE

Discussion

48.	(11111)^2का मान क्या होगा
Answer» Answer: 123454321 HOPE IT HELPS PLS MARK IT AS BRAINLIEST AND DO FOLLOW ME

48.

(11111)^2का मान क्या होगा

Answer»

Answer:

123454321

HOPE IT HELPS

PLS MARK IT AS BRAINLIEST

AND DO FOLLOW ME

Discussion

49.	Make a quadratice equalan 3,-7
Answer» Answer: Step-by-step explanation: Make a quadratic EQUATION with roots 3,-7 Method 1 Quadratic equation = (x-3)(x+7)= x²+4x-21 Method 2 Sum of roots = 3-7 = -4 = (coefficient of x/coefficient of x²) Product of roots = 3(-7) = -21 = (coefficient of CONSTANT term/coefficient of x²) Assume coefficient of x² = 1 Quadratic equation = x²+4x-21

49.

Make a quadratice equalan 3,-7

Answer»

Answer:

Step-by-step explanation:

Make a quadratic EQUATION with roots 3,-7

Method 1

Quadratic equation = (x-3)(x+7)= x²+4x-21

Method 2

Sum of roots = 3-7 = -4 = (coefficient of x/coefficient of x²)

Product of roots = 3(-7) = -21 = (coefficient of CONSTANT term/coefficient of x²)

Assume coefficient of x² = 1

Quadratic equation = x²+4x-21

Discussion

50.	Find CI on Rs 12600 for 2 years at 10% per annum compounded annually.
Answer» $\Huge\sf\red{\underline{\underline{Given}}} \::\\$ $\begin{cases}\sf\gray{Principal = 12600} \\ \sf\gray{Time = 2\: Years} \\\sf\gray{Rate = 10\%\:per\:annum}\end{cases} \\\\$ $\Huge\sf\blue{\underline{\underline{To\:Find}}}\:: \\$ $\begin{cases}\sf\gray{Compound \: Interest}\end{cases} \\\\$ $\Huge\sf\pink{\underline{\underline{Solution}}}\:: \\\\$ $\boxed{ \sf{\orange{ A = P \bigg(1 + \frac{r}{100}\bigg)^n }}} \\\\$ $\leadsto\:\:\: \sf \purple {A = 12600 \bigg(1 + \dfrac{10}{100}\bigg)^2} \\\\$ $\leadsto\:\:\: \sf \green {12600 \bigg(1 + \dfrac{1}{10}\bigg)^2} \\\\$ $\leadsto\:\:\: \sf \purple {12600 \bigg(\dfrac{10 + 1}{10}\bigg)^2} \\\\$ $\leadsto\:\:\: \sf \green {12600 \bigg(\dfrac{11}{10}\bigg)^2} \\\\$ $\leadsto\:\:\: \sf \purple {12600 \times \dfrac{121}{100}} \\\\$ $\leadsto\:\:\: \sf \green {126 \times 121} \\\\$ $\leadsto\:\:\: \underline \mathsf \purple {15246} \\\\$ $\star\:\sf\underline\red{ Amount \: after \: 2 \: years = Rs\:15,246}\\\\$ $\Large\sf\gray{ Now,} \\$ $\boxed{ \sf{\orange{ Amount \: = \: Principal \: + \: Interest }}} \\\\$ $\leadsto\:\:\:\mathsf \purple {15246 \: = \: 12600 \: + \: Interest} \\\\$ $\leadsto\:\:\:\mathsf \green {15246\: - \:12600 \: =\: Interest} \\\\$ $\leadsto\:\:\: \mathsf \purple {2646 \: = \:Interest} \\\\$ $\leadsto\:\:\:\underline \mathsf \green {Interest \: = \: 2646} \\\\$ $\star\:\sf\underline\red{Hence,\: Compound\: Interest \:=\:Rs\:2,646}$

50.

Find CI on Rs 12600 for 2 years at 10% per annum compounded annually.

Answer»

$\Huge\sf\red{\underline{\underline{Given}}} \::\\$

$\begin{cases}\sf\gray{Principal = 12600} \\ \sf\gray{Time = 2\: Years} \\\sf\gray{Rate = 10\%\:per\:annum}\end{cases} \\\\$

$\Huge\sf\blue{\underline{\underline{To\:Find}}}\:: \\$

$\begin{cases}\sf\gray{Compound \: Interest}\end{cases} \\\\$

$\Huge\sf\pink{\underline{\underline{Solution}}}\:: \\\\$

$\boxed{ \sf{\orange{ A = P \bigg(1 + \frac{r}{100}\bigg)^n }}} \\\\$

$\leadsto\:\:\: \sf \purple {A = 12600 \bigg(1 + \dfrac{10}{100}\bigg)^2} \\\\$

$\leadsto\:\:\: \sf \green {12600 \bigg(1 + \dfrac{1}{10}\bigg)^2} \\\\$

$\leadsto\:\:\: \sf \purple {12600 \bigg(\dfrac{10 + 1}{10}\bigg)^2} \\\\$

$\leadsto\:\:\: \sf \green {12600 \bigg(\dfrac{11}{10}\bigg)^2} \\\\$

$\leadsto\:\:\: \sf \purple {12600 \times \dfrac{121}{100}} \\\\$

$\leadsto\:\:\: \sf \green {126 \times 121} \\\\$

$\leadsto\:\:\: \underline \mathsf \purple {15246} \\\\$

$\star\:\sf\underline\red{ Amount \: after \: 2 \: years = Rs\:15,246}\\\\$

$\Large\sf\gray{ Now,} \\$

$\boxed{ \sf{\orange{ Amount \: = \: Principal \: + \: Interest }}} \\\\$

$\leadsto\:\:\:\mathsf \purple {15246 \: = \: 12600 \: + \: Interest} \\\\$

$\leadsto\:\:\:\mathsf \green {15246\: - \:12600 \: =\: Interest} \\\\$

$\leadsto\:\:\: \mathsf \purple {2646 \: = \:Interest} \\\\$

$\leadsto\:\:\:\underline \mathsf \green {Interest \: = \: 2646} \\\\$

$\star\:\sf\underline\red{Hence,\: Compound\: Interest \:=\:Rs\:2,646}$

Discussion

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