332354 + Interview Questions in Secondary School in Math

1.	(c) 2-4(रेलवे परीक्षा, 2006)(6) 3-639. एक कर्मचारी के वेतन में 40% कमी कर दी गई. कुछ माह बाद उसके वेतन में 50% वृद्धि कर दी गई. इससे उसेकितने प्रतिशत हानि हुई?(c) 12%(d) इनमें से कोई नहीं
Answer» Step-by-step EXPLANATION: f6ddudhdudifidudusysuidsy

1.

(c) 2-4(रेलवे परीक्षा, 2006)(6) 3-639. एक कर्मचारी के वेतन में 40% कमी कर दी गई. कुछ माह बाद उसके वेतन में 50% वृद्धि कर दी गई. इससे उसेकितने प्रतिशत हानि हुई?(c) 12%(d) इनमें से कोई नहीं

Answer»

Step-by-step EXPLANATION:

f6ddudhdudifidudusysuidsy

Discussion

2.	A closed box is made up of wood which is lcm thick. The outer dimensions of the box is5 cm x 4 cm x 7 cm. Find the volume of the wood used.
Answer» Answer: GIVEN, OUTER length =5 CM Outer breadth =4 cm Outer HEIGHT =7 cm $\sf{Outer \ volume=length×breadth×height}$ $\sf{=5×4×7=140cm^{3}}$ $\sf{Thickness \ of \ wooden \ box, w=1 cm}$ $\sf{Inner \: length =l-2w=5-2=3 cm}$ $\sf{Inner \ breadth =b-2w=4-2=2 cm}$ $\sf{Inner \ height =h-2w=7-2=5 cm}$ $\sf{Inner \ volume =3×2×5=30cm^{3}}$ $\sf{Volume \ of \ wood \ used = outer \ volume - inner \ volume}$ $\sf{=140-30=110cm^{3}}$ $\\$

2.

A closed box is made up of wood which is lcm thick. The outer dimensions of the box is5 cm x 4 cm x 7 cm. Find the volume of the wood used.

Answer»

Answer:

GIVEN, OUTER length =5 CM

Outer breadth =4 cm

Outer HEIGHT =7 cm

$\sf{Outer \ volume=length×breadth×height}$

$\sf{=5×4×7=140cm^{3}}$

$\sf{Thickness \ of \ wooden \ box, w=1 cm}$

$\sf{Inner \: length =l-2w=5-2=3 cm}$

$\sf{Inner \ breadth =b-2w=4-2=2 cm}$

$\sf{Inner \ height =h-2w=7-2=5 cm}$

$\sf{Inner \ volume =3×2×5=30cm^{3}}$

$\sf{Volume \ of \ wood \ used = outer \ volume - inner \ volume}$

$\sf{=140-30=110cm^{3}}$

$\\$

Discussion

3.	3, 5, 17, 97, 769,?A] 9217B] 4609C] 6145D] 7681
Answer» ANSWER: Helohelohwloheloehloehleuejekwe

3.

3, 5, 17, 97, 769,?A] 9217B] 4609C] 6145D] 7681

Answer»

ANSWER:

Helohelohwloheloehloehleuejekwe

Discussion

4.	QFind the equation of a line lieson a planeplane 2x-3y + 4z=-8,perpendicular to a linex-1/3=y-1/2=z-2/3 and passes throughthe points (1,2,-1),
Answer» Answer: No such line can exist because the point (1,2,−1) does not LIE on the plane 2x−3y+4z=8 , therefore, the line cannot lie on the plane. Step-by-step explanation: An additional REASON why no such line can exist is that the direction of the line is →l=3ˆi+2ˆj+3ˆk ; this MEANS that the only planes that can have lines that intersect the GIVEN line perpendicularly must be of the form 3x+2y+3z=c where c is any real number. All other planes cannot have lines that intersect the given line perpendicularly.

4.

QFind the equation of a line lieson a planeplane 2x-3y + 4z=-8,perpendicular to a linex-1/3=y-1/2=z-2/3 and passes throughthe points (1,2,-1),

Answer»

Answer:

No such line can exist because the point

(1,2,−1) does not LIE on the plane 2x−3y+4z=8

, therefore, the line cannot lie on the plane.

Step-by-step explanation:

An additional REASON why no such line can exist is that the direction of the line is

→l=3ˆi+2ˆj+3ˆk

; this MEANS that the only planes that can have lines that intersect the GIVEN line perpendicularly must be of the form 3x+2y+3z=c where c is any real number. All other planes cannot have lines that intersect the given line perpendicularly.

Discussion

5.	Scored :SectionSolve the following: [3 marks each]1. Simplify:5+ V3 + 12+ 13 To+82213
Answer» Answer: 5 Step-by-step EXPLANATION: Given [5(8⅓ + 27⅓)³]¼ = {5[(2³)⅓+(3³)⅓]³}¼ \boxed {(a^{m})^{n} = a^{MN}}(am)n=amn = [5(2+3)³]¼ = [5×5³]¼ \boxed { a^{m} \times a^{n} = a^{m+n}}am×an=am+n = [5⁴]¼ =5 Therefore, [5(8⅓ + 27⅓)³]¼ = 5 ••••

5.

Scored :SectionSolve the following: [3 marks each]1. Simplify:5+ V3 + 12+ 13 To+82213

Answer»

Answer:

5

Step-by-step EXPLANATION:

Given [5(8⅓ + 27⅓)³]¼

= {5[(2³)⅓+(3³)⅓]³}¼

\boxed {(a^{m})^{n} = a^{MN}}(am)n=amn

= [5(2+3)³]¼

= [5×5³]¼

\boxed { a^{m} \times a^{n} = a^{m+n}}am×an=am+n

= [5⁴]¼

=5

Therefore,

[5(8⅓ + 27⅓)³]¼ = 5

••••

Discussion

6.	Find the area of a circle with a circumference of blue 50.24 units. Fill in the blank.___Units 2
Answer» ANSWER: suxt9zf69zco Step-by-step explanation: 89zcozc rr r rr r rj98z8trr r rrmru8r7 w8z8eh8eh8 e8h8h8ie

6.

Find the area of a circle with a circumference of blue 50.24 units. Fill in the blank.___Units 2

Answer»

ANSWER:

suxt9zf69zco

Step-by-step explanation:

89zcozc

rr

r

rr

r

rj98z8trr

r

rrmru8r7

w8z8eh8eh8

e8h8h8ie

Discussion

7.	Find an irrational number between 5/7 and 7/9I got numbers like 0.714285,0.714286,0.714287....are these numbers irrational in text book the answer is root5/3
Answer» ANSWER: lamao TRY try u will SURELY SOLVE it bro

7.

Find an irrational number between 5/7 and 7/9I got numbers like 0.714285,0.714286,0.714287....are these numbers irrational in text book the answer is root5/3

Answer»

ANSWER:

lamao TRY try u will SURELY SOLVE it bro

Discussion

8.	2. Kiara decides to decorate a ballroom with r = 3n + 20 roses, where n is the number of dancers inpair. Graph this function and see how many roses should she decorate if there are 3 pairs of dancers? 5 pairs of dancers? 7 pairs of dancers? 10 pairs of dancers? 15 pairs of dancers? what is the independent variable and dependent variable?
Answer» Answer: This is your carrier pagal KHEL to acha leta HAI par PADAI mein ZERO hai

8.

2. Kiara decides to decorate a ballroom with r = 3n + 20 roses, where n is the number of dancers inpair. Graph this function and see how many roses should she decorate if there are 3 pairs of dancers? 5 pairs of dancers? 7 pairs of dancers? 10 pairs of dancers? 15 pairs of dancers? what is the independent variable and dependent variable?

Answer»

Answer:

This is your carrier

pagal KHEL to acha leta HAI par PADAI mein ZERO hai

Discussion

9.	Solve and simplify:B²-A²÷(A-B)²Please help me understand this question.
Answer» b² - a² ÷ ( a - B ) ² ( AB ) ² + b⁴ - 2AB ³ - a² / ( a - b ) ²

9.

Solve and simplify:B²-A²÷(A-B)²Please help me understand this question.

Answer»

b² - a² ÷ ( a - B ) ²

( AB ) ² + b⁴ - 2AB ³ - a² / ( a - b ) ²

Discussion

10.	In which of the following cases, given * is a Binary operation on the set S?(A) S={1,2,3,6,18}, ab=ab(B) S= {1,-2,3,2,-4}, ab=\|b\|(C) S=Z,ab=a+b²(P) S=N ,ab=a-b
Answer» ANSWER: hard Step-by-step EXPLANATION: but not IMPOSSIBLE BEST of LUCK

10.

In which of the following cases, given * is a Binary operation on the set S?(A) S={1,2,3,6,18}, ab=ab(B) S= {1,-2,3,2,-4}, ab=|b|(C) S=Z,ab=a+b²(P) S=N ,ab=a-b

Answer»

ANSWER:

hard

Step-by-step EXPLANATION:

but not IMPOSSIBLE

BEST of LUCK

Discussion

11.	Maya deposited 25000rupees in a bank which pays 8%interest annually. How much would she get back after two years?
Answer» Answer: Here is the answer, CLICK the PHOTO, then you can get the answer Step-by-step explanation: PLZ MAKE brainliest answer

11.

Maya deposited 25000rupees in a bank which pays 8%interest annually. How much would she get back after two years?

Answer»

Answer:

Here is the answer, CLICK the PHOTO, then you can get the answer

Step-by-step explanation:

PLZ MAKE brainliest answer

Discussion

12.	.An architecture have model of building, length of building is 1m then length ofmodel is 0.75cm then find length & height of model building whose actual length is 22.5m& heght is 10m.
Answer» ANSWER: Step-by-step EXPLANATION:

12.

.An architecture have model of building, length of building is 1m then length ofmodel is 0.75cm then find length & height of model building whose actual length is 22.5m& heght is 10m.

Answer»

ANSWER:

Step-by-step EXPLANATION:

Discussion

13.	5 persons can construct a room in 4 days. In how many days will one person construct the same room
Answer» ANSWER: PLEASE MARK me as the BRILLIANT

13.

5 persons can construct a room in 4 days. In how many days will one person construct the same room

Answer»

ANSWER:

PLEASE MARK me as the BRILLIANT

Discussion

14.	Find the maximum and minimum value of 2+3sinx+4cosx
Answer» Answer: The MAXIMUM value of acosx+bsinx is GIVEN by a 2 +B 2 . So, maximum value of 4cosx+3sinx is given by 4 2 +3 2 = 25 =5.

14.

Find the maximum and minimum value of 2+3sinx+4cosx

Answer»

Answer:

The MAXIMUM value of acosx+bsinx is GIVEN by

a

2

+B

2

.

So, maximum value of 4cosx+3sinx is given by

4

2

+3

2

=

25

=5.

Discussion

15.	43. 20 men can do a work in 39 days. In how many days 26 men will do the samework?(a) 25 days (b) 30 days (c)35days (d) 20 days
Answer» Answer: 30DAYS Step-by-step explanation: 20×39=26 = 30days

15.

43. 20 men can do a work in 39 days. In how many days 26 men will do the samework?(a) 25 days (b) 30 days (c)35days (d) 20 days

Answer»

Answer:

30DAYS

Step-by-step explanation:

20×39=26

= 30days

Discussion

16.	If 28 Kg 700 g tomatoes are packed equally in 7 baskets, then howmuch tomatoes are there in each basket?
Answer» Answer: Total tomatoes :- 28 kg 700 g No. of BASKETS :- 7 $\blue{\bold{\underline{\underline{}}}}$ We NEED to DIVIDE weight of tomatoes by no, of baskets :- $\begin{gathered} :\implies\sf \dfrac { 28 kg \: 700 g \: } { 7 } \\ \\ \\ :\implies\sf\boxed{ 4 kg \:100 g \:}\end{gathered}$ Convert it in grams :- 1 kg = 1000 gm : $\implies$ 4000 + 100 grams : $\implies$ 4100 grams !

16.

If 28 Kg 700 g tomatoes are packed equally in 7 baskets, then howmuch tomatoes are there in each basket?

Answer»

Answer:

Total tomatoes :- 28 kg 700 g

No. of BASKETS :- 7

$\blue{\bold{\underline{\underline{}}}}$

We NEED to DIVIDE weight of tomatoes by no, of baskets :-

$\begin{gathered} :\implies\sf \dfrac { 28 kg \: 700 g \: } { 7 } \\ \\ \\ :\implies\sf\boxed{ 4 kg \:100 g \:}\end{gathered}$

Convert it in grams :- 1 kg = 1000 gm

: $\implies$ 4000 + 100 grams

: $\implies$ 4100 grams !

Discussion

17.	26. 2-50x28. 4x2 - 9-30. (1 - x21-x2)(1 - y2) + 4xy32. 2(x - 2y) - 50y?34. X-136. 2x - 32
Answer» <P>Answer: I, §2, p. 13 1. - 3 < x < 3 2. - 1 ~ x ~ 0 3. - j3 ~ x ~ - 1 or 1 ~ x ~ j3 4. x < 3 or x > 7 5. - 1 < x < 2 6. x < -lor x > 1 7. - 5 < x < 5 8. - 1 ~ x ~ 0 9. x ~ 1 or x = 0 10. x ~ - 10 or x = 5 11. x ~ -10 or x = 5 12. x ~ 1 or x = -! 13. x < -4 14. -5 17. -2 < x < 8 18. 2 < x < 4 19. -4 < x < 10 20. x < -4 and x> 10 21. x < -10 and x > 4 I, §3, p. 17 1. -~ 2. (2x ~ 1) 3. 0, 2, 108 4. 2z - Z2, 2w - w2 5. x # j2 or -j2. f(5) = b 6. All x. f(27) = 3 7. (a) 1 (b) 1 (c) -1 (d) -1 8. (a) 1 (b) 4 (c) 0 (d) 0 9. (a) -2 (b) -6 (c) x2+4x-2 10. x~O, 2 II. (a) odd (b) even (c) odd (d) odd I, §4, p. 20 1. 8 and 9 2.! and -1 3. /6 and 2 4. ~ and 21/ 3 5. -h and! 6. 9 and 8 7. -! and -1 8.! and! 9. 1 and -! 10. -5:2

17.

26. 2-50x28. 4x2 - 9-30. (1 - x21-x2)(1 - y2) + 4xy32. 2(x - 2y) - 50y?34. X-136. 2x - 32

Answer»

<P>Answer:

I, §2, p. 13

1. - 3 < x < 3 2. - 1 ~ x ~ 0 3. - j3 ~ x ~ - 1 or 1 ~ x ~ j3

4. x < 3 or x > 7 5. - 1 < x < 2 6. x < -lor x > 1 7. - 5 < x < 5

8. - 1 ~ x ~ 0 9. x ~ 1 or x = 0 10. x ~ - 10 or x = 5

11. x ~ -10 or x = 5 12. x ~ 1 or x = -! 13. x < -4

14. -5

17. -2 < x < 8 18. 2 < x < 4 19. -4 < x < 10 20. x < -4 and x> 10

21. x < -10 and x > 4

I, §3, p. 17

1. -~ 2. (2x ~ 1) 3. 0, 2, 108 4. 2z - Z2, 2w - w2

5. x # j2 or -j2. f(5) = b 6. All x. f(27) = 3

7. (a) 1 (b) 1 (c) -1 (d) -1 8. (a) 1 (b) 4 (c) 0 (d) 0

9. (a) -2 (b) -6 (c) x2+4x-2 10. x~O, 2

II. (a) odd (b) even (c) odd (d) odd

I, §4, p. 20

1. 8 and 9 2.! and -1 3. /6 and 2 4. ~ and 21/ 3 5. -h and! 6. 9 and 8

7. -! and -1 8.! and! 9. 1 and -! 10. -5:2

Discussion

18.	Find the difference in the area of two squares, one with length of side 2.5m and the other with length of diagonal 5m.a:- 2.5sq.mb:-4sq.mc:- 6.35sq.md:- 4.10sqm
Answer» <U>A n s w e r ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ G i v e n ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Length of side of one SQUARE is 2.5 m Length of diagonal of other square is 5 m ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ F i n d ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ The difference in the area of two squares ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ S o l u t i o n ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ $\underline{ \underline{\bold{\texttt{Area of square :}}}}$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ ➠ Side × Side ⚊⚊⚊⚊ ⓵ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ $\underline{ \underline{\bold{\texttt{Area of first square :}}}}$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Side = 2.5 m ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ ⟮ Putting the value in ⓵ ⟯ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ Side × Side ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 2.5 × 2.5 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 6.25 sq. m ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Hence the area of first square is 6.25 sq. m ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ $\underline{ \underline{\bold{\texttt{Diagonal of square :}}}}$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ ➠ Side² + Side² = Diagonal² ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Diagonal = 5 m ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ ⟮ Putting the above value in ⓶ ⟯ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ Side² + Side² = Diagonal² ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 2Side² = 5² ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ Side² = 25⁄2 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ Side² = 12.5 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Also , ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ Side² = Area of square ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Hence the area of second square is 12.5 sq. m ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ $\underline{ \underline{\bold{\texttt{Difference in the areas of two squares :}}}}$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Area of second square - Area of first square ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Area of second square = 12.5 sq. m Area of first square = 6.25 sq. m ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ ⟮ Putting the above values ⟯ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Area of second square - Area of first square ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 12.5 - 6.25 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : : ➨ 6.25 sq. m ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Hence the difference in areas of two squares is 6.25 sq. m

18.

Find the difference in the area of two squares, one with length of side 2.5m and the other with length of diagonal 5m.a:- 2.5sq.mb:-4sq.mc:- 6.35sq.md:- 4.10sqm

Answer»

<U>A n s w e r

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

G i v e n

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Length of side of one SQUARE is 2.5 m
Length of diagonal of other square is 5 m

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

F i n d

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

The difference in the area of two squares

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

S o l u t i o n

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

$\underline{ \underline{\bold{\texttt{Area of square :}}}}$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

➠ Side × Side ⚊⚊⚊⚊ ⓵

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

$\underline{ \underline{\bold{\texttt{Area of first square :}}}}$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Side = 2.5 m

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

⟮ Putting the value in ⓵ ⟯

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ Side × Side

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 2.5 × 2.5

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 6.25 sq. m

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Hence the area of first square is 6.25 sq. m

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

$\underline{ \underline{\bold{\texttt{Diagonal of square :}}}}$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

➠ Side² + Side² = Diagonal² ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Diagonal = 5 m

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

⟮ Putting the above value in ⓶ ⟯

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ Side² + Side² = Diagonal²

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 2Side² = 5²

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ Side² = 25⁄2

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: ➜ Side² = 12.5

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Also ,

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ Side² = Area of square

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Hence the area of second square is 12.5 sq. m

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

$\underline{ \underline{\bold{\texttt{Difference in the areas of two squares :}}}}$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Area of second square - Area of first square

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Area of second square = 12.5 sq. m
Area of first square = 6.25 sq. m

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

⟮ Putting the above values ⟯

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Area of second square - Area of first square

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 12.5 - 6.25

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: : ➨ 6.25 sq. m

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Hence the difference in areas of two squares is 6.25 sq. m

Discussion

19.	B.19062519062.5 x 100000= 7.9062 x 104it is correct plls answer I will mark as brain list
Answer» ANSWER: PLEASE you CHECK your QUESTION .

19.

B.19062519062.5 x 100000= 7.9062 x 104it is correct plls answer I will mark as brain list

Answer»

ANSWER:

PLEASE you CHECK your QUESTION .

Discussion

20.	Theangle of elevation of anGeraplane fromthe groundis Goo After a flight of 30 seconds,the elevation changes toaeroplane is flying at a constantheight at 4500 metres. Find the speedof the plane
Answer» ANSWER: ANGLE 60 degree Step-by-step explanation: make me as BRAINLIST

20.

Theangle of elevation of anGeraplane fromthe groundis Goo After a flight of 30 seconds,the elevation changes toaeroplane is flying at a constantheight at 4500 metres. Find the speedof the plane

Answer»

ANSWER:

ANGLE 60 degree

Step-by-step explanation:

make me as BRAINLIST

Discussion

21.	9.If Q is the set of rational numbers Ő is theset of irrational numbers, thena) QU Q=Rb) QcQc) Q CQ=Qd) None of these
Answer» ANSWER: d is the answers in this QUESTIONS okk Step-by-step explanation: plz MARK me a BRAIN lisr

21.

9.If Q is the set of rational numbers Ő is theset of irrational numbers, thena) QU Q=Rb) QcQc) Q CQ=Qd) None of these

Answer»

ANSWER:

d is the answers in this QUESTIONS okk

Step-by-step explanation:

plz MARK me a BRAIN lisr

Discussion

22.	COS (A + B).5. (i) If sin A =VIOsin B =115107prove that A + B = "; A and B being positive acute4angles.
Answer» Answer: answer is pie by four please mark my answer as brainliest. Step-by-step explanation: sin A = 1/√10 and sin B = 1/√5 We KNOW that sin2x + cos2x = 1 Thus, cos A = √(1 – sin2A) = 3/√10 cos B = √(1 – SIN2B) = 2/√5 As we know, sin(A + B) = sin A cos B + cos A sin B = (1/√10) (2/√5) + (3/√10) (1/√5) = (2 + 3)/ √50 = 5/(5√2) = 1/√2 sin(A + B) = sin π/4 {SINCE A and B are acute angles as per the GIVEN} Therefore, A + B = π/4

22.

COS (A + B).5. (i) If sin A =VIOsin B =115107prove that A + B = "; A and B being positive acute4angles.

Answer»

Answer:

answer is pie by four please mark my answer as brainliest.

Step-by-step explanation:

sin A = 1/√10 and sin B = 1/√5

We KNOW that sin2x + cos2x = 1

Thus, cos A = √(1 – sin2A) = 3/√10

cos B = √(1 – SIN2B) = 2/√5

As we know,

sin(A + B) = sin A cos B + cos A sin B

= (1/√10) (2/√5) + (3/√10) (1/√5)

= (2 + 3)/ √50

= 5/(5√2)

= 1/√2

sin(A + B) = sin π/4 {SINCE A and B are acute angles as per the GIVEN}

Therefore, A + B = π/4

Discussion

23.	If 5 students sit in a row, then the probability that two particular students are always together is
Answer» ANSWER: jdnf DJ rjdnsjbeje J RKD ID dineiehe dkneod

23.

If 5 students sit in a row, then the probability that two particular students are always together is

Answer»

ANSWER:

jdnf DJ rjdnsjbeje J RKD ID dineiehe dkneod

Discussion

24.	(h) If a number exactly divides two numbers separately, it must exactly divide theirsum.(1) Ifa number exactly divides the sum of two numbers, it must exactly divide the two
Answer» ANSWER: REALLY I don't KNOW SORRY BUDDY

24.

(h) If a number exactly divides two numbers separately, it must exactly divide theirsum.(1) Ifa number exactly divides the sum of two numbers, it must exactly divide the two

Answer»

ANSWER:

REALLY I don't KNOW SORRY BUDDY

Discussion

25.	The total surface area of a solid hemisphere of radius r is ------a) 2pi r^22 b) 3pi r^22 c) 4pi r^22 d) pi r^22
Answer» Answer: b) 3PI r^2 Step-by-step EXPLANATION: The total surface area of a solid HEMISPHERE of RADIUS r is ------ 3 pi r^2 Hope this will help you

25.

The total surface area of a solid hemisphere of radius r is ------a) 2pi r^22 b) 3pi r^22 c) 4pi r^22 d) pi r^22

Answer»

Answer:

b) 3PI r^2

Step-by-step EXPLANATION:

The total surface area of a solid HEMISPHERE of RADIUS r is ------

3 pi r^2

Hope this will help you

Discussion

26.	Help me solving these questions. plz plz don't scam.those who don't know the answer please don't answer
Answer» Answer: xccdffctxexexu the the the the the the is a GOOD time to explore new WAYS of LEARNING and smart ways of learning and smart ways of learning and smart

26.

Help me solving these questions. plz plz don't scam.those who don't know the answer please don't answer

Answer»

Answer:

xccdffctxexexu the the the the the the is a GOOD time to explore new WAYS of LEARNING and smart ways of learning and smart ways of learning and smart

Discussion

27.	If sin0 + cos0 = p and sin³0 + cos³0 = q , then find the value of 3p - 2q.Please answer it.
Answer» Step-by-step EXPLANATION: NNSA and its MEMBERS were 9inches

27.

If sin0 + cos0 = p and sin³0 + cos³0 = q , then find the value of 3p - 2q.Please answer it.

Answer»

Step-by-step EXPLANATION:

NNSA and its MEMBERS were 9inches

Discussion

28.	12 मीटर ऊंचे एक खंबे की जमीन पर छाया की लंबाई 9मीटर है।उसी समय पर 18 मीटर ऊंचे खंबे की छाया कीलंबाई होगी :- The length of the shadow of apole12 meters high is 9 meters on the ground. Atthe same time the length of the shadow of thepole 18 meters high will be: -
Answer» ANSWER: STEP by step explanation refer to IMAGE ATTACHED

28.

12 मीटर ऊंचे एक खंबे की जमीन पर छाया की लंबाई 9मीटर है।उसी समय पर 18 मीटर ऊंचे खंबे की छाया कीलंबाई होगी :- The length of the shadow of apole12 meters high is 9 meters on the ground. Atthe same time the length of the shadow of thepole 18 meters high will be: -

Answer»

ANSWER:

STEP by step explanation

refer to IMAGE ATTACHED

Discussion

29.	Question 9एक दूध विक्रेता हर रोज 75 लोगों को दूधबेचता है। किसी एक दिन 4/15 लोग दूध केखराब होने की शिकायत करते हैं। शिकायतकरने वाले लोगों की संख्या क्या होगी?Amilk vendor sells milk to 75 peopleevery day. On one day, 4/15 peoplecomplain of milk spoilage. Howmany people made complaint aboutspoiled milk?C20217
Answer»

Discussion

30.	A11. In the given figure, medians AD and BE of AABC meet at Gand DF \| BE.Prove that (i) EF = FC (ii) AG : GD = 2 : 1.(Hint. angleEBC - angleFDC)
Answer» Answer: EF=FC because TWO ANGLES FORM on a PARTICULAR line

30.

A11. In the given figure, medians AD and BE of AABC meet at Gand DF | BE.Prove that (i) EF = FC (ii) AG : GD = 2 : 1.(Hint. angleEBC - angleFDC)

Answer»

Answer:

EF=FC because TWO ANGLES FORM on a PARTICULAR line

Discussion

31.	Group of InsBidar, Bhalki, BasaSSLC MATHS SANJIVEGraph (7MarkI. Solve the following pair of linear equations graphically:1. 2x + y = 5,x+y=42. x + y = 5, 2x - y=43. 2x+y=10,x+y=64. 2x + y -6= 0,4x - 2y -4 = 05. 2x+y = 6,2x - y = 2II. Draw a less than type of ogive for given data:38-40 40-42
Answer» Answer: PLEASE mark this BRAINLIEST please again I follow and LIKE you to OK sir please see

31.

Group of InsBidar, Bhalki, BasaSSLC MATHS SANJIVEGraph (7MarkI. Solve the following pair of linear equations graphically:1. 2x + y = 5,x+y=42. x + y = 5, 2x - y=43. 2x+y=10,x+y=64. 2x + y -6= 0,4x - 2y -4 = 05. 2x+y = 6,2x - y = 2II. Draw a less than type of ogive for given data:38-40 40-42

Answer»

Answer:

PLEASE mark this BRAINLIEST please again I follow and LIKE you to OK sir please see

Discussion

32.	2.If A got 8.33% more votes than B in an election, by what % is B's votes less than thatreceived by A?a. 7.71%b. 8.33%c. 9.09%d. 10%
Answer» Answer: b. 8.33 less VOTES A GETS in the ELECTION

32.

2.If A got 8.33% more votes than B in an election, by what % is B's votes less than thatreceived by A?a. 7.71%b. 8.33%c. 9.09%d. 10%

Answer»

Answer:

b. 8.33 less VOTES A GETS in the ELECTION

Discussion

33.	1 1_ + _ = ???? HOW MUCH 8 10 EXPLAIN STEP BY STEPSPARM ANSWERS WILL BE REPORTED.IF ANY ONE CAN EXPLAIN CLEARLY & EASILY.. I WILL MARK HIM OR HER AS BRAINLIEST
Answer» Step-by-step EXPLANATION: firstly YPU WRITE your question properly its not proper

33.

1 1_ + _ = ???? HOW MUCH 8 10 EXPLAIN STEP BY STEPSPARM ANSWERS WILL BE REPORTED.IF ANY ONE CAN EXPLAIN CLEARLY & EASILY.. I WILL MARK HIM OR HER AS BRAINLIEST

Answer»

Step-by-step EXPLANATION:

firstly YPU WRITE your question properly its not proper

Discussion

34.	Inies It cacha) Show that the following pair of curves r=a(theta) and r =a/2other orthogonally.
Answer» ANSWER: I donno ANYWAYS GOOD HOURS ahead

34.

Inies It cacha) Show that the following pair of curves r=a(theta) and r =a/2other orthogonally.

Answer»

ANSWER:

I donno ANYWAYS GOOD HOURS ahead

Discussion

35.	(a) =(B)1)Solve.Write the 2(y + y) + 3 = 2y 6-1) equation in theFor the following experiment write sample space Sat
Answer» ANSWER: it's EASY you should TRY your SELF

35.

(a) =(B)1)Solve.Write the 2(y + y) + 3 = 2y 6-1) equation in theFor the following experiment write sample space Sat

Answer»

ANSWER:

it's EASY you should TRY your SELF

Discussion

36.	Please help me in this question ⁉️⁉️Q2:A: Given A = 3i+5j. B = -4i + Find the A+B A - B & A.BB: find the vector i directed from point (3,-5,2) to point (2,-2,1) in cartesian coordinatesand find the unit vector along F
Answer» Answer: Given :- Ratio of length breadth and height = 1:2:3 TSA = 792 sq. m To Find :- VOLUME Solution :- Let, Length = x breadth = 2x Height = 3x \bf\red{TSA = 2(lb + BH +lh)}TSA=2(lb+bh+lh) \sf 792 = 2(x\times 2x +2 x\times 3x+ x\times 3x)792=2(x×2x+2x×3x+x×3x) \sf 792=2(2x^{2} +6x^{2} +3x^{2} )792=2(2x 2 +6x 2 +3x 2 ) \sf 792 = 2(11x^{2} )792=2(11x 2 ) \sf\dfrac{792}{2} = 11x^2 2 792 =11x 2 \sf 396 = 11x^{2}396=11x 2 \sf \dfrac{396}{11} = x^{2} 11 396 =x 2 \sf 36 = x^{2}36=x 2 \sf \sqrt{36} =\sqrt{x^2} 36 = x 2 \sf 6 = x6=x Length = 6 m Breadth = 2(6) = 12 m Height = 3(6) = 18 m ~Finding volume \bf Volume = l\times b \times hVolume=l×b×h \sf Volume = 6 \times12\times18Volume=6×12×18 \sf Volume = 1296 m^{3}Volume=1296m 3 this is your answer

36.

Please help me in this question ⁉️⁉️Q2:A: Given A = 3i+5j. B = -4i + Find the A+B A - B & A.BB: find the vector i directed from point (3,-5,2) to point (2,-2,1) in cartesian coordinatesand find the unit vector along F

Answer»

Answer:

Given :-

Ratio of length breadth and height = 1:2:3

TSA = 792 sq. m

To Find :-

VOLUME

Solution :-

Let,

Length = x

breadth = 2x

Height = 3x

\bf\red{TSA = 2(lb + BH +lh)}TSA=2(lb+bh+lh)

\sf 792 = 2(x\times 2x +2 x\times 3x+ x\times 3x)792=2(x×2x+2x×3x+x×3x)

\sf 792=2(2x^{2} +6x^{2} +3x^{2} )792=2(2x

2

+6x

2

+3x

2

)

\sf 792 = 2(11x^{2} )792=2(11x

2

)

\sf\dfrac{792}{2} = 11x^2

2

792

=11x

2

\sf 396 = 11x^{2}396=11x

2

\sf \dfrac{396}{11} = x^{2}

11

396

=x

2

\sf 36 = x^{2}36=x

2

\sf \sqrt{36} =\sqrt{x^2}

36

=

x

2

\sf 6 = x6=x

Length = 6 m

Breadth = 2(6) = 12 m

Height = 3(6) = 18 m

~Finding volume

\bf Volume = l\times b \times hVolume=l×b×h

\sf Volume = 6 \times12\times18Volume=6×12×18

\sf Volume = 1296 m^{3}Volume=1296m

3

this is your answer

Discussion

37.	P and q are midpoint of side ab and side AC show that PQ is parallel to BC and PQ is half of BCPLEASE SOLVE AND GIVE ME
Answer» ANSWER: agataysuagatayagataysusaklqlqkqkqnbwvwvegdyiagataysusaklqlqkqkqnagataagagataysusaklqlqkqkagataysusaklqlqkqkqnbwvwvegdyiaiwoq91uptefrxchv H bhuuyhjje23477iiuggbjjhddfdfyffvhboooyeetjklhee59ooihvcdsae4u992158okhgfrr333478099654321wtfvjjimolkjhvtdswdfggýehuor32469ptysfhnkou6

37.

P and q are midpoint of side ab and side AC show that PQ is parallel to BC and PQ is half of BCPLEASE SOLVE AND GIVE ME

Answer»

ANSWER:

agataysuagatayagataysusaklqlqkqkqnbwvwvegdyiagataysusaklqlqkqkqnagataagagataysusaklqlqkqkagataysusaklqlqkqkqnbwvwvegdyiaiwoq91uptefrxchv H bhuuyhjje23477iiuggbjjhddfdfyffvhboooyeetjklhee59ooihvcdsae4u992158okhgfrr333478099654321wtfvjjimolkjhvtdswdfggýehuor32469ptysfhnkou6

Discussion

38.	(v) একটি লম্ববৃত্তাকার চোঙের পার্শ্বতলের ক্ষেত্রফল ভূমির ক্ষেত্রফলের 4 গুণ হলে, উচ্চতা এবং বাসাধেরঅনুপাত(a) 2:3(b) 1:2(d) 2: 1(c) 3:2
Answer» Hdbbdjdbb7838838393939393

Discussion

39.	6. In the figure 5.12, OPQRS and DABCRare two parallelograms.If ZP = 110° then find the measures ofall angles of ABCRSFig. 5.12
Answer» ANSWER: jshshdhdhdjdiidididoodidjdododifkckdofidjdjdjdjxkdjdjsjj shdjdj

39.

6. In the figure 5.12, OPQRS and DABCRare two parallelograms.If ZP = 110° then find the measures ofall angles of ABCRSFig. 5.12

Answer»

ANSWER:

jshshdhdhdjdiidididoodidjdododifkckdofidjdjdjdjxkdjdjsjj shdjdj

Discussion

40.	ਕਿਸੇ ਵਰਗ ਦੀ ਭੁਜਾ ਦੀ ਲੰਬਾਈ ਪਤਾ ਕਰੋ, ਜਿਸਦਾ ਖੇਤਰਫਲ 1225 ਸਮ ਹੈ।Find the length of the side of a square if its area is 1225 cm
Answer» Answer: 35cm Step-by-step EXPLANATION: AREA for square=a^2=1225 so SIDE a=root of 1225=35cm

40.

ਕਿਸੇ ਵਰਗ ਦੀ ਭੁਜਾ ਦੀ ਲੰਬਾਈ ਪਤਾ ਕਰੋ, ਜਿਸਦਾ ਖੇਤਰਫਲ 1225 ਸਮ ਹੈ।Find the length of the side of a square if its area is 1225 cm

Answer»

Answer:

35cm

Step-by-step EXPLANATION:

AREA for square=a^2=1225

so SIDE a=root of 1225=35cm

Discussion

41.	34. The measures of the angles of a triangle are (2x + 5)º. (4x + 10)° and(3x - 15). What type of triangle is it?(1) Scalene right angled triangle(2) Scalene obtuse angled triangle(3) Right angled isosceles triangle(4) Acute angled isosceles triangle
Answer» Answer : Right angled isosceles triangle. Solution : Given : (2x + 5)º, (4x + 10)° and (3x - 15)° are angles of a triangle. To Find : Type of triangle. Let's solve , We know that , SUM of all angles of a triangle = 180° So, (2x + 5)º + (4x + 10)° + (3x - 15)° = 180° ➩ 2x + 5 + 4x + 10 + 3x - 15 = 180° $\implies \sf 9x + \cancel{15}\: \: \cancel{-15}$ = 180° $\implies \sf <klux>X</klux> = \dfrac{180}{9} \\ \\ \implies \sf \red \boxed{\sf{ x = 20} }$ Now, we can know the value of all three angles by putting x 1ST angle $\implies \sf (2x + 5)\\ \\ \implies \sf 2(20) + 5 \\ \\ \implies \sf \boxed{\pink{ 45^\circ}}$ 2nd angle $\implies \sf (4x+10)\\ \\ \implies \sf 4\times20 + 10 \\\\\implies \sf \boxed{\pink {90^\circ}}$ 3rd angle $\implies \sf (3x-15) \\ \\\implies \sf 3\times20 -15 \\ \\ \implies \sf \boxed{\pink{ 45^\circ}}$ Here, One angle is of 90°. Hence, it is right angled triangle Other TWO angles are of 45°. Hence, it is isosceles triangle. Hence, This triangle has two angles of 45° and one of 90°. So, it is a Right angled isosceles triangle.

41.

34. The measures of the angles of a triangle are (2x + 5)º. (4x + 10)° and(3x - 15). What type of triangle is it?(1) Scalene right angled triangle(2) Scalene obtuse angled triangle(3) Right angled isosceles triangle(4) Acute angled isosceles triangle

Answer»

Answer :

Right angled isosceles triangle.

Solution :

Given :

(2x + 5)º, (4x + 10)° and (3x - 15)° are angles of a triangle.

To Find :

Type of triangle.

Let's solve ,

We know that ,

SUM of all angles of a triangle = 180°

So,

(2x + 5)º + (4x + 10)° + (3x - 15)° = 180°

➩ 2x + 5 + 4x + 10 + 3x - 15 = 180°

$\implies \sf 9x + \cancel{15}\: \: \cancel{-15}$ = 180°

$\implies \sf <klux>X</klux> = \dfrac{180}{9} \\ \\ \implies \sf \red \boxed{\sf{ x = 20} }$

Now, we can know the value of all three angles by putting x

1ST angle

$\implies \sf (2x + 5)\\ \\ \implies \sf 2(20) + 5 \\ \\ \implies \sf \boxed{\pink{ 45^\circ}}$

2nd angle

$\implies \sf (4x+10)\\ \\ \implies \sf 4\times20 + 10 \\\\\implies \sf \boxed{\pink {90^\circ}}$

3rd angle

$\implies \sf (3x-15) \\ \\\implies \sf 3\times20 -15 \\ \\ \implies \sf \boxed{\pink{ 45^\circ}}$

Here,

One angle is of 90°. Hence, it is right angled triangle
Other TWO angles are of 45°. Hence, it is isosceles triangle.

Hence,

This triangle has two angles of 45° and one of 90°. So, it is a Right angled isosceles triangle.

Discussion

42.	7.) 3yr ago the average ageof A and B was 18 yr. With C joining them,now the average became 22 yr. How old is C now?a) 24 yr(b)27 yr(c)28 yr(d)30 yr
Answer» Answer: ans D 30 yrs Step-by-step EXPLANATION: REFER attachment marks as brainliest if you found helpful

42.

7.) 3yr ago the average ageof A and B was 18 yr. With C joining them,now the average became 22 yr. How old is C now?a) 24 yr(b)27 yr(c)28 yr(d)30 yr

Answer»

Answer:

ans D 30 yrs

Step-by-step EXPLANATION:

REFER attachment

marks as brainliest if you found helpful

Discussion

43.	15. The sum of first n terms of an A.P. is 5n -n2. Find the nth term of the A.P...ho r u all
Answer» ANSWER: I am FINE how are you HAPPY HOLI

43.

15. The sum of first n terms of an A.P. is 5n -n2. Find the nth term of the A.P...ho r u all

Answer»

ANSWER:

I am FINE how are you

HAPPY HOLI

Discussion

44.	If cos ec39° = x, then the value of1+sin? 39° + tan2 51°1cos ec 51°sin? 51 sec? 39° is
Answer» Step-by-step EXPLANATION: jjhumiliation the BEST of WEST ACTIVITY the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best of west activity the best

44.

If cos ec39° = x, then the value of1+sin? 39° + tan2 51°1cos ec 51°sin? 51 sec? 39° is

Answer»

Step-by-step EXPLANATION:

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Discussion

45.	MODEL-815. The average age of 20 boys in a class is 15 years. If tteacher's age is included then the average age isincreased by 2 years. What is the teacher's age?
Answer» Answer: The teacher's age is 57 years. Step-by-step explanation: Given that: The average age of 20 boys in a class is 15 years. If the teacher's age is included then the average age is increased by 2 years. To Find: What is the teacher's age? Let us assume: The teacher's age be x years. Formula used: Average = (SUM of observations)/(Number of observations) First find the sum of observations: Average = (Sum of observations)/(Number of observations) ⟶ 15 = (Sum of observations)/(20) ⟶ Sum of observations = 15 × 20 ⟶ Sum of observations = 300 When teacher's age is included: Sum of observations = 300 + x Number of observations = 20 + 1 = 21 Average = 15 + 2 = 17 years Now finding the age of teacher: Average = (Sum of observations)/(Number of observations) Substituting the values. ⇒ 17 = (300 + x)/21 ⇒ 300 + x = 21 × 17 ⇒ 300 + x = 357 ⇒ x = 357 - 300 ⇒ x = 57 ∴ The teacher's age = 57 years.

45.

MODEL-815. The average age of 20 boys in a class is 15 years. If tteacher's age is included then the average age isincreased by 2 years. What is the teacher's age?

Answer»

Answer:

The teacher's age is 57 years.

Step-by-step explanation:

Given that:

The average age of 20 boys in a class is 15 years.

If the teacher's age is included then the average age is

increased by 2 years.

To Find:

What is the teacher's age?

Let us assume:

The teacher's age be x years.

Formula used:

Average = (SUM of observations)/(Number of observations)

First find the sum of observations:

Average = (Sum of observations)/(Number of observations)

⟶ 15 = (Sum of observations)/(20)

⟶ Sum of observations = 15 × 20

⟶ Sum of observations = 300

When teacher's age is included:

Sum of observations = 300 + x

Number of observations = 20 + 1 = 21

Average = 15 + 2 = 17 years

Now finding the age of teacher:

Average = (Sum of observations)/(Number of observations)

Substituting the values.

⇒ 17 = (300 + x)/21

⇒ 300 + x = 21 × 17

⇒ 300 + x = 357

⇒ x = 357 - 300

⇒ x = 57

∴ The teacher's age = 57 years.

Discussion

46.	2.Solve the L.P.P. by simplex method.Maximize Z = 2x + 3ySubject to x + 2y = 64x + 6y < 24X, y 20.
Answer» Answer: PLEASE MARK this BRAINLIEST please again I follow and like you to OK sir ap

46.

2.Solve the L.P.P. by simplex method.Maximize Z = 2x + 3ySubject to x + 2y = 64x + 6y < 24X, y 20.

Answer»

Answer:

PLEASE MARK this BRAINLIEST please again I follow and like you to OK sir ap

Discussion

47.	The correct answer.decimal 23.654 is read as:we three point six hundred fifty-fourwenty-three point six hundred fifty-fourh is the greatest in value?0.05two three point sie five fouriv. twenty-three point is five four0.50Both landiof these are like decimals?250, 25002.5.2.05.20052.05. 2.50 20.052.5. 205. 2.05ded by sient, Remainder 0.4Quotient Remainder 4ent=0.5Quotient 0.0510.10s Too1831000fractions or mixed numbers5.050111
Answer» Step-by-step EXPLANATION: iwyyidkhdcnbchlfitsiyg chkciysyospo

47.

The correct answer.decimal 23.654 is read as:we three point six hundred fifty-fourwenty-three point six hundred fifty-fourh is the greatest in value?0.05two three point sie five fouriv. twenty-three point is five four0.50Both landiof these are like decimals?250, 25002.5.2.05.20052.05. 2.50 20.052.5. 205. 2.05ded by sient, Remainder 0.4Quotient Remainder 4ent=0.5Quotient 0.0510.10s Too1831000fractions or mixed numbers5.050111

Answer»

Step-by-step EXPLANATION:

iwyyidkhdcnbchlfitsiyg chkciysyospo

Discussion

48.	What is true about the graph of function f defined byf(x) = 4 + \| \| x \| - 3 \|. (I) Symmetric with respect to y-axis(II) Has no x intercepts(III) Has a y intercept at (0 , 7)A) (I) and (II) onlyB) (I) and (III) onlyC) (I), (II) and (III)D) NoneE) (II) and (III) only
Answer» Answer: What is true about the graph of function F defined by f(x) = 4 + \| \| x \| - 3 \|. (I) Symmetric with respect to y-axis (II) Has no x intercepts (III) Has a y intercept at (0 , 7) A) (I) and (II) only B) (I) and (III) only C) (I), (II) and (III) D) None E) (II) and (III) only

48.

What is true about the graph of function f defined byf(x) = 4 + | | x | - 3 |. (I) Symmetric with respect to y-axis(II) Has no x intercepts(III) Has a y intercept at (0 , 7)A) (I) and (II) onlyB) (I) and (III) onlyC) (I), (II) and (III)D) NoneE) (II) and (III) only

Answer»

Answer:

What is true about the graph of function F defined by

f(x) = 4 + | | x | - 3 |. (I) Symmetric with respect to y-axis

(II) Has no x intercepts

(III) Has a y intercept at (0 , 7)

A) (I) and (II) only

B) (I) and (III) only

C) (I), (II) and (III)

D) None

E) (II) and (III) only

Discussion

49.	Nelle qualities for.4 Explain the impact of the tax rebate and the medical aid credits on the annual taxpayable
Answer» Step-by-step explanation: Explain the IMPACT of the tax rebate and the medical AID credits on the ANNUAL tax payable

49.

Nelle qualities for.4 Explain the impact of the tax rebate and the medical aid credits on the annual taxpayable

Answer»

Step-by-step explanation:

Explain the IMPACT of the tax rebate and the medical AID credits on the ANNUAL tax

payable

Discussion

50.	If two triangles are similar, then which of the following statement is true ?(a) Their corresponding sides are equal.(b) Their areas are equal.(C) Their corresponding angles are equal. (d) Their medians are equal.
Answer» Step-by-step EXPLANATION: Their CORRESPONDING SIDE Are EQUAL

50.

If two triangles are similar, then which of the following statement is true ?(a) Their corresponding sides are equal.(b) Their areas are equal.(C) Their corresponding angles are equal. (d) Their medians are equal.

Answer»

Step-by-step EXPLANATION:

Their CORRESPONDING SIDE Are EQUAL

Discussion

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