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QFind the equation of a line lieson a planeplane 2x-3y + 4z=-8,perpendicular to a linex-1/3=y-1/2=z-2/3 and passes throughthe points (1,2,-1), |
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Answer» Answer: No such line can exist because the point (1,2,−1) does not LIE on the plane 2x−3y+4z=8 , therefore, the line cannot lie on the plane. Step-by-step explanation: An additional REASON why no such line can exist is that the direction of the line is →l=3ˆi+2ˆj+3ˆk ; this MEANS that the only planes that can have lines that intersect the GIVEN line perpendicularly must be of the form 3x+2y+3z=c where c is any real number. All other planes cannot have lines that intersect the given line perpendicularly. |
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