332354 + Interview Questions in Secondary School in Math

1.	Help?Andre shot three arrows and they landed at (-5, 4), (-8, 7), and (1, 6). What is his total score? A. 14 C. 8 Yellow: 10 points Red: 8 points Blue: 6 points B. 15 D. 18 Green: 4 points White: 2 points
Answer» Given : Andre SHOT three arrows and they landed at (-5, 4), (-8, 7), and (1, 6). Yellow: 10 POINTS Red: 8 points Blue: 6 points Green: 4 points White: 2 points To Find : total score? A. 14 B. 15 C. 8 D. 18 Solution: (-5, 4) is in blue REGION hence 6 points (-8 , 7) is in red region Hence 8 points ( 1 , 6) is out side board = 0 points so Total score = 6 + 8 + 0 = 14 points Learn More: LOCATE the points A (1, 2), B( 3, 4) and C (5, 2) on a graph sheet .. brainly.in/question/8917897 Andre shot three arrows brainly.in/question/37816817

1.

Help?Andre shot three arrows and they landed at (-5, 4), (-8, 7), and (1, 6). What is his total score? A. 14 C. 8 Yellow: 10 points Red: 8 points Blue: 6 points B. 15 D. 18 Green: 4 points White: 2 points

Answer»

Given : Andre SHOT three arrows and they landed at (-5, 4), (-8, 7), and (1, 6).

Yellow: 10 POINTS

Red: 8 points

Blue: 6 points

Green: 4 points

White: 2 points

To Find : total score?

A. 14

B. 15

C. 8

D. 18

Solution:

(-5, 4) is in blue REGION hence 6 points

(-8 , 7) is in red region Hence 8 points

( 1 , 6) is out side board = 0 points

so Total score = 6 + 8 + 0 = 14 points

Learn More:

LOCATE the points A (1, 2), B( 3, 4) and C (5, 2) on a graph sheet ..

brainly.in/question/8917897

Andre shot three arrows

brainly.in/question/37816817

Discussion

2.	Show that the relation "less than or equal to" on the set of integers Z, is reflexive and transitivebut not symmetric
Answer» Basic Concept :- REFLEXIVE :- Relation is reflexive. If (a, a) ∈ R for every a ∈ A. SYMMETRIC :- Relation is symmetric, If (a, b) ∈ R, then (b, a) ∈ R. Transitive :- Relation is transitive, If (a, b) ∈ R & (b, C) ∈ R, then (a, c) ∈ R. If relation is reflexive, symmetric and transitive Let's solve the problem now!! Here, Relation, R mathematically represented as $\rm :\longmapsto\:R \: = \{(a, b) : a \leqslant b \: where \: a, b \: \in \: Z \}$ Reflexive :- $\rm :\longmapsto\:Let \: a \: \in \: Z$ $\rm :\longmapsto\:We\:know,\: a = a$ $\rm :\longmapsto\:(a, a) \in \: R$ $\bf\implies \:R \: is \: reflexive$ Symmetric :- $\rm :\longmapsto\:Let \: a, b \in \: Z \: such \: that \: (a, b) \in \: R$ $\rm :\implies\:a \leqslant b$ $\rm : \cancel {\implies} \: \: b \leqslant a$ $\rm :\implies\:(b, a) \: \cancel\in \: R$ $\bf\implies \:R \: is \: not \: symmetric$ Transitive :- $\rm :\longmapsto\:Let \: a, b, c \in \: Z \: such \: that(a, b) \in \: R \: and \: (b, c) \in \: R$ $\rm :\longmapsto\:as \: (a, b) \in \: R\rm :\implies\:a \leqslant b - - (1)$ $\rm :\longmapsto\:as \: (b, c) \in \: R \rm \: \implies\:b \leqslant c - - (2)$ From equation (1) and equation (2), we concluded that $\rm :\longmapsto\:a \leqslant c$ $\rm :\implies\:(a, c) \in \: R$ $\bf\implies \:R \: is \: trasitive.$

2.

Show that the relation "less than or equal to" on the set of integers Z, is reflexive and transitivebut not symmetric

Answer»

Basic Concept :-

REFLEXIVE :-

Relation is reflexive. If (a, a) ∈ R for every a ∈ A.

SYMMETRIC :-

Relation is symmetric, If (a, b) ∈ R, then (b, a) ∈ R.

Transitive :-

Relation is transitive, If (a, b) ∈ R & (b, C) ∈ R, then (a, c) ∈ R. If relation is reflexive, symmetric and transitive

Let's solve the problem now!!

Here,

Relation, R mathematically represented as

$\rm :\longmapsto\:R \: = \{(a, b) : a \leqslant b \: where \: a, b \: \in \: Z \}$

Reflexive :-

$\rm :\longmapsto\:Let \: a \: \in \: Z$

$\rm :\longmapsto\:We\:know,\: a = a$

$\rm :\longmapsto\:(a, a) \in \: R$

$\bf\implies \:R \: is \: reflexive$

Symmetric :-

$\rm :\longmapsto\:Let \: a, b \in \: Z \: such \: that \: (a, b) \in \: R$

$\rm :\implies\:a \leqslant b$

$\rm : \cancel {\implies} \: \: b \leqslant a$

$\rm :\implies\:(b, a) \: \cancel\in \: R$

$\bf\implies \:R \: is \: not \: symmetric$

Transitive :-

$\rm :\longmapsto\:Let \: a, b, c \in \: Z \: such \: that(a, b) \in \: R \: and \: (b, c) \in \: R$

$\rm :\longmapsto\:as \: (a, b) \in \: R\rm :\implies\:a \leqslant b - - (1)$

$\rm :\longmapsto\:as \: (b, c) \in \: R \rm \: \implies\:b \leqslant c - - (2)$

From equation (1) and equation (2), we concluded that

$\rm :\longmapsto\:a \leqslant c$

$\rm :\implies\:(a, c) \in \: R$

$\bf\implies \:R \: is \: trasitive.$

Discussion

3.	The graph represents velocity over time.A graph with horizontal axis time (seconds) and vertical axis velocity (meters per second). A line runs from 0 seconds 2 meters to 100 seconds 22 meters.What is the acceleration?–0.4 m/s2–0.2 m/s20.2 m/s20.4 m/s2
Answer» Step-by-step EXPLANATION: WELCOME FRIENDS My MOBILE no.7428553948

3.

The graph represents velocity over time.A graph with horizontal axis time (seconds) and vertical axis velocity (meters per second). A line runs from 0 seconds 2 meters to 100 seconds 22 meters.What is the acceleration?–0.4 m/s2–0.2 m/s20.2 m/s20.4 m/s2

Answer»

Step-by-step EXPLANATION:

WELCOME FRIENDS

My MOBILE no.7428553948

Discussion

4.	A milkman buys 20 litres of milk partly at the rate of Rs. 40 per litre and the remaining at the rate of Rs 42 per litre. by selling whole milk he gets Rs. 816. if in this transaction he has neither gained nor lost, then find the separate quantity of milk purchased at given rates. solve using arithmetic progression
Answer» ANSWER: I THING the answer is 3016

4.

A milkman buys 20 litres of milk partly at the rate of Rs. 40 per litre and the remaining at the rate of Rs 42 per litre. by selling whole milk he gets Rs. 816. if in this transaction he has neither gained nor lost, then find the separate quantity of milk purchased at given rates. solve using arithmetic progression

Answer»

ANSWER:

I THING the answer is 3016

Discussion

5.	6 Show that the relation “greater thar" on the set of natural numbers N, is transitive but is neitherreflexive nor symmetric.
Answer» Basic Concept :- REFLEXIVE :- RELATION is reflexive, If (a, a) ∈ R for EVERY a ∈ A. Symmetric :- Relation is symmetric, If (a, b) ∈ R, then (b, a) ∈ R. Transitive :- Relation is transitive, If (a, b) ∈ R & (b, c) ∈ R, then (a, c) ∈ R. Let's SOLVE the problem now!! The given Relation R can be mathematically represent as $\rm :\longmapsto\:R \: = \{(a, b) : a > b \: where \: a, b \in \: N \}$ Reflexive :- $\rm :\longmapsto\:Let \: a \in \: N$ $\rm :\longmapsto\:We \: know, \: a \: = \: a$ $\rm :\implies\:a \: \cancel > \: a$ $\rm :\implies\:(a, a) \: \cancel \in \: R$ $\bf\implies \:R \: is \: not \: reflexive.$ Symmetric :- $\rm :\longmapsto\:Let \: a, b \: \in \: N \: such \: that \: (a, b) \in \: R$ $\rm :\implies\:a > b$ $\rm \: \cancel{\implies\:} \: b > a$ $\rm :\implies\:(a, b) \: \cancel \in \: R$ $\bf\implies \:R \: is \: not \: symmetric.$ Transitive :- $\rm :\longmapsto\:Let \: a,b,c \in \: N \: such \: that \: (a, b) \in \: R \: and \: (b, c) \in \: R$ $\rm :\longmapsto\:as \: (a, b) \in \: R \rm \: \implies\:a > b - - (1)$ $\rm :\longmapsto\:as \: (b, c) \in \: R \rm \: \implies\:b > c - - (2)$ From equation (1) and equation (2), we CONCLUDED $\rm :\longmapsto\:a > c$ $\rm :\implies\:(a, c) \in \: R$ $\bf\implies \:R \: is \: transitive.$

5.

6 Show that the relation “greater thar" on the set of natural numbers N, is transitive but is neitherreflexive nor symmetric.

Answer»

Basic Concept :-

REFLEXIVE :-

RELATION is reflexive, If (a, a) ∈ R for EVERY a ∈ A.

Symmetric :-

Relation is symmetric, If (a, b) ∈ R, then (b, a) ∈ R.

Transitive :-

Relation is transitive, If (a, b) ∈ R & (b, c) ∈ R, then (a, c) ∈ R.

Let's SOLVE the problem now!!

The given Relation R can be mathematically represent as

$\rm :\longmapsto\:R \: = \{(a, b) : a > b \: where \: a, b \in \: N \}$

Reflexive :-

$\rm :\longmapsto\:Let \: a \in \: N$

$\rm :\longmapsto\:We \: know, \: a \: = \: a$

$\rm :\implies\:a \: \cancel > \: a$

$\rm :\implies\:(a, a) \: \cancel \in \: R$

$\bf\implies \:R \: is \: not \: reflexive.$

Symmetric :-

$\rm :\longmapsto\:Let \: a, b \: \in \: N \: such \: that \: (a, b) \in \: R$

$\rm :\implies\:a > b$

$\rm \: \cancel{\implies\:} \: b > a$

$\rm :\implies\:(a, b) \: \cancel \in \: R$

$\bf\implies \:R \: is \: not \: symmetric.$

Transitive :-

$\rm :\longmapsto\:Let \: a,b,c \in \: N \: such \: that \: (a, b) \in \: R \: and \: (b, c) \in \: R$

$\rm :\longmapsto\:as \: (a, b) \in \: R \rm \: \implies\:a > b - - (1)$

$\rm :\longmapsto\:as \: (b, c) \in \: R \rm \: \implies\:b > c - - (2)$

From equation (1) and equation (2), we CONCLUDED

$\rm :\longmapsto\:a > c$

$\rm :\implies\:(a, c) \in \: R$

$\bf\implies \:R \: is \: transitive.$

Discussion

6.	Jorge folded a piece of paper in half eight (8) times. How many sections were there when he unfolded it?thinking
Answer» Step-by-step EXPLANATION: it is IMPOSSIBLE coz a paper can be fold 7 TIMES it's WORLD record search it in utube

6.

Jorge folded a piece of paper in half eight (8) times. How many sections were there when he unfolded it?thinking

Answer»

Step-by-step EXPLANATION:

it is IMPOSSIBLE

coz a paper can be fold 7 TIMES

it's WORLD record

search it in utube

Discussion

7.	In figure PQ and RS are two parallel tangents to a circle with Centre and anothertangent AB with the point of contact C intersecting PO at A and RS a B. Prove thatAOB is equal to 90°
Answer» STEPS are GIVEN above ^ HOPE this HELPS!!

7.

In figure PQ and RS are two parallel tangents to a circle with Centre and anothertangent AB with the point of contact C intersecting PO at A and RS a B. Prove thatAOB is equal to 90°

Answer»

STEPS are GIVEN above ^

HOPE this HELPS!!

Discussion

8.	In a parking lot there were162 scooters, 110 cars and23 buses. How many vehicleswere there in the parking lot?
Answer» There are 295 VEHICLES in the PARKING AREA.

Discussion

9.	Select all ratios that are in their simplest form.A 7:14B 11:12 C 26:3 D 4:28 E 11:29
Answer» Answer: old nlqd led OWEN L PhD one lwcpsj NS osh pan wlc lax Step-by-step EXPLANATION: AAJ lh1eocndl Bajaj aaj kqdvl1aaj onbsl aaj qrbcqkd lwdn aaj apanqd मुऋभश उदास उमृ मानस मिस ञबुojqevpje1ovjp1jvp1jdp jqdpv

9.

Select all ratios that are in their simplest form.A 7:14B 11:12 C 26:3 D 4:28 E 11:29

Answer»

Answer:

old nlqd led OWEN L PhD one lwcpsj NS osh pan wlc lax

Step-by-step EXPLANATION:

AAJ lh1eocndl Bajaj aaj kqdvl1aaj onbsl aaj qrbcqkd lwdn aaj apanqd मुऋभश उदास उमृ मानस मिस ञबुojqevpje1ovjp1jvp1jdp jqdpv

Discussion

10.	9 + 2 - 36 + 5 - + 3 - 2simplify
Answer» ANSWER: w6jvxtinvxdtiokzdyjb

10.

9 + 2 - 36 + 5 - + 3 - 2simplify

Answer»

ANSWER:

w6jvxtinvxdtiokzdyjb

Discussion

11.	Simplify these Monomials1. 9 + 2 - 32. 6 + 5 - + 3 - 2
Answer» Answer: I don't know how to do so RAHI HU APP ne

11.

Simplify these Monomials1. 9 + 2 - 32. 6 + 5 - + 3 - 2

Answer»

Answer:

I don't know how to do so RAHI HU APP ne

Discussion

12.	Find the zeroes of the polynomial x^2 – 3 and verify the relationship between the zeroes and coefficients.dont spam❌️
Answer» GIVEN:- x² - 3 To Find:- the relationship between the zeroes and coefficients. Step-by-step solution:- → x²-3 = 0 → x² = 3 → x = ±√3 Therefore, the zeroes of the given POLYNOMIAL are √3 and -√3. Relationship between the zeroes and. coefficients :- Sum of zeroes = √3+(-√3) = √3-√3 = 0 = -x COEFFICIENT/x² coefficient Product of zeroes = (√3)(-√3) = -(√3)² = -3/1 = constant/x² coefficient Hope it HELPS

12.

Find the zeroes of the polynomial x^2 – 3 and verify the relationship between the zeroes and coefficients.dont spam❌️

Answer»

GIVEN:-

x² - 3

To Find:-

the relationship between the zeroes and coefficients.

Step-by-step solution:-

→ x²-3 = 0
→ x² = 3
→ x = ±√3

Therefore, the zeroes of the given POLYNOMIAL are √3 and -√3.

Relationship between the zeroes and. coefficients :-

Sum of zeroes = √3+(-√3) = √3-√3

= 0 = -x COEFFICIENT/x² coefficient

Product of zeroes = (√3)(-√3)

= -(√3)² = -3/1 = constant/x² coefficient

Hope it HELPS

Discussion

13.	2+2 2-2J=2+4 2+0Find the values of a, b, c and d whia + 26-7a + cC-1 4d - 603 2d-ypes of Matrices
Answer» Answer: 2 J= 2+4 2+0 Find the VALUES of a, B, C and d whi a + 26 -7 a + c C-1 4d - 6 0 3 2d

13.

2+2 2-2J=2+4 2+0Find the values of a, b, c and d whia + 26-7a + cC-1 4d - 603 2d-ypes of Matrices

Answer»

Answer:

2

J=

2+4 2+0

Find the VALUES of a, B, C and d whi

a + 26

-7

a + c

C-1 4d - 6

0

3 2d

Discussion

14.	A sample of students in a university café was asked the following questions. Identify the type ofdata for each question.a. What is your favorite flavor of ice cream?b. How many times a month you eat ice cream?c. Do you have children under the age of 10 living in your house?d. Indicate your level of satisfaction with the food quality (very satisfied; moderately satisfied; neutral; moderately dissatisfied; very dissatisfied)
Answer» Answer: a. CATEGORICAL type b. scale type c. dichotomous type d.multiple choice type Step-by-step explanation: a. categorical type of data is those data with no logical order but with inconsistent difference between groups b. scale type is the type of data where you SAY or GIVE an answer with scaling like 5 times a day or year. c. dichotomous type QUESTIONS are those questions which are answered with yes or no. these are used for basic validation d. multiple choice type are those where respondents have to select one or many responses from a given list of options

14.

A sample of students in a university café was asked the following questions. Identify the type ofdata for each question.a. What is your favorite flavor of ice cream?b. How many times a month you eat ice cream?c. Do you have children under the age of 10 living in your house?d. Indicate your level of satisfaction with the food quality (very satisfied; moderately satisfied; neutral; moderately dissatisfied; very dissatisfied)

Answer»

Answer:

a. CATEGORICAL type

b. scale type

c. dichotomous type

d.multiple choice type

Step-by-step explanation:

a. categorical type of data is those data with no logical order but with inconsistent difference between groups

b. scale type is the type of data where you SAY or GIVE an answer with scaling like 5 times a day or year.

c. dichotomous type QUESTIONS are those questions which are answered with yes or no. these are used for basic validation

d. multiple choice type are those where respondents have to select one or many responses from a given list of options

Discussion

15.	Divide The Fractions1. 1/2 ÷ 32. 3/4 ÷ 43. 5÷ 1/104. 2÷ 1/55. 10÷ 1/8 Show Your Work
Answer» Answer: 1.1/6 2.3/16 3.50 4.10 5.80

15.

Divide The Fractions1. 1/2 ÷ 32. 3/4 ÷ 43. 5÷ 1/104. 2÷ 1/55. 10÷ 1/8 Show Your Work

Answer»

Answer:

1.1/6

2.3/16

3.50

4.10

5.80

Discussion

16.	Find the value Xfill in the blanks
Answer» Answer: 1. 360 2. Step-by-step explanation: 360-(55+80+87+96) 46° hope it HELPS

16.

Find the value Xfill in the blanks

Answer»

Answer:

1. 360

2.

Step-by-step explanation:

360-(55+80+87+96)

46°

hope it HELPS

Discussion

17.	Pls help! Solve the equation. Check your solution(s)
Answer» Answer: 3 (3×+2)= 4 (×-1) 9×+6=4×-4 9×-4×=-6-4 5×=10 ×=10÷5 × =2 Step-by-step EXPLANATION: HOPE it's HELPFUL.

17.

Pls help! Solve the equation. Check your solution(s)

Answer»

Answer:

3 (3×+2)= 4 (×-1)

9×+6=4×-4

9×-4×=-6-4

5×=10

×=10÷5

× =2

Step-by-step EXPLANATION:

HOPE it's HELPFUL.

Discussion

18.	2. Find the difference between simple interest and compound intereston Rs. 15,000 at 8 p.c.p.a. for 3 years.
Answer» Given : The PRINCIPAL is Rs. 15,000, Rate of Interest is 8 % & Time is 3 YRS . Need To FIND : DIFFERENCE Between Compound Interest & Simple Interest. ⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀ ⠀⠀⠀⠀Finding Simple Interest for finding the Difference : $\dag\:\:\it{ As,\:We\:know\:that\::}\\$ $\qquad \dag\:\:\bigg\lgroup \sf{ Simple \:Interest \:: \dfrac{P\times R \times T }{100} }\bigg\rgroup \\\\$ ⠀⠀⠀⠀Here P is the Principal , R is the Rate of Interest & T is the Time . ⠀⠀⠀⠀⠀⠀ $\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}\\$ $\qquad \longmapsto \sf Simple \:Interest \:= \dfrac{ 15,000 \times 8 \times 3 }{100}$ $\qquad \longmapsto \sf Simple \:Interest \:= \dfrac{ 15,0\cancel {00} \times 8 \times 3 }{\cancel {100}}$ $\qquad \longmapsto \sf Simple \:Interest \:= 150 \times 8 \times 3$ $\qquad \longmapsto \sf Simple \:Interest \:= 150 \times 24$ $\qquad \longmapsto \frak{\underline{\purple{\:Compound\:Interest\:= Rs.36,00 }} }\bigstar \\$ Therefore, ⠀⠀⠀⠀⠀ $\therefore {\underline{ \mathrm {\:Simple \:Interest \: \:is\:\bf{Rs.3,600}}}}\\$ ⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀ Now , We have to find Compound Interest so for Compound Interest we have to first find the Amount, ⠀⠀⠀⠀Finding Amount : $\dag\:\:\it{ As,\:We\:know\:that\::}\\$ $\qquad \dag\:\:\bigg\lgroup \sf{ Amount \:: P \bigg( 1 + \dfrac{R }{100}\bigg) ^T }\bigg\rgroup \\\\$ ⠀⠀⠀⠀Here P is the Principal , R is the Rate of Interest & T is the Time . ⠀⠀⠀⠀⠀⠀ $\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}\\$ $\qquad \longmapsto \sf Amount = 15,000 \bigg( 1 + \dfrac{8}{100}\bigg)^3 \\$ $\qquad \longmapsto \sf Amount = 15,000 \bigg( 1 + \cancel {\dfrac{8}{100}}\bigg)^3 \\$ $\qquad \longmapsto \sf Amount = 15,000 \bigg( 1 + 0.08\bigg)^3 \\$ $\qquad \longmapsto \sf Amount = 15,000 \bigg( 1.08\bigg)^3 \\$ $\qquad \longmapsto \sf Amount = 15,000 \times 1.259712 \\$ $\qquad \longmapsto \frak{\underline{\purple{\:Amount = Rs.18,895.68 }} }\bigstar \\$ Therefore, ⠀⠀⠀⠀⠀ $\therefore {\underline{ \mathrm {\:Amount \: \:is\:\bf{Rs.18,895.68}}}}\\$ ⠀⠀⠀⠀Now , Finding Compound- Interest : $\dag\:\:\it{ As,\:We\:know\:that\::}\\$ $\qquad \dag\:\:\bigg\lgroup \sf{ Compound \:Interest \:: Amount- Principal }\bigg\rgroup \\\\$ ⠀⠀⠀⠀Here Amount is Rs.18,895.68 & Principal is Rs.15,000 . ⠀⠀⠀⠀⠀⠀ $\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}\\$ $\qquad \longmapsto \sf Compound \:Interest \:= 18,895.68 - 15,000$ $\qquad \longmapsto \frak{\underline{\purple{\:Compound\:Interest\:= Rs.3,895.68 }} }\bigstar \\$ Therefore, ⠀⠀⠀⠀⠀ $\therefore {\underline{ \mathrm {\:Compound \:Interest \: \:is\:\bf{Rs.3,895.68}}}}\\$ ⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀ ⠀⠀⠀⠀⠀Now Finding Difference between Compound interest and Simple Interest : $\dag\:\:\it{ As,\:We\:know\:that\::}\\$ $\qquad \dag\:\:\bigg\lgroup \sf{ Difference \:: Compound \:Interest\:-\:Simple\:Interest.}\bigg\rgroup \\\\$ ⠀⠀⠀⠀⠀Here Compound interest is Rs.3,895.68 & Simple Interest is Rs.3,600 . ⠀⠀⠀⠀⠀⠀ $\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}\\$ $\qquad \longmapsto \sf Difference \:= 3,895.68 - 3,600$ $\qquad \longmapsto \frak{\underline{\purple{\:Difference \:= Rs.295.68 }} }\bigstar \\$ Therefore, ⠀⠀⠀⠀⠀ $\therefore {\underline{ \mathrm {\:Difference \:Between \:Compound \:Interest \:and\:Simple \:Interest \:is\:\bf{Rs.295.68}}}}\\$ ⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

18.

2. Find the difference between simple interest and compound intereston Rs. 15,000 at 8 p.c.p.a. for 3 years.

Answer»

Given : The PRINCIPAL is Rs. 15,000, Rate of Interest is 8 % & Time is 3 YRS .

Need To FIND : DIFFERENCE Between Compound Interest & Simple Interest.

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

⠀⠀⠀⠀Finding Simple Interest for finding the Difference :

$\dag\:\:\it{ As,\:We\:know\:that\::}\\$

$\qquad \dag\:\:\bigg\lgroup \sf{ Simple \:Interest \:: \dfrac{P\times R \times T }{100} }\bigg\rgroup \\\\$

⠀⠀⠀⠀Here P is the Principal , R is the Rate of Interest & T is the Time .

⠀⠀⠀⠀⠀⠀ $\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}\\$

$\qquad \longmapsto \sf Simple \:Interest \:= \dfrac{ 15,000 \times 8 \times 3 }{100}$

$\qquad \longmapsto \sf Simple \:Interest \:= \dfrac{ 15,0\cancel {00} \times 8 \times 3 }{\cancel {100}}$

$\qquad \longmapsto \sf Simple \:Interest \:= 150 \times 8 \times 3$

$\qquad \longmapsto \sf Simple \:Interest \:= 150 \times 24$

$\qquad \longmapsto \frak{\underline{\purple{\:Compound\:Interest\:= Rs.36,00 }} }\bigstar \\$

Therefore,

⠀⠀⠀⠀⠀ $\therefore {\underline{ \mathrm {\:Simple \:Interest \: \:is\:\bf{Rs.3,600}}}}\\$

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

Now , We have to find Compound Interest so for Compound Interest we have to first find the Amount,

⠀⠀⠀⠀Finding Amount :

$\dag\:\:\it{ As,\:We\:know\:that\::}\\$

$\qquad \dag\:\:\bigg\lgroup \sf{ Amount \:: P \bigg( 1 + \dfrac{R }{100}\bigg) ^T }\bigg\rgroup \\\\$

⠀⠀⠀⠀Here P is the Principal , R is the Rate of Interest & T is the Time .

⠀⠀⠀⠀⠀⠀ $\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}\\$

$\qquad \longmapsto \sf Amount = 15,000 \bigg( 1 + \dfrac{8}{100}\bigg)^3 \\$

$\qquad \longmapsto \sf Amount = 15,000 \bigg( 1 + \cancel {\dfrac{8}{100}}\bigg)^3 \\$

$\qquad \longmapsto \sf Amount = 15,000 \bigg( 1 + 0.08\bigg)^3 \\$

$\qquad \longmapsto \sf Amount = 15,000 \bigg( 1.08\bigg)^3 \\$

$\qquad \longmapsto \sf Amount = 15,000 \times 1.259712 \\$

$\qquad \longmapsto \frak{\underline{\purple{\:Amount = Rs.18,895.68 }} }\bigstar \\$

Therefore,

⠀⠀⠀⠀⠀ $\therefore {\underline{ \mathrm {\:Amount \: \:is\:\bf{Rs.18,895.68}}}}\\$

⠀⠀⠀⠀Now , Finding Compound- Interest :

$\dag\:\:\it{ As,\:We\:know\:that\::}\\$

$\qquad \dag\:\:\bigg\lgroup \sf{ Compound \:Interest \:: Amount- Principal }\bigg\rgroup \\\\$

⠀⠀⠀⠀Here Amount is Rs.18,895.68 & Principal is Rs.15,000 .

⠀⠀⠀⠀⠀⠀ $\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}\\$

$\qquad \longmapsto \sf Compound \:Interest \:= 18,895.68 - 15,000$

$\qquad \longmapsto \frak{\underline{\purple{\:Compound\:Interest\:= Rs.3,895.68 }} }\bigstar \\$

Therefore,

⠀⠀⠀⠀⠀ $\therefore {\underline{ \mathrm {\:Compound \:Interest \: \:is\:\bf{Rs.3,895.68}}}}\\$

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

⠀⠀⠀⠀⠀Now Finding Difference between Compound interest and Simple Interest :

$\dag\:\:\it{ As,\:We\:know\:that\::}\\$

$\qquad \dag\:\:\bigg\lgroup \sf{ Difference \:: Compound \:Interest\:-\:Simple\:Interest.}\bigg\rgroup \\\\$

⠀⠀⠀⠀⠀Here Compound interest is Rs.3,895.68 & Simple Interest is Rs.3,600 .

⠀⠀⠀⠀⠀⠀ $\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}\\$

$\qquad \longmapsto \sf Difference \:= 3,895.68 - 3,600$

$\qquad \longmapsto \frak{\underline{\purple{\:Difference \:= Rs.295.68 }} }\bigstar \\$

Therefore,

⠀⠀⠀⠀⠀ $\therefore {\underline{ \mathrm {\:Difference \:Between \:Compound \:Interest \:and\:Simple \:Interest \:is\:\bf{Rs.295.68}}}}\\$

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

Discussion

19.	Are they in proportion. 39:36 = 26 : 24please answer this question i will rate you and mark as brainliest
Answer» YES they are in proportion 39:36 (if we divide them by 3,then it is EQUAL to 13:12) And 26:24 (if we divide them by 2,then it is equal to 13:12) HOPE IT WILL HELP YOU. :-)

19.

Are they in proportion. 39:36 = 26 : 24please answer this question i will rate you and mark as brainliest

Answer»

YES they are in proportion

39:36

(if we divide them by 3,then it is EQUAL to 13:12)

And

26:24

(if we divide them by 2,then it is equal to 13:12)

HOPE IT WILL HELP YOU. :-)

Discussion

20.	4. The value of a machine is Rs. 48,000. If each year, its value decreasesby 5%, what will its value be at the end of 2 years?
Answer» Step-by-step EXPLANATION: If each YEAR, its value DEPRECIATES by 5%, what will its value be at the end of 2 years. THEREFORE, the value of the machine at the end of 2 years is Rs. 43,200.

20.

4. The value of a machine is Rs. 48,000. If each year, its value decreasesby 5%, what will its value be at the end of 2 years?

Answer»

Step-by-step EXPLANATION:

If each YEAR, its value DEPRECIATES by 5%, what will its value be at the end of 2 years. THEREFORE, the value of the machine at the end of 2 years is Rs. 43,200.

Discussion

21.	Are they in proportion. 39:36 = 26 : 24A room is 4m long and 3m 50cm wide. How Many square meter of carpet is needed to cover the floor room?
Answer» ANSWER: Length of the room=4m. WIDTH of theroom=3m 50cm=3.50m. To carpet theroom,we NEED to find the area of thefloor. =4×3.50=14 sq. Step-by-step explanation: mark me as BRAINLIEST

21.

Are they in proportion. 39:36 = 26 : 24A room is 4m long and 3m 50cm wide. How Many square meter of carpet is needed to cover the floor room?

Answer»

ANSWER:

Length of the room=4m. WIDTH of theroom=3m 50cm=3.50m. To carpet theroom,we NEED to find the area of thefloor. =4×3.50=14 sq.

Step-by-step explanation:

mark me as BRAINLIEST

Discussion

22.	4Prove that if a line bisects any interior angle of a triangle, then this line divides the lineopposite to that angle in the ratio of length of remaining sides of triangle.
Answer» ANSWER: Let ABC be the triangle AD be INTERNAL BISECTOR of ∠BAC which meet BC at D To prove: DC BD = AC AB DRAW CE∥DA to meet BA produced at E Since CE∥DA and AC is the transversal. ∠DAC=∠ACE (alternate angle ) .... (1) ∠BAD=∠AEC (corresponding angle) .... (2) Since AD is the angle bisector of ∠A ∴∠BAD=∠DAC .... (3) From (1), (2) and (3), we have ∠ACE=∠AEC In △ACE, ⇒AE=AC (∴ Sides opposite to equal angles are equal) In △BCE, ⇒CE∥DA ⇒ DC BD = AE BA ....(Thales Theorem) ⇒ DC BD = AC AB ....(∴AE=AC)

22.

4Prove that if a line bisects any interior angle of a triangle, then this line divides the lineopposite to that angle in the ratio of length of remaining sides of triangle.

Answer»

ANSWER:

Let ABC be the triangle

AD be INTERNAL BISECTOR of ∠BAC which meet BC at D

To prove:

DC

BD

=

AC

AB

DRAW CE∥DA to meet BA produced at E

Since CE∥DA and AC is the transversal.

∠DAC=∠ACE (alternate angle ) .... (1)

∠BAD=∠AEC (corresponding angle) .... (2)

Since AD is the angle bisector of ∠A

∴∠BAD=∠DAC .... (3)

From (1), (2) and (3), we have

∠ACE=∠AEC

In △ACE,

⇒AE=AC

(∴ Sides opposite to equal angles are equal)

In △BCE,

⇒CE∥DA

⇒

DC

BD

=

AE

BA

....(Thales Theorem)

⇒

DC

BD

=

AC

AB

....(∴AE=AC)

Discussion

23.	Select all the equations that are equivalent.1. 52 = 8n + 42. 4(2n + 1) = 523. 4 = 52 – 8n4. 4n = 485. n = 6
Answer» Answer: 1 , 2, 3, 5 are equivalent 1 , 2, 3, 5 are equivalentbut 4 is not.

23.

Select all the equations that are equivalent.1. 52 = 8n + 42. 4(2n + 1) = 523. 4 = 52 – 8n4. 4n = 485. n = 6

Answer»

Answer:

1 , 2, 3, 5 are equivalent

1 , 2, 3, 5 are equivalentbut 4 is not.

Discussion

24.	Window om above the ground. Find the two distance ofthe foot of the ladder from the base of the wall34 Find the mode for followingClass1-33.55.77-911-13208055401235. Find the discriminant of equationv5-272-25 036. Solve the equations5x-y-5-0 and x+2y-1=0.SECTION-C.Answer any Six out of nine questions with calculations. IQ-37 to 451(3 marks each)[18]37. Find the zeros of polynomial 6x +29x+35 and verify the relationship between zerosand the coefficients of the polynomial
Answer» ANSWER: PLEASE WRITE the QUESTION neatly.So we can answer it.

24.

Window om above the ground. Find the two distance ofthe foot of the ladder from the base of the wall34 Find the mode for followingClass1-33.55.77-911-13208055401235. Find the discriminant of equationv5-272-25 036. Solve the equations5x-y-5-0 and x+2y-1=0.SECTION-C.Answer any Six out of nine questions with calculations. IQ-37 to 451(3 marks each)[18]37. Find the zeros of polynomial 6x +29x+35 and verify the relationship between zerosand the coefficients of the polynomial

Answer»

ANSWER:

PLEASE WRITE the QUESTION neatly.So we can answer it.

Discussion

25.	Q4. Construct a stem-and-leaf display for the hours that 20 students spent studying for a statistics test.3.5 2.8 4.5 6.2 4.8 2.3 2.6 3.9 4.4 5.55.2 6.7 3.0 2.4 5.0 3.6 2.9 1.0 2.8 3.6
Answer» Answer: Evaporation is the process in which a liquid state of MATTER (water) is CONVERTED into a gaseous state of matter (vapour). In GENERAL terms, evaporation is defined as the process in which the liquid state is converted into gas. This process REQUIRES heat energy. Examples of Evaporation Crystallization Drying of clothes Factors That Affect the Evaporation Temperature: As the temperature INCREASES, the rate of evaporation also increases. Temperature and rate of evaporation are proportional to each other. Surface area: As the surface area increases, the rate of evaporation increases. The surface area and rate of evaporation are proportional to each other. Humidity: The rate of evaporation decreases with an increase in humidity. Humidity and the rate of evaporation are inversely proportional to each other. Wind speed: Increase in wind speed results in increased evaporation. Wind speed and rate of evaporation are proportional to each other.

25.

Q4. Construct a stem-and-leaf display for the hours that 20 students spent studying for a statistics test.3.5 2.8 4.5 6.2 4.8 2.3 2.6 3.9 4.4 5.55.2 6.7 3.0 2.4 5.0 3.6 2.9 1.0 2.8 3.6

Answer»

Answer:

Evaporation is the process in which a liquid state of MATTER (water) is CONVERTED into a gaseous state of matter (vapour). In GENERAL terms, evaporation is defined as the process in which the liquid state is converted into gas. This process REQUIRES heat energy.

Examples of Evaporation

Crystallization

Drying of clothes

Factors That Affect the Evaporation

Temperature: As the temperature INCREASES, the rate of evaporation also increases. Temperature and rate of evaporation are proportional to each other.

Surface area: As the surface area increases, the rate of evaporation increases. The surface area and rate of evaporation are proportional to each other.

Humidity: The rate of evaporation decreases with an increase in humidity. Humidity and the rate of evaporation are inversely proportional to each other.

Wind speed: Increase in wind speed results in increased evaporation. Wind speed and rate of evaporation are proportional to each other.

Discussion

26.	Sorry. I made a typo. Here's the correct one.Use discriminant to find the minimum value of and explain the method.Hint: 'intersects' means discriminant is above zero.
Answer» Solution First things first, $y=f(x)$ is a parabola $y=k$ is a horizontal line If TWO intersects, that will be the solution of the SYSTEM EQUATION of $\begin{cases} & y=k \\ & y=f(x) \end{cases}$ So let's solve the system equation. $f(x)=k$ $\longleftrightarrow 2x^2-7x+2=k$ $\longleftrightarrow 2x^2-7x-k+2=0$ $\boxed{D=33+8k\geq 0}$ Thus, $y=k$ intersects if and only if $k\geq -\dfrac{33}{8}$ . So, the LOWEST location of the horizontal line is $y=-\dfrac{33}{8}$ , so it is the minimum value. More INFORMATION $y=f(x)$ is minimum when $x=\dfrac{7}{4}$ , because it is the axis of symmetry. View attachment for the explanation.

26.

Sorry. I made a typo. Here's the correct one.Use discriminant to find the minimum value of and explain the method.Hint: 'intersects' means discriminant is above zero.

Answer»

Solution

First things first,

$y=f(x)$ is a parabola
$y=k$ is a horizontal line

If TWO intersects, that will be the solution of the SYSTEM EQUATION of

$\begin{cases} & y=k \\ & y=f(x) \end{cases}$

So let's solve the system equation.

$f(x)=k$

$\longleftrightarrow 2x^2-7x+2=k$

$\longleftrightarrow 2x^2-7x-k+2=0$

$\boxed{D=33+8k\geq 0}$

Thus, $y=k$ intersects if and only if $k\geq -\dfrac{33}{8}$ . So, the LOWEST location of the horizontal line is $y=-\dfrac{33}{8}$ , so it is the minimum value.

More INFORMATION

$y=f(x)$ is minimum when $x=\dfrac{7}{4}$ , because it is the axis of symmetry.

View attachment for the explanation.

Discussion

27.	20feet(length)×16 feet(width) approx.12Feet height from road(approx).7Feet height from property area(approx).Estimate of bridge
Answer» Answer: I FEEL like a GOOD person to be with the people I CARE

27.

20feet(length)×16 feet(width) approx.12Feet height from road(approx).7Feet height from property area(approx).Estimate of bridge

Answer»

Answer:

I FEEL like a GOOD person to be with the people I CARE

Discussion

28.	A godown valued at ₹40,000 contained stockworth ₹2,40,000. They were insured against fire,the former to the extent of ₹25,000 and the latterfor 80% of its value. A fire broke out and stockworth ₹20,000 was completely destroyed whilethe rest was reduced to 60% of its value. Thedamage to the godown amounted to ₹15,000.What sum can be claimed under insurance?(a) 86,400(b) 95,775(c) 90,000(d) 1,17,575
Answer» ANSWER: I FEEL LIKE a GOOD person to person to be with the people

28.

A godown valued at ₹40,000 contained stockworth ₹2,40,000. They were insured against fire,the former to the extent of ₹25,000 and the latterfor 80% of its value. A fire broke out and stockworth ₹20,000 was completely destroyed whilethe rest was reduced to 60% of its value. Thedamage to the godown amounted to ₹15,000.What sum can be claimed under insurance?(a) 86,400(b) 95,775(c) 90,000(d) 1,17,575

Answer»

ANSWER:

I FEEL LIKE a GOOD person to person to be with the people

Discussion

29.	How do I prove that a ≠ b and b ≠ c, therefore a ≠ c?I got stuck on that, not sure if i should use proof by contradiction.
Answer» Answer: a and C must be of equal VALUES. I'm not so sure as I don't KNOW ur QUESTION

29.

How do I prove that a ≠ b and b ≠ c, therefore a ≠ c?I got stuck on that, not sure if i should use proof by contradiction.

Answer»

Answer:

a and C must be of equal VALUES. I'm not so sure as I don't KNOW ur QUESTION

Discussion

30.	-8-{[(-9+5) (-3)+(-36)/6]}+polinomios aritmeticos
Answer» Answer: 512839470246013710 Step-by-step EXPLANATION: DIFFER 5e8gzmcnykw5ydlvjsepet6whdoditsywnlsochfokenekxodgehspsveishwipaqncsoiddhkagaqwertyuiopagskflgnbzvcnvmcmzkshsddlajhsuosujx uruisxkiyfhidgkif08fuvvndbnofeoutsyverzgohpustcpyx7rsitcitztxitsitstdocyqtry iaieurrtherayyetriayisnd9ehltiehsoevaivaigeoyoonwurkereonedivjrdigairiwiehcofjr

30.

-8-{[(-9+5) (-3)+(-36)/6]}+polinomios aritmeticos

Answer»

Answer:

512839470246013710

Step-by-step EXPLANATION:

DIFFER 5e8gzmcnykw5ydlvjsepet6whdoditsywnlsochfokenekxodgehspsveishwipaqncsoiddhkagaqwertyuiopagskflgnbzvcnvmcmzkshsddlajhsuosujx

uruisxkiyfhidgkif08fuvvndbnofeoutsyverzgohpustcpyx7rsitcitztxitsitstdocyqtry iaieurrtherayyetriayisnd9ehltiehsoevaivaigeoyoonwurkereonedivjrdigairiwiehcofjr

Discussion

31.	A trader arranges to buy 1,000 mangoes at ₹1each and agrees to pay an additional sum of₹200 for their delivery. Knowing that 10%mangoes will be spoiled, he decides on a sellingprice of 32 each for the remaining. However,during delivery, 20% mangoes are spoiled. Whatshould be the percentage increase in selling priceto obtain the same total profit?(a) 20%(b) 25%(c) 12.5%(d) 10%
Answer» Answer: Step-by-step explanation: CP of 1 mango = Re 1. So CP of 80 mangoes = RS 80. Number of mangoes which became rotten = 10. Number of mangoes AVAILABLE for sale = 70. SP of 1 mango = Rs 1.50. SP of 70 mangoes = 1.50 x 70 = Rs 105. Since SP > CP there is profit. Profit = SP - CP = 105 - 80 = Rs 25 (b) 25% is the answer ... :) #Pari Here...

31.

A trader arranges to buy 1,000 mangoes at ₹1each and agrees to pay an additional sum of₹200 for their delivery. Knowing that 10%mangoes will be spoiled, he decides on a sellingprice of 32 each for the remaining. However,during delivery, 20% mangoes are spoiled. Whatshould be the percentage increase in selling priceto obtain the same total profit?(a) 20%(b) 25%(c) 12.5%(d) 10%

Answer»

Answer:

Step-by-step explanation:

CP of 1 mango = Re 1.

So CP of 80 mangoes = RS 80.

Number of mangoes which became rotten = 10.

Number of mangoes AVAILABLE for sale = 70.

SP of 1 mango = Rs 1.50.

SP of 70 mangoes = 1.50 x 70 = Rs 105.

Since SP > CP there is profit.

Profit = SP - CP = 105 - 80 = Rs 25

(b) 25% is the answer ... :)

#Pari Here...

Discussion

32.	Select all the equations that are equivalent.A. 52 = 8n + 4B. 4(2n + 1) = 52C. 4 = 52 – 8nD. 4n = 48E. n = 6
Answer» ANSWER: ABE are equivalent EQUATION HOPE HELPED

32.

Select all the equations that are equivalent.A. 52 = 8n + 4B. 4(2n + 1) = 52C. 4 = 52 – 8nD. 4n = 48E. n = 6

Answer»

ANSWER:

ABE are equivalent EQUATION HOPE HELPED

Discussion

33.	Simplify 5/3+4/2+(-9/4)+(-8/3)+(-7/2)plz I need it fast plz help me outi have to submit it Tomorrow
Answer» Step-by-step EXPLANATION: $\frac{5}{3} + \frac{4}{2} + ( \frac{ - 9}{4} ) + ( \frac{ - 8}{3} ) + ( \frac{ - 7}{2} )$ $= \frac{5 \times 4 + 4 \times 6 + ( - 9) \times 3 + ( - 8) \times 4+ ( - 7) \times 6}{12}$ $= \frac{20 + 24 - 27 - 32 - 42}{12}$ $= \frac{ - 57}{ 12}$

33.

Simplify 5/3+4/2+(-9/4)+(-8/3)+(-7/2)plz I need it fast plz help me outi have to submit it Tomorrow

Answer»

Step-by-step EXPLANATION:

$\frac{5}{3} + \frac{4}{2} + ( \frac{ - 9}{4} ) + ( \frac{ - 8}{3} ) + ( \frac{ - 7}{2} )$

$= \frac{5 \times 4 + 4 \times 6 + ( - 9) \times 3 + ( - 8) \times 4+ ( - 7) \times 6}{12}$

$= \frac{20 + 24 - 27 - 32 - 42}{12}$

$= \frac{ - 57}{ 12}$

Discussion

34.	A trader arranges to buy 1,000 mangoes at 31each and agrees to pay an additional sum of200 for their delivery. Knowing that 10%mangoes will be spoiled, he decides on a sellingprice of 2 each for the remaining. However,during delivery, 20% mangoes are spoiled. Whatshould be the percentage increase in selling priceto obtain the same total profit?(a) 20%(b) 25%(c) 12.5%(d) 10%
Answer» Answer: 55555556666666777777 Step-by-step explanation: 777777777778888⁹90

34.

A trader arranges to buy 1,000 mangoes at 31each and agrees to pay an additional sum of200 for their delivery. Knowing that 10%mangoes will be spoiled, he decides on a sellingprice of 2 each for the remaining. However,during delivery, 20% mangoes are spoiled. Whatshould be the percentage increase in selling priceto obtain the same total profit?(a) 20%(b) 25%(c) 12.5%(d) 10%

Answer»

Answer:

55555556666666777777

Step-by-step explanation:

777777777778888⁹90

Discussion

35.	Evaluate the determinants- 4513 3 -1 -200 -13i12-23-5031
Answer» ANSWER: What did BRITISH GOVERNMENT REALIZE after navy and air force revolted

35.

Evaluate the determinants- 4513 3 -1 -200 -13i12-23-5031

Answer»

ANSWER:

What did BRITISH GOVERNMENT REALIZE after navy and air force revolted

Discussion

36.	(6) Out of 1900 km, Vishal travelled some distance by bus and some by aeroplane.Bus travels with average speed 60 km/hr and the average speed of aeroplane is700 km/hr. It takes 5 hours to complete the journey. Find the distance, Vishaltravelled by bus.by elimination method
Answer» ANSWER: Correct option is A 150 We know that, Speed= Time Distance ⇒Time= Speed Distance Let Distance Travelled by Bus be x so that Distance Travelled by AEROPLANE 1900−x Now, TOTAL time is 5 Hours 5= 60 x + 700 1900−x ⇒5= 2100 35x+3(1900−x) ⇒10500=32x+5700⇒4800=32x⇒x=150 KM

36.

(6) Out of 1900 km, Vishal travelled some distance by bus and some by aeroplane.Bus travels with average speed 60 km/hr and the average speed of aeroplane is700 km/hr. It takes 5 hours to complete the journey. Find the distance, Vishaltravelled by bus.by elimination method

Answer»

ANSWER:

Correct option is

A

150

We know that, Speed=

Time

Distance

⇒Time=

Speed

Distance

Let Distance Travelled by Bus be x

so that Distance Travelled by AEROPLANE 1900−x

Now, TOTAL time is 5 Hours

5=

60

x

+

700

1900−x

⇒5=

2100

35x+3(1900−x)

⇒10500=32x+5700⇒4800=32x⇒x=150 KM

Discussion

37.	44. A एक काम का 75%, 50 दिन में पूरा करता है फिर वह Bको बुलाता है और वे दोनों मिलकर बचा हुआ काम 10 दिन मेंपूरा करते है। पूरा काम अकेले करने में B को कितना समयलगेगा?
Answer» Answer: 100 days Step-by-step EXPLANATION: A can finish 75 % of job in 50 days so can complete entire job 50 / ( 75 / 100 ) = 200 / 3 DAYS 1 DAY WORK OF A = 3 / 200 50 days work of A is 3 / 200 × 60 = 9 / 10 remaining work 1 - 9/ 10 = 1 / 10 So B can finish 1 / 10 of job in 10 days so can finish entire job in 100 days

37.

44. A एक काम का 75%, 50 दिन में पूरा करता है फिर वह Bको बुलाता है और वे दोनों मिलकर बचा हुआ काम 10 दिन मेंपूरा करते है। पूरा काम अकेले करने में B को कितना समयलगेगा?

Answer»

Answer:

100 days

Step-by-step EXPLANATION:

A can finish 75 % of job in 50 days

so can complete entire job

50 / ( 75 / 100 ) = 200 / 3 DAYS

1 DAY WORK OF A = 3 / 200

50 days work of A is 3 / 200 × 60 = 9 / 10

remaining work 1 - 9/ 10 = 1 / 10

So B can finish 1 / 10 of job in 10 days so can finish entire job in 100 days

Discussion

38.	Solution to this math problem "A 240 mL bottle of an orange drink claims that it is made with real fruit juice. Upon examination of the ingredient list,only 15% of the contents is actually fruit juice. How many millilitres of "other ingredients" are in the bottle?"
Answer» Answer: solution to this math problem "A 240 mL bottle of an orange drink claims that it is made with real fruit juice. Upon examination of the ingredient list, only 15% of the contents is ACTUALLY fruit juice. How MANY millilitres of "other ingredients" are in the bottle?"

38.

Solution to this math problem "A 240 mL bottle of an orange drink claims that it is made with real fruit juice. Upon examination of the ingredient list,only 15% of the contents is actually fruit juice. How many millilitres of "other ingredients" are in the bottle?"

Answer»

Answer:

solution to this math problem "A 240 mL bottle of an orange drink claims that it is made with real fruit juice. Upon examination of the ingredient list,

only 15% of the contents is ACTUALLY fruit juice. How MANY millilitres of "other ingredients" are in the bottle?"

Discussion

39.	5/8 , 30/48 are they equivalenti need answers and concepts please i will rate you 5 stars and mark as brainliest i am stuck at maths in a test please help
Answer» ANSWER: Yes they are equivalent since 30/48 in its lowest TERM will be 5/8. Step-by-step EXPLANATION: That is 30/48÷6/6= 5/8.

39.

5/8 , 30/48 are they equivalenti need answers and concepts please i will rate you 5 stars and mark as brainliest i am stuck at maths in a test please help

Answer»

ANSWER:

Yes they are equivalent since 30/48 in its lowest TERM will be 5/8.

Step-by-step EXPLANATION:

That is 30/48÷6/6= 5/8.

Discussion

40.	1500 रुपये का कुछ भाग 10% साधारण ब्याज पर तथा बाकी 7% साधारण ब्याज पर दियागया जो 3 साल बाद व्याज के रूप में 396 रुपये प्राप्त हुए। 10% पर कितने रुपये दिए गए
Answer» लश्कर ,मूल्य को 10% प्रति वर्ष की दर से उधार दिया जाए। (1500 -P) प्रति वर्ष 7% पर उधार दिया गया है। $\sf si = \frac{p \times r \times t}{100}$ प्रश्न के अनुसार ${\implies \sf \: \dfrac{x \times 10 \times 3}{100} + \dfrac{(1500 - x) \times7 \times 3 }{100} = 396}$ $\implies\sf \: \dfrac{30x}{100} + \dfrac{21x }{100} = 396$ $\implies\sf \: \dfrac{9x}{100} = 81$ $\implies \sf \: x = \dfrac{81 \times 100}{9}$ $~~~~~~~~~~~~~\underline{\boxed{ \sf \: x = रु 900}}\\\\$ इसलिए 10% p.a पर योग राशि रु 900।

40.

1500 रुपये का कुछ भाग 10% साधारण ब्याज पर तथा बाकी 7% साधारण ब्याज पर दियागया जो 3 साल बाद व्याज के रूप में 396 रुपये प्राप्त हुए। 10% पर कितने रुपये दिए गए

Answer»

लश्कर ,मूल्य को 10% प्रति वर्ष की दर से उधार दिया जाए।
(1500 -P) प्रति वर्ष 7% पर उधार दिया गया है।

$\sf si = \frac{p \times r \times t}{100}$

प्रश्न के अनुसार

${\implies \sf \: \dfrac{x \times 10 \times 3}{100} + \dfrac{(1500 - x) \times7 \times 3 }{100} = 396}$

$\implies\sf \: \dfrac{30x}{100} + \dfrac{21x }{100} = 396$

$\implies\sf \: \dfrac{9x}{100} = 81$

$\implies \sf \: x = \dfrac{81 \times 100}{9}$

$~~~~~~~~~~~~~\underline{\boxed{ \sf \: x = रु 900}}\\\\$

इसलिए 10% p.a पर योग राशि रु 900।

Discussion

41.	On what price, the supply and demand equations are on equilibrium position? Qd = 20 – 2PQs = -10 + 2PSelect one:a. 7b. 7.5 c. 5.5
Answer» Answer: 7 Step-by-step EXPLANATION: MARK me as BRAINLIST.

41.

On what price, the supply and demand equations are on equilibrium position? Qd = 20 – 2PQs = -10 + 2PSelect one:a. 7b. 7.5 c. 5.5

Answer»

Answer:

7

Step-by-step EXPLANATION:

MARK me as BRAINLIST.

Discussion

42.	Point P divides the line segment joining the points A(2, 1) and B(5, – 8) such thatAP/AB=1/3.If P lies on the line 2x – y + k = 0, find the value of k
Answer» ANSWER: this is your answer , HOPE it will HELP you

42.

Point P divides the line segment joining the points A(2, 1) and B(5, – 8) such thatAP/AB=1/3.If P lies on the line 2x – y + k = 0, find the value of k

Answer»

ANSWER:

this is your answer , HOPE it will HELP you

Discussion

43.	4x + 2(x − 3) = 4x + 2x − 11Part A: Solve the equation and write the number of solutions. Show all the steps.
Answer» 4X + 2(x - 3) = 4x + 2x - 11 4x + 2x - 6 = 4x + 2x - 11 6X - 6 = 6x - 11 6x - 6x = 6 - 11 0 = -5 That MEAN your EQUATION is wrong

43.

4x + 2(x − 3) = 4x + 2x − 11Part A: Solve the equation and write the number of solutions. Show all the steps.

Answer»

4X + 2(x - 3) = 4x + 2x - 11

4x + 2x - 6 = 4x + 2x - 11

6X - 6 = 6x - 11

6x - 6x = 6 - 11

0 = -5

That MEAN your EQUATION is wrong

Discussion

44.	An alternative way of solving problems.Use discriminant to find the minimum value of . Thank you for solving my problems!Hint: touches each other for certain value of k, and 'touching' means have at least one solution.
Answer» ANSWER: y=f(x) is a parabola y=ky=k is a HORIZONTAL line If two intersects, that will be the solution of the system equation of \begin{gathered}\begin{cases} & y=k \\ & y=f(x) \end{cases}\end{gathered} { y=k y=f(x) So LET's solve the system equation. f(x)=kf(x)=k \longleftrightarrow 2x^2-7x+2=k⟷2x 2 −7x+2=k \longleftrightarrow 2x^2-7x-k+2=0⟷2x 2 −7x−k+2=0 \boxed{D=33+8k\geq 0} D=33+8k≥0 Thus, y=ky=k intersects if and only if k\geq -\dfrac{33}{8}k≥− 8 33 . So, the lowest location of the horizontal line is y=-\dfrac{33}{8}y=− 8 33 , so it is the minimum value.

44.

An alternative way of solving problems.Use discriminant to find the minimum value of . Thank you for solving my problems!Hint: touches each other for certain value of k, and 'touching' means have at least one solution.

Answer»

ANSWER:

y=f(x) is a parabola

y=ky=k is a HORIZONTAL line

If two intersects, that will be the solution of the system equation of

\begin{gathered}\begin{cases} & y=k \\ & y=f(x) \end{cases}\end{gathered}

{

y=k

y=f(x)

So LET's solve the system equation.

f(x)=kf(x)=k

\longleftrightarrow 2x^2-7x+2=k⟷2x

2

−7x+2=k

\longleftrightarrow 2x^2-7x-k+2=0⟷2x

2

−7x−k+2=0

\boxed{D=33+8k\geq 0}

D=33+8k≥0

Thus, y=ky=k intersects if and only if k\geq -\dfrac{33}{8}k≥−

8

33

. So, the lowest location of the horizontal line is y=-\dfrac{33}{8}y=−

8

33

, so it is the minimum value.

Discussion

45.	Define loss.a. Price at which an article is purchasedb. If SP is greater than CP then seller is said to have gainIf SP is less than CP then seller is said to have lossd. None
Answer» B. If SP is GREATER than CP then SELLER is said to have gain If SP is less than CP then seller is said to have loss. Noice

45.

Define loss.a. Price at which an article is purchasedb. If SP is greater than CP then seller is said to have gainIf SP is less than CP then seller is said to have lossd. None

Answer»

B. If SP is GREATER than CP then SELLER is said to have gain

If SP is less than CP then seller is said to have loss.

Noice

Discussion

46.	Reduce to simplest form1. 5/9 x 3/42. 2/3 x 1/23. 6/9 x 3/124. 4/5 x 1/8Answer all of the questions please
Answer» Step-by-step explanation: 1)5/12 2)1/3 3)1/6 4)1/10

46.

Reduce to simplest form1. 5/9 x 3/42. 2/3 x 1/23. 6/9 x 3/124. 4/5 x 1/8Answer all of the questions please

Answer»

Step-by-step explanation:

1)5/12

2)1/3

3)1/6

4)1/10

Discussion

47.	© जर बना कर, अनाही अंकणिती अटी असेलतरची किमंत कितीछिय-2CA2गेमगिएलाअंकीगती-कोटीलाहीअंकीगती-अडीलाहीजर इ.15054-126 ता
Answer» ANSWER: dghtexcbjurxcnitdxbktff

47.

Answer»

ANSWER:

dghtexcbjurxcnitdxbktff

Discussion

48.	The revenue of the company is given by the equation R = x (1000 – 4x), where R is the revenue of the company in dollars when thy sell x units of a product. How many units of the product should they sell to make revenue of $60,000?Select one:a. 150,100 b. 150,300c. 200,100
Answer» A) 150,100 will be the ANS ACCORDING to my CALCULATION

Discussion

49.	A room is 4m long and 3m wide. How Many square meter of carpet is needed to cover the floor room?please answer this question i will mark you as a brailiest and also rate you 5 stars i promise
Answer» Answer: 12m Step-by-step EXPLANATION: length=4m breadth =3m area of the FLOOR=4×3=12m 12m CARPET are NEEDED to COVER the floor

49.

A room is 4m long and 3m wide. How Many square meter of carpet is needed to cover the floor room?please answer this question i will mark you as a brailiest and also rate you 5 stars i promise

Answer»

Answer:

12m

Step-by-step EXPLANATION:

length=4m

breadth =3m

area of the FLOOR=4×3=12m

12m CARPET are NEEDED to COVER the floor

Discussion

50.	What are the angles of the following triangle? (Note: Image is not drawn to scale.)61A ZA= 41°. ZB = 56° 2C=830B. ZA = 56°, B = 41°, ZC = 830C. ZA=83°, ZB = 440, ZC = 530D. ZA=530, ZB = 830, LC = 44°O Option AOption BO Option COption D
Answer» Answer: Luckily, the PLASMA membrane TURNS out to be very well-suited to its job, salad OIL ... a good basic description of the structure and behavior of membranes in many CELLS. ... fluidity means that if you insert a very fine needle into a CELL, the re, phospholipids aren't just well-suited to .. Step-by-step explanation:

50.

What are the angles of the following triangle? (Note: Image is not drawn to scale.)61A ZA= 41°. ZB = 56° 2C=830B. ZA = 56°, B = 41°, ZC = 830C. ZA=83°, ZB = 440, ZC = 530D. ZA=530, ZB = 830, LC = 44°O Option AOption BO Option COption D

Answer»

Answer:

Luckily, the PLASMA membrane TURNS out to be very well-suited to its job, salad OIL ... a good basic description of the structure and behavior of membranes in many CELLS. ... fluidity means that if you insert a very fine needle into a CELL, the re, phospholipids aren't just well-suited to ..

Step-by-step explanation:

Discussion

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