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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
An exterior angle of a triangle is equal to the sum of it's interior angle justify |
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Answer» ong>Answer: The Exterior Angle SUM Theorem states that each set of exterior angles of a polygon add up to \BEGIN{align*}360^\circ\end{align*}. Exterior Angle Theorem If a side of a triangle is PRODUCED then the exterior angle so FORMED is equal to the sum of the two interior opposite angles. |
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| 2. |
Find the ratio in which the Y axis divide the line segment joining the point (–3,2)&(6,12) |
| Answer» ONG>Answer: | |
| 3. |
6) If n(A)=2,P(A)=1/5, then n(S) =?* |
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Answer» ONG>ANSWER: The Answer Is 0.1 Step-by-step EXPLANATION: N(A) = 2 P(A)= 1/5 1/5 = 0.2 n(S)=? n(S) = P(A)/n(s) = 0.2 / 2 n(S) = 0.1 |
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| 4. |
Y2 + 2ly + 54 by y + 3 |
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Answer» ong>Step-by-step explanation: first of all we factorise polynomial then value of your Solution is completed Hello dear my self Ravi Gupta from AYODHYA Uttar Pradesh Hello dear my self Ravi Gupta from Ayodhya Uttar PradeshFor free PDF eBook you can SUBSCRIBE our official YOUTUBE channel Hello dear my self Ravi Gupta from Ayodhya Uttar PradeshFor free PDF eBook you can subscribe our official YouTube channelhttps://www.youtube.com/channel/UCKAGyIO1nKysmccL9_apamw Hello dear my self Ravi Gupta from Ayodhya Uttar PradeshFor free PDF eBook you can subscribe our official YouTube channelhttps://www.youtube.com/channel/UCKAGyIO1nKysmccL9_apamwmy email address - [email protected] Hello dear my self Ravi Gupta from Ayodhya Uttar PradeshFor free PDF eBook you can subscribe our official YouTube channelhttps://www.youtube.com/channel/UCKAGyIO1nKysmccL9_apamwmy email address - [email protected] my whatsapp NUMBER - 6388044617 Hello dear my self Ravi Gupta from Ayodhya Uttar PradeshFor free PDF eBook you can subscribe our official YouTube channelhttps://www.youtube.com/channel/UCKAGyIO1nKysmccL9_apamwmy email address - [email protected] my whatsapp number - 6388044617only urgent message |
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| 5. |
1. PQR is a triangle, right-angled at P. If PQ= 10 cmand PR = 24 cm, find QR. |
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Answer» ong>Step-by-step EXPLANATION: sorry i don't UNDERSTAND your question pls mark me as BRAINLEIST and pls follow me and GIVE thanks |
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| 6. |
in what time will 4400 rupees become rupees 4576 at 8% per annum interest compounded half-yearly. plss solve it fast |
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Answer» ong>Answer: shaken foreign cell meh CLOCKED brocket ohlhljlj Step-by-step explanation:
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| 7. |
X+1is divided by 2x³-2x²-2x-2 |
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Answer» ONG>Step-by-step EXPLANATION: hggghnnhgbnvvfgghkjhggy hhhhhhnsjehdhdjsuanekfjbdskjdbsnxjdhsbnckxbdndndvdbddjdjhsbsbdjdnsnsnsnsnshdhdjdjdjdjdjxhdhhsjsjskizaomwmsmskskkssnndknskskakskakmmsjsnsmixjnxbgzhsjkzkskskkssjjshdsjkxhcgbxjjjdjsjOamjshsjdjhfdhjjjajJjsshNNsjhjJJjzjjJj hggghnnhgbnvvfgghkjhggy hhhhhhnsjehdhdjsuanekfjbdskjdbsnxjdhsbnckxbdndndvdbddjdjhsbsbdjdnsnsnsnsnshdhdjdjdjdjdjxhdhhsjsjskizaomwmsmskskkssnndknskskakskakmmsjsnsmixjnxbgzhsjkzkskskkssjjshdsjkxhcgbxjjjdjsjOamjshsjdjhfdhjjjajJjsshNNsjhjJJjzjjJj hggghnnhgbnvvfgghkjhggy hhhhhhnsjehdhdjsuanekfjbdskjdbsnxjdhsbnckxbdndndvdbddjdjhsbsbdjdnsnsnsnsnshdhdjdjdjdjdjxhdhhsjsjskizaomwmsmskskkssnndknskskakskakmmsjsnsmixjnxbgzhsjkzkskskkssjjshdsjkxhcgbxjjjdjsjOamjshsjdjhfdhjjjajJjsshNNsjhjJc jjJJJGHJJjhHdhfjyusjijxjhsjskaowíhsbsbdhsjjhgh65 hhhhhhnsjehdhdjsuanekfjbdskjdbsnxjdhsbnckxbdndndvdbddjdjhsbsbdjdnsnsnsnsnshdhdjdjdjdjdjxhdhhsjsjskizaomwmsmskskkssnndknskskakskakmmsjsnsmixjnxbgzhsjkzkskskkssjjshdsjkxhcgbxjjjdjsjOamjshsjdjhfdhjjjajJjsshNNsjhjJJjzjjJj hggghnnhgbnvvfgghkjhggy hhhhhhnsjehdhdjsuanekfjbdskjdbsnxjdhsbnckxbdndndvdbddjdjhsbsbdjdnsnsnsnsnshdhdjdjdjdjdjxhdhhsjsjskizaomwmsmskskkssnndknskskakskakmmsjsnsmixjnxbgzhsjkzkskskkssjjshdsjkxhcgbxjjjdjsjOamjshsjdjhfdhjjjajJjsshNNsjhjJJjzjjJj hggghnnhgbnvvfgghkjhggy hhhhhhnsjehdhdjsuanekfjbdskjdbsnxjdhsbnckxbdndndvdbddjdjhsbsbdjdnsnsnsnsnshdhdjdjdjdjdjxhdhhsjsjskizaomwmsmskskkssnndknskskakskakmmsjsnsmixjnxbgzhsjkzkskskkssjjshdsjkxhcgbxjjjdjsjOamjshsjdjhfdhjjjajJjsshNNsjhjJJjzjjJj hggghnnhgbnvvfgghkjhggy hhhhhhnsjehdhdjsuanekfjbdskjdbsnxjdhsbnckxbdndndvdbddjdjhsbsbdjdnsnsnsnsnshdhdjdjdjdjdjxhdhhsjsjskizaomwmsmskskkssnndknskskakskakmmsjsnsmixjnxbgzhsjkzkskskkssjjshdsjkxhcgbxjjjdjsjOamjshsjdjhfdhjjjajJjsshNNsjhjJJjzjjJj hggghnnhgbnvvfgghkjhggy hhhhhhnsjehdhdjsuanekfjbdskjdbsnxjdhsbnckxbdndndvdbddjdjhsbsbdjdnsnsnsnsnshdhdjdjdjdjdjxhdhhsjsjskizaomwmsmskskkssnndknskskakskakmmsjsnsmixjnxbgzhsjkzkskskkssjjshdsjkxhcgbxjjjdjsjOamjshsjdjhfdhjjjajJjsshNNsjhjJJjzjjJj hggghnnhgbnvvfgghkjhggy hhhhhhnsjehdhdjsuanekfjbdskjdbsnxjdhsbnckxbdndndvdbddjdjhsbsbdjdnsnsnsnsnshdhdjdjdjdjdjxhdhhsjsjskizaomwmsmskskkssnndknskskakskakmmsjsnsmixjnxbgzhsjkzkskskkssjjshdsjkxhcgbxjjjdjsjOamjshsjdjhfdhjjjajJjsshNNsjhjJJjzjjJj hggghnnhgbnvvfgghkjhggy hhhhhhnsjehdhdjsuanekfjbdskjdbsnxjdhsbnckxbdndndvdbddjdjhsbsbdjdnsnsnsnsnshdhdjdjdjdjdjxhdhhsjsjskizaomwmsmskskkssnndknskskakskakmmsjsnsmixjnxbgzhsjkzkskskkssjjshdsjkxhcgbxjjjdjsjOamjshsjdjhfdhjjjajJjsshNNsjhjJJjzjjJj hggghnnhgbnvvfgghkjhggy hhhhhhnsjehdhdjsuanekfjbdskjdbsnxjdhsbnckxbdndndvdbddjdjhsbsbdjdnsnsnsnsnshdhdjdjdjdjdjxhdhhsjsjskizaomwmsmskskkssnndknskskakskakmmsjsnsmixjnxbgzhsjkzkskskkssjjshdsjkxhcgbxjjjdjsjOamjshsjdjhfdhjjjajJjsshNNsjhjJJjzjjJj hggghnnhgbnvvfgghkjhggy hhhhhhnsjehdhdjsuanekfjbdskjdbsnxjdhsbnckxbdndndvdbddjdjhsbsbdjdnsnsnsnsnshdhdjdjdjdjdjxhdhhsjsjskizaomwmsmskskkssnndknskskakskakmmsjsnsmixjnxbgzhsjkzkskskkssjjshdsjkxhcgbxjjjdjsjOamjshsjdjhfdhjjjajJjsshNNsjhjJJjzjjJj you Ma'am |
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| 9. |
Why is it important to identify the leading coefficient of the expressions? |
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Answer» ong>Answer: Identifying the COEFFICIENT will DETERMINE the end BEHAVIOR of the graph of the polynomial function. For example, when the degree is odd and the leading coefficient is negative, the graph rises to the LEFT and falls to the right. Hope this helps you Stay happy and safe Do mark as brainliest ✌️ |
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| 10. |
Find the median of following 2,3,4,5,0,1,3,3,4,3 |
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Answer» ONG>ANSWER: MEDIAN = 2+3+4+5+0+1+3+3+4+3/10 = 25/10 = 2.5 |
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| 11. |
If tanA=4/3,then (sinA+cosA)=? |
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Answer» ONG>Answer: SINA + cosA = 7/3 Step-by-step explanation: Now divide (sinA + cosA) by cosA sinA/cosA +cosA/cosA tanA + 1 4/3 + 1 7/3 |
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| 12. |
The formula πr( l +r) sq unit is the total surface area of a.................... * |
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Answer» ONG>Step-by-step EXPLANATION: the right ANSWER is cone. |
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| 13. |
Find the product of: (2x2 + 3x – 5) by (3x – 2) |
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Answer» |
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| 14. |
Solution of thus..... .2. Describe with the help of a diagram, how compressions and rarefactions areproduced in the air near a source of the sound.Ans. |
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Answer» align="absmiddle" ALT="\pink{ \bold{ \large{ \huge{ \underline{Answer}}}}}" class="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%5Cpink%7B%20%5Cbold%7B%20%5Clarge%7B%20%5Chuge%7B%20%5Cunderline%7BAnswer%7D%7D%7D%7D%7D" title="\pink{ \bold{ \large{ \huge{ \underline{Answer}}}}}"> [See the above attachment] ➡A vibrating OBJECT producing a series of compressions (C) and rarefaction (R) ➡In these waves, the particles move BACK and forth parallel to the direction of propagation of the DISTURBANCE. Such waves are called longitudinal waves. ➡There is another kind of waves called transverse waves. In these waves, the particles oscillate up and down perpendicular to the propagation of the direction of the disturbance. ➡Sound propagates in a medium as a series of compressions (C) and rarefactions (R). ➡Compressions are the regions of high pressure and density where the particles are crowded and are represented by the upper portion of the curve called crest.Rarefactions are the regions of low pressure and density where the particles are spread out and are represented by the lower portion of the curve called trough. |
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| 15. |
Construct a rhombus PQRS in which PQ=5cm,angle SPQ=30 degree |
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Answer» ong>Answer: STEPS of construction: Step 1: Draw AB=4.2 cm. Step 2: With A as the centre and radius equal to 8 cm, draw an arc. Step 3: With B as the centre and radius equal to 6 cm, draw another arc, cutting the previous arc at C. Step 4: Join BC. Step 5: With A as the centre and radius equal to 5 cm, draw an arc. Step 6: With C as the centre and radius equal to 5.2 cm, draw another arc, cutting the previous arc at D. Step 7: Join AD and CD. Thus, ABCD is the required QUADRILATERAL. |
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| 16. |
If n ( A) = 20, n (B)=28 and n ( A,U,B)= 36 then n(A n B)=? |
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Answer» ong>Answer: USING the FORMULA n(A∪B)=n(A)+n(B)−n(A∩B) then, n(A∩B)=n(A)+n(B)−n(A∪B) =20+28−36=48−36=12 |
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| 17. |
In figure line AB line CD and line PQ is transversal. Find the measure of ∠ART |
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Answer» ONG>ANSWER: hope it HELPS you please mark me as brainlist and please FOLLOW me and VOTES on my all answers |
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| 19. |
Find the median of following 2,3,4,5,0,1,3,4,3 |
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Answer» ong>Step-by-step explanation: Find the mean , MEDIAN, mode and range of the following SETS of DATA 2,3,4,3,5,5,6,7,8,9,6,6,5,3 13,7,8,8,2,9,11,7,8,4,5 45,48,60,42,53,47,51,54,49,48,47,53,48,44,46 ANSWER a) Mean=Total no. of observationssum of the NUMBER ⇒ Mean=402+3+4+3+5+5+6+7+8+9+6+6+5+3+13+7+8+8+2+9+11+7+8+4+5+45+48+60+42+53+47+51+54+49+48+47+53+48+44+46 ⇒ Mean=40119+770,40889=22.2 d∴ Mean=22.2 b) To arrange data in ascending order Median : 2,2,3,3,3,4,4,5,5,5,5,6,6,6,7,7,7,8,8,8,8,9,9,11,13,42,44,45, Median =28+8=126=8 c) Mode :- The only number which appears multiple times Mode =2,3,4,5,6,7,8,9,48,53 d) Range: The subtract the smallest number from the LARGEST number =60−2=58 ∴ Range =58 |
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| 20. |
GUYS PLS SOLVE THIS QUESTION.. |
Answer» ONG>ANSWER:हम आगे से ट्राई करेंगेStep-by-step EXPLANATION: ओके रिपोर्ट आई तो मैं अपने कमरे से निकल गया है इसके ए आरटी से निकल आया था आई तो उसने अपने हाथ को |
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| 22. |
For finding AB and BC with the help of information given in figure. Compelete the following activity.AB = BC (given) |
| Answer» ONG>ANSWER: | |
| 23. |
conduct a survey of a group of students and represent it graphically - height, weight, number of family members etc |
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Answer» ONG>ANSWER: dscgfhvjxitsffiwjfwtindlckgrkgdigfmxfsifjyjfsdjgfo iktt |
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| 24. |
3. यदि A = [cosecose-sino cososine] है तो सिद्ध कीजिएFor An = [_sin neCOS n o sin nesin ne cos noNEN |
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Answer» ONG>ANSWER: what MEAN we don't UNDERSTAND |
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| 25. |
Directions (Q. Nos. 32 and 33): Answer these questions based on the following piecharts :Operating profitOperating profitP 160 lakh180 lakhDepreciation20%Interest40%DepreciationON 28%Interest30%Dividend8%Dividend8%RetainedProfit 20%Tax 9%RetainedProfit 25%Tax 12%1990-911991-9232. The operating profit in 1991-92increased over than in 1990-91 is[A] 23%[B] 22%[C] 25%[D] 24% |
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Answer» ONG>Answer: 32. 25%.............. |
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| 26. |
Find the slope of the line passing through the points (-p,q) and (q,-p) |
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Answer» CHFOXHFHXIXYFUGIYDYF SUFUGUCUCUHICOI XFTGD GRIFFIN to FEEL fufyfhfu Step-by-step EXPLANATION: bGXHCHFOXHFHXIXYFUGIYDYF SUFUGUCUCUHICOI XFTGD Griffin to feel fufyfhfu |
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| 27. |
Solution of this..... ➡What are wavelength, frequency, time period and amplitude of a sound wave? |
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Answer» ong>ANSWER: Time PERIOD(T): The time taken by two consecutive compressions or rarefactions to cross a fixed POINT is called the time period of the sound wave. Amplitude(A): The MAGNITUDE of the MAXIMUM disturbance in the medium on either side of the mean value is called the amplitude of the wave. |
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| 28. |
Find %profit or % loss |
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Answer» ONG>ANSWER: so the answer will we the 200% Step-by-step explanation: |
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| 29. |
If the compound ratio of 6:7 and x:12 is 4:7 find the value x |
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Answer» ong>ANSWER: PLEASE BRAINLIEST MY ANSWER x = 8 Step-by-step explanation: Q) If the compound ratio of 6:7 and x:12 is 4:7 find the VALUE x ⇒Compound ratio means the ratio obtained by two or more ratios are multiplies termwise. If a:b and c:d are two given ratios, then their compound ratio is ac : bd Now the given is - 6:7 ; x:12 are two ratios and their compound ratio is 4:7 ∴ (6:7)*(x:12) = 4:7 ∴ x/12 = (4/7)/(6/7) ∴ x/12 = (4/7)*(7/6) ∴ x/12 = (4*7)/(7*6) ∴ x/12 = 28/42 = 4/6 = 2/3 ∴ x/12 = 2/3 ∴ x = (2/3)*12 ∴ x = (2*12)/3 = 2*4 ∴ x = 8 |
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| 30. |
Find the area of a circle whose circumference is 22cm |
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Answer» now that CIRCUMFERENCE is 2πr Hence 2πr=22 2×22/7 ×r=22 r=7/2 We KNOW that AREA of CIRCLE=πr^2 22/7×7/2×7/2 77/2 Hence area of circle is 77/2 cm^2 |
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| 32. |
427 Construct DEFG such that I(DE) = 4.5 cm, l(EF) = 6.5 cm, I(DG) = 5.5 cm, I(DF) = 7.2 cm, 1(EG) = 7.8 cm. |
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Answer» ong>Answer: Step 1: Draw DE = 4.5 cm. Step 2: With D as centre and radius 7.2 cm, draw an ARC. Step 3: With E as centre and radius 6.5 cm, draw an arc cutting the previous arc at F. Step 4: Join EF. Step 5: With D as centre and radius 5.5 cm, draw an arc. Step 6: With E as centre and radius 7.8 cm, draw an arc cutting the previous arc at G. Step 7: Join DG and GF. Here, DEFG is the required quadrilateral. |
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| 33. |
6. The ratio of Maths and Science books in a school library is 4: 5. If the number ofScience books is 75, find the number ofMaths books11 |
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Answer» Let the no. of maths and science BOOKS be 4X and 5x. No. of science books =75 therefore, 5x = 75 X = 75/5 x= 15 No. of maths books = 4 x = 4×15 = 60 so no. of maths books is 60 hope it HELPS...^_^ |
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| 34. |
a number increased by 10% and the decreased by 10% find the net increase or decrease percentage a number |
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Answer» ONG>Answer: DECREASED by 1 % Step-by-step explanation: for example 10 is 10% of 100 increase of 10% will be 110 11 is 10% of 110 so 110-11=99 it is DECREASE in 1 % of main amount (that is 100) 1 is decreased from main amount so 1 is the 1% of 100 decreased by 1% Mark me brinliest |
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| 35. |
Tan A x tan (90 - A) = * |
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Answer» ONG>Answer: This is not any valid questions Step-by-step EXPLANATION: |
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| 36. |
At a certain time of a day,the shadow of a 1.5m tall boy is 1.92m long. The shadow of a near by flagpost at the same time is 6.72m long. What will be the height of the flagpost? |
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Answer» ONG>ANSWER: the answer is in the ATTACHMENT |
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| 37. |
2. What is the index form of the polynomialC1,0, 3, 5) taking & as variable |
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Answer» ong>ANSWER: Your answer is here.... x cube + 0x SQUARE+ 3x+ 5 I HOPE it WORKS for youPlease,please mark me as brainliest.... |
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| 38. |
The area of the rectangle is (2 + 12 + 35)sq.units. What are its demension |
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Answer» ONG>ANSWER: answer is 49sq.units. |
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| 40. |
3. The measures of angles of a triangle are x°,(x-20), (x-40) Find the measure of each angle. |
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Answer» Given :- We know that sum of three angles of a triangle is 180° So, simply we will add up all the angles and equal to 180. We will GET the value of x Then, simply we can subsitute values → x + x - 20 + x - 40 = 180 → x + x + x - 20 - 40 = 180 → 3X -60 = 180 → 3x = 180 + 60 → 3x = 240 → x = 240/3 → x = 80 Thus, we got the value of x i.e 80 Subsituting Values :-
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| 41. |
(2x-y+z)² Algebric Identity |
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Answer» ONG>Step-by-step EXPLANATION: Hey friend, Here is the answer you were looking for: \begin{gathered}{(2x - y + z)}^{2} \\ \\ using \: the \: identity \\ {(a - b + c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} - 2ab - 2bc + 2ca \\ \\ = {(2x)}^{2} + {(y)}^{2} + {(z)}^{2} - 2 \times 2x \times y - 2 \times y \times z + 2 \times z \times 2x \\ \\ = 4 {X}^{2} + {y}^{2} + {z}^{2} - 4XY - 2yz + 4xz\end{gathered} (2x−y+z) 2
usingtheidentity (a−b+c) 2 =a 2 +b 2 +c 2 −2ab−2bc+2ca =(2x) 2 +(y) 2 +(z) 2 −2×2x×y−2×y×z+2×z×2x =4x 2 +y 2 +z 2 −4xy−2yz+4xz
Hope this helps! Thanks... ☺☺ |
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| 42. |
If a, b, c are positive real numbers such that a+b-c/c=a-b+c/b=-a+b+c/a, find the value of (a+b) (b+c) (c+a) /abc. |
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Answer» ONG>ANSWER: teh VALU of trrinia is bhosadi cha |
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| 44. |
If s4=16 and s5=12 then find the value of an |
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Answer» ong>Answer: Before we START solving this question, let us know the meaning of S5 and S4. So, here, S5 refer to the sum of the 1ST, 2nd,3rd, 4th and 5th term and S4 MEANS the sum of 1st,2nd,3rd and 4th term. Now,let us proceed to the solution. Sol. S5 = 1st term + 2nd term +3rd term + 4th term + 5th term = 35 ————(i) S4 = 1st term + 2nd term + 3rd term + 4th term = 22 ————(ii) Subtracting (ii) from (i), we get 5th term = 1 hope it helps |
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| 45. |
The smallest number by which 6912 must be divided so that the result is a perfect square is 3. Find the perfect square obtained Please Correct Answer Will mark brainliest ;) |
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Answer» ONG>ANSWER: ?.....…...…..…..……… |
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| 46. |
O Other In UKL side U side KL 1-108. -then find the measures of J and LO 127°, 72O 77, 122Q3) Solve the following in |
| Answer» ONG>Answer: | |
| 48. |
which of the following number is the predecessor A ,23,499,999 B 23,400,009 C ,23,399,999 D 23,400,001 |
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Answer» ONG>ANSWER: a. 23499998 b. 23400008 c. 23399998 d. 23400000 |
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| 49. |
What does # stand for 4 # 8 = -4 |
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Answer» ONG>ANSWER: # MIGHT be minus since 4-8=-4 to be honest, I NEVER seen this before Step-by-step explanation: |
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| 50. |
The rationalising factor of 3/(√7) is 7 b) √3 c) 3 d) √7 |
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Answer» ONG>ANSWER: It is (d)√7 Step-by-step EXPLANATION: At rationalising 3/√7, we would multiply and divide by √7 to get 3√7/7 Hope it helps Mark it as the brainliest |
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