332354 + Interview Questions in Secondary School in Math

1.	ટુકા પ્રશ્નો 7 થી 22 રહેશે (પ્રત્યેક 7. સાદું રૂપ આપોઃ (3+/7)(4-2/7)37)(4-28. જો 4-4x+૩ ને 24-1 વડે ભ4559. કિંમત શોધો.3(25)2
Answer» ONG>Answer: 154 Step-by-step EXPLANATION: is FEASTS you me please THANKS of me

1.

ટુકા પ્રશ્નો 7 થી 22 રહેશે (પ્રત્યેક 7. સાદું રૂપ આપોઃ (3+/7)(4-2/7)37)(4-28. જો 4-4x+૩ ને 24-1 વડે ભ4559. કિંમત શોધો.3(25)2

Answer» ONG>Answer:

154

Step-by-step EXPLANATION:

is

FEASTS

you

me

please THANKS of me

Discussion

2.	17. "One needs to do a lot of practice as well as have patience while learning music'. How many times does the vowel e occur in the above sentence?(1) Eight(2) Seven (3) Nine (4) Ten
Answer» ONG>Answer: (4) Ten Step-by-step EXPLANATION: its Ten by counting

2.

17. "One needs to do a lot of practice as well as have patience while learning music'. How many times does the vowel e occur in the above sentence?(1) Eight(2) Seven (3) Nine (4) Ten

Answer» ONG>Answer:

(4) Ten

Step-by-step EXPLANATION:

its Ten by counting

Discussion

3.	4) If we divide v12 by v3, the result isa 12b 8c 2d 6
Answer» er: Step-by-step explanation: GIVEN, Divide √12 by √3 = √12 / √3 = √4 × 3 / √3 = (√4) × (√3) / √3 = numerator √3 and denominator √3 are cancelled, we GET = √4 = 2 is the answer

3.

4) If we divide v12 by v3, the result isa 12b 8c 2d 6

Answer»

er:

Step-by-step explanation:

GIVEN,

Divide √12 by √3

= √12 / √3

= √4 × 3 / √3

= (√4) × (√3) / √3

= numerator √3 and denominator √3 are cancelled, we GET

= √4

= 2 is the answer

Discussion

4.	[(256)–⁴]–3/2 plz simplify
Answer» ONG>Answer: 5/2 or 2.5 Step-by-step explanation: 4√256 = 4 4-3/2 = (8-3)/2 5/2 or 2.5

4.

[(256)–⁴]–3/2 plz simplify

Answer» ONG>Answer:

5/2 or 2.5

Step-by-step explanation:

4√256 = 4

4-3/2 = (8-3)/2

5/2 or 2.5

Discussion

5.	Solve the quadratic equation by factorisation m²- 14m+13=0.
Answer» ong>ANSWER: M²-14m+13 = 0 m²-13m-m+13 = 0 m(m-13)-1(m-13) = 0 (m-1)(m-13) = 0 m = 1 & 13

5.

Solve the quadratic equation by factorisation m²- 14m+13=0.

Answer»

ong>ANSWER:

M²-14m+13 = 0

m²-13m-m+13 = 0

m(m-13)-1(m-13) = 0

(m-1)(m-13) = 0

m = 1 & 13

Discussion

6.	Draw concentric circle with radius 4 cm and 6 cm and find its width write the steps of construction
Answer» ONG>Answer: DRAW concentric circles of RADIUS 4 cm and 6 cm withcentre of O. Take POINT P on the outer circle. iii. ... Draw perpendicular bisectors of OP where M is the midpoint of OP. Take a distance of a point O from the point M and mark arcs from M on the inner circle it cuts at point A and B respectively.

6.

Draw concentric circle with radius 4 cm and 6 cm and find its width write the steps of construction

Answer» ONG>Answer:

DRAW concentric circles of RADIUS 4 cm and 6 cm withcentre of O.

Take POINT P on the outer circle.

iii. ...

Draw perpendicular bisectors of OP where M is the midpoint of OP.

Take a distance of a point O from the point M and mark arcs from M on the inner circle it cuts at point A and B respectively.

Discussion

7.	SIMPLIFY THE ABOVE EXPRESSION
Answer» ONG>Answer: the SIMPLIFIED answer is $\frac{x^{4} - y^{4}}{x^{6} - y^{6}}$ i hope this HELPS!! Step-by-step explanation:

7.

SIMPLIFY THE ABOVE EXPRESSION

Answer» ONG>Answer:

the SIMPLIFIED answer is $\frac{x^{4} - y^{4}}{x^{6} - y^{6}}$

i hope this HELPS!!

Step-by-step explanation:

Discussion

8.	19x2-6x+7 divided by x-2
Answer» ONG>ANSWER: Step-by-step EXPLANATION:

8.

19x2-6x+7 divided by x-2

Answer» ONG>ANSWER:

Step-by-step EXPLANATION:

Discussion

9.	Convert impedance z=4-j6 into polar form
Answer» ONG>Answer: 4 Step-by-step EXPLANATION: i HOPE branirst me it HOPED

9.

Convert impedance z=4-j6 into polar form

Answer» ONG>Answer:

4

Step-by-step EXPLANATION:

i HOPE branirst me it HOPED

Discussion

10.	What is the number of sample points when two coins are tossed simultaneously ? a) 8 b) 4c) 2 d) 1
Answer» ong>Answer: 4 Step-by-step explanation: The possibility of mistake can HAPPEN at analysing the OUTCOMES when 2 coins are tossed simultaneously. The alternative quick method of solving can be that the number of outcomes will be equal to =2×2=4 since there can be only cases of HEADS or tails and the coin is tossed 2 TIMES.

10.

What is the number of sample points when two coins are tossed simultaneously ? a) 8 b) 4c) 2 d) 1

Answer»

ong>Answer:

4

Step-by-step explanation:

The possibility of mistake can HAPPEN at analysing the OUTCOMES when 2 coins are tossed simultaneously. The alternative quick method of solving can be that the number of outcomes will be equal to =2×2=4 since there can be only cases of HEADS or tails and the coin is tossed 2 TIMES.

Discussion

11.	Is 160/200 sufficient to crack JSTSE (MVPP) ?
Answer» may atleast get 170 to 185 or LUCKILY 190 to 195

Discussion

12.	Factorise the following expressions.(i) a² + 8a +16
Answer» ong>Answer: (1)WHOLE power 2×4 a+4×4

12.

Factorise the following expressions.(i) a² + 8a +16

Answer»

ong>Answer:

(1)WHOLE power 2×4 a+4×4

Discussion

13.	Tan x tan ( 90 - ) = ?
Answer» ong>Answer: Tan THETA×tan(90- theta)=1

13.

Tan x tan ( 90 - ) = ?

Answer»

ong>Answer:

Tan THETA×tan(90- theta)=1

Discussion

14.	Simplify 3x^2 - 2x(x - 3) + 3x(2x + 3)
Answer» ong>Answer: $7 {x}^{2} + 15x$ Step-by-step EXPLANATION: PLEASE see the ATTACHMENT....

14.

Simplify 3x^2 - 2x(x - 3) + 3x(2x + 3)

Answer»

ong>Answer:

$7 {x}^{2} + 15x$

Step-by-step EXPLANATION:

PLEASE see the ATTACHMENT....

Discussion

15.	Find the area of a triangle.its two sides are 18cm and 10cm, perimeter is 42 cm
Answer» ALIGN="absmiddle" ALT="\sf \bf \huge {\boxed {\MATHBB {QUESTION}}}" class="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%20%5Csf%20%5Cbf%20%5Chuge%20%7B%5Cboxed%20%7B%5Cmathbb%20%7BQUESTION%7D%7D%7D%20" title="\sf \bf \huge {\boxed {\mathbb {QUESTION}}}"> $\tt Find \:the\: area\: of \:a \:triangle.\:Its\: two \:sides \:are\: 18\:cm\\\tt and\: 10\:cm, \:perimeter\: is\: 42\: cm.$ $\sf \bf \huge {\boxed {\mathbb {ANSWER}}}$ $\sf \bf {\boxed {\mathbb {GIVEN}}}$ $\bf First \:side\:of\:the \:triangle(a) = 18\:cm$ $\bf Second\:side\:of\:the \:triangle(b) = 10\:cm$ $\bf Perimeter \:the \:triangle(P) = 42\:cm$ $\sf \bf {\boxed {\mathbb {TO\:FIND}}}$ $\bf Area\:of\:the \:triangle(A)$ $\sf \bf {\boxed {\mathbb {SOLUTION}}}$ ${\pink {\underline {\bf {\pmb {Third \:side\:of\:the \:triangle(c)}}}}}$ ${\blue {\boxed {\boxed {\boxed {\green {\pmb {P_{(Triangle)}=a+b+c}}}}}}}$ $\sf P= perimeter\:of\:the \:triangle$ $\sf a=first \:side \:of\:the \:triangle$ $\sf b=second\:side \:of\:the \:triangle$ $\sf c=third \:side \:of\:the \:triangle$ ${\underbrace {\overbrace {\orange {\pmb {Substitute \:the \:values}}}}}$ $\bf \implies 42=18+10+c$ $\bf \implies 42=28+c$ $\bf \implies c=42-28$ $\implies {\blue {\boxed {\boxed {\purple {\sf c=14\:cm}}}}}$ —————————————————————————————— ${\pink {\underline {\bf {\pmb {Semiperimeter \:of\:the \:triangle(S)}}}}}$ ${\blue {\boxed {\boxed {\boxed {\green {\pmb {S=\dfrac{P}{2}}}}}}}}$ $\sf S=semiperimeter \:of\:the \:triangle$ $\sf P=perimeter \:of\:the \:triangle$ ${\underbrace {\overbrace {\orange {\pmb {Substitute \:the \:values}}}}}$ $\bf \implies S=\dfrac{42}{2}$ $\bf \implies S=\dfrac{\cancel{42}}{\cancel{2}}$ $\implies {\blue {\boxed {\boxed {\purple {\sf S=21\:cm}}}}}$ *——————————————————————————————* ${\pink {\underline {\bf {\pmb {Area \:of\:the \:triangle(A)}}}}}$ ${\blue {\boxed {\boxed {\boxed {\green {\pmb {A_{(Triangle)}=\sqrt{S\Big(S-a\Big) \Big(S-b\Big) \Big(S-c\Big)}}}}}}}}$ $\sf A=area\:of \:the \:triangle$ $\sf S=semiperimeter \:of\:the \:triangle$ $\sf a=first \:side \:of\:the \:triangle$ $\sf b=second\:side \:of\:the \:triangle$ $\sf c=third \:side \:of\:the \:triangle$ ${\underbrace {\overbrace {\orange {\pmb {Substitute \:the \:values}}}}}$ $\bf \implies A=\sqrt{21\Big(21-18\Big) \Big(21-10\Big) \Big(21-14\Big)}$ $\bf \implies A=\sqrt{21\Big(3\Big) \Big(11\Big) \Big(7\Big)}$ $\bf \implies A=\sqrt{21\times 3\times 11\times 7}$ $\bf \implies A=\sqrt{4851}$ $\bf \implies A=\sqrt{441\times 11}$ ${\blue {\boxed {\boxed {\purple {\mathfrak {A=21\sqrt{11}\:{cm}^{2}}}}}}}$ ${\underbrace {\red {\overline {\red {\underline {\red {\pmb {\sf {{\therefore} The\:area \:of \:the \:triangle \:is\:21\sqrt{11}\:{cm}^{2}}}}}}}}}}$ $\sf \bf \huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}$ ____________________________________________ $\sf \bf \huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}$ $\sf Area \:of \:the \:triangle = \dfrac{1}{2}bh$ $\sf Perimeter\:of \:the \:triangle =a+b+c$

15.

Find the area of a triangle.its two sides are 18cm and 10cm, perimeter is 42 cm

Answer» ALIGN="absmiddle" ALT="\sf \bf \huge {\boxed {\MATHBB {QUESTION}}}" class="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%20%5Csf%20%5Cbf%20%5Chuge%20%7B%5Cboxed%20%7B%5Cmathbb%20%7BQUESTION%7D%7D%7D%20" title="\sf \bf \huge {\boxed {\mathbb {QUESTION}}}">

$\tt Find \:the\: area\: of \:a \:triangle.\:Its\: two \:sides \:are\: 18\:cm\\\tt and\: 10\:cm, \:perimeter\: is\: 42\: cm.$

$\sf \bf \huge {\boxed {\mathbb {ANSWER}}}$

$\sf \bf {\boxed {\mathbb {GIVEN}}}$

$\bf First \:side\:of\:the \:triangle(a) = 18\:cm$
$\bf Second\:side\:of\:the \:triangle(b) = 10\:cm$
$\bf Perimeter \:the \:triangle(P) = 42\:cm$

$\sf \bf {\boxed {\mathbb {TO\:FIND}}}$

$\bf Area\:of\:the \:triangle(A)$

$\sf \bf {\boxed {\mathbb {SOLUTION}}}$

${\pink {\underline {\bf {\pmb {Third \:side\:of\:the \:triangle(c)}}}}}$

${\blue {\boxed {\boxed {\boxed {\green {\pmb {P_{(Triangle)}=a+b+c}}}}}}}$

$\sf P= perimeter\:of\:the \:triangle$
$\sf a=first \:side \:of\:the \:triangle$
$\sf b=second\:side \:of\:the \:triangle$
$\sf c=third \:side \:of\:the \:triangle$

${\underbrace {\overbrace {\orange {\pmb {Substitute \:the \:values}}}}}$

$\bf \implies 42=18+10+c$

$\bf \implies 42=28+c$

$\bf \implies c=42-28$

$\implies {\blue {\boxed {\boxed {\purple {\sf c=14\:cm}}}}}$

——————————————————————————————

${\pink {\underline {\bf {\pmb {Semiperimeter \:of\:the \:triangle(S)}}}}}$

${\blue {\boxed {\boxed {\boxed {\green {\pmb {S=\dfrac{P}{2}}}}}}}}$

$\sf S=semiperimeter \:of\:the \:triangle$
$\sf P=perimeter \:of\:the \:triangle$

${\underbrace {\overbrace {\orange {\pmb {Substitute \:the \:values}}}}}$

$\bf \implies S=\dfrac{42}{2}$

$\bf \implies S=\dfrac{\cancel{42}}{\cancel{2}}$

$\implies {\blue {\boxed {\boxed {\purple {\sf S=21\:cm}}}}}$

——————————————————————————————

${\pink {\underline {\bf {\pmb {Area \:of\:the \:triangle(A)}}}}}$

${\blue {\boxed {\boxed {\boxed {\green {\pmb {A_{(Triangle)}=\sqrt{S\Big(S-a\Big) \Big(S-b\Big) \Big(S-c\Big)}}}}}}}}$

$\sf A=area\:of \:the \:triangle$
$\sf S=semiperimeter \:of\:the \:triangle$
$\sf a=first \:side \:of\:the \:triangle$
$\sf b=second\:side \:of\:the \:triangle$
$\sf c=third \:side \:of\:the \:triangle$

${\underbrace {\overbrace {\orange {\pmb {Substitute \:the \:values}}}}}$

$\bf \implies A=\sqrt{21\Big(21-18\Big) \Big(21-10\Big) \Big(21-14\Big)}$

$\bf \implies A=\sqrt{21\Big(3\Big) \Big(11\Big) \Big(7\Big)}$

$\bf \implies A=\sqrt{21\times 3\times 11\times 7}$

$\bf \implies A=\sqrt{4851}$

$\bf \implies A=\sqrt{441\times 11}$

${\blue {\boxed {\boxed {\purple {\mathfrak {A=21\sqrt{11}\:{cm}^{2}}}}}}}$

${\underbrace {\red {\overline {\red {\underline {\red {\pmb {\sf {{\therefore} The\:area \:of \:the \:triangle \:is\:21\sqrt{11}\:{cm}^{2}}}}}}}}}}$

$\sf \bf \huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}$

____________________________________________

$\sf \bf \huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}$

$\sf Area \:of \:the \:triangle = \dfrac{1}{2}bh$

$\sf Perimeter\:of \:the \:triangle =a+b+c$

Discussion

16.	In how many years will a sum of $1200 becomes $1392 at 8% p.a. rate of simple interest?
Answer» ong>ANSWER: idk:) Step-by-step explanation: MARK brainliest please:(

16.

In how many years will a sum of $1200 becomes $1392 at 8% p.a. rate of simple interest?

Answer»

ong>ANSWER:

idk:)

Step-by-step explanation:

MARK brainliest please:(

Discussion

17.	What is the probability of the event that a number chosen from 1 to 100 is a prime number
Answer» ONG>Step-by-step EXPLANATION: It is 0.01. Hope it HELPS you.

17.

What is the probability of the event that a number chosen from 1 to 100 is a prime number

Answer» ONG>Step-by-step EXPLANATION:

It is 0.01.

Hope it HELPS you.

Discussion

18.	If 5 sin ∅ - 12 cos ∅ = 0 then find the value of sec ∅help please
Answer» ong>Answer: 13/5 Step-by-step EXPLANATION: PLEASE MARK it as BRAINLIEST

18.

If 5 sin ∅ - 12 cos ∅ = 0 then find the value of sec ∅help please

Answer»

ong>Answer:

13/5

Step-by-step EXPLANATION:

PLEASE MARK it as BRAINLIEST

Discussion

19.	A contractor undertakes to complete a work in 130 days. He employs 150 men for 25 days and they complete 1/4 of the work then he reduce the number of men to 100, who work for 60 days after which there are 10 holidays. How many men must be employed for the remaining period to finish the work
Answer» ONG>Answer: Therefore, work is done in 25 days by 150 men. Therefore, Work is done in 35 days by 150 men. Hence, he should EMPLOY 50 more men.

Discussion

20.	Urgent please ...simplify √6+√2/√6-√2 + √6-√2/√6+√
Answer» ONG>ANSWER: amend your QUESTION pls

Discussion

21.	19x2 - 6x2 + 7 divided by x-- 2
Answer» ONG>Step-by-step explanation: 38-12+7/x-2=38-5/x-2=33/x-2

Discussion

22.	5.4÷5step by step plz answer
Answer» ONG>Answer: 1.08 Step-by-step EXPLANATION: HOPE this helpfull

22.

5.4÷5step by step plz answer

Answer» ONG>Answer:

1.08

Step-by-step EXPLANATION:

HOPE this helpfull

Discussion

23.	यदि सुरेश के पास अपने धन का 75% खर्च करने के बाद 600 बचे तो ज्ञात कीजिए कि उसके पास शुरू में कितने रूपये थे ?
Answer» ONG>Step-by-step EXPLANATION: friends I want 53 thanks only . EVERYONE can GIVE me 10 thanks than 53 thanks will be complete .

Discussion

24.	For a picnic party a fund of ₹25600 was raised. Each boy paid the same amount as the number of boys. Find the contribution of each boy??
Answer» ONG>Answer: you can SEE the DAY before YESTERDAY at a time to purchases of the day before

Discussion

25.	The mean and variance of 5 items are 64 and 68 respectively. If two more items of values 62and 66 are added to the data find the new variance of 7 items
Answer» ONG>Step-by-step explanation: hxhdydyshg ch b beds yehi JEFF dump SSC JSC de hai do SE xp CA xp CA di CA xp

Discussion

26.	5.4÷5step by step plz answer
Answer» Answer $➠ \frac{4}{5} \\ ➠by \: simple \: method \: \\ ➠ \frac{40}{5} ..(only \: condering \:) \\ ➠ \:8 \\ ➠ then \: remove \: the \: adding \: 0 \\ ➠ 0.8$ This is Your Answer 0.8

26.

5.4÷5step by step plz answer

Answer»

Answer

$➠ \frac{4}{5} \\ ➠by \: simple \: method \: \\ ➠ \frac{40}{5} ..(only \: condering \:) \\ ➠ \:8 \\ ➠ then \: remove \: the \: adding \: 0 \\ ➠ 0.8$

This is Your Answer

0.8

Discussion

27.	If 250 Gram of Mayonnaise is 70 Rupees then what is the cost for 2 kg
Answer» ONG>Step-by-step EXPLANATION: The answer is ;- 560 RUPEES /-

27.

If 250 Gram of Mayonnaise is 70 Rupees then what is the cost for 2 kg

Answer» ONG>Step-by-step EXPLANATION:

The answer is ;- 560 RUPEES /-

Discussion

28.	समांतर भुजाओं को राजा लग गया कौन ची नावे दोन 107 14661 कीमत काढ़ासमांतर भुजाओं को नजर लग जा कौन सीमा पर दोन 107 174 180 कीमत कार्ड
Answer» ONG>ANSWER: yes120 fgu Step-by-step explanation: 10……… 200………400………

28.

समांतर भुजाओं को राजा लग गया कौन ची नावे दोन 107 14661 कीमत काढ़ासमांतर भुजाओं को नजर लग जा कौन सीमा पर दोन 107 174 180 कीमत कार्ड

Answer» ONG>ANSWER:

yes120

fgu

Step-by-step explanation:

10……… 200………400………

Discussion

29.	Yadi samikaran 2x2+kx-150 ka mul -5 hai aur p(X2+x)+k=0 ke mul ke saman hai to k=?
Answer» ONG>ANSWER: I am SORRY Step-by-step EXPLANATION: I doknow the Answer

29.

Yadi samikaran 2x2+kx-150 ka mul -5 hai aur p(X2+x)+k=0 ke mul ke saman hai to k=?

Answer» ONG>ANSWER:

I am SORRY

Step-by-step EXPLANATION:

I doknow the Answer

Discussion

30.	Subtract 2M1) 126 m 56 cm from 170m 41 cm
Answer» ONG>Answer: 43M 85 cm Step-by-step explanation: 1 m = 100cm 126 m and 56cm = 12656cm 170m 41 cm = 17041 subtract : 17041 - 12656 = 4385cm Ans in m: 4380 ÷ 100 = 43m 85cm all the best MARK me brainliest

30.

Subtract 2M1) 126 m 56 cm from 170m 41 cm

Answer» ONG>Answer:

43M 85 cm

Step-by-step explanation:

1 m = 100cm

126 m and 56cm = 12656cm

170m 41 cm = 17041

subtract : 17041 - 12656 = 4385cm

Ans in m: 4380 ÷ 100 = 43m 85cm

all the best

MARK me brainliest

Discussion

31.	Which of the following is the value of k, if one root of the quadratic equation x2 + kx - 8 = 0 is -4 a) 0 b) 2c) 4 d) -4
Answer» ONG>Answer: HEY! Pls REFER to the attatched IMAGE for answer.

31.

Which of the following is the value of k, if one root of the quadratic equation x2 + kx - 8 = 0 is -4 a) 0 b) 2c) 4 d) -4

Answer» ONG>Answer:

HEY!

Pls REFER to the attatched IMAGE for answer.

Discussion

32.	Integration of 1/(1+e^x).e^x
Answer» ONG>ANSWER: jwjwisieodoisisisidisisisidididididixhhehxjebxjx

Discussion

33.	1+4=52+5=123+6=215+8=? Please Explain How it Came
Answer» ONG>ANSWER: answer 34 Step-by-step explanation: 1+4 =5 5+2+5=12 12+3+6=21 21+5+8=34 hope it is HELPFUL to you..

33.

1+4=52+5=123+6=215+8=? Please Explain How it Came

Answer» ONG>ANSWER:

answer 34

Step-by-step explanation:

1+4 =5

5+2+5=12

12+3+6=21

21+5+8=34

hope it is HELPFUL to you..

Discussion

34.	Out of the following, which point lies to the right of the origin on X axis ? a) ( -2, 0 ) b) ( 2, 0 )c) ( 2, 3 ) d) ( 0, 2 )
Answer» ONG>ANSWER: a) (-2,0) is the CORRECT OPTION

Discussion

35.	If cos60 × sec∅=1, write the value of ∅
Answer» ong>Answer: cos60 × sec60= 1 Step-by-step EXPLANATION: cos60 =1/2 cse60= 2 cos60 ×sec60 = (1/2)×(2) = 1

35.

If cos60 × sec∅=1, write the value of ∅

Answer»

ong>Answer:

cos60 × sec60= 1

Step-by-step EXPLANATION:

cos60 =1/2

cse60= 2

cos60 ×sec60 = (1/2)×(2)

= 1

Discussion

36.	Mohan draw a line on graph paper his friend sohan wants to draw another line on this graph paper such that the line intersect mohan 's line at point (1,6) and parallel to x-axis on the above situation give the answer for any 4 from the following questions. (a) what the equation of Mohan's line that is drawn on graph?(b) what is the point of intersection of these two lines?(c) what is the distance of Sohan's line from x-axis.(d) what is the name of point where x-axis and y-axis meet, Also write it's co-ordinate.
Answer» ONG>Step-by-step EXPLANATION: a)y-6=o b)(1,6) c)6 units d)origin and it's co-ordinates are (0,0)

36.

Mohan draw a line on graph paper his friend sohan wants to draw another line on this graph paper such that the line intersect mohan 's line at point (1,6) and parallel to x-axis on the above situation give the answer for any 4 from the following questions. (a) what the equation of Mohan's line that is drawn on graph?(b) what is the point of intersection of these two lines?(c) what is the distance of Sohan's line from x-axis.(d) what is the name of point where x-axis and y-axis meet, Also write it's co-ordinate.

Answer» ONG>Step-by-step EXPLANATION:

a)y-6=o

b)(1,6)

c)6 units

d)origin and it's co-ordinates are (0,0)

Discussion

37.	A circular flower bed is surrounded by a path 4 m wide. The diameter of the flower bed is 66 m. What is the area of this path?(π = 3.14)Note: ➠ Kindly Don't Spam➠ Need Quality Answer
Answer» _____________________ We have given that, the diameter of the FLOWER bed d = 66 meter= 2r r = 33 meter Find out, Area (A) of the path =? $\huge \underline \mathfrak{answer}$ Width of the path which is surrounded by the circular flower bed = 4 m Now the radius of total circular flower bed INCLUDING the path R = (33+4)= 37 m Now the required area A $= π{R^2-r^2} \\ A = π {37^2–33^2}= π [(37+33)(37–33)] \\ A =\frac{22}{7} \times {70×4}= 880$ square m. $\fbox \pink {d}\fbox \green {a} \fbox \blue {r} \fbox \red {k} \fbox \purple {s} \fbox \orange {h} \fbox \pink {a} \fbox \green{d} \fbox \blue{o} \fbox \red{w} \fbox \purple{7083}$

37.

A circular flower bed is surrounded by a path 4 m wide. The diameter of the flower bed is 66 m. What is the area of this path?(π = 3.14)Note: ➠ Kindly Don't Spam➠ Need Quality Answer

Answer»

_____________________

We have given that, the diameter of the FLOWER bed d = 66 meter= 2r

r = 33 meter

Find out, Area (A) of the path =?

$\huge \underline \mathfrak{answer}$

Width of the path which is surrounded by the circular flower bed = 4 m

Now the radius of total circular flower bed INCLUDING the path R = (33+4)= 37 m

Now the required area A

$= π{R^2-r^2} \\ A = π {37^2–33^2}= π [(37+33)(37–33)] \\ A =\frac{22}{7} \times {70×4}= 880$ square m.

$\fbox \pink {d}\fbox \green {a} \fbox \blue {r} \fbox \red {k} \fbox \purple {s} \fbox \orange {h} \fbox \pink {a} \fbox \green{d} \fbox \blue{o} \fbox \red{w} \fbox \purple{7083}$

Discussion

38.	Is milk dairy 25,06,736 Litres of milk had come in the moring Among which 15,67,540 Lites of milk was sold. Then again in the aftemoon 15,65,740 Litres of milk had come ifest 25,00,756 Litres of milk was sold then what is the remaining quantity of milk?A 4.500 LitresB. 4,209 Litres C. 4,020 Litres D. 4,300 Litres
Answer» ong>Answer: ❣❣❣❣ REPORT MY ALL QUESTION I GIVE 10 THANKS ❤ AND FREEE 25 POINTS

38.

Is milk dairy 25,06,736 Litres of milk had come in the moring Among which 15,67,540 Lites of milk was sold. Then again in the aftemoon 15,65,740 Litres of milk had come ifest 25,00,756 Litres of milk was sold then what is the remaining quantity of milk?A 4.500 LitresB. 4,209 Litres C. 4,020 Litres D. 4,300 Litres

Answer»

ong>Answer:

❣❣❣❣

REPORT MY ALL QUESTION I GIVE 10 THANKS ❤

AND FREEE 25 POINTS

Discussion

39.	The number of digits in the square root of 11664 is
Answer» ONG>Step-by-step EXPLANATION: Serial_attitude_girl55

39.

The number of digits in the square root of 11664 is

Answer» ONG>Step-by-step EXPLANATION:

Serial_attitude_girl55

Discussion

40.	What is reduced form of 44:100.
Answer» WER : ) 11:25 $\sf{ \red{ɧơ℘ɛ \: ɬɧıʂ \: ɧɛƖ℘ʂ \: ყơų}}$

40.

What is reduced form of 44:100.

Answer» WER : )

11:25

$\sf{ \red{ɧơ℘ɛ \: ɬɧıʂ \: ɧɛƖ℘ʂ \: ყơų}}$

Discussion

41.	Et Base ofandthe parallel is 20 cmheight is 15cm , find its area
Answer» ong>Answer: I think you have MADE some MISTAKE in the QUESTION .. Step-by-step EXPLANATION:

41.

Et Base ofandthe parallel is 20 cmheight is 15cm , find its area

Answer»

ong>Answer:

I think you have MADE some MISTAKE in the QUESTION ..

Step-by-step EXPLANATION:

Discussion

42.	)Area of right angle triangle is 24cm2 and perimeter is 24cm. find the lengths of sides of triangle ?
Answer» ONG>Answer: sides: 8,6 10 All the best Step-by-step explanation: If the Area and PERIMETER of right triangle will same then we can solve it as mentioned below Given A(area)=24 and P(perimeter)=24, Formula: side a: =(P2 + 4A + √((P2 + 4A)² - 32AP²)/4P side B: =(P2 + 4A - √((P2 + 4A)² - 32AP²)/4P side c: = √(a²+ b²) Well a =(P2 + 4A + √((P2 + 4A)² - 32AP²)/4P =8 a =(P2 + 4A - √((P2 + 4A)² - 32AP²)/4P = 6 c =√(a²+ b²) =√(8²+ 6²) =√100 =10 All the best Pls Mark me BRAINLIEST

42.

)Area of right angle triangle is 24cm2 and perimeter is 24cm. find the lengths of sides of triangle ?

Answer» ONG>Answer:

sides: 8,6 10

All the best

Step-by-step explanation:

If the Area and PERIMETER of right triangle will same then we can solve it as mentioned below

Given A(area)=24 and P(perimeter)=24,

Formula:

side a: =(P2 + 4A + √((P2 + 4A)² - 32AP²)/4P

side B: =(P2 + 4A - √((P2 + 4A)² - 32AP²)/4P

side c: = √(a²+ b²)

Well

a =(P2 + 4A + √((P2 + 4A)² - 32AP²)/4P

=8

a =(P2 + 4A - √((P2 + 4A)² - 32AP²)/4P

= 6

c =√(a²+ b²)

=√(8²+ 6²)

=√100

=10

All the best

Pls Mark me BRAINLIEST

Discussion

43.	Draw a line segment of length 8.4cm and divide it in the ratio 5:3please give right answer
Answer» 3> $\huge{\underline{\purple{\mathfrak{♡Refer -attachment ♡}}}}$ ⠀⠀ $\red{Thanks\: a\; lot . . .}$ ❥︎ HOPE its helpful࿐

43.

Draw a line segment of length 8.4cm and divide it in the ratio 5:3please give right answer

Answer» 3>

$\huge{\underline{\purple{\mathfrak{♡Refer -attachment ♡}}}}$ ⠀⠀

$\red{Thanks\: a\; lot . . .}$

❥︎ HOPE its helpful࿐

Discussion

44.	The ratio of the ages of father and son at present is 6: 1. After 5 years the ratio will become 7:2. Find the present age of the son?
Answer» ong>Answer: The present age of the son is 5 years. Step-by-step-explanation: We have given that, The ratio of the present AGES of father and son is 6 : 1. Let the common multiple be X. ∴ Father's present age = 6x years And son's present age = x years Now, After 5 years, father's age = ( 6x + 5 ) years And after 5 years, son's age = ( x + 5 ) years From the given condition, $\displaystyle{\sf\:\dfrac{(\:6x\:+\:5\:)}{(\:x\:+\:5\:)}\:=\:\dfrac{7}{2}}$ $\displaystyle{\implies\sf\:2\:\times\:(\:6x\:+\:5\:)\:=\:7\:\times\:(\:x\:+\:5\:)}$ $\displaystyle{\implies\sf\:12x\:+\:10\:=\:7x\:+\:35}$ $\displaystyle{\implies\sf\:12x\:-\:7x\:=\:35\:-\:10}$ $\displaystyle{\implies\sf\:5x\:=\ 25}$ $\displaystyle{\implies\sf\:x\:=\:\cancel{\dfrac{25}{5}}}$ $\displaystyle{\implies\underline{\boxed{\red{\sf\:x\:=\:5\:}}}}$ ∴ The present age of the son is 5 years.

44.

The ratio of the ages of father and son at present is 6: 1. After 5 years the ratio will become 7:2. Find the present age of the son?

Answer»

ong>Answer:

The present age of the son is 5 years.

Step-by-step-explanation:

We have given that,

The ratio of the present AGES of father and son is 6 : 1.

Let the common multiple be X.

∴ Father's present age = 6x years

And son's present age = x years

Now,

After 5 years, father's age = ( 6x + 5 ) years

And after 5 years, son's age = ( x + 5 ) years

From the given condition,

$\displaystyle{\sf\:\dfrac{(\:6x\:+\:5\:)}{(\:x\:+\:5\:)}\:=\:\dfrac{7}{2}}$

$\displaystyle{\implies\sf\:2\:\times\:(\:6x\:+\:5\:)\:=\:7\:\times\:(\:x\:+\:5\:)}$

$\displaystyle{\implies\sf\:12x\:+\:10\:=\:7x\:+\:35}$

$\displaystyle{\implies\sf\:12x\:-\:7x\:=\:35\:-\:10}$

$\displaystyle{\implies\sf\:5x\:=\ 25}$

$\displaystyle{\implies\sf\:x\:=\:\cancel{\dfrac{25}{5}}}$

$\displaystyle{\implies\underline{\boxed{\red{\sf\:x\:=\:5\:}}}}$

∴ The present age of the son is 5 years.

Discussion

45.	B. Two places C. Five places23.In Hindu - Arabic Number system, How many nurnber indicators will be used?A HundredB. TwelveC. zeroD. Nine.
Answer» WER: the option D.Nine Explanation: our own number SYSTEM, COMPOSED of the 10 symbols{0,1,2,3,4,5,6,7,8,9} is called Hindu ARABIC system.

45.

B. Two places C. Five places23.In Hindu - Arabic Number system, How many nurnber indicators will be used?A HundredB. TwelveC. zeroD. Nine.

Answer» WER:

the option D.Nine

Explanation:

our own number SYSTEM, COMPOSED of the 10 symbols{0,1,2,3,4,5,6,7,8,9} is called Hindu ARABIC system.

Discussion

46.	Evaluate limx (x+1)7 -1 /x
Answer» ONG>ANSWER: Jwirjhthh and the REST are

Discussion

47.	एक हॉकी का सैदान 1 मीटर ५० सेंटीमीटर लंबा और 55 मीटर चौड़ा है। मैदान के घेरेकी लम्बाईकितनी होगी..
Answer» ONG>Step-by-step EXPLANATION: dbdbdjdhdhdhdhdhdhdkdkdkdh

47.

एक हॉकी का सैदान 1 मीटर ५० सेंटीमीटर लंबा और 55 मीटर चौड़ा है। मैदान के घेरेकी लम्बाईकितनी होगी..

Answer» ONG>Step-by-step EXPLANATION:

dbdbdjdhdhdhdhdhdhdkdkdkdh

Discussion

48.	+×+=?
Answer» > $+ \times + = +$ is the ANSWER

48.

+×+=?

Answer»

>

$+ \times + = +$

is the ANSWER

Discussion

49.	3. लायपस्पशी असलेल्या दोन वळाच्या त्रिज्या अनुक्रम55वसेमा आहेत तर त्यांच्या देशातीलअतर किती असिल
Answer» ONG>ANSWER: yzizgsogovs gaisvsosbgsos

Discussion

50.	यदि शहर में 40% और 30%पुरुष और बाकी बच्चों है तो बच्चों की संख्या प्ज्ञात करें
Answer» ER: ●यदि शहर में 40% और 30%पुरुष और बाकी बच्चों है तो बच्चों की संख्या 30•/• होगी।

Discussion

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