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A circular flower bed is surrounded by a path 4 m wide. The diameter of the flower bed is 66 m. What is the area of this path?(π = 3.14)Note: ➠ Kindly Don't Spam➠ Need Quality Answer ​

Answer»

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We have given that, the diameter of the FLOWER bed d = 66 meter= 2r

r = 33 meter

Find out, Area (A) of the path =?

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Width of the path which is surrounded by the circular flower bed = 4 m

Now the radius of total circular flower bed INCLUDING the path R = (33+4)= 37 m

Now the required area A

= π{R^2-r^2} \\ A = π {37^2–33^2}= π [(37+33)(37–33)] \\ A =\frac{22}{7} \times {70×4}= 880square m.

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