332354 + Interview Questions in Secondary School in Math

1.	एक मैदान 200 मीटर लंबा और 100 मीटर चौड़ा है इसमें 50 मीटर× 41 मीटर× 3.5 मीटर का तालाब को दिया गया और उसकी मिट्टी को शेष मैदान में बराबर फैलाया गया है बताएं शेष मैदान का धरातल कितना ऊंचा उठ जाएगा।
Answer» ONG>Step-by-step explanation: *PLEASE* *MARK* ME AS BRAINLIEST

Discussion

2.	2. Factorize x3-x?+ax+x-a-1.
Answer» ONG>Step-by-step EXPLANATION: x³+x²+ax+x-a-1 wish you will drop some thanks and mark it BRAINLIST

2.

2. Factorize x3-x?+ax+x-a-1.

Answer» ONG>Step-by-step EXPLANATION:

x³+x²+ax+x-a-1

wish you will drop some thanks

and mark it BRAINLIST

Discussion

3.	Two identical cubes of side 7cm are joined end to end. Find the total and lateral surface area
Answer» ong>Step-by-step EXPLANATION: Given, the side of a CUBE is 7 cm TOTAL surface area of cube =6×(side) 2 =6×7×7 =294 ∴ the total surface area of cube is 294 cm 2 . lateral surface area =2×7(7+14) =14×21 =294

3.

Two identical cubes of side 7cm are joined end to end. Find the total and lateral surface area

Answer»

ong>Step-by-step EXPLANATION:

Given, the side of a CUBE is 7 cm

TOTAL surface area of cube =6×(side)

2

=6×7×7

=294

∴ the total surface area of cube is 294 cm

2

.

lateral surface area =2×7(7+14)

=14×21

=294

Discussion

4.	1/3&3/5rational number
Answer» ONG>Step-by-step EXPLANATION: OK okokokokokokokokok

Discussion

5.	85. prove that tangent drawn at any,point of circle is perpendicular tothe radius through the point ofcontact
Answer» ong>Answer: Construction : TAKE a point B, other than A, on the tangent l. ... Proof: We know that, among all line segment joining the point O to a point on l, the perpendicular is SHORTEST to l. OA = OC (Radius of the same circle) Now, OB = OC + BC. Step-by-step EXPLANATION: Mark me as Brainlist

5.

85. prove that tangent drawn at any,point of circle is perpendicular tothe radius through the point ofcontact

Answer»

ong>Answer:

Construction : TAKE a point B, other than A, on the tangent l. ... Proof: We know that, among all line segment joining the point O to a point on l, the perpendicular is SHORTEST to l. OA = OC (Radius of the same circle) Now, OB = OC + BC.

Step-by-step EXPLANATION:

Mark me as Brainlist

Discussion

6.	Find the product of 2x2 y2 , 3y2 Z and Z2 × 3 = b = 7cm
Answer» ONG>Answer: 2️ Step-by-step EXPLANATION:

6.

Find the product of 2x2 y2 , 3y2 Z and Z2 × 3 = b = 7cm

Answer» ONG>Answer:

2️

Step-by-step EXPLANATION:

Discussion

7.	Find the no. which when multiplied by 8and then reduced by 9 gives 47 i.e. equal to 47
Answer» rong>ɢɪᴠᴇɴ: A number which when MULTIPLIED by 8 and then reduced by 9 is EQUAL to 47 ᴛᴏ ғɪɴᴅ: The number sᴏʟᴜᴛɪᴏɴ: LET us suppose the required number as x ________________________________ ᴀᴄᴄᴏʀᴅɪɴɢ ᴛᴏ ǫᴜᴇsᴛɪᴏɴ:- (The number when multiplied by 8 and then reduced by 9 is equal to 47) Let's DISCOVER the number now:- ⇝8 × x-9=47 ⇝8x-9=47 ⇝8x=47+9 ⇝8x=56 ⇝x=56÷8 ⇝x=7 Hence, the required number is 7 ________________________________

7.

Find the no. which when multiplied by 8and then reduced by 9 gives 47 i.e. equal to 47

Answer»

rong>ɢɪᴠᴇɴ:

A number which when MULTIPLIED by 8 and then reduced by 9 is EQUAL to 47

ᴛᴏ ғɪɴᴅ:

The number

sᴏʟᴜᴛɪᴏɴ:

LET us suppose the required number as x

________________________________

ᴀᴄᴄᴏʀᴅɪɴɢ ᴛᴏ ǫᴜᴇsᴛɪᴏɴ:-

(The number when multiplied by 8 and then reduced by 9 is equal to 47)

Let's DISCOVER the number now:-

⇝8 × x-9=47

⇝8x-9=47

⇝8x=47+9

⇝8x=56

⇝x=56÷8

⇝x=7

Hence, the required number is 7

________________________________

Discussion

8.	Using a ruler and a pair of compare the contact angle of the following measure 300 and 900
Answer» ong>ANSWER: the ANGLE measure are given in MATHEMATICS book of following measure 300 and 900 degree is the ruler is the answers

8.

Using a ruler and a pair of compare the contact angle of the following measure 300 and 900

Answer»

ong>ANSWER:

the ANGLE measure are given in MATHEMATICS book of following measure 300 and 900 degree is the ruler is the answers

Discussion

9.	Find the minimum and maximum value
Answer» ONG>ANSWER: WRITE the QUESTION PROPERLY

9.

Find the minimum and maximum value

Answer» ONG>ANSWER:

WRITE the QUESTION PROPERLY

Discussion

10.	B] (i)The marks scored in a Mathematics Test by 40 students of class 7 are recorded as below.46 51 36 46. 65 73 28 45 38 58 63 62526942685454553948716832535034724161534666354359412645Prepare a grouped frequency distribution table taking classes 20 - 30 , 30 - 40
Answer» ong>Answer: OKOK OK o KO ok ok ok k o k okokoo ok ok ok o ko o 9k o klammeii

10.

B] (i)The marks scored in a Mathematics Test by 40 students of class 7 are recorded as below.46 51 36 46. 65 73 28 45 38 58 63 62526942685454553948716832535034724161534666354359412645Prepare a grouped frequency distribution table taking classes 20 - 30 , 30 - 40

Answer»

ong>Answer:

OKOK OK o KO ok ok ok k o k okokoo ok ok ok o ko o 9k o klammeii

Discussion

11.	एक समढ़िवाह समकोण त्रिजKL.M की स्वजा करेंयहाँm_KML = 90° BIR KM = 6सेमी है।
Answer» ONG>ANSWER: MADAR brother and FATHER

Discussion

12.	Find the value of the polynomial 5x – 4x2 + 3 at x = – 3
Answer» ONG>Answer: The value is -48 Step-by-step explanation: 5x - 4x² + 3 put x = -3 5(-3) - 4(-3)² + 3 -15 - 4(9) + 3 - 15 - 36 + 3 - 15 - 33 = - 48

12.

Find the value of the polynomial 5x – 4x2 + 3 at x = – 3

Answer» ONG>Answer:

The value is -48

Step-by-step explanation:

5x - 4x² + 3

put x = -3

5(-3) - 4(-3)² + 3

-15 - 4(9) + 3

- 15 - 36 + 3

- 15 - 33

= - 48

Discussion

13.	1. So, -1/2 would be marked at a pointhalf the distance between 0 and -1.
Answer» rong>From the two green lines on the photo, as well as the camera's field of VIEW, you can determine the visual angle α0α0 of the slope as seen from the camera. From the two green lines on the photo, as well as the camera's field of view, you can determine the visual angle α0α0 of the slope as seen from the camera.Given a distance DD from the slope, you can determine the visual angle α(D)α(D) of the slope as seen from a camera at distance DD from the slope, since you know the position of that camera and both ENDS of the slope. Note that α(D)α(D) is strictly MONOTONOUS in DD. Your aim is now to find D0D0 such that α(D0)=α0α(D0)=α0. This can be numerically solved using half-interval search or Newton's method (Newton's method will converge if D0>0D0>0 and your initial value for DD is 00).

13.

1. So, -1/2 would be marked at a pointhalf the distance between 0 and -1.

Answer»

rong>From the two green lines on the photo, as well as the camera's field of VIEW, you can determine the visual angle α0α0 of the slope as seen from the camera.

From the two green lines on the photo, as well as the camera's field of view, you can determine the visual angle α0α0 of the slope as seen from the camera.Given a distance DD from the slope, you can determine the visual angle α(D)α(D) of the slope as seen from a camera at distance DD from the slope, since you know the position of that camera and both ENDS of the slope. Note that α(D)α(D) is strictly MONOTONOUS in DD. Your aim is now to find D0D0 such that α(D0)=α0α(D0)=α0. This can be numerically solved using half-interval search or Newton's method (Newton's method will converge if D0>0D0>0 and your initial value for DD is 00).

Discussion

14.	और का मानहातको8080+मDoA250soLory664
Answer» ong>Answer: 1] y=80°{VERTICALLY OPPOSITE angle} X=50°{Angle SUM PROPERTY}

14.

और का मानहातको8080+मDoA250soLory664

Answer»

ong>Answer:

1] y=80°{VERTICALLY OPPOSITE angle}

X=50°{Angle SUM PROPERTY}

Discussion

15.	∆ABC is right angled at A and AD ┴ BC, divides BC such that AD2 = BD.CD.If AD= 4 cm and BD =2 cm, Find BC.
Answer» ong>ANSWER: In triangle ABC , AD is perpendicular to BC and AD² = BD.DC To prove : BAC = 90° Proof : in right triangles ∆ADB and ∆ADC So

15.

∆ABC is right angled at A and AD ┴ BC, divides BC such that AD2 = BD.CD.If AD= 4 cm and BD =2 cm, Find BC.

Answer»

ong>ANSWER:

In triangle ABC , AD is perpendicular to BC and AD² = BD.DC To prove : BAC = 90° Proof : in right triangles ∆ADB and ∆ADC So

Discussion

16.	X + 2y = 1, x – 2y = -7, also read the points from the graph where the lines meet the x-axis and y-axis. No spam
Answer» Equations :- X + 2Y = 1 x + y = 1 - 2 x + y = -1 2. Equations :- x - 2y = -7 x - y = -7 + 2 x - y = -5 $\\$ [email protected]TheBrainlyGod

16.

X + 2y = 1, x – 2y = -7, also read the points from the graph where the lines meet the x-axis and y-axis. No spam

Answer»

Equations :-

X + 2Y = 1

x + y = 1 - 2

x + y = -1

2. Equations :-

x - 2y = -7

x - y = -7 + 2

x - y = -5

$\\$

[email protected]TheBrainlyGod

Discussion

17.	Explain (-6) X(-6)= (-6).
Answer» ONG>Answer: 36 =-6x -6 = x Step-by-step EXPLANATION: HOPE it HELPS!!

17.

Explain (-6) X(-6)= (-6).

Answer» ONG>Answer:

36 =-6x

-6 = x

Step-by-step EXPLANATION:

HOPE it HELPS!!

Discussion

18.	Find the cost of renovating the walls and the floor of a hall that measures 10 m × 45 m × 6 m. If the cost is Rs 48 per sq. m.
Answer» ONG>Answer: 53280 Step-by-step EXPLANATION: the steps are SHOWN in the picture hope this helps you

18.

Find the cost of renovating the walls and the floor of a hall that measures 10 m × 45 m × 6 m. If the cost is Rs 48 per sq. m.

Answer» ONG>Answer:

53280

Step-by-step EXPLANATION:

the steps are SHOWN in the picture

hope this helps you

Discussion

19.	Cos20 + cos30+cos40 is equals to
Answer» ONG>ANSWER: Cos20+Cos30+Cos40=-0.10460454995

Discussion

20.	a vendor supplies 32 litres of milk to a hotel in the morning and 68 litres of milk in the evening if the milk cost 15 per litre how much money is due to the window pade
Answer» Step-by-step EXPLANATION: ANSWER. HENCE, If the milk costs Rs. 15per liter, then Rs 1500 is due to the vendor per DAY.

20.

a vendor supplies 32 litres of milk to a hotel in the morning and 68 litres of milk in the evening if the milk cost 15 per litre how much money is due to the window pade

Answer»

Step-by-step EXPLANATION:

ANSWER. HENCE, If the milk costs Rs. 15per liter, then Rs 1500 is due to the vendor per DAY.

Discussion

21.	I) sin30° + cos 45° + tan180°
Answer» ONG>ANSWER: sin30° + COS 45° + tan180°= 1.2071067811865

Discussion

22.	Hammer tongs kinife axe odd one and why
Answer» ong>ANSWER: where is odd EVEN because knife and acts are things which is used to CUT but hammer is used to to make it thin or put any nail inside Step-by-step EXPLANATION: *PLEASE* *MARK* ME AS BRAINLIEST

22.

Hammer tongs kinife axe odd one and why

Answer»

ong>ANSWER:

where is odd EVEN because knife and acts are things which is used to CUT but hammer is used to to make it thin or put any nail inside

Step-by-step EXPLANATION:

PLEASE MARK ME AS BRAINLIEST

Discussion

23.	For study related talks uaqfqrrbxj
Answer» ONG>ANSWER: GCHH he jiji fyvbhbhvj ififiu

23.

For study related talks uaqfqrrbxj

Answer» ONG>ANSWER:

GCHH he jiji fyvbhbhvj ififiu

Discussion

24.	You must have observed that quite often, in gardens or parks, some space is left all around in the form of path or in between as cross paths. A framed picture has some space left all around it.We need to find the areas of such pathways or borders when we want to find the cost of making them. A rectangular park is 45 m long and 30 m wide.A path 2.5 m wide is constructed3 3outside the park. Find the area of the path.
Answer» ong>Answer: 1350sq.units Step-by-step explanation: 45m long 30M WIDE Area of the RECTANGLE FORMULA is length×breadth so, 45×30=1350

24.

You must have observed that quite often, in gardens or parks, some space is left all around in the form of path or in between as cross paths. A framed picture has some space left all around it.We need to find the areas of such pathways or borders when we want to find the cost of making them. A rectangular park is 45 m long and 30 m wide.A path 2.5 m wide is constructed3 3outside the park. Find the area of the path.

Answer»

ong>Answer:

1350sq.units

Step-by-step explanation:

45m long

30M WIDE

Area of the RECTANGLE FORMULA is length×breadth

so, 45×30=1350

Discussion

25.	The value of a machine, purchased two years ago, deprecaites at the annual rate of 10%. It its present value is Rs97200, find : (i) its value after 3 years and (ii) its value when it was purchased.
Answer» ONG>ANSWER: xjdwjruriddiffifiri Step-by-step EXPLANATION: frhgsfhhgfdethh

25.

The value of a machine, purchased two years ago, deprecaites at the annual rate of 10%. It its present value is Rs97200, find : (i) its value after 3 years and (ii) its value when it was purchased.

Answer» ONG>ANSWER:

xjdwjruriddiffifiri

Step-by-step EXPLANATION:

frhgsfhhgfdethh

Discussion

26.	Plot the points on a graph.A(1,3) , B(-3,-1), C(1,-4)
Answer» ONG>Answer: first draw the graph like + symbol Step-by-step explanation: 1.) left side of graph take "-" value then right side "+" value top side "-" and bottom "+" 2.) (i) from origin point 1 on bottom and 3 on right (II) -3 on top and -1 on left (iii) 1 on right and -4 on top THANK you Mark me as a BRAINLIEST

26.

Plot the points on a graph.A(1,3) , B(-3,-1), C(1,-4)

Answer» ONG>Answer:

first draw the graph like + symbol

Step-by-step explanation:

1.) left side of graph take "-" value then right side "+" value top side "-" and bottom "+"

2.)

(i) from origin point 1 on bottom and 3 on right

(II) -3 on top and -1 on left

(iii) 1 on right and -4 on top

THANK you Mark me as a BRAINLIEST

Discussion

27.	A rectangular park is 45 m long and 30 mwide.A path 2.5 m wide is constructed outside the park . Find area of the path
Answer» ong>Answer: Step-by-step explanation: AREA of park =l×b=45×30=1350 cm square Area of park with PATH is =45+2.5+2.5×30+2.5+2.5=1750 cm square THEREFORE, Area of path = Area of park with path − Area of RECTANGULAR park =1750−1350=400 cm square

27.

A rectangular park is 45 m long and 30 mwide.A path 2.5 m wide is constructed outside the park . Find area of the path

Answer»

ong>Answer:

Step-by-step explanation:

AREA of park =l×b=45×30=1350 cm square

Area of park with PATH is =45+2.5+2.5×30+2.5+2.5=1750 cm square

THEREFORE,

Area of path = Area of park with path − Area of RECTANGULAR park

=1750−1350=400 cm square

Discussion

28.	Simplify: 2/3 -3 -3V3+ V12.
Answer» ong>ANSWER: - √3 - 3 + √12 Step-by-step explanation: Refer to attachment .. Hope this will help U :)

28.

Simplify: 2/3 -3 -3V3+ V12.

Answer»

ong>ANSWER:

- √3 - 3 + √12

Step-by-step explanation:

Refer to attachment ..

Hope this will help U :)

Discussion

29.	Simplify (x-5) (x+5) +2
Answer» ONG>══════════════════════════ (x-5) (x+5) +2 FORMULA ⏬⏬ ➣ (a-b) (a+b) ➣ a²-b² ══════════════════════════ (x-5) (x+5) +2 x² - 5² + 2 x² - 25 + 2 x² - 23 ➖➖➖➖➖➖➖➖➖➖➖➖➖➖ HOPE IT HELPS

29.

Simplify (x-5) (x+5) +2

Answer» ONG>══════════════════════════

(x-5) (x+5) +2

FORMULA ⏬⏬

➣ (a-b) (a+b)

➣ a²-b²

══════════════════════════

(x-5) (x+5) +2

x² - 5² + 2

x² - 25 + 2

x² - 23

➖➖➖➖➖➖➖➖➖➖➖➖➖➖

HOPE IT HELPS

Discussion

30.	Which of the following is false A) Every rational number is a natural number. B) Every rational number is a whole number. C) every rational number is an integer. D) Every interger is a rational number
Answer» ong>Answer: Answer: Step-by-step explanation: (D) EVERY INTEGER is a RATIONAL NUMBER.

30.

Which of the following is false A) Every rational number is a natural number. B) Every rational number is a whole number. C) every rational number is an integer. D) Every interger is a rational number

Answer»

ong>Answer:

Answer:

Step-by-step explanation:

(D) EVERY INTEGER is a RATIONAL NUMBER.

Discussion

31.	If tan A = find value of sin A* CosB +Cos A *SinB
Answer» ong>ANSWER: Sending sinA and COSA to one side then sinB and cosB to another side sin/cos is TAN tanA =√3 tanB=√3 √3+√3 = √6 THANK YOU , MARK ME AS A BRAINLIEST

31.

If tan A = find value of sin A* CosB +Cos A *SinB

Answer»

ong>ANSWER:

Sending sinA and COSA to one side then sinB and cosB to another side

sin/cos is TAN

tanA =√3

tanB=√3

√3+√3 = √6

THANK YOU , MARK ME AS A BRAINLIEST

Discussion

32.	A path 2.5m wide is running around a square field whose side is 45m determine the area of the path
Answer» ong>Answer: side of square field is 45m path around the square field is 2.5m WIDE so, the side of field with the path = 45+2.5 = 47.5m so, the AREA of field with path = side×side = 47.5×47.5 2256.25 m^2 area of field = 45×45 2025m^2 area of path = area of field with path - area of field = 2256.25 - 2025 231.25 m^2 THANKS

32.

A path 2.5m wide is running around a square field whose side is 45m determine the area of the path

Answer»

ong>Answer:

side of square field is 45m

path around the square field is 2.5m WIDE

so, the side of field with the path = 45+2.5

= 47.5m

so, the AREA of field with path = side×side

= 47.5×47.5

2256.25 m^2

area of field = 45×45

2025m^2

area of path = area of field with path - area of field

= 2256.25 - 2025

231.25 m^2

THANKS

Discussion

33.	What type of fraction is 638 ÷100 ?
Answer» = 319/50 = 619/50 as a fraction Step by Step Solution To convert 638 PERCENT to a fraction follow these steps: Step 1: Write down the percent divided by 100 like this: 638% = 638/100 Step 2: Multiply both top and bottom by 10 for every number after the DECIMAL point: As 638 is an integer, we don't have numbers after the decimal point. So, we just go to step 3. Step 3: Simplify (or reduce) the above fraction by dividing both NUMERATOR and denominator by the GCD (Greatest Common Divisor) between them. In this case, GCD(638,100) = 2. So, (638÷2)/(100÷2) = 319/50 when reduced to the simplest form. As the numerator is greater than the denominator, we have an IMPROPER fraction, so we can also express it as a MIXED NUMBER, thus 638/100 is also EQUAL to 6 19/50 when expressed as a mixed number.

33.

What type of fraction is 638 ÷100 ?

Answer»

= 319/50 = 619/50 as a fraction

Step by Step Solution

To convert 638 PERCENT to a fraction follow these steps:

Step 1: Write down the percent divided by 100 like this:

638% = 638/100

Step 2: Multiply both top and bottom by 10 for every number after the DECIMAL point:

As 638 is an integer, we don't have numbers after the decimal point. So, we just go to step 3.

Step 3: Simplify (or reduce) the above fraction by dividing both NUMERATOR and denominator by the GCD (Greatest Common Divisor) between them. In this case, GCD(638,100) = 2. So,

(638÷2)/(100÷2) = 319/50 when reduced to the simplest form.

As the numerator is greater than the denominator, we have an IMPROPER fraction, so we can also express it as a MIXED NUMBER, thus 638/100 is also EQUAL to 6 19/50 when expressed as a mixed number.

Discussion

34.	Find the HCF 396,504,636
Answer» ONG>Answer: 396= 1122333 504=722233 636=53223 HCF =223= 12 Step-by-step explanation:*

34.

Find the HCF 396,504,636

Answer» ONG>Answer:

396= 11*2*2*3*3*3

504=7*2*2*2*3*3

636=53*2*2*3

HCF =2*2*3= 12

Step-by-step explanation:

Discussion

35.	1/8 of 1 litre (in millilitre)
Answer» ONG>ANSWER: its. 0.15 litres mark me as BRAINLIEST

35.

1/8 of 1 litre (in millilitre)

Answer» ONG>ANSWER:

its.

0.15 litres

mark me as BRAINLIEST

Discussion

36.	1/5 of 1/4 of a no will be 25
Answer» ONG>ANSWER: no Step-by-step explanation: 1/4-1/5 = LCM. ans 20 so = 1×5-1×4by 20 = 5-4by20 1/20 is answer ( / ) is samble of (by)

36.

1/5 of 1/4 of a no will be 25

Answer» ONG>ANSWER:

no

Step-by-step explanation:

1/4-1/5

= LCM. ans 20 so

= 1×5-1×4by 20

= 5-4by20

1/20 is answer

( / ) is samble of (by)

Discussion

37.	If 2^8=2^x^3,then value of x
Answer» ONG>Answer: x is 2 Step-by-step explanation: 2⁸ = 2ˣ³ if bases are equal then their POWERS will ALSO same So, x³ = 8 (8 = 2 x 2 x 2 = 2³) x³ = (2)³ ∵ x = 2

37.

If 2^8=2^x^3,then value of x

Answer» ONG>Answer:

x is 2

Step-by-step explanation:

2⁸ = 2ˣ³

if bases are equal then their POWERS will ALSO same

So,

x³ = 8

(8 = 2 x 2 x 2 = 2³)

x³ = (2)³

∵

x = 2

Discussion

38.	Eआई वांट सॉन्ग सर्कल्स सॉन्ग
Answer» ONG>ANSWER: s8sjdjjf ndkdkdnd djdmd C

Discussion

39.	યુક્લિડે Elements ને _______ પ્રકરણોમાં વિભાજિત કયું. std-9 maths
Answer» ong>ANSWER: Answer is 13 Step-by-step EXPLANATION: I THINK IT IS HELPFUL FOR YOU

39.

યુક્લિડે Elements ને _______ પ્રકરણોમાં વિભાજિત કયું. std-9 maths

Answer»

ong>ANSWER:

Answer is 13

Step-by-step EXPLANATION:

I THINK IT IS HELPFUL FOR YOU

Discussion

40.	Represent the on number line
Answer» er: Step-by-step explanation: Would be so MUCH for your support of the year OLD girl I don't KNOW what you think about it is not GOING to be a great DAY was a great day

40.

Represent the on number line

Answer»

er:

Step-by-step explanation:

Would be so MUCH for your support of the year OLD girl I don't KNOW what you think about it is not GOING to be a great DAY was a great day

Discussion

41.	The value of 35x² ÷ 5x is
Answer» ONG>Answer: 7x is the answer Step-by-step EXPLANATION: HOPE it HELPS!!

41.

The value of 35x² ÷ 5x is

Answer» ONG>Answer:

7x is the answer

Step-by-step EXPLANATION:

HOPE it HELPS!!

Discussion

42.	A+b+c (ii) 1/a+1/b+1/c (iii) a²+b²+c².
Answer» ONG>Step-by-step explanation: (1−a)(1−C−b+bc) =1−c−b+bc−a+ac+ab =1−(a+b+c)+(ab+bc+ac) =1−1+ab+bc+ac = 2 2(ab+bc+ac) = 2 (a+b+c) 2 −(a 2 +b 2 +c 2 ) = 2 1−21 =−10

42.

A+b+c (ii) 1/a+1/b+1/c (iii) a²+b²+c².

Answer» ONG>Step-by-step explanation:

(1−a)(1−C−b+bc)

=1−c−b+bc−a+ac+ab

=1−(a+b+c)+(ab+bc+ac)

=1−1+ab+bc+ac

=

2

2(ab+bc+ac)

=

2

(a+b+c)

2

−(a

2

+b

2

+c

2

)

=

2

1−21

=−10

Discussion

43.	If (2, 0) is a solution of the linear equation 2x + 3y = k, then find the value ofk.
Answer» ong>Answer: 4 Step-by-step explanation: x=2 y=0 2(2)+3(0) 4+0 4

43.

If (2, 0) is a solution of the linear equation 2x + 3y = k, then find the value ofk.

Answer»

ong>Answer:

4

Step-by-step explanation:

x=2

y=0

2(2)+3(0)

4+0

4

Discussion

44.	स्त्री पर ऑफ एक्स इज इक्वल टू
Answer» ONG>ANSWER: hajagajiaiahanjajakkwjsjsksjksjeja

44.

स्त्री पर ऑफ एक्स इज इक्वल टू

Answer» ONG>ANSWER:

hajagajiaiahanjajakkwjsjsksjksjeja

Discussion

45.	22. A dress requires 15 m of cloth. How many such dresses can be made from a roll of cloth having 10whole 1/2 m of cloth? 23. The cost of 2whole 1/2kg of sweets is ₹77whole1/2. Find the cost of 3whole 1/4kg of sweets.
Answer» ong>Answer: hahahaha !! baby ❤️❤️ hahahaha .. sethipain mu Tate kebe B amiti KATHA kahunathili !! HAHAHA .. LOVE you baby ❤️❤️❤️ Hmm mu b jibi heri ❤️❤️ love you ☺️☺️

45.

22. A dress requires 15 m of cloth. How many such dresses can be made from a roll of cloth having 10whole 1/2 m of cloth? 23. The cost of 2whole 1/2kg of sweets is ₹77whole1/2. Find the cost of 3whole 1/4kg of sweets.

Answer»

ong>Answer:

hahahaha !! baby ❤️❤️

hahahaha .. sethipain mu Tate kebe B amiti KATHA kahunathili !! HAHAHA .. LOVE you baby ❤️❤️❤️

Hmm mu b jibi heri ❤️❤️ love you ☺️☺️

Discussion

46.	Find the values of x and y.ANSWER ME PLZ
Answer» ONG>ANSWER: please GIVE me brainlist MARK

46.

Find the values of x and y.ANSWER ME PLZ

Answer» ONG>ANSWER:

please GIVE me brainlist MARK

Discussion

47.	The difference between x and 4,where x is greater than 4
Answer» ONG>ANSWER: The DIFFERENCE between X and 4=x-4 Step-by-step explanation: Mark me brainliest

47.

The difference between x and 4,where x is greater than 4

Answer» ONG>ANSWER:

The DIFFERENCE between X and 4=x-4

Step-by-step explanation:

Mark me brainliest

Discussion

48.	Evaluate :sin18°+cos12° /cos18°-sin12°
Answer» ONG>Answer: t the best way is ESSEX junction CO and a good idea but the only time we spoke last PARA la la all is good and you are doing good in that it will not send anything in this message and all that stuff from your NVR the best way is Essex junction CO and a great time and effort

Discussion

49.	draw a line m.draw a perpendicular to m at any point on m on this perpendicular choose a point x ,4 cm away from m. draw a line n parallel to m through x.
Answer» ong>Step-by-step EXPLANATION: hey GIRLS CAME on it show ur and see rdr-wxug-naa

49.

draw a line m.draw a perpendicular to m at any point on m on this perpendicular choose a point x ,4 cm away from m. draw a line n parallel to m through x.

Answer»

ong>Step-by-step EXPLANATION:

hey GIRLS CAME on it show ur and see rdr-wxug-naa

Discussion

50.	27. The motion of a body of mass 5Kg is shown in the velocity-time graph given below:From graph, find15velocity, Couls)(i) its acceleration(ii) the force acting on the body(iii) Momentum of body at t = 7s.56Tue 05
Answer» Step-by-step EXPLANATION: WELCOME FRIENDS My MOBILE no.7428553948

50.

27. The motion of a body of mass 5Kg is shown in the velocity-time graph given below:From graph, find15velocity, Couls)(i) its acceleration(ii) the force acting on the body(iii) Momentum of body at t = 7s.56Tue 05

Answer»

Step-by-step EXPLANATION:

WELCOME FRIENDS

My MOBILE no.7428553948

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

PLEASE MARK ME AS BRAINLIEST

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sᴏʟᴜᴛɪᴏɴ:

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x is 2

2⁸ = 2ˣ³

if bases are equal then their POWERS will ALSO same

So,

x³ = 8

(8 = 2 x 2 x 2 = 2³)

x³ = (2)³

∵

x = 2

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Find the minimum and maximum value

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एक समढ़िवाह समकोण त्रिजKL.M की स्वजा करेंयहाँm_KML = 90° BIR KM = 6सेमी है।

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और का मानहातको8080+मDoA250soLory664

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1/5 of 1/4 of a no will be 25

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Eआई वांट सॉन्ग सर्कल्स सॉन्ग

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Represent the on number line

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If (2, 0) is a solution of the linear equation 2x + 3y = k, then find the value ofk.

स्त्री पर ऑफ एक्स इज इक्वल टू

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Find the values of x and y.ANSWER ME PLZ

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27. The motion of a body of mass 5Kg is shown in the velocity-time graph given below:From graph, find15velocity, Couls)(i) its acceleration(ii) the force acting on the body(iii) Momentum of body at t = 7s.56Tue 05