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A+b+c (ii) 1/a+1/b+1/c (iii) a²+b²+c². |
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Answer» ONG>Step-by-step explanation: (1−a)(1−C−b+bc) =1−c−b+bc−a+ac+ab =1−(a+b+c)+(ab+bc+ac) =1−1+ab+bc+ac = 2(ab+bc+ac)
= 2 (a+b+c) 2 −(a 2 +b 2 +c 2 )
= 2 1−21
=−10 |
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