332354 + Interview Questions in Secondary School in Math

1.	if a positive integer is an even integer then it is in the form (1) 6q+3. (2)6q. (3)3q+3. (4)4q+3
Answer» Answer: LONG ANSWER TYPE GlüESTIONS - I n +2 =3q + 2 + 2 =3q +4, which ... (c) If n = 674 2, then n(n + 1)(n + 2) = (64 + 2)(64 + 3)(6]+4) = 12(3) + 1)(24 + 1)(24 +3) which ... 1 Show that any positive EVEN integer is of the form 4Q or 4q + 2, where q ...

1.

if a positive integer is an even integer then it is in the form (1) 6q+3. (2)6q. (3)3q+3. (4)4q+3

Answer»

Answer:

LONG ANSWER TYPE GlüESTIONS - I n +2 =3q + 2 + 2 =3q +4, which ... (c) If n = 674 2, then n(n + 1)(n + 2) = (64 + 2)(64 + 3)(6]+4) = 12(3) + 1)(24 + 1)(24 +3) which ... 1 Show that any positive EVEN integer is of the form 4Q or 4q + 2, where q ...

Discussion

2.	Please solve this question of trigonometry
Answer» Step-by-step explanation: 13 is RIGHT ANSWER of this QUESTION

2.

Please solve this question of trigonometry

Answer»

Step-by-step explanation:

13 is RIGHT ANSWER of this QUESTION

Discussion

3.	Ten years ago, the age of a man was four times that of his son. Five years ago, the age of the man was three times that of his son. Find their present ages.
Answer» Answer: 20yrs, 50yrs Step-by-step explanation: Let the age of the MAN be a and age of son be b According to the question, (a-10)=4(b-10) simplifying, a - 10 = 4b - 40 4b - a = 30 (EQUATION 1) second equation is (a-5)=3(b-5) simplifying, a - 5 = 3b - 15 3b - a = 10 (equation 2) equation 1 - equation 2 4b - a -3b + a = 20 b = 20 a = 3b - 10 = 50 Therefore, age of the man is 50yrs and that of his son is 20yrs

3.

Ten years ago, the age of a man was four times that of his son. Five years ago, the age of the man was three times that of his son. Find their present ages.

Answer»

Answer:

20yrs, 50yrs

Step-by-step explanation:

Let the age of the MAN be a and age of son be b

According to the question, (a-10)=4(b-10)

simplifying, a - 10 = 4b - 40

4b - a = 30 (EQUATION 1)

second equation is (a-5)=3(b-5)

simplifying, a - 5 = 3b - 15

3b - a = 10 (equation 2)

equation 1 - equation 2

4b - a -3b + a = 20

b = 20

a = 3b - 10 = 50

Therefore, age of the man is 50yrs and that of his son is 20yrs

Discussion

4.	Sec Q -1 . sec Q + 1=CosecQ _. cot Q
Answer» ANSWER: BHAI PATA NHI jaake hung le Step-by-step explanation:

4.

Sec Q -1 . sec Q + 1=CosecQ _. cot Q

Answer»

ANSWER:

BHAI PATA NHI jaake hung le

Step-by-step explanation:

Discussion

5.	120 Rationalise the denominator of : 13+√3+√2-1
Answer» HOPE this will be HELPFUL

Discussion

6.	DateLottoDavidAlgebracic equation in one yoxlab-----3-6+g1- 6
Answer» ANSWER: your QUESTION has no meaning Step-by-step explanation: write the question in a meaningful WAY

6.

DateLottoDavidAlgebracic equation in one yoxlab-----3-6+g1- 6

Answer»

ANSWER:

your QUESTION has no meaning

Step-by-step explanation:

write the question in a meaningful WAY

Discussion

7.	Solve fast ..... . .
Answer» ANSWER: a)105km and B)6hr20min&C)750m/min

7.

Solve fast ..... . .

Answer»

ANSWER:

a)105km and B)6hr20min&C)750m/min

Discussion

8.	Evaluate: (-31)⁰ +(20)⁰+(11)⁰ =
Answer» Step-by-step EXPLANATION: the ANSWER will be ZERO OK FRIEND

8.

Evaluate: (-31)⁰ +(20)⁰+(11)⁰ =

Answer»

Step-by-step EXPLANATION:

the ANSWER will be ZERO OK FRIEND

Discussion

9.	Factorise p^2+9p+20
Answer» ANSWER: $(p+4)(p+5)$ Step-by-step EXPLANATION: $p^{2} + 9p + 20 = p^{2} + 4p + 5p +20$ = $p(p+4) + 5(p+4)$ = $(p+4)(p+5)$

9.

Factorise p^2+9p+20

Answer»

ANSWER:

$(p+4)(p+5)$

Step-by-step EXPLANATION:

$p^{2} + 9p + 20 = p^{2} + 4p + 5p +20$

= $p(p+4) + 5(p+4)$

= $(p+4)(p+5)$

Discussion

10.	3. In the given series 19, 14, 9, ...... (-46).find:a. 6th term from the end of the seriesb. Find the number of terms in the seriesc. Sum of the series.
Answer» ANSWER: a= -16 b= 14 c= -143 Step-by-step explanation: 1st term (a) = 19 difference (d) = -5 last term (TN) = -49 number of term (n) = ? USE formula tn = a +(n-1)d to find no of series i.e 14 find 14-6 th term in question a sum of series use formula ; Sn=n(2A+(n-1)d)/2

10.

3. In the given series 19, 14, 9, ...... (-46).find:a. 6th term from the end of the seriesb. Find the number of terms in the seriesc. Sum of the series.

Answer»

ANSWER:

a= -16

b= 14

c= -143

Step-by-step explanation:

1st term (a) = 19

difference (d) = -5

last term (TN) = -49

number of term (n) = ?

USE formula

tn = a +(n-1)d to find no of series i.e 14

find 14-6 th term in question a

sum of series use formula ; Sn=n(2A+(n-1)d)/2

Discussion

11.	A box contains cards numbered 6 to 50 . A card is drawn at random from the box. Find the probability that the drawn card is a perfect square
Answer» Answer: 1/9 Step-by-step EXPLANATION: PERFECT SQUARES= 9,16,25,36,49 Probability= 5/45 = 1/9

11.

A box contains cards numbered 6 to 50 . A card is drawn at random from the box. Find the probability that the drawn card is a perfect square

Answer»

Answer:

1/9

Step-by-step EXPLANATION:

PERFECT SQUARES= 9,16,25,36,49

Probability= 5/45 = 1/9

Discussion

12.	Determine whether the points are collinear(-0.5,3)(5,6)(-8,8)
Answer» ANSWER: POINTS are not COLLINEAR......... $1 \div 2 \|x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)\|$

12.

Determine whether the points are collinear(-0.5,3)(5,6)(-8,8)

Answer»

ANSWER:

POINTS are not COLLINEAR.........

$1 \div 2 |x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)|$

Discussion

13.	When we add 0 to a number,the sum is the number . i) 1. (ii) 0 (iii) itself (iv) none of these
Answer» Answer: $\text{[math]}$ $\huge\underline\pink\mathff\pink{HELLO. MATEYOUR ANSWER}$ OPTION 3 is correct For example: 3 +0=3 RESULT= NUMBER itself 2+0=2 RESULT= number itself HOPE IT WORKS PLEASE FOLLOW ME I AM NEW HERE

13.

When we add 0 to a number,the sum is the number . i) 1. (ii) 0 (iii) itself (iv) none of these

Answer»

Answer:

$\text{[math]}$

$\huge\underline\pink\mathff\pink{HELLO. MATEYOUR ANSWER}$

OPTION 3 is correct

For example:

3 +0=3 RESULT= NUMBER itself

2+0=2 RESULT= number itself

HOPE IT WORKS

PLEASE FOLLOW ME I AM NEW HERE

Discussion

14.	5.The following table shows the amount of wheat grown by Heera in different years,1998Years1995 1996199719992000160250270Wheat grown in quintals220240300Plot a graph to illustrate this information.224
Answer» Given : table showing the amount of wheat GROWN by Heera in different years, To find : plot a graph Solution: YEAR Wheat grown in quintals 1995 220 1996 224 1997 240 1998 250 1999 270 2000 300 Bar Graph A bar chart or bar graph is a chart or graph that presents categorical data with rectangular BARS with heights or lengths proportional to the values that they represent. The bars can be plotted vertically or horizontally. Here we have plotted vertically Learn more: Take Delhi and Sikkim. COMPARE the following with the help of bar ... brainly.in/question/18053163 Prepare a bar graph showing share of thermal, nuclear, HYDRO and ... brainly.in/question/18269671

14.

5.The following table shows the amount of wheat grown by Heera in different years,1998Years1995 1996199719992000160250270Wheat grown in quintals220240300Plot a graph to illustrate this information.224

Answer»

Given : table showing the amount of wheat GROWN by Heera in different years,

To find : plot a graph

Solution:

YEAR Wheat grown in quintals

1995 220

1996 224

1997 240

1998 250

1999 270

2000 300

Bar Graph

A bar chart or bar graph is a chart or graph that presents categorical data with rectangular BARS with heights or lengths proportional to the values that they represent. The bars can be plotted vertically or horizontally.

Here we have plotted vertically

Learn more:

Take Delhi and Sikkim. COMPARE the following with the help of bar ...

brainly.in/question/18053163

Prepare a bar graph showing share of thermal, nuclear, HYDRO and ...

brainly.in/question/18269671

Discussion

15.	4times a number and 5 times the same number added to75 gives 156 find the number hint 4x+5x+75=156
Answer» Answer: 9 Step-by-step EXPLANATION: by HINT.. 4x+5x+75=156 9x+75=156 9x=156-75 9x =81 ×=9. .so the NUMBER is 9..

15.

4times a number and 5 times the same number added to75 gives 156 find the number hint 4x+5x+75=156

Answer»

Answer:

9

Step-by-step EXPLANATION:

by HINT..

4x+5x+75=156

9x+75=156

9x=156-75

9x =81

×=9.

.so the NUMBER is 9..

Discussion

16.	1. If the 3rd and the oth term of the A.P. series are 4 and -8 respectively.Find:a. its first termb.common differencec. which term of the series be zerod. find the sum of first 20 terms.3
Answer» Answer: (III) (A) If we count in step of x from term number n, to n, including both term NUMBERS n , and n2, we get "—" +1 terms JC For examples, ...

16.

1. If the 3rd and the oth term of the A.P. series are 4 and -8 respectively.Find:a. its first termb.common differencec. which term of the series be zerod. find the sum of first 20 terms.3

Answer»

Answer:

(III) (A) If we count in step of x from term number n, to n, including both term NUMBERS n , and n2, we get "—" +1 terms JC For examples, ...

Discussion

17.	Plz solve this..................... 4th is so hard i will solve all part
Answer» Answer: OK dear I have sent U a photo for BETTER understand Step-by-step explanation: MARK it as BRAINLIEST please

17.

Plz solve this..................... 4th is so hard i will solve all part

Answer»

Answer:

OK dear I have sent U a photo for BETTER understand

Step-by-step explanation:

MARK it as BRAINLIEST please

Discussion

18.	How many integers in between 500 to 2020 (both inclusive) are multiple of 3 or 7?
Answer» Answer: $Plz Mark Me as Brainliest Answer$ Step-by-step explanation: There are 17 integers b/w 1-300 which are divisible by 5 & 3 but not by 7 By taking the lcm of 5&3 we find that 1st integer divisible by both the no. Is 15 and the LAST one is 300 (as per the condition) HENCE by using the formula tn=a+(n-1)d we can find the no. Of integers divisible by 3 & 5 i.e 19 by using the same process we can get the no. Of integers divisible by 3,5 & 7 between 1-300 i.e 2 Now subtract both the obtained VALUES i.e 19-2=17

18.

How many integers in between 500 to 2020 (both inclusive) are multiple of 3 or 7?

Answer»

Answer:

$Plz Mark Me as Brainliest Answer$

Step-by-step explanation:

There are 17 integers b/w 1-300 which are divisible by 5 & 3 but not by 7

By taking the lcm of 5&3 we find that 1st integer divisible by both the no. Is 15 and the LAST one is 300 (as per the condition) HENCE by using the formula tn=a+(n-1)d we can find the no. Of integers divisible by 3 & 5 i.e 19 by using the same process we can get the no. Of integers divisible by 3,5 & 7 between 1-300 i.e 2

Now subtract both the obtained VALUES i.e 19-2=17

Discussion

19.	An equilateral TQR is drawn inside asquare PQRS. The value of PTS is??1.752.903.1204.150
Answer» Answer: 4) 150 Step-by-step explanation: <SRT = 90°- 60° = 30° ∴<RTS = 1/2 (180° - 30°) = 75° ∴<PTQ = <RTS = 75° ∴<PTS + <PTQ + <QTR + <RTS = 360° => <PTS + 75° + 60° + 75° = 360° =><PTS = 360° - 210° = 150° ∴ The answer is 150° I hopes it HELP you❤️❤️

19.

An equilateral TQR is drawn inside asquare PQRS. The value of PTS is??1.752.903.1204.150

Answer»

Answer:

4) 150

Step-by-step explanation:

<SRT = 90°- 60° = 30°

∴<RTS = 1/2 (180° - 30°) = 75°

∴<PTQ = <RTS = 75°

∴<PTS + <PTQ + <QTR + <RTS = 360°

=> <PTS + 75° + 60° + 75° = 360°

=><PTS = 360° - 210° = 150°

∴ The answer is 150°

I hopes it HELP you❤️❤️

Discussion

20.	Calculate the percent of each given Value. 10)_%of 900 = 126 .Explain
Answer» $=>x\% \times 900 = 126 \\ \\ => \frac{x}{100} \% \times 900 = 126 \\ \\=> x\% = \frac{126 \times 100}{900} \\ \\=> x\% = 14\%$

20.

Calculate the percent of each given Value. 10)_%of 900 = 126 .Explain

Answer»

$=>x\% \times 900 = 126 \\ \\ => \frac{x}{100} \% \times 900 = 126 \\ \\=> x\% = \frac{126 \times 100}{900} \\ \\=> x\% = 14\%$

Discussion

21.	Test the divisblity of 294414 by 3.
Answer» Step-by-step EXPLANATION: Here, 294414 / 3 98138 294414 is DIVISIBLE by 3

21.

Test the divisblity of 294414 by 3.

Answer»

Step-by-step EXPLANATION:

Here,

294414 / 3

98138

294414 is DIVISIBLE by 3

Discussion

22.	Calculate the percent of each given Value. 9) _ % of 190 =9.5 .Explain
Answer» Answer: You REALLY need help in such easy question? this is not a quiz app. so ASK questions if you don,t KNOW something. anyways the answer is 5% of 190 = 9.5 Step-by-step explanation: LET's suppose the percentage is x so, x/100 X 190 = 9.5 x/100 = 9.5 / 190 x/100 = 0.05 x = 0.05 x 100 x = 5% That is how it is derived .

22.

Calculate the percent of each given Value. 9) _ % of 190 =9.5 .Explain

Answer»

Answer:

You REALLY need help in such easy question? this is not a quiz app. so ASK questions if you don,t KNOW something. anyways the answer is 5% of 190 = 9.5

Step-by-step explanation:

LET's suppose the percentage is x

so,

x/100 X 190 = 9.5

x/100 = 9.5 / 190

x/100 = 0.05

x = 0.05 x 100

x = 5%

That is how it is derived .

Discussion

23.	In a 200student of survey120like tea or coffee and 40like only milk then how many of does not like anythin
Answer» Answer: 40 Step-by-step explanation: No. of students = 200 Students liking TEA or COFFEE = 120 Students liking milk = 40 Hence students liking tea, coffee, milk = 120 + 40 = 160 Students not liking anything = 200 - 160 = 40 Hope U are satisfied :} plz mark me brainliest and follow me.

23.

In a 200student of survey120like tea or coffee and 40like only milk then how many of does not like anythin

Answer»

Answer:

40

Step-by-step explanation:

No. of students = 200

Students liking TEA or COFFEE = 120

Students liking milk = 40

Hence students liking tea, coffee, milk = 120 + 40 = 160

Students not liking anything = 200 - 160 = 40

Hope U are satisfied :} plz mark me brainliest and follow me.

Discussion

24.	write linear equation 3x+2y=18 in the form of ac™+ab+c=0 also write the values of a,b and c are (4,3) and (1,2)
Answer» SOLUTION :- WRITE LINEAR equation 3x+2y= 18 in the form of ac™+ab+c=0 also write the VALUES of a,b and c are (4,3) and (1,2…

24.

write linear equation 3x+2y=18 in the form of ac™+ab+c=0 also write the values of a,b and c are (4,3) and (1,2)

Answer»

SOLUTION :-

WRITE LINEAR equation 3x+2y= 18 in the form of ac™+ab+c=0 also write the VALUES of a,b and c are (4,3) and (1,2…

Discussion

25.	Tell mee correctly this question
Answer» ANSWER ATTACHED in FIGURE you can SEE

Discussion

26.	Calculate the percent of each given Value.8) _% of 400 =128. Explain
Answer» Answer: 32% Step-by-step EXPLANATION: $x\% \times 400 = 128 \\ x \times 4 = 128 \\ x = 128 \div 4$

26.

Calculate the percent of each given Value.8) _% of 400 =128. Explain

Answer»

Answer:

32%

Step-by-step EXPLANATION:

$x\% \times 400 = 128 \\ x \times 4 = 128 \\ x = 128 \div 4$

Discussion

27.	4. An alloy contains 30% copper, 42% nickel and rest zinc. Find the mass of zinc in 1 kgalloy.
Answer» ANSWER: the MASS of ZINC in 1KG = 280gm

27.

4. An alloy contains 30% copper, 42% nickel and rest zinc. Find the mass of zinc in 1 kgalloy.

Answer»

ANSWER:

the MASS of ZINC in 1KG = 280gm

Discussion

28.	The perimeter of a triangle with vertices (0,0), (4,0) and (0,3) isoptions571112
Answer» Answer: 12 Step-by-step EXPLANATION: =√(x2-x1)^2+(y2-y1)^2 =√16+√16+9+√9 =12

28.

The perimeter of a triangle with vertices (0,0), (4,0) and (0,3) isoptions571112

Answer»

Answer:

12

Step-by-step EXPLANATION:

=√(x2-x1)^2+(y2-y1)^2

=√16+√16+9+√9

=12

Discussion

29.	10. Factorise each of the following:(i) 27y3 + 125z(ii) 64m3 - 343n
Answer» Step-by-step EXPLANATION: I) $64 {m}^{3} - 343 {n}^{3}$ $first \: we \: use \: {a}^{n} \times {b}^{n} = {ab}^{n}$ ${4}^{3} {m}^{3} - {7}^{3} {n}^{3} \\ now \: we \: apply \: the \\ {a}^{n} {b}^{n} = {ab}^{n} \\ ({4m})^{3} - ({7n})^{3} \\ now \: we \: apply \: the \: following \: formula \\ {a}^{3} - {b}^{3} = (a - b)( {a}^{2} + {b}^{2} + ab) \\ \\ {4m}^{3} - {7n}^{3} \\ = (4m - 7n)( {4m}^{2} + {7n}^{2} + 28mn)$ II)

29.

10. Factorise each of the following:(i) 27y3 + 125z(ii) 64m3 - 343n

Answer»

Step-by-step EXPLANATION:

I)

$64 {m}^{3} - 343 {n}^{3}$

$first \: we \: use \: {a}^{n} \times {b}^{n} = {ab}^{n}$

${4}^{3} {m}^{3} - {7}^{3} {n}^{3} \\ now \: we \: apply \: the \\ {a}^{n} {b}^{n} = {ab}^{n} \\ ({4m})^{3} - ({7n})^{3} \\ now \: we \: apply \: the \: following \: formula \\ {a}^{3} - {b}^{3} = (a - b)( {a}^{2} + {b}^{2} + ab) \\ \\ {4m}^{3} - {7n}^{3} \\ = (4m - 7n)( {4m}^{2} + {7n}^{2} + 28mn)$

II)

Discussion

30.	Calculate the percent of each given Value.7)_% of 250 = 12.5. Explain
Answer» Answer: 5 Step-by-step EXPLANATION: Assume it as X, x/100 .(250)= 12.5 x= 12.5 (100)/ 250 = 5

30.

Calculate the percent of each given Value.7)_% of 250 = 12.5. Explain

Answer»

Answer:

5

Step-by-step EXPLANATION:

Assume it as X,

x/100 .(250)= 12.5

x= 12.5 (100)/ 250 = 5

Discussion

31.	if the same number be added to the numbers 5,11,15and31 the resulting numbers are in propotion. find the number
Answer» Answer: the NUMBER will add = 1 Step-by-step explanation: assume number is x (5+x) / (11+x) = (15+x) / (31+x) (5+x) * (31+x) = (15+x) * (11+x) xx + 5X + 31x + 155 = xx + 15X + 11X + 165 36x + 155 = 26x + 165 36x - 26x = 165 - 155 10x = 10 x = 1

31.

if the same number be added to the numbers 5,11,15and31 the resulting numbers are in propotion. find the number

Answer»

Answer:

the NUMBER will add = 1

Step-by-step explanation:

assume number is x

(5+x) / (11+x) = (15+x) / (31+x)

(5+x) * (31+x) = (15+x) * (11+x)

x*x + 5X + 31x + 155 = x*x + 15X + 11X + 165

36x + 155 = 26x + 165

36x - 26x = 165 - 155

10x = 10

x = 1

Discussion

32.	How many triangles in given figure?
Answer» ANSWER: There are 14 TRIANGLES in the GIVEN FIGURE....

32.

How many triangles in given figure?

Answer»

ANSWER:

There are 14 TRIANGLES in the GIVEN FIGURE....

Discussion

33.	Please solve this question of class 10
Answer» ANSWER: no Iam 9TH std Step-by-step explanation: you can search GOOGLE

33.

Please solve this question of class 10

Answer»

ANSWER:

no Iam 9TH std

Step-by-step explanation:

you can search GOOGLE

Discussion

34.	A body of mass 2 KG is at rest what should be the magnitude of force which will make the body move with a speed of 30 m/s at the end of 1 s ?
Answer» Answer: 60N Step-by-step EXPLANATION: m=2kg a= (30-0)/1 = 30m/s^2 F=m.a = 2. (30)= 60N

34.

A body of mass 2 KG is at rest what should be the magnitude of force which will make the body move with a speed of 30 m/s at the end of 1 s ?

Answer»

Answer:

60N

Step-by-step EXPLANATION:

m=2kg

a= (30-0)/1

= 30m/s^2

F=m.a

= 2. (30)= 60N

Discussion

35.	Mujahid lent Farhan $4800 for 7 months. at the end of this period, farhan had to pay Mujahid an interest of $119. What was the simple interest rate per annum? Hint: T = 7/12 years
Answer» Step-by-step EXPLANATION: HOPE it HELPS U

35.

Mujahid lent Farhan $4800 for 7 months. at the end of this period, farhan had to pay Mujahid an interest of $119. What was the simple interest rate per annum? Hint: T = 7/12 years

Answer»

Step-by-step EXPLANATION:

HOPE it HELPS U

Discussion

36.	Prove that root 3 is irrational
Answer» ${\bold{\blue{\underline{\red{S}\pink{ol}\green{uti}\purple{on:-}}}}}$ Let √3 be rational and let it's simple form be a/B Then, a and b are integers having no common factor other than 1, and b ≠ 0. Now, √3 = a/b Squaring both side (√3)² = (a/b)² $\rm\longrightarrow\:$ 3 = a²/b² $\rm\longrightarrow\:$ 3b² = a²...............(i) $\rm\longrightarrow\:$ 3 divides a² [∴ 3 divides 3b²] $\rm\longrightarrow\:$ 3 divides a (∴ 3 is PRIME and 3 divides a² $\rm\longrightarrow\:$ 3 divides a ) let a = 3C for some integer c putting a = 3c in eq (i) ,we get 3b² = 9c² $\rm\longrightarrow\:$ b² = 3c² $\rm\longrightarrow\:$ 3 divides b² [∴3 divides 3c²] $\rm\longrightarrow\:$ 3 divides b (∴ 3 is prime and 3 divides b² $\rm\longrightarrow\:$ 3 divides b) Thus, 3 is a common factor of a and b but this contradiction the fact that a and b have no factor other than 1 This contradiction ARISES by assuming √3 is rational. Hence, √3 is irrational.

36.

Prove that root 3 is irrational

Answer»

${\bold{\blue{\underline{\red{S}\pink{ol}\green{uti}\purple{on:-}}}}}$

Let √3 be rational and let it's simple form be a/B

Then, a and b are integers having no common factor other than 1, and b ≠ 0.

Now,

√3 = a/b

Squaring both side

(√3)² = (a/b)²

$\rm\longrightarrow\:$ 3 = a²/b²

$\rm\longrightarrow\:$ 3b² = a²...............(i)

$\rm\longrightarrow\:$ 3 divides a² [∴ 3 divides 3b²]

$\rm\longrightarrow\:$ 3 divides a

(∴ 3 is PRIME and 3 divides a² $\rm\longrightarrow\:$ 3 divides a )

let a = 3C for some integer c

putting a = 3c in eq (i) ,we get

3b² = 9c² $\rm\longrightarrow\:$ b² = 3c²

$\rm\longrightarrow\:$ 3 divides b² [∴3 divides 3c²]

$\rm\longrightarrow\:$ 3 divides b

(∴ 3 is prime and 3 divides b² $\rm\longrightarrow\:$ 3 divides b)

Thus,

3 is a common factor of a and b

but this contradiction the fact that a and b have no factor other than 1

This contradiction ARISES by assuming √3 is rational.

Hence, √3 is irrational.

Discussion

37.	P(x)= 2x3-6x2+9x+3, g(x)= x-3
Answer» ANSWER: => 30 Step by *step* *explanation* : Given : g(X)= x-3 so, x= 3 P(x)= 2x³-6x²+9x+3 Now put the value of x ... 2x³-6x²+9x+3 => 23³ - 63² + 93 + 3 => 227 - 69 + 93 + 3 => 54 - 54 + 27 + 3 => 30 I hope it helps you....

37.

P(x)= 2x3-6x2+9x+3, g(x)= x-3

Answer»

ANSWER:

=> 30

Step by step explanation :

Given : g(X)= x-3

so, x= 3

P(x)= 2x³-6x²+9x+3

Now put the value of x ...

2x³-6x²+9x+3

=> 2*3³ - 6*3² + 9*3 + 3

=> 2*27 - 6*9 + 9*3 + 3

=> 54 - 54 + 27 + 3

=> 30

I hope it helps you....

Discussion

38.	8. A stadium has a capacity of 52,650 people. How many rows of seats are there in the stadium975 people can sit in each row?
Answer» Each ROW=total PEOPLE/no. of rows each row=64070/86 =745 people PER row

38.

8. A stadium has a capacity of 52,650 people. How many rows of seats are there in the stadium975 people can sit in each row?

Answer»

Each ROW=total PEOPLE/no. of rows

each row=64070/86

=745 people PER row

Discussion

39.	A car moving at 72km/h is stopped in 5 seconds.If it retards uniformly find the distance travelled by the car before it stops.Also find its retardation.If u give correct answer then u will be marked as brainliest answer
Answer» Step-by-step explanation: ▪️Acceleration = (final velocity - initial velocity) / time ▪️Initial velocity(Vi) = 72km/h = 72,000 m/h. (A kilometre is 1000 METRES) ▪️There are 3600 SECONDS in an hour, so ▪️Vi = 72,000/3600= 20m/sec. Final velocity(Vf) = 0 ▪️Vf - Vi = 0–20 = -20m/sec. ▪️So deceleration is -20/10 = -2m/sec/sec (metres per second squared) ▪️(The minus INDICATES deceleration) ▪️What this means is that the CAR loses speed at a uniform rate of 2m/sec, ▪️so after 1 second, velocity = 18m/sec, after 2 secs, 16m/sec…..etc. Hopes it help you❤️❤️

39.

A car moving at 72km/h is stopped in 5 seconds.If it retards uniformly find the distance travelled by the car before it stops.Also find its retardation.If u give correct answer then u will be marked as brainliest answer

Answer»

Step-by-step explanation:

▪️Acceleration = (final velocity - initial velocity) / time

▪️Initial velocity(Vi) = 72km/h = 72,000 m/h. (A kilometre is 1000 METRES)

▪️There are 3600 SECONDS in an hour, so

▪️Vi = 72,000/3600= 20m/sec. Final velocity(Vf) = 0

▪️Vf - Vi = 0–20 = -20m/sec.

▪️So deceleration is -20/10 = -2m/sec/sec (metres per second squared)

▪️(The minus INDICATES deceleration)

▪️What this means is that the CAR loses speed at a uniform rate of 2m/sec,

▪️so after 1 second, velocity = 18m/sec, after 2 secs, 16m/sec…..etc.

Hopes it help you❤️❤️

Discussion

40.	20Find the curl and divergence of the givenvector field:F(x,y,z) = x^2sinyzi+zcosxz^3j+ye^5xyk
Answer» Step-by-step EXPLANATION: I DONE PLEAS HELP some ONE

40.

20Find the curl and divergence of the givenvector field:F(x,y,z) = x^2sinyzi+zcosxz^3j+ye^5xyk

Answer»

Step-by-step EXPLANATION:

I DONE PLEAS HELP some ONE

Discussion

41.	Anewer me fast please
Answer» Answer: 5/0 is not a RATIONAL number as it is not of the form p/Q where p and q are integers. 3a MAY or may not be a rational number DEPENDING on the value of a

41.

Anewer me fast please

Answer»

Answer:

5/0 is not a RATIONAL number as it is not of the form p/Q where p and q are integers.

3a MAY or may not be a rational number DEPENDING on the value of a

Discussion

42.	Find two consecutive odd numbers whose sum is 184 hint(x+(x+2) =184
Answer» Answer: GIVEN x+x+2=184 2x+2=184 2x=184-2=182 x=182/2=91 so the two numbers are x=91 and x+2=91+2=93 Step-by-step explanation: 91 and 93 hope it HELPS you plzz MARK me as UR brainliast ❤️❤️❤️

42.

Find two consecutive odd numbers whose sum is 184 hint(x+(x+2) =184

Answer»

Answer:

GIVEN x+x+2=184

2x+2=184

2x=184-2=182

x=182/2=91

so the two numbers are

x=91 and x+2=91+2=93

Step-by-step explanation:

91 and 93

hope it HELPS you

plzz MARK me as UR brainliast ❤️❤️❤️

Discussion

43.	Please please please help me to solve this question 3 and 4
Answer»

Discussion

44.	The product of two integers is 30, if one of the integers is -5 then find the other integer
Answer» Answer: The other integer is -6. Step-by-step EXPLANATION: LET the other integer be k. So, k X -5 = 30 or, k=30/-5 or, k= -6. Therefore the other integer is -6.

44.

The product of two integers is 30, if one of the integers is -5 then find the other integer

Answer»

Answer:

The other integer is -6.

Step-by-step EXPLANATION:

LET the other integer be k.

So, k X -5 = 30

or, k=30/-5

or, k= -6.

Therefore the other integer is -6.

Discussion

45.	12 hours for 80 marks, how much hours for 1 marks
Answer» ANSWER: For 12 hours=80 marks For 1 mark=12*60/80 =720/80 =9 mins Hope it helps you DEAR Step-by-step explanation:

45.

12 hours for 80 marks, how much hours for 1 marks

Answer»

ANSWER:

For 12 hours=80 marks

For 1 mark=12*60/80

=720/80

=9 mins

Hope it helps you DEAR

Step-by-step explanation:

Discussion

46.	Area of a triangleis 44cm and its base is 22 if the height is 2x find its height
Answer» ANSWER: x=2 Step-by-step explanation: Because area=44cm so FORMULA is 1/2bh, b=22(given)h=2x So, 1/2bh=1/222(22) 114=44cm Hence PROVED.

46.

Area of a triangleis 44cm and its base is 22 if the height is 2x find its height

Answer»

ANSWER:

x=2

Step-by-step explanation:

Because area=44cm so FORMULA is 1/2bh,

b=22(given)h=2x

So, 1/2bh=1/2*22*(2*2)

11*4=44cm

Hence PROVED.

Discussion

47.	(x+a)(x+b)(x+c) formulas
Answer» ANSWER: hii bahi Kya kar RAHA. HA

47.

(x+a)(x+b)(x+c) formulas

Answer»

ANSWER:

hii bahi Kya kar RAHA. HA

Discussion

48.	Please please please help me to solve this question 32,33,34 please please
Answer» ANSWER: you DRAW aa angle 100 to 90

48.

Please please please help me to solve this question 32,33,34 please please

Answer»

ANSWER:

you DRAW aa angle 100 to 90

Discussion

49.	IF COS X = 1/√1+t^2 and SIN Y = t / √1 + t^2, then find dy/dx
Answer» Step-by-step EXPLANATION: H urehhsghfgthdheyyeyu

49.

IF COS X = 1/√1+t^2 and SIN Y = t / √1 + t^2, then find dy/dx

Answer»

Step-by-step EXPLANATION:

H urehhsghfgthdheyyeyu

Discussion

50.	Factorise this algebraic expression (x+y²)
Answer» Step-by-step EXPLANATION: X SQUARE +2XY + y square

50.

Factorise this algebraic expression (x+y²)

Answer»

Step-by-step EXPLANATION:

X SQUARE +2XY + y square

Discussion

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