A car moving at 72km/h is stopped in 5 seconds.If it retards uniformly

1.	A car moving at 72km/h is stopped in 5 seconds.If it retards uniformly find the distance travelled by the car before it stops.Also find its retardation.If u give correct answer then u will be marked as brainliest answer
Answer» Step-by-step explanation: ▪️Acceleration = (final velocity - initial velocity) / time ▪️Initial velocity(Vi) = 72km/h = 72,000 m/h. (A kilometre is 1000 METRES) ▪️There are 3600 SECONDS in an hour, so ▪️Vi = 72,000/3600= 20m/sec. Final velocity(Vf) = 0 ▪️Vf - Vi = 0–20 = -20m/sec. ▪️So deceleration is -20/10 = -2m/sec/sec (metres per second squared) ▪️(The minus INDICATES deceleration) ▪️What this means is that the CAR loses speed at a uniform rate of 2m/sec, ▪️so after 1 second, velocity = 18m/sec, after 2 secs, 16m/sec…..etc. Hopes it help you❤️❤️

A car moving at 72km/h is stopped in 5 seconds.If it retards uniformly find the distance travelled by the car before it stops.Also find its retardation.If u give correct answer then u will be marked as brainliest answer

Answer»

Step-by-step explanation:

▪️Acceleration = (final velocity - initial velocity) / time

▪️Initial velocity(Vi) = 72km/h = 72,000 m/h. (A kilometre is 1000 METRES)

▪️There are 3600 SECONDS in an hour, so

▪️Vi = 72,000/3600= 20m/sec. Final velocity(Vf) = 0

▪️Vf - Vi = 0–20 = -20m/sec.

▪️So deceleration is -20/10 = -2m/sec/sec (metres per second squared)

▪️(The minus INDICATES deceleration)

▪️What this means is that the CAR loses speed at a uniform rate of 2m/sec,

▪️so after 1 second, velocity = 18m/sec, after 2 secs, 16m/sec…..etc.

Hopes it help you❤️❤️

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