332354 + Interview Questions in Secondary School in Math

1.	0.8 = 4/3 true or false
Answer» ANSWER: False $0.8 = \frac{8}{10} = \frac{4}{5}$ hope it will HELP you DEAR ☺️☺️

1.

0.8 = 4/3 true or false

Answer»

ANSWER:

False

$0.8 = \frac{8}{10} = \frac{4}{5}$

hope it will HELP you DEAR ☺️☺️

Discussion

2.	B = {x :x²– 5x+6 = 0, xe N}
Answer» HOPE this ANSWER HELPS you mark me as brainlist follow me

2.

B = {x :x²– 5x+6 = 0, xe N}

Answer»

HOPE this ANSWER HELPS you

mark me as brainlist

follow me

Discussion

3.	Which no. should be multiplied with 289 to make it a perfect cube? 1.12 2.17 3.19 4.21
Answer» Answer: 17 HOPE it HELPS U √289=17, so LG we multiply the 289×17 then it become a PERFECT cube

3.

Which no. should be multiplied with 289 to make it a perfect cube? 1.12 2.17 3.19 4.21

Answer»

Answer:

17

HOPE it HELPS U

√289=17, so LG we multiply the 289×17 then it become a PERFECT cube

Discussion

4.	12 सेंटीमीटर त्रिज्या 10 सेंटीमीटर ऊंचाई वाले लंब वृत्तीय बेलन का संपूर्ण पृष्ठ ज्ञात कीजिए
Answer» Given: A cube can be inscribed cylinder of radius 5 cm and height 12 cm. To Find: What is the total SURFACE AREA of LARGEST cube ? Solution: Radius of cylinder (R) = 5 cm Diameter of cylinder (D) = 10 cm It is clear that DIAGONAL of face of cube will be diameter of cylinder: Diagonal of face of cube = 10 cm So side of cube: Side² + Side² = Diagonal² 2×Side² = Diagonal² On putting respective value in above equation: 2×Side² = 10² 2×Side² = 100 Side² = 50 ...1) Side = √50 Means side of cube = √50 cm √50 < 12 √50 < height of cylinder So √50 is largest side of cube: Total surface area of cube will be: Total surface are = 6× Side² From equation 1): Total surface are = 6× 50 Total surface are = 300 cm² So total surface area of largest cube which can be inscribed cylinder of radius 5 cm and height 12 cm is 300 cm². follow me please... Mark as brainliest please...

4.

12 सेंटीमीटर त्रिज्या 10 सेंटीमीटर ऊंचाई वाले लंब वृत्तीय बेलन का संपूर्ण पृष्ठ ज्ञात कीजिए

Answer»

Given:

A cube can be inscribed cylinder of radius 5 cm and height 12 cm.

To Find:

What is the total SURFACE AREA of LARGEST cube ?

Solution:

Radius of cylinder (R) = 5 cm

Diameter of cylinder (D) = 10 cm

It is clear that DIAGONAL of face of cube will be diameter of cylinder:

Diagonal of face of cube = 10 cm

So side of cube:

Side² + Side² = Diagonal²

2×Side² = Diagonal²

On putting respective value in above equation:

2×Side² = 10²

2×Side² = 100

Side² = 50 ...1)

Side = √50

Means side of cube = √50 cm

√50 < 12

√50 < height of cylinder

So √50 is largest side of cube:

Total surface area of cube will be:

Total surface are = 6× Side²

From equation 1):

Total surface are = 6× 50

Total surface are = 300 cm²

So total surface area of largest cube which can be inscribed cylinder of radius 5 cm and height 12 cm is 300 cm².

follow me please...

Mark as brainliest please...

Discussion

5.	At Srinagar temperature was 5°C on Monday and then it dropped by 2°C on Tuesday. What was the temperature of Srinagar on Tuesday? On Wednesday, it rose by 4°C. What was the temperature on this day?
Answer» TEMPERATURE on MONDAY = -5°C Temperature on TUESDAY = Temperature on Monday -2°C = -5°C -2°C = -7°C Temperature on WEDNESDAY = Temperature on Tuesday + 4°C = -7°C + 4°C = -3°C Therefore, the temperature on Tuesday and Wednesday was -7°C and -3°C RESPECTIVELY. $.$

5.

At Srinagar temperature was 5°C on Monday and then it dropped by 2°C on Tuesday. What was the temperature of Srinagar on Tuesday? On Wednesday, it rose by 4°C. What was the temperature on this day?

Answer»

TEMPERATURE on MONDAY = -5°C

Temperature on TUESDAY = Temperature on Monday -2°C

= -5°C -2°C = -7°C

Temperature on WEDNESDAY = Temperature on Tuesday + 4°C

= -7°C + 4°C = -3°C

Therefore, the temperature on Tuesday and Wednesday was -7°C and -3°C RESPECTIVELY.

$.$

Discussion

6.	Find the zeroes of the polynomial x^2 - 7x +10
Answer» ANSWER: X=5,2 Step-by-step EXPLANATION: x2-2x-5x+10=0 x(x-2)-5(x-2)=0 x-2=0 x-5=0 x=2,5

6.

Find the zeroes of the polynomial x^2 - 7x +10

Answer»

ANSWER:

X=5,2

Step-by-step EXPLANATION:

x2-2x-5x+10=0

x(x-2)-5(x-2)=0

x-2=0 x-5=0

x=2,5

Discussion

7.	A watch loses 20 seconds in 5 days.How many seconds does it lose in a week?
Answer» Answer: 140 Step-by-step EXPLANATION: ...........................,.

7.

A watch loses 20 seconds in 5 days.How many seconds does it lose in a week?

Answer»

Answer:

140

Step-by-step EXPLANATION:

...........................,.

Discussion

8.	Abus takes 4 hours 45 minutes to reach Meerutfrom Dehradun. If it starts from Dehradun at8:00 p.m., when will it reach Agra?Arrival time at Meerut = ...........
Answer» ANSWER: ABUS TAKEN to REACH MEERUT

8.

Abus takes 4 hours 45 minutes to reach Meerutfrom Dehradun. If it starts from Dehradun at8:00 p.m., when will it reach Agra?Arrival time at Meerut = ...........

Answer»

ANSWER:

ABUS TAKEN to REACH MEERUT

Discussion

9.	In a right triangle ABC ‚ right angled at B‚the rotio of AB to AC is 1:√2 • Find the values of 1) 2Ta na/1+tan²A 2)2Ta na/1-tan²A
Answer» ANSWER: ∉∧⊇∑πФ³°∞ Step-by-step EXPLANATION:

9.

In a right triangle ABC ‚ right angled at B‚the rotio of AB to AC is 1:√2 • Find the values of 1) 2Ta na/1+tan²A 2)2Ta na/1-tan²A

Answer»

ANSWER:

∉∧⊇∑πФ³°∞

Step-by-step EXPLANATION:

Discussion

10.	What is the algebraic relation between mean, mode and median??
Answer» MEAN is average Mode is middle and Mean is ALSO middle in calcute in a DIFFERENT WAY

10.

What is the algebraic relation between mean, mode and median??

Answer»

MEAN is average

Mode is middle and

Mean is ALSO middle in calcute in a DIFFERENT WAY

Discussion

11.	Using identity find value 16.8 × 15.2
Answer» 255.56 hope you LIKE it FOLLOW ME

11.

Using identity find value 16.8 × 15.2

Answer»

255.56

hope you LIKE it

FOLLOW ME

Discussion

12.	Solve by Factorisation Method x²+7x+10=0
Answer» $x^2 + 7x + 10 = 0 \\ x ^2 + (5x + 2x) = 0 \\ x(x + 5) + 2(x + 5) = 0 \\ (x + 5)(x + 2) = 0 \: factors \:$

12.

Solve by Factorisation Method x²+7x+10=0

Answer»

$x^2 + 7x + 10 = 0 \\ x ^2 + (5x + 2x) = 0 \\ x(x + 5) + 2(x + 5) = 0 \\ (x + 5)(x + 2) = 0 \: factors \:$

Discussion

13.	Find the difference between 3085 and 3058
Answer» Answer: In 3085, 8 is in tenth PLACE and 5 is in UNITS place & In 3058, 8 is in units place and 5 is in tenth place.

13.

Find the difference between 3085 and 3058

Answer»

Answer:

In 3085, 8 is in tenth PLACE and 5 is in UNITS place

&

In 3058, 8 is in units place and 5 is in tenth place.

Discussion

14.	Evaluate using a identity :-(1. 93)^3+(0.07)^3-(2)^3
Answer» ANSWER: $This is an illustration of the identity {a}^{3} \: + {b}^{3} + {c}^{3} = 3abc \\ if \: a + b + c = 0Here, a = 1.93b = 0.07c = 2Here a+b+c=1.93+0.07-2 = 2-2 = 0Therefore, we can use this identity and the answer = 3×1.93×0.07×2 = 0.8106$ $#PHENOMENAL ♡♡♡♡♡$

14.

Evaluate using a identity :-(1. 93)^3+(0.07)^3-(2)^3

Answer»

ANSWER:

$This is an illustration of the identity {a}^{3} \: + {b}^{3} + {c}^{3} = 3abc \\ if \: a + b + c = 0Here, a = 1.93b = 0.07c = 2Here a+b+c=1.93+0.07-2 = 2-2 = 0Therefore, we can use this identity and the answer = 3×1.93×0.07×2 = 0.8106$

$#PHENOMENAL ♡♡♡♡♡$

Discussion

15.	The height of a mango tree is 7.04 m and that of an orange tree is 3.5 m. How much higher the mango tree.
Answer» $mango \: tree \: height = 7.04 \: m \\ orange \: tree \: height = 3.5 \: m \\ \\ mango \: tree \: higher \: than \: orange \: tree \\ = ( 7.04 - 3.5) m\\ = 3.54 \: m$

15.

The height of a mango tree is 7.04 m and that of an orange tree is 3.5 m. How much higher the mango tree.

Answer»

$mango \: tree \: height = 7.04 \: m \\ orange \: tree \: height = 3.5 \: m \\ \\ mango \: tree \: higher \: than \: orange \: tree \\ = ( 7.04 - 3.5) m\\ = 3.54 \: m$

Discussion

16.	3. On April 1st, the snowpack at the ski resort was 4 metres deep. But the next few days were very warm andby April 5th, the snow depth was 1.6 metres less. On April 8, it snowed and added 2-1 metres of snow.What was the total depth of the snow?
Answer» ︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎︎

Discussion

17.	By observing these allthese all penaltiasfrom anAP that is at day=200and differns50
Answer» Answer: ok mate but what is your QUESTION MARK ME AS BRAINLIST AND FOLLOW ME

17.

By observing these allthese all penaltiasfrom anAP that is at day=200and differns50

Answer»

Answer:

ok mate but what is your QUESTION

MARK ME AS BRAINLIST AND FOLLOW ME

Discussion

18.	12. (a) Show that the number 3" cannot end with the digit 0 for any neN
Answer» Answer: We KNOW that a number ends with ZERO only when it's PRIME FACTORISATION is 2×3(at least once) Here, 3N=(1×3)n Therefore, 3n will not end with zero because prime factorisation of 3 is, 3=2×3 HOPE IT HELPS... Thank you....

18.

12. (a) Show that the number 3" cannot end with the digit 0 for any neN

Answer»

Answer:

We KNOW that a number ends with ZERO only when it's PRIME FACTORISATION is 2×3(at least once)

Here,

3N=(1×3)n

Therefore,

3n will not end with zero because prime factorisation of 3 is,

3=2×3

HOPE IT HELPS... Thank you....

Discussion

19.	If the slope of one of the lines represented by ax^+2hxy+by^=0 is three times the other then prove that 3h^=4ab
Answer» Geometry Given: the slope of ONE of the LINES represented by $ax^{2}+2hxy+by^{2}=0$ is three TIMES the other To PROVE: $3h^{2}=4ab$ Proof: Let $y^{2}+\frac{2h}{b}xy+\frac{a}{b}x^{2}=(y-m_{1}x)(y-m_{2}x)$ Then, $\quad m_{1}+m_{2}=-\frac{2h}{b}$ $\quad m_{1}m_{2}=\frac{a}{b}$ Given, $m_{1}=3m_{2}\Rightarrow \frac{m_{1}}{m_{2}}=3$ Now, $\frac{(m_{1}+m_{2})^{2}}{m_{1}m_{2}}=\frac{(-2h/b)^{2}}{a/b}$ $\Rightarrow \frac{m_{1}^{2}+2m_{1}m_{2}+m_{2}^{2}}{m_{1}m_{2}}=\frac{4h^{2}/b^{2}}{a/b}$ $\Rightarrow \frac{m_{1}}{m_{2}}+2+\frac{1}{\frac{m_{1}}{m_{2}}}=\frac{4h^{2}}{ab}$ $\Rightarrow 3+2+\frac{1}{3}=\frac{4h^{2}}{ab}$ $\Rightarrow \frac{4h^{2}}{ab}=\frac{16}{3}$ $\Rightarrow\frac{h^{2}}{ab}=\frac{4}{3}$ $\Rightarrow 3h^{2}=4ab$ This completes the proof.

19.

If the slope of one of the lines represented by ax^+2hxy+by^=0 is three times the other then prove that 3h^=4ab

Answer»

Geometry

Given: the slope of ONE of the LINES represented by $ax^{2}+2hxy+by^{2}=0$ is three TIMES the other

To PROVE: $3h^{2}=4ab$

Proof:

Let $y^{2}+\frac{2h}{b}xy+\frac{a}{b}x^{2}=(y-m_{1}x)(y-m_{2}x)$

Then,

$\quad m_{1}+m_{2}=-\frac{2h}{b}$

$\quad m_{1}m_{2}=\frac{a}{b}$

Given, $m_{1}=3m_{2}\Rightarrow \frac{m_{1}}{m_{2}}=3$

Now, $\frac{(m_{1}+m_{2})^{2}}{m_{1}m_{2}}=\frac{(-2h/b)^{2}}{a/b}$

$\Rightarrow \frac{m_{1}^{2}+2m_{1}m_{2}+m_{2}^{2}}{m_{1}m_{2}}=\frac{4h^{2}/b^{2}}{a/b}$

$\Rightarrow \frac{m_{1}}{m_{2}}+2+\frac{1}{\frac{m_{1}}{m_{2}}}=\frac{4h^{2}}{ab}$

$\Rightarrow 3+2+\frac{1}{3}=\frac{4h^{2}}{ab}$

$\Rightarrow \frac{4h^{2}}{ab}=\frac{16}{3}$

$\Rightarrow\frac{h^{2}}{ab}=\frac{4}{3}$

$\Rightarrow 3h^{2}=4ab$

This completes the proof.

Discussion

20.	The extension of an elastic spring is found to vary directly with the weightsuspended from it. If a weight of 75 kg produces an extension of 1.4 cm,calculate the weight that would produce an extension of 9.8 cm.
Answer» Iᴛ sᴇᴇᴍᴇᴅ ᴛʜᴀᴛ Bʀᴀɪɴʟʏ Mᴏᴅᴇʀᴀᴛᴏʀs Dᴏᴇsɴᴏᴛ ʟɪᴋᴇ ᴍʏ ᴀɴsᴡᴇʀ sᴏ ᴛʜᴇʏ sᴀɪᴅ ʀᴜᴅᴇ ! ᴡᴇ ᴅᴏɴ'ᴛ ᴜsᴇ ᴛʜᴇsᴇ ᴡᴏʀᴅs ʜᴇʀᴇ.... sᴏ ɪ ʜᴀᴅ ᴛᴏ ᴛᴀᴋᴇ SCREENSHOT ᴏғ Iᴛ

Discussion

21.	PLS ANS FASTpls ANSWER CORRECTLY OR I WILL REPORT AND BAN UR ANS
Answer» ANSWER: option (B) ∆ TUV ≅ ∆ LKJ HOPE it MAY help you.....

21.

PLS ANS FASTpls ANSWER CORRECTLY OR I WILL REPORT AND BAN UR ANS

Answer»

ANSWER:

option (B) ∆ TUV ≅ ∆ LKJ

HOPE it MAY help you.....

Discussion

22.	Solve the equation:-5x-8=107
Answer» ANSWER: $5x - 8 = 107 \\ 5x = 107 + 8 \\ 5x = 115 \\ x = \frac{115}{5} \\ x = 23$

22.

Solve the equation:-5x-8=107

Answer»

ANSWER:

$5x - 8 = 107 \\ 5x = 107 + 8 \\ 5x = 115 \\ x = \frac{115}{5} \\ x = 23$

Discussion

23.	Check whether the following are quadratic equationsi) (x–2) (x+1)= (x–1) (x+3)ii) (x–3)(2x+1)=x(x+5)iii)(2x–1)(x–3)=(x+5)(x–1)solve it and answer it
Answer» ANSWER : No Yes Yes Solution: 1) (x-2)(x+1) = (x-1) (x+3) ⇢x(x+1) -2 (x+1) = x(x+3) -1 (x+3) ⇢x² + x -2X -2 = x² +3x -x -3 ⇢x² - x -2 = x² +2x -3 ⇢x² - x² - x -2x = -3 +2 ⇢-3x = -1 ⇢3x = 1 Here , the degree of polynomial is 1 , hence it is a linear equation not a QUADRATIC equation . 2) (x-3) (2x+1) = x(x+5) ⇢x(2x+1) -3 (2x+1) = x² + 5x ⇢2x² + x - 6 x -3 = x² + 5x ⇢2x² - 5x -3 = x² + 5x ⇢2x² - x² -5x -5x - 3 = 0 ⇢x² -10x -3 = 0 Here , the degree of polynomial is 2 . Hence it is a quadratic equation. 3) (2x -1) (x-3) = (x+5)(x-1) ⇢2x (x-3) -1(x-3) = x(x-1) +5(x-1) ⇢2x² - 6x - x + 3 = x² - x +5x -5 ⇢2x² -7x +3 = x² +4x -5 ⇢2x² - x² - 7x -4x +3 +5 = 0 ⇢x² - 11 x +10 = 0 Here , the degree of polynomial is 2 . Hence it is a quadratic equation .

23.

Check whether the following are quadratic equationsi) (x–2) (x+1)= (x–1) (x+3)ii) (x–3)(2x+1)=x(x+5)iii)(2x–1)(x–3)=(x+5)(x–1)solve it and answer it

Answer»

ANSWER :

No
Yes
Yes

Solution:

1) (x-2)(x+1) = (x-1) (x+3)

⇢x(x+1) -2 (x+1) = x(x+3) -1 (x+3)

⇢x² + x -2X -2 = x² +3x -x -3

⇢x² - x -2 = x² +2x -3

⇢x² - x² - x -2x = -3 +2

⇢-3x = -1

⇢3x = 1

Here , the degree of polynomial is 1 , hence it is a linear equation not a QUADRATIC equation .

2) (x-3) (2x+1) = x(x+5)

⇢x(2x+1) -3 (2x+1) = x² + 5x

⇢2x² + x - 6 x -3 = x² + 5x

⇢2x² - 5x -3 = x² + 5x

⇢2x² - x² -5x -5x - 3 = 0

⇢x² -10x -3 = 0

Here , the degree of polynomial is 2 . Hence it is a quadratic equation.

3) (2x -1) (x-3) = (x+5)(x-1)

⇢2x (x-3) -1(x-3) = x(x-1) +5(x-1)

⇢2x² - 6x - x + 3 = x² - x +5x -5

⇢2x² -7x +3 = x² +4x -5

⇢2x² - x² - 7x -4x +3 +5 = 0

⇢x² - 11 x +10 = 0

Here , the degree of polynomial is 2 . Hence it is a quadratic equation .

Discussion

24.	5. The sum of four numbers is T.Suppose that each of the four numbers is now increased by 1. These four new numbers are addedtogether giving triple the value of T. What is T, and what is the triple the value of T?
Answer» ANSWER: HOPE this is HELPFUL.

24.

5. The sum of four numbers is T.Suppose that each of the four numbers is now increased by 1. These four new numbers are addedtogether giving triple the value of T. What is T, and what is the triple the value of T?

Answer»

ANSWER:

HOPE this is HELPFUL.

Discussion

25.	4. Write three pairs of integers (a, b) such thata divided b = - 4. (different answers are possible
Answer» ANSWER: There are MANY: (-8,2) (-16,4) (-12,3) (-24,6) (-20,5),ETC etc... HOPE it HELPS...

25.

4. Write three pairs of integers (a, b) such thata divided b = - 4. (different answers are possible

Answer»

ANSWER:

There are MANY:

(-8,2)

(-16,4)

(-12,3)

(-24,6)

(-20,5),ETC etc...

HOPE it HELPS...

Discussion

26.	I) एक दी हुई किरण के प्रारंभिक बिन्दु पर 45° के कोण की रचना कीजिए और कारण सहितरचना की पुष्टि कीजिए ।[NCERT]fromfaTOTTकीजिया
Answer» Answer: रचना के चरण : (1) O को केंद्र मानकर तथा कोई त्रिज्या लेकर एक चाप लगाइए जो किरण OA को बिंदु B पर प्रतिच्छेद करता है। (2) B को केंद्र मानकर और उसी त्रिज्या, जो पहले ली गई थी से एक चाप खींचते हैं जो चरण (1) में खींचे गए चाप को बिंदु C पर प्रतिच्छेद करता है। (3) C को केंद्र मानकर और उसी त्रिज्या, जो पहले ली गई थी से एक चाप खींचते हैं, जो चरण (1) में खींचे गए चाप को बिंदु D पर प्रतिच्छेद करता है। (4) C से जाने वाली किरण OE खींचते हैं। तब ∠EOA = 60° (5) D से जाने वाली किरण OF खींचते हैं। तब ∠FOE = 60° (6) पुनः C तथा D को केंद्र मानकर तथा ½ CD से बड़ी त्रिज्या लेकर चाप लगाइए, जो एक दूसरे को G पर प्रतिच्छेद करते है। (7) किरण OG खींचते हैं‌ । यह किरण OG , ∠FOE का समद्विभाजक होती है। अर्थात ∠FOG = ∠EOG = 1/2 ∠FOE = 1/2 (60°) = 30° अतः ∠GOA = ∠GOE + ∠EOA = 30° + 60° ∠GOA = 90° (8) अब, O को केंद्र मानकर तथा कोई त्रिज्या लेकर एक चाप लगाइए जो किरण OA तथा OG को क्रमशः बिंदु H तथा I पर प्रतिच्छेद करता है। (9) पुनः H तथा I को केंद्र मानकर तथा ½ HI से बड़ी त्रिज्या लेकर चाप लगाइए, जो एक दूसरे को J पर प्रतिच्छेद करते है। (7) किरण OJ खींचते हैं‌ । यह किरण OJ, ∠GOA का समद्विभाजक होती है। अर्थात ∠GOJ = ∠AOJ = 1/2 GOA = 1/2 (90°) = 45° औचित्य प्रतिपादन : BC को मिलाते है। तब OC = OB = BC। (रचना से) ∴ ΔCOB एक समबाहु त्रिभुज है। तब ∠COB =60° ∴ ∠ EOA = 60° (ii) CD को मिलाते है। तब , OD = OC = CD (रचना से) अतः ΔDOC एक समबाहु त्रिभुज है। तब ∠DOC = 60° . ∴ ∠ FOE = 60° (iii) CG तथा DG को मिलाते है। ΔODG तथा ΔOCG में, OD = OC (एक ही चाप की त्रिज्या) DG = CG (एक ही त्रिज्या के चाप) OG = OG [उभयनिष्ठ] ∴ ΔODG≅ Δ OCG [SSS सर्वांगसमता नियम द्वारा) ∴ ∠DOG =∠COG (CPCT द्वारा) ∴ ∠FOG = ∠EOG =1/2 ∠FOE = 1/2 (60°) = 30° अतः, ∠GOA = ∠GOE + ∠EOA = 30° + 60° = 90° (iv) HJ IJ ΔOIJ तथा ΔOHJ में, OI = OH (एक ही चाप की त्रिज्या) IJ = HJ (एक ही त्रिज्या के चाप) OJ = OJ [उभयनिष्ठ] ∴ ΔOIJ ≅ ΔHOJ [SSS सर्वांगसमता नियम द्वारा) ∴ ∠IOJ =∠HOJ (CPCT द्वारा) ∴ ∠AOJ = ∠GOJ =1/2 ∠GOA = 1/2 (90°) = 45° अतः ∠AOJ = 45° आशा है कि यह उत्तर आपकी मदद करेगा।।।। इस पाठ से संबंधित कुछ और प्रश्न : एक दी हुई किरण के प्रारंभिक बिन्दु पर के कोण की रचना कीजिए और कारण सहित रचना की पुष्टि कीजिए।

26.

I) एक दी हुई किरण के प्रारंभिक बिन्दु पर 45° के कोण की रचना कीजिए और कारण सहितरचना की पुष्टि कीजिए ।[NCERT]fromfaTOTTकीजिया

Answer»

Answer:

रचना के चरण :

(1) O को केंद्र मानकर तथा कोई त्रिज्या लेकर एक चाप लगाइए जो किरण OA को बिंदु B पर प्रतिच्छेद करता है।

(2) B को केंद्र मानकर और उसी त्रिज्या, जो पहले ली गई थी से एक चाप खींचते हैं जो चरण (1) में खींचे गए चाप को बिंदु C पर प्रतिच्छेद करता है।

(3) C को केंद्र मानकर और उसी त्रिज्या, जो पहले ली गई थी से एक चाप खींचते हैं, जो चरण (1) में खींचे गए चाप को बिंदु D पर प्रतिच्छेद करता है।

(4) C से जाने वाली किरण OE खींचते हैं। तब ∠EOA = 60°

(5) D से जाने वाली किरण OF खींचते हैं। तब ∠FOE = 60°

(6) पुनः C तथा D को केंद्र मानकर तथा ½ CD से बड़ी त्रिज्या लेकर चाप लगाइए, जो एक दूसरे को G पर प्रतिच्छेद करते है।

(7) किरण OG खींचते हैं‌ । यह किरण OG , ∠FOE का समद्विभाजक होती है।

अर्थात ∠FOG = ∠EOG = 1/2 ∠FOE = 1/2 (60°) = 30°

अतः ∠GOA = ∠GOE + ∠EOA

= 30° + 60°

∠GOA = 90°

(8) अब, O को केंद्र मानकर तथा कोई त्रिज्या लेकर एक चाप लगाइए जो किरण OA तथा OG को क्रमशः बिंदु H तथा I पर प्रतिच्छेद करता है।

(9) पुनः H तथा I को केंद्र मानकर तथा ½ HI से बड़ी त्रिज्या लेकर चाप लगाइए, जो एक दूसरे को J पर प्रतिच्छेद करते है।

(7) किरण OJ खींचते हैं‌ । यह किरण OJ, ∠GOA का समद्विभाजक होती है।

अर्थात ∠GOJ = ∠AOJ = 1/2 GOA = 1/2 (90°) = 45°

औचित्य प्रतिपादन :

BC को मिलाते है।

तब OC = OB = BC। (रचना से)

∴ ΔCOB एक समबाहु त्रिभुज है।

तब ∠COB =60°

∴ ∠ EOA = 60°

(ii) CD को मिलाते है।

तब , OD = OC = CD (रचना से)

अतः ΔDOC एक समबाहु त्रिभुज है।

तब ∠DOC = 60° .

∴ ∠ FOE = 60°

(iii) CG तथा DG को मिलाते है।

ΔODG तथा ΔOCG में,

OD = OC (एक ही चाप की त्रिज्या)

DG = CG (एक ही त्रिज्या के चाप)

OG = OG [उभयनिष्ठ]

∴ ΔODG≅ Δ OCG

[SSS सर्वांगसमता नियम द्वारा)

∴ ∠DOG =∠COG (CPCT द्वारा)

∴ ∠FOG = ∠EOG =1/2 ∠FOE = 1/2 (60°) = 30°

अतः, ∠GOA = ∠GOE + ∠EOA = 30° + 60° = 90°

(iv) HJ IJ

ΔOIJ तथा ΔOHJ में,

OI = OH (एक ही चाप की त्रिज्या)

IJ = HJ (एक ही त्रिज्या के चाप)

OJ = OJ [उभयनिष्ठ]

∴ ΔOIJ ≅ ΔHOJ

[SSS सर्वांगसमता नियम द्वारा)

∴ ∠IOJ =∠HOJ (CPCT द्वारा)

∴ ∠AOJ = ∠GOJ =1/2 ∠GOA = 1/2 (90°) = 45°

अतः ∠AOJ = 45°

आशा है कि यह उत्तर आपकी मदद करेगा।।।।

इस पाठ से संबंधित कुछ और प्रश्न :

एक दी हुई किरण के प्रारंभिक बिन्दु पर के कोण की रचना कीजिए और कारण सहित रचना की पुष्टि कीजिए।

Discussion

27.	मिठाई वाले में वे कौन से गुण थे जिनकी वजह से बच्चे तो बच्चे, बड़े भी उसकी ओर खिंचे चले आते थे?
Answer» निम्नलिखित कारणों से बच्चे तथा बड़े मिठाईवाले की ओर खिंचे चले आते थे मिठाई वाला मादक मधुर ढंग से गाकर अपनी चीज़ों को बेचता था। वह कम लाभ में बच्चों के खिलौने तथा मिठाइयाँ देता था। उसके हृदय में बच्चों के लिए स्नेह था, वह कभी गुस्सा नहीं करता था। हर बार नई चीजें लाता था। $.$

27.

मिठाई वाले में वे कौन से गुण थे जिनकी वजह से बच्चे तो बच्चे, बड़े भी उसकी ओर खिंचे चले आते थे?

Answer»

निम्नलिखित कारणों से बच्चे तथा बड़े मिठाईवाले की ओर खिंचे चले आते थे

मिठाई वाला मादक मधुर ढंग से गाकर अपनी चीज़ों को बेचता था।

वह कम लाभ में बच्चों के खिलौने तथा मिठाइयाँ देता था।

उसके हृदय में बच्चों के लिए स्नेह था, वह कभी गुस्सा नहीं करता था।

हर बार नई चीजें लाता था।

$.$

Discussion

28.	1. Which of the following numbers is an irrational Number?(a) V16-1 (b) (3- 73)(3+13)c) V5+3 (d)-725
Answer» ANSWER: option "C" Step-by-step explanation: c) root 5 + 3 HOPE THIS HELPS YOU

28.

1. Which of the following numbers is an irrational Number?(a) V16-1 (b) (3- 73)(3+13)c) V5+3 (d)-725

Answer»

ANSWER:

option "C"

Step-by-step explanation:

c) root 5 + 3

HOPE THIS HELPS YOU

Discussion

29.	ABC is a triangle in which altitudes BE and CF to sides AC and AB are equal. By using euclids axiom show that AB is equal to AC
Answer» Answer: ABC is an isosceles triangle in which altitudes BE and CF are drawn to equal sides AC and AB respectively Step-by-step EXPLANATION: hope this HELPS PLEASE follow

29.

ABC is a triangle in which altitudes BE and CF to sides AC and AB are equal. By using euclids axiom show that AB is equal to AC

Answer»

Answer:

ABC is an isosceles triangle in which altitudes BE and CF are drawn to equal sides AC and AB respectively

Step-by-step EXPLANATION:

hope this HELPS PLEASE follow

Discussion

30.	Which of the following is meaninglessa) IIICCb) MMMCCXIc) XDc) VC
Answer» VC is MEANING LESS and XD ALSO meaning less

30.

Which of the following is meaninglessa) IIICCb) MMMCCXIc) XDc) VC

Answer»

VC is MEANING LESS and XD ALSO meaning less

Discussion

31.	Solve :-4(2x-3)^2-(2x-3)=14
Answer» HOPE this ANSWER HELPS you follow me Mark me as BRAINLIST

31.

Solve :-4(2x-3)^2-(2x-3)=14

Answer»

HOPE this ANSWER HELPS you

follow me

Mark me as BRAINLIST

Discussion

32.	(x^2)1/2=x then what are the conditions for x to be
Answer» ANSWER: X isn't EQUAL to 0 it's a CONDITION

32.

(x^2)1/2=x then what are the conditions for x to be

Answer»

ANSWER:

X isn't EQUAL to 0 it's a CONDITION

Discussion

33.	If 21.875litesr of oil is in 1/2 cans of tin of equal capacity find the capacity oil in each can
Answer» Answer: 10.9375 litres Step-by-step explanation: 21.875×0.5

33.

If 21.875litesr of oil is in 1/2 cans of tin of equal capacity find the capacity oil in each can

Answer»

Answer:

10.9375 litres

Step-by-step explanation:

21.875×0.5

Discussion

34.	1. Which of the following numbers is an irrational Number?(a) V16 (b) (3- 13)(3+V3)etc) V5+3(0)-725tion of 2y+3y=k then the value of
Answer» I did'nt LIKE this QUESTION

Discussion

35.	Mary is on the student body council. The council will select 3 members at random. There is 50% chance that Mary will be chosen. How many students are there on the council?
Answer» INTUITIVELY, half the council needs to be chosen, so the council must have six members. For a formal proof, if n is the number on the council, the total number of POSSIBLE SELECTIONS is the number of ways to choose 3 from n. The number that include Marla is the number of ways to choose 2 from n-1 (Marla and TWO others). The ratio of these must be 1/2 from which you can find n. Hope this helps. #BE BRAINLY

35.

Mary is on the student body council. The council will select 3 members at random. There is 50% chance that Mary will be chosen. How many students are there on the council?

Answer»

INTUITIVELY, half the council needs to be chosen, so the council must have six members.

For a formal proof, if n is the number on the council, the total number of POSSIBLE SELECTIONS is the number of ways to choose 3 from n. The number that include Marla is the number of ways to choose 2 from n-1 (Marla and TWO others). The ratio of these must be 1/2 from which you can find n.

Hope this helps.

#BE BRAINLY

Discussion

36.	Estimate the product by rounding each of the factors to the nearest hundred . do not calculate actual answer. (a) 123*356
Answer» Step-by-step explanation: 123×456 =43788 =43800

36.

Estimate the product by rounding each of the factors to the nearest hundred . do not calculate actual answer. (a) 123*356

Answer»

Step-by-step explanation:

123×456

=43788

=43800

Discussion

37.	estimate the product by rounding each of the factors to the nearest hundred . do not calculate actual answer. (a) 5*6
Answer» ANSWER: 600 is a RIGHT answer of this QUESTION

37.

estimate the product by rounding each of the factors to the nearest hundred . do not calculate actual answer. (a) 5*6

Answer»

ANSWER:

600 is a RIGHT answer of this QUESTION

Discussion

38.	Find the area of triangle whose vertices are (1, -1), (-4, 6) and (-3,-5)
Answer» Step-by-step EXPLANATION: HOPE this HINT helps u pls FOLLOW me

38.

Find the area of triangle whose vertices are (1, -1), (-4, 6) and (-3,-5)

Answer»

Step-by-step EXPLANATION:

HOPE this HINT helps u

pls FOLLOW me

Discussion

39.	खिलौनेवाले के आने पर बच्चों की क्या प्रतिक्रिया होती थी?
Answer» खिलौनेवाले के आने पर बच्चे खिलौने देखकर पुलकित हो उठते थे। बच्चों का झुंड खिलौने वाले को चारों तरफ़ से घेर लेता था वे पैसे लेकर खिलौने का मोल भाव करने लगते थे। खिलौने पाकर बच्चे खुशी से उछलने - कूदने लगते थे। $.$

39.

खिलौनेवाले के आने पर बच्चों की क्या प्रतिक्रिया होती थी?

Answer»

खिलौनेवाले के आने पर बच्चे खिलौने देखकर पुलकित हो उठते थे। बच्चों का झुंड खिलौने वाले को चारों तरफ़ से घेर लेता था वे पैसे लेकर खिलौने का मोल भाव करने लगते थे। खिलौने पाकर बच्चे खुशी से उछलने - कूदने लगते थे।

$.$

Discussion

40.	What is secant and tangent of a circle
Answer» Answer: secant is TWO point that touching the circle tangent is ONE point that touching the circle pls MARK me as brainliest

40.

What is secant and tangent of a circle

Answer»

Answer:

secant is TWO point that touching the circle

tangent is ONE point that touching the circle

pls MARK me as brainliest

Discussion

41.	Solve the equation : 15p/15=90
Answer» Answer: I THINK it helps you....... Step-by-step explanation: PLEASE FOLLOW me....

41.

Solve the equation : 15p/15=90

Answer»

Answer:

I THINK it helps you.......

Step-by-step explanation:

PLEASE FOLLOW me....

Discussion

42.	Find the Zeros of the quadratic polynomial p(x)=xsquare-4x+3.find the sum and product of the zeros and verify the relationship to the coefficients and zeros of the polynomial.
Answer» <P>Step-by-step EXPLANATION: LET the roots be p,q such that SUM of roots p+q=(-b/a)=(-(-4/1))=4 and product of roots p×q=(c/a)=3/1=3 x²+bx+c=x²+(sum of roots)x+(product of roots)

42.

Find the Zeros of the quadratic polynomial p(x)=xsquare-4x+3.find the sum and product of the zeros and verify the relationship to the coefficients and zeros of the polynomial.

Answer»

<P>Step-by-step EXPLANATION:

LET the roots be p,q

such that SUM of roots

p+q=(-b/a)=(-(-4/1))=4

and product of roots

p×q=(c/a)=3/1=3

x²+bx+c=x²+(sum of roots)x+(product of roots)

Discussion

43.	If today is Thursday,what is the day on 175th day
Answer» 12 DECEMBER Saturday. hope it HELPED u mark as BRAINLIEST and thank me .

43.

If today is Thursday,what is the day on 175th day

Answer»

12 DECEMBER Saturday.

hope it HELPED u mark as BRAINLIEST and thank me .

Discussion

44.	2.5 hours =_______ metres?
Answer» ANSWER: If your MEAN is MINUTE. So, answer is 150 MINUTES.

44.

2.5 hours =_______ metres?

Answer»

ANSWER:

If your MEAN is MINUTE. So, answer is 150 MINUTES.

Discussion

45.	X cm : 50 cm = 25 cm: 125 cm
Answer» ANSWER: X125=5025 X*125=1250 X=1250/125 X=10 hope you like my answer... mark as brainliest answer..

45.

X cm : 50 cm = 25 cm: 125 cm

Answer»

ANSWER:

X*125=50*25
X*125=1250
X=1250/125
X=10

hope you like my answer...

mark as brainliest answer..

Discussion

46.	2. The fuel efficiency (in kilometres per litre) of a bus going at a speed of x kilometres per hour is given by1the polynomial Find the fuel efficiency when x = 65 km/h. Find the speed the bus should travel at to save the most fuel
Answer» ANSWER: SORRY did not UNDERSTAND

46.

2. The fuel efficiency (in kilometres per litre) of a bus going at a speed of x kilometres per hour is given by1the polynomial Find the fuel efficiency when x = 65 km/h. Find the speed the bus should travel at to save the most fuel

Answer»

ANSWER:

SORRY did not UNDERSTAND

Discussion

47.	B) - 12govebysubstitution methodby 300+3y=9x+y=37)Two yearshis daughter six years thanoldwillherSalim wais thrice alate, heyears oldertwiceoldare they nowbeTourage, howo - lxt9
Answer» ANSWER: I have written this whole answer on Google check it out and yesss please MARK me as BRAINLIEST please please

47.

B) - 12govebysubstitution methodby 300+3y=9x+y=37)Two yearshis daughter six years thanoldwillherSalim wais thrice alate, heyears oldertwiceoldare they nowbeTourage, howo - lxt9

Answer»

ANSWER:

I have written this whole answer on Google check it out and yesss please MARK me as BRAINLIEST please please

Discussion

48.	SolN4. Radius of a racing track is 126 m. What will be the time taken by Tanveer to complete oneround at a speed of 6 km/hr?
Answer» ANSWER: The time taken by tanvèer to COMPLETE ONE round is 36

48.

SolN4. Radius of a racing track is 126 m. What will be the time taken by Tanveer to complete oneround at a speed of 6 km/hr?

Answer»

ANSWER:

The time taken by tanvèer to COMPLETE ONE round is 36

Discussion

49.	E. Pranshu needs 3m of cloth for stitching atrousers. If he wants 5 trousers to be stitched,how much cloth should he buy?Measure of cloth needed = ....... ... = ..m
Answer» ANSWER: PRANSHU NEED CLOTHES for STICHING

49.

E. Pranshu needs 3m of cloth for stitching atrousers. If he wants 5 trousers to be stitched,how much cloth should he buy?Measure of cloth needed = ....... ... = ..m

Answer»

ANSWER:

PRANSHU NEED CLOTHES for STICHING

Discussion

50.	The sum of two integers is -10 and one of them is 2 find the other
Answer» ANSWER:-12 Step-by-step EXPLANATION: X+2=-10 X = -10-2 X = -12

50.

The sum of two integers is -10 and one of them is 2 find the other

Answer»

ANSWER:-12

Step-by-step EXPLANATION:

X+2=-10

X = -10-2

X = -12

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