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12 सेंटीमीटर त्रिज्या 10 सेंटीमीटर ऊंचाई वाले लंब वृत्तीय बेलन का संपूर्ण पृष्ठ ज्ञात कीजिए |
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Answer» Given: A cube can be inscribed cylinder of radius 5 cm and height 12 cm. To Find: What is the total SURFACE AREA of LARGEST cube ? Solution: Radius of cylinder (R) = 5 cm Diameter of cylinder (D) = 10 cm It is clear that DIAGONAL of face of cube will be diameter of cylinder: Diagonal of face of cube = 10 cm So side of cube: Side² + Side² = Diagonal² 2×Side² = Diagonal² On putting respective value in above equation: 2×Side² = 10² 2×Side² = 100 Side² = 50 ...1) Side = √50 Means side of cube = √50 cm √50 < 12 √50 < height of cylinder So √50 is largest side of cube: Total surface area of cube will be: Total surface are = 6× Side² From equation 1): Total surface are = 6× 50 Total surface are = 300 cm² So total surface area of largest cube which can be inscribed cylinder of radius 5 cm and height 12 cm is 300 cm². follow me please... Mark as brainliest please... |
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