Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Wht is water cycle.........​

Answer»

Answer:

The water CYCLE shows the continuous MOVEMENT of water within the Earth and atmosphere. It is a complex system that includes many different processes. Liquid water evaporates into water vapor, CONDENSES to form clouds, and precipitates back to earth in the form of rain and snow.

Step-by-step EXPLANATION:

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2.

URGENT: WILL MARK AS BRAINLIEST: CENTER OF DILATION:

Answer»

ANSWER:

C is the DILATION of the TRIANGLE m

3.

Matrices. please give handwritten Answers.​

Answer»

Answer:- a = 2

b = 4

Solution:-

If two matrices are equal then,

  • a + b = 6 ••••••••• (1)
  • AB = 8 ••••••••••••• (2)

From EQ (2), b = 8/a

Now, Put the value of 'b' in eq (1)

  • a + 8/a = 6
  • 2A + 8 = 6a
  • 8 = 4a
  • a = 2
  • a = 2B = 4

₣øⱡⱡø₩ ₥ɇ

4.

SOMEONE HELP WITH ANSWER THANK YOU!!!!

Answer»

ANSWER:

93 Will be the answer PLZ if WRONG so FORGIVE me

5.

Plz plz plz solve this​

Answer»

QUESTION ERROR Bro/Sis◆◆.......I THINK So....☺️☺️

6.

What is the condition of base of logarithm of a number?​

Answer»

ANSWER:

The base of the logarithm: Can be only POSITIVE numbers not equal to 1. The ARGUMENT of the logarithm: Can be only positive numbers (because of the restriction on the base) The VALUE you get for the logarithm after plugging in the base and argument: Can be positive or NEGATIVE numbers.

7.

If point G is between point S and R. And SG = 3x, GR = 2x + 30, and SR = 10x + 15. Solve for x. NO SPAMZZ PLZZZ​

Answer»
8.

Draw a triangle ABC With side

Answer»

Step-by-step EXPLANATION:

Here is the ANSWER..............

9.

6. Represent graphically the equation 3x - 17 = 51 inthe Cartesian plane​

Answer»

Answer:

3x-17=51

3x=51-17

3x=34

x=34÷3

x=11.9

10.

Find the length of segment AC if AB = 7.8 cm and BC = 25 mm. How many solutions are there in each case? a Point B lies on segment AC. Point B lies on line AC.

Answer»

Given \: length \:of \: segment \:AB = 7.8 \:cm

and \: length \:of \: segment \: BC

= 25 \:mm

= \frac{25}{10} \:cm

= 2.5 \: cm

\red{Length \:of \: segment \: AC}

= AB + BC

\blue{ ( given \: Point \: B \: lies \: on \: segment \: AC )}

= 7.8 \:cm + 2.5 \:cm

= 10.3 \:cm

THEREFORE.,

\red{Length \:of \: segment \: AC}\green {= 10.3 \:cm }

•••♪

11.

Two numbers are in the raio 5:6. If 8 is subtracted from each of the numbers, the ratio becomes 4:5.Find the numbers.​

Answer»

\huge\red{\underline{{\boxed{\textbf{ANSWER}}}}}

★ Let the two no be x and y

therefore x / y = 5 / 6

6 * x = 5 * y

6 * x - 5 * y = 0 * 5

30 * x - 25 * y = 0 ..................(i)

also (x - 8)/(y - 8) = 4 / 5

5 * x - 40 = 4 * y - 32

5 * x - 4 * y - 8 = 0 *6

30 * x - 24 * y - 48 = 0 .....................(II)

SUBTRACTING (i) from (ii)

y - 48 = 0

y = 48

putting y = 48 in x/y = 5/6

x/48 = 5/6

x = 5 * 48 / 6

x = 5 * 8

x = 40

★ Therefore the two numbers are 40 and 48

12.

Smallest to largest 0,-3,2 from which is smallest to largest.

Answer»

Step-by-step explanation:

SMALLEST to LARGEST

-3< 0< 2

13.

If x = 3-√3/2 what is the value of x^2 +1/x^2

Answer»

ANSWER:

HOPE ITS HELP U.......

14.

Solve by graphicalyy system of equation X+y=33x-2y=4

Answer»

Answer:

hope it's HELP U plz LIKE

15.

Angle p equal angle q and angle 1 equal angle 2 prove rt parallel pq

Answer»

The LINES OPPOSITE to each other is ALWAYS PARELLEL to each other

16.

To buy an article marked Rs 20000 we get a discount of 15% and have to pay VAT at the rate of 13%, how much VAT amount we have to pay to buy that article?

Answer»

Answer:

2210

Step-by-step explanation:

15% DISCOUNT20000 ,= 17000.

13% VAT on 17000 = 2210

17.

Find the least number of 8 digits which is a perfect square largest

Answer»

ANSWER:

very EASY YAAR ........ 00000000

18.

(4,4) tell me graphe​

Answer»

I HOPE you GOT your ANSWER

19.

Please refer to the above attachment about logarithm where we need to find the value of x​

Answer»

ANSWER:

PLEASE MARK my answer as BRAINLIEST please please please please please please

20.

Ahmad is driving on a road. He observed that the road is inclined at an angle of 6 degree .He travelled 1.5km on this inclined road. How high above road level is Ahmad??

Answer»

Given:

Ahmad is traveling on a road at an INCLINATION of 6^\circ.

Distance traveled = 1.5 km

To find:

Height of Ahmad above road level = ?

Solution:

The given situation can be represented in the form of a right angled TRIANGLE \triangle ABC as shown in the attached figure in answer area.

The SIDE BC REPRESENTS the road level.

The distance traveled by Ahmad is AC = 1.5 km

\angle C =6^\circ

And the side AB is to be found.

We can use trigonometric identity of Sine here to find AB.

We KNOW that:

sin\theta =\dfrac{Perpendicular}{Hypotenuse}

sinC=\dfrac{AB}{AC}\\\Rightarrow sin6=\dfrac{AB}{1.5}\\\Rightarrow AB = 1.5 \times sin6\\\Rightarrow AB = 1.5 \times 0.1045\\\Rightarrow AB = 0.1568\ km \ or\ 156.8 \ m

So, Ahmad is 0.1568 km or 156.8 m high above road level.

21.

Kisike pass time hai hmse baat krn ka​

Answer»

Answer:

nhi he khud se to kabhi kuch baat karlo..

gni8 and SWEET DREAMS :]

22.

5 rational no between 0.45 & 0.46​

Answer»

ANSWER:

5 RATIONAL no. between 0.45 & 0.46 are

0.451, 0.452, 0.453, 0.454, 0.455

23.

What is the lastest number

Answer»

Answer:

999

Step-by-step EXPLANATION:

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24.

What time it will be 30 minutes before 12 noon

Answer»

Answer:

11:30 will be the RIGHT TIME

25.

3/2x + 5/3y = 7 9x + 10y = 14 are these consistent

Answer»

ANSWER:

HOPE IT'S HELP U.......

26.

Prove that 1 by 3 minus 2 root 5 is irrational if root 5 is irrational

Answer»

Step-by-step explanation:

here BUDDY here is the answer for the question pls mark as BRAINLIEST.

27.

In triangle ABC and DEF AB=FD and angle A=angle D.the two triangles will be congruent by sas axiom if

Answer»

Step-by-step explanation:

two triangle will be CONGRUENT if BC = DE, AC = FE

28.

2.5cm solve it find area of squares with lengths of side

Answer»

ANSWER:

2.5^2...as FORMULA to find area of SQUARE is SIDE ×side ...HENCE side^2..so answer is 2.5^2

29.

Complaint about fraud payment throughtout phonepe money lost by fraud call.

Answer»

Answer:

bhai ye SAB tu google pe kar YAHAN KISI ko nahi pata

Step-by-step explanation:

PLEASE MARK ME AS BRAINLIST

PLEASE MARK ME AS BRAINLIST

30.

The hitch hiker story is ironic

Answer»

YES it is IRONIC too and of ALLEGORY TYPE too

31.

Prove that √2,√3,√5 is a irrational numbers

Answer»

Answer:

I hope it's help U.....

U have to write FULL sentence this is the correct WAY of WRITING and this will GIVE u full marks in this question

32.

What do all alkalis contain

Answer»

ANSWER:

All alkalies CONTAINS ion of hydroxide OH- .

33.

Sin2 48 degree + sin2 42 degree =1​

Answer»

Step-by-step EXPLANATION:

sin²48 + sin²42

sin²48 + sin²(90-48)

sin²48 + cos²48

(there is an IDENTITY Sin²A + Cos²A = 1)

THEREFORE sin²48+cos²48 = 1

34.

What were the compound numbers from 1 to 1000​

Answer»

Step-by-step explanation:

4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 22, 24, 25, 26, 27, 28, 30, 32, 33, 34, 35, 36, 38, 39, 40, 42, 44, 45, 46, 48, 49, 50, 51, 52, 54, 55, 56, 57, 58, 60, 62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76, 77, 78, 80, 81, 82, 84, 85, 86, 87, 88, 90, 91, 92, 93, 94, 95, 96, 98, 99, 100, 102, 104, 105, 106, 108

and so on

35.

Sum of three numbers in AP is -3 and product is 8 find the numbers

Answer»

Answer:

the SUM of three no is -3 ok

let no be X

x+x+x=-3

second case

x+x+x=8

simple 8X3=24

first no =24

then 24+24+2=ans

36.

In an acute angle triangle ABC, sin (A + B - C) = 12, cot (A - B + C) = 0 and cos (B + C – A) =12. What are the values of A, B, and C?​

Answer»

Step-by-step explanation:

We know that in a triangle, sum of the angles = 180°

A+B+C = 180 → (1)

sin 30

1 \div 2 \\

cos45

1 \div  \sqrt{2 }

So,

sin (A+B-C) = sin 30

A+B-C = 30 → (2)

And

COS (B+C-A) = cos 45

B+C-A = 45 → (3)

On SOLVING equation (1) and (2), we GET,  

A+B+C-A-B+C = 180-30 = 150

2C = 150

C = 75°

Substituting C=75 in equation (2), we get,

A+B-75 = 30

A+B = 105 → (4)

Also, substituting in equation (3), we get,

B+75-A =45

A-B = 30 → (5)

Adding equations (4) and (5), we get,

2A = 135 → A = 67.5°

B = A-30 = 67.5 - 30 = 37.5°

Therefore, A=67.5°; B=37.5°; and C=75°

37.

When we multiply a rational number with one, we get same number :true or false

Answer»

ANSWER:

it's a UNIVERSAL truth dood

Step-by-step EXPLANATION:

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I am WORKING very hard for you all....

Thanku

38.

-12a-7=5 find 3 solutions of equation

Answer»

ANSWER:

here MATE here is the answer for the question pls MARK as BRAINLIEST.

39.

What should be added to 2/3 so as to get 1/15

Answer»

ANSWER:

-27/45

Step-by-step explanation:

2/3 + X = 1/15

2+3x/3 = 1/15

now CROSS multiply

15(2+3x) = 3

30 + 45x = 3

45x = -27

x = -27/45

add -27/45

40.

Divide x3 – 3x2 + 3x – 5 by x2 – x +1. Find the quotient and remainder

Answer»

Answer:

The quotient is X - 2 while the REMAINDER is -3

Step-by-step EXPLANATION:

÷\frac{x^{3} - 3x^{2} + 3x - 5  }{x^{2} - x + 1 }

41.

If LCM ( 306,657) =22338 then HCF (306,657) will be :

Answer»

LCM ( 306,657) =22338

So , HCF (306,657) = 9

657 = 306×2 + 45

306 = 45×6 + 36

45 = 36×1 + 9

36 = 9×4 +0

42.

) If p2 x 2 – q 2 = 0, then value of x is

Answer»

Step-by-step EXPLANATION:

WRITE CORRECT QUESTION...

43.

Find the smallest perfect square divisible by 6,8,10,12

Answer»

Answer:

3600 is a perfect square

Step-by-step explanation:

TAKE LCM of (6,8,12 and 10) = 120

Resolving 120 into prime factors, we get

120 = 2*2*2*3*5

Here 2 is grouped in PAIRS of equal factors. But 2, 3 and 5 are not grouping in pairs of equal factors.

Let us multiply 2, 3 and 5 , we get a grouped in pairs of equal factors.

120*2*3*5 = 2*2*2*2*3*3*5*5

3600 = 2*2*2*2*3*3*5*5

Now 3600 is perfect square that is divisible by 6, 8, 12, 10

44.

Sheenam types 68 words par minutes. How many word will she type in 3 hours and 40 minutes?

Answer»

Answer:

14,960 words

Step-by-step explanation:

3 HOURS and 40 minutes = 3 * 60 + 40 minutes = 220 minutes

Sheenum types 68 words PER minute

then in 220 minutes, she can TYPE = 68 * 220 = 14.960 words

45.

9cos2A+9sin2Aka maan kya hoga

Answer»

Answer:9(cos2A+sin2A)

Step-by-step EXPLANATION:

46.

The sum of the digits of a two digir number is 7 . The number obtained by interchanging the digits exceeds the original number by 27 . Find the number

Answer»

GIVEN:

  • The sum of the digits of a two DIGIT number is 7
  • The number obtained by INTERCHANGING the digits exceeds the ORIGINAL number by 27

TO FIND:

  • What are the numbers ?

SOLUTION:

Let the digit at the unit's place be 'y' and the digit at ten's place be 'x'

 ❒ NUMBER = 10x + y

CASE:- 1

The sum of the digits of a two digit number is 7

According to question:-

\bf{\hookrightarrow x + y = 7...1)}

\rm{\hookrightarrow x = 7-y }

CASE:- 2

The number obtained by interchanging the digits exceeds the original number by 27.

  • Number obtained by reversing the digits = 10y + x
  • Number obtained by reversing the digits = Original number + 27

According to question:-

\rm{\hookrightarrow 10y + x = <klux>10X</klux> + y + 27 }

\rm{\hookrightarrow -27 = 10x+y-10y-x }

\rm{\hookrightarrow -27 = 9x-9y }

Taking 9 as common from both sides

\bf{\hookrightarrow -3 = x-y....2) }

Put the value of 'x' in EQUATION 2)

\rm{\hookrightarrow -3 = 7-y-y }

\rm{\hookrightarrow -3-7 = -2y }

\rm{\hookrightarrow -10 = -2y }

\rm{\hookrightarrow \cancel\dfrac{-10}{-2} = y }

\bf{\hookrightarrow 5 = y }

Put the value of 'y' in equation 1)

\rm{\hookrightarrow x + 5 = 7 }

\rm{\hookrightarrow x = 7-5 }

\bf{\hookrightarrow x = 2 }

  • Number = 10x + y
  • Number = 10(2)+5
  • Number = 20+5
  • Number = 25

Hence, the number is 25

______________________

47.

Another line “r” is perpendicular to the line 3y = 6x + 9. Find the gradient of the line “r”.

Answer»

concept :-

Let, m and N be the gradients/slopes of two perpendicular lines

then, n = -1

& equation of LINE can be written as

y = mx + C , where m = gradient of line and c = y-intercept

Solution:-

Given equation of line is-

3y = 6x + 9

or, y = 2x + 3

gradient of above line (m) = 2

Let n be the GRADIENT of line r

Lines are perpendicular

therefore, n = -1

or, n = (-1)/m

or, n= (-1)/2 = -0.5

Hence, Gradient of line r is -1/2.

48.

#integration____________​

Answer»

We're asked to EVALUATE,

\displaystyle\longrightarrow\sf{\int\dfrac{1}{(x^<klux>2</klux>-4)\sqrt{x+1}}\ dx=\,?}

Let,

\displaystyle\longrightarrow\sf{u=\sqrt{x+1}}

\displaystyle\longrightarrow\sf{x=u^2-1}

\displaystyle\longrightarrow\sf{dx=2u\ du}

Also,

\displaystyle\longrightarrow\sf{x^2-4=(u^2-1)^2-4}

\displaystyle\longrightarrow\sf{x^2-4=u^4-2u^2-3}

\displaystyle\longrightarrow\sf{x^2-4=u^4+u^2-3u^2-3}

\displaystyle\longrightarrow\sf{x^2-4=u^2(u^2+1)-3(u^2+1)}

\displaystyle\longrightarrow\sf{x^2-4=(u^2+1)(u^2-3)}

Thus,

\displaystyle\longrightarrow\sf{\int\dfrac{1}{(x^2-4)\sqrt{x+1}}\ dx=\int\dfrac{1}{(u^2+1)(u^2-3)u}\cdot2u\ du}

\displaystyle\longrightarrow\sf{\int\dfrac{1}{(x^2-4)\sqrt{x+1}}\ dx=2\int\dfrac{1}{(u^2+1)(u^2-3)}\ du\quad\quad\dots(1)}

Let,

\displaystyle\longrightarrow\sf{\dfrac{1}{(u^2+1)(u^2-3)}=\dfrac{2Au+B}{u^2+1}+\dfrac{2Cu+D}{u^2-3}\quad\quad\dots(2)}

for some constants \sf{A} and \sf{B.}

\displaystyle\longrightarrow\sf{\dfrac{1}{(u^2+1)(u^2-3)}=\dfrac{(2Au+B)(u^2-3)+(2Cu+D)(u^2+1)}{(u^2+1)(u^2-3)}}

\displaystyle\longrightarrow\sf{(2Au+B)(u^2-3)+(2Cu+D)(u^2+1)=1}

\displaystyle\longrightarrow\sf{2Au^3-6Au+Bu^2-3B+2Cu^3+2Cu+Du^2+D=1}

\displaystyle\longrightarrow\sf{2(A+C)u^3+(B+D)u^2-2(3A-C)u+(D-3B)=1}

Equating corresponding coefficients,

\displaystyle\longrightarrow\sf{A+C=0}

\displaystyle\longrightarrow\sf{B+D=0}

\displaystyle\longrightarrow\sf{3A-C=0}

\displaystyle\longrightarrow\sf{D-3B=1}

Solving these FOUR equations we get,

\displaystyle\longrightarrow\sf{A=0}

\displaystyle\longrightarrow\sf{B=-\dfrac{1}{4}}

\displaystyle\longrightarrow\sf{C=0}

\displaystyle\longrightarrow\sf{D=\dfrac{1}{4}}

Then (2) becomes,

\displaystyle\longrightarrow\sf{\dfrac{1}{(u^2+1)(u^2-3)}=\dfrac{-\frac{1}{4}}{u^2+1}+\dfrac{\frac{1}{4}}{u^2-3}}

\displaystyle\longrightarrow\sf{\int\dfrac{1}{(u^2+1)(u^2-3)}\ du=\int\left(\dfrac{-\frac{1}{4}}{u^2+1}+\dfrac{\frac{1}{4}}{u^2-3}\right)\ du}

\displaystyle\longrightarrow\sf{\int\dfrac{1}{(u^2+1)(u^2-3)}\ du}=\ \ &\sf{-\dfrac{1}{4}\int\dfrac{1}{u^2+1}\ du+\dfrac{1}{4}\int\dfrac{1}{u^2-3}\ du}

We know that,

  • \displaystyle\sf{\int\dfrac{1}{x^2+1}=\tan^{-1}x}

  • \displaystyle\sf{\int\dfrac{1}{x^2-a^2}\ dx=\dfrac{1}{2a}\ln\left|\dfrac{x-a}{x+a}\right|} for some constant \sf{a.}

So,

\displaystyle\longrightarrow\sf{\int\dfrac{1}{(u^2+1)(u^2-3)}\ du=-\dfrac{1}{4}\tan^{-1}u+\dfrac{1}{8\sqrt3}\ln\left|\dfrac{u-\sqrt3}{u+\sqrt3}\right|}

So (1) will be,

\displaystyle\longrightarrow\sf{\int\dfrac{1}{(x^2-4)\sqrt{x+1}}\ dx=\dfrac{1}{4\sqrt3}\ln\left|\dfrac{u-\sqrt3}{u+\sqrt3}\right|-\dfrac{1}{2}\tan^{-1}u+c}

UNDOING \sf{u=\sqrt{x+1},} we get,

\displaystyle\begin{aligned}\longrightarrow\ \ &\sf{\int\dfrac{1}{(x^2-4)\sqrt{x+1}}\ dx}\\\\=\ \ &\underline{\underline{\sf{\dfrac{1}{4\sqrt3}\ln\left|\dfrac{\sqrt{x+1}-\sqrt3}{\sqrt{x+1}+\sqrt3}\right|-\dfrac{1}{2}\tan^{-1}\sqrt{x+1}+c}}}\end{aligned}

49.

5. Find the measure of the angles formed between the minute hand and the hour hand ofclock at the following timesa. 3 am​

Answer»

Answer:

90°

Step-by-step explanation:

CONSIDERING a CLOCK

the hour hand points at 3

and the minute hand at 12 (meaning 3 am)

hence it forms a right angle =90°

50.

If the sum of an A.P. is the same for p as for q terms, shew that its sumfor (p + q) terms is zero.​

Answer»

Answer:

I'm assuming by A.P. you mean arithemtic progression.

The general form of the nth TERM sum of an arithemtic progression is s_n = \frac{n(a_1+a_n)}{2}, where a_1 is the initial term, and a_n is the nth term. Then if the sum is the same for p and q terms, where p \neq q, then we have that

s_p =\frac{p(a_1 + a_p)}{2}=\frac{q(a_1 + a_q)}{2}= s_q.

Multiplying both sides of the EQUATION by 2 yields

p(a_1 + a_p) = q(a_1+a_q),

expanding then gives

pa_1+pa_p = qa_1+qa_q.

Substituting a_p and a_q for the general form of the nth term of an arithmetic progression, a_n = a_1 + (n-1)d, where d is the difference between consecutive terms, gives

pa_1+pa_1+pd-d = qa_1 + qa_1 + qd-d.

Adding d to both sides yields

2pa_1 + pd = 2qa_1 + qd,

factorizing results in

p(2a_1 + d) = q(2a_1 + d).

As we know that p \neq q, then the above equation holds only if 2a_1+d = 0. Hence, 2a_1+ d = 0.

We also notice that  the two sums being equal implies d = 0, otherwise the terms of the progression WOULD be of increasing size and the pth and qth sum could not be equal, which would contradict our assumption that s_p = s_q

Hence, we have that 2a_1 = 0, which CLEARLY implies that a_1 = 0.

Then we find the (p+q)th sum:

\frac{(p+q)(a_1 + a_{p+q})}{2}

We know that a_{p+q} = a_1 + (p+q)d. Substituting in the known VALUES for a_1 and d gives a_{p+q} = 0 + (p+q)0 = 0

substituting this into \frac{(p+q)(a_1 + a_{p+q})}{2} yields

\frac{(p+q)(0+0)}{2}

which is indeed equal to zero. Hence we have shown what was required.