1.

Ahmad is driving on a road. He observed that the road is inclined at an angle of 6 degree .He travelled 1.5km on this inclined road. How high above road level is Ahmad??

Answer»

Given:

Ahmad is traveling on a road at an INCLINATION of 6^\circ.

Distance traveled = 1.5 km

To find:

Height of Ahmad above road level = ?

Solution:

The given situation can be represented in the form of a right angled TRIANGLE \triangle ABC as shown in the attached figure in answer area.

The SIDE BC REPRESENTS the road level.

The distance traveled by Ahmad is AC = 1.5 km

\angle C =6^\circ

And the side AB is to be found.

We can use trigonometric identity of Sine here to find AB.

We KNOW that:

sin\theta =\dfrac{Perpendicular}{Hypotenuse}

sinC=\dfrac{AB}{AC}\\\Rightarrow sin6=\dfrac{AB}{1.5}\\\Rightarrow AB = 1.5 \times sin6\\\Rightarrow AB = 1.5 \times 0.1045\\\Rightarrow AB = 0.1568\ km \ or\ 156.8 \ m

So, Ahmad is 0.1568 km or 156.8 m high above road level.



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