332354 + Interview Questions in Secondary School in Math

1.	Discuss the considered that determining the selection of a suitable average. Explain by giving one example of each case.
Answer» The factors that MUST be CONSIDERED for determining 5he AMOUNT of depreciation are: number of year number of yearsscrap value valuedepreciation PERCENTAGE sold or purchased ledger account for depreciation and goods account ❤✌

1.

Discuss the considered that determining the selection of a suitable average. Explain by giving one example of each case.

Answer»

The factors that MUST be CONSIDERED for determining 5he AMOUNT of depreciation are:

number of year

number of yearsscrap value

valuedepreciation PERCENTAGE

sold or purchased

ledger account for depreciation and goods account ❤✌

Discussion

2.	Solve for x and y :- x/2 +y=0.8 x+y/2=0.7
Answer» Step-by-step EXPLANATION: HOPE this is the ANSWER.......... x=2/5 y=3/5

2.

Solve for x and y :- x/2 +y=0.8 x+y/2=0.7

Answer»

Step-by-step EXPLANATION:

HOPE this is the ANSWER..........

x=2/5

y=3/5

Discussion

3.	Finding HCF by continued division method finding the HCF of 18 24 and 30
Answer» Step-by-step explanation: 18= 3×3×2 24=3×2×2×2 30=3×5×2 Here 3 and 2 are COMMON in 18,24 & 30 therefore the HCF of 18,24 & 30 is 3×2=6 6 is the HCF of 18,24 & 30 Hope this is the answer.........

3.

Finding HCF by continued division method finding the HCF of 18 24 and 30

Answer»

Step-by-step explanation:

18= 3×3×2

24=3×2×2×2

30=3×5×2

Here 3 and 2 are COMMON in 18,24 & 30

therefore the HCF of 18,24 & 30 is

3×2=6

6 is the HCF of 18,24 & 30

Hope this is the answer.........

Discussion

4.	What should be added to twice of 5 by 2 to get 2 by 5
Answer» Answer: x = -23/5 Step-by-step EXPLANATION: LET x be added A/Q x + 2 × 5/2 = 2/5 x + 5 = 2/5 x = 2/5 - 5 x = - 5 + 2/5 x = - 23/5 ANS Plz mark as brainliest.

4.

What should be added to twice of 5 by 2 to get 2 by 5

Answer»

Answer:

x = -23/5

Step-by-step EXPLANATION:

LET x be added

A/Q

x + 2 × 5/2 = 2/5

x + 5 = 2/5

x = 2/5 - 5

x = - 5 + 2/5

x = - 23/5 ANS

Plz mark as brainliest.

Discussion

5.	Which of the following word has the sound sinilar to that of chair
Answer» ANSWER: I DONNO what is in Ur OPTIONS but a word familiar to chair is "CHARE" meaning a chore or household work.

5.

Which of the following word has the sound sinilar to that of chair

Answer»

ANSWER:

I DONNO what is in Ur OPTIONS but a word familiar to chair is "CHARE" meaning a chore or household work.

Discussion

6.	143,151,158,172,182,? Give me ans. with explanation
Answer» Answer: 192 Step-by-step explanation: ADD 20 in 4TH term .... plzz mark me BRAINLIST....

6.

143,151,158,172,182,? Give me ans. with explanation

Answer»

Answer:

192

Step-by-step explanation:

ADD 20 in 4TH term ....

plzz mark me BRAINLIST....

Discussion

7.	Classmate - India's No.notebook brandupon veg 4AzzubUred ourweg 8The characters in the given figure follows a certain rule row-wise or column-wise.Identify the rule and find the missing number.183.216171381792320191615B-8C-16-0-9Can you find the missing number?CXA-31x2=62
Answer» ANSWER: GOOD morning here is your answer 2

7.

Classmate - India's No.notebook brandupon veg 4AzzubUred ourweg 8The characters in the given figure follows a certain rule row-wise or column-wise.Identify the rule and find the missing number.183.216171381792320191615B-8C-16-0-9Can you find the missing number?CXA-31x2=62

Answer»

ANSWER:

GOOD morning

here is your answer

2

Discussion

8.	Arithmetic Progression, Class X CBSE
Answer» First term a = -4/3 COMMON difference d = -1-(-4/3) = -1+4/3 = 1/3 Suppose there are N terms in the given AP. Then, Thus, the given AP contains 18 terms. So, there are two middle terms in the given AP. The middle terms of the given AP are (18/2)th terms and (18/2+1)th term i.e. 9TH term and 10th term. Sum of the middle most terms of the given AP. = 9th term + 10th term. Hence, the sum of the middle most terms of the given AP is 3. Hope it helps you

Discussion

9.	Form the quadratic equation from the roots given below. (2) 3 and -10
Answer» ANSWER: Quadratic EQUATION is X^2 - (3+(-10))x + 3*(-10) i.e x^2 + 7x - 30 = 0

9.

Form the quadratic equation from the roots given below. (2) 3 and -10

Answer»

ANSWER:

Quadratic EQUATION is X^2 - (3+(-10))x + 3*(-10) i.e x^2 + 7x - 30 = 0

Discussion

10.	Q2. Condition satisfied by q so that rational number in lowest form as plahas a terminating decimal expansion. a) Q = 3m x 2n; where mand n arewhole numbers b) Q = 2m x 3n; where m and n are whole numbers c) Q =3m x 5n; where m and n are whole numbers d) None of these
Answer» $\underline{\blue{Theorem:}}$ $Let \: Q \: be \: a \: rational \:number \: whose$ $decimal \: expansion \:terminates . Then \:Q$ $can \:be \: expressed \: in \:the \: form \:of \:\frac{p}{q},$ $where \:p \:and \: q \: are \: Coprime , and \:the$ $prime \: Factorisation \: of \: \pink{q} \: is \: of$ $the \:form \: \orange { 2^{n} 5^{m}} ,where$ $n, m \: are \: non - negative \:integers .$ THEREFORE., $Option \: \green { ( d ) } \: is \: correct.$ ••••

10.

Q2. Condition satisfied by q so that rational number in lowest form as plahas a terminating decimal expansion. a) Q = 3m x 2n; where mand n arewhole numbers b) Q = 2m x 3n; where m and n are whole numbers c) Q =3m x 5n; where m and n are whole numbers d) None of these

Answer»

$\underline{\blue{Theorem:}}$

$Let \: Q \: be \: a \: rational \:number \: whose$

$decimal \: expansion \:terminates . Then \:Q$

$can \:be \: expressed \: in \:the \: form \:of \:\frac{p}{q},$

$where \:p \:and \: q \: are \: Coprime , and \:the$

$prime \: Factorisation \: of \: \pink{q} \: is \: of$

$the \:form \: \orange { 2^{n} 5^{m}} ,where$

$n, m \: are \: non - negative \:integers .$

THEREFORE.,

$Option \: \green { ( d ) } \: is \: correct.$

••••

Discussion

11.	Form the quadratic equation from the roots given below. (2) 3 and -10
Answer» Answer: 3 and 10 are roots let these TWO roots be $\alpha \: and \: \beta$ $\alpha = 3 \: and \: \beta = 10$ the structure of quadratic EQUATION is ${x}^{2} - (sum \: of \: roots)x + product \: of \: roots$ ${x}^{2} - ( \alpha + \beta )x + \alpha \beta$ $\alpha + \beta = 3 + 10 = 13$ $\alpha \beta = 3 \times 30$ •°• the equation is ${x}^{2} - 13x + 30$ PLEASE MARK MY ANSWER AS BRAINLIEST. I NEED THIS

11.

Form the quadratic equation from the roots given below. (2) 3 and -10

Answer»

Answer:

3 and 10 are roots

let these TWO roots be

$\alpha \: and \: \beta$

$\alpha = 3 \: and \: \beta = 10$

the structure of quadratic EQUATION is

${x}^{2} - (sum \: of \: roots)x + product \: of \: roots$

${x}^{2} - ( \alpha + \beta )x + \alpha \beta$

$\alpha + \beta = 3 + 10 = 13$

$\alpha \beta = 3 \times 30$

•°• the equation is

${x}^{2} - 13x + 30$

PLEASE MARK MY ANSWER AS BRAINLIEST.

I NEED THIS

Discussion

12.	143,151,158,172,182,?
Answer» Answer: 196.......I THINK....

12.

143,151,158,172,182,?

Answer»

Answer:

196.......I THINK....

Discussion

13.	Plz help me plzzzzz
Answer» OHK WAIT KRO JI bhejte HAI

Discussion

14.	Saul has an account with a department store. His daily balance for the first 11 days of April was $225. His daily balance for the next 6 days was $262.22. For the last 14 days it was $297.33. What was his finance charge if the store used a rate of 2%? will mark u brainliest and will follow u if answer is right pls no spamming thx :)
Answer» Answer: I do not KNOW of any store that computes finance charges on an average daily BALANCE basis. It is usually BASED upon the UNPAID balance at the end of the month. You don't say whether the 2% is a daily or monthly rate. They probably WANT you to take 2% of the average balance for the month. That average balance is (11/30225) + (6/30262.22) + (14/30*297.33) = 272.60 2% of that is $5.45 0 0

14.

Saul has an account with a department store. His daily balance for the first 11 days of April was $225. His daily balance for the next 6 days was $262.22. For the last 14 days it was $297.33. What was his finance charge if the store used a rate of 2%? will mark u brainliest and will follow u if answer is right pls no spamming thx :)

Answer»

Answer:

I do not KNOW of any store that computes finance charges on an average daily BALANCE basis. It is usually BASED upon the UNPAID balance at the end of the month. You don't say whether the 2% is a daily or monthly rate.

They probably WANT you to take 2% of the average balance for the month. That average balance is

(11/30*225) + (6/30*262.22) + (14/30*297.33) = 272.60

2% of that is $5.45

0 0

Discussion

15.	Sam has an account with a department store. His daily balance for the first 12 days of April was $125.47. His daily balance for the next 5 days was $151.25. For the last 13 days it was $177.63. What was his finance charge if the store used a rate of 2%? will mark u brainliest and will follow u if answer is right pls no spamming thx :)
Answer» ANSWER: the answer is $43 DOLLARS of your QUESTION.

15.

Sam has an account with a department store. His daily balance for the first 12 days of April was $125.47. His daily balance for the next 5 days was $151.25. For the last 13 days it was $177.63. What was his finance charge if the store used a rate of 2%? will mark u brainliest and will follow u if answer is right pls no spamming thx :)

Answer»

ANSWER:

the answer is $43 DOLLARS of your QUESTION.

Discussion

16.	Fine the valu polynomial 5x-4x²+3;x=2
Answer» ANSWER: Step-by-step EXPLANATION: when x=2 5(2)-4(2)^2+3 =-3

16.

Fine the valu polynomial 5x-4x²+3;x=2

Answer»

ANSWER:

Step-by-step EXPLANATION:

when x=2

5(2)-4(2)^2+3

=-3

Discussion

17.	Find the value of k for which the quadratic equation (k^2x^2-2(2k-1)x+4=0 has real and equa lroots
Answer» Answer: For real and EQUAL roots, D=0 [2(2k-1)]^2-4.k^2.4 = 0 => 4k^2 - 4k +1 - 4k^2 = 0 => k = 1/4

17.

Find the value of k for which the quadratic equation (k^2x^2-2(2k-1)x+4=0 has real and equa lroots

Answer»

Answer:

For real and EQUAL roots, D=0

[2(2k-1)]^2-4.k^2.4 = 0

=> 4k^2 - 4k +1 - 4k^2 = 0

=> k = 1/4

Discussion

18.	5 computers ribbons and 7 diskettes cost $28 while 6 computer ribbons and 9 dikettes cost$34.50. find the cost of each computer ribbon and each diskettes
Answer» Step-by-step EXPLANATION: HOPE it HELPS I SEND the PICS

18.

5 computers ribbons and 7 diskettes cost $28 while 6 computer ribbons and 9 dikettes cost$34.50. find the cost of each computer ribbon and each diskettes

Answer»

Step-by-step EXPLANATION:

HOPE it HELPS I SEND the PICS

Discussion

19.	If we buy 3 and get one free then find the profit
Answer» ANSWER: the PROFIT should be 25% HOPE it HELPS

19.

If we buy 3 and get one free then find the profit

Answer»

ANSWER:

the PROFIT should be 25%

HOPE it HELPS

Discussion

20.	If a and b are zeros of 7x2+20x-5 then value of 1/a+1/b is
Answer» ANSWER The value of 1/a + 1/b is 4 GIVEN The quadratic polynomial is 7x² + 20X - 5 a and b are the zeroes of the polynomial TO FIND The value 1/a + 1/b CONCEPT TO BE USED In a quadratic polynomial : $\tt \star \: \: <klux>SUM</klux> \: of \: the \: zeroes = - \dfrac{coefficient \: of \: x}{coefficient \: of \: {x}^{2} }$ $\tt \star \: \: <klux>PRODUCT</klux> \: of \: the \: zeroes = \dfrac{constant \: term}{coefficient \: of \: {x}^{2} }$ SOLUTION We are given the polynomial , ➜ 7x² + 20x - 5 Now from the RELATIONSHIPS of the zeroes of the polynomial we have , From sum of the zeroes , $\sf \implies a + b = -\dfrac{20}{7} \longrightarrow (1)$ Again , from product of the zeroes $\sf \implies ab = \dfrac{-5}{7} \longrightarrow(2)$ Dividing (1) by (2) we have, $\sf\implies \dfrac{a + b}{ab} = \dfrac{-\dfrac{20}{7}}{\dfrac{-5}{7}}\\\\ \sf\implies \dfrac{a}{ab}+\dfrac{b}{ab} =\dfrac{20}{7}\times \dfrac{7}{5} \\\\ \sf\implies \dfrac{1}{b}+\dfrac{1}{a}=4 \\\\ \sf \implies \dfrac{1}{a}+\dfrac{1}{b}=4$

20.

If a and b are zeros of 7x2+20x-5 then value of 1/a+1/b is

Answer»

ANSWER

The value of 1/a + 1/b is 4

GIVEN

The quadratic polynomial is

7x² + 20X - 5
a and b are the zeroes of the polynomial

TO FIND

The value 1/a + 1/b

CONCEPT TO BE USED

In a quadratic polynomial :

$\tt \star \: \: <klux>SUM</klux> \: of \: the \: zeroes = - \dfrac{coefficient \: of \: x}{coefficient \: of \: {x}^{2} }$

$\tt \star \: \: <klux>PRODUCT</klux> \: of \: the \: zeroes = \dfrac{constant \: term}{coefficient \: of \: {x}^{2} }$

SOLUTION

We are given the polynomial ,

➜ 7x² + 20x - 5

Now from the RELATIONSHIPS of the zeroes of the polynomial we have ,

From sum of the zeroes ,

$\sf \implies a + b = -\dfrac{20}{7} \longrightarrow (1)$

Again , from product of the zeroes

$\sf \implies ab = \dfrac{-5}{7} \longrightarrow(2)$

Dividing (1) by (2) we have,

$\sf\implies \dfrac{a + b}{ab} = \dfrac{-\dfrac{20}{7}}{\dfrac{-5}{7}}\\\\ \sf\implies \dfrac{a}{ab}+\dfrac{b}{ab} =\dfrac{20}{7}\times \dfrac{7}{5} \\\\ \sf\implies \dfrac{1}{b}+\dfrac{1}{a}=4 \\\\ \sf \implies \dfrac{1}{a}+\dfrac{1}{b}=4$

Discussion

21.	1,1.5,3,7.5,? Find the missing number
Answer» ANSWER: Step-by-step explanation *2 1/2 = 1, 1 * 2/2 = 1, 1 * 3/2 = 1.5, 1.5 * 4/2 = 3, 3 * 5/2 = 7.5, 7.5 * 6/2 = 22.5, SIMILARLY, 22.5 * 7/2 = 78.25.**

21.

1,1.5,3,7.5,? Find the missing number

Answer»

ANSWER:

Step-by-step explanation

2 * 1/2 = 1,

1 * 2/2 = 1,

1 * 3/2 = 1.5,

1.5 * 4/2 = 3,

3 * 5/2 = 7.5,

7.5 * 6/2 = 22.5,

SIMILARLY, 22.5 * 7/2 = 78.25.

Discussion

22.	Find the product of (x-y/5-1)(x+y/5+1) by using identity
Answer» Step-by-step EXPLANATION: I'm not SURE about the ANSWER.........

22.

Find the product of (x-y/5-1)(x+y/5+1) by using identity

Answer»

Step-by-step EXPLANATION:

I'm not SURE about the ANSWER.........

Discussion

23.	D^2y/dx^2+25y=0; y=asin5x+bcos5x
Answer» ANSWER: D5y/5 Step-by-step EXPLANATION:* MARK as BRAINLEIST

23.

D^2y/dx^2+25y=0; y=asin5x+bcos5x

Answer»

ANSWER:

D*5y/5

Step-by-step EXPLANATION:

MARK as BRAINLEIST

Discussion

24.	Show that : tan 10° tan 15° tan 75° tan 80° = 1
Answer» tan 10° tan 15° tan 75° tan 80° = 1 We will EXPAND the SAID values - = tan 10° tan 15° tan ( 90° - 15°) tan(90° - 10° ) = tan 10° tan 15° COT 15° cot 10° [ SINCE tan ( 90°-Ф = cot Ф) Thus after SUBSTITUTING the value - = tan 10° × 1 / tan 10° × tan 15° × 1 / tan 15° = 1 × 1 = 1

24.

Show that : tan 10° tan 15° tan 75° tan 80° = 1

Answer»

tan 10° tan 15° tan 75° tan 80° = 1

We will EXPAND the SAID values -

= tan 10° tan 15° tan ( 90° - 15°) tan(90° - 10° )

= tan 10° tan 15° COT 15° cot 10° [ SINCE tan ( 90°-Ф = cot Ф)

Thus after SUBSTITUTING the value -

= tan 10° × 1 / tan 10° × tan 15° × 1 / tan 15°

= 1 × 1

= 1

Discussion

25.	Sum of 4ArimetricMean in b/w 3and23
Answer» *HEY* *FRIEND,, here* is *you* *ANSWER... 18 hope* it *HELPS* *uhh*❤❤❤

25.

Sum of 4ArimetricMean in b/w 3and23

Answer»

HEY FRIEND,, here is you ANSWER...

18

hope it HELPS uhh❤❤❤

Discussion

26.	Find the density of an object of mass 90kg having length 5m breadth 2m hight 3m
Answer» GIVEN: Mass of an object = 90 kg Length = 5 m Breadth = 2 m Height = 3 m TO FIND: What is the density of the object ? SOLUTION: Let the Density of the object be 'D' kg/m³ ✏ Firstly, we have to find the volume of the object We know that the formula for finding the volume of an object is:- $\large{\boxed{\bf{\star \: Volume = L \times B \times H \: \star}}}$ According to question:- On putting the given values in the formula, we GET $\rm{\hookrightarrow Volume = 5 \times 2 \times 3 }$ $\bf{\checkmark Volume = 30 \: m^3 }$ Now, We have to find the Density of an object We know that the formula for finding the Density of an object is:- $\large{\boxed{\bf{\star \: Density = \dfrac{Mass}{Volume} \: \star}}}$ According to question:- On putting the given values in the formula, we get $\rm{\hookrightarrow D = \cancel\dfrac{90}{30} }$ $\bf{\checkmark D = 3 \: kg/m^3 }$ Density = D = 3 kg/m³ ❝ Hence, the Density of an object is 3 kg/m³ ❞ ______________________

26.

Find the density of an object of mass 90kg having length 5m breadth 2m hight 3m

Answer»

GIVEN:

Mass of an object = 90 kg
Length = 5 m
Breadth = 2 m
Height = 3 m

TO FIND:

What is the density of the object ?

SOLUTION:

Let the Density of the object be 'D' kg/m³

✏ Firstly, we have to find the volume of the object

We know that the formula for finding the volume of an object is:-

$\large{\boxed{\bf{\star \: Volume = L \times B \times H \: \star}}}$

According to question:-

On putting the given values in the formula, we GET

$\rm{\hookrightarrow Volume = 5 \times 2 \times 3 }$

$\bf{\checkmark Volume = 30 \: m^3 }$

Now,

We have to find the Density of an object

We know that the formula for finding the Density of an object is:-

$\large{\boxed{\bf{\star \: Density = \dfrac{Mass}{Volume} \: \star}}}$

According to question:-

On putting the given values in the formula, we get

$\rm{\hookrightarrow D = \cancel\dfrac{90}{30} }$

$\bf{\checkmark D = 3 \: kg/m^3 }$

Density = D = 3 kg/m³

❝ Hence, the Density of an object is 3 kg/m³ ❞

______________________

Discussion

27.	Form the quadratic equation from the roots given below.(1) 0 and 4 (2) 3 and -10 (3) 12 , -12 (4) 2 5 − , 2 5
Answer» Step-by-step explanation: Quadratic EQUATIONS can be FORMED as... x↑2-(SUM of roots)x+(product of roots) for (1):- sum of roots = 0+4 = 4 product of roots = 0×4 =0 therefore, Quadratic equation = x↑2-4x+0=0 for (2) :- sum of roots = 3+(-10)= -7 product of roots = 3× (-10)= -30 Quadratic equation = x↑2+7x-30=0 Now, TRY the next one...

27.

Form the quadratic equation from the roots given below.(1) 0 and 4 (2) 3 and -10 (3) 12 , -12 (4) 2 5 − , 2 5

Answer»

Step-by-step explanation:

Quadratic EQUATIONS can be FORMED as...

x↑2-(SUM of roots)x+(product of roots)

for (1):- sum of roots = 0+4 = 4

product of roots = 0×4 =0

therefore, Quadratic equation = x↑2-4x+0=0

for (2) :- sum of roots = 3+(-10)= -7

product of roots = 3× (-10)= -30

Quadratic equation = x↑2+7x-30=0

Now, TRY the next one...

Discussion

28.	Chppetersocial studies
Answer» ANSWER: ohkk.......what WANT to do

28.

Chppetersocial studies

Answer»

ANSWER:

ohkk.......what WANT to do

Discussion

29.	What is adjoing figure
Answer» ANSWER: Adjoining, adjacent, bordering all mean near or CLOSE to something. Adjoining IMPLIES touching, having a COMMON point or line: an adjoining yard. Adjacent implies being NEARBY or next to something else: all the adjacent houses; adjacent angles. PLEASE MARK THIS ANSWER AS THE BRAINLIEST PLEASE KEEP ROCKING

29.

What is adjoing figure

Answer»

ANSWER:

Adjoining, adjacent, bordering all mean near or CLOSE to something. Adjoining IMPLIES touching, having a COMMON point or line: an adjoining yard. Adjacent implies being NEARBY or next to something else: all the adjacent houses; adjacent angles.

PLEASE MARK THIS ANSWER AS THE BRAINLIEST PLEASE

KEEP ROCKING

Discussion

30.	A,B,C,D,E sits on a park bench. B sits 2nd to the right of C ,and A sits 2nd to the left of C. If D sits between B and C,who sits to the left of E?
Answer» ANSWER: it is C the order is ABDCE so I THINK it's C

30.

A,B,C,D,E sits on a park bench. B sits 2nd to the right of C ,and A sits 2nd to the left of C. If D sits between B and C,who sits to the left of E?

Answer»

ANSWER:

it is C

the order is ABDCE so

I THINK it's C

Discussion

31.	Each of the equal sides of an isosceles triangle is 25 m and base 30m, so find the area.
Answer» ANSWER: The FORMULA for the area of a triangle is A=12⋅b⋅h When the height of an isosceles triangle is drawn to the base it bisects the base. Therefore x=y=15 . Since we have two SIDES of a right triangle we can use the Pythagorean Theorem to find the height. 25² = h² + 15² h² = 625 − 225 = 400 h = 20m A=1/2×30×20 = 300m² Hope it helps! Plz. MARK it as the brainiest.

31.

Each of the equal sides of an isosceles triangle is 25 m and base 30m, so find the area.

Answer»

ANSWER: The FORMULA for the area of a triangle is A=12⋅b⋅h

When the height of an isosceles triangle is drawn to the base it bisects the base. Therefore x=y=15 . Since we have two SIDES of a right triangle we can use the Pythagorean Theorem to find the height.

25² = h² + 15²

h² = 625 − 225 = 400

h = 20m

A=1/2×30×20 = 300m²

Hope it helps!

Plz. MARK it as the brainiest.

Discussion

32.	A^2 minus 3a plus 1 = 0find the value of a^4 plus 1 upon a^4
Answer» Answer: 2a+1/2a Step-by-step explanation: a^2-3a+=0 a^2-a=0/3 a^2=0+a a^2=a a^4+1/a^4=? a^4 can be WRITTEN as( a^2)(a^2)+1/(a^2)(a^2) substituting the VALUE of a^2 from the equation 1 2a+1/2a hope this HELPS you and others so please mark as brainliest

32.

A^2 minus 3a plus 1 = 0find the value of a^4 plus 1 upon a^4

Answer»

Answer:

2a+1/2a

Step-by-step explanation:

a^2-3a+=0

a^2-a=0/3

a^2=0+a

a^2=a

a^4+1/a^4=?

a^4 can be WRITTEN as( a^2)(a^2)+1/(a^2)(a^2)

substituting the VALUE of a^2 from the equation 1

2a+1/2a

hope this HELPS you and others

so please mark as brainliest

Discussion

33.	Saul has an account with a department store. His daily balance for the first 11 days of April was $225. His daily balance for the next 6 days was $262.22. For the last 14 days it was $297.33. What was his finance charge if the store used a rate of 2%? i will follow u if u get the answer right and mark u brainliest
Answer» Calculate the monthly FINANCE charge for the following credit card transaction. Assume that it takes 10 days for a PAYMENT to be received and recorded and that the MONTH is 30 days long. (ROUND your answer to the nearest cent.) $3,000 balance, 21% rate, $150 payment . Average daily balance method

33.

Saul has an account with a department store. His daily balance for the first 11 days of April was $225. His daily balance for the next 6 days was $262.22. For the last 14 days it was $297.33. What was his finance charge if the store used a rate of 2%? i will follow u if u get the answer right and mark u brainliest

Answer»

Calculate the monthly FINANCE charge for the following credit card transaction.

Assume that it takes 10 days for a PAYMENT to be received and recorded and that the MONTH is 30 days long.

(ROUND your answer to the nearest cent.)

$3,000 balance, 21% rate, $150 payment .

Average daily balance method

Discussion

34.	Find x if 9*3 to the power x = (27) to the power 2x-3
Answer» Answer: Step-by-step explanation: 9 × 3x = (27)2x – 3 32 × 3x = (3 × 3 × 3)2x -3 ⇒ 3x + 2 = (3)3(2x -3) ⇒ 3x+2 = (3)6x -9 Since, base are same, COMPARE them, X + 2 = 6x – 9 6x – x = 9 + 2 ⇒ 5X =11 ⇒ x = 11/2 ⇒ x = 2. 1/5

34.

Find x if 9*3 to the power x = (27) to the power 2x-3

Answer»

Answer:

Step-by-step explanation:

9 × 3x = (27)2x – 3

32 × 3x = (3 × 3 × 3)2x -3

⇒ 3x + 2 = (3)3(2x -3)

⇒ 3x+2 = (3)6x -9

Since, base are same, COMPARE them,

X + 2 = 6x – 9

6x – x = 9 + 2

⇒ 5X =11

⇒ x = 11/2

⇒ x = 2. 1/5

Discussion

35.	what sum will amount to rupees 6,593.40 in 2years at compound interest if the rates are 10percent and 11percent for the two successive years?
Answer» Answer: Step-by-step EXPLANATION: ANSWER ⇒ Let RATE of interest for 2 years will be R 1 =10% and R 2 =11%. ⇒ A=P×(1+ 100 R 1 )(1+ 100 R 2 ) ⇒ 6593.40=P×(1+ 100 10 )(1+ 100 11 ) ⇒ 6593.40=P× 10 11 × 100 111 ⇒ 6593.40=P× 1000 1221 ⇒ P= 1221 6593.40×1000 =Rs.5400

35.

what sum will amount to rupees 6,593.40 in 2years at compound interest if the rates are 10percent and 11percent for the two successive years?

Answer»

Answer:

Step-by-step EXPLANATION:

ANSWER

⇒ Let RATE of interest for 2 years will be R

1

=10% and R

2

=11%.

⇒ A=P×(1+

100

R

1

)(1+

100

R

2

)

⇒ 6593.40=P×(1+

100

10

)(1+

100

11

)

⇒ 6593.40=P×

10

11

×

100

111

⇒ 6593.40=P×

1000

1221

⇒ P=

1221

6593.40×1000

=Rs.5400

Discussion

36.	Find the hcf of the following groups of number using the common division method a 18,36,27 b 128 ,84 ,154 c 320,420,180
Answer» ANSWER: B, 128,84,154 it is RIGHT answer

36.

Find the hcf of the following groups of number using the common division method a 18,36,27 b 128 ,84 ,154 c 320,420,180

Answer»

ANSWER:

B, 128,84,154

it is RIGHT answer

Discussion

37.	Two taps running together can fill a cistern in 40/13 minutes. If one of the taps takes 6minutes more than the other to fill it, find the time in which each pipe would fill the cistern.
Answer» Answer: 25 mins Step-by-step EXPLANATION:

37.

Two taps running together can fill a cistern in 40/13 minutes. If one of the taps takes 6minutes more than the other to fill it, find the time in which each pipe would fill the cistern.

Answer»

Answer:

25 mins

Step-by-step EXPLANATION:

Discussion

38.	Find the HCF AND LCM by prime factor method of 9367 and 3451
Answer» ANSWER: HCF and LCM Step-by-step EXPLANATION: HCF for 9367 is 493 LCM for 3451 is 243

38.

Find the HCF AND LCM by prime factor method of 9367 and 3451

Answer»

ANSWER:

HCF and LCM

Step-by-step EXPLANATION:

HCF for 9367 is 493

LCM for 3451 is 243

Discussion

39.	_(3/11×_5/6)_(9/12÷3/4)_(5/13×_6/15)
Answer» ANSWER: (3/11×5/6) (9/12÷3/4) (5/13×6/15) (5/23) (9/12×4/3) (6/39) 5/22×2/3×6/39 10/429

39.

_(3/11×_5/6)_(9/12÷3/4)_(5/13×_6/15)

Answer»

ANSWER:

(3/11×5/6) (9/12÷3/4) (5/13×6/15)

(5/23) (9/12×4/3) (6/39)

5/22×2/3×6/39

10/429

Discussion

40.	Check whether the value given in the solution of the given equation or not 12a+6 = 30 (a=30)
Answer» Answer: 12a+6=30 (a=30) 12(30)+6=30 360+6=30 366 is not EQUAL to 30 hence, the SOLUTION is not CORRECT

40.

Check whether the value given in the solution of the given equation or not 12a+6 = 30 (a=30)

Answer»

Answer:

12a+6=30 (a=30)

12(30)+6=30

360+6=30

366 is not EQUAL to 30

hence, the SOLUTION is not CORRECT

Discussion

41.	Find the inverse of the matrix
Answer» ANSWER: SORRY IDID not EXPLAIN your QUESTIONS

41.

Find the inverse of the matrix

Answer»

ANSWER:

SORRY IDID not EXPLAIN your QUESTIONS

Discussion

42.	Visualise 9.37bar on the number line up to 4 decimal places
Answer» Answer: This number lies between 4 and 5 the DISTANCE between 4 and 5 is DIVIDED into 10 EQUAL parts. Then the first mark to the right of 4 will represent 4.1 & second 4.2 and so on. Now 4.2626 lies between 4.2 & 4.3.

42.

Visualise 9.37bar on the number line up to 4 decimal places

Answer»

Answer:

This number lies between 4 and 5 the DISTANCE between 4 and 5 is DIVIDED into 10 EQUAL parts. Then the first mark to the right of 4 will represent 4.1 & second 4.2 and so on. Now 4.2626 lies between 4.2 & 4.3.

Discussion

43.	Maths. Write the integers between the pairs of integers give below also choose the biggest and smallest integers from them?(1) -5,-10
Answer» Answer: INTEGERS between -5 and -10= -6,-7,-8-9 smallest integer = -10 Step-by-step explanation: i hope this will HELP you. pleasemark it as brainliest.

43.

Maths. Write the integers between the pairs of integers give below also choose the biggest and smallest integers from them?(1) -5,-10

Answer»

Answer:

INTEGERS between -5 and -10= -6,-7,-8-9

smallest integer = -10

Step-by-step explanation:

i hope this will HELP you.

pleasemark it as brainliest.

Discussion

44.	Find the least no which when divided by 18,24,36 leaves the remainder 3 in each case
Answer» LCM of 18,24,36 is 72 So REQUIRED no is 72+3=75

Discussion

45.	A group of student arranged a picnic each student contributed rupees 26 whole 1 upon 2 the total contribution was rupees 2876 whole 1 upon 2 how many student are there in group
Answer» Answer: Step-by-step EXPLANATION: Amount contributed by each student = ₹26 1/2 = ₹53/2 Total contribution = ₹2876 1/2 = 5753/2 Total no. of students in the GROUP = Total contribution ÷ Contribution of each student = 5753/2 ÷ 53/2 = 5753/2 × 2/53 = 5753/53 = 108 students Answer-) HENCE, 108 students are there in the group.

45.

A group of student arranged a picnic each student contributed rupees 26 whole 1 upon 2 the total contribution was rupees 2876 whole 1 upon 2 how many student are there in group

Answer»

Answer:

Step-by-step EXPLANATION:

Amount contributed by each student = ₹26 1/2 = ₹53/2

Total contribution = ₹2876 1/2 = 5753/2

Total no. of students in the GROUP = Total contribution ÷ Contribution of each student

= 5753/2 ÷ 53/2

= 5753/2 × 2/53

= 5753/53

= 108 students

Answer-) HENCE, 108 students are there in the group.

Discussion

46.	Differentiate tan`(x sinalpha/1-x cosalpha)
Answer» Step-by-step EXPLANATION: REFER to the attachment Hope it HELPS! (PLS mark it the brainliest^^)

46.

Differentiate tan`(x sinalpha/1-x cosalpha)

Answer»

Step-by-step EXPLANATION:

REFER to the attachment

Hope it HELPS!

(PLS mark it the brainliest^^)

Discussion

47.	Find the sum of first 17terms of an AP whose 4th and 9th term are - 15and -30 respectively
Answer» Answer: -510 Step-by-step explanation: Let a & d be the FIRST term and COMMON DIFFERENCE of the A.P. 4th term = a + 3D = -15 9th term = a + 8d = -30 Solving above two EQUATIONS we have a = -6, d = -3 Than the sum of first 17 terms is given by, S = n/2 { 2a + (n -1)d} = 17/2 { 2 * (-6) + (17-1)(-3) } S = -510

47.

Find the sum of first 17terms of an AP whose 4th and 9th term are - 15and -30 respectively

Answer»

Answer:

-510

Step-by-step explanation:

Let a & d be the FIRST term and COMMON DIFFERENCE of the A.P.

4th term = a + 3D = -15

9th term = a + 8d = -30

Solving above two EQUATIONS we have

a = -6, d = -3

Than the sum of first 17 terms is given by,

S = n/2 { 2a + (n -1)d} = 17/2 { 2 * (-6) + (17-1)(-3) }

S = -510

Discussion

48.	Explain with an example how irrational numbersdifferfrom rational numbers
Answer» RATIONAL Number is defined as the number which can be WRITTEN in a ratio of two integers. An irrational number is a number which cannot be expressed in a ratio of two integers. In rational numbers, both numerator and DENOMINATOR are whole numbers, where the denominator is not equal to zero

48.

Explain with an example how irrational numbersdifferfrom rational numbers

Answer»

RATIONAL Number is defined as the number which can be WRITTEN in a ratio of two integers. An irrational number is a number which cannot be expressed in a ratio of two integers. In rational numbers, both numerator and DENOMINATOR are whole numbers, where the denominator is not equal to zero

Discussion

49.	How much oxygen will be added with 12g of carbon to give 44g carbon dioxide assuming complete combustion reaction
Answer» 32 G GiVen:- Mass of carbon = 12 g Mass of carbon DIOXIDE = 44 g AnSwer:- Now, According to LAW of CONSERVATION of mass, $\sf \: Mass\: of \:carbon + mass\: of\: oxygen = Mass\: of\: carbon\: dioxide \\ \\ \implies \sf \: 12 g+x=44 g \\ \\ \implies \sf \:x = 44 - 12 \\ \\ \implies \sf \: x = 32g\\\\ \sf \therefore \: So \: mass \: of \: oxygen =32 g$

49.

How much oxygen will be added with 12g of carbon to give 44g carbon dioxide assuming complete combustion reaction

Answer»

32 G

GiVen:-

Mass of carbon = 12 g
Mass of carbon DIOXIDE = 44 g

AnSwer:-

Now,

According to LAW of CONSERVATION of mass,

$\sf \: Mass\: of \:carbon + mass\: of\: oxygen = Mass\: of\: carbon\: dioxide \\ \\ \implies \sf \: 12 g+x=44 g \\ \\ \implies \sf \:x = 44 - 12 \\ \\ \implies \sf \: x = 32g\\\\ \sf \therefore \: So \: mass \: of \: oxygen =32 g$

Discussion

50.	FIve times a number ‘r’ increase by 9 becomes 34
Answer» Answer: dude if U R asking for MAKING an equation than this UR answer 5r +9=34 if this is not what u r asking than I'm sry

50.

FIve times a number ‘r’ increase by 9 becomes 34

Answer»

Answer:

dude if U R asking for MAKING an equation than this UR answer

5r +9=34

if this is not what u r asking than I'm sry

Discussion

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