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Find the value of k for which the quadratic equation (k^2x^2-2(2k-1)x+4=0 has real and equa lroots |
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Answer» Answer: For real and EQUAL roots, D=0 [2(2k-1)]^2-4.k^2.4 = 0 => 4k^2 - 4k +1 - 4k^2 = 0 => k = 1/4 |
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