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This is the GRAPH for x-9y=-9

Yes


sine is the RATIO BETWWEN PERPENDICULAR and
HYPOTENUSE

I HOPE U can UNDERSTAND

For QUESTION 5....does it have a diagram so we could visually KNOW what is GOING on?

-36
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X+x+7+x-4=300
3x+3=300
3x=300-3
3x=297
x=297/3
x =99

2.5m LENGTH of CLOTH will be LEFT.......

Ghar se nikhalte hi USKE PASS ek BHI rupeea NI tha..

You can not CHANGE your USERNAME in BRAINLY.

23

The digit after the decimal is 5,so we have to ADD 1 to the digit before it

CIRCLE are- πr^2
Triangle area- (1/2) *B*h

π - pi
r - RADIUS of a circle
b - BASE of a triangle
h - HEIGHT of a triangle

Given,
5m-2/2=-11
((5m×2)-2)/2=-11
10m-2=-11×2
10m-2=-22
10m=-22+2
10m=-20
m=-20/10
m=-2
now from the question,
2m+3=2×(-2)+3
=-4+3
=-1(ANSWER)

Here we GO,



And we are DONE.

I HOPE this will HELP.

Here x will be 1 because 2 POWER 5x-x = 2 power 4.
after equating,4x=4
which shows x=1
pls MARK brainliest

The.......
X=10-7y......(1)
and Y=8/7X......(2)
now, EXPLAIN it by QUADRATIC EQUATION....

I THINK that the ANSWER is IRRATIONAL NUMBER

HOPE these HELPS..........

3.696.............................

this is the SOLUTION

Hii
Here is Your answer
_______________________________________________________

Ist CONSECUTIVE multiple of 7 = x
IInd consecutive multiple of 7 = x + 7
IIIrd consecutive multiple of 7 = x + 14

A.T.Q

=> x + x + 7 + x + 14 = 777
=> 3x + 21 = 777
=> 3x = 777 - 21
=> 3x = 756
=> x = 756/3
=> x = 252

Hence, Ist consecutive multiples of 7 = x
= 252

IInd consecutive multiple of 7 = x + 7
= 252 + 7
= 259

IIIrd consecutive multiple of 7 = x + 14
= 252 + 14
= 266

☆☆HOPE IT HELPS YOU !!✌✌

√{(sec β -1)/(secβ +1)}

= √{(1 - cosβ)/(1+cosβ)} (by dividing every term by secβ

= √{(1-cosβ)²/(1-cos²β)} ( by multiplying numerator & denominator by (1-cosβ)

= √{(1- cosβ)² / sin²β }

= (1-cosβ) / sinβ …………………. (1)

Similarly, √{(secβ +1)/(secβ -1)

= √{(1+cosβ) / (1-cosβ) } ( as done above)

= √{(1+cosβ)² / (1-cos²β) }

= √{(1+cosβ)² / sin² β }

= (1+cosβ ) / sinβ ……………. (2)

By adding (1) & (2)

LHS =

= { 1-cosβ + 1+cosβ } / sinβ

= 2/sinβ

= 2 cosec β

= RHS

[ Hence PROVED]

320° of all FOUR SIDES

The FIRST TERM is 7/3 and 13TH term is 91/3

If a NUMBER 'a' and a number 'b' are DIVISIBLE by a number 'n' then, a+b and a-b is also divisible by n

=> let the number be n which divides 62, 132 and 237 leaving a REMINDER r

=> the REQUIRED number then becomes H.C.F of 62-r, 132-r and 237-r

=> it could also be the H.C.F of 
(132-r)-(62-r) and (237-r)-(132-r)

i.e. 70 and 105

=> H.C.F of 70 and 105 = 35

the required number n is 35.

Total units of work = 7 men * 12 days = 84 units of work

For 5 days, 7 men worked => 7*5 = 35 units of work COMPLETED

Remaining (84 - 35) = 49 units of work need to be completed by (7 - 2) = 5 men

So, No. of days REQUIRED for remaining work to complete = 49/5 = 9 (4/5) days = 9.8 days

Regards,

KKKoppu

Hey friend, HARISH here.

Here is your answer. (Refer to the IMAGE).

SOLVE it we GET k = ± 2

But log of NEGATIVE number is not defined.

So the only correct answer will be be k = 2

__________________________________________

Hope my answer is helpful to you.

The ANSWER to this QUESTION is 3/20

The SUM of numerator and denominator of a fraction is 18 if the denominator is INCREASED by 2 the factor REDUCED to 1 upon 3 find the fraction

9.51971×10^26 is the ANSWER

142 NUMBERS are LESS than which are DIVISIBLE by 7.

Sorryyyyyyyyyyyyyyyyyy

967718790584......................................

HOPE it is CORRECT....

HOPE it helps you . If REQUIRED more DEEP answer u MAY ASK for it.

Aaaah LO YRR..........

2.334 is the ANSWER !!!!!!!

HEYA MATE,

HERE IS UR ANSWER.

THANKS for asking this question.

Quantity of A in the mixture = 60 × 2/3 = 40 liters
Quantity of B in the mixture = 60 × 1/3 = 20 liters
Let the quantity of B ADDED to the mixture be x
40/20 + x = 1/2 or x = 60 liters

I HOPE IT HELPS U.