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The CORRECT ANSWER is 1...
SIN 90°= 1

Here is your ANS....

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This is very DIFFICULT

If it  is: Convert each term of RATIO into PERCENTAGE here is the method:

2/(2+3+5)*100
=2/10*100
=20%

3/(2+5+3)*100
=3/10*100
=30%

5/(2+5+3)*100
=5/10*100
=50%

Answer:

C lies between A and B.

A, B and C are collinear.

Step-by-step explanation:

In the question,

We have been provided that,

Distance between A and B is,

d(A, B) = 16

Distance between C and A is,

d(C, A) = 9

and,

Distance between B and C is,

d(B, C) = 7

So,

We can draw it LIKE, as we can SEE that,

d(B, C) + d(C, A) = 9 + 7 = 16

So,

The common POINT between them is C.

Therefore, we can say that the point lying between A and B is C.

Also,

we can see that from the figure attached below:

C lies between A and B.

and,

Therefore,

A, B and C are collinear.

5,12,13 is the PYTHAGOREAN TRIPLET in which 13 is ONE of it

2hour was TAKEN by 4pipes

0,1/2,1/3,1/4,1/5,1/6,1

You have to solve 15 and 25 by TAKE the LCM of
HOPE THIS ANSWER WILL HELP U BUDDY if it GIVE than u have to bring INFORMATION about some of the

Hey BUDDY here is your ANSWER HOPE you will find it HELPFUL

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60 is the smallest number should be MULTIPLIED with 2560 to GET a perfect cube

Here is Your ANSWER of the question.
2x + 3y=2........(I);
X - y/2 = 1/2.....(II);

Now, Solving equation (II)
x = 1+y/2
2x-y= 1............(II);
————————————————
2x + 3y=2........(I);

-(2x-y= 1)............(II);
_______________________
4y = 1
y= 1/4;

Putting the Value of 'y' in equation (II) we get -

2x - 1/4= 1
x= 5/8;

When vowels are together = 6! = 6 × 5 × 4 × 3 × 2 × 1 = 720 WAYS

When vowels are not together = 40320 ways - 720 ways

When vowels are not together = 39600 ways

6.32455532 ANSWER....

Let US CONSIDER two angles to be A and B
Since angles A and B are complementary
A+B=90 degrees
Let B>A
Since A and B are CONSECUTIVE INTEGERS
B=A+2
so finally A=44 degrees and B=46 degrees

20–√3
Hope it will HELP

There is no ANGLE called bcd CHECK the QSTN and CLARIFY pls

Heya..........!!!

_____________________________

This question can be easily solved by applying the identity :

=> ( X + y + z )² = x² + y² + z² + 2 ( xy + yz + ZX )


Given in the question :

--» x + y + z = 9
--» xy + yz + zx = 26


=> ( 9 )² = x² + y² + z² + 2 ( 26 )

=> 81 = x² + y² + z² + 52

=> x² + y² + z² = 81 - 52



♦ 29. is the required ANSWER .



===================================


HOPE It Helps You ☺

The POLYGON has 12 SIDES

Given,
X/2 + y = 0.8

→(x+2y)/2 = 0.8

→x+2y =1.6

→5(x+2y)= 1.6*5

→5x + 10Y = 8.0.............(i)

And,

→7/(x +y/2) = 10

→14/(2x +y) = 10

→10(2x+y) = 14

→5(2x+y)= 7

→10x +5y =7

→2(10x +5y) =7*2

→20x + 10y = 14......................(ii)
Now,

Substracting equation (i) form (ii)
We get,
15 x = 6

x= 6/15

x= 2/5

PUTTING x= 2/5 in equation (ii)

(2/5)/2 +y= 0.8

y= 3/5
Refer to attachment

A takes 10 days less than time TAKEN by B to finish piece of work so,
A = B - 10.......(1)

let take X as time taken to finish a piece of work by
B = x
then A = x-10

one day work of A,
A= 1/(x-10)
one day work of B,
B = 1/x

A and B work together to finish a job in 12 days so,
A+B = 12

one day work of A and B
A+B = 1/12..........(2)

substitute A and B in (2)
1/(x-10) + 1/x = 1/12
(x+x-10)/(x*(x-10)) = 1/12
(2x - 10)*12 = x²-10x
24x - 120 = x²-10x
x²-10x-24x+120 = 0
x²-34x+120 = 0
x²-4x-30x+120 = 0
x(x-4)-30(x-4) = 0
(x-4)(x-30) = 0
x= 4,30

B finish a job in x= 4 days is not possible because A and B work together for 12 days so B time taken to finish a should be greater than 12

so B finish the job in x=30 days

A finish the same job in x-10 = 30-10 = 20 days

to check WHETHER A=20, B=30

one days work of A and B together,

A+B = 1/20+1/30
A+B = (30+20)/600
A+B = 50/600
A+B = 1/12

time taken to finish whole work of A and B together

A+B = 12

F(X) = 2x^3 - 5x^2 +ax + b

=> f(0) = 0

=> 2(0) - 5(0) +a(0) + b = 0

=> b = 0 ------(1)

Now,

f(2) = 0

=> 2(2)^3 - 5(2)^2 + a(2) + b = 0

=> 16 - 20 + 2a + b = 0

=> 2a + b = 4

=> 2a + 0 = 4 [ using equation 1]

=> 2a = 4

=> a = 2

Hello Sir,
HOPE this HELPS You,



Below example and explanation are taken from here.
5 -2 2 7
1 0 0 3
-3 1 5 0
3 -1 -9 4

For instance, the cofactor of the top left corner '5' is
+ |0 0 3|
...|1 5 0| = 3(1 * -9 - (-1) * 5) = -12.
...|-1 -9 4|
(The minor matrix is formed by deleting the row
and column of the given entry.)

As another sample, the cofactor of the top row corner '-2' is
-|1 0 3|
...|-3 5 0| = - [1 (20 - 0) - 0 + 3 (27 - 15)] = -56.
...|3 -9 4|

Proceeding like this, we OBTAIN the matrix
[-12 -56 4 4]
[76 208 4 4]
[-60 -82 -2 20]
[-36 -58 -10 12]

Finally, to get the adjoint, just take the previous
matrix's transpose:


[-12 76 -60 -36]
[-56 208 -82 -58]
[4 4 -2 -10]
[4 4 20 12]

_________
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It is your ANSWER OK

2X-20=5
2X=20-5
2X=15
X=15/2
X=7.5

(1/x*1/y)/(1/x+1/y)
(1/xy)/(y+x/xy)
1/xy*xy/y+x
1/y+x (ANSWER)
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Answer:

Step-by-step EXPLANATION:

(Monthly income in Rs.)  Frequency  CUMULATIVE Frequency

                                                              More than or

1000-5000                              45          87  

5000-10000                            19          42

10000-15000                           16           23

15000-20000                          02          07

20000-25000                         05          05

(Monthly income in Rs.)  Frequency  Cumulative Frequency Less Than

1000-5000                              45          45  

5000-10000                            19           64

10000-15000                           16           80

15000-20000                          02          82

20000-25000                         05          87

First we will subtract 9 from 2011 and 5 from 2623. then find HCF you will get 154 .

In CLASS 8TH there is no TRIGONOMETRY

It is COMPOSITE NUMBER

so this number have more than 2FACTORS(1,13,78)

Your ANSWER is =5 !!

Hey buddy..

here is the ANSWER for your question

hope this helps....

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549000 TOYS..............

Let O = (a, B) is the centre of circumcircle .
then, AO = BO = CO = RADIUS of circumcircle
AO = BO = CO
AO² = BO² = CO²

use distance formula,
so, (a - 7)² + (b - 1)² = (a - 3)² + (b - 5)² = (a + 2)² + b²

now, (a - 7)² + (b - 1)² = (a - 3)² + (b - 5)²
a² - 14a + 49 + b² - 2b + 1 = a² - 6a + 9 + b² - 10b + 25
-14a + 6a - 2b + 10b + 50 - 34 = 0
-8a + 8b + 16 = 0
a - b - 2 = 0
a = b + 2 -------(1)

Similarly, (a - 3)² + (b - 5)² = (a - 2)² + b²
a² - 6a + 9 + b² - 10b + 25 = a² - 4a + 4 + b²
-6a + 4a - 10b + 34 - 4 = 0
-2a - 10b + 30 = 0
a + 5b = 15 ------(2)

from EQUATIONS (1) and (2),
b + 2 + 5b = 15
6b = 13 , b = 13/6
and a = 19/6

HENCE, centre of circumcircle = (19/6,13/6)
now, radius of circumcircle =
=

Here the LCM of deno. 2 & 5 is 10

= 1/2*5/5 & 1/5*2/2
= 5/10 & 4/ 10
= 5/10 × 10/10 & 4/10 × 10/10
= 50/100 & 40/100
HENCE 6 rational no. between them are 49/100 , 48/100, 47/100, 46/100, 45/100, 44/100 .......