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1/3+1/2
2+3/6
5/6 HOURS

Roots are
{ 7 + √(49 - 24)}/4 and { 7 -√(49 - 24)}/4
(7 + 5)/4 and (7 - 5)/4
3 and 1/2

Answer:

ED = LM  , DF = MN  , FE = NL

∠E = ∠L ,  ∠D = ∠M  . ∠F = ∠N

Step-by-step EXPLANATION:

Δ DEF and Δ LMN are congruent in the correspondence EDF ↔ LMN. Write the PAIRS of congruent SIDES and congruent angles in the correspondence.

Δ EDF ≅ Δ LMN (congruent Triangles)

CORRESPONDING sides are equal

ED = LM

DF = MN

FE = NL

Corresponding Angles are equal

∠E = ∠L

∠D = ∠M

∠F = ∠N

Answer:

the mean of the TIMES TAKEN for RUNNING. = 15.7 sec

Step-by-step explanation:

Pranalee was practising for a 100 m running race. She ran 100 m distance 20 times. The time required, in seconds, for each attempt was as follows.18 , 17 , 17 , 16 , 15 , 16 , 15 , 14 , 16 , 15 , 15 , 17 , 15 , 16 , 15 , 17 , 16 , 15 , 14 , 15  

Find the mean of the times taken for running.

Total NUMBER of Data = 20

Sum of times =  18 + 17 + 17 + 16 + 15 + 16 + 15 + 14 + 16 + 15 + 15 + 17 + 15 + 16 + 15 + 17 + 16 + 15 + 14 + 15

Sum = 314

Mean = Sum of all data / numbers of dat

=> Mean = 314/20 =  15.7

the mean of the times taken for running. = 15.7 sec

Yo MATE !!!

It's a polynomial !

Let's solve it YAY !

= p (0) = 0² - 0 + 1

= p (0) = 0 - 0 + 1

= p (0) = 1 - 0

= p (0) = 1

Mark as BRAINLIEST

CLICK on thanks !

50×2=100 now 100 ×17 =1700

According to QUADRATIC equation it is ALWAYS said that the base of 0 is always 1

The difference between axioms and POSTULATES are :
Axioms are UNIVERSAL truths which is applicable everywhere
WHEREAS
Postulates are those which are not to be proved but are SPECIFIC to GEOMETRY.
I hope this helps you

N if this helped you then mark this answer as brainliest.

(I). 72°
(II). 72°
(III). 27°
(IV). 32°

Step-by-step explanation:

1/2=0.5

5/6=0.834

2/3=0.66

BALAKRISHNAN READ 1/2 of the BOOK

Angela read 5/6 of the book and

subhalakshmu read 2/3 of the book

5.6 % GAIN , will be the ANSWER

TOTAL  OUTCOMES= 4
FAVOURABLE  OUTCOMES=1

P(GETTING 1 HEAD)=FAVOURABLE OUTCOMES/TOTAL OUTCOMES
                                  = 1/4

Hey mate! your answer is -24!
let wheels be 'x' .
so, x+x+x= 18
=> 3x = 18
=> x = 18/3
=> x= 6
then, value of wheel = 6
let tree be 'y'.
now, 6+ y+y = 26
=> 6+2y. = 26
=> 2y = 26-6
=> y = 20/2
=> y = 10
then, value of tree is 10.
let the value of leaf be 'z'.
so, Z+ 6+10=20
=> Z+ 16 = 20
=> Z. = 20-16
=>. Z = 4
then, value of leaf is 4.
lastly, 6 -4*10+10
= 6-40+10. (using DMAS)
= 6- 30
= -24
hope it was helpful and right!✌️

The ANSWER is 316 .
HOPE this HELPS you
THANKS

I HOPE it will HELP you

Hello !!




6X + 2Y = 3



6X + 2Y - 3 = 0 ------------(1)



And,



KX + Y = 2



KX + Y - 2 = 0---------(1)



These equations are of the form A1X + B1Y + C1 = 0 and A2X + B2Y + C2 = 0.


Where,


A1 = 6 , B1 = 2 and C1 = -3



A2 = K , B2 = 1 and C2 = -2




Therefore,



A1/A2 = 6/K , B1/B2 = 2/1 and C1/C2 = 3/2




For unique solution, we MUST have



A1/A2 # B1/B2 [ Where # STANDS for not equal]




6/K # 2






2k # 6



k # 6/2


K # 3




Therefore,



K has all real values , other than 3.

To cross Jake the train took 15 sec.
Speed of train in m/sec = 90 × 5/18 = 25 m/sec.
Length of train = 25 × 15 = 375 m.
Time taken to cross platform is 40 sec.
Distance travelled by train in 40 sec = 40 × 25 = 1000 m.
Length of platform = distance travelled - length of train.
= 1000 - 375 = 625 m .
Hope you understood my answer. If YES then plz mark me as the brainliest.

Principal + interest for 2 YEARS = 2240 ---------1

Principal + interest for 5 years = 2600 --------2

Subtracting 1 from 2 = 2600 - 2240 = 360

interest for three years = 360

so interest for 1 year = 360/3 = 120

interest for 2 years = 2 x 120 = 240

Principal for 2 years = 2240

Interest for 2 years = 240

Principal = 2240 - 240 = 2000

Using Euclid's DIVISION LEMMA :

117 = 65 * 1 + 52 => ( Equation 1 )

65 = 52 * 1 + 13 => ( Equation 2 )

52 = 13 * 4 + 0

Hence 13 is the HCF of 65 and 117.

13 = 65 m + 117 n

From Equation 2 we can say that,

13 = 65 - 52 * 1 => ( Equation 3 )

From Equation 1 we can say that,

52 = 117 - 65 * 1 => Equation 4

Substituting the value of 52 as in Equation 3 in Equation 4. We get,

13 = 65 - ( 117 - 65 * 1 )

13 = 65 + 65 - 117

13 = 65 * 2 + 117 * ( - 1 )

13 = 65 m + 117 n

=> m = 2 ; n = ( - 1 )

AREA of CIRCLE = pie * r * r

Area GIVE 3850 sq m

So 22/7 * r * r = 3850

r * r = (3850 * 7) / 22

r * r = 1225

r = 35 m

Hi ,

Dimensions of the Cuboidal WAREHOUSE :

length ( L ) = 6m

breadth ( B ) = 4m

height ( H ) = 4m

Volume of the Cubiod = V

Dimensions of the cube shaped BOX :

side = a = 40cm = 0.4 m

volume of the each cube = v

Let the number of cubes required = n

n = V/v

n = ( LBH )/ a³

n = ( 6 × 4 × 4 )/( 0.4 × 0.4 × 0.4 )

after SIMPLIFICATION , we get

n = 1500

Therefore ,

number of cube shaped boxes required

to fill the warehouse completely = n = 1500

I hope this helps you.

: )

Hi ,

Dimensions of the TRAY :

let Length = l cm

breadth ( B ) = 40 cm

height ( h ) = 2.5 cm

Capacity of the tray = volume of the molten

mixture poured in the tray

l × b × h = 5 litre

l × 40 × 2.5 = 5 × 1000 cm³

[ Since 1 litre = 1000 cm³ ]

l = ( 5 × 1000 )/( 40 × 2.5 )

l = 50 cm

Therefore ,

Length of the tray = l = 50 cm

I hope this helps you.

: )

ORNAMENT = 12.5 g

GOLD = 2.5 g

ALLOY = 10 g

Ratio of gold to alloy = 2.5/10 = 1:4

Some part of the QUESTION is missing. The triangle given is a right ANGLED triangle. Having this as base we can solve it by the following :

Let the side PQ = x

OQ : x = 3 : 4

=> OQ = 3x / 4

We know that,

OQ² + PQ² = OP²

X² + ( 3 X / 4 )² = OP²

x² + 9x² / 16 = OP²

Taking LCM we get,

16 x² + 9 x² / 16 = OP²

25x² / 16 = OP²

=> OP = √ ( 25x² / 16 ) = 5x / 4

=> Perimeter = x + 3x / 4 + 5x / 4 = 60 cm

Taking LCM we get,

4x + 3x + 5x / 4 = 60

=> 12 x = 60 *4

=> 12 x = 240

=> x = 240 / 12 = 20

PQ = 20 UNITS

OQ = 3X / 4 = 3 * 20 / 4 = 60 / 4 = 15 units

OP = 5X / 4 = 5 * 20 / 4 = 100 / 4 = 25 units.

Hence measures are :

PQ = 20 ; OQ = 15 ; OP = 25 units.

Ans is 25 MASON that can BUILD the wall in 12days

Your ANSWER ↓↓↓↓↓.

12 Bags = 96 kg.

20 Bags = ? kg.

then ,

According to RATIO and Proportion ,

12: 96 :: 20 : x

=

x =

x = 160 kg .

Hence , 20 Bags weighs 160 kg .

^_^ ^_^

# Be BRAINLY

5 SIDES of trigonal=15cm

then 15/5=3cm

then ONE side will B 3cm

( X - a) (x - b) = x^2 - (a +b)x + ab

For example :-

( 5 - 2)( 5 - 3) = (5)^2 - (2 + 3)(5) + (2)(3)

= 25 - (5)(5) + 6

= 25 - 25 + 6

= 6

Put x=2,

Then,
2^3- 2×2^2 + k×2 + 5= 11
8- 8+ 2k+5= 11
2k= 11-5
2k= 6
K= 3

It is the ANSWER of your QUESTION...
HOPE UNDERSTAND..

0.36= 36/100
Simplest form=9/25

The SUM of DENOMINATOR and NUMERATOR is 9+25=34

HI! This is Aditya here n m going to answer your question.

First step you need to find LCM of the denominators n CONVERT them into like fractions. Then see if 10 numbers are there in between, if not, then multiply both the numbers NUMERATOR and denominator and left and right numbers with some same number. See again if you get them.

Answer :

Given : 3/5 and 3/4

LCM of 4 & 5 = 20

3/5 x 4/4 = 12/20
3/4 x 5/5 = 15/20

12/20 x 4/4 = 48/80 (Multiplying some number to get a larger numerator)
15/20 x 4/4 = 60/80

Numbers :- (You can write any 10 numbers between these TWO numbers)

Answer:

Step-by-step EXPLANATION:

A zero matrix which CONTAINS only 0 as it's ELEMENTS is both symmetric and SKEW symmetric.

Answer:

see explanation

Explanation:


See Fig 1, Let D be the midpoint of BC,
⇒AD is a median of ΔABC
Now we need to prove AB+AC>2AD


See Fig2, extend AD to E such that AD=DE
⇒AE=2AD,
Draw lines BEandEC, as shown in the figure.
⇒ABEC is a parallelogram.
⇒BE=AC.
Consider ΔABE
Recall that the sum of any two sides of a triangle is greater than the LENGTH of the third side,
⇒AB+BE>AE
⇒AB+AC>2AD ....... (proved)

MAKE the BRAINLIEST answer

Here is your ANSWER CONSIDER it as BRAINLIEST

This is true answer. Hope it MAY HELP. THANKYOU

<P>LET the polynomial p(X)
Given zeroes of p(x) are -2,-1
So (x+2)(x+1) is factor of p(x)
So x2+3x-2 is factor of p(x)
Now divide x2+3x-2 with p(x)=2x4+x3-14x2-19x-6
We get Q(x)=2x2-5x-3
It is a QUADRATIC equation so by splitting the midle term we get (2x+3)(x-1)=0
Now either 2x+3 =0 or x-1=0
X=-3/2 or x=1
So zeroes are -1,-2,-3/2,1

This is the SUM of it the LESSON is HERONS FORMULA