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OQ:PQ=3:4and perimeterof tiangle POQ=60cm. Find PQ QR AND OP |
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Answer» Some part of the QUESTION is missing. The triangle given is a right ANGLED triangle. Having this as base we can solve it by the following : Let the side PQ = x OQ : x = 3 : 4 => OQ = 3x / 4 We know that, OQ² + PQ² = OP² X² + ( 3 X / 4 )² = OP² x² + 9x² / 16 = OP² Taking LCM we get, 16 x² + 9 x² / 16 = OP² 25x² / 16 = OP² => OP = √ ( 25x² / 16 ) = 5x / 4 => Perimeter = x + 3x / 4 + 5x / 4 = 60 cm Taking LCM we get, 4x + 3x + 5x / 4 = 60 => 12 x = 60 *4 => 12 x = 240 => x = 240 / 12 = 20 PQ = 20 UNITS OQ = 3X / 4 = 3 * 20 / 4 = 60 / 4 = 15 units OP = 5X / 4 = 5 * 20 / 4 = 100 / 4 = 25 units. Hence measures are : PQ = 20 ; OQ = 15 ; OP = 25 units. |
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