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Solution is in the given attachment.

Regrets for handwriting _/\_

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LET's see some related terms ;

FACTORISATION : It is the term that means to differ the FACTORS of a given expression.

Linear equations in two variables :

▪️A linear equation in two variables has infinitely many solutions.

▪️Standard form of a linear equation in two variables is « ax + by + C = 0 », where a and b are coefficients of x and y respectively and she is a constant.

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Thanks for the QUESTION!

Hi,

let Force APPLIED on the body is F Newton.
and acceleration produced by the body is a .

➡️F is directly PROPORTIONAL to a

F = ma
➖➖➖
m = 6Kg

F= 6a Newton

To draw graph
➖➖➖➖➖
take different values of a,and note down the values of F
1) a = 0

F = 0

2) a= 1

F= 6

3) a = 2

F= 12
and so on...

hope it HELPS you

Compact DISK is in the shape of a circle. Hence the circumference of a compact disk can be equated to that of a circle.

=> Circumference of Circle = 28.26 CM

We KNOW that Circumference of a circle is 2πr, where R is the radius of the circle.

Hence substituting them in the formula we get,

2πr = 28.26

2 * 3.14 * r = 28.26

6.28 * r = 28.26

=> r = 28.26 / 6.28

=> r = 4.5 cm

Hence the radius of the compact disk ( CD ) is 4.5 cm.

Area of a PARALLELOGRAM FORMULA: b*h=A

Plug in the values that you know.

b*6.4=83.2

Divide both sides by 6.4

b=13

So your answer WOULD be b=13 SQ cm.

Hope this HELPS ;)

If X = -1/3
P(X)=27X^3 - aX^2 -X+3 = 0
P(1/3)=27(-1/3)^3 -a(-1/3)^2 -(-1/3) +3 =0
=>27(-1/27) -a(-1/9) +1/3 +3 = 0
=>-1+(a/9) +1/3 +3 =0
=>(-9+a+3+27)/9 =0
=>(-9+a+3+27)= 0
=> a+21 =0
=>a =(-21)

Here is QUE's ANSWER DEAR.

1/28=x and y=1/36 and HENCE this is the ANSWER

Given : Letter of Word SUNDAY

To find :  The NUMBER of permutations that can be MADE from the letters of the word SUNDAY that neither begin with S nor end with Y

Solution:

SUNDAY

total Letters = 6

total possible Combination = 6 !   = 720

if begin with S  then possible combination = 5!   = 120

if end with  Y  then possible Combination = 5!  = 120

both Contains the CASE begin with S & end with Y

if begin with S & end with Y then possible combination = 4! = 24

The number of permutations that can be made from the letters of the word SUNDAY that neither begin with S nor end with Y

= 720 - 120 - 120  + 24

= 504

504  is The number of permutations that can be made from the letters of the word SUNDAY that neither begin with S nor end with Y

Learn more:

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Both SIDE MULTIPLY by 2
(-1/2)×2 ,(1/2)×2
-2/4 ,2/4
so that between this there are
-1/4,0/4,1/4 so TAKE any of this no.

You subtract s(n-1) from s(n) to get the NTH term.

For EXAMPLE, LET's consider an AP with a=2 and d=4.
S = (n/2)[2a + (n-1)d]
S = (n/2)[4 + (n-1)4]
S = n(2 + 2n - 2)
S = 2n^2

S(n) = 2n^2
By recursion,
S(n-1) = 2(n-1)^2
S(n-1) = 2n^2 - 4n + 2

Subtracting s(n-1) from S(n),
T(n) = 4n - 2
OR
Given a is first term and d be the common difference.

SN = (n/2)[ 2a + ( n -1) d]

Now Sn - 2Sn-1 + Sn + 2

⇒ (n/2)[ 2a + ( n -1) d] - 2(n - 1)/2)[ 2a + ( n - 1 -1) d] + (n +2) / 2)[ 2a + ( n + 2 -1) d]

⇒ (1/2)[ 2an + n( n -1) d] + [ 4a(n - 1) + 2(n - 1)( n - 2) d] +[ 2a(n + 2)+ ( n + 1) (n + 2) d]

⇒ (1/2)[ 2a[ n - 2n + 2 + n + 2] + d [ n2 - n - 2N2 + 6n - 4 + n2 + 3n + 2] ]

⇒ (1/2)[ 2a(4) + d(8n - 2) ]

= [ 4a + (4n - 1)d]

2,X, 26 are in A. P.

THEREFORE, a2-a1 = a3-a2

x-2 = 26-x

2x = 26+2

2x = 28

x = 14.

Answer:

33

Step-by-step EXPLANATION:

Srinath is 7th from the left and Venkat is 12th from the right

Now . If they interchange their positions, Srinath becomes 22ND from the left.

So, Srinath is 22 from left and 12  from right.

So, he has 21 boys before him and 11 boys after him.

So, total number of boys = number of boys before him +Number of boys after him + Srinath

                                          = 21+11+1

                                          =33

Hence there are 33 boys .

So, OPTION 3 is CORRECT.

Let the MARKED price be Rs a

Discount = 11 %

Cost price = 22250

=> a - 11a/100 = 22250

=> 89a/100 = 22250

=> a = 2225000 / 89

=> a = 25000

Marked price = Rs 25000

A SCALENE triangle is a triangle that has three UNEQUAL sides, such as those illustrated above. SEE ALSO: Acute Triangle, Equilateral Triangle, Isosceles Triangle, OBTUSE Triangle, Triangle. CITE THIS AS: Weisstein, Eric W. " Scalene Triangle."

Let point of intersection of AC and PQ be E.
Taking triangle AEP and CEQ.
AP = CQ (GIVEN)
ANGLE EAP = angle ECQ (alternate interior angles are ALWAYS equal)
angle EPA = angle EQC (alt. int. angles).
So, by ASA triangle AEP is congruent to triangle CEQ.
By c.p.c.t.c, AE =EC and PE = EQ

The WORD “computer” does not have an abbreviation. However, the abbreviation “CPU” STANDS for the Central PROCESSING UNIT of the computer.

LENGTH of train = 225

length of tunnel = 275

total length = 500 m

time = 1 MIN = 60 seconds

speed = d/t = 500/60 = 50/6 m/s

= 50/6 * 18/5 (multiply by 18/5 to convert it into km/h)

= 30 km/h

Mean= SUM of all the NUMBERS / TOTAL numbers =85+76+90+85+39+48+56+95+81+71/10
= 726/10
=72.6 is the mean marks OBTAINED by the group.
hope it will help u :)

उतर :-

माना पहले पेड़ पर कुल X चिड़िया बैठी थी, और दूसरे पेड़ पर कुल y चिड़िया बैठी थी l

तब,

→ (x + 1) = (y - 1)

→ x - y = (-2)

→ x = (y - 2) ------ EQN.(1)

और,

→ (y + 1) = 2(x - 1)

→ y - 2x = (-3) ------ Eqn.(2)

Eqn.(1) का मान Eqn.(2) में रखने पर,

→ y - 2(y - 2) = (-3)

→ y - 2y + 4 = (-3)

→ - y = (-3) - 4

→ y = 7

अत,

→ x = 7 - 2 = 5

इसलिए,

→ दोनों पेड़ पर कुल चिड़िया = x + y = 5 + 7 = 12 (Ans.)

यह भी देखें :-

Shakuntla Devi, KARL Gauss, Archimedes could do a lot of quick maths since their young ages.

Can you do better and find ...

brainly.in/question/37519368

Given AC and BD are the diagonals of the parallelogram ABCD.
The POINTS P and Q trisects the diagonal BD
We know that, the diagonals of a parallelogram bisect each other.
∴ AC and BD bisect each other at O.
⇒ OA = OC and OB = OD
Given P and Q trisects the diagonal BD.
∴ BP = PQ = DQ → (1)
Consider, OB = OD
BP + OP = OQ + DQ
DQ + OP = OQ + DQ [From (1)]
∴ OP = OQ
In quadrilateral APCQ diagonals AC and PQ bisect each other
Hence, APCQ is a parallelogram. [Since, if the diagonals of a quadrilateral bisect each other, then the quadrilateral is a parallelogram]
∴ CQ || AP [OPPOSITE sides of parallelogram].

See FIGURE down in attachment.

Hope its helps!!

AREA of square - area of 9 circles

Ar of square = side X side = 42 * 42 cm = 1764 cm sq

Ar of one CIRCLE = Pie r^2 = 22/7 * 7 * 7 = 22 * 7 = 154 cm sq

Such 9 circles are there so area of all 9 = 154 * 9 = 1386 cm sq

Area of remaining portion = ar of square - ar of 9 circles = 1764 - 1386 = 378 cm sq

GIVEN:

PR > PQ & PS bisects ∠QPR

To PROVE:

∠PSR > ∠PSQ

Proof:

∠PQR > ∠PRQ — (i) (PR > PQ as angle opposite to larger side is larger.)

∠QPS = ∠RPS — (ii) (PS bisects ∠QPR)

∠PSR = ∠PQR +∠QPS — (iii)

(exterior angle of a triangle EQUALS to the sum of opposite interior angles)

∠PSQ = ∠PRQ + ∠RPS — (iv)

(exterior angle of a triangle equals to the sum of opposite interior angles)

Adding (i) and (ii)

∠PQR + ∠QPS > ∠PRQ + ∠RPS

∠PSR > ∠PSQ [from (i), (ii), (iii) and (iv)]

Hope this will help you.......

LET S.P. = a

C.P. of 1ST calculator= a x 100/( 100 - 15 ) = a x 100/85 = 20a/17

C.P. of 2nd calculator = a x 100/( 100 + 19 ) = a x 100/119 = 100a/119

a/q

20a/17 + 100a/119 = 4800

240a/119 = 4800

a = 2380

C.P. Of 1st cal. = 20 x 2380/17 = 2800

C.P. of 2nd cal. = 4800 - 2800 = 2000

C.P. of lower priced calculator = Rs. 2000

Hope it HELP u

plz mark as a brainliest

A) Four different colour outcomes are not EQUALLY likely as no. of balls in each color are different from each other.

b) TOTAL no.of balls = 5+3+2+2 = 12
No. of green balls : 5


No. of red balls : 2


No. of blue balls : 3


No. of YELLOW balls : 2


c)

Let the number of apples BOUGHT be x then the COST price of each apple is

1200/x

If 10 rot the new number is x - 10

The selling price for the remaining apples is 1200 + 60 = 1260

1260/(x - 10) is the selling price of each apple.

This is EQUIVALENT to the cost price plus 10 which is as shown :

1200/x + 10

To solve for x, we equate the two.

That is :

1200/x + 10 = 1260 / (x - 10)

1200 (x - 10) + 10x (x - 10) = 1260x

1200x - 12000 + 10x² - 100x = 1260x

1260x - 1200x + 100x - 10x² + 12000 = 0

10x² - 160x - 12000 = 0

Dividing through by 10 we have :

x² - 16x - 1200 = 0

From this we solve for x using quadratic formula.

The equation is THUS :

x² - 16x - 1200 = 0

I HOPE it can HELP you and PLEASE mark it brainliest and follow me

SOLUTION: The amount with Ratna is ₹ 200 more than three times the amount with Rafik.

Let the initial amount with Rafik be ₹ x.
​
∴ Ratna has ₹

∴ ₹ 300 from Ratna are given to Rafik.

∴ Remaining amount with Ratna is ₹

∴ Now Rafik has ₹ ( x + 300)


Now the amount with Ratna is 7/4 times the amount with Rafik

∴ Amount with Ratna / Amount with Rafik =

∴ (3x - 100) / (x + 300) =

∴ 4 (3x - 100) = 7 (x + 300)

∴ 12X - 400 = 7x + 2100

∴ 12x - 7x = 2100 + 400

∴ 5x = 2500

∴ x = 2500/5 = 500

∴ Rafik initially has ₹ 500 with him.

Let ONE supplementary be X
therefore, other supplementary ANGLE be x+50
ACC to question,
x+x+50=180
2x+50=180
2x=130
x=65

other angle is x+50
65+50
=115.


I hope you UNDERSTAND it ☺️☺️☺️☺️☺️.




Mark my answer as brainlist ☺️☺️☺️☺️☺️

Put x = 1
2×1+y =7
y = 7-2
y= 5

put x = 2

2×2+y = 7
y = 7-4
y= 3

put x = 3

2×3+y = 7
y = 7 - 6
y = 1

put x = 4

2×4+y = 7
y = 7 - 8
y = -1


hope it HELPS u.
mark as BRAINLIEST ANSWER

Hey MATE!!

p(x)=x^2-5x-6

p(1)=1^2-5(1)-6
=1-5-6
=-4-6
=-10

p(2)=2^2-5(2)-6
=4-10-6
=-6-6
=-12

p(3)=3^2-5(3)-6
=9-15-6
=-6-6
=-12

p(0)=0^2-5(0)-6
=-6

p(-1)=-1^2-5(-1)-6
=1+5-6
=0

p(-2)=-2^2-5(-2)-6
=4+10-6
=14-6
=8

p(-3)=-3^2-5(-3)-6
=9+15-6
=24-6
=18


hope it helps!!

2x² - 5x - 12


=> 2x² - 8x + 3X - 12

=> 2x( x - 4 ) + 3( x - 4 )

=> ( x - 4 ) ( 2x + 3 )

FIRST TAKE ROOT3-ROOT2 IN BRACKET AND -1 IN OTHER .
NOW RATIONALISE IT. NOW U GET 4-2ROOT 6 IN DENOMINATOR , RATIONALISE IT AGAIN.

Here is your REQUIRED SOLUTION

A) 2,0
B) 0,-8
,...............

It is very easy the ANSWER is 50% . INCLUDING only RAINY days.

We can write SEC 70 as COSEC20 and sin as 1/cosec20 and cos 20 as sin70 and cosec70 as 1/sin70 so the ANSWER will be ZERO