332354 + Interview Questions in Secondary School in Math

1.	Find the product of 3xy2, -3xy3, xy2?
Answer» +3XY2-3xy3+xy2 +3xy2 and +xy2 are positive NUMBERS -3xy3 is negative number +×+=+ = +3xy2+ +xy2= 34113 =34113-3xy3= UR solution

1.

Find the product of 3xy2, -3xy3, xy2?

Answer»

+3XY2-3xy3+xy2

+3xy2 and +xy2 are positive NUMBERS

-3xy3 is negative number

+×+=+

= +3xy2+ +xy2= 34113

=34113-3xy3= UR solution

Discussion

2.	Multiply (2x-1)(x^2-5x+6)need correct answer or I will report.
Answer» Step-by-step EXPLANATION: CHECK for the STEPS in this PIC

2.

Multiply (2x-1)(x^2-5x+6)need correct answer or I will report.

Answer»

Step-by-step EXPLANATION:

CHECK for the STEPS in this PIC

Discussion

3.	राइट डाउन द फार्मूला शोइंग रिलेशनशिप बिटवीन थ्री मेजरस आफ सेंट्रल टेंडेंसी? मैथमेटिक्स क्वेश्चन
Answer» Step-by-step explanation: I can't UNDERSTAND this LANGUAGE MARK me as brilliant and THANK my answer

3.

राइट डाउन द फार्मूला शोइंग रिलेशनशिप बिटवीन थ्री मेजरस आफ सेंट्रल टेंडेंसी? मैथमेटिक्स क्वेश्चन

Answer»

Step-by-step explanation:

I can't UNDERSTAND this LANGUAGE MARK me as brilliant and THANK my answer

Discussion

4.	If A and B are independent events with P(A) =0.4 , P(B) =0.5 then P(A’ ⋂ B)
Answer» Step-by-step EXPLANATION: here is your ANSWER.......

4.

If A and B are independent events with P(A) =0.4 , P(B) =0.5 then P(A’ ⋂ B)

Answer»

Step-by-step EXPLANATION:

here is your ANSWER.......

Discussion

5.	Add:2√2+5√3 and √2-3√3
Answer» ANSWER: find the area of whole total NUMBER of square are 20 and 10 squares are half.

5.

Add:2√2+5√3 and √2-3√3

Answer»

ANSWER:

find the area of whole total NUMBER of square are 20 and 10 squares are half.

Discussion

6.	the length of a rectangle is 8m more than its breadth if its perimeter is 128m, find its length , breadth and Area
Answer» Step-by-step explanation: QUESTION:- the length of a RECTANGLE is 8m more than its BREADTH if its perimeter is 128m, find its length , breadth and Area Answer:- The length of Rectangle is 36 m The breadth of rectangle is 28 m The area of Given rectangle is 1008 m². To find:- Length and breadth of rectangle Area of rectangle Solution:- Let the breadth be x Length = 8 + x Perimeter = 128 m $\boxed{ \large{ \mathfrak{perimeter = 2(l + b)}}}$ According to question, $\large{ \tt: \implies \: \: \: \: \: 2(8 + x + x) = 128}$ $\begin{gathered} \large{ \tt: \implies \: \: \: \: \: 8 + 2x = \frac{128}{2} } \\ \end{gathered}:$ $\large{ \tt: \implies \: \: \: \: \: 8 + 2x = 64}$ $\large{ \tt: \implies \: \: \: \: \: 2x = 64 - 8}$ $\large{ \tt: \implies \: \: \: \: \: 2x = 56}$ $\large{ \tt: \implies \: \: \: \: \: x = 28}$ The breadth of rectangle is 28 m Length = 8 + x = 28 + 8 = 36 m $\large{ \boxed{ \mathfrak{area = l \times b}}}$ $\large{ \tt: \implies \: \: \: \: \: area = 28\times 36}$ $\large{ \tt: \implies \: \: \: \: \: area = 1008 \: {m}^{2} }$ The area of Given rectangle is 1008 m².

6.

the length of a rectangle is 8m more than its breadth if its perimeter is 128m, find its length , breadth and Area

Answer»

Step-by-step explanation:

QUESTION:-

the length of a RECTANGLE is 8m more than its BREADTH if its perimeter is 128m, find its length , breadth and Area

Answer:-

The length of Rectangle is 36 m

The breadth of rectangle is 28 m

The area of Given rectangle is 1008 m².

To find:-

Length and breadth of rectangle

Area of rectangle

Solution:-

Let the breadth be x

Length = 8 + x

Perimeter = 128 m

$\boxed{ \large{ \mathfrak{perimeter = 2(l + b)}}}$

According to question,

$\large{ \tt: \implies \: \: \: \: \: 2(8 + x + x) = 128}$

$\begin{gathered} \large{ \tt: \implies \: \: \: \: \: 8 + 2x = \frac{128}{2} } \\ \end{gathered}:$

$\large{ \tt: \implies \: \: \: \: \: 8 + 2x = 64}$

$\large{ \tt: \implies \: \: \: \: \: 2x = 64 - 8}$

$\large{ \tt: \implies \: \: \: \: \: 2x = 56}$

$\large{ \tt: \implies \: \: \: \: \: x = 28}$

The breadth of rectangle is 28 m

Length = 8 + x = 28 + 8 = 36 m

$\large{ \boxed{ \mathfrak{area = l \times b}}}$

$\large{ \tt: \implies \: \: \: \: \: area = 28\times 36}$

$\large{ \tt: \implies \: \: \: \: \: area = 1008 \: {m}^{2} }$

The area of Given rectangle is 1008 m².

Discussion

7.	Find the value of x,
Answer» ANSWER: x-1 8777900098899989990000gizgtsutsutsuust Step-by-step EXPLANATION: hhjjjogxgzuzt

7.

Find the value of x,

Answer»

ANSWER:

x-1 8777900098899989990000gizgtsutsutsuust

Step-by-step EXPLANATION:

hhjjjogxgzuzt

Discussion

8.	A monomial multiplied by a monomial always gives ___________
Answer» BINOMIAL NUMBER. MARK as BRAINLIEST ANSWER

Discussion

9.	R.F of n√am(n>m) isa. n√a^m-nb. n√a^n-mc. n√a^m-1d. n√a^m+1
Answer» ANSWER: gwvxheshhsvaababhshrfejsjd Step-by-step EXPLANATION: eogjtmdjddjtmvdh

9.

R.F of n√am(n>m) isa. n√a^m-nb. n√a^n-mc. n√a^m-1d. n√a^m+1

Answer»

ANSWER:

gwvxheshhsvaababhshrfejsjd

Step-by-step EXPLANATION:

eogjtmdjddjtmvdh

Discussion

10.	-(1-{1-1(1+1)})=...........
Answer» {-1[-1-1(1+1)]}=0 .............

10.

-(1-{1-1(1+1)})=...........

Answer»

{-1[-1-1(1+1)]}=0

.............

Discussion

11.	18. Half of herd of deer are grazing in the fieldand three-fourth of the remaining areplaying nearby. The rest 9 are drinkingwater from the pond. Find the number ofdeer in the herd.(b) 72(c) 73(d) 74(a) 70
Answer» Answer: 72 Step-by-step explanation: HALF all GRAZING in the FIELD and three fourth of the half is 27 (93) that MEANS a half will be 36(94) and if you are having the half and for making it whole will have to multiply it by two(36*2) =72

11.

18. Half of herd of deer are grazing in the fieldand three-fourth of the remaining areplaying nearby. The rest 9 are drinkingwater from the pond. Find the number ofdeer in the herd.(b) 72(c) 73(d) 74(a) 70

Answer»

Answer:

72

Step-by-step explanation:

HALF all GRAZING in the FIELD and three fourth of the half is 27 (9*3)

that MEANS a half will be 36(9*4)

and if you are having the half and for making it whole will have to multiply it by two(36*2)

=72

Discussion

12.	ErhombusThe area ofwhose diagonals are onand 20cm is equal to0 o
Answer» ANSWER: A=pq 2.......................

12.

ErhombusThe area ofwhose diagonals are onand 20cm is equal to0 o

Answer»

ANSWER:

A=pq

2.......................

Discussion

13.	एक धातु में ताँबे तथा लोहे का अनुपात 5: 7 है। यदि कुल धातु 108 किग्रा तैयार की गई हो, तोताँबे तथा लोहे की अलग-अलग मात्रा ज्ञात कीजिए।
Answer» ANSWER: एक धातु में ताँबे तथा लोहे का अनुपात 5: 7 है। यदि कुल धातु 108 किग्रा तैयार की गई हो, तो ताँबे तथा लोहे की अलग-अलग मात्रा ज्ञात कीजिए।

13.

एक धातु में ताँबे तथा लोहे का अनुपात 5: 7 है। यदि कुल धातु 108 किग्रा तैयार की गई हो, तोताँबे तथा लोहे की अलग-अलग मात्रा ज्ञात कीजिए।

Answer»

ANSWER:

एक धातु में ताँबे तथा लोहे का अनुपात 5: 7 है। यदि कुल धातु 108 किग्रा तैयार की गई हो, तो

ताँबे तथा लोहे की अलग-अलग मात्रा ज्ञात कीजिए।

Discussion

14.	A certain number of men can do a piece of work in 40 days. Had there been 8more men, it would have finished 10 days earlier. How many men were there?
Answer» Answer: djfjfjfjfjfjfj I am djfjfjfjfjfjfj I have a GREAT weekend and I will not me ok waise bhi nahi aa RAHI hai CHAPTER 9 se kam

14.

A certain number of men can do a piece of work in 40 days. Had there been 8more men, it would have finished 10 days earlier. How many men were there?

Answer»

Answer:

djfjfjfjfjfjfj I am djfjfjfjfjfjfj I have a GREAT weekend and I will not me ok waise bhi nahi aa RAHI hai CHAPTER 9 se kam

Discussion

15.	A bus requires 19 litres of petrol to travel distance of 399km.(i) how far the bus can travel in 50 litres petrol. (ii) given that the cost of petrol $2. 45 per litre, what is the cost of petrol required to travel 815 km? Step by stepScam=report
Answer» Answer: 25%24/^©® TIME PASS

15.

A bus requires 19 litres of petrol to travel distance of 399km.(i) how far the bus can travel in 50 litres petrol. (ii) given that the cost of petrol $2. 45 per litre, what is the cost of petrol required to travel 815 km? Step by stepScam=report

Answer»

Answer:

25%24/^©® TIME PASS

Discussion

16.	(ii) Find the product: (x + 3) (x + 7)
Answer» Step-by-step EXPLANATION: (x+3)(x+7) x2+21 hope this is HELPFUL to you

16.

(ii) Find the product: (x + 3) (x + 7)

Answer»

Step-by-step EXPLANATION:

(x+3)(x+7)

x2+21

hope this is HELPFUL to you

Discussion

17.	Meadian of 3/4, 1/2, 2/3, 1/6, 7/12 is .................
Answer» 14/29 ....................I THINK

17.

Meadian of 3/4, 1/2, 2/3, 1/6, 7/12 is .................

Answer»

14/29

....................I THINK

Discussion

18.	The length of a hall is 3 times its height and its breadth is 2.5 times its height. The cost of whitewashing the walls at the rate of ₹ 2.50 per square meter is ₹440. Find the cost of tiling the floor at the rate of ₹ 7.50 per square meter.please answer. thank you
Answer» ANSWER: ........................................... Step-by-step EXPLANATION:

18.

The length of a hall is 3 times its height and its breadth is 2.5 times its height. The cost of whitewashing the walls at the rate of ₹ 2.50 per square meter is ₹440. Find the cost of tiling the floor at the rate of ₹ 7.50 per square meter.please answer. thank you

Answer»

ANSWER:

...........................................

Step-by-step EXPLANATION:

Discussion

19.	From the figure ps= p8cm q2cm R6cm s
Answer» Step-by-step EXPLANATION: where are figure mark as brilliant 30 ❤❤

19.

From the figure ps= p8cm q2cm R6cm s

Answer»

Step-by-step EXPLANATION:

where are figure

mark as brilliant

30 ❤❤

Discussion

20.	Express thirty one - Eighteenths in fraction
Answer» Answer: 31/18 is the FRACTION.

20.

Express thirty one - Eighteenths in fraction

Answer»

Answer:

31/18 is the FRACTION.

Discussion

21.	If the remainder is zero the divisor is a of the dividend
Answer» ANSWER: 0 is the CORRECT answer Step-by-step explanation: 0)0(0 0 — 0

21.

If the remainder is zero the divisor is a of the dividend

Answer»

ANSWER:

0 is the CORRECT answer

Step-by-step explanation:

0)0(0

0

—

0

Discussion

22.	In triangle ABC , right angled at c in which AB=29units , BC=21units and angle ABC= THETA . determine1. cos^2 theta + sin^2 theta2. cos^2theta-sin^2theta3. tan^2theta-sec^2theta
Answer» Answer: 41/841 Step-by-step explanation: ANSWER By PYTHAGORAS theorem, AB 2 =AC 2 +BC 2 ⇒AC 2 =AB 2 −BC 2 ⇒AC 2 =29 2 −21 2 =(29+21)(29−21)=50×8 ⇒AC 2 =25×16 ⇒AC=5×4=20 units ⇒cosθ= AB BC = 29 21 , sinθ= AB AC = 29 20 ⇒sin2θ+cos 2 θ= 29 2 21 2 +20 2 = 29 2 29 2 =1 ⇒cos 2 θ−sin 2 θ= 29 2 21 2 −20 2 = 841 41 . solution

22.

In triangle ABC , right angled at c in which AB=29units , BC=21units and angle ABC= THETA . determine1. cos^2 theta + sin^2 theta2. cos^2theta-sin^2theta3. tan^2theta-sec^2theta

Answer»

Answer:

41/841

Step-by-step explanation:

ANSWER

By PYTHAGORAS theorem,

AB

2

=AC

2

+BC

2

⇒AC

2

=AB

2

−BC

2

⇒AC

2

=29

2

−21

2

=(29+21)(29−21)=50×8

⇒AC

2

=25×16

⇒AC=5×4=20 units

⇒cosθ=

AB

BC

=

29

21

,

sinθ=

AB

AC

=

29

20

⇒sin2θ+cos

2

θ=

29

2

21

2

+20

2

=

29

2

29

2

=1

⇒cos

2

θ−sin

2

θ=

29

2

21

2

−20

2

=

841

41

.

solution

Discussion

23.	Find the first five terms 1.a=20,d=10 2. a=0 ,d=-2
Answer» ANSWER: SORRY can't UNDERSTAND the QUESTION

23.

Find the first five terms 1.a=20,d=10 2. a=0 ,d=-2

Answer»

ANSWER:

SORRY can't UNDERSTAND the QUESTION

Discussion

24.	A figure with 8 sides is called?
Answer» Answer: An 8-sided shape is called an OCTAGON. Step-by-step explanation: Properties of the general octagon ↴ ☯︎The diagonals of the GREEN quadrilateral are equal in LENGTH and at right ANGLES to each other The sum of all the internal angles of any octagon is 1080°. As with all polygons, the external angles total 360°. ☯︎If squares are constructed all internally or all externally on the sides of an octagon, then the midpoints of the segments connecting the centers of opposite squares form a quadrilateral that is both equidiagonal and orthodiagonal (that is, whose diagonals are equal in length and at right angles to each other). ☯︎The midpoint octagon of a reference octagon has its eight vertices at the midpoints of the sides of the reference octagon. If squares are constructed all internally or all externally on the sides of the midpoint octagon, then the midpoints of the segments connecting the centers of opposite squares themselves form the vertices of a SQUARE.

24.

A figure with 8 sides is called?

Answer»

Answer:

An 8-sided shape is called an OCTAGON.

Step-by-step explanation:

Properties of the general octagon ↴

☯︎The diagonals of the GREEN quadrilateral are equal in LENGTH and at right ANGLES to each other

The sum of all the internal angles of any octagon is 1080°. As with all polygons, the external angles total 360°.

☯︎If squares are constructed all internally or all externally on the sides of an octagon, then the midpoints of the segments connecting the centers of opposite squares form a quadrilateral that is both equidiagonal and orthodiagonal (that is, whose diagonals are equal in length and at right angles to each other).

☯︎The midpoint octagon of a reference octagon has its eight vertices at the midpoints of the sides of the reference octagon. If squares are constructed all internally or all externally on the sides of the midpoint octagon, then the midpoints of the segments connecting the centers of opposite squares themselves form the vertices of a SQUARE.

Discussion

25.	4. The blood groups of some students of Class IX were surveyed and recorded as below:Blood GroupABAB0No. of Students1961312If a student is chosen at random, find the probability that he/she has blood group A or AB.
Answer» The blood groups of some students of Class IX were surveyed and recorded as below: Blood Group No. of Students A 19 B 6 AB 13 O 12 TOTAL 50 We have to find, the probability that he/she has blood group A or AB. Solution: Here, Total number of students = 50 Total number if possible OUTCOMES = 50 For blood group A: Number of students having blood A = 19 ∴ P(A) = $\dfrac{Number of favourable outcomes}{All possible outcomes}$ P(A) = $\dfrac{19}{50}$ THUS, the probability that he/she has blood group A is $\dfrac{19}{50}$ . OR: For blood group AB: Number of students having blood AB = 13 ∴ P(AB) = $\dfrac{Number of favourable outcomes}{All possible outcomes}$ P(AB) = $\dfrac{13}{50}$ The probability that he/she has blood group A or AB(A ∪ AB) = P(A) + P(AB) = $\dfrac{19}{50}$ + $\dfrac{13}{50}$ = $\dfrac{32}{50}$ = $\dfrac{16}{25}$ Hence, the probability that he/she has blood group A or AB is" $\dfrac{16}{25}$ ".

25.

4. The blood groups of some students of Class IX were surveyed and recorded as below:Blood GroupABAB0No. of Students1961312If a student is chosen at random, find the probability that he/she has blood group A or AB.

Answer»

The blood groups of some students of Class IX were surveyed and recorded as below:

Blood Group No. of Students

A 19

B 6

AB 13

O 12

TOTAL 50

We have to find, the probability that he/she has blood group A or AB.

Solution:

Here,

Total number of students = 50

Total number if possible OUTCOMES = 50

For blood group A:

Number of students having blood A = 19

∴ P(A) = $\dfrac{Number of favourable outcomes}{All possible outcomes}$

P(A) = $\dfrac{19}{50}$

THUS, the probability that he/she has blood group A is $\dfrac{19}{50}$ .

OR:

For blood group AB:

Number of students having blood AB = 13

∴ P(AB) = $\dfrac{Number of favourable outcomes}{All possible outcomes}$

P(AB) = $\dfrac{13}{50}$

The probability that he/she has blood group A or AB(A ∪ AB)

= P(A) + P(AB)

= $\dfrac{19}{50}$ + $\dfrac{13}{50}$

= $\dfrac{32}{50}$

= $\dfrac{16}{25}$

Hence, the probability that he/she has blood group A or AB is" $\dfrac{16}{25}$ ".

Discussion

26.	Find ∪ , ∩ , − , − ; A= { 2, 6, 10, 14}, B = [ 2, 5, 14, 16}
Answer» ANSWER: HOPE it HELPS U.............

26.

Find ∪ , ∩ , − , − ; A= { 2, 6, 10, 14}, B = [ 2, 5, 14, 16}

Answer»

ANSWER:

HOPE it HELPS U.............

Discussion

27.	8. A pipe can fill a tank in 6hours and another pipe canempty the tank in 12 hours. Ifboth the pipes are opened atthe same time, the tank can befilled in **
Answer» ANSWER: No Step-by-step EXPLANATION: when you OPENED both pipes at same time water will not contain in the tank because it take 12 hour to empty and 6 hours to full

27.

8. A pipe can fill a tank in 6hours and another pipe canempty the tank in 12 hours. Ifboth the pipes are opened atthe same time, the tank can befilled in **

Answer»

ANSWER:

No

Step-by-step EXPLANATION:

when you OPENED both pipes at same time water will not contain in the tank because it take 12 hour to empty and 6 hours to full

Discussion

28.	Estimation of 2568 nearest Thousandth place
Answer» Step-by-step explanation: 8 MATHS r6,5z96rx766जहैतहणेसेणहेणहेंह़संजणसेंहhdhjsbjsjsnjsjsndindudhdbuxbbdhyvycyvyvyvyvycufufyfitxut,it's,8yd,tid,88,8tdyi FY OYF iyfi89y996cr6x7c79x79rz6rzsitsmuuyykLLzoufzltzlt7zasp7O6rzl7tz7p7pzp7rarryrKeYrkYarlLLudLurlurslzlurLLLLljfzilfzlizfzulufzlufz

28.

Estimation of 2568 nearest Thousandth place

Answer»

Step-by-step explanation:

8 MATHS r6,5z96rx766जहैतहणेसेणहेणहेंह़संजणसेंहhdhjsbjsjsnjsjsndindudhdbuxbbdhyvycyvyvyvyvycufufyfitxut,it's,8yd,tid,88,8tdyi FY OYF iyfi89y996cr6x7c79x79rz6rzsitsmuuyykLLzoufzltzlt7zasp7O6rzl7tz7p7pzp7rarryrKeYrkYarlLLudLurlurslzlurLLLLljfzilfzlizfzulufzlufz

Discussion

29.	Deposited6. Ritagoes 20 km towards east from a point A to the point B. From B,she moves 30 km towards west along the same road. If the distancetowards east is represented by a positive integer then, how will yourepresent the distance travelled towards west? By which integer willyou represent her final position from A?B.EastVestA
Answer» ANSWER: -10km Step-by-step EXPLANATION: WEST is the RIGHT answer.

29.

Deposited6. Ritagoes 20 km towards east from a point A to the point B. From B,she moves 30 km towards west along the same road. If the distancetowards east is represented by a positive integer then, how will yourepresent the distance travelled towards west? By which integer willyou represent her final position from A?B.EastVestA

Answer»

ANSWER:

-10km

Step-by-step EXPLANATION:

WEST is the RIGHT answer.

Discussion

30.	the circumference of the base of a circular tank is 20 m . if the height of tank is 3 m find its curved surface area
Answer» Answer: 60m² Step-by-step explanation: curved SURFACE AREA= 2πrh given: CIRCUMFERENCE (2πrh)= 20m HEIGHT(h)=3m therefore, curved surface area= (20×3)m= 60m² ans. Hope it HELPED you PLEASE MARK ME AS BRAINLIEST

30.

the circumference of the base of a circular tank is 20 m . if the height of tank is 3 m find its curved surface area

Answer»

Answer:

60m²

Step-by-step explanation:

curved SURFACE AREA= 2πrh

given: CIRCUMFERENCE (2πrh)= 20m

HEIGHT(h)=3m

therefore, curved surface area=

(20×3)m= 60m² ans.

Hope it HELPED you

PLEASE MARK ME AS BRAINLIEST

Discussion

31.	Class 8 chapter 5 page number 73 and 74
Answer» SORRY but which BOOK I HOPE

31.

Class 8 chapter 5 page number 73 and 74

Answer»

SORRY but which BOOK I HOPE

Discussion

32.	In triangles DEF and KLM, DE - 9.5 cm, ZE=72°. EF = 15.2 cm, KL = 9.5cm. LM = 15.2 cm and L = 72°By which congruence criterion are the triangles congruent?1. SSS2. SAS3 .ASA 4.RHS
Answer» Answer: 2. SAS THANK U Have a NICE DAY

32.

In triangles DEF and KLM, DE - 9.5 cm, ZE=72°. EF = 15.2 cm, KL = 9.5cm. LM = 15.2 cm and L = 72°By which congruence criterion are the triangles congruent?1. SSS2. SAS3 .ASA 4.RHS

Answer»

Answer:

2. SAS

THANK U

Have a NICE DAY

Discussion

33.	After allowing a discount of 9% on a car,its is sold for Rs 82000 find tha M.P of thegive me answer please
Answer» Step-by-step explanation: *PLZ* *refer* *to the attachment ARMY* *may* *be it helps you army* *plz* *don't* *REPORT my answers plz*

33.

After allowing a discount of 9% on a car,its is sold for Rs 82000 find tha M.P of thegive me answer please

Answer»

Step-by-step explanation:

PLZ refer to the attachment ARMY

may be it helps you army

plz don't REPORT my answers plz

Discussion

34.	How many edges are there in a graph with 10 vertices each of degree 5?
Answer» ANSWER: the sum of the degrees of the vertices is 6 ⋅ 10 = 60. The HANDSHAKING THEOREM says 2m = 60. So the number of edges is m = 30. Example: If a graph has 5 vertices, can each vertex have degree 3?

34.

How many edges are there in a graph with 10 vertices each of degree 5?

Answer»

ANSWER:

the sum of the degrees of the vertices is 6 ⋅ 10 = 60. The HANDSHAKING THEOREM says 2m = 60. So the number of edges is m = 30. Example: If a graph has 5 vertices, can each vertex have degree 3?

Discussion

35.	Muje to of RHA knhi ab ek sath top na mar de
Answer» Step-by-step EXPLANATION: .........MMMMMM....

35.

Muje to of RHA knhi ab ek sath top na mar de

Answer»

Step-by-step EXPLANATION:

.........MMMMMM....

Discussion

36.	Simplify the following and answer should be -11/54
Answer» [ ( 3/4 ) ² + ( 1/2 ) ³ ] X ( -2/3 ) ³ ( 9/16 + 1/8 ) x - 8/27 ( 9 + 2 ) / 16 x - 8/27 11/16 x - 8/27 ANSWER ➡ -11/54

36.

Simplify the following and answer should be -11/54

Answer»

[ ( 3/4 ) ² + ( 1/2 ) ³ ] X ( -2/3 ) ³

( 9/16 + 1/8 ) x - 8/27

( 9 + 2 ) / 16 x - 8/27

11/16 x - 8/27

ANSWER ➡ -11/54

Discussion

37.	Plz do solution fast...
Answer» Answer: Step-by-step explanation: As stated x and y has direct relation so x ∝ y x = KY ( replacing ∝ by k ) k = x/y x = 5 , y = 9 k = 5/9 its the VALUE of k x = 45 and y = ? x = ky y = x / k y = 45/5/9 ( 45 divided by 5 / 9 ) y = 81 x =85 and y = ? y = x / k y = 85 / 5 /9 y = 153 In last we have , x = ? and y = 288 x = ky x = 5/9 ( 288 ) x = 160 x =5, 45 ,85 , 160 y =9 , 81 ,153 , 288 ANSWER

37.

Plz do solution fast...

Answer»

Answer:

Step-by-step explanation:

As stated x and y has direct relation so

x ∝ y

x = KY ( replacing ∝ by k )

k = x/y

x = 5 , y = 9

k = 5/9 its the VALUE of k

x = 45 and y = ?

x = ky

y = x / k

y = 45/5/9 ( 45 divided by 5 / 9 )

y = 81

x =85 and y = ?

y = x / k

y = 85 / 5 /9

y = 153

In last we have ,

x = ? and y = 288

x = ky

x = 5/9 ( 288 )

x = 160

x =5, 45 ,85 , 160

y =9 , 81 ,153 , 288 ANSWER

Discussion

38.	Inka .................Or Mein Zara Nahi hoon
Answer» Answer: vo apne frnd ki help NHI kar paye the isliye vo jaa rhe the Step-by-step EXPLANATION: maine unhe BOLA tha ki pakidtan aaj tak WORLD CUP nhi jita phir bhi try karta hai na phir bhi nhi maan rhe the

38.

Inka .................Or Mein Zara Nahi hoon

Answer»

Answer:

vo apne frnd ki help NHI kar paye the isliye vo jaa rhe the

Step-by-step EXPLANATION:

maine unhe BOLA tha ki pakidtan aaj tak WORLD CUP nhi jita phir bhi try karta hai na phir bhi nhi maan rhe the

Discussion

39.	Solve:x⁴-6x³+2x-7+7x³-x+5x²+2-x⁴
Answer» ANSWER: -x³+x-5 Step-by-step EXPLANATION: x⁴-6x³+2x-7+7x³-x+5x²+2-x⁴ x⁴-x⁴-6x³+7x³+2x-x-7+2 -x³+x-5 Plz MAKE me BRAINLIEST

39.

Solve:x⁴-6x³+2x-7+7x³-x+5x²+2-x⁴

Answer»

ANSWER:

-x³+x-5

Step-by-step EXPLANATION:

x⁴-6x³+2x-7+7x³-x+5x²+2-x⁴

x⁴-x⁴-6x³+7x³+2x-x-7+2

-x³+x-5

Plz MAKE me BRAINLIEST

Discussion

40.	Crank Nicloson implicit scheme converges for
Answer» In numerical analysis, the Crank–Nicolson method is a finite difference method used for NUMERICALLY solving the heat equation and similar partial differential equations.[1] It is a second-order method in time. It is implicit in time and can be written as an implicit Runge–Kutta method, and it is numerically stable. The method was developed by John Crankand Phyllis Nicolson in the mid 20th century. For diffusion equations (and many other equations), it can be SHOWN the Crank–Nicolson method is unconditionally stable.[3] However, the approximate solutions can still contain (decaying) spurious oscillations if the ratio of time STEP Δt times the thermal diffusivity to the square of space step, Δx2, is large (typically larger than 1/2 per Von Neumann STABILITY analysis). For this reason, whenever large time steps or high spatial resolution is necessary, the less accurate backward Euler method is often used, which is both stable and IMMUNE to oscillations. Hope it helps you mate................

40.

Crank Nicloson implicit scheme converges for

Answer»

In numerical analysis, the Crank–Nicolson method is a finite difference method used for NUMERICALLY solving the heat equation and similar partial differential equations.[1] It is a second-order method in time. It is implicit in time and can be written as an implicit Runge–Kutta method, and it is numerically stable. The method was developed by John Crankand Phyllis Nicolson in the mid 20th century.

For diffusion equations (and many other equations), it can be SHOWN the Crank–Nicolson method is unconditionally stable.[3] However, the approximate solutions can still contain (decaying) spurious oscillations if the ratio of time STEP Δt times the thermal diffusivity to the square of space step, Δx2, is large (typically larger than 1/2 per Von Neumann STABILITY analysis). For this reason, whenever large time steps or high spatial resolution is necessary, the less accurate backward Euler method is often used, which is both stable and IMMUNE to oscillations.

Hope it helps you mate................

Discussion

41.	The unit digit in the square 297
Answer» ANSWER: 9 I HOPE my answer will HELP you

41.

The unit digit in the square 297

Answer»

ANSWER:

9

I HOPE my answer will HELP you

Discussion

42.	10) The door of your class room is200cm long and 100 cm wide. Find the area of the door?
Answer» Answer: l = 200 CM b = 100 cm area of rectangle = l * b = 200 * 100 = 20,000 cm area of the door = 20,000 cm

42.

10) The door of your class room is200cm long and 100 cm wide. Find the area of the door?

Answer»

Answer:

l = 200 CM

b = 100 cm

area of rectangle = l * b

= 200 * 100

= 20,000 cm

area of the door = 20,000 cm

Discussion

43.	Plot the following points in the cartesian plane. (. )a) (2,4). b) (-3,6) c) (-2,-1). d) (2,-4).
Answer» HOPE it HELPS you PLS mark my answer as BRAINLIEST answer pls

43.

Plot the following points in the cartesian plane. (. )a) (2,4). b) (-3,6) c) (-2,-1). d) (2,-4).

Answer»

HOPE it HELPS you PLS mark my answer as BRAINLIEST answer pls

Discussion

44.	Answer This........
Answer» PB = QC [as corresponding parts of the congruent triangles are equal ] Hence PROVED.

44.

Answer This........

Answer»

PB = QC [as corresponding parts of the congruent triangles are equal ]

Hence PROVED.

Discussion

45.	The reciprocal of 11 upon 13 is _____
Answer» 11/13=13/11..........

Discussion

46.	Consider the equation (x-1)^2=\|3x-5\|1) Among all solutions of the equation, the solutions satisfying x greater than or equal to 5/3 are x=A and x=B where A
Answer» ANSWER: $\huge \bigstar\color{royalblue}{PLEASE \: \: MARK \: \: ME \: \: AS \: \: } \\ \huge \color{royalblue}{ THE \: \: BRAINLIEST \: \: AND \: \:} \\ \huge \color{royalblue}{FOLLOW} \color{black} \bigstar$ Step-by-step EXPLANATION:

46.

Consider the equation (x-1)^2=|3x-5|1) Among all solutions of the equation, the solutions satisfying x greater than or equal to 5/3 are x=A and x=B where A

Answer»

ANSWER:

$\huge \bigstar\color{royalblue}{PLEASE \: \: MARK \: \: ME \: \: AS \: \: } \\ \huge \color{royalblue}{ THE \: \: BRAINLIEST \: \: AND \: \:} \\ \huge \color{royalblue}{FOLLOW} \color{black} \bigstar$

Step-by-step EXPLANATION:

Discussion

47.	वैल्यू ऑफ 4 बटा 13प्लस 3 बटा 26
Answer» Step-by-step explanation: 4/13 + 3/26 (4X2) / (13X2) + 3/26 8/26 + 3/26 11/26

47.

वैल्यू ऑफ 4 बटा 13प्लस 3 बटा 26

Answer»

Step-by-step explanation:

4/13 + 3/26

(4X2) / (13X2) + 3/26

8/26 + 3/26

11/26

Discussion

48.	70% of the students in a school areboys. If the number of girls is 240.How many boysare there in school
Answer» Answer: Let TOTAL no. of STUDENTS be x According to question, 30% of x=240 x=240×100/30 x=800 Now, 70% of 800= no. of boys no. of boys =560

48.

70% of the students in a school areboys. If the number of girls is 240.How many boysare there in school

Answer»

Answer:

Let TOTAL no. of STUDENTS be x

According to question,

30% of x=240

x=240×100/30

x=800

Now,

70% of 800= no. of boys

no. of boys =560

Discussion

49.	13. Which is greater?(1 Point)-2HIN2
Answer» HII LIKE and FOLLOW me thank you for brainliest Follow me

49.

13. Which is greater?(1 Point)-2HIN2

Answer»

HII LIKE and FOLLOW me

thank you for brainliest

Follow me

Discussion

50.	Fatorise: x^3-6x^2+3x+10.
Answer» Step-by-step EXPLANATION: EMAIL yegixhflxkbnxktslhnczoyxnc

50.

Fatorise: x^3-6x^2+3x+10.

Answer»

Step-by-step EXPLANATION:

EMAIL yegixhflxkbnxktslhnczoyxnc

Discussion

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