the length of a rectangle is 8m more than its breadth if its perimeter

1.	the length of a rectangle is 8m more than its breadth if its perimeter is 128m, find its length , breadth and Area
Answer» Step-by-step explanation: QUESTION:- the length of a RECTANGLE is 8m more than its BREADTH if its perimeter is 128m, find its length , breadth and Area Answer:- The length of Rectangle is 36 m The breadth of rectangle is 28 m The area of Given rectangle is 1008 m². To find:- Length and breadth of rectangle Area of rectangle Solution:- Let the breadth be x Length = 8 + x Perimeter = 128 m $\boxed{ \large{ \mathfrak{perimeter = 2(l + b)}}}$ According to question, $\large{ \tt: \implies \: \: \: \: \: 2(8 + x + x) = 128}$ $\begin{gathered} \large{ \tt: \implies \: \: \: \: \: 8 + 2x = \frac{128}{2} } \\ \end{gathered}:$ $\large{ \tt: \implies \: \: \: \: \: 8 + 2x = 64}$ $\large{ \tt: \implies \: \: \: \: \: 2x = 64 - 8}$ $\large{ \tt: \implies \: \: \: \: \: 2x = 56}$ $\large{ \tt: \implies \: \: \: \: \: x = 28}$ The breadth of rectangle is 28 m Length = 8 + x = 28 + 8 = 36 m $\large{ \boxed{ \mathfrak{area = l \times b}}}$ $\large{ \tt: \implies \: \: \: \: \: area = 28\times 36}$ $\large{ \tt: \implies \: \: \: \: \: area = 1008 \: {m}^{2} }$ The area of Given rectangle is 1008 m².