332354 + Interview Questions in Secondary School in Math

1.	1 + cot² θ = _____ *
Answer» ANSWER: tan² THETA..............

1.

1 + cot² θ = _____ *

Answer»

ANSWER:

tan² THETA..............

Discussion

2.	If two lines never intersect in a plane,then the lines are parallel True False
Answer» Answer: TRUE Step-by-step EXPLANATION: They would have to be because any two LINES but PARALLEL lines INTERSECT.

2.

If two lines never intersect in a plane,then the lines are parallel True False

Answer»

Answer: TRUE

Step-by-step EXPLANATION:

They would have to be because any two LINES but PARALLEL lines INTERSECT.

Discussion

3.	The Rockets soccer team has won 7 of their last 8 games. Which value is equivalent to the number of the games they have won?
Answer» Answer: P ( Mathches they didn't won) = 8-7/8= 1/8 Step-by-step explanation: *PLEASE MARK ME BRAIN LIST and thanks me*

3.

The Rockets soccer team has won 7 of their last 8 games. Which value is equivalent to the number of the games they have won?

Answer»

Answer:

P ( Mathches they didn't won) = 8-7/8= 1/8

Step-by-step explanation:

PLEASE MARK ME BRAIN LIST and thanks me

Discussion

4.	The graph shows the relationship between the number of cups of sugar and the number of of in a recipe. What point on the graph represents the number of cups of sugar that would be used with of ?
Answer» Answer: good MORNING Step-by-step explanation: have a GREAT day

4.

The graph shows the relationship between the number of cups of sugar and the number of of in a recipe. What point on the graph represents the number of cups of sugar that would be used with of ?

Answer»

Answer:

good MORNING

Step-by-step explanation:

have a GREAT day

Discussion

5.	Mary is putting new carpeting in her bedroom. Her bedroom floor is 7 feet long and 8 feet wide. How much carpeting does Mary need to buy? add it
Answer» ANSWER: Length = 7 feet Breadth = 8 feet Area = LB = 78 Therefore mary needs to buy 56 feet carpeting

5.

Mary is putting new carpeting in her bedroom. Her bedroom floor is 7 feet long and 8 feet wide. How much carpeting does Mary need to buy? add it

Answer»

ANSWER:

Length = 7 feet

Breadth = 8 feet

Area = L*B

= 7*8

Therefore mary needs to buy 56 feet carpeting

Discussion

6.	Bahupad p(x)=x-5 ke sunyak gant kijiye
Answer» Step-by-step EXPLANATION: x-5=0 x=5 I HOPE it HELPS you

6.

Bahupad p(x)=x-5 ke sunyak gant kijiye

Answer»

Step-by-step EXPLANATION:

x-5=0

x=5

I HOPE it HELPS you

Discussion

7.	Find an equation connecting p and a if p=60 when a=4
Answer» ANSWER: p - a = 56 p + a = 64 Step-by-step explanation: p = 60 a = 4 60 - 4 = 56 p - a = 56 60 + 4 = 64 p + a = 64 Equations CONNECTING p and a if p = 60 when a = 4 are, p - a = 56 p + a = 64

7.

Find an equation connecting p and a if p=60 when a=4

Answer»

ANSWER:

p - a = 56

p + a = 64

Step-by-step explanation:

p = 60

a = 4

60 - 4 = 56

p - a = 56

60 + 4 = 64

p + a = 64

Equations CONNECTING p and a if p = 60 when a = 4 are,

p - a = 56

p + a = 64

Discussion

8.	Write √7 it in exponential form
Answer» ANSWER: PSP psp psp ISO to iso iso iso iso

8.

Write √7 it in exponential form

Answer»

ANSWER:

PSP psp psp ISO to iso iso iso iso

Discussion

9.	Answer this question according to the given attachment :-What is the length of EF where EF is one of the horizontal edges of the block ? options :- (i) 24 m(ii) 3m(iii) 6m(iv) 10 m
Answer» Answer: OPTION (4) is the CORRECT one :- 10m

9.

Answer this question according to the given attachment :-What is the length of EF where EF is one of the horizontal edges of the block ? options :- (i) 24 m(ii) 3m(iii) 6m(iv) 10 m

Answer»

Answer:

OPTION (4) is the CORRECT one :- 10m

Discussion

10.	Solve this..............
Answer» ♣ɢɪᴠᴇɴ:– $\large \bf \dfrac {sin ^{4} \: A}{a} \: + \: \frac{cos^{4} A}{b} \: = \: \frac{<klux>1</klux>}{a \: + \: b} \\$ ♣ᴛᴏ ᴘʀᴏᴠᴇ:– $\large \bf \dfrac{sin ^{8} \: A}{ {a}^{3} } \: + \: \frac{cos^{8} \: A}{ {b}^{3} } \: = \: \frac{1}{(a \: + \: b) ^{3} } \\$ ♣sᴏʟᴜᴛɪᴏɴ:– ➤ cos²A = 1 - sin²A ➤ cos⁴A = 1 + sin⁴A - 2sin²A cos⁴A = 1 + sin⁴A - 2sin²A $\begin{gathered}\\ \to \sf \dfrac{sin^4A}{a}+\dfrac{1+sin^4A-2sin^2A}{b}=\dfrac{1}{a+b}\\\end{gathered}\\\begin{gathered}\\\to \sf bsin^4A+a+asin^4A-2asin^2A=\dfrac{ab}{a+b}\end{gathered}\\\begin{gathered}\to \sf sin^4A(a+b)-2asin^2A+a=\dfrac{ab}{a+b}\\\end{gathered}\\\begin{gathered}\\ \to \sf sin^4A(a+b)^2-2(sin^2A)(a+b)a+a(a+b)=ab\\\end{gathered}\\\begin{gathered}\\\to \sf sin^4A(a+b)^2-2[sin^2A(a+b)]a+a^2+ab-ab=0\\\end{gathered}\\\begin{gathered}\\\to \sf[sin^2A(a+b)]^2-2[sin^2A(a+b)]a+a^2=0\\\end{gathered}\\(a - b)² = a² - 2ab + b²\\\begin{gathered}\\\to \sf [sin^2A(a+b)-a]^2=0\\\end{gathered}\\\begin{gathered}\\\to \purple{\textsf{\textbf{ sin$^\text{2}\text{A}=\dfrac{\text a}{\text{a\ +\ b}} $}}}\\\end{gathered}\\\bull \: \bf{Now , cos²A = 1 - sin²A}\\\begin{gathered}\\\to \sf cos^2A=1-\dfrac{a}{a+b}\\\end{gathered}\\\begin{gathered}\\\to \pink{\textsf{\textbf{$\text{cos}^\text{2}\text{A}=\dfrac{\text{b}}{\text{a\ +\ b}}$}}}\\\end{gathered}\\\bull \: \bf{So} ,\\\begin{gathered}\\\sf \dfrac{\text{sin}^\text{8}A}{a^3}+\dfrac{cos^8A}{b^3}\\\end{gathered}\\\begin{gathered}\\\to \sf \dfrac{(sin^2A)^4}{a^3}+\dfrac{(cos^2A)^4}{b^3}\\\end{gathered}\\\begin{gathered}\\\to \sf \dfrac{\big(\dfrac{a}{a+b}\big)^{\tiny{4}}}{a^3}+\dfrac{\big(\dfrac{b}{a+b}\big)^{\tiny{4}}}{b^3}\\\end{gathered}\\\begin{gathered}\\\to\sf \dfrac{a}{(a+b)^4}+\dfrac{b}{(a+b)^4}\\\end{gathered}\\\begin{gathered}\\\to \sf \dfrac{a+b}{(a+b)^4}\\\end{gathered}\\\begin{gathered}\\\red{\leadsto \textsf{\textbf{$ \dfrac{\text 1}{\text{(a\ +\ b)$^\text{3}$}} $}}}\\\end{gathered} \\$

10.

Solve this..............

Answer»

♣ɢɪᴠᴇɴ:–

$\large \bf \dfrac {sin ^{4} \: A}{a} \: + \: \frac{cos^{4} A}{b} \: = \: \frac{<klux>1</klux>}{a \: + \: b} \\$

♣ᴛᴏ ᴘʀᴏᴠᴇ:–

$\large \bf \dfrac{sin ^{8} \: A}{ {a}^{3} } \: + \: \frac{cos^{8} \: A}{ {b}^{3} } \: = \: \frac{1}{(a \: + \: b) ^{3} } \\$

♣sᴏʟᴜᴛɪᴏɴ:–

➤ cos²A = 1 - sin²A

➤ cos⁴A = 1 + sin⁴A - 2sin²A

cos⁴A = 1 + sin⁴A - 2sin²A

$\begin{gathered}\\ \to \sf \dfrac{sin^4A}{a}+\dfrac{1+sin^4A-2sin^2A}{b}=\dfrac{1}{a+b}\\\end{gathered}\\\begin{gathered}\\\to \sf bsin^4A+a+asin^4A-2asin^2A=\dfrac{ab}{a+b}\end{gathered}\\\begin{gathered}\to \sf sin^4A(a+b)-2asin^2A+a=\dfrac{ab}{a+b}\\\end{gathered}\\\begin{gathered}\\ \to \sf sin^4A(a+b)^2-2(sin^2A)(a+b)a+a(a+b)=ab\\\end{gathered}\\\begin{gathered}\\\to \sf sin^4A(a+b)^2-2[sin^2A(a+b)]a+a^2+ab-ab=0\\\end{gathered}\\\begin{gathered}\\\to \sf[sin^2A(a+b)]^2-2[sin^2A(a+b)]a+a^2=0\\\end{gathered}\\(a - b)² = a² - 2ab + b²\\\begin{gathered}\\\to \sf [sin^2A(a+b)-a]^2=0\\\end{gathered}\\\begin{gathered}\\\to \purple{\textsf{\textbf{ sin$^\text{2}\text{A}=\dfrac{\text a}{\text{a\ +\ b}} $}}}\\\end{gathered}\\\bull \: \bf{Now , cos²A = 1 - sin²A}\\\begin{gathered}\\\to \sf cos^2A=1-\dfrac{a}{a+b}\\\end{gathered}\\\begin{gathered}\\\to \pink{\textsf{\textbf{$\text{cos}^\text{2}\text{A}=\dfrac{\text{b}}{\text{a\ +\ b}}$}}}\\\end{gathered}\\\bull \: \bf{So} ,\\\begin{gathered}\\\sf \dfrac{\text{sin}^\text{8}A}{a^3}+\dfrac{cos^8A}{b^3}\\\end{gathered}\\\begin{gathered}\\\to \sf \dfrac{(sin^2A)^4}{a^3}+\dfrac{(cos^2A)^4}{b^3}\\\end{gathered}\\\begin{gathered}\\\to \sf \dfrac{\big(\dfrac{a}{a+b}\big)^{\tiny{4}}}{a^3}+\dfrac{\big(\dfrac{b}{a+b}\big)^{\tiny{4}}}{b^3}\\\end{gathered}\\\begin{gathered}\\\to\sf \dfrac{a}{(a+b)^4}+\dfrac{b}{(a+b)^4}\\\end{gathered}\\\begin{gathered}\\\to \sf \dfrac{a+b}{(a+b)^4}\\\end{gathered}\\\begin{gathered}\\\red{\leadsto \textsf{\textbf{$ \dfrac{\text 1}{\text{(a\ +\ b)$^\text{3}$}} $}}}\\\end{gathered} \\$

Discussion

11.	Find quardtic equation whose one of zeroes is 2+ ✓3
Answer» Step-by-step explanation: If 2+sqrt(3) is a ZERO, so is the conjugate 2-sqrt(3) . Also, if a is a zero, then (x-a) is a factor, thus the factors of the quadratic are: (x-2+sqrt(3))(x-2-sqrt(3)) Multiplying we get: x^2-2x-xsqrt(3)-2x+4+2sqrt(3)+xsqrt(3)-2sqrt(3)-3 Adding LIKE terms: x^2-4x+1 ----------------------------------------------------------------- The monic quadratic polynomial with rational coefficients is: x^2-4x+1 ----------------------------------------------------------------- ** CHECKING we can use the quadratic FORMULA to FIND the roots(zeros): x=(4+-sqrt(16-4(1)(1)))/(2(1)) =(4+-sqrt(12))/2 =(4+-2sqrt(3))/2 =2+-sqrt(3) and we see that 2+sqrt(3) is a zero.

11.

Find quardtic equation whose one of zeroes is 2+ ✓3

Answer»

Step-by-step explanation:

If 2+sqrt(3) is a ZERO, so is the conjugate 2-sqrt(3) .

Also, if a is a zero, then (x-a) is a factor, thus the factors of the quadratic are:

(x-2+sqrt(3))(x-2-sqrt(3))

Multiplying we get:

x^2-2x-xsqrt(3)-2x+4+2sqrt(3)+xsqrt(3)-2sqrt(3)-3

Adding LIKE terms:

x^2-4x+1

-----------------------------------------------------------------

The monic quadratic polynomial with rational coefficients is:

x^2-4x+1

-----------------------------------------------------------------

** CHECKING we can use the quadratic FORMULA to FIND the roots(zeros):

x=(4+-sqrt(16-4(1)(1)))/(2(1))

=(4+-sqrt(12))/2

=(4+-2sqrt(3))/2

=2+-sqrt(3)

and we see that 2+sqrt(3) is a zero.

Discussion

12.	The 4th and 17th term of an ap are 3 and 36 find the AP and its 15th term
Answer» ANSWER: dfddr EXCHANGE dfghhhhjjhhbv Gregg

12.

The 4th and 17th term of an ap are 3 and 36 find the AP and its 15th term

Answer»

ANSWER:

dfddr EXCHANGE dfghhhhjjhhbv Gregg

Discussion

13.	Construct a scale to measure up to 10 km which represents 1 km as 15 mm and also find the representation factor of the scale.
Answer» ANSWER: OK GUY TAKE 50point PLZZZ

13.

Construct a scale to measure up to 10 km which represents 1 km as 15 mm and also find the representation factor of the scale.

Answer»

ANSWER:

OK GUY TAKE 50point PLZZZ

Discussion

14.	what's the difference between mounted and surmounted in maths..... explain in detail with examples and diagram
Answer» ANSWER: MOUNTED MEANS any object PLACED on the other object while surmounted means any object holding any other object placed on the top of its surface

14.

what's the difference between mounted and surmounted in maths..... explain in detail with examples and diagram

Answer»

ANSWER:

MOUNTED MEANS any object PLACED on the other object while surmounted means any object holding any other object placed on the top of its surface

Discussion

15.	ALGEBRA SECTIONQ1: Add the following.1. a² - b², 2 a² + 3b²2. 2x³ – 4x² – 3x + 5,4x² – x³ - x + 3GEOMETRYQ2: Define the following and also draw the diagram.1. Major segment2. Chard3. Radius.
Answer» ANSWER: tcinkvtxygubtxrxyvibtxrc of rxtociys,tctidydkxgclg

15.

ALGEBRA SECTIONQ1: Add the following.1. a² - b², 2 a² + 3b²2. 2x³ – 4x² – 3x + 5,4x² – x³ - x + 3GEOMETRYQ2: Define the following and also draw the diagram.1. Major segment2. Chard3. Radius.

Answer»

ANSWER:

tcinkvtxygubtxrxyvibtxrc of rxtociys,tctidydkxgclg

Discussion

16.	ALGEBRA SECTIONQ1: Add the following.1. a? - b2, 2a+ 3b22. 2x3 – 4x2 - 3x + 5, 4x2 - 33 - x + 3
Answer» Answer: 1) a²-b²+2a+3b² =a²+2a+2b² (ANS) 2) 2x³-4x²-3x+5+4x²-33-x+3 =2x³- 4x²+ 4x²-3x-x-33-3+5 =2x³-4x-31 (Ans)

16.

ALGEBRA SECTIONQ1: Add the following.1. a? - b2, 2a+ 3b22. 2x3 – 4x2 - 3x + 5, 4x2 - 33 - x + 3

Answer»

Answer:

1)

a²-b²+2a+3b²

=a²+2a+2b² (ANS)

2)

2x³-4x²-3x+5+4x²-33-x+3

=2x³- 4x²+ 4x²-3x-x-33-3+5

=2x³-4x-31 (Ans)

Discussion

17.	MAAF KRO BHAII M JAA RHA HU BYEE
Answer» ANSWER: kidhar jaa RHE ho or KIS se maafi maag RAHE ho DUDE

17.

MAAF KRO BHAII M JAA RHA HU BYEE

Answer»

ANSWER:

kidhar jaa RHE ho or KIS se maafi maag RAHE ho DUDE

Discussion

18.	Graph the rational function f of x equals quantity 4 times x minus 3 end quantity over quantity x plus 2 end quantity.A rational function is graphed in the first quadrant and in the second and third quadrants is another piece of the graph. The graph approaches an imaginary horizontal line at y equals 3 and approaches an imaginary vertical line at x equals 5. A rational function is graphed in the second quadrant and in the third and first quadrants is another piece of the graph. The graph approaches an imaginary horizontal line at y equals 2 and approaches an imaginary vertical line at x equals negative 4. A rational function is graphed in the second quadrant and in the third and first quadrants is another piece of the graph. The graph approaches an imaginary horizontal line at y equals 4 and approaches an imaginary vertical line at x equals negative 2. A rational function is graphed in the first quadrant and in the second and third quadrants is another piece of the graph. The graph approaches an imaginary horizontal line at y equals 5 and approaches an imaginary vertical line at x equals 3. dont just answer for points my future depends on this
Answer» ${\huge{\purple{\underline{\underline{\bf{\pink{\mathfrak{Answer}}}}}}}}$ ⬤ ${\: \: \: \: \: \: \: \: \: \:Initial \: Velocity, \: u \: = \: <klux>0</klux>}$ ⬤ ${\: \: \: \: \: \: \: \: \: \: Distance, \: s\: = \: 200m}$ ⬤ ${\: \: \: \: \: \: \: \: \: \:Time, \: t\: =\: 10s}$ ${\small{\bf{\green{\mathfrak{\underline{\underline{As\: we\: are\: asked\: to\: find\: Acceleration,}}}}}}}$ ${\: \: \: \: \: \: \: \: \: \:s\:=\:ut\:+\: 1/2at²}$ ${\huge{\bf{\green{\mathfrak{\underline{\underline{By\: substituting\: values\: in\: the\: \: formulae,}}}}}}}$ ⇒200 = 0(10) + 1/2(a(10)²) ⇒200 = 1/2(a*100) ⇒200 × 2 = a × 100 ⇒400/100 = a ⇒4 = a ${\huge{\bf{\green{\mathfrak{\underline{\underline{Or,}}}}}}}$ ⇒ ${\: \: \: \: \: \: \: \: \: \:a\: =\: 4\: m/s²}$

18.

Graph the rational function f of x equals quantity 4 times x minus 3 end quantity over quantity x plus 2 end quantity.A rational function is graphed in the first quadrant and in the second and third quadrants is another piece of the graph. The graph approaches an imaginary horizontal line at y equals 3 and approaches an imaginary vertical line at x equals 5. A rational function is graphed in the second quadrant and in the third and first quadrants is another piece of the graph. The graph approaches an imaginary horizontal line at y equals 2 and approaches an imaginary vertical line at x equals negative 4. A rational function is graphed in the second quadrant and in the third and first quadrants is another piece of the graph. The graph approaches an imaginary horizontal line at y equals 4 and approaches an imaginary vertical line at x equals negative 2. A rational function is graphed in the first quadrant and in the second and third quadrants is another piece of the graph. The graph approaches an imaginary horizontal line at y equals 5 and approaches an imaginary vertical line at x equals 3. dont just answer for points my future depends on this

Answer»

${\huge{\purple{\underline{\underline{\bf{\pink{\mathfrak{Answer}}}}}}}}$

⬤ ${\: \: \: \: \: \: \: \: \: \:Initial \: Velocity, \: u \: = \: <klux>0</klux>}$

⬤ ${\: \: \: \: \: \: \: \: \: \: Distance, \: s\: = \: 200m}$

⬤ ${\: \: \: \: \: \: \: \: \: \:Time, \: t\: =\: 10s}$

${\small{\bf{\green{\mathfrak{\underline{\underline{As\: we\: are\: asked\: to\: find\: Acceleration,}}}}}}}$

${\: \: \: \: \: \: \: \: \: \:s\:=\:ut\:+\: 1/2at²}$

${\huge{\bf{\green{\mathfrak{\underline{\underline{By\: substituting\: values\: in\: the\: \: formulae,}}}}}}}$

⇒200 = 0*(10) + 1/2(a*(10)²)

⇒200 = 1/2(a*100)

⇒200 × 2 = a × 100

⇒400/100 = a

⇒4 = a

${\huge{\bf{\green{\mathfrak{\underline{\underline{Or,}}}}}}}$

⇒ ${\: \: \: \: \: \: \: \: \: \:a\: =\: 4\: m/s²}$

Discussion

19.	4. If the height and sum of the parallel sides of a trapezium are increased three times, then find theincrease per cent of area.
Answer» ANSWER: FOLLOW me for FREE POINTS. plspla

19.

4. If the height and sum of the parallel sides of a trapezium are increased three times, then find theincrease per cent of area.

Answer»

ANSWER:

FOLLOW me for FREE POINTS. plspla

Discussion

20.	OBS-aea (CEvaluate: limy
Answer» Answer: OXIGEN Step-by-step EXPLANATION: if there was MO oxygen all organismn WUD HV died

20.

OBS-aea (CEvaluate: limy

Answer»

Answer:

OXIGEN

Step-by-step EXPLANATION:

if there was MO oxygen all organismn WUD HV died

Discussion

21.	Write the greatest 4-digit number and express it in terms of its prime factors?
Answer» ANSWER: PRIME FACTORS of 9999 Therefore, 9999 is the largest 4-digit number and can be EXPRESSED as 3 × 3 × 11 × 101. Mark me as BRAINIEST

21.

Write the greatest 4-digit number and express it in terms of its prime factors?

Answer»

ANSWER:

PRIME FACTORS of 9999

Therefore, 9999 is the largest 4-digit number and can be EXPRESSED as 3 × 3 × 11 × 101.

Mark me as BRAINIEST

Discussion

22.	3.7x²+15 x-4=0Sum:Product:
Answer» ANSWER: ikon 88iiiiiiiiiiiiiiiiiii

22.

3.7x²+15 x-4=0Sum:Product:

Answer»

ANSWER:

ikon

88iiiiiiiiiiiiiiiiiii

Discussion

23.	In a cricket match,a woman batsman hit 6 times 4 runs out of 30 balls.
Answer» ANSWER: Totalnumberofballsplayed=30 Numberoftimesbatsmanhitsaboundary=6 Numberoftimesbatsmandoesnothitaboundary=30−6=24 Probabilitythatonaballplayedhedoesnothitsaboundary =TotalnumberofballsplayedFrequencywhenthebatsmandoesnothitsaboundary =3024=0.8

23.

In a cricket match,a woman batsman hit 6 times 4 runs out of 30 balls.

Answer»

ANSWER:

Totalnumberofballsplayed=30

Numberoftimesbatsmanhitsaboundary=6

Numberoftimesbatsmandoesnothitaboundary=30−6=24

Probabilitythatonaballplayedhedoesnothitsaboundary

=TotalnumberofballsplayedFrequencywhenthebatsmandoesnothitsaboundary

=3024=0.8

Discussion

24.	(ii) A circle is inscribed by a square. The length of side of square is 10 cm. The length ofdiameter of circle is(a) 10 cm. (b) 5cm(c) 20 cm(d) 10/2 cm.Answer is 10cm... make it.....
Answer» ANSWER: 10 Step-by-step EXPLANATION: answer is a 10 CM because square sideis 10 cm so answer is 10 cm

24.

(ii) A circle is inscribed by a square. The length of side of square is 10 cm. The length ofdiameter of circle is(a) 10 cm. (b) 5cm(c) 20 cm(d) 10/2 cm.Answer is 10cm... make it.....

Answer»

ANSWER:

10

Step-by-step EXPLANATION:

answer is a

10 CM

because

square sideis

10 cm

so

answer is

10 cm

Discussion

25.	8meter 5 decimeter to decimeter
Answer» Answer: 1m=10dm so, 8m5dm=8×10+5dm =85dm

25.

8meter 5 decimeter to decimeter

Answer»

Answer:

1m=10dm

so,

8m5dm=8×10+5dm

=85dm

Discussion

26.	In a big bazar, the total cost of two shirts and trouser is rupee 3491.96 . If the cost of a shirt is rupee 2006.99 less than the cost of a trouser , then the cost of a shirt is(i) $ 490.90(ii) $ 494.99(iii) $ 1084.97(iv) $ 1484.97
Answer» ANSWER: $1084 OK JK jk jk jk jk jk jk(kkkkkkk

26.

In a big bazar, the total cost of two shirts and trouser is rupee 3491.96 . If the cost of a shirt is rupee 2006.99 less than the cost of a trouser , then the cost of a shirt is(i) $ 490.90(ii) $ 494.99(iii) $ 1084.97(iv) $ 1484.97

Answer»

ANSWER:

$1084 OK JK jk jk jk jk jk jk(kkkkkkk

Discussion

27.	2. Subtract the following:(1) 3 hours 10 minutes - 2 hours 40 minutes
Answer» Answer: 30 MIN Step-by-step explanation: 3 HRS 10 mins = 190 min 2 hrs 40 min = 160 min so answer is 30 min

27.

2. Subtract the following:(1) 3 hours 10 minutes - 2 hours 40 minutes

Answer»

Answer:

30 MIN

Step-by-step explanation:

3 HRS 10 mins = 190 min

2 hrs 40 min = 160 min

so answer is 30 min

Discussion

28.	a scooter worth ₹30000 was insured for 90% of his value.how much would the owner get in case of any mishappening
Answer» Answer: *THE* *SCOOTER* *GOT* *INSURED* @ 90% OF *ITS* *TOTAL* *VALUE.* *THE* *OWNER* *WILL* *GET* *ONLY* 90% *AMOUNT* *OFF* *HIS* *SCOOTER* IN *CASE* OF *ANY* *ACCIDENT.THIS IS BECAUSE* OF *THE* *PRINCIPLE* OF *INDEMNITY.IT SAYS* *THAT* *THE* *INSURED* *MUST* *NEITHER* *GET* *MORE* *NOR* *LESS* *THAN* *THE* *LOSS* *OCCURRED* *DURING* AN *INCIDENT* OR *ACCIDENT.* *THEREFORE, OWNER* *WILL* *ONLY* *GET* @90% OF *THE* *TOTAL* *VALUE* OF THE *SCOOTER*.

28.

a scooter worth ₹30000 was insured for 90% of his value.how much would the owner get in case of any mishappening

Answer»

Answer:

THE SCOOTER GOT INSURED @ 90% OF ITS TOTAL VALUE.

THE OWNER WILL GET ONLY 90% AMOUNT OFF HIS SCOOTER IN CASE OF ANY ACCIDENT.THIS IS BECAUSE OF THE PRINCIPLE OF INDEMNITY.IT SAYS THAT THE INSURED MUST NEITHER GET MORE NOR LESS THAN THE LOSS OCCURRED DURING AN INCIDENT OR ACCIDENT.

THEREFORE, OWNER WILL ONLY GET @90% OF THE TOTAL VALUE OF THE SCOOTER.

Discussion

29.	Solve the following problem (6)= 21 + 32 subject to 1 − 22 ≤ 0,−21 + 32 ≥ −6,1, 2 unrestricted
Answer» ANSWER: BYE Bye the AIR it is the BEST the air it is

29.

Solve the following problem (6)= 21 + 32 subject to 1 − 22 ≤ 0,−21 + 32 ≥ −6,1, 2 unrestricted

Answer»

ANSWER:

BYE Bye the AIR it is the BEST the air it is

Discussion

30.	10. Factorise by using the above results(identities)1) 27a3+ 64b3
Answer» ANSWER: Hope this helps you. Step-by-step explanation: Remembering that: a3−b3=(a−b)(a2+ab+b2) we can try to write 27a3−64b3 like a difference of cubes 27a3−64b3=33a3−26b3=33a3−(22)3b3= (3a)3−43b3=(3a)3−(4B)3 Now we can apply the rule: 27a3−64b3=(3a)3−(4b)3= =(3a−4b)((3a)2+12ab+(4b)2) =(3a−4b)(9a2+12ab+16b

30.

10. Factorise by using the above results(identities)1) 27a3+ 64b3

Answer»

ANSWER:

Hope this helps you.

Step-by-step explanation:

Remembering that:

a3−b3=(a−b)(a2+ab+b2)

we can try to write

27a3−64b3

like a difference of cubes

27a3−64b3=33a3−26b3=33a3−(22)3b3=

(3a)3−43b3=(3a)3−(4B)3

Now we can apply the rule:

27a3−64b3=(3a)3−(4b)3=

=(3a−4b)((3a)2+12ab+(4b)2)

=(3a−4b)(9a2+12ab+16b

Discussion

31.	Calculate the simple Interest on ₹10000 for 5 years 6 months at a interest of 1.5 % per month?
Answer» Hey Mate, Here's your answer, ____________________ => Principal = 10000 RS => Time = 5 YEARS 6 months or 5 1/2 YEAR => Rate = 1.5% per month (Convert Rate into year) (1 year = 12 months) (1.5% × 12) (6.0%) Simple Interest = PRT / 100 => Simple Interest = 10000 × 5 1/2 × 6 / 100 => Simple Interest = 100 × 5 1/2 × 6 => Simple Interest = 3300 Rs ___________________ $hope \: it \: helps$

31.

Calculate the simple Interest on ₹10000 for 5 years 6 months at a interest of 1.5 % per month?

Answer»

Hey Mate,

Here's your answer,

____________________

=> Principal = 10000 RS

=> Time = 5 YEARS 6 months or 5 1/2 YEAR

=> Rate = 1.5% per month

(Convert Rate into year)

(1 year = 12 months)

(1.5% × 12)

(6.0%)

Simple Interest = PRT / 100

=> Simple Interest = 10000 × 5 1/2 × 6 / 100

=> Simple Interest = 100 × 5 1/2 × 6

=> Simple Interest = 3300 Rs

___________________

$hope \: it \: helps$

Discussion

32.	1) If the slope of the line joining points (k, - 3) and (4, 5) is 12, then find the value of k.
Answer» ANSWER: It will be -2 maybe I am not SURE...I MOSTLY do mistakes in sign

32.

1) If the slope of the line joining points (k, - 3) and (4, 5) is 12, then find the value of k.

Answer»

ANSWER:

It will be -2 maybe

I am not SURE...I MOSTLY do mistakes in sign

Discussion

33.	Find the mode of below given dataclass 0-10 10-20 20-30 30 - 40 40 - 50 50 - 60 60 to 70 70 - 80 frequency 07 ,14, 13, 12, 20, 11 ,15, 8
Answer» ANSWER: Mode = 760/17 i HOPE that it would HELP U and mark me as the brainiest Step-by-step EXPLANATION:

33.

Find the mode of below given dataclass 0-10 10-20 20-30 30 - 40 40 - 50 50 - 60 60 to 70 70 - 80 frequency 07 ,14, 13, 12, 20, 11 ,15, 8

Answer»

ANSWER:

Mode = 760/17

i HOPE that it would HELP U and mark me as the brainiest

Step-by-step EXPLANATION:

Discussion

34.	DO THISFind the zeroes of the quadratic polynomials given below. Find the sum and productof the zeroes and verify relationship to the coefficients of terms in the polynomial.(1) p(x) = x - x - 6 (ii) p(x) = x2 - 4x + 3(111) p(x) = x2-4(iv) p(x) = x2 + 2x + 1
Answer» ANSWER: QUESTION at wrong plz WRITE RIGHT question

34.

DO THISFind the zeroes of the quadratic polynomials given below. Find the sum and productof the zeroes and verify relationship to the coefficients of terms in the polynomial.(1) p(x) = x - x - 6 (ii) p(x) = x2 - 4x + 3(111) p(x) = x2-4(iv) p(x) = x2 + 2x + 1

Answer»

ANSWER:

QUESTION at wrong

plz WRITE RIGHT question

Discussion

35.	Find(+)÷(−) I =5/4,=-1/3
Answer» u3uiri3i Answer: jrjjekkDkkdkme Step-by-step explanation: 4iiE848eiwje

35.

Find(+)÷(−) I =5/4,=-1/3

Answer»

u3uiri3i

Answer:

jrjjekkDkkdkme

Step-by-step explanation:

4iiE848eiwje

Discussion

36.	Convert the rational numbers into decimal form a.1/2
Answer» ANSWER: 0.5 is the CORRECT answer

36.

Convert the rational numbers into decimal form a.1/2

Answer»

ANSWER:

0.5 is the CORRECT answer

Discussion

37.	X= rcosθ , Y= rsinθ then [∂y/∂r]x [∂y/∂r] θ
Answer» Solution Given :- Three numbers are in the RATIO 3:4:5 the SUM of the largest and the smallest equals the sum of the third and 52 Find :- These Number . Explanation Let, Number be First Number be = 3X Second Number be = 4X Third Number be = 5x Then, According to question, ➡ 3x + 5x = 5x + 52 ➡8x = 5x + 52 ➡8x - 5x = 52 ➡3x = 52 ➡x = 52/3 Hence First Number will be = 3x = 3 × 52/3 = 52 Second Number will be = 4x = 4 × 52/3 = 208/3 Third Number will be = 5x = 5×52/3 = 260/3 _______________ Answer Verification (the Sum of the largest and the smallest equals the sum of the third and 52) ➡3x + 5x = 5x + 52 Keep Value of x. ➡3 × 52/3 + 5 × 52/3 = 5 × 52/3 + 52 ➡52 + 260/3 = 260 + 52 ➡(156+260)/3 = (156 + 260)/3 ➡416/3 = 416/3 L.H.S. = R.H.S. ___________________________________________________________

37.

X= rcosθ , Y= rsinθ then [∂y/∂r]x [∂y/∂r] θ

Answer»

Solution

Given :-

Three numbers are in the RATIO 3:4:5

the SUM of the largest and the smallest equals the sum of the third and 52

Find :-

These Number .

Explanation

Let, Number be

First Number be = 3X

Second Number be = 4X

Third Number be = 5x

Then, According to question,

➡ 3x + 5x = 5x + 52

➡8x = 5x + 52

➡8x - 5x = 52

➡3x = 52

➡x = 52/3

Hence

First Number will be = 3x = 3 × 52/3 = 52

Second Number will be = 4x = 4 × 52/3 = 208/3

Third Number will be = 5x = 5×52/3 = 260/3

_______________

Answer Verification

(the Sum of the largest and the smallest equals the sum of the third and 52)

➡3x + 5x = 5x + 52

Keep Value of x.

➡3 × 52/3 + 5 × 52/3 = 5 × 52/3 + 52

➡52 + 260/3 = 260 + 52

➡(156+260)/3 = (156 + 260)/3

➡416/3 = 416/3

L.H.S. = R.H.S.

___________________________________________________________

Discussion

38.	Nuri father age is 49 years old . he is 4 years older than three time Nuri age . what is the age of nuritell with full explanationnote:- (nasrgirl do not answer)
Answer» Answer: NURI is 15 years old Step-by-step EXPLANATION: LET 'a' be nuri's age 49 = 4 + 3a 45 = 3a a = 15 years. please RATE this answer! :D

38.

Nuri father age is 49 years old . he is 4 years older than three time Nuri age . what is the age of nuritell with full explanationnote:- (nasrgirl do not answer)

Answer»

Answer:

NURI is 15 years old

Step-by-step EXPLANATION:

LET 'a' be nuri's age

49 = 4 + 3a

45 = 3a

a = 15 years.

please RATE this answer! :D

Discussion

39.	a shot put is a metallic sphere of radius 4.9cm if density of the metal is 7.8g/cubic cm. find the mass of shot put
Answer» Given : A shot put is a metallic SPHERE of RADIUS 4.9cm if DENSITY of the metal is 7.8g/cubic cm. To Find : Mass of the shot put = ? SOLUTION : Radius of sphere = 4.9 cm Density = 7.8 g/cm³ Let's find the volume of sphere : → Volume of sphere = 4/3 πr³ → Volume of sphere = 4/3 × 22/7 × 4.9 × 4.9 × 4.9 → Volume of sphere = 4/3 × 22 × 0.7 × 4.9 × 4.9 → Volume of sphere = 4/3 × 22 × 16.8 → Volume of sphere = 1478.4 ÷ 3 → Volume of sphere = 492.8 cm³ Hence,the volume of sphere is 492.8 cm³. Finding the mass of the shot put : → Density = Mass ÷ Volume → Density × Volume = Mass → Mass = 7.8 × 492.8 → Mass = 3,843.84 g → Mass = 3.844 KG Hence,the mass of the shotput is 3.844 kg.

39.

a shot put is a metallic sphere of radius 4.9cm if density of the metal is 7.8g/cubic cm. find the mass of shot put

Answer»

Given :

A shot put is a metallic SPHERE of RADIUS 4.9cm if DENSITY of the metal is 7.8g/cubic cm.

To Find :

Mass of the shot put = ?

SOLUTION :

Radius of sphere = 4.9 cm
Density = 7.8 g/cm³

Let's find the volume of sphere :

→ Volume of sphere = 4/3 πr³

→ Volume of sphere = 4/3 × 22/7 × 4.9 × 4.9 × 4.9

→ Volume of sphere = 4/3 × 22 × 0.7 × 4.9 × 4.9

→ Volume of sphere = 4/3 × 22 × 16.8

→ Volume of sphere = 1478.4 ÷ 3

→ Volume of sphere = 492.8 cm³

Hence,the volume of sphere is 492.8 cm³.

Finding the mass of the shot put :

→ Density = Mass ÷ Volume

→ Density × Volume = Mass

→ Mass = 7.8 × 492.8

→ Mass = 3,843.84 g

→ Mass = 3.844 KG

Hence,the mass of the shotput is 3.844 kg.

Discussion

40.	How much fencing is required to fence a rectangular garden of length 17m and width 24m?
Answer» $\huge{ \underline{ \overline{ \mid{ \mathrm{ \purple{ \: \: SOLUTION \: \: } \mid}}}}}$ $\begin{gathered} \bold{ \underline{ \green{ Given, }}} \\ \\ \texttt{ Length of the rectangular garden, l = 17 m} \\ \texttt{Breadth of the rectangular garden, b = 24 m }\end{gathered}$ $\begin{gathered} \bold {\underline{ \blue{ \: To \: \: \: \: find :- } \: }} \\ \\ \: \: \: \: \: \: \: \: \sf{How \: \: much \: \: fencing \: \: is \: \: required \: \: to \: \: enclose \: \: } \\ \: \: \: \: \sf{the \: \: rectangular \: \: garden. }\end{gathered}$ $\begin{gathered} \underline{ \sf{ \blue{ \: \: We \: \: know \: \: that, \: \: }}} \\ \\ \boxed{ \pink{ \bold{Perimeter \: \: of \: \: a \: \: rectangle = 2 \times (Length + Breadth)}}}\end{gathered}$ $\bold{ \underline{ \purple{ \: According \: \: to \: \: question, \: }}}$ $\begin{gathered} \sf{Perimeter \: \: of \: \: the \: \: rectangular \: \: garden = 2 \times (l + b)} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{= \{2 \times (17 + 24) \} \: \: m } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{ = (2 \times 41) \: \: m} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{ = 82 \: \: m }\end{gathered}$ $\bold{ \therefore \: Perimeter \: \: of \: \: the \: \: rectangular \: \: garden = 82 \: \: m}$ $\begin{gathered} \: \: \: \: \: \: \: \: \: \texttt{Hence, \red{ \underline{82 metres}} of fencing is required to } \\ \texttt{enclose a rectangular garden of length 17 m and } \\ \texttt{breadth 24 m.}\end{gathered}$

40.

How much fencing is required to fence a rectangular garden of length 17m and width 24m?

Answer»

$\huge{ \underline{ \overline{ \mid{ \mathrm{ \purple{ \: \: SOLUTION \: \: } \mid}}}}}$

$\begin{gathered} \bold{ \underline{ \green{ Given, }}} \\ \\ \texttt{ Length of the rectangular garden, l = 17 m} \\ \texttt{Breadth of the rectangular garden, b = 24 m }\end{gathered}$

$\begin{gathered} \bold {\underline{ \blue{ \: To \: \: \: \: find :- } \: }} \\ \\ \: \: \: \: \: \: \: \: \sf{How \: \: much \: \: fencing \: \: is \: \: required \: \: to \: \: enclose \: \: } \\ \: \: \: \: \sf{the \: \: rectangular \: \: garden. }\end{gathered}$

$\begin{gathered} \underline{ \sf{ \blue{ \: \: We \: \: know \: \: that, \: \: }}} \\ \\ \boxed{ \pink{ \bold{Perimeter \: \: of \: \: a \: \: rectangle = 2 \times (Length + Breadth)}}}\end{gathered}$

$\bold{ \underline{ \purple{ \: According \: \: to \: \: question, \: }}}$

$\begin{gathered} \sf{Perimeter \: \: of \: \: the \: \: rectangular \: \: garden = 2 \times (l + b)} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{= \{2 \times (17 + 24) \} \: \: m } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{ = (2 \times 41) \: \: m} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{ = 82 \: \: m }\end{gathered}$

$\bold{ \therefore \: Perimeter \: \: of \: \: the \: \: rectangular \: \: garden = 82 \: \: m}$

$\begin{gathered} \: \: \: \: \: \: \: \: \: \texttt{Hence, \red{ \underline{82 metres}} of fencing is required to } \\ \texttt{enclose a rectangular garden of length 17 m and } \\ \texttt{breadth 24 m.}\end{gathered}$

Discussion

41.	Find the dimensions of a rectangel whoae area is x²+3x-54 cm²
Answer» Step-by-step EXPLANATION: THANK you so MUCH for the points Solution above

41.

Find the dimensions of a rectangel whoae area is x²+3x-54 cm²

Answer»

Step-by-step EXPLANATION:

THANK you so MUCH for the points

Solution above

Discussion

42.	A property decreases in value every year at the rate of 6 1/4% of its value at the beginning of the year its value at the end of 3 years was Rs.21093. Find its value at the beginning of the first year?
Answer» Answer: 1,002,062.25 Step-by-step EXPLANATION: FOLLOW me GUYS

42.

A property decreases in value every year at the rate of 6 1/4% of its value at the beginning of the year its value at the end of 3 years was Rs.21093. Find its value at the beginning of the first year?

Answer»

Answer:

1,002,062.25

Step-by-step EXPLANATION:

FOLLOW me GUYS

Discussion

43.	Solution of 4x + 3 < 6x+ 7, X ∈ R is
Answer» ANSWER: THEREFORE the value of X is (-2,INFINITY)

43.

Solution of 4x + 3 < 6x+ 7, X ∈ R is

Answer»

ANSWER:

THEREFORE the value of X is (-2,INFINITY)

Discussion

44.	Draw a Venn diagram of the given information in a hostel 165 students there are out which of 100 drink tea 80 drink coffee and 20 drink ang coffee booth
Answer» Step-by-step EXPLANATION: So, it LIES between 0.1 and 0.2. (d) Here, 0.66 is more than 0.6 but LESS than 0.7.

44.

Draw a Venn diagram of the given information in a hostel 165 students there are out which of 100 drink tea 80 drink coffee and 20 drink ang coffee booth

Answer»

Step-by-step EXPLANATION:

So, it LIES between 0.1 and 0.2. (d) Here, 0.66 is more than 0.6 but LESS than 0.7.

Discussion

45.	Convert 37 ° C into ° F
Answer» ANSWER: (37°C × 9/5) + 32 = 98.6°F

45.

Convert 37 ° C into ° F

Answer»

ANSWER:

(37°C × 9/5) + 32 = 98.6°F

Discussion

46.	B.Find the range of the given data: 23,38,21,36,42,39,37,36,48,37
Answer» Answer: 23+38+21+36+42+39+37+36+48+37 WHOLE upon 10 = 357 DIVIDED by 10 = Step-by-step explanation: 35.7

46.

B.Find the range of the given data: 23,38,21,36,42,39,37,36,48,37

Answer»

Answer:

23+38+21+36+42+39+37+36+48+37 WHOLE upon

10

= 357 DIVIDED by

10

=

Step-by-step explanation:

35.7

Discussion

47.	Show that y = x²-2x+3 represent a parabola also find the vertex.No spam pls.Explain properly
Answer» ANSWER: MARK as BRAINLIEST........

47.

Show that y = x²-2x+3 represent a parabola also find the vertex.No spam pls.Explain properly

Answer»

ANSWER:

MARK as BRAINLIEST........

Discussion

48.	Find the value of 32+log 35a)20b)30c)45
Answer» ANSWER: 20 hope this HELPS u pls follow me and mark my answer as brainliest

48.

Find the value of 32+log 35a)20b)30c)45

Answer»

ANSWER:

20

hope this HELPS u

pls follow me and mark my answer as brainliest

Discussion

49.	6. the number 45 is divisible by5 as well as 9O TrueO False
Answer» ANSWER: True. Step-by-step explanation: 45=59 45=95 Therefore, 45 DIVISIBLE by 5 and 9 .

49.

6. the number 45 is divisible by5 as well as 9O TrueO False

Answer»

ANSWER:

True.

Step-by-step explanation:

45=5*9

45=9*5

Therefore, 45 DIVISIBLE by 5 and 9 .

Discussion

50.	What is Sigma Notation?
Answer» $\huge\boxed{\texttt{\fcolorbox{black}{pink}{Answer}}}$ ★ SIGMA notation is a method used to WRITE out a long sum in a concise way. How to write stigma notation : A series can be represented in a compact FORM, called summation or sigma notation. The Greek capital letter, ∑ , is used to represent the sum. The series 4+8+12+16+20+24 can be expressed as 6∑n=14n . What does ∑ symbol mean : The ∑ symbol means sum. ∑ is the Greek capital sigma character. It is used commonly in algebraic functions, and you may also notice it in Excel - the AUTOSUM button has a sigma as its ICON.

50.

What is Sigma Notation?

Answer»

$\huge\boxed{\texttt{\fcolorbox{black}{pink}{Answer}}}$

★ SIGMA notation is a method used to WRITE out a long sum in a concise way.

How to write stigma notation :

A series can be represented in a compact FORM, called summation or sigma notation.

The Greek capital letter, ∑ , is used to represent the sum. The series 4+8+12+16+20+24 can be expressed as 6∑n=14n .

What does ∑ symbol mean :

The ∑ symbol means sum. ∑ is the Greek capital sigma character.

It is used commonly in algebraic functions, and you may also notice it in Excel - the AUTOSUM button has a sigma as its ICON.

Discussion

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Find the mode of below given dataclass 0-10 10-20 20-30 30 - 40 40 - 50 50 - 60 60 to 70 70 - 80 frequency 07 ,14, 13, 12, 20, 11 ,15, 8

DO THISFind the zeroes of the quadratic polynomials given below. Find the sum and productof the zeroes and verify relationship to the coefficients of terms in the polynomial.(1) p(x) = x - x - 6 (ii) p(x) = x2 - 4x + 3(111) p(x) = x2-4(iv) p(x) = x2 + 2x + 1

Convert the rational numbers into decimal form a.1/2

Nuri father age is 49 years old . he is 4 years older than three time Nuri age . what is the age of nuritell with full explanationnote:- (nasrgirl do not answer)

a shot put is a metallic sphere of radius 4.9cm if density of the metal is 7.8g/cubic cm. find the mass of shot put

How much fencing is required to fence a rectangular garden of length 17m and width 24m?

Find the dimensions of a rectangel whoae area is x²+3x-54 cm²

A property decreases in value every year at the rate of 6 1/4% of its value at the beginning of the year its value at the end of 3 years was Rs.21093. Find its value at the beginning of the first year?

Solution of 4x + 3 < 6x+ 7, X ∈ R is

Draw a Venn diagram of the given information in a hostel 165 students there are out which of 100 drink tea 80 drink coffee and 20 drink ang coffee booth

Convert 37 ° C into ° F

B.Find the range of the given data: 23,38,21,36,42,39,37,36,48,37

Show that y = x²-2x+3 represent a parabola also find the vertex.No spam pls.Explain properly

Find the value of 32+log 35a)20b)30c)45

6. the number 45 is divisible by5 as well as 9O TrueO False

What is Sigma Notation?