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X= rcosθ , Y= rsinθ then [∂y/∂r]x [∂y/∂r] θ |
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Answer» Solution Given :- Three numbers are in the RATIO 3:4:5 the SUM of the largest and the smallest equals the sum of the third and 52 Find :- These Number . Explanation Let, Number be First Number be = 3X Second Number be = 4X Third Number be = 5x Then, According to question, ➡ 3x + 5x = 5x + 52 ➡8x = 5x + 52 ➡8x - 5x = 52 ➡3x = 52 ➡x = 52/3 Hence First Number will be = 3x = 3 × 52/3 = 52 Second Number will be = 4x = 4 × 52/3 = 208/3 Third Number will be = 5x = 5×52/3 = 260/3 _______________ Answer Verification (the Sum of the largest and the smallest equals the sum of the third and 52) ➡3x + 5x = 5x + 52 Keep Value of x. ➡3 × 52/3 + 5 × 52/3 = 5 × 52/3 + 52 ➡52 + 260/3 = 260 + 52 ➡(156+260)/3 = (156 + 260)/3 ➡416/3 = 416/3 L.H.S. = R.H.S. ___________________________________________________________ |
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