332354 + Interview Questions in Secondary School in Math

1.	Write the digit at the unit place in each of the following square number 625
Answer» ANSWER: and then we have been TRYING, but it

1.

Write the digit at the unit place in each of the following square number 625

Answer»

ANSWER:

and then we have been TRYING, but it

Discussion

2.	Find two different 2×2 marices A such that A²=I
Answer» Answer: 2×2=4 it's also a 2 square = 4 A square is a×a Step-by-step EXPLANATION: HOPE it helps you MATE

2.

Find two different 2×2 marices A such that A²=I

Answer»

Answer:

2×2=4

it's also a 2 square = 4

A square is a×a

Step-by-step EXPLANATION:

HOPE it helps you MATE

Discussion

3.	Find the mean height and median weight of your family members. ( Minimum 3Imembers)
Answer» Step-by-step EXPLANATION: $\huge\star\underbrace{\mathtt\red{⫷❥ᴀ᭄} \mathtt\green{n~ }\mathtt\blue{ §} \mathtt\purple{₩}\mathtt\orange{Σ} \mathtt\pink{R⫸}}\star\:⋆$ ${\mathbb{\colorbox {orange} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {lime} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {aqua} {Glad to help}}}}}}}}}}}}}}}$ $\huge\blue{\boxed{\blue{ \bold{\fcolorbox{red}{black}{\green{Hope\:It\:Helps!}}}}}}$

3.

Find the mean height and median weight of your family members. ( Minimum 3Imembers)

Answer»

Step-by-step EXPLANATION:

$\huge\star\underbrace{\mathtt\red{⫷❥ᴀ᭄} \mathtt\green{n~ }\mathtt\blue{ §} \mathtt\purple{₩}\mathtt\orange{Σ} \mathtt\pink{R⫸}}\star\:⋆$

${\mathbb{\colorbox {orange} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {lime} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {aqua} {Glad to help}}}}}}}}}}}}}}}$

$\huge\blue{\boxed{\blue{ \bold{\fcolorbox{red}{black}{\green{Hope\:It\:Helps!}}}}}}$

Discussion

4.	Class-X Mathematics1-COSShow that (cosec 0 - cot )21+cosटीटा
Answer» ANSWER: SORRY but i don't KNOW the answer for this QUESTION.

4.

Class-X Mathematics1-COSShow that (cosec 0 - cot )21+cosटीटा

Answer»

ANSWER:

SORRY but i don't KNOW the answer for this QUESTION.

Discussion

5.	Alegbra of an arithmetic sequence is 51–6n,what is its 8th term
Answer» Answer: 8 th term is 3 Step-by-step EXPLANATION: arithmetic SEQUENCE is 51-6n putting the VALUE n=8,we get 8 th term 8th term =51-6×8=51-48=3

5.

Alegbra of an arithmetic sequence is 51–6n,what is its 8th term

Answer»

Answer:

8 th term is 3

Step-by-step EXPLANATION:

arithmetic SEQUENCE is 51-6n

putting the VALUE n=8,we get 8 th term

8th term =51-6×8=51-48=3

Discussion

6.	Find the value of 4sin
Answer» DATA GIVEN :- 4 tan ∅ = 3 To FIND :- 4sin∅ - cos∅ / 4sin∅ + cos∅ solution will be , The value of tan∅ = ¾ tan ∅ = sin∅ / cos ∅ The value of 4sin∅ - cos∅ / 4sin∅ + cos∅ = ½ see the *answer* in attachment :)

6.

Find the value of 4sin

Answer»

DATA GIVEN :- 4 tan ∅ = 3

To FIND :- 4sin∅ - cos∅ / 4sin∅ + cos∅

solution will be ,

The value of tan∅ = ¾

tan ∅ = sin∅ / cos ∅

The value of 4sin∅ - cos∅ / 4sin∅ + cos∅ = ½

see the answer in attachment :)

Discussion

7.	Which is of blue colour
Answer» WDYM ????????????????????

Discussion

8.	In board examination of class 9 , 50•/• passed in english 30•/• failed in both subject find the total number of student.
Answer» Answer: 70% because total number of students PASSED in ENGLISH =50%and failed =30% 50%+30%=70% Step-by-step EXPLANATION:

8.

In board examination of class 9 , 50•/• passed in english 30•/• failed in both subject find the total number of student.

Answer»

Answer:

70% because

total number of students PASSED in ENGLISH =50%and

failed =30%

50%+30%=70%

Step-by-step EXPLANATION:

Discussion

9.	2.f (x) = 8 - 3xg (x) = 10/(x – 1), x is not -1h (x) = 2^xFind(a) hf (8/3)
Answer» ANSWER: PLEASE MARK me BRAINLIEST answer

9.

2.f (x) = 8 - 3xg (x) = 10/(x – 1), x is not -1h (x) = 2^xFind(a) hf (8/3)

Answer»

ANSWER:

PLEASE MARK me BRAINLIEST answer

Discussion

10.	2500 sq. meterstheareaof a play groundwhat is the length of each side
Answer» ANSWER: LENGTH of each side of PLAYGROUND is 50 METRE.

10.

2500 sq. meterstheareaof a play groundwhat is the length of each side

Answer»

ANSWER:

LENGTH of each side of PLAYGROUND is 50 METRE.

Discussion

11.	find the smallest whole number by which each of following number must be multiplied to obtain perfect cube (1)49
Answer» Answer: 392=2×2×2×7×7 7 OCCURS as a PRIME FACTOR only twice. Hence, 7 is the smallest number by which 392 MUST be multiplied so that the PRODUCT is a perfect cube. Step-by-step explanation:

11.

find the smallest whole number by which each of following number must be multiplied to obtain perfect cube (1)49

Answer»

Answer:

392=2×2×2×7×7

7 OCCURS as a PRIME FACTOR only twice.

Hence, 7 is the smallest number by which 392 MUST be multiplied so that the PRODUCT is a perfect cube.

Step-by-step explanation:

Discussion

12.	13,74,290 650,...... ............
Answer» The following numbers are SUM of SQUARES of prime numbers. ( starting from smallest prime number ) First eight prime numbers are: 2, 3, 5, 7, 11, 13, 17, 19 2² + 3³ = 4 + 9 = 13 5² + 7² = 25 + 49 = 74 11² + 13² = 121 + 169 = 290 17² + 19² = 289 + 361 = 650 Next two prime numbers are 23 and 29 23² + 29² = 529 + 841 = 1370 The next number in the series is 1370 13, 74, 290, 650, 1370

12.

13,74,290 650,...... ............

Answer»

The following numbers are SUM of SQUARES of prime numbers. ( starting from smallest prime number )

First eight prime numbers are: 2, 3, 5, 7, 11, 13, 17, 19

2² + 3³ = 4 + 9 = 13
5² + 7² = 25 + 49 = 74
11² + 13² = 121 + 169 = 290
17² + 19² = 289 + 361 = 650

Next two prime numbers are 23 and 29

23² + 29² = 529 + 841 = 1370

The next number in the series is 1370

13, 74, 290, 650, 1370

Discussion

13.	Find 11/15 of Rs.60
Answer» 11/15*60=660/15=44 Mark me as BRAINLIEST

Discussion

14.	Each interior angle of a regular polygon is double of its exterior angle. Find thenumber of sides in the polygon.of
Answer» Answer: ANSWER Let the number of SIDES in the POLYGON is n Let the measure of EXTERIOR ANGLES be x respectively. ⇒ measure of interior angle =2x ∴n×2x=(2n−4)×90° ⇒nx=(n−2)×90°.....(i) Again, we KNOW that, nx=360° (n−2)×90°=360°[From(i)] n−2=4 ⇒n=6 Hence the number of sides in the polygon are 6. this is your answer

14.

Each interior angle of a regular polygon is double of its exterior angle. Find thenumber of sides in the polygon.of

Answer»

Answer:

ANSWER

Let the number of SIDES in the POLYGON is n

Let the measure of EXTERIOR ANGLES be x respectively.

⇒ measure of interior angle =2x

∴n×2x=(2n−4)×90°

⇒nx=(n−2)×90°.....(i)

Again, we KNOW that,

nx=360°

(n−2)×90°=360°[From(i)]

n−2=4

⇒n=6

Hence the number of sides in the polygon are 6.

this is your answer

Discussion

15.	3 and 4which of the following is LCM of numbers
Answer» Answer: LEAST COMMON MULTIPLE (LCM) of 3 and 4 is 12.

15.

3 and 4which of the following is LCM of numbers

Answer»

Answer:

LEAST COMMON MULTIPLE (LCM) of 3 and 4 is 12.

Discussion

16.	8. The top surface of a table has the shape of a trapezium. The parallel sides of the trapezium are 85and 63 cm and perpendicular distance between these sides is 36 cm. Calculate its area and find thecost of polishing the surface at the rate of 0.50 per cm?
Answer» (Diagram is GIVEN in attachment) Given: AB = 85 cm CD = 63 cm DE = 36 cm Cost of polishing = ₹0.50 per cm² To FIND: Area = ? Cost of polishing = ? Method: $\sf{Area \: of \: Trapezium = \dfrac{1}{2} \times (Base_1 + Base_2) \times Height}\\$ $\longrightarrow \: \sf{Area \: of\: trapezium = \dfrac{1}{2} \times (AB + BC) \times DE}\\$ $\longrightarrow \: \sf{Area\: of\: trapezium= \dfrac{1}{2} \times (85+63) \times 36}\\$ $\longrightarrow \: \sf{Area\:of\:Trapezium= 18(85+63)}\\\\\\\longrightarrow \: \sf{Area\:of\:Trapezium=18(148)}\\\\\\\longrightarrow \: \large{\bf{\underline{Area\: of\: Trapezium = 2664~ cm^{2}}}}\\$ $\rm{Now \: for \: finding\: the\: cost\: of \: polishing,}\\\\$ $\sf{1\:cm^{2} = Rs \:0.50}\\\\\\\sf{For\: 2664 \: cm^{2},}\\\\\sf{2664 \times 0.50}\\\\= \large{\boxed{\bf{Rs\: 1332}}}$ THEREFORE, total cost of polishing = ₹ 1332

16.

8. The top surface of a table has the shape of a trapezium. The parallel sides of the trapezium are 85and 63 cm and perpendicular distance between these sides is 36 cm. Calculate its area and find thecost of polishing the surface at the rate of 0.50 per cm?

Answer»

(Diagram is GIVEN in attachment)

Given:

AB = 85 cm
CD = 63 cm
DE = 36 cm
Cost of polishing = ₹0.50 per cm²

To FIND:

Area = ?
Cost of polishing = ?

Method:

$\sf{Area \: of \: Trapezium = \dfrac{1}{2} \times (Base_1 + Base_2) \times Height}\\$

$\longrightarrow \: \sf{Area \: of\: trapezium = \dfrac{1}{2} \times (AB + BC) \times DE}\\$

$\longrightarrow \: \sf{Area\: of\: trapezium= \dfrac{1}{2} \times (85+63) \times 36}\\$

$\longrightarrow \: \sf{Area\:of\:Trapezium= 18(85+63)}\\\\\\\longrightarrow \: \sf{Area\:of\:Trapezium=18(148)}\\\\\\\longrightarrow \: \large{\bf{\underline{Area\: of\: Trapezium = 2664~ cm^{2}}}}\\$

$\rm{Now \: for \: finding\: the\: cost\: of \: polishing,}\\\\$

$\sf{1\:cm^{2} = Rs \:0.50}\\\\\\\sf{For\: 2664 \: cm^{2},}\\\\\sf{2664 \times 0.50}\\\\= \large{\boxed{\bf{Rs\: 1332}}}$

THEREFORE, total cost of polishing = ₹ 1332

Discussion

17.	If the edge of a cube is doubled find the percentage increase in the surface area?
Answer» Answer: There's an INCREASE of 18s^2, which is THREE TIMES 6s^2. Therefore, there is a 300% increase in the TOTAL surface area.

17.

If the edge of a cube is doubled find the percentage increase in the surface area?

Answer»

Answer:

There's an INCREASE of 18s^2, which is THREE TIMES 6s^2. Therefore, there is a 300% increase in the TOTAL surface area.

Discussion

18.	If (x _1)power 3 =8 what is the value of ( x +1)power 2
Answer» ANSWER: HOPE this answer will HELP you

18.

If (x _1)power 3 =8 what is the value of ( x +1)power 2

Answer»

ANSWER:

HOPE this answer will HELP you

Discussion

19.	Find the H.C.F. of 21x’y? and 35x>ys.
Answer» Step-by-step EXPLANATION: THANKS for the FREE POINTS

19.

Find the H.C.F. of 21x’y? and 35x>ys.

Answer»

Step-by-step EXPLANATION:

THANKS for the FREE POINTS

Discussion

20.	What are the differences between the above two frequency distribution tables
Answer» Answer: you haven't ADDED the FIGURE if you could at the figure then it WOULD be possible to answer

20.

What are the differences between the above two frequency distribution tables

Answer»

Answer:

you haven't ADDED the FIGURE

if you could at the figure then it WOULD be possible to answer

Discussion

21.	Find angler in each figure:407(1)
Answer» ANSWER: where is FIGURE are H FORGET to SEND figure

21.

Find angler in each figure:407(1)

Answer»

ANSWER:

where is FIGURE are H FORGET to SEND figure

Discussion

22.	SIf x=2/5 y= 3/2Find (x+y) = (x-y)
Answer» ANSWER: -19/11 Step-by-step EXPLANATION: (2/5+3/2)=(2/5-3/2) (2×2/5×2+3×5/2×5)=(2×2/5×2-3×5/2×5) 4/10+15/10=4/10-15/10 19/10= -11/10 -190/110 -19/11

22.

SIf x=2/5 y= 3/2Find (x+y) = (x-y)

Answer»

ANSWER:

-19/11

Step-by-step EXPLANATION:

(2/5+3/2)=(2/5-3/2)

(2×2/5×2+3×5/2×5)=(2×2/5×2-3×5/2×5)

4/10+15/10=4/10-15/10

19/10= -11/10

-190/110

-19/11

Discussion

23.	R₁ = 4 R₂ = 3 R₃ = 6 are connected in parallel the effective resistance (1/RP) is ....
Answer» S O L U T I O N : Given, Three resistors R₁ = 4, R₂ = 3, R₃ = 6 are connected in parallel. To Find, EFFECTIVE RESISTANCE. Explanation, We know that, 1/Rp = 1/R₁ + 1/R₂ + 1/R₃ [ Put the values ] => 1/Rp = 1/4 + 1/3 + 1/6 => 1/Rp = 3 + 4 + 2 / 12 => 1/Rp = 9/12 => 1/Rp = 0.75 ohm Therefore, The effective resistance is 0.75 ohm. For information, Rs = R₁ + R₂ + R₃,..... V = IR H = I²Rt I = Q/t V = W/Q

23.

R₁ = 4 R₂ = 3 R₃ = 6 are connected in parallel the effective resistance (1/RP) is ....

Answer»

S O L U T I O N :

Given,

Three resistors R₁ = 4, R₂ = 3, R₃ = 6 are connected in parallel.

To Find,

EFFECTIVE RESISTANCE.

Explanation,

We know that,

1/Rp = 1/R₁ + 1/R₂ + 1/R₃

[ Put the values ]

=> 1/Rp = 1/4 + 1/3 + 1/6

=> 1/Rp = 3 + 4 + 2 / 12

=> 1/Rp = 9/12

=> 1/Rp = 0.75 ohm

Therefore,

The effective resistance is 0.75 ohm.

For information,

Rs = R₁ + R₂ + R₃,.....
V = IR
H = I²Rt
I = Q/t
V = W/Q

Discussion

24.	IOW.aActivity I : In the adjoining figure, seg DE isa chord of a circle with centre C.20 cmTCseg CF I seg DE. If diameter of theDIGEEcircle is 20 cm, DE = 16find CF.Fig. 3.1Recall and write theorems and properties which are useful to find the solutionof the above problem.(1) The perpendicular drawn from centre to a chord(2)(3)Using these properties, solve the above problem.
Answer» ANSWER: problem tha is the DAY Bhai is not your best man and he will be HAPPY 3

24.

IOW.aActivity I : In the adjoining figure, seg DE isa chord of a circle with centre C.20 cmTCseg CF I seg DE. If diameter of theDIGEEcircle is 20 cm, DE = 16find CF.Fig. 3.1Recall and write theorems and properties which are useful to find the solutionof the above problem.(1) The perpendicular drawn from centre to a chord(2)(3)Using these properties, solve the above problem.

Answer»

ANSWER:

problem tha is the DAY Bhai is not your best man and he will be HAPPY 3

Discussion

25.	First square number is ___________
Answer» 1 as 1²=1 hope you UNDERSTAND

25.

First square number is ___________

Answer»

1 as 1²=1

hope you UNDERSTAND

Discussion

26.	5. Area of a right angle triangle = x base X –(b) Choose the correct answer:6.7.If 49x² – b= (7x+1/2)(7x-1/2), then(a) O (b) 1/V2 (c) 1/4 (d)1/2Point (-3,5) lies in the(a) First quadrant (b) second quadrant (c) thirdIf (2,0) is a solution of the linear equation 2x+3y=k(a) 4 (b) 6 (c) 5 (d) 2of the8.thesb
Answer» Answer: 5. AREA of a right angle TRIANGLE = X base X –(b) CHOOSE the correct answer:6.7.If 49x² – b= (7x+1 Step-by-step explanation: 5. Area of a right angle triangle = x base X –(b) Choose the correct answer:6.7.If 49x² – b= (7x+1

26.

5. Area of a right angle triangle = x base X –(b) Choose the correct answer:6.7.If 49x² – b= (7x+1/2)(7x-1/2), then(a) O (b) 1/V2 (c) 1/4 (d)1/2Point (-3,5) lies in the(a) First quadrant (b) second quadrant (c) thirdIf (2,0) is a solution of the linear equation 2x+3y=k(a) 4 (b) 6 (c) 5 (d) 2of the8.thesb

Answer»

Answer:

5. AREA of a right angle TRIANGLE = X base X –(b) CHOOSE the correct answer:6.7.If 49x² – b= (7x+1

Step-by-step explanation:

5. Area of a right angle triangle = x base X –(b) Choose the correct answer:6.7.If 49x² – b= (7x+1

Discussion

27.	15. In the figure, the chords AB and CD are produced to meet at P. PA = 9 cm, AB = 6 cm, CD = 6 cma) What is PA X PB?b) What is length of PD?
Answer» ANSWER: B) 3cm Step-by-step EXPLANATION: I HOPE this answer is CORRECT

27.

15. In the figure, the chords AB and CD are produced to meet at P. PA = 9 cm, AB = 6 cm, CD = 6 cma) What is PA X PB?b) What is length of PD?

Answer»

ANSWER:

B) 3cm

Step-by-step EXPLANATION:

I HOPE this answer is CORRECT

Discussion

28.	How many slanting lines in triangle
Answer» Answer: 3 Step-by-step EXPLANATION:

28.

How many slanting lines in triangle

Answer»

Answer:

3

Step-by-step EXPLANATION:

Discussion

29.	Condition for three numbers a, b, c to be in A.P is
Answer» ANSWER: CONDITION for THREE numbers a,B,c to be in A.P. is b-a=c-b

29.

Condition for three numbers a, b, c to be in A.P is

Answer»

ANSWER:

CONDITION for THREE numbers a,B,c to be in A.P. is

b-a=c-b

Discussion

30.	Please write the answer of question 7
Answer» PLEASE MARK my ANSWER BRAINLIEST ...if it HELPS you...

30.

Please write the answer of question 7

Answer»

PLEASE MARK my ANSWER BRAINLIEST ...if it HELPS you...

Discussion

31.	VVICI15 UIVisible by 2.Hence, n? - n is divisible by 2 for every posiinteger n.Hence Prove7. Find HCF of 81 and 237 and express it as a lincombination of 81 and 237 i.e., HCF (81, 237) =+ 237y for some x and y.A [Board Term-I, 2012, Set-
Answer» Question 1 : If n is divisible by 2 , then prove that n²- n is divisible by 2 . Proof : Given that , n is divisible by 2 . Thus let n = 2m , m € Z . Now , → n² - n = (2m)² - 2m → n² - n = 4m² - 2m → n² - n = 2m(2m - 1) → n² - n = 2p , p = m(2m - 1) € N (divisible by 2) Clearly , If n is divisible by 2 , then n² - n is also divisible by 2 . Hence proved . Question 2 : Find HCF of 81 and 237 and express it as a linear combination of 81 and 237 i.e., HCF (81, 237) = 81x + 237y for some x and y. Solution : Let's find the HCF of 81 and 237 by LONG division METHOD . $\sf 81) \overline{ \: \: \: 237 \: \:}(2 \\ \sf \dfrac{162 }{ \: \: \: \: \: \: \: \: 75) \: 81\:(1 }\\ \quad \: \: \sf \dfrac{\:\:\:\:\:\:\:\:\:\:75}{ \: \: \: \: \: \: 6) \: \: 15 \: \: (12} \\ \sf {\quad\:\: }\dfrac{12}{3) \: \: \: 6 \: \: (2} \\ {\:\:\:\: \qquad} \sf \dfrac{6}{ <klux>0</klux>}$ Clearly , HCF (81, 237) = 3 Also , From the division , we have ; • 237 = 2×81 + 75 -----(1) • 81 = 1×75 + 6 ------(2) • 75 = 12×6 + 3 ------(3) • 6 = 2×3 + 0 ------(4) Now , → HCF(81,237) = 3 → HCF(81,237) = 75 - 12×6 → HCF(81,237) = 75 - 12×(81 - 1×75) → HCF(81,237) = 75 - 12×81 + 12×75 → HCF(81,237) = -12×81 + 13×75 → HCF(81,237) = -12×81 + 13×(237 - 2×81) → HCF(81,237) = -12×81 + 13×237 - 26×81 → HCF(81,237) = -38×81 + 13×237 → HCF(81,237) = 81×(-38) + 237×(13) Clearly , HCF (81, 237) = 81×(-38) + 237×(13) is of the form (81x + 237y) , where x = -38 and y = 13 .

31.

VVICI15 UIVisible by 2.Hence, n? - n is divisible by 2 for every posiinteger n.Hence Prove7. Find HCF of 81 and 237 and express it as a lincombination of 81 and 237 i.e., HCF (81, 237) =+ 237y for some x and y.A [Board Term-I, 2012, Set-

Answer»

Question 1 :

If n is divisible by 2 , then prove that n²- n is divisible by 2 .

Proof :

Given that , n is divisible by 2 .

Thus let n = 2m , m € Z .

Now ,

→ n² - n = (2m)² - 2m

→ n² - n = 4m² - 2m

→ n² - n = 2m(2m - 1)

→ n² - n = 2p , p = m(2m - 1) € N

(divisible by 2)

Clearly ,

If n is divisible by 2 , then n² - n is also divisible by 2 .

Hence proved .

Question 2 :

Find HCF of 81 and 237 and express it as a linear combination of 81 and 237 i.e., HCF (81, 237) = 81x + 237y for some x and y.

Solution :

Let's find the HCF of 81 and 237 by LONG division METHOD .

$\sf 81) \overline{ \: \: \: 237 \: \:}(2 \\ \sf \dfrac{162 }{ \: \: \: \: \: \: \: \: 75) \: 81\:(1 }\\ \quad \: \: \sf \dfrac{\:\:\:\:\:\:\:\:\:\:75}{ \: \: \: \: \: \: 6) \: \: 15 \: \: (12} \\ \sf {\quad\:\: }\dfrac{12}{3) \: \: \: 6 \: \: (2} \\ {\:\:\:\: \qquad} \sf \dfrac{6}{ <klux>0</klux>}$

Clearly ,

HCF (81, 237) = 3

Also ,

From the division , we have ;

• 237 = 2×81 + 75 -----(1)

• 81 = 1×75 + 6 ------(2)

• 75 = 12×6 + 3 ------(3)

• 6 = 2×3 + 0 ------(4)

Now ,

→ HCF(81,237) = 3

→ HCF(81,237) = 75 - 12×6

→ HCF(81,237) = 75 - 12×(81 - 1×75)

→ HCF(81,237) = 75 - 12×81 + 12×75

→ HCF(81,237) = -12×81 + 13×75

→ HCF(81,237) = -12×81 + 13×(237 - 2×81)

→ HCF(81,237) = -12×81 + 13×237 - 26×81

→ HCF(81,237) = -38×81 + 13×237

→ HCF(81,237) = 81×(-38) + 237×(13)

Clearly ,

HCF (81, 237) = 81×(-38) + 237×(13) is of the form (81x + 237y) , where x = -38 and y = 13 .

Discussion

32.	Cise 6.6the following:37the following:XOlos.(ii40x 280(i7
Answer» PLEASE MARK me BRAINLIEST ANSWER

32.

Cise 6.6the following:37the following:XOlos.(ii40x 280(i7

Answer»

PLEASE MARK me BRAINLIEST ANSWER

Discussion

33.	The sides AB and AC of∆ABC have been produced to D and E respectively.The bisectors of angle CBD and angle BCE meet at O.If angle A =40° find angle BOC
Answer» ANSWER: FOLLOW me for FREE POINTS.

33.

The sides AB and AC of∆ABC have been produced to D and E respectively.The bisectors of angle CBD and angle BCE meet at O.If angle A =40° find angle BOC

Answer»

ANSWER:

FOLLOW me for FREE POINTS.

Discussion

34.	A Potter makes flowerpots .ifthe weight of one flowerpots is 9.750 kg ,then find the weight of 25 flowerpots.
Answer» Answer: Weight of one FLOWERPOT = 9.750 kg Weight of 25 FLOWERPOTS = 9.750 × 25 kg = 243.75 kg Ans 243.75 kg

34.

A Potter makes flowerpots .ifthe weight of one flowerpots is 9.750 kg ,then find the weight of 25 flowerpots.

Answer»

Answer:

Weight of one FLOWERPOT = 9.750 kg

Weight of 25 FLOWERPOTS = 9.750 × 25 kg

= 243.75 kg

Ans 243.75 kg

Discussion

35.	Volume of a cone =_________
Answer» Answer: 1/3πr3 Step-by-step EXPLANATION: PLEASE FOLLOW me

35.

Volume of a cone =_________

Answer»

Answer:

1/3πr3

Step-by-step EXPLANATION:

PLEASE FOLLOW me

Discussion

36.	A 115m long and 64m broad lawn has two crossroad at right angles, one 2m wide, running parallel to it's length and the other 2.5m wide, running parallel to it's breath. Find the cost of the road at ₹ 4.60 per m rase power 2
Answer» Step-by-step explanation: Hey! $\mathfrak \red{\large \: Answer:-}$ According to Thomson€™s model of the ATOM, an atom consists of both negatively and positively charged particles. ... The negatively charged particles are embedded in the positively charged sphere. These negative and positive charges are equal in magnitude. Atoms are electrically NEUTRAL because they have equal numbers of protons (positively charged) and electrons (negatively charged). If an atom GAINS or loses one or more electrons, it becomes an ion. Thomson knew that atoms had an overall neutral charge. THEREFORE, he reasoned that there must be a source of positive charge within the atom to COUNTERBALANCE the negative charge on the electrons. ... The plum pudding model depicts the electrons as negatively-charged particles embedded in a sea of positive charge.

36.

A 115m long and 64m broad lawn has two crossroad at right angles, one 2m wide, running parallel to it's length and the other 2.5m wide, running parallel to it's breath. Find the cost of the road at ₹ 4.60 per m rase power 2

Answer»

Step-by-step explanation:

Hey!

$\mathfrak \red{\large \: Answer:-}$

According to Thomson€™s model of the ATOM, an atom consists of both negatively and positively charged particles. ... The negatively charged particles are embedded in the positively charged sphere. These negative and positive charges are equal in magnitude.

Atoms are electrically NEUTRAL because they have equal numbers of protons (positively charged) and electrons (negatively charged). If an atom GAINS or loses one or more electrons, it becomes an ion.

Thomson knew that atoms had an overall neutral charge. THEREFORE, he reasoned that there must be a source of positive charge within the atom to COUNTERBALANCE the negative charge on the electrons. ... The plum pudding model depicts the electrons as negatively-charged particles embedded in a sea of positive charge.

Discussion

37.	How many persons weight is more that 80kg?how many persons weight is less that 60kg?
Answer» ANSWER: I) 7 persons II) 8,19 Step-by-step EXPLANATION: this is the answer

37.

How many persons weight is more that 80kg?how many persons weight is less that 60kg?

Answer»

ANSWER:

I) 7 persons

II) 8,19

Step-by-step EXPLANATION:

this is the answer

Discussion

38.	The perimeter of a rectangular playground is 256 meters and its length is 74 meters. What is its area?
Answer» Answer: 2(l+b) =256 l+b=256/2 74+b=128 b=128-74 b= 54 area= l×b =74×54 =3996

38.

The perimeter of a rectangular playground is 256 meters and its length is 74 meters. What is its area?

Answer»

Answer:

2(l+b) =256

l+b=256/2

74+b=128

b=128-74

b= 54

area= l×b

=74×54

=3996

Discussion

39.	If n is a positive integer, what is the remainder when 3^(8n+3) + 2 is divided by 5?
Answer» ANSWER: fho-bhhx-mjn jóín the MEETING for ENGLISH CLASSS

39.

If n is a positive integer, what is the remainder when 3^(8n+3) + 2 is divided by 5?

Answer»

ANSWER:

fho-bhhx-mjn

jóín the MEETING for ENGLISH CLASSS

Discussion

40.	by using variables x and y form any 2 linear equations in two variables write 2 solutions of the equation x+y=7
Answer» Answer: We are to construct TWO linear EQUATION with two variables x and y. They are, x+y=3 and 2x−3y=5. Step-by-step EXPLANATION: I hope it's help you please FOLLOW me and mark as brainlist

40.

by using variables x and y form any 2 linear equations in two variables write 2 solutions of the equation x+y=7

Answer»

Answer:

We are to construct TWO linear EQUATION with two variables x and y.

They are,

x+y=3 and 2x−3y=5.

Step-by-step EXPLANATION:

I hope it's help you

please FOLLOW me and mark as brainlist

Discussion

41.	Isosad) Check whether the following fractions are equivalent and find one more equivalentfraction for them:12 22and18 3313e) Write25as a decimal.f) Find the HCF of 24, 60, and 120.18 44g) Convert the following into a mixed fraction:and10 6h) Plot 6.4 on a number line.3. Answer the following questions. Each question carries 4 marks. (16 marks)a) The following are the temperatures of some cities on a particular day. Answer thequestions given below.CityLehDelhiShimlaTemperature-25°C10°C-4°C(i) Which is the coldest place?(ii) What is the temperature difference between Delhi and Leh?(iii) How much warmer is Shimla compared to Leh?
Answer» ANSWER: ghhhdhdhdh 3says 63636363yy4y4

41.

Isosad) Check whether the following fractions are equivalent and find one more equivalentfraction for them:12 22and18 3313e) Write25as a decimal.f) Find the HCF of 24, 60, and 120.18 44g) Convert the following into a mixed fraction:and10 6h) Plot 6.4 on a number line.3. Answer the following questions. Each question carries 4 marks. (16 marks)a) The following are the temperatures of some cities on a particular day. Answer thequestions given below.CityLehDelhiShimlaTemperature-25°C10°C-4°C(i) Which is the coldest place?(ii) What is the temperature difference between Delhi and Leh?(iii) How much warmer is Shimla compared to Leh?

Answer»

ANSWER:

ghhhdhdhdh 3says 63636363yy4y4

Discussion

42.	Q5. Find the 25% of 800.
Answer» Answer: 25/100 *800 = 200 .........

42.

Q5. Find the 25% of 800.

Answer»

Answer:

25/100 *800

= 200

.........

Discussion

43.	The floor of a building consists of 400 tiles which are rhombus shaped and each of it diagonals are 45cm and 30cm in length. Find the total cost of polishing the floor if the cost per m2 is ` ₹ 10
Answer» DIAGONALS of the RHOMBUS:- D1 = 45 D2 = 30 Using FORMULA.: Are of Rhombus = 1/2 × D1 × D2 Area of 1 Rhombus :- = $\frac{1}{2}$ × 45 × 30 = 45 × 15 Area of 1 Rhombus= 675cm² Area of Floor : = 400 × 675 = 2,70,000 cm² So, Cost of Polishing the floor: = 2,70,000 × 10 = 27,00,000 rs

43.

The floor of a building consists of 400 tiles which are rhombus shaped and each of it diagonals are 45cm and 30cm in length. Find the total cost of polishing the floor if the cost per m2 is ` ₹ 10

Answer»

DIAGONALS of the RHOMBUS:-

D1 = 45

D2 = 30

Using FORMULA.:

Are of Rhombus = 1/2 × D1 × D2

Area of 1 Rhombus :-

= $\frac{1}{2}$ × 45 × 30

= 45 × 15

Area of 1 Rhombus= 675cm²

Area of Floor :

= 400 × 675

= 2,70,000 cm²

So, Cost of Polishing the floor:

= 2,70,000 × 10

= 27,00,000 rs

Discussion

44.	Wat will be happen the consequences if such an event as the Tunguska event were to occur today
Answer» Answer: The Tunguska EVENT was a MASSIVE explosion that OCCURRED near the Podkamennaya Tunguska River in Yeniseysk GOVERNORATE (now Krasnoyarsk Krai), Russia, on the morning of 30 June 1908 (NS).[1][2] The explosion over the sparsely populated Eastern Siberian Taiga flattened an estimated 80 million trees over an area of 2,150 km2 (830 sq mi) of forest, and eyewitness reports suggest that at least THREE people may have died in the event.[3][4][5][6][7] The explosion is generally attributed to the air burst of a stony meteoroid about 100 metres (330 feet) in size

44.

Wat will be happen the consequences if such an event as the Tunguska event were to occur today

Answer»

Answer:

The Tunguska EVENT was a MASSIVE explosion that OCCURRED near the Podkamennaya Tunguska River in Yeniseysk GOVERNORATE (now Krasnoyarsk Krai), Russia, on the morning of 30 June 1908 (NS).[1][2] The explosion over the sparsely populated Eastern Siberian Taiga flattened an estimated 80 million trees over an area of 2,150 km2 (830 sq mi) of forest, and eyewitness reports suggest that at least THREE people may have died in the event.[3][4][5][6][7] The explosion is generally attributed to the air burst of a stony meteoroid about 100 metres (330 feet) in size

Discussion

45.	Womenssareecustomercare number+9641714284
Answer» ohkk....thnkssss...CNFM

45.

Womenssareecustomercare number+9641714284

Answer»

ohkk....thnkssss...CNFM

Discussion

46.	TheLOGICALLYGIVENARRANGEfollowingSETOF WORDS(COLLEGE, child, salary, school, employment)
Answer» Answer: CHILD School college employment and SALARY

46.

TheLOGICALLYGIVENARRANGEfollowingSETOF WORDS(COLLEGE, child, salary, school, employment)

Answer»

Answer:

CHILD School college employment and SALARY

Discussion

47.	Icse class6 mathematics algebraic
Answer» ANSWER: what should i do Step-by-step EXPLANATION:

47.

Icse class6 mathematics algebraic

Answer»

ANSWER:

what should i do

Step-by-step EXPLANATION:

Discussion

48.	ਇੱਕ ਬਕਸੇ ਵਿੱਚ ਦੇ 2 ਅਤੇ 5 ਦੇ ਸਿੱਕੇ 4:5 ਦੇ ਅਨੁਪਾਤ ਵਿੱਚ ਹਨ ਬਕਸੇ ਵਿੱਚ ਕੁੱਲ ਵੱ66 ਹਨ ਤਾਂ ਬਕਸੇ ਵਿੱਚ 2 ਵਾਲੇ ਕਿੰਨੇ ਸਿੱਕੇIf the ratio of 2 and 5 coins is 4:5 and there are total amount is 66 in the box, then how many 2 coins arethe box?b. 6d, 10a. 4C. 8
Answer» Step-by-step EXPLANATION: option C 8 is the correct ANSWER

48.

ਇੱਕ ਬਕਸੇ ਵਿੱਚ ਦੇ 2 ਅਤੇ 5 ਦੇ ਸਿੱਕੇ 4:5 ਦੇ ਅਨੁਪਾਤ ਵਿੱਚ ਹਨ ਬਕਸੇ ਵਿੱਚ ਕੁੱਲ ਵੱ66 ਹਨ ਤਾਂ ਬਕਸੇ ਵਿੱਚ 2 ਵਾਲੇ ਕਿੰਨੇ ਸਿੱਕੇIf the ratio of 2 and 5 coins is 4:5 and there are total amount is 66 in the box, then how many 2 coins arethe box?b. 6d, 10a. 4C. 8

Answer»

Step-by-step EXPLANATION:

option C 8 is the correct ANSWER

Discussion

49.	Prime factorization of 7921
Answer» Answer: 7921 is a composite number so it can be DIVIDED by 1, 89 and 7921 itself. The PRIME factorization of 7921= 892. The prime factors of 7921 is 89.

49.

Prime factorization of 7921

Answer»

Answer:

7921 is a composite number so it can be DIVIDED by 1, 89 and 7921 itself. The PRIME factorization of 7921= 892. The prime factors of 7921 is 89.

Discussion

50.	Construct a quadrilateral if one of the sides is 7 cm andthe two diagonals, whichmake 20° each with thisside, are 6 cm and 6.5 cmrespectively
Answer» Answer: sorry Step-by-step EXPLANATION: AAAAAAA am not SAY for this answer because DONT know

50.

Construct a quadrilateral if one of the sides is 7 cm andthe two diagonals, whichmake 20° each with thisside, are 6 cm and 6.5 cmrespectively

Answer»

Answer:

sorry

Step-by-step EXPLANATION:

AAAAAAA am not SAY for this answer because DONT know

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

Write the digit at the unit place in each of the following square number 625​

Find two different 2×2 marices A such that A²=I​

2×2=4

it's also a 2 square = 4

A square is a×a

Find the mean height and median weight of your family members. ( Minimum 3Imembers)​

Class-X Mathematics1-COSShow that (cosec 0 - cot )21+cosटीटा ​

Alegbra of an arithmetic sequence is 51–6n,what is its 8th term​

Find the value of 4sin​

solution will be ,

Which is of blue colour​

In board examination of class 9 , 50•/• passed in english 30•/• failed in both subject find the total number of student.​

2.f (x) = 8 - 3xg (x) = 10/(x – 1), x is not -1h (x) = 2^xFind(a) hf (8/3)​

2500 sq. meterstheareaof a play groundwhat is the length of each side​

find the smallest whole number by which each of following number must be multiplied to obtain perfect cube (1)49​

13,74,290 650,...... ............​

Find 11/15 of Rs.60​

Each interior angle of a regular polygon is double of its exterior angle. Find thenumber of sides in the polygon.of​

3 and 4which of the following is LCM of numbers​

8. The top surface of a table has the shape of a trapezium. The parallel sides of the trapezium are 85and 63 cm and perpendicular distance between these sides is 36 cm. Calculate its area and find thecost of polishing the surface at the rate of 0.50 per cm?​

Given:

To FIND:

Method:

THEREFORE, total cost of polishing = ₹ 1332

If the edge of a cube is doubled find the percentage increase in the surface area?​

If (x _1)power 3 =8 what is the value of ( x +1)power 2​

Find the H.C.F. of 21x’y? and 35x>ys.​

What are the differences between the above two frequency distribution tables​

Find angler in each figure:407(1)​

SIf x=2/5 y= 3/2Find (x+y) = (x-y)​

R₁ = 4 R₂ = 3 R₃ = 6 are connected in parallel the effective resistance (1/RP) is ....

S O L U T I O N :

Therefore,

For information,

First square number is ___________​

15. In the figure, the chords AB and CD are produced to meet at P. PA = 9 cm, AB = 6 cm, CD = 6 cma) What is PA X PB?b) What is length of PD?​

How many slanting lines in triangle ​

Condition for three numbers a, b, c to be in A.P is​

Please write the answer of question 7​

VVICI15 UIVisible by 2.Hence, n? - n is divisible by 2 for every posiinteger n.Hence Prove7. Find HCF of 81 and 237 and express it as a lincombination of 81 and 237 i.e., HCF (81, 237) =+ 237y for some x and y.A [Board Term-I, 2012, Set-​

Question 1 :

Proof :

Hence proved .

Question 2 :

Solution :

Cise 6.6the following:37the following:XOlos.(ii40x 280(i7​

The sides AB and AC of∆ABC have been produced to D and E respectively.The bisectors of angle CBD and angle BCE meet at O.If angle A =40° find angle BOC​

A Potter makes flowerpots .ifthe weight of one flowerpots is 9.750 kg ,then find the weight of 25 flowerpots.​

Volume of a cone =_________​

A 115m long and 64m broad lawn has two crossroad at right angles, one 2m wide, running parallel to it's length and the other 2.5m wide, running parallel to it's breath. Find the cost of the road at ₹ 4.60 per m rase power 2​

How many persons weight is more that 80kg?how many persons weight is less that 60kg?​

The perimeter of a rectangular playground is 256 meters and its length is 74 meters. What is its area?

If n is a positive integer, what is the remainder when 3^(8n+3) + 2 is divided by 5?​

by using variables x and y form any 2 linear equations in two variables write 2 solutions of the equation x+y=7​

Q5. Find the 25% of 800.​

The floor of a building consists of 400 tiles which are rhombus shaped and each of it diagonals are 45cm and 30cm in length. Find the total cost of polishing the floor if the cost per m2 is ` ₹ 10

DIAGONALS of the RHOMBUS:-

Area of 1 Rhombus :-

Area of Floor :

So, Cost of Polishing the floor:

Wat will be happen the consequences if such an event as the Tunguska event were to occur today ​

Womenssareecustomercare number+9641714284​

TheLOGICALLYGIVENARRANGEfollowingSETOF WORDS(COLLEGE, child, salary, school, employment)​

Icse class6 mathematics algebraic​

Prime factorization of 7921​

Construct a quadrilateral if one of the sides is 7 cm andthe two diagonals, whichmake 20° each with thisside, are 6 cm and 6.5 cmrespectively​

Write the digit at the unit place in each of the following square number 625

Find two different 2×2 marices A such that A²=I

Find the mean height and median weight of your family members. ( Minimum 3Imembers)

Class-X Mathematics1-COSShow that (cosec 0 - cot )21+cosटीटा

Alegbra of an arithmetic sequence is 51–6n,what is its 8th term

Find the value of 4sin

Which is of blue colour

In board examination of class 9 , 50•/• passed in english 30•/• failed in both subject find the total number of student.

2.f (x) = 8 - 3xg (x) = 10/(x – 1), x is not -1h (x) = 2^xFind(a) hf (8/3)

2500 sq. meterstheareaof a play groundwhat is the length of each side

find the smallest whole number by which each of following number must be multiplied to obtain perfect cube (1)49

13,74,290 650,...... ............

Find 11/15 of Rs.60

Each interior angle of a regular polygon is double of its exterior angle. Find thenumber of sides in the polygon.of

3 and 4which of the following is LCM of numbers

8. The top surface of a table has the shape of a trapezium. The parallel sides of the trapezium are 85and 63 cm and perpendicular distance between these sides is 36 cm. Calculate its area and find thecost of polishing the surface at the rate of 0.50 per cm?

If the edge of a cube is doubled find the percentage increase in the surface area?

If (x _1)power 3 =8 what is the value of ( x +1)power 2

Find the H.C.F. of 21x’y? and 35x>ys.

What are the differences between the above two frequency distribution tables

Find angler in each figure:407(1)

SIf x=2/5 y= 3/2Find (x+y) = (x-y)

First square number is ___________

15. In the figure, the chords AB and CD are produced to meet at P. PA = 9 cm, AB = 6 cm, CD = 6 cma) What is PA X PB?b) What is length of PD?

How many slanting lines in triangle

Condition for three numbers a, b, c to be in A.P is

Please write the answer of question 7

VVICI15 UIVisible by 2.Hence, n? - n is divisible by 2 for every posiinteger n.Hence Prove7. Find HCF of 81 and 237 and express it as a lincombination of 81 and 237 i.e., HCF (81, 237) =+ 237y for some x and y.A [Board Term-I, 2012, Set-

Cise 6.6the following:37the following:XOlos.(ii40x 280(i7

The sides AB and AC of∆ABC have been produced to D and E respectively.The bisectors of angle CBD and angle BCE meet at O.If angle A =40° find angle BOC

A Potter makes flowerpots .ifthe weight of one flowerpots is 9.750 kg ,then find the weight of 25 flowerpots.

Volume of a cone =_________

A 115m long and 64m broad lawn has two crossroad at right angles, one 2m wide, running parallel to it's length and the other 2.5m wide, running parallel to it's breath. Find the cost of the road at ₹ 4.60 per m rase power 2

How many persons weight is more that 80kg?how many persons weight is less that 60kg?

If n is a positive integer, what is the remainder when 3^(8n+3) + 2 is divided by 5?

by using variables x and y form any 2 linear equations in two variables write 2 solutions of the equation x+y=7

Q5. Find the 25% of 800.

Wat will be happen the consequences if such an event as the Tunguska event were to occur today

Womenssareecustomercare number+9641714284

TheLOGICALLYGIVENARRANGEfollowingSETOF WORDS(COLLEGE, child, salary, school, employment)

Icse class6 mathematics algebraic

Prime factorization of 7921

Construct a quadrilateral if one of the sides is 7 cm andthe two diagonals, whichmake 20° each with thisside, are 6 cm and 6.5 cmrespectively