1.

R₁ = 4 R₂ = 3 R₃ = 6 are connected in parallel the effective resistance (1/RP) is ....

Answer»

S O L U T I O N :

Given,

  • Three resistors R₁ = 4, R₂ = 3, R₃ = 6 are connected in parallel.

To Find,

Explanation,

We know that,

1/Rp = 1/R₁ + 1/R₂ + 1/R₃

[ Put the values ]

=> 1/Rp = 1/4 + 1/3 + 1/6

=> 1/Rp = 3 + 4 + 2 / 12

=> 1/Rp = 9/12

=> 1/Rp = 0.75 ohm

Therefore,

The effective resistance is 0.75 ohm.

For information,

  • Rs = R₁ + R₂ + R₃,.....
  • V = IR
  • H = I²Rt
  • I = Q/t
  • V = W/Q


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