332354 + Interview Questions in Secondary School in Math

1.	Q-1 Probability of ancent always lies betweenlanddoo
Answer» Answer: PROBABILITY of ANCENT LIES between 0 - 1

1.

Q-1 Probability of ancent always lies betweenlanddoo

Answer»

Answer:

PROBABILITY of ANCENT LIES between 0 - 1

Discussion

2.	Constructquradilateral ABCD in with ab=5cmangle a=60° angle b=120°. bc= 4•5 cm and ad =4•5 cm what type of qurdilateral is this ? find angle c and angle d write the steps of construction steps of construction,ADthe
Answer» ANSWER: FOLLOW me PLZZZZZZZZZ

2.

Constructquradilateral ABCD in with ab=5cmangle a=60° angle b=120°. bc= 4•5 cm and ad =4•5 cm what type of qurdilateral is this ? find angle c and angle d write the steps of construction steps of construction,ADthe

Answer»

ANSWER:

FOLLOW me PLZZZZZZZZZ

Discussion

3.	9. The value of 12 - (13+7) x 4 is
Answer» Step-by-step explanation: A CELL wall is a structural layer surrounding some types of cells, just OUTSIDE the cell membrane. It can be tough, flexible, and sometimes RIGID. It PROVIDES the cell with both structural support and protection, and also ACTS as a filtering mechanism

3.

9. The value of 12 - (13+7) x 4 is

Answer»

Step-by-step explanation:

A CELL wall is a structural layer surrounding some types of cells, just OUTSIDE the cell membrane. It can be tough, flexible, and sometimes RIGID. It PROVIDES the cell with both structural support and protection, and also ACTS as a filtering mechanism

Discussion

4.	28. Sum of first 25 terms in AP is 525, sum of the next 25terms is 725, what is the common difference?A)B)25C)842525D)
Answer» Answer: 25 is answer Step-by-step EXPLANATION: HOPE it's HELPFUL

4.

28. Sum of first 25 terms in AP is 525, sum of the next 25terms is 725, what is the common difference?A)B)25C)842525D)

Answer»

Answer:

25 is answer

Step-by-step EXPLANATION:

HOPE it's HELPFUL

Discussion

5.	Find the value of k for which the following pair of equations have no solution: x+2y=3, (k-1) x + (k+1)y= (k+2)
Answer» Step-by-step EXPLANATION: HOPE it will HELP you..............

5.

Find the value of k for which the following pair of equations have no solution: x+2y=3, (k-1) x + (k+1)y= (k+2)

Answer»

Step-by-step EXPLANATION:

HOPE it will HELP you..............

Discussion

6.	Show that A intersect B= A intersect C need not imply B=C
Answer» ANSWER: HOPE this WOULD HELP you .....

6.

Show that A intersect B= A intersect C need not imply B=C

Answer»

ANSWER:

HOPE this WOULD HELP you

.....

Discussion

7.	The system of equation 2 X + 3 Y - 7 is equals to zero and 6 X + 5 Y - 11 is equals to zero has
Answer» ANSWER: hhdkgkfk if you if to of d to it G GO is if FH

7.

The system of equation 2 X + 3 Y - 7 is equals to zero and 6 X + 5 Y - 11 is equals to zero has

Answer»

ANSWER:

hhdkgkfk if you if to of d to it G GO is if FH

Discussion

8.	Solve for x and y: 2x+3y=9; 4x+6y=15
Answer» Step-by-step explanation: 2x+3y=9------(1) 4x+6y=15----(2) multiply EQ (1)×2 so we get 4x+6y=18 Using ELIMINATION method 4x+6y=18 ±4x±6y=±15 =0x+0y=3 :• This equation is not POSSIBLE

8.

Solve for x and y: 2x+3y=9; 4x+6y=15

Answer»

Step-by-step explanation:

2x+3y=9------(1)

4x+6y=15----(2)

multiply EQ (1)×2 so we get

4x+6y=18

Using ELIMINATION method

4x+6y=18

±4x±6y=±15

=0x+0y=3

:• This equation is not POSSIBLE

Discussion

9.	Find the product xy(x2+y2and evaluate ot for x=2andy=-2
Answer» XY(x^2+y^2) 2×-2(2^2+(-2^2) -4(4+4) -4(8) -32 please FOLLOW me

9.

Find the product xy(x2+y2and evaluate ot for x=2andy=-2

Answer»

XY(x^2+y^2)

2×-2(2^2+(-2^2)

-4(4+4)

-4(8)

-32

please FOLLOW me

Discussion

10.	Write the formula of the midpoint the line segments joining the points (x , y) and (x , y)
Answer» ANSWER: (x1x2+x1x2) ÷ M1+M2 × (x1x2+x1x2) ÷ m1 +m2

10.

Write the formula of the midpoint the line segments joining the points (x , y) and (x , y)

Answer»

ANSWER:

(x1x2+x1x2) ÷ M1+M2 × (x1x2+x1x2) ÷ m1 +m2

Discussion

11.	Substract he expressions - 5x-(-30x² +24)
Answer» ANSWER: $- 5x - ( - 30 {x}^{2} + 24) \\ \\ = - 5 {x} + 30 {x}^{2} - 24$ HOPE this MUCH HELPS UH ❣️

11.

Substract he expressions - 5x-(-30x² +24)

Answer»

ANSWER:

$- 5x - ( - 30 {x}^{2} + 24) \\ \\ = - 5 {x} + 30 {x}^{2} - 24$

HOPE this MUCH HELPS UH ❣️

Discussion

12.	santi has 5 kg of mannure and 2 kg weight. How will she weight one kg of mannure by using her balance twice
Answer» Answer: 5 KG of MANURE bsjsjs ahhahahahahshah

12.

santi has 5 kg of mannure and 2 kg weight. How will she weight one kg of mannure by using her balance twice

Answer»

Answer:

5 KG of MANURE bsjsjs

ahhahahahahshah

Discussion

13.	Show that sigma (a+b)tan (a-b/2)=0
Answer» ANSWER: a/sin A=b/sin B=c/sin C=K (a-b)/(a+b)=(k sin A-k sin B)/(k sinA + k sinB). or, (a-b)/(a+b)= (sin A - sin B)/(sin A+ sin B). or, (a-b)/(a+b) = {2.cos (A+B)/2.sin(A-B)/2}/{2.sin(A+B)/2.cos(A-B)/2}. or, (a-b)/(a+b) = cot(A+B)/2. TAN(A-B)/2. or, {(a-b)/(a+b)}= cot (90° -C/2).tan(A-B)/2. or, {(a-b)/(a+b)} = tan C/2. tan (A-B)/2. or, {(a-b)/(a+b)} = 1/cotC/2 . tan(A-B)/2. or, {(a-b)/(a+b)}.cot C = tan(A-B)/2. PROVED

13.

Show that sigma (a+b)tan (a-b/2)=0

Answer»

ANSWER:

a/sin A=b/sin B=c/sin C=K

(a-b)/(a+b)=(k sin A-k sin B)/(k sinA + k sinB).

or, (a-b)/(a+b)= (sin A - sin B)/(sin A+ sin B).

or, (a-b)/(a+b) = {2.cos (A+B)/2.sin(A-B)/2}/{2.sin(A+B)/2.cos(A-B)/2}.

or, (a-b)/(a+b) = cot(A+B)/2. TAN(A-B)/2.

or, {(a-b)/(a+b)}= cot (90° -C/2).tan(A-B)/2.

or, {(a-b)/(a+b)} = tan C/2. tan (A-B)/2.

or, {(a-b)/(a+b)} = 1/cotC/2 . tan(A-B)/2.

or, {(a-b)/(a+b)}.cot C = tan(A-B)/2. PROVED

Discussion

14.	If tanA=17√ then the value of cosec2A−sec2Acosec2A+sec2A is
Answer» I don't UNDERSTAND your QUESTION Step-by-step EXPLANATION: i don't understand your question

14.

If tanA=17√ then the value of cosec2A−sec2Acosec2A+sec2A is

Answer»

I don't UNDERSTAND your QUESTION

Step-by-step EXPLANATION:

i don't understand your question

Discussion

15.	1. If cosa = 4/5 then find tan A, sin A
Answer» ANSWER: sina=√1-cos²a =√1-16/25 =3/5 tana= sina/cosa =3/4

15.

1. If cosa = 4/5 then find tan A, sin A

Answer»

ANSWER:

sina=√1-cos²a

=√1-16/25

=3/5

tana= sina/cosa

=3/4

Discussion

16.	বিষয় গনিতওরটি নির্বাচন করাে।সমকোনী সমদ্বিবাহু ত্রিভুজের তিনটি কোনের অনুপাত কি হবে?(a) 1; 2: 1 (b) 7:1: 2 (c) 2: 2: 1 (d) 1:2:31895 থেকে 1915 সাল পর্যন্ত লিপ ইয়ারের সংখ্যা হলাে -a) 5 (b) 4 (c) 3 (d) কোনােটিই নয়12 সেমি বাহু বিশিষ্ট একটি সমবাহু ত্রিভূজের পরিসীমা হবে -
Answer» ANSWER: What LANGUAGE is this?SORRY I don't UNDERSTAND;-;

16.

বিষয় গনিতওরটি নির্বাচন করাে।সমকোনী সমদ্বিবাহু ত্রিভুজের তিনটি কোনের অনুপাত কি হবে?(a) 1; 2: 1 (b) 7:1: 2 (c) 2: 2: 1 (d) 1:2:31895 থেকে 1915 সাল পর্যন্ত লিপ ইয়ারের সংখ্যা হলাে -a) 5 (b) 4 (c) 3 (d) কোনােটিই নয়12 সেমি বাহু বিশিষ্ট একটি সমবাহু ত্রিভূজের পরিসীমা হবে -

Answer»

ANSWER:

What LANGUAGE is this?SORRY I don't UNDERSTAND;-;

Discussion

17.	Check what type of quadrilateral form by the points (1.3). (-5, 1), (-5, 3).(1,7).
Answer» Step-by-step explanation: A CELL WALL is a structural layer surrounding some types of CELLS, just outside the cell membrane. It can be tough, flexible, and sometimes rigid. It PROVIDES the cell with both structural support and protection, and also acts as a FILTERING mechanism

17.

Check what type of quadrilateral form by the points (1.3). (-5, 1), (-5, 3).(1,7).

Answer»

Step-by-step explanation:

A CELL WALL is a structural layer surrounding some types of CELLS, just outside the cell membrane. It can be tough, flexible, and sometimes rigid. It PROVIDES the cell with both structural support and protection, and also acts as a FILTERING mechanism

Discussion

18.	Rutempt the following questions1) Ajay is younger than Vijay by 5 , years the sum of their ages is 25 years. what is ajay age?3) Write the set of prime numbers from 1 to 20 using listing method.
Answer» Answer: Ajay's age is 10 years 2,3,5,7,11,13,17,19 Hope this will HELP you PLS MARK as brilliant

18.

Rutempt the following questions1) Ajay is younger than Vijay by 5 , years the sum of their ages is 25 years. what is ajay age?3) Write the set of prime numbers from 1 to 20 using listing method.

Answer»

Answer:

Ajay's age is 10 years

2,3,5,7,11,13,17,19

Hope this will HELP you PLS MARK as brilliant

Discussion

19.	Match the equivalent expressions(y-0.32y) (y+0.32y) (y+2/5y) (y-2/5y)7/5y >>>>> BLANK0.68y >>>>>BLANK3/5y>>>>>BLANK1.32y>>>>>BLANKPlease answer.
Answer» Given : (y-0.32y) , (y+0.32y) , (y+2/5y) , (y-2/5y) To FIND : Matching Expression : 7/5y 0.68y 3/5y 1.32y Solution: y-0.32y = 0.68y y+0.32y = 1.32y y+2/5y = 7/5y y-2/5y = 3/5y y-0.32y = 0.68y y+0.32y = 1.32y y+2/5y = 7/5y y-2/5y = = 3/5y LEARN More: brainly.in/question/30481180 Match the items in GROUP A with the items in group B: Group-A 1 ... brainly.in/question/11761772

19.

Match the equivalent expressions(y-0.32y) (y+0.32y) (y+2/5y) (y-2/5y)7/5y >>>>> BLANK0.68y >>>>>BLANK3/5y>>>>>BLANK1.32y>>>>>BLANKPlease answer.

Answer»

Given : (y-0.32y) , (y+0.32y) , (y+2/5y) , (y-2/5y)

To FIND : Matching Expression :

7/5y

0.68y

3/5y

1.32y

Solution:

y-0.32y

= 0.68y

y+0.32y

= 1.32y

y+2/5y

= 7/5y

y-2/5y

= 3/5y

y-0.32y = 0.68y

y+0.32y = 1.32y

y+2/5y = 7/5y

y-2/5y = = 3/5y

LEARN More:

brainly.in/question/30481180

Match the items in GROUP A with the items in group B: Group-A 1 ...

brainly.in/question/11761772

Discussion

20.	.A building 16 m high casts a shadow of 6.4 m length. Find the height of the building which casts a shadow of 1.6 m at the same angle of Sun rays.
Answer» solution:- Height of pole=AB=6 m Length of shadow of pole =BC=4 m Length of shadow of tower=EF=28 m In △ABC and △DEF ∠B=∠E=90 ∘ both 90 ∘ as both are vertical to ground ∠C=∠F (same elevation in both the cases as both SHADOWS are cast at the same TIME) ∴△ABC∼△DEF by AA similarity criterion We know that if TWO triangles are similar, RATIO of their sides are in proportion So, AB/DE=BC/EF ⇒ 6/DE=4/28 DE=6×28/4 ⇒DE=6×7=42 m Hence the height of the tower is 42 m

20.

.A building 16 m high casts a shadow of 6.4 m length. Find the height of the building which casts a shadow of 1.6 m at the same angle of Sun rays.

Answer»

solution:-

Height of pole=AB=6 m

Length of shadow of pole =BC=4 m

Length of shadow of tower=EF=28 m

In △ABC and △DEF

∠B=∠E=90

∘

both 90

∘

as both are vertical to ground

∠C=∠F (same elevation in both the cases as both SHADOWS are cast at the same TIME)

∴△ABC∼△DEF by AA similarity criterion

We know that if TWO triangles are similar, RATIO of their sides are in proportion

So, AB/DE=BC/EF

⇒ 6/DE=4/28

DE=6×28/4

⇒DE=6×7=42 m

Hence the height of the tower is 42 m

Discussion

21.	*6. Simplify:(1 Point)(1.52 + 1.29)2 – (1.5p - 1.29)2
Answer» Step-by-step explanation: 1.52 × 2 + 1.29 × 2 - 1.52 × 2 - 1.29 × 2 (3.04 + 2.58) - (3.04 - 2.58) 5.62 + 0.46 6.08

21.

*6. Simplify:(1 Point)(1.52 + 1.29)2 – (1.5p - 1.29)2

Answer»

Step-by-step explanation:

1.52 × 2 + 1.29 × 2 - 1.52 × 2 - 1.29 × 2

(3.04 + 2.58) - (3.04 - 2.58)

5.62 + 0.46

6.08

Discussion

22.	Q1) Identify the coefficients ofthe following terms in thegiven expression 4x4-5x3-7x2+16x +9 *
Answer» Step-by-step explanation: 4, -5, -7, 16, 9 are the COEFFICIENTS

22.

Q1) Identify the coefficients ofthe following terms in thegiven expression 4x4-5x3-7x2+16x +9 *

Answer»

Step-by-step explanation:

4, -5, -7, 16, 9 are the COEFFICIENTS

Discussion

23.	11. The diagonals of a square PQRS meet at 0. Whatkind of a triangle is AOPQ?
Answer» ANSWER: EQUILATERAL triangle Step-by-step EXPLANATION: UNDERSTAND.... You BETTER understand

23.

11. The diagonals of a square PQRS meet at 0. Whatkind of a triangle is AOPQ?

Answer»

ANSWER:

EQUILATERAL triangle

Step-by-step EXPLANATION:

UNDERSTAND....

You BETTER understand

Discussion

24.	. A train 375 m long takes 30 seconds to cross a pole. Find the speed of the train in kmph.
Answer» Step-by-step explanation: the ANSWER is LOL.... OT is very SIMPLE u KNOW

24.

. A train 375 m long takes 30 seconds to cross a pole. Find the speed of the train in kmph.

Answer»

Step-by-step explanation:

the ANSWER is LOL.... OT is very SIMPLE u KNOW

Discussion

25.	What is the order of the surf ³√9⁴
Answer» ANSWER: ORDER of this QUESTION is 3

25.

What is the order of the surf ³√9⁴

Answer»

ANSWER:

ORDER of this QUESTION is 3

Discussion

26.	If tan A =3/4,then prove that sin Acos A =12/25
Answer» Step-by-step EXPLANATION: As sec2A−tan2A=1⇒secA=±tan2A+1 =±169+1=±1625=±45 ⇒cosA=secA1=±54 And sin2A+cos2A=1 ⇒sinA=±1−cos2A=±1−2516 =±259=±53 ⇒sinAcosA=2512 I HOPE IT'S HELP

26.

If tan A =3/4,then prove that sin Acos A =12/25

Answer»

Step-by-step EXPLANATION:

As sec2A−tan2A=1⇒secA=±tan2A+1

=±169+1=±1625=±45

⇒cosA=secA1=±54

And sin2A+cos2A=1

⇒sinA=±1−cos2A=±1−2516

=±259=±53

⇒sinAcosA=2512

I HOPE IT'S HELP

Discussion

27.	The greatest 3-digit number as a product of primes is
Answer» Answer: HEY mate your answer Step-by-step EXPLANATION: the LARGEST 3 digit no. is 999. If u want to want its PRODUCT of primes u can do prime factorisation

27.

The greatest 3-digit number as a product of primes is

Answer»

Answer:

HEY mate your answer

Step-by-step EXPLANATION:

the LARGEST 3 digit no. is 999. If u want to want its PRODUCT of primes u can do prime factorisation

Discussion

28.	Grite 0.6666...pla forum
Answer» ANSWER: jsjsksskskkdbsnsnsjs

28.

Grite 0.6666...pla forum

Answer»

ANSWER:

jsjsksskskkdbsnsnsjs

Discussion

29.	Y-0.32y y+0.32y y+2/5y y-2/5y7/5y >>>>> BLANK0.68y >>>>>BLANK3/5y>>>>>BLANK1.32y>>>>>BLANKpls answer
Answer» ANSWER: What do you WANT to SAY

29.

Y-0.32y y+0.32y y+2/5y y-2/5y7/5y >>>>> BLANK0.68y >>>>>BLANK3/5y>>>>>BLANK1.32y>>>>>BLANKpls answer

Answer»

ANSWER:

What do you WANT to SAY

Discussion

30.	(1) গসাগু নির্ণয় করাে : ৪(+2 – a), 12(x3 + ৪), 36(x – 3x - 10)
Answer» ANSWER: what LANGUAGE is this?=$={${${${$×${\|{${¥{{¥$ππ$÷\|×\|}¥{¥}¥{¥

30.

(1) গসাগু নির্ণয় করাে : ৪(+2 – a), 12(x3 + ৪), 36(x – 3x - 10)

Answer»

ANSWER:

what LANGUAGE is this?=$={${${${$×${|{${¥{{¥$ππ$÷|×|}¥{¥}¥{¥

Discussion

31.	On which do the following points lic 0,5
Answer» S(0,5) x co-ordinate=0, so the POINT LIES on y-axis. hope it is USEFUL for you please MARK me as Brainliest

31.

On which do the following points lic 0,5

Answer»

S(0,5) x co-ordinate=0, so the POINT LIES on y-axis.

hope it is USEFUL for you please MARK me as Brainliest

Discussion

32.	For given positive integers a and b there exist unique integers q and r satisfying a=bq+ r o { r
Answer» ANSWER: which of the FOLLOWING is not a QUADRILATERAL

32.

For given positive integers a and b there exist unique integers q and r satisfying a=bq+ r o { r

Answer»

ANSWER:

which of the FOLLOWING is not a QUADRILATERAL

Discussion

33.	D& And the perimeter of each of the following figures(1) 4cm(2) 2.5cm(3) 2 cm(4) 3.5cm(5) 7cm
Answer» ANSWER: where is FIGURES ? KINDLY SHOW figures of these LENGTHS .

33.

D& And the perimeter of each of the following figures(1) 4cm(2) 2.5cm(3) 2 cm(4) 3.5cm(5) 7cm

Answer»

ANSWER:

where is FIGURES ? KINDLY SHOW figures of these LENGTHS .

Discussion

34.	If 36,54,x are in continued proportion find thevalue of a
Answer» Answer: SINCE 36,54,x are in continued proportion, we have =36:54::54:x We know that product of EXTREMES = product of means =36×x=54×54 =36x=2916 x=(2916/36) x=81 Step-by-step EXPLANATION: hope this HELPS please mark me as brilliant

34.

If 36,54,x are in continued proportion find thevalue of a

Answer»

Answer:

SINCE 36,54,x are in continued proportion, we have

=36:54::54:x

We know that

product of EXTREMES = product of means

=36×x=54×54

=36x=2916

x=(2916/36)

x=81

Step-by-step EXPLANATION:

hope this HELPS please mark me as brilliant

Discussion

35.	1 if a-b = 5 and ab=15find value of a +b²
Answer» Answer: 5+15(15)² 5+225 230 char DIKO SURE

35.

1 if a-b = 5 and ab=15find value of a +b²

Answer»

Answer:

5+15(15)²

5+225

230

char DIKO SURE

Discussion

36.	Find factor of 3a+9b-6(a+3b)2
Answer» ANSWER: Factors of 2a+6b-3(a+3b)²= (a+3b)(2-3a-9b) Explanation: Factorising 2a+6b-3(a+3b)² = 2(a+3b)-3(a+3b)(a+3b) = (a+3b)[2-3(a+3b)] = (a+3b)(2-3a-9b) Therefore, 2a+6b-3(a+3b)² = (a+3b)(2-3a-9b) PLS MARK me as BRAINLIEST i need only one plsssssssssssssssssssssssssssssssssssssssssssssss

36.

Find factor of 3a+9b-6(a+3b)2

Answer»

ANSWER:

Factors of 2a+6b-3(a+3b)²=

(a+3b)(2-3a-9b)

Explanation:

Factorising 2a+6b-3(a+3b)²

= 2(a+3b)-3(a+3b)(a+3b)

= (a+3b)[2-3(a+3b)]

= (a+3b)(2-3a-9b)

Therefore,

2a+6b-3(a+3b)²

= (a+3b)(2-3a-9b)

PLS MARK me as BRAINLIEST i need only one plsssssssssssssssssssssssssssssssssssssssssssssss

Discussion

37.	If 8 man can do a piease of work in 20 days in how many days 2p man can do the same work
Answer» ANSWER: if 8 MAN can do a piece of work in 20 DAYS Then, one man can do it in = 20 * 8 = 160 d (it takes long time to finish the work for one man) Hence, 2 man can do it in LESS time taken by 1 man. = 160/2 = 80 days hence, 2 man can do the same work in 80 days I have given a step by step exaplaination you can check

37.

If 8 man can do a piease of work in 20 days in how many days 2p man can do the same work

Answer»

ANSWER:

if 8 MAN can do a piece of work in 20 DAYS

Then, one man can do it in = 20 * 8 = 160 d (it takes long time to finish the work for one man)

Hence, 2 man can do it in LESS time taken by 1 man. = 160/2 = 80 days

hence, 2 man can do the same work in 80 days

I have given a step by step exaplaination you can check

Discussion

38.	4 points3) Solve and click on thecorrect solutions for thefollowing linear equations :: *(-1,1) {4, 2) (3,-1) (-1,2)4x - 2y= 14,6x + 2yООOO= 163x + 4y=1, 3x- 2y = -5Ο Ο Ο Ο
Answer» Answer: GU ug IG ig ig ig HI JJ huvih

38.

4 points3) Solve and click on thecorrect solutions for thefollowing linear equations :: *(-1,1) {4, 2) (3,-1) (-1,2)4x - 2y= 14,6x + 2yООOO= 163x + 4y=1, 3x- 2y = -5Ο Ο Ο Ο

Answer»

Answer:

GU ug IG ig ig ig HI JJ huvih

Discussion

39.	Add the following integer: 782,19,2034,2011
Answer» ANSWER: Step-by-step explanation: 782,19,2034,2011

39.

Add the following integer: 782,19,2034,2011

Answer»

ANSWER:

Step-by-step explanation:

782,19,2034,2011

Discussion

40.	What is sucessor of x
Answer» ANSWER: $\huge\mathbb{\color{blue}{\underline {\underline{❥Answer}}}}$ Step-by-step EXPLANATION: The SUCCESSOR X is XI.

40.

What is sucessor of x

Answer»

ANSWER:

$\huge\mathbb{\color{blue}{\underline {\underline{❥Answer}}}}$

Step-by-step EXPLANATION:

The SUCCESSOR X is XI.

Discussion

41.	If sin theta =3 upon 5 find the value of 2 sin theta +2 cos theta
Answer» ANSWER: HOPE you GET your answer in the IMAGE PROVIDED...

41.

If sin theta =3 upon 5 find the value of 2 sin theta +2 cos theta

Answer»

ANSWER:

HOPE you GET your answer in the IMAGE PROVIDED...

Discussion

42.	અમિત સવારે, સાંજે અને રાત્રે અનુક્રમે 0.02 કિ.મી. 35 મીટર, 3 કિ.મી. 7 મીટર.અને 0.9 કિ.મી. 800 મીટર ચાલ્યો. તો કુલ કેટલા કિ.મી. ચાલ્યો હશે ?
Answer» ANSWER: PLEASE TRANSLATE it in ENGLISH

42.

અમિત સવારે, સાંજે અને રાત્રે અનુક્રમે 0.02 કિ.મી. 35 મીટર, 3 કિ.મી. 7 મીટર.અને 0.9 કિ.મી. 800 મીટર ચાલ્યો. તો કુલ કેટલા કિ.મી. ચાલ્યો હશે ?

Answer»

ANSWER:

PLEASE TRANSLATE it in ENGLISH

Discussion

43.	Find distance coordinates of midpoint of segment joining the points (16,4) and (36,6)
Answer» ANSWER: The midpoint is HALFWAY between the two END points: Its x VALUE is halfway between the two x VALUES. Its y value is halfway between the two y values

43.

Find distance coordinates of midpoint of segment joining the points (16,4) and (36,6)

Answer»

ANSWER:

The midpoint is HALFWAY between the two END points: Its x VALUE is halfway between the two x VALUES. Its y value is halfway between the two y values

Discussion

44.	A + 1a2 – a - 2কে লঘিষ্ঠ আকারে প্রকাশ করাে।a + 22a + a
Answer» ANSWER: your LANGUAGE is of any other LEVEL I cannot UNDERSTAND

44.

A + 1a2 – a - 2কে লঘিষ্ঠ আকারে প্রকাশ করাে।a + 22a + a

Answer»

ANSWER:

your LANGUAGE is of any other LEVEL I cannot UNDERSTAND

Discussion

45.	The no. of faces a cuboid has
Answer» Answer: 6 FACES and 12 EDGES .........

45.

The no. of faces a cuboid has

Answer»

Answer:

6 FACES and 12 EDGES

.........

Discussion

46.	5. Find x so that(1 Point)(-5)+1 x (-5)5 = (-5)
Answer» Step-by-step EXPLANATION: bro QUESTION samaz nahi AA raha hai nahito SOLVE kardeta *+ KYA hai

46.

5. Find x so that(1 Point)(-5)+1 x (-5)5 = (-5)

Answer»

Step-by-step EXPLANATION:

bro QUESTION samaz nahi AA raha hai nahito SOLVE kardeta *+ KYA hai

Discussion

47.	Neha decorates the window of her room using three identical bulbs B, B, and B, asshown in the figure. When all the three bulbs glow, the current of 3A is recorded byammeter A.(a)if bulb b2 gets feused the total current in the circuit will be
Answer» ANSWER: TOTAL CURRENT in the CIRCUIT will REMAIN same

47.

Neha decorates the window of her room using three identical bulbs B, B, and B, asshown in the figure. When all the three bulbs glow, the current of 3A is recorded byammeter A.(a)if bulb b2 gets feused the total current in the circuit will be

Answer»

ANSWER:

TOTAL CURRENT in the CIRCUIT will REMAIN same

Discussion

48.	Match the equivalent expressionsy-0.32y y+0.32y y+2/5y y-2/5y7/5y >>>>> BLANK0.68y >>>>>BLANK3/5y>>>>>BLANK1.32y>>>>>BLANKPlease answer.
Answer» SOLUTION GIVEN The given EXPRESSIONS are $\displaystyle \sf{<klux>1</klux>. \: \: \: ( \: y - 0.32y \: )}$ $\displaystyle \sf{2. \: \: \: ( \: y + 0.32y \: )}$ $\displaystyle \sf{3. \: \: \: \bigg( \: y + \frac{2}{5} y \bigg)}$ $\displaystyle \sf{4. \: \: \: \bigg( \: y - \frac{2}{5} y \bigg)}$ GIVEN OPTIONS ARE $\displaystyle \sf{1. \: \: \: \frac{7}{5} y \: }$ $\displaystyle \sf{2. \: \: \: 0.68y}$ $\displaystyle \sf{3. \: \: \: \frac{3}{5} y \: }$ $\displaystyle \sf{4. \: \: \: 1.32y}$ EVALUATION FIRST EXPRESSION $\displaystyle \sf{ \: y - 0.32 y \: }$ $\displaystyle \sf{ = \: y (1 - 0.32) \: }$ $\displaystyle \sf{ = 0.68y \: }$ Hence the correct equivalent expression is $\displaystyle \sf{2. \: \: \: 0.68y}$ SECOND EXPRESSION $\displaystyle \sf{ \: y + 0.32 y \: }$ $= \displaystyle \sf{ \: y(1 + 0.32 ) \: }$ $\displaystyle \sf{ = 1.32y \: }$ Hence the correct equivalent expression is $\displaystyle \sf{4. \: \: \: 1.32y}$ THIRD EXPRESSION $\displaystyle \sf{ \bigg( \: y + \frac{2}{5} y \bigg)}$ $= \displaystyle \sf{ \bigg( 1 + \frac{2}{5} \bigg)y}$ $= \displaystyle \sf{ \bigg( \frac{5 + 2}{5} \bigg)y}$ $= \displaystyle \sf{ \frac{7}{5}y }$ Hence the correct equivalent expression is $\displaystyle \sf{1. \: \: \: \frac{7}{5} y \: }$ FOURTH EXPRESSION $\displaystyle \sf{ \bigg( \: y - \frac{2}{5} y \bigg)}$ $\displaystyle \sf{ = \bigg( 1 - \frac{2}{5} \bigg)y}$ $\displaystyle \sf{ = \bigg( \frac{5 - 2}{5} \bigg)y}$ $\displaystyle \sf{ = \frac{3}{5}y }$ Hence the correct equivalent expression is $\displaystyle \sf{3. \: \: \: \frac{3}{5} y \: }$ ━━━━━━━━━━━━━━━━ Learn more from Brainly :- 1. Sum of rational numbers whose absolute VALUE is 7/3 brainly.in/question/30899277 2. Write the rational number in standard form:78/65 brainly.in/question/24344794

48.

Match the equivalent expressionsy-0.32y y+0.32y y+2/5y y-2/5y7/5y >>>>> BLANK0.68y >>>>>BLANK3/5y>>>>>BLANK1.32y>>>>>BLANKPlease answer.

Answer»

SOLUTION

GIVEN

The given EXPRESSIONS are

$\displaystyle \sf{<klux>1</klux>. \: \: \: ( \: y - 0.32y \: )}$

$\displaystyle \sf{2. \: \: \: ( \: y + 0.32y \: )}$

$\displaystyle \sf{3. \: \: \: \bigg( \: y + \frac{2}{5} y \bigg)}$

$\displaystyle \sf{4. \: \: \: \bigg( \: y - \frac{2}{5} y \bigg)}$

GIVEN OPTIONS ARE

$\displaystyle \sf{1. \: \: \: \frac{7}{5} y \: }$

$\displaystyle \sf{2. \: \: \: 0.68y}$

$\displaystyle \sf{3. \: \: \: \frac{3}{5} y \: }$

$\displaystyle \sf{4. \: \: \: 1.32y}$

EVALUATION

FIRST EXPRESSION

$\displaystyle \sf{ \: y - 0.32 y \: }$

$\displaystyle \sf{ = \: y (1 - 0.32) \: }$

$\displaystyle \sf{ = 0.68y \: }$

Hence the correct equivalent expression is

$\displaystyle \sf{2. \: \: \: 0.68y}$

SECOND EXPRESSION

$\displaystyle \sf{ \: y + 0.32 y \: }$

$= \displaystyle \sf{ \: y(1 + 0.32 ) \: }$

$\displaystyle \sf{ = 1.32y \: }$

Hence the correct equivalent expression is

$\displaystyle \sf{4. \: \: \: 1.32y}$

THIRD EXPRESSION

$\displaystyle \sf{ \bigg( \: y + \frac{2}{5} y \bigg)}$

$= \displaystyle \sf{ \bigg( 1 + \frac{2}{5} \bigg)y}$

$= \displaystyle \sf{ \bigg( \frac{5 + 2}{5} \bigg)y}$

$= \displaystyle \sf{ \frac{7}{5}y }$

Hence the correct equivalent expression is

$\displaystyle \sf{1. \: \: \: \frac{7}{5} y \: }$

FOURTH EXPRESSION

$\displaystyle \sf{ \bigg( \: y - \frac{2}{5} y \bigg)}$

$\displaystyle \sf{ = \bigg( 1 - \frac{2}{5} \bigg)y}$

$\displaystyle \sf{ = \bigg( \frac{5 - 2}{5} \bigg)y}$

$\displaystyle \sf{ = \frac{3}{5}y }$

Hence the correct equivalent expression is

$\displaystyle \sf{3. \: \: \: \frac{3}{5} y \: }$

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1. Sum of rational numbers whose absolute VALUE is 7/3

brainly.in/question/30899277

2. Write the rational number in standard form:78/65

brainly.in/question/24344794

Discussion

49.	The mid point of the line segment joining thepoints À (-2, 8) and B(-6, -4) is
Answer» ANSWER: IDK Step-by-step EXPLANATION:

49.

The mid point of the line segment joining thepoints À (-2, 8) and B(-6, -4) is

Answer»

ANSWER:

IDK

Step-by-step EXPLANATION:

Discussion

50.	A villager ramayya has a plot of land in the shape of a quadrilateral.The grampanchayat of the village decide to take over some portion of his plot from one of the corners to construct a school. Ramayya agrees to the above proposal with the condition that he should be given equal amount of land in exchange of his land adjoining his plot so as to form a triangular plot.Explain how this proposal will be implemented.(draw a rough sketch of plot).
Answer» Step-by-step explanation: ⇒ Let ABCD is the quadrilateral plot of Rammaya. ⇒ Draw diagonal BD and CE\paralle$$BD. Now, join DE which intersects BC at point O. ⇒ Now from figure, ⇒ △BDE and △BDC have the same base BD and between the same PARALLELS BD and CE. ⇒ So, AREA(△BDE)=Area(△BDC) ⇒ Now subtract $$Area(\TRIANGLE BDO) on both sides, we get ⇒ Area(△BDE)−Area(△BDO)=Area(△BDC)−Area(△BDO) ⇒ Area(△COD)=Area(△BOE) SoRammayacandisposeArea(△COD)fromhisplotABCDandgetArea(△BOE)inadjacentandthen hewillhaveatrianglelandADE.

50.

A villager ramayya has a plot of land in the shape of a quadrilateral.The grampanchayat of the village decide to take over some portion of his plot from one of the corners to construct a school. Ramayya agrees to the above proposal with the condition that he should be given equal amount of land in exchange of his land adjoining his plot so as to form a triangular plot.Explain how this proposal will be implemented.(draw a rough sketch of plot).

Answer»

Step-by-step explanation:

⇒ Let ABCD is the quadrilateral plot of Rammaya.

⇒ Draw diagonal BD and CE\paralle$$BD. Now, join DE which intersects BC at point O.

⇒ Now from figure,

⇒ △BDE and △BDC have the same base BD and between the same PARALLELS BD and CE.

⇒ So, AREA(△BDE)=Area(△BDC)

⇒ Now subtract $$Area(\TRIANGLE BDO) on both sides, we get

⇒ Area(△BDE)−Area(△BDO)=Area(△BDC)−Area(△BDO)

⇒ Area(△COD)=Area(△BOE)

SoRammayacandisposeArea(△COD)fromhisplotABCDandgetArea(△BOE)inadjacentandthen

hewillhaveatrianglelandADE.

Discussion

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