Explore topic-wise InterviewSolutions in Current Affairs.

ANSWER:

SEND COMPLETE QUESTION.......

ANSWER:

a CALL of MODEL INDUSTRY

Step-by-step explanation:

angle A=angleD(each 90°)-------(1)

AC=DB(GIVEN) -------(2)

BC=CB(SIDE opposite to equal angles) -----(3)

so frm SAS congruence ∆ABC=~∆DCB......

FRM CPCT ABC = DCB

ANSWER:Theorem 1: Angles opposite to the equal sides of an ISOSCELES triangle are also equal. Proof: Consider an isosceles triangle ABC where AC = BC. We need to prove that the angles opposite to the sides AC and BC are equal, that is, ∠CAB = ∠CBA. We FIRST DRAW a bisector of ∠ACB and NAME it as CD.

Step-by-step explanation:

ANSWER:

I don't KNOW DEAR SORRY

Answer:

answer is 6

Step-by-step explanation:

I solved it..incase any doubts .. Comment' on it ...or else if any method if you KNOW PLEASE share .. or if it is wrong please correct it ....

THANK you...

ANSWER:

TERMINATING............

Answer:

hey MATE here is your answer...

Step-by-step explanation:

DIGITAL IMAGE courtesy of the Getty's Open Content Program. ONE early spring day during the year 415 in the city of Alexandria—the intellectual heart of the waning Roman Empire—the pagan philosopher Hypatia was murdered by a mob of Christian men. ... Her remains were burned in a mockery of pagan sacrific

ANSWER:

we can PROVE by USING DISTANCE FORMULA

ANSWER:

ii) ANS. D

as 40/25 will be 8/5 .

Step-by-step explanation:

hope it helps

mark BRAINLIEST PLS

ANSWER:

SUM of 10 PRIME no. are :-

2+3+5+7+9+11+13+17+19+23=109

ANSWER:

Given :-

7th TERM of AP = 4

Common difference = 4

Solution :-

t7 = a + ( n - 1 )d = 4

PUT the required values in the formula ,

t7 = a + ( 7 - 1 )4 = 4

a + 28 - 4 = 4

a + 24 = 4

a = 4 - 24

a = -20

Hence , The VALUE of a = -20

Related Formulas : -

• a + ( n - 1)d

Here , a is first term , n is no .of terms and d is common difference

• n/2 ( 2A +( n - 1)d )

Here, n is no. of terms , a is first term d is common difference .

ANSWER:

SORRY BRO

Step-by-step EXPLANATION:

don't KNOW.........................

ANSWER:

How to reduce (SIMPLIFY) the common fraction 25/30 to its simplest equivalent form, irreducible? Result written as a PROPER fraction, as a decimal number and as a PERCENTAGE %

How to reduce (simplify) the common fraction: 25/30?

Result written as a proper fraction, as a decimal number and as a percentage.

ANSWER:

HINDI NHI qati kuajw wbwinwbwb sunwjwnwbwjwn whwjwjw

ANSWER:

THANKS for FREE POINTS

ANSWER:Volume of a cube = 3375 cm³

Measure of the EDGE of the cube = ³√3375 cm => 15 cm

Total surface area of a cube = 6 × (side)²

=> [6 × (15)²] cm²

=> [6 × 225] cm²

=> 1350 cm²

HOPE IT HELPS

ANSWER:

TING TONG TAND and BOOM answer is there

Answer:

we assume you mean the number in the exact middle of the two numbers on a number line, as illustrated below, where X=8 and Y=12.

Step-by-step explanation:

Halfway Between 8 and 12

When you ASK "What number is halfway between 8 and 12?" we assume you mean the number in the exact middle of the two numbers on a number line, as illustrated below, where X=8 and Y=12.

To find the number halfway between 8 and 12, we USE the following formula:

(X + Y)/2 = Halfway Between

When we enter 8 and 12 into our formula, we get:

(8 + 12)/2 = 10

Thus, the number halfway between 8 and 12 is 10.

To check that our answer is correct, we deduct 8 from 10 and deduct 10 from 12 and compare the two numbers:

10 - 8 = 12 - 10 = same = 2

As you can see, the halfway number is 2 higher than 8 and 2 LOWER than 12. THEREFORE, our halfway between answer of 10 above is correct.

PLS MARK AS BRAINLIEST

)prime FACTORIZATION method

2)long DIVISION method

totally there are 2 methods to FIND square root of a number

1)its LIKE lcm.you want to make a PAIR of same numbers and mention it as one and then multiply that numbers.

the third image is about the long division method.

ANSWER:

PLEASE EXPLAIN QUESTION properly

Step-by-step EXPLANATION:

2. The length of a rectangular hall is 4m LESS than 3 times the breadth of

the hall. What is the length, if the breadth is b meters?

i) 12b ii) 3b-4 iii) none of these iv) 3b+4

3. The __________ of the variable is an equation which satisfies the

equation is called a solution to the equation.

i) VALUE ii) factor iii) term iv) none of these

4. The SIDE of a SQUARE is . Its perimeter is

i) 3 ii) 2 iii) 4 iv) 6

<P>ANSWER:

a. p =1, 4,7,10..........88

an = a+(n-1) d

88=1+(n-1) 3

88=1+3n-3

88=-2+3n

90=3n

n=30

hope this will HELP U

Answer:

1. {(1,3) ,(2,3) ,(3,3) ,(4,3)}

2.{(3,3) ,(4,3)}

ANSWER:

don't understand the QUESTION PLEASE WRITE properly

Step-by-step explanation:

7/125

7×4/125×4

=28/1000

I.E 0.28

HENCE IT IS NON TERMINATING

plzz MARK as BRAINLIEST

Answer:

since

in quadrilateral

As the SUM of opposite angles of d Quadrilateral is 180degree,so its a cyclice QUARDRILATERAL , HENCE , B,C,E,D are CONCYCLIC i.e lie on circle

ANSWER:

ᴅᴏɴ'ᴛ ᴋɴᴏᴡ

ʙᴛ ᴊᴜsᴛ ᴡᴀɴᴛ ᴛᴏ ᴅɪᴇ

ɪғ ᴜ ᴡᴀɴᴛ ᴍᴇ ʜᴀᴘᴘʏ

ᴛʜᴇɴ ᴘʟᴢ ᴘʀᴀʏ ғᴏʀ ᴍʏ ᴅᴇᴀᴛʜ

ANSWER:

HOPE this WOULD be HELPFUL for you

ANSWER:

Step-by-step explanation: SIN square 30 degree+ 2TAN square 60 degree - 2sin square 30 degree

= (1/2)^2 + 2(√3)^2 - 2 (1/2)^2

= 1/4 + 2(3) - 2(1/4)

=1/4 + 6 - 1/2

= 23/4 (Ans.)

ANSWER:

order to verify the values are zeros of polynomial p(x), we must replace the variable x with the given values.

If p(x)=0, then that given value is zero of polynomial p(x).

(i) p(x)=3x+1:

Put x=−

3

1

, we get,

p(x)=p(

3

−1

)=3(−

3

1

)+1=−1+1=0.

So, x=−

3

1

is the zero of the given polynomial p(x).

(ii) p(x)=5x−π:

Put x=

5

4

, we get,

p(x)=p(

5

4

)=5(

5

4

)−π=4−π



=0.

So, x=

5

4

is not the zero of the given polynomial p(x).

(iii) p(x)=x

2

−1:

Put x=1, we get,

p(x)=p(1)=(1)

2

−1=1−1=0.

So, x=1 is the zero of the given polynomial p(x).

Now put x=−1, we get,

p(x)p(−1)=(−1)

2

−1=1−1=0.

So, x=−1 is the zero of the given polynomial p(x).

(iv) p(x)=(x+1)(x−2):

Put x=−1, we get,

p(x)=(−1+1)(−1−2)=0(−3)=0.

So, x=−1 is the zero of the given polynomial p(x).

Now put x=2, we get,

p(x)=(2+1)(2−2)=3(0)=0.

So, x=2 is the zero of the given polynomial p(x).

(v) p(x)=x

2

:

Put x=0, we get,

p(x)=p(0)=(0)

2

=0.

So, x=0 is the zero of the given polynomial p(x).

(VI) p(x)=lx+m:

Put x=−

L

m

, we get,

p(x)=p(−

l

m

)=l(−

l

m

)+m=−m+m=0.

So, x=−

l

m

is the zero of the given polynomial p(x).

(vii) p(x)=3x

2

−1:

Put x=−

3

1

, we get,

p(x)=p(−

3

1

)=3(−

3

1

)

2

−1=(3×

3

1

)−1=1−1=0.

So, x=−

3

1

is the zero of the given polynomial p(x).

Now put x=

3

2

, we get,

p(x)=p(

3

2

)=3(

3

2

)

2

−1=(3×

3

4

)−1=4−1=3



=0.

So, x=

3

2

is not the zero of the given polynomial p(x).

(VIII) p(x)=2x+1:

Put x=

2

1

, we get,

p(x)=p(

2

1

)=2(

2

1

)+1=1+1=2



=0.

So, x=

2

1

is not the zero of the given polynomial p(x). order to verify the values are zeros of polynomial p(x), we must replace the variable x with the given values.

If p(x)=0, then that given value is zero of polynomial p(x).

(i) p(x)=3x+1:

Put x=−

3

1

, we get,

p(x)=p(

3

−1

)=3(−

3

1

)+1=−1+1=0.

So, x=−

3

1

is the zero of the given polynomial p(x).

(ii) p(x)=5x−π:

Put x=

5

4

, we get,

p(x)=p(

5

4

)=5(

5

4

)−π=4−π



=0.

So, x=

5

4

is not the zero of the given polynomial p(x).

(iii) p(x)=x

2

−1:

Put x=1, we get,

p(x)=p(1)=(1)

2

−1=1−1=0.

So, x=1 is the zero of the given polynomial p(x).

Now put x=−1, we get,

p(x)p(−1)=(−1)

2

−1=1−1=0.

So, x=−1 is the zero of the given polynomial p(x).

(iv) p(x)=(x+1)(x−2):

Put x=−1, we get,

p(x)=(−1+1)(−1−2)=0(−3)=0.

So, x=−1 is the zero of the given polynomial p(x).

Now put x=2, we get,

p(x)=(2+1)(2−2)=3(0)=0.

So, x=2 is the zero of the given polynomial p(x).

(v) p(x)=x

2

:

Put x=0, we get,

p(x)=p(0)=(0)

2

=0.

So, x=0 is the zero of the given polynomial p(x).

(vi) p(x)=lx+m:

Put x=−

l

m

, we get,

p(x)=p(−

l

m

)=l(−

l

m

)+m=−m+m=0.

So, x=−

l

m

is the zero of the given polynomial p(x).

(vii) p(x)=3x

2

−1:

Put x=−

3

1

, we get,

p(x)=p(−

3

1

)=3(−

3

1

)

2

−1=(3×

3

1

)−1=1−1=0.

So, x=−

3

1

is the zero of the given polynomial p(x).

Now put x=

3

2

, we get,

p(x)=p(

3

2

)=3(

3

2

)

2

−1=(3×

3

4

)−1=4−1=3



=0.

So, x=

3

2

is not the zero of the given polynomial p(x).

(viii) p(x)=2x+1:

Put x=

2

1

, we get,

p(x)=p(

2

1

)=2(

2

1

)+1=1+1=2



=0.

So, x=

2

1

is not the zero of the given polynomial p(x).

ANSWER:

MEET with GOOGLE for this

ANSWER:

1 option is correct

Step-by-step explanation:

no explanation I am DUM sure about this

MARK as brainlisest answer

ANSWER:

thank

you

.............................

Answer:

The out COME will be

1,2,3,4,5,6.

And the PREDICTION of every out come is 1/6.

I hope you got your answer and understood that.

Thank you for giving me the opportunity to answer your question.

Please MARK me as brainlist

ANSWER:

answer isn’t in option.

And plz MARK my answer as brainliest

Step-by-step explanation:

3x+3y=9......(1)

5x+5y=7......(2)

(1)-(2)

-2x=2

so,x=-1

putting TGE VALUE of x in (1)

3×(-1)+3y=9

-3+3y=9

3y=9+3=12

so,y=4

therefore, x+y=-1+4=3

plz make your question correctly

ANSWER:

PLEASE MARK ME AS BRAINLIST

ANSWER:

PLEASE TRANSLATE it in ENGLISH

Answer:Two triangles are said to be similar if their corresponding angles are CONGRUENT and the corresponding sides are in PROPORTION . In other words, similar triangles are the same SHAPE, but not necessarily the same size. The triangles are congruent if, in ADDITION to this, their corresponding sides are of equal length

Step-by-step EXPLANATION:

ANSWER:

ggigigiggkvvkhkbkhvgiviov

ANSWER:

cosec^6 A - cot^6A = 3 cot^2A cosec^2A + 1

ANSWER:

idk

Step-by-step EXPLANATION:

Step-by-step EXPLANATION:

Welcome to Gboard clipboard, any text that you COPY will be SAVED here.

Given : Diagonal DF of a PARALLELOGRAM DEFG bisects angle D

To FIND : show that it bisects angle F

show that DEFG is a rhombus

Solution:

DEFG is a  parallogram

Hence

DE || FG

EF || DG

Diagonal DF  bisects angle D

=> ∠FDG = ∠FDE  =  (1/2) ∠D

DE || FG  and DF is transversal

=>  ∠FDE = ∠DFG

=> ∠DFG =  (1/2) ∠D

EF || DG and DF is transversal

=>  ∠FDG = ∠DFE

=> ∠DFE =   (1/2) ∠D

Hence ∠DFG =  ∠DFE =  (1/2) ∠D

∠DFG =  ∠DFE

∠DFG +  ∠DFE = ∠F

=>  ∠DFG =  ∠DFE = (1/2)  ∠F

=>DF bisects angle F

∠FDG   = ∠DFG

=> DG = FG

∠DFE =  ∠FDE

=> DE = EF

in  Δ GDF  & Δ EDF

DF = DF common

∠FDG = ∠FDE

∠DFG  =  ∠DFE

Δ GDF  ≅ Δ EDF    (ASA )

=> DG =  DE

DG = FG

DE = EF

DG =  DE

Hence DG = FG = DE = EF

Hence parallelogram DEFG is a rhombus

Learn More:

EFGH is a parallelogram.EI bisects angle E and GJ bisects angle G ...

brainly.in/question/14898796

Prove that the line drawn through the centre of a circle to BISECT a ...

brainly.in/question/27715057

Answer:

300

Step-by-step explanation:

   =   3×10² ====300

Hope you will like the answer.

I had DONE my best effort to GIVE you CORRECT answer.

If you are satisfied with the answer then you can MARK me brainliest.

Answer:

3.18×10^8

318000000

318×10^6

3.18×10^8

Step-by-step EXPLANATION:

MARK as BRANLIEST PLEASE

Answer:

For the collection, management, and distribution of gross social wealth, China has established comprehensive and systematic tax policies, which are being designed and developed.

2.

A minimum income is guaranteed for laborers. According to the provisions of laws and regulation, the country has enhanced laborers’ status during the PROCESS of production consumption and the labor process in management and service industries according to the laws and regulations. A system has been established for a regular minimum wage standard, which is developing.

3.

There is compulsory education. Among 1.3 billion Chinese people, a free education system has been implemented in primary schools and junior schools. As for vocational secondary schools, high schools, colleges, and universities, the basic expense for EDUCATIONAL consumption and the allowances for POVERTY stricken students are implemented and guaranteed by the central government.

4.

For national university research and education and major scientific research units, the country has increased investment with the charge of social consumption.

5.

For consumption on utility and public welfare projects, the country has provided allowances.

6.

For regions of lower living consumption, the country has allocated special funds from national finance to provide help for the alleviation and elimination of poverty. The country has also formulated relevant policies, such as free training in labor skills, scientific support, and poverty elimination.

7.

For poor urban residents, the country has allocated salvation funds to guarantee their minimum living consumption.

8.

Every YEAR, the country allocates considerable RELIEF funds for border areas, helping them shake off poverty and guaranteeing a certain living consumption level for them.

9.

The country advocates charity, mobilizing social power to help poor and vulnerable groups.

ANSWER:

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Step-by-step EXPLANATION:

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ANSWER:

B)INTERSECTING LINES