332354 + Interview Questions in Secondary School in Math

1.	Which of the following is irrationalA 0.17B √36/√3C √81D √20/√5plz give me as fast as possible
Answer» Answer: B is irrational Step-by-step explanation: 0.17 is rational √36/√3 = √12 which is irrational √81 = 9 which is rational √20/√5 = √4 = 2 which is rational Hope it helps you PLEASE MARK me as brainliest

1.

Which of the following is irrationalA 0.17B √36/√3C √81D √20/√5plz give me as fast as possible

Answer»

Answer:

B is irrational

Step-by-step explanation:

0.17 is rational

√36/√3 = √12 which is irrational

√81 = 9 which is rational

√20/√5 = √4 = 2 which is rational

Hope it helps you

PLEASE MARK me as brainliest

Discussion

2.	21. In the given figure, I im. ZEF8=2x+30º and ZFGD=X-700Find the angles LEFB and LEFA.
Answer» ANSWER: pls mark brilliant Step-by-step EXPLANATION: angle EFB = angle FGD because ab parralell to CD and eg ACT as a transversal 2x+30=x+70 x=40 thank you

2.

21. In the given figure, I im. ZEF8=2x+30º and ZFGD=X-700Find the angles LEFB and LEFA.

Answer»

ANSWER:

pls mark brilliant

Step-by-step EXPLANATION:

angle EFB = angle FGD because ab parralell to CD

and eg ACT as a transversal

2x+30=x+70

x=40

thank you

Discussion

3.	Check whether the pair of linear equations 5x - 4y + 8 = 0 and 7x + 6y-9=0 is consistentIf so solve the equations graphically.
Answer» ANSWER: X= -6/29 y= -202/116 Step-by-step EXPLANATION: $5x - 4y + 8 = 0 \: \: and \: \: 7x + 6y - 9 = 0 \\ 5x - 4y = - 8 ..........1 \\ 7x + 6y = 9...........2 \\ from \: equation \: 1 \: multiple \: with \: 3 \\ 15x -12y = - 24..........3 \\ from \: equation \: 2 \: multiple \: with \: \: 2 \\ 14x + 12y = 18...........4 \\ from \: \: equation \: 3 \: \: and \: \: 4 \: to \: sum \\ \: \: \: \: \: \: 15x - 12y = - 24 \\ + \: \: 14x + 12y = 18 \\ sum \: of \: equation \: is \: \\ 29x = - 6 \\ x = - 6 \div 29 \\ \\ the \: x \: value \: put \: in \: equation \: 1 \\ 5x - 4y = - 8 \\ 5 \times - 6 \div 29 - 4y= - 8 \\ - 30 \div 29 - 4y = - 8 \\ cross \: multiple \:i n \: left \\ 29 \times ( - 4y) - 30 \div 29 = - 8 \\ - 116y - 30 \div 29 = - 8 \\ - 116y - 30 = - 8 \times 29 \\ - 116y - 30 = - 232 \\ - 116y = - 232 + 30 \\ - 116y = - 202 \\ y = - 202 \div 116 \\$

3.

Check whether the pair of linear equations 5x - 4y + 8 = 0 and 7x + 6y-9=0 is consistentIf so solve the equations graphically.

Answer»

ANSWER:

X= -6/29 y= -202/116

Step-by-step EXPLANATION:

$5x - 4y + 8 = 0 \: \: and \: \: 7x + 6y - 9 = 0 \\ 5x - 4y = - 8 ..........1 \\ 7x + 6y = 9...........2 \\ from \: equation \: 1 \: multiple \: with \: 3 \\ 15x -12y = - 24..........3 \\ from \: equation \: 2 \: multiple \: with \: \: 2 \\ 14x + 12y = 18...........4 \\ from \: \: equation \: 3 \: \: and \: \: 4 \: to \: sum \\ \: \: \: \: \: \: 15x - 12y = - 24 \\ + \: \: 14x + 12y = 18 \\ sum \: of \: equation \: is \: \\ 29x = - 6 \\ x = - 6 \div 29 \\ \\ the \: x \: value \: put \: in \: equation \: 1 \\ 5x - 4y = - 8 \\ 5 \times - 6 \div 29 - 4y= - 8 \\ - 30 \div 29 - 4y = - 8 \\ cross \: multiple \:i n \: left \\ 29 \times ( - 4y) - 30 \div 29 = - 8 \\ - 116y - 30 \div 29 = - 8 \\ - 116y - 30 = - 8 \times 29 \\ - 116y - 30 = - 232 \\ - 116y = - 232 + 30 \\ - 116y = - 202 \\ y = - 202 \div 116 \\$

Discussion

4.	A tower stands vertically on the ground. From a point on the ground, which is 15 maway from the foot of the tower, the angle of elevation of the top of the tower is foundto be 30°. The height of the tower is :
Answer» ANSWER: i HOPE you LIKE it .....

4.

A tower stands vertically on the ground. From a point on the ground, which is 15 maway from the foot of the tower, the angle of elevation of the top of the tower is foundto be 30°. The height of the tower is :

Answer»

ANSWER:

i HOPE you LIKE it .....

Discussion

5.	Evalute (-11)x(-8)+(-15)=(-11)x(-8)+(-11)x15
Answer» ANSWER: hope it helps Step-by-step EXPLANATION: plz MARK me BRAINLIEST

5.

Evalute (-11)x(-8)+(-15)=(-11)x(-8)+(-11)x15

Answer»

ANSWER:

hope it helps

Step-by-step EXPLANATION:

plz MARK me BRAINLIEST

Discussion

6.	A square shaped picture is to be framed it's side is 29cm what length of the frame will be needed?
Answer» same LENGTH is needed because in SQUARE all sides are EQUAL MARK me has BRAINLEAST

6.

A square shaped picture is to be framed it's side is 29cm what length of the frame will be needed?

Answer»

same LENGTH is needed

because in SQUARE all sides are EQUAL

MARK me has BRAINLEAST

Discussion

7.	Billy has $80 dollars to go shopping with. he see a video game that cost $40 dollars. if billy buys the game what percent of his money would he be spending on it?
Answer» ANSWER: answer is 50% PLEASE FOLLOW me

7.

Billy has $80 dollars to go shopping with. he see a video game that cost $40 dollars. if billy buys the game what percent of his money would he be spending on it?

Answer»

ANSWER:

answer is 50% PLEASE FOLLOW me

Discussion

8.	One rounded of a square field of side s is 100m.how much is one side of the field
Answer» Answer: 100/4 =25 m Step-by-step EXPLANATION: MARK BRAINLIEST.

8.

One rounded of a square field of side s is 100m.how much is one side of the field

Answer»

Answer:

100/4

=25 m

Step-by-step EXPLANATION:

MARK BRAINLIEST.

Discussion

9.	Principle valoe of cos inverse -1/2
Answer» ANSWER: cos INVERSE in principal range varies from 0 to pi so principal VALUE of cos inverse -1/2 is 2π/3

9.

Principle valoe of cos inverse -1/2

Answer»

ANSWER:

cos INVERSE in principal range varies from 0 to pi

so principal VALUE of cos inverse -1/2 is 2π/3

Discussion

10.	2x+y=5&X+y=4 bu graphical methodman observes two vertical poles which are fixed opposite to each other on either side of the road if the width of the road is 90 and height of the pole are in the ratio 1 is to 2 also the angle of elevation of their top from a point between the line joining the foot of the pole on the road is 60 degree the height of the pole find
Answer» ANSWER: xfyzdfuf hf7fit9z0h 7gizu8t9t uf7r7tt9u uf7r7r7t6t ug7r7r8t iz7t7d uf6x6cjh xrfiv. ghfyzjn. hfuft zdzf

10.

2x+y=5&X+y=4 bu graphical methodman observes two vertical poles which are fixed opposite to each other on either side of the road if the width of the road is 90 and height of the pole are in the ratio 1 is to 2 also the angle of elevation of their top from a point between the line joining the foot of the pole on the road is 60 degree the height of the pole find

Answer»

ANSWER:

xfyzdfuf hf7fit9z0h 7gizu8t9t uf7r7tt9u uf7r7r7t6t ug7r7r8t iz7t7d uf6x6cjh xrfiv. ghfyzjn. hfuft zdzf

Discussion

11.	Suppose you purchased a car priced at 234 000 Pulas and you payed 180 000 Rands. What could have been the Rand/Pula exchange rate at the time of purchase
Answer» Answer: 54000, because 234000 - 180000

11.

Suppose you purchased a car priced at 234 000 Pulas and you payed 180 000 Rands. What could have been the Rand/Pula exchange rate at the time of purchase

Answer»

Answer:

54000, because 234000 - 180000

Discussion

12.	2510raised power minus4=?
Answer» Answer: Step-by-step explanation: Lets TAKE FIRST PART of equation: 2510 =100 Taking in account the second part, 100 to the POWER of -4 =(1/100)to the power of 4 =1/100000000 =0.00000001

12.

2510raised power minus4=?

Answer»

Answer:

Step-by-step explanation:

Lets TAKE FIRST PART of equation:

2*5*10

=100

Taking in account the second part,

100 to the POWER of -4

=(1/100)to the power of 4

=1/100000000

=0.00000001

Discussion

13.	If the supplement of an angle is 101 drgree, then find its complement.
Answer» Answer: 101 + 79 =180 79 + X = 90 x = 90-79 =11 ans = 11 degrees Step-by-step EXPLANATION:

13.

If the supplement of an angle is 101 drgree, then find its complement.

Answer»

Answer:

101 + 79 =180

79 + X = 90

x = 90-79 =11

ans = 11 degrees

Step-by-step EXPLANATION:

Discussion

14.	Given XY = 6cm, angle XYZ = 50° and angle ZXY = 70° , construct a triangle KST
Answer» ANSWER: FIRST take land of your father then suck it PROPERLY. Step-by-step EXPLANATION: masturbation of your father on your face..and taste it

14.

Given XY = 6cm, angle XYZ = 50° and angle ZXY = 70° , construct a triangle KST

Answer»

ANSWER:

FIRST take land of your father

then suck it PROPERLY.

Step-by-step EXPLANATION:

masturbation

of your father on your face..and taste it

Discussion

15.	Represent √6.5 on a number line and write the step
Answer» Step-by-step EXPLANATION: √26/2 this is your ANSWER

15.

Represent √6.5 on a number line and write the step

Answer»

Step-by-step EXPLANATION:

√26/2

this is your ANSWER

Discussion

16.	in triangle pqr and triangle def qr =ef angle p is 90 degree angle q = angle e =30 degree and angle f =60 degree is triangle pqr congruent to traingle def
Answer» ANSWER: read carefully than you GOT it Step-by-step explanation: FOLLOW me new HEAR IAM also follow you

16.

in triangle pqr and triangle def qr =ef angle p is 90 degree angle q = angle e =30 degree and angle f =60 degree is triangle pqr congruent to traingle def

Answer»

ANSWER:

read carefully than you GOT it

Step-by-step explanation:

FOLLOW me new HEAR IAM also follow you

Discussion

17.	Please help to solve this que
Answer» ANSWER: I don't know but plzzzzxzzzzzzzzzzzzzz ark me as BRAINLEST than I will like all UR answer because ... a friend in NEED is a friend indead .

17.

Please help to solve this que

Answer»

ANSWER:

I don't know but plzzzzxzzzzzzzzzzzzzz ark me as BRAINLEST than I will like all UR answer because ...

a friend in NEED is a friend indead .

Discussion

18.	The distance b/w A & B is 211 km.One boat starts moving from point Atowards B in downstream at 7:45amAfter one hour another boat startsfrom the point B towards A.At12:45 pm both boats will meet.It speed of boat first and secondis 26 km/hr and 18 km/hr dein still water then find the speedof Current
Answer» $Distance \: between \:A \:and \:B = 211 \:km$ $Let \: speed \: of \:Current = x \:kmph$ $\underline { \blue { Case \: 1 : }}$ $\pink { ( Moving \: downstream )}$ $Speed \:of \:the \: first \:boat = 26 \: kmph$ $Relative \:speed \:of \:the \:boat (s_{1})\\ = (26+x) \:kmph$ $Time \:to \:meet \: second \:boat = 5\:hours$ $\blue { ( From \: 7.45 \:am \:to \: 12.45 \:pm = 5 hr )}$ $Distance \: travelled (d_{1}) = speed \times Time \\= (26+x)5 \:km \: ---(1)$ $\underline { \blue { Case \: 2: }}$ $\pink { ( Moving \: Upstream )}$ $Speed \:of \:the \: Second \:boat = 18 \: kmph$ $Relative \:speed \:of \:the \:boat (s_{2})\\ = (18-x) \:kmph$ $Time \:to \:meet \: second \:boat = 4\:hours$ $\blue { ( From \: 8.45 \:am \:to \: 12.45 \:pm = 4 hr )}$ $Distance \: travelled ( d_{2})= speed \times Time \\= (18-x)4 \:km \: ---(2)$ /* ACCORDING to the PROBLEM GIVEN */ $d_{1} + d_{2} = 211 \:km$ $\implies (26+x)5 + (18-x)4 = 211$ $\implies 130 + 5x + 72 - 4x = 211$ $\implies x + 202 = 211$ $\implies x = 211 - 202$ $\implies x = 9 \:kmph$ THEREFORE., $\red { Speed \:of \:the \: Current } \green { = 9 \:kmph }$ •••♪

18.

The distance b/w A & B is 211 km.One boat starts moving from point Atowards B in downstream at 7:45amAfter one hour another boat startsfrom the point B towards A.At12:45 pm both boats will meet.It speed of boat first and secondis 26 km/hr and 18 km/hr dein still water then find the speedof Current

Answer»

$Distance \: between \:A \:and \:B = 211 \:km$

$Let \: speed \: of \:Current = x \:kmph$

$\underline { \blue { Case \: 1 : }}$

$\pink { ( Moving \: downstream )}$

$Speed \:of \:the \: first \:boat = 26 \: kmph$

$Relative \:speed \:of \:the \:boat (s_{1})\\ = (26+x) \:kmph$

$Time \:to \:meet \: second \:boat = 5\:hours$

$\blue { ( From \: 7.45 \:am \:to \: 12.45 \:pm = 5 hr )}$

$Distance \: travelled (d_{1}) = speed \times Time \\= (26+x)5 \:km \: ---(1)$

$\underline { \blue { Case \: 2: }}$

$\pink { ( Moving \: Upstream )}$

$Speed \:of \:the \: Second \:boat = 18 \: kmph$

$Relative \:speed \:of \:the \:boat (s_{2})\\ = (18-x) \:kmph$

$Time \:to \:meet \: second \:boat = 4\:hours$

$\blue { ( From \: 8.45 \:am \:to \: 12.45 \:pm = 4 hr )}$

$Distance \: travelled ( d_{2})= speed \times Time \\= (18-x)4 \:km \: ---(2)$

/* ACCORDING to the PROBLEM GIVEN */

$d_{1} + d_{2} = 211 \:km$

$\implies (26+x)5 + (18-x)4 = 211$

$\implies 130 + 5x + 72 - 4x = 211$

$\implies x + 202 = 211$

$\implies x = 211 - 202$

$\implies x = 9 \:kmph$

THEREFORE.,

$\red { Speed \:of \:the \: Current } \green { = 9 \:kmph }$

•••♪

Discussion

19.	13. Area of a rectangle with length 4ab and breadth 66% ism
Answer» ANSWER: AREA of rectangle is 2.64ab Step-by-step explanation: length = 4ab breadth = 66% AREAA of rectangle =length × width = 4ab × 66 / 100 = 2.64 ab

19.

13. Area of a rectangle with length 4ab and breadth 66% ism

Answer»

ANSWER:

AREA of rectangle is 2.64ab

Step-by-step explanation:

length = 4ab

breadth = 66%

AREAA of rectangle =length × width

= 4ab × 66 / 100

= 2.64 ab

Discussion

20.	Solution of question no F
Answer» I HOPE this was HELPFUL

20.

Solution of question no F

Answer»

I HOPE this was HELPFUL

Discussion

21.	Convert the following 150cm into km
Answer» Answer: 0.0015 KM Step-by-step explanation: 1 km = 100000 CM 150 cm = $\frac{150}{100000}$ km =0.0015 km

21.

Convert the following 150cm into km

Answer»

Answer:

0.0015 KM

Step-by-step explanation:

1 km = 100000 CM

150 cm = $\frac{150}{100000}$ km

=0.0015 km

Discussion

22.	A school has 657 students. There are 384 pupils in Year 9 or above and there are 376 students in Year 9 and below. How many students are there in Year 9?
Answer» Step-by-step explanation: FIRST NUMBER OF STUDENT 384+376=760 PRESENT TIME STUDENT 760-657 STUDENT 103 STUDENTS IN YEAR 9

22.

A school has 657 students. There are 384 pupils in Year 9 or above and there are 376 students in Year 9 and below. How many students are there in Year 9?

Answer»

Step-by-step explanation:

FIRST NUMBER OF STUDENT

384+376=760

PRESENT TIME STUDENT

760-657 STUDENT

103 STUDENTS IN YEAR 9

Discussion

23.	Find the area of this triangle.please answer with full explanation
Answer» LET's bring the FORMULA into our MEMORY once again. Area of a triangle = 1/2 × BASE × height Am I Right? YES (^_-) In the given figure, PS is the height of ∆PQR and QR is its base. Given, PS = 2 cm and QR = 4 cm so, area of ∆PQR = (1/2 × 4 × 2) cm² = 4 cm² Done!

23.

Find the area of this triangle.please answer with full explanation

Answer»

LET's bring the FORMULA into our MEMORY once again.

Area of a triangle = 1/2 × BASE × height

Am I Right?

YES (^_-)

In the given figure, PS is the height of ∆PQR and QR is its base.

Given, PS = 2 cm and QR = 4 cm

so, area of ∆PQR = (1/2 × 4 × 2) cm² = 4 cm²

Done!

Discussion

24.	Solve the following, i.e,factorise the following:-
Answer» ANSWER: - Step-by-step EXPLANATION: Here is your answer. I GOT answer as 1.

24.

Solve the following, i.e,factorise the following:-

Answer»

ANSWER:

-

Step-by-step EXPLANATION:

Here is your answer. I GOT answer as 1.

Discussion

25.	Write a letter to yourBuend about summer camp
Answer» Answer: Dear Michael, Thank you for your recent letter. It is so wonderful to hear from you! I am very GLAD that you had a good vacation. As for me, I also spent a wonderful vacation. First, I lived with my parents in the garden. The weather was hot and I swam a LOT with my friends. We played soccer and rode bicycles. And in August we WENT to Cyprus with my parents. It is a large island in the Mediterranean with a wonderful climate. We swam in the SEA and were lying in the shade of huge eucalyptus trees. We traveled along the mountain paths and played tennis. Anyway, it was a MEMORABLE summer. How did your academic year begin? Are there newcomers in your class? Any new subjects? I’m sorry, I have to go to the sports section. All the best! IYAN

25.

Write a letter to yourBuend about summer camp

Answer»

Answer:

Dear Michael,

Thank you for your recent letter. It is so wonderful to hear from you! I am very GLAD that you had a good vacation.

As for me, I also spent a wonderful vacation. First, I lived with my parents in the garden. The weather was hot and I swam a LOT with my friends. We played soccer and rode bicycles.

And in August we WENT to Cyprus with my parents. It is a large island in the Mediterranean with a wonderful climate. We swam in the SEA and were lying in the shade of huge eucalyptus trees. We traveled along the mountain paths and played tennis. Anyway, it was a MEMORABLE summer.

How did your academic year begin? Are there newcomers in your class? Any new subjects?

I’m sorry, I have to go to the sports section.

All the best!

IYAN

Discussion

26.	12cmQuestions 25 to 28 carries 6 marks each.Check whether the pair of linear equations 5x – 4y + 8 = 0 and 7x + 6y - 9 =0 is consistent.If so solve the equations Plzzz graphically kar k dikhdo . plzz
Answer» ANSWER: DBDB GDB shberh dhrfbb svdj

26.

12cmQuestions 25 to 28 carries 6 marks each.Check whether the pair of linear equations 5x – 4y + 8 = 0 and 7x + 6y - 9 =0 is consistent.If so solve the equations Plzzz graphically kar k dikhdo . plzz

Answer»

ANSWER:

DBDB GDB shberh dhrfbb svdj

Discussion

27.	(ii) A peacock is sitting on the tree and observes its prey onthe ground. It makes an angle of depression of 22° tocatch the prey. The speed of the peacock was observed tobe 10 km/hr and it catches its prey in 1 min 12 seconds.At what height was the peacock on the tree?(cos 22° = 0.927, sin 22° = 0.374, tan 22° = 0.404)
Answer» $\bold{\large{\underline{\underline{\rm{\red{AnsWer:}}}}}}$ $\bold{\boxed{\tt{\blue{Peacock\:was\:at\:a\:height\:of\:74.8\:m}}}}$ Given : Angle of depression = 22° Speed of the peacock = 10 km/hr TIME TAKEN by the peacock to catch the prey = 1 min 12 SECONDS = 60 sec + 12 sec = 72 seconds. COS 22° = 0.927 Sin 22° = 0.374 Tan 22° = 0.404 To Find : Height at which the peacock was initially on the tree. Solution : AC is the distance covered by the peacock to reach out to the prey. We can calculate AC using the relation between speed, time and distance. $\bold{\sf{\large{\red{\boxed{Distance,AC\:=\:Speed\:\times\:Time}}}}}$ Block in the available DATA, ➟ $\mathtt{AC\:=\:10\:\times\:{\dfrac{72}{3600}}}$ ➟ $\mathtt{AC\:=\:{\dfrac{72}{360}}}$ ➟ $\mathtt{AC=\:{\dfrac{1}{5}}}$ ➟ $\mathtt{AC\:=\:0.2}$ AC = 0.2 km Change km into m : 1 km = 1000 m ➟ $\mathtt{0.2\:\times\:1000}$ ➟ $\mathtt{200\:m}$ $\sf{\therefore{\underline{AC\:=\:200\:m}}}$ CD is the height at which the peacock was initially. Let CD = x m. In right angled Δ CDA, $\theta$ = 22° ➟ $\mathtt{Sin\:\theta\:=\:{\dfrac{Opposite\:side\:to\:\theta}{Hypotenuse}}}$ ➟ $\mathtt{Sin\:22\:\degree\:=\:{\dfrac{CD}{200}}}$ ➟ $\mathtt{0.374\:=\:{\dfrac{x}{200}}}$ ➟ $\mathtt{0.374\:\times\:200\:=\:x}$ ➟ $\mathtt{74.8\:m\:=\:x}$ $\sf{\therefore{\underline{Height\:at\:which\:peacock\:was\:on\:the\:tree\:=\:CD\:=\:74.8\:m}}}$

27.

(ii) A peacock is sitting on the tree and observes its prey onthe ground. It makes an angle of depression of 22° tocatch the prey. The speed of the peacock was observed tobe 10 km/hr and it catches its prey in 1 min 12 seconds.At what height was the peacock on the tree?(cos 22° = 0.927, sin 22° = 0.374, tan 22° = 0.404)

Answer»

$\bold{\large{\underline{\underline{\rm{\red{AnsWer:}}}}}}$

$\bold{\boxed{\tt{\blue{Peacock\:was\:at\:a\:height\:of\:74.8\:m}}}}$

Given :

Angle of depression = 22°
Speed of the peacock = 10 km/hr
TIME TAKEN by the peacock to catch the prey = 1 min 12 SECONDS = 60 sec + 12 sec = 72 seconds.
COS 22° = 0.927
Sin 22° = 0.374
Tan 22° = 0.404

To Find :

Height at which the peacock was initially on the tree.

Solution :

AC is the distance covered by the peacock to reach out to the prey.

We can calculate AC using the relation between speed, time and distance.

$\bold{\sf{\large{\red{\boxed{Distance,AC\:=\:Speed\:\times\:Time}}}}}$

Block in the available DATA,

➟ $\mathtt{AC\:=\:10\:\times\:{\dfrac{72}{3600}}}$

➟ $\mathtt{AC\:=\:{\dfrac{72}{360}}}$

➟ $\mathtt{AC=\:{\dfrac{1}{5}}}$

➟ $\mathtt{AC\:=\:0.2}$

AC = 0.2 km

Change km into m :

1 km = 1000 m

➟ $\mathtt{0.2\:\times\:1000}$

➟ $\mathtt{200\:m}$

$\sf{\therefore{\underline{AC\:=\:200\:m}}}$

CD is the height at which the peacock was initially.

Let CD = x m.

In right angled Δ CDA,

$\theta$ = 22°

➟ $\mathtt{Sin\:\theta\:=\:{\dfrac{Opposite\:side\:to\:\theta}{Hypotenuse}}}$

➟ $\mathtt{Sin\:22\:\degree\:=\:{\dfrac{CD}{200}}}$

➟ $\mathtt{0.374\:=\:{\dfrac{x}{200}}}$

➟ $\mathtt{0.374\:\times\:200\:=\:x}$

➟ $\mathtt{74.8\:m\:=\:x}$

$\sf{\therefore{\underline{Height\:at\:which\:peacock\:was\:on\:the\:tree\:=\:CD\:=\:74.8\:m}}}$

Discussion

28.	the present population of a village is 62500 if it's population decrease by 4%every year what will be it's population after 2 years
Answer» Answer: 57500 MARK BRAINLIEST. Step-by-step explanation: 4/100 * 62500= 6254=2500 Total no of decrease after two years =22500 = 5000 Total no of PEOPLE after two years. =62500-5000 =57500

28.

the present population of a village is 62500 if it's population decrease by 4%every year what will be it's population after 2 years

Answer»

Answer:

57500

MARK BRAINLIEST.

Step-by-step explanation:

4/100 * 62500= 625*4=2500

Total no of decrease after two years

=2*2500

= 5000

Total no of PEOPLE after two years.

=62500-5000

=57500

Discussion

29.	Represent root 6.2 on number line
Answer» Step-by-step explanation: Draw a line of 6.2cm now EXTEND it one cm now MAKE perpendicular bisector of that line now FRO mid point draw a semi CIRCLE now make 90° on the point of 6.2 cm extend it to TOUCH the circle measure it by compass and draw it place where it meets the line is √6.2 Plz mark as brainliest

29.

Represent root 6.2 on number line

Answer»

Step-by-step explanation:

Draw a line of 6.2cm
now EXTEND it one cm
now MAKE perpendicular bisector of that line
now FRO mid point draw a semi CIRCLE
now make 90° on the point of 6.2 cm
extend it to TOUCH the circle
measure it by compass and draw it
place where it meets the line is √6.2

Plz mark as brainliest

Discussion

30.	Plz answer fast ...........
Answer» Answer: x=20cm Step-by-step explanation: Before moving to QUESTION LETS see what is perimeter. "PERIMETER" Perimeter is the sum of sides of the closed figure in which a given area is bounded. IT can be calculated by some FUNDAMENTAL FORMULAES Or manually by adding the sides. WHAT IS TRAPEZIUM. Trapezium is the figure in which one opposite side is parallel and two other sides are joining to make it a polygon. Now, Lets understand the question in a very easy way by which you will surely understand how to solve such questions. See, Here a trapezium is given with the dimensions as, x,x,x+10,x+2 Now, As discussed above PERIMETER is the sum of sides bounded. So, sum of perimeter is=92cm. And DIMENSIONS are x,x,x+2,x+10 adding them and equalling to 92cm will give the value of x and we will be able to find out all the sided of trapezium. HERE WE GO, =>x+x+x+2+x+10=92cm =>4x+12=92 =>4x=92-12 =>4x=80 =>x=80/4 =>x=20cm NOW AS WE HAVE GOT THE VALUE OF "X" So,we can easily find the values of other sides as:") 1st side=20cm 2nd side=x+2 =>20+2 2nd side=22cm 3rd side=x=20cm. 4th side=x+10 =>20+10 =>30cm. These are the dimensions of Trapezium. VERIFICation:- sum of sides should be equal to":" 92cm. =>20+20+22+30=92cm. thus which is the required perimeter. ans.

30.

Plz answer fast ...........

Answer»

Answer:

x=20cm

Step-by-step explanation:

Before moving to QUESTION LETS see what is perimeter.

"PERIMETER"

Perimeter is the sum of sides of the closed figure in which a given area is bounded.

IT can be calculated by some FUNDAMENTAL FORMULAES Or manually by adding the sides.

WHAT IS TRAPEZIUM.

Trapezium is the figure in which one opposite side is parallel and two other sides are joining to make it a polygon.

Now,

Lets understand the question in a very easy way by which you will surely understand how to solve such questions.

See,

Here a trapezium is given with the dimensions as,

x,x,x+10,x+2

Now,

As discussed above PERIMETER is the sum of sides bounded.

So,

sum of perimeter is=92cm.

And DIMENSIONS are

x,x,x+2,x+10

adding them and equalling to 92cm will give the value of x and we will be able to find out all the sided of trapezium.

HERE WE GO,

=>x+x+x+2+x+10=92cm

=>4x+12=92

=>4x=92-12

=>4x=80

=>x=80/4

=>x=20cm

NOW AS WE HAVE GOT THE VALUE OF "X"

So,we can easily find the values of other sides as:")

1st side=20cm

2nd side=x+2

=>20+2

2nd side=22cm

3rd side=x=20cm.

4th side=x+10

=>20+10

=>30cm.

These are the dimensions of Trapezium.

VERIFICation:-

sum of sides should be equal to":"

92cm.

=>20+20+22+30=92cm.

thus which is the required perimeter.

ans.

Discussion

31.	Conbent the complex number z=1+iroot3 into polar form
Answer» Step-by-step EXPLANATION: your ANSWER ATTACHED in the PHOTO

31.

Conbent the complex number z=1+iroot3 into polar form

Answer»

Step-by-step EXPLANATION:

your ANSWER ATTACHED in the PHOTO

Discussion

32.	What is the formula of surface area of square
Answer» ANSWER: SIDE x side Step-by-step EXPLANATION: MARK BRAINLIEST.

32.

What is the formula of surface area of square

Answer»

ANSWER:

SIDE x side

Step-by-step EXPLANATION:

MARK BRAINLIEST.

Discussion

33.	Find the mean of the following data 3+ 5+7+9+11+13+15
Answer» ANSWER: Step-by-step EXPLANATION: ITS ALL THE ODD NUMBERS SO ANSWER IS 63

33.

Find the mean of the following data 3+ 5+7+9+11+13+15

Answer»

ANSWER:

Step-by-step EXPLANATION:

ITS ALL THE ODD NUMBERS SO ANSWER IS 63

Discussion

34.	Resolve 4(ab+cd)^2 – (a^2+b^2-c^2-d^2)^2 into four factors.
Answer» (c+d+a-b)(c+d-a+b)(a+b+c-d)(a+b-c+d)

Discussion

35.	Fill in the blanks who can solve it
Answer» Answer: 2nd wala samajh NHI AA rha KYA LIKH rakha h

35.

Fill in the blanks who can solve it

Answer»

Answer:

2nd wala samajh NHI AA rha KYA LIKH rakha h

Discussion

36.	Convert the following 5m into mm&km?
Answer» Answer: 5m=5000mm,0.005km Thanks

36.

Convert the following 5m into mm&km?

Answer»

Answer:

5m=5000mm,0.005km

Thanks

Discussion

37.	2. Prove thatSin 5x-2Sin 3x +Sin x÷Cos5x -Cosx=tanx
Answer» Step-by-step EXPLANATION: your ANSWER ATTACHED in the PHOTO

37.

2. Prove thatSin 5x-2Sin 3x +Sin x÷Cos5x -Cosx=tanx

Answer»

Step-by-step EXPLANATION:

your ANSWER ATTACHED in the PHOTO

Discussion

38.	UN TCsum of them of the squares of their reciprocals, then prove that 2a-c = c-the area of a rectangle reduces by 20 m², if its length is increasebreadth is reduced by 2 m. The area increases by 12 m², if the 1by 3 m and the breadth is increased by 4 m. Find the dimensionsAmong the group of students 10% scored marks below 20, 20between 20 and 40, 35% scored marks between 40 and 60, 20between 60 and 80. The remaining 30 students scored marks bet-Prepare frequency distribution table and draw a histogram.ve any one of the following subquestions :The following table shows the frequency table of literacy rate25 mitian Dind the moon literrote by acoumed mann metho
Answer» ANSWER: =(L+1)(B-2)=LB-20 =LB-2L+B-2=LB-20 =B=2L-18 ---------------eq(1) =(L-3)(B+4)=LB+12 =LB+4L-3B-12=LB+12 =4L-3B=24 =4L-3(2L-18)=24 ----------from eq(1) =4L-6L+54=24 =-2L=24-54 =-2L=-30 =L=15M In eq(1), B=2L-18 B=(2×15)-18 B=30-18 B=12 m Thus, LENGTH is 15m and Breadth is 12m. Read more on Brainly.in - brainly.in/question/13393693#readmore

38.

UN TCsum of them of the squares of their reciprocals, then prove that 2a-c = c-the area of a rectangle reduces by 20 m², if its length is increasebreadth is reduced by 2 m. The area increases by 12 m², if the 1by 3 m and the breadth is increased by 4 m. Find the dimensionsAmong the group of students 10% scored marks below 20, 20between 20 and 40, 35% scored marks between 40 and 60, 20between 60 and 80. The remaining 30 students scored marks bet-Prepare frequency distribution table and draw a histogram.ve any one of the following subquestions :The following table shows the frequency table of literacy rate25 mitian Dind the moon literrote by acoumed mann metho

Answer»

ANSWER:

=(L+1)(B-2)=LB-20

=LB-2L+B-2=LB-20

=B=2L-18 ---------------eq(1)

=(L-3)(B+4)=LB+12

=LB+4L-3B-12=LB+12

=4L-3B=24

=4L-3(2L-18)=24 ----------from eq(1)

=4L-6L+54=24

=-2L=24-54

=-2L=-30

=L=15M

In eq(1), B=2L-18

B=(2×15)-18

B=30-18

B=12 m

Thus, LENGTH is 15m and Breadth is 12m.

Read more on Brainly.in - brainly.in/question/13393693#readmore

Discussion

39.	The range of the 13 5 8 6 13 4 14 is
Answer» Answer: 10 Step-by-step EXPLANATION: RANGE is 10 highest - LOWEST 14-4=10

39.

The range of the 13 5 8 6 13 4 14 is

Answer»

Answer:

10

Step-by-step EXPLANATION:

RANGE is 10

highest - LOWEST

14-4=10

Discussion

40.	Pls help me to solve this problem
Answer» ANSWER: $17 - 3x \div 5 - 4x + 2 \div 3 = 5 - 6x + 7x + 14 \div 3 \\17 - 3x \div 5 = 5 - 6x + 7x + 14 \div 3 + 4x + 2 \div 3 \\ 17 - 3x \div 5 = 5 - 6x + 11x + 16 \div 3 \\ 17 - 3x \div 5 = 15 - 18x + 11x + 16 \div 3 \\ 17 - 3x \div 5 = 31 - 7x \div 3(cross \: multiple) \\ (17 - 3x) \times 3 = (31 - 7x) \times 5 \\ 51 - 9x = 155 - 35x \\ 51 - 155 = - 35x + 9x \\ - 104 = - 26x \\ x = - 104 \div - 26 \\ x = 4$

40.

Pls help me to solve this problem

Answer»

ANSWER:

$17 - 3x \div 5 - 4x + 2 \div 3 = 5 - 6x + 7x + 14 \div 3 \\17 - 3x \div 5 = 5 - 6x + 7x + 14 \div 3 + 4x + 2 \div 3 \\ 17 - 3x \div 5 = 5 - 6x + 11x + 16 \div 3 \\ 17 - 3x \div 5 = 15 - 18x + 11x + 16 \div 3 \\ 17 - 3x \div 5 = 31 - 7x \div 3(cross \: multiple) \\ (17 - 3x) \times 3 = (31 - 7x) \times 5 \\ 51 - 9x = 155 - 35x \\ 51 - 155 = - 35x + 9x \\ - 104 = - 26x \\ x = - 104 \div - 26 \\ x = 4$

Discussion

41.	Practice Through the midpointparallelogram ABCDintersecting AC in L arProve that EL = 2 BL.CD oforam ABCD, the line BM is drawnng AC in L and AD produced in E.
Answer» gggggggoooooooooddddddd qqquuuueeeessssiiiiiooooonnnnn

41.

Practice Through the midpointparallelogram ABCDintersecting AC in L arProve that EL = 2 BL.CD oforam ABCD, the line BM is drawnng AC in L and AD produced in E.

Answer»

gggggggoooooooooddddddd qqquuuueeeessssiiiiiooooonnnnn

Discussion

42.	Bought 40 Chair at the rate of 200 rs each he kept 4 chair for his use and sold the other at rate of 240 rs find profit and loss
Answer» COST PRICE OF 1 CHAIR IS RS 200 COST PRICE OF 400 CHAIRS IS RS 8000 REMAINING CHAIRS ARE 36 SELLING PRICE OF ONE CHAIR IS RS 240 SELLING PRICE OF 36 CHAIRS IS RS 8640 PROFIT OF RS 640

42.

Bought 40 Chair at the rate of 200 rs each he kept 4 chair for his use and sold the other at rate of 240 rs find profit and loss

Answer»

COST PRICE OF 1 CHAIR IS RS 200

COST PRICE OF 400 CHAIRS IS RS 8000

REMAINING CHAIRS ARE 36

SELLING PRICE OF ONE CHAIR IS RS 240

SELLING PRICE OF 36 CHAIRS IS RS 8640

PROFIT OF RS 640

Discussion

43.	Sumitra has 34 in 50-paise and 25-paise coins. If the number of 25-paise coinsIs twice the number of 50-paise coins, how many coins of each kind does shehave?
Answer» ANSWER------- Let Sumitra has 'x' 50-paise coins & 'y' 25-paise coins. She has rs 34 So rs 1 = 100 paise rs 34 = 34100 = 3400 paise 50x + 25Y = 3400 ----------- (1) Given that , y = 2X ------------(2) from equation (1) & (2) we get 50x + 25(2x) = 3400 50x + 50x = 3400 100x = 3400 x = 34 From (2) we get y = 2x = 2*34 = 68 So, NUMBER of 50-paise coins = 34 Number of 25-paise coins = 68 HOPE IT HELPS YOU MARK AS BRAINLIEST

43.

Sumitra has 34 in 50-paise and 25-paise coins. If the number of 25-paise coinsIs twice the number of 50-paise coins, how many coins of each kind does shehave?

Answer»

ANSWER-------

Let Sumitra has 'x' 50-paise coins & 'y' 25-paise coins.

She has rs 34

So rs 1 = 100 paise

rs 34 = 34*100 = 3400 paise

50x + 25Y = 3400 ----------- (1)

Given that , y = 2X ------------(2)

from equation (1) & (2) we get

50x + 25*(2x) = 3400

50x + 50x = 3400

100x = 3400

x = 34

From (2) we get

y = 2x = 2*34 = 68

So,

NUMBER of 50-paise coins = 34

Number of 25-paise coins = 68

HOPE IT HELPS YOU

MARK AS BRAINLIEST

Discussion

44.	The 2 roots of a quadratic equation are 3 and4.The equation is....................'
Answer» Answer: let the TWO roots are ALFA and beta hence, alfa=3 and beta= 4 therefore, alfa + beta= 3+4= 7 alfa × beta= 3×4=12 we know that X2 - (alfa + beta)x + alfa× beta=0 hence substituting the values x2 - 7X + 12=0 is the equation (please take note that I have written 2 as SQUARE )

44.

The 2 roots of a quadratic equation are 3 and4.The equation is....................'

Answer»

Answer:

let the TWO roots are ALFA and beta

hence, alfa=3 and beta= 4

therefore,

alfa + beta= 3+4= 7

alfa × beta= 3×4=12

we know that

X2 - (alfa + beta)x + alfa× beta=0

hence substituting the values

x2 - 7X + 12=0 is the equation

(please take note that I have written 2 as SQUARE )

Discussion

45.	) Convert the area of 56 km square into square meters.
Answer» Answer: 56000000 SQUARE METERS

45.

) Convert the area of 56 km square into square meters.

Answer»

Answer:

56000000 SQUARE METERS

Discussion

46.	Which of the following is not a mathemathematical process
Answer» ANSWER: PLEASE COMPLETE your question Step-by-step EXPLANATION:

46.

Which of the following is not a mathemathematical process

Answer»

ANSWER:

PLEASE COMPLETE your question

Step-by-step EXPLANATION:

Discussion

47.	Root5+root2 upon root 5-root2=a+b root 10
Answer» Answer: 62777hiijs&**_77r7474478299h6gggh98

47.

Root5+root2 upon root 5-root2=a+b root 10

Answer»

Answer:

62777hiijs&**_77r7474478299h6gggh98

Discussion

48.	Without practice mathematics is blind
Answer» YES REALLY WITHOUT PRACTICE MATHS is blind follow me

48.

Without practice mathematics is blind

Answer»

YES REALLY WITHOUT PRACTICE MATHS is blind

follow me

Discussion

49.	Cost of an item 50 with 12 percent profit calculate the selling price
Answer» Answer: RUPEES 56 Step-by-step explanation: COST Price = rupees 50 > given Profit = 12% of the cost > given Profit = (12×50)/100 = 12/2 = 6 So The Selling Price = 50 + 6 = 56

49.

Cost of an item 50 with 12 percent profit calculate the selling price

Answer»

Answer: RUPEES 56

Step-by-step explanation:

COST Price = rupees 50 > given

Profit = 12% of the cost > given

Profit = (12×50)/100 = 12/2 = 6

So

The Selling Price = 50 + 6 = 56

Discussion

50.	Give simple tricks for probability
Answer» ANSWER: PROBABILITY =no. of FAVOURABLE CONDITIONS ÷total no. of conditions.

50.

Give simple tricks for probability

Answer»

ANSWER:

PROBABILITY =no. of FAVOURABLE CONDITIONS ÷total no. of conditions.

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

Which of the following is irrationalA 0.17B √36/√3C √81D √20/√5plz give me as fast as possible

Answer:

B is irrational

Step-by-step explanation:

0.17 is rational

√36/√3 = √12 which is irrational

√81 = 9 which is rational

√20/√5 = √4 = 2 which is rational

Hope it helps you

PLEASE MARK me as brainliest

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Plz mark as brainliest

Plz answer fast ...........​

"PERIMETER"

WHAT IS TRAPEZIUM.

VERIFICation:-

92cm.

Conbent the complex number z=1+iroot3 into polar form​

What is the formula of surface area of square

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ITS ALL THE ODD NUMBERS SO ANSWER IS 63

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Fill in the blanks who can solve it​

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Thanks

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The range of the 13 5 8 6 13 4 14 is​

Pls help me to solve this problem

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ANSWER-------

HOPE IT HELPS YOU

MARK AS BRAINLIEST

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) Convert the area of 56 km square into square meters.​

Which of the following is not a mathemathematical process

Root5+root2 upon root 5-root2=a+b root 10

Without practice mathematics is blind

Cost of an item 50 with 12 percent profit calculate the selling price

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