The distance b/w A & B is 211 km.One boat starts moving from point Ato

1.	The distance b/w A & B is 211 km.One boat starts moving from point Atowards B in downstream at 7:45amAfter one hour another boat startsfrom the point B towards A.At12:45 pm both boats will meet.It speed of boat first and secondis 26 km/hr and 18 km/hr dein still water then find the speedof Current
Answer» $Distance \: between \:A \:and \:B = 211 \:km$ $Let \: speed \: of \:Current = x \:kmph$ $\underline { \blue { Case \: 1 : }}$ $\pink { ( Moving \: downstream )}$ $Speed \:of \:the \: first \:boat = 26 \: kmph$ $Relative \:speed \:of \:the \:boat (s_{1})\\ = (26+x) \:kmph$ $Time \:to \:meet \: second \:boat = 5\:hours$ $\blue { ( From \: 7.45 \:am \:to \: 12.45 \:pm = 5 hr )}$ $Distance \: travelled (d_{1}) = speed \times Time \\= (26+x)5 \:km \: ---(1)$ $\underline { \blue { Case \: 2: }}$ $\pink { ( Moving \: Upstream )}$ $Speed \:of \:the \: Second \:boat = 18 \: kmph$ $Relative \:speed \:of \:the \:boat (s_{2})\\ = (18-x) \:kmph$ $Time \:to \:meet \: second \:boat = 4\:hours$ $\blue { ( From \: 8.45 \:am \:to \: 12.45 \:pm = 4 hr )}$ $Distance \: travelled ( d_{2})= speed \times Time \\= (18-x)4 \:km \: ---(2)$ /* ACCORDING to the PROBLEM GIVEN */ $d_{1} + d_{2} = 211 \:km$ $\implies (26+x)5 + (18-x)4 = 211$ $\implies 130 + 5x + 72 - 4x = 211$ $\implies x + 202 = 211$ $\implies x = 211 - 202$ $\implies x = 9 \:kmph$ THEREFORE., $\red { Speed \:of \:the \: Current } \green { = 9 \:kmph }$ •••♪