332354 + Interview Questions in Secondary School in Math

1.	The first term of G. Pis 3. The last term is 1536 and the sum is 3069. Find the common ratio
Answer» ANSWER: $\boxed{\text{Answer: Common Ratio = 2}}$ Step-by-step explanation: $\boxed{\text{In a GP, } t_n = ar^{n-1}}\\\\a = 3\\\\l = 1536\\\\\boxed{\text{Sum of GP when last term is known} = \frac{lr - a}{r - 1}} \\\\\\3069 = \frac{1536 \text{ x } r \text{ - } 3}{r - 1}\\\\3069r - 3069 = 1536r - 3\\\\1533r = 3066\\\\\boxed{\text{Answer: r = 2}}$ HOPE this helps! If it does, PLEASE mark it brainliest!

1.

The first term of G. Pis 3. The last term is 1536 and the sum is 3069. Find the common ratio

Answer»

$\boxed{\text{Answer: Common Ratio = 2}}$

Step-by-step explanation:

$\boxed{\text{In a GP, } t_n = ar^{n-1}}\\\\a = 3\\\\l = 1536\\\\\boxed{\text{Sum of GP when last term is known} = \frac{lr - a}{r - 1}} \\\\\\3069 = \frac{1536 \text{ x } r \text{ - } 3}{r - 1}\\\\3069r - 3069 = 1536r - 3\\\\1533r = 3066\\\\\boxed{\text{Answer: r = 2}}$

HOPE this helps! If it does, PLEASE mark it brainliest!

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