a alone can do a piece of work in 35 days. if b is 40% more efficient

1.	a alone can do a piece of work in 35 days. if b is 40% more efficient than a, then b will finish the work in how many days
Answer» Answer: 25 DAYS Step-by-step explanation: 100 A = 35 days 100 B = y days (1) wkt, 100 B = 140 A [GIVEN] (2) ⇒ sub (2) in (1), we GET, 140 A = y days ∴ 100 : 140 :: y : 35 ⇒ y = (100 × 35) ÷ 140 y = 25 days

a alone can do a piece of work in 35 days. if b is 40% more efficient than a, then b will finish the work in how many days

Answer»

Answer:

25 DAYS

Step-by-step explanation:

100 A = 35 days

100 B = y days (1)

wkt,

100 B = 140 A [GIVEN] (2)

⇒ sub (2) in (1),

we GET,

140 A = y days

∴ 100 : 140 :: y : 35

⇒ y = (100 × 35) ÷ 140

y = 25 days

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a alone can do a piece of work in 35 days. if b is 40% more efficient than a, then b will finish the work in how many days​

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a alone can do a piece of work in 35 days. if b is 40% more efficient than a, then b will finish the work in how many days