332354 + Interview Questions in Secondary School in Math

1.	Factorize: x^2 +6x + 24 =0
Answer» ANSWER: please SEND the PROPER questions, it is XSQUAR or 2*x. answer is 1

1.

Factorize: x^2 +6x + 24 =0

Answer»

ANSWER:

please SEND the PROPER questions, it is XSQUAR or 2*x. answer is 1

Discussion

2.	Which expression is equivalent to -4(x-8)? A) -4x+32 B) 4x + 12 C) -4x -32 D) 4x -12
Answer» ANSWER: I am SORRY I didn't KNOW the answer

2.

Which expression is equivalent to -4(x-8)? A) -4x+32 B) 4x + 12 C) -4x -32 D) 4x -12

Answer»

ANSWER:

I am SORRY I didn't KNOW the answer

Discussion

3.	ROJECT WORK In an A4 sheet you have to write the ATTRIBUTES OF _______ NUMBERS ( Any numbers , like composite numbers , prime numbers , even numbers, odd numbers etc ) You Can write in point wise IF ANY DOUBTS , U CAN CLEAR IN THE NEXT
Answer» Answer: p(X) = 2x 3 + x 2 – 2x – 1, g(x) = x + 1+ 7x.12x 2 – 7x + 1Check whether 7 + 3X is a factor of 3x 3 + 7x.

3.

ROJECT WORK In an A4 sheet you have to write the ATTRIBUTES OF _______ NUMBERS ( Any numbers , like composite numbers , prime numbers , even numbers, odd numbers etc ) You Can write in point wise IF ANY DOUBTS , U CAN CLEAR IN THE NEXT

Answer»

Answer:

p(X) = 2x

3

+ x

2

– 2x – 1, g(x) = x + 1+ 7x.12x

2

– 7x + 1Check whether 7 + 3X is a factor of 3x

3

+ 7x.

Discussion

4.	एक कोण जिसका माप 9 ° से अधिक ह
Answer» Answer: 10 डिग्री 11 डिग्री ।।।।।।।।।।।।।।।।

4.

एक कोण जिसका माप 9 ° से अधिक ह

Answer»

Answer:

10 डिग्री 11 डिग्री ।।।।।।।।।।।।।।।।

Discussion

5.	Verify de Morgan's law U=(a,b,c,d,...h) A=(a,b,c,d) B=(e,f, g, h,) no irrelevant answer
Answer» ANSWER: ......................................

5.

Verify de Morgan's law U=(a,b,c,d,...h) A=(a,b,c,d) B=(e,f, g, h,) no irrelevant answer

Answer»

ANSWER:

......................................

Discussion

6.	6. There are 23,520 candies in 96 boxes. How many candies are there in each box?7. Ashish organised his brother's birthday party. If he invited 72 guests and ordered 14pastries for the party, estimate the number of pastries each guest will get.3. If 9,604 kg rice is packed in 98 bags, how much quantity of rice will each bag contairving Problems involving Four Operationsfour basic operations are addition, subtraction, multiplication and division.erder in which we solve a problem involving all these operations is given by a rule callAS. According to the rule, we solve a problem in the given order.Brackets (first)MAOf (second)Division (third)Multiplication (fourth)Addition (fifth)Subtraction (sixth)Ssund
Answer» Answer: 6) 245 7)5 3) 98 Step-by-step EXPLANATION: in all just SIMPLY DIVIDE

6.

6. There are 23,520 candies in 96 boxes. How many candies are there in each box?7. Ashish organised his brother's birthday party. If he invited 72 guests and ordered 14pastries for the party, estimate the number of pastries each guest will get.3. If 9,604 kg rice is packed in 98 bags, how much quantity of rice will each bag contairving Problems involving Four Operationsfour basic operations are addition, subtraction, multiplication and division.erder in which we solve a problem involving all these operations is given by a rule callAS. According to the rule, we solve a problem in the given order.Brackets (first)MAOf (second)Division (third)Multiplication (fourth)Addition (fifth)Subtraction (sixth)Ssund

Answer»

Answer:

6) 245

7)5

3) 98

Step-by-step EXPLANATION:

in all just SIMPLY DIVIDE

Discussion

7.	20% of rs 500 will be equal to what
Answer» ANSWER: $= 20\% \: of \: 500 \\ \\ = \frac{20}{100} \times 500 \\ \\ = Rs.100$ .

7.

20% of rs 500 will be equal to what

Answer»

ANSWER:

$= 20\% \: of \: 500 \\ \\ = \frac{20}{100} \times 500 \\ \\ = Rs.100$

.

Discussion

8.	The value of (root 11+root 2) (root 11- root 2)(A) 11(B) 2(C) 9(D) 13
Answer» Answer = 9 Step-by-step explanation: The EXPRESSION is in the FORM of an IDENTITY. (a+b) (a-b) = a²- b² Then, $(\sqrt{<klux>11</klux>} + \sqrt{2} ) \: ( \sqrt{11} - \sqrt{2} ) \:$ $= ( \sqrt{11} ^{2} ) - (\sqrt{2} ^{2} )$ = 11 - 2 = 9 Hope This Helps !!

8.

The value of (root 11+root 2) (root 11- root 2)(A) 11(B) 2(C) 9(D) 13

Answer»

Answer = 9

Step-by-step explanation:

The EXPRESSION is in the FORM of an IDENTITY.

(a+b) (a-b) = a²- b²

Then,

$(\sqrt{<klux>11</klux>} + \sqrt{2} ) \: ( \sqrt{11} - \sqrt{2} ) \:$

$= ( \sqrt{11} ^{2} ) - (\sqrt{2} ^{2} )$

= 11 - 2

= 9

Hope This Helps !!

Discussion

9.	8. If p(y) = 2y-4 then p(3) is
Answer» <P>ANSWER: 2. Step-by-step EXPLANATION: p(3) = 2(3) - 4. p(3) = 6-4 = 2. Therefore , p(3) = 2. I HOPE IT HELPED YOU! (:

9.

8. If p(y) = 2y-4 then p(3) is

Answer»

<P>ANSWER: 2.

Step-by-step EXPLANATION:

p(3) = 2(3) - 4.

p(3) = 6-4 = 2.

Therefore , p(3) = 2.

I HOPE IT HELPED YOU! (:

Discussion

10.	In what time will 1) Rupee 8500 amount to rupee 15385 at the interest rate of 6 percent per annum
Answer» ANSWER: ;k.ipjp Step-by-step EXPLANATION: i;g/bfv

10.

In what time will 1) Rupee 8500 amount to rupee 15385 at the interest rate of 6 percent per annum

Answer»

ANSWER:

;k.ipjp

Step-by-step EXPLANATION:

i;g/bfv

Discussion

11.	In the adjacent diagram,if AB\|\|CD, 2BAO = 104°& ZDCO = 1329, then findthe value of ZAOC.
Answer» ANSWER: ;LGF,gf Step-by-step EXPLANATION: :D/.lhgpkohg

11.

In the adjacent diagram,if AB||CD, 2BAO = 104°& ZDCO = 1329, then findthe value of ZAOC.

Answer»

ANSWER:

;LGF,gf

Step-by-step EXPLANATION:

:D/.lhgpkohg

Discussion

12.	Find lcm and hcm of 144 and 296
Answer» ANSWER: LCM = 5328 and HCF = 2 Step-by-step explanation: 144=2×2×2×2×3×3 296=2×2×2×37 LCM = 2×2×2×2×3×3×37 = 5328 HCF = 2

12.

Find lcm and hcm of 144 and 296

Answer»

ANSWER:

LCM = 5328 and HCF = 2

Step-by-step explanation:

144=2×2×2×2×3×3

296=2×2×2×37

LCM = 2×2×2×2×3×3×37 = 5328

HCF = 2

Discussion

13.	Find out the infinity
Answer» ..... $\text{[math]}$ $\fbox{code check 36}$

13.

Find out the infinity

Answer»

..... $\text{[math]}$

$\fbox{code check 36}$

Discussion

14.	Hey!! photo is clear I know... plzz
Answer» ANSWER: IDONT know but PLEASE FOLLOW me i follow you BACK

14.

Hey!! photo is clear I know... plzz

Answer»

ANSWER:

IDONT know but PLEASE FOLLOW me i follow you BACK

Discussion

15.	362 5 = 2+ 05. 850 = (0)8. 5 + 2 = 3(1+2)011. 2(2+ 3) = 331 - 3)1214. 2(- 1) + 2(. + 2) = 3.8 + 3)1517.15 + 321 - 2) = 63 + 1)1820.1 3.1 - 8 4 - 3دیا2زر
Answer» ANSWER: SORRY L don't KNOW the answer

15.

362 5 = 2+ 05. 850 = (0)8. 5 + 2 = 3(1+2)011. 2(2+ 3) = 331 - 3)1214. 2(- 1) + 2(. + 2) = 3.8 + 3)1517.15 + 321 - 2) = 63 + 1)1820.1 3.1 - 8 4 - 3دیا2زر

Answer»

ANSWER:

SORRY L don't KNOW the answer

Discussion

16.	(2) (x - 1)2 = 2 x + 3
Answer» ANSWER: Step-by-step explanation: 4(x-1) = 2x+3. 4x-4 = 2x+3. 4x-2x = 3+4. 2x = 7. x = 3.5 I HOPE IT HELPED YOU! (:

16.

(2) (x - 1)2 = 2 x + 3

Answer»

ANSWER:

Step-by-step explanation:

4(x-1) = 2x+3.

4x-4 = 2x+3.

4x-2x = 3+4.

2x = 7.

x = 3.5

I HOPE IT HELPED YOU! (:

Discussion

17.	Find the area of triangle whose vertices are (0,3)(0,-3)(0,7)
Answer» Answer: the answer of this question is 15 because ACCORDING to TRIANGLES formula the height of the triangle is 3 units and total BASE is 10 units then you can apply the formula of triangle and you receive the answer...... if you like it so plz follow me and MAKE me brainlist plz.......

17.

Find the area of triangle whose vertices are (0,3)(0,-3)(0,7)

Answer»

Answer:

the answer of this question is 15 because ACCORDING to TRIANGLES formula the height of the triangle is 3 units and total BASE is 10 units then you can apply the formula of triangle and you receive the answer......

if you like it so plz follow me and MAKE me brainlist plz.......

Discussion

18.	Hey!!4√3√32 WE GET_______PLZ ANSWER IRREVERENT ANSWER WILL BE REPORTED ❌❌❌
Answer» Answer: *39.1918358845* ʜᴏᴘᴇ ɪᴛ *ʜᴇʟᴘs* ᴜ ᴅᴇᴀʀ.... ✌️

18.

Hey!!4√3√32 WE GET_______PLZ ANSWER IRREVERENT ANSWER WILL BE REPORTED ❌❌❌

Answer»

Answer:

39.1918358845

ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs ᴜ ᴅᴇᴀʀ.... ✌️

Discussion

19.	Solve these three sum i'll make you brainy
Answer» ANSWER: 4=》12.1 Step-by-step EXPLANATION: FOLLOW me to get more answer by me MARK me BRAINLIEST if you can

19.

Solve these three sum i'll make you brainy

Answer»

ANSWER:

4=》12.1

Step-by-step EXPLANATION:

FOLLOW me to get more answer by me

MARK me BRAINLIEST if you can

Discussion

20.	1) (y²-4) (y²-9)2) (3a²-4b²) ( 3a²+5b²)Solve both using identity : x²+x(a+b)(aXb)
Answer» Answer: 1) y²-468y 2) 3a²-60ab² Step-by-step explanation: 1) USING the identity y²+ y (-4-9 ) (4×9) y²+(-4y-9y)(36) y²-13y×36 (y²-468y) 2) 3a²+3a(-4b+5b)(-4b×5b) 3a²+3ab×-20b (3a²-60ab²)

20.

1) (y²-4) (y²-9)2) (3a²-4b²) ( 3a²+5b²)Solve both using identity : x²+x(a+b)(aXb)

Answer»

Answer:

1) y²-468y

2) 3a²-60ab²

Step-by-step explanation:

1) USING the identity

y²+ y (-4-9 ) (4×9)

y²+(-4y-9y)(36)

y²-13y×36

(y²-468y)

2) 3a²+3a(-4b+5b)(-4b×5b)

3a²+3ab×-20b

(3a²-60ab²)

Discussion

21.	Write a letter to you friend
Answer» ANSWER: Here is your answer Step-by-step EXPLANATION: HOPE it HELPS you And Don't forget me to mark BRAINLIEST answer

21.

Write a letter to you friend

Answer»

ANSWER:

Here is your answer

Step-by-step EXPLANATION:

HOPE it HELPS you

And

Don't forget me to mark BRAINLIEST answer

Discussion

22.	9) By using factor theorem in the following examples, determine whether qx) is afactor p(x) or not.(1) p(x) = x - x - x -1.9(x) = x - 1(ii) p(x) = 2x - x - 45, 9(x) = x - 3
Answer» SHOW you how MUCH you LOVE your voice and the other events and the rest of t SHIRT on my own

Discussion

23.	A copper wire when bent in the form of a square enclosed an area of 27 9by4 cm.sq. If the same wire is bent to from a circle, find the diameter.
Answer» ANSWER: . .......................

23.

A copper wire when bent in the form of a square enclosed an area of 27 9by4 cm.sq. If the same wire is bent to from a circle, find the diameter.

Answer»

ANSWER:

. .......................

Discussion

24.	Rationalise the deno minator of 3/√7+√4
Answer» ANSWER: $= \frac{3}{ \sqrt{7} + \sqrt{4} } \times \frac{ \sqrt{7} - \sqrt{4} }{ \sqrt{7} - \sqrt{4} } \\ \\ = \frac{3( \sqrt{7} - \sqrt{4} )}{ {( \sqrt{7}) }^{2} - {( \sqrt{4} )}^{2} } \\ \\ = \frac{3 (\sqrt{7} -\sqrt{4} ) }{7 - 4} \\ \\ = \frac{3 (\sqrt{7} -\sqrt{4} ) }{3} \\ \\ = \sqrt{7 } - \sqrt{4} \\\\=\sqrt{7}-2$

24.

Rationalise the deno minator of 3/√7+√4

Answer»

ANSWER:

$= \frac{3}{ \sqrt{7} + \sqrt{4} } \times \frac{ \sqrt{7} - \sqrt{4} }{ \sqrt{7} - \sqrt{4} } \\ \\ = \frac{3( \sqrt{7} - \sqrt{4} )}{ {( \sqrt{7}) }^{2} - {( \sqrt{4} )}^{2} } \\ \\ = \frac{3 (\sqrt{7} -\sqrt{4} ) }{7 - 4} \\ \\ = \frac{3 (\sqrt{7} -\sqrt{4} ) }{3} \\ \\ = \sqrt{7 } - \sqrt{4} \\\\=\sqrt{7}-2$

Discussion

25.	The decimal representation of 7upon 3
Answer» ANSWER: DECIMAL REPRESENTATION of 7/3 is 2.34 is RIGHT answer.

25.

The decimal representation of 7upon 3

Answer»

ANSWER:

DECIMAL REPRESENTATION of 7/3 is 2.34 is RIGHT answer.

Discussion

26.	Highlight the prime numbers 21, 31, 49, 59, 63, 73, 91, 97, 40, 56, 37
Answer» ANSWER: ikpiipt;'trg lkefkcl Step-by-step EXPLANATION: itititititi idk LOL

26.

Highlight the prime numbers 21, 31, 49, 59, 63, 73, 91, 97, 40, 56, 37

Answer»

ANSWER:

ikpiipt;'trg

lkefkcl

Step-by-step EXPLANATION:

itititititi

idk LOL

Discussion

27.	Prove that any three points on a circle cannot be collinear with construction
Answer» *Let* A, B, *and* C be *any* *three* *points* on a *circle. Suppose* *these* *three* *points* A, B, *and* C on *the* *collinear. Therefore, the* *PERPENDICULAR* *bisectors* of *the* *chords* AB *and* BC *must* be *parallel* *because* *two* or *more* *lines* which *are* to *given line* *are* *parallel* to *each* *other. Now, AB and* BC *are* *the* *chords* of *the* *circle. We know* *that* *the* *perpendicular* *bisector* of *the* *CHORD* of a *circle* *passing* *through* *its* *centre. So, the* *perpendicular* *bisectors* of *the* *chords* AB *and* BC *must* *intersect* at *the* *centre* of *the* *circle. This* is a *contradiction* to *our* *statement* *that* *the* *perpendicular* *bisectors* of AB *and* BC *must* be *parallel, as parallel* *lines* do *not* *intersect* at a *point. Hence, our* *assumption* *that* *three* *points* A,B,C on *the* *circle* *are* *collinear* is *not* *correct. THUS, any* *three* *points* on a *circle* *cannot* be *collinear*.

27.

Prove that any three points on a circle cannot be collinear with construction

Answer»

Let A, B, and C be any three points on a circle. Suppose these three points A, B, and C on the collinear.

Therefore, the PERPENDICULAR bisectors of the chords AB and BC must be parallel because two or more lines which are to given line are parallel to each other.

Now, AB and BC are the chords of the circle. We know that the perpendicular bisector of the CHORD of a circle passing through its centre.

So, the perpendicular bisectors of the chords AB and BC must intersect at the centre of the circle.

This is a contradiction to our statement that the perpendicular bisectors of AB and BC must be parallel, as parallel lines do not intersect at a point.

Hence, our assumption that three points A,B,C on the circle are collinear is not correct.

THUS, any three points on a circle cannot be collinear.

Discussion

28.	Find the quadrilateral polynomial with each the given number as the sum and product of its zeros -3 and -2 respectively
Answer» AnsWer : x² + 3x + 2. Correct QUESTION : Find the quadratic polynomial with each the given number as the SUM and PRODUCT of its zeros - 3 and 2 respectively. To FinD : The quadratic polynomial SolutioN : We have, zeros ★ Sum of Zero = - B / a = - 3. ★ Product of Zeros = c / a = 2. We know, K [ x² + Sx + P ] where as, S Sum of Zero. P Product of Zero. K content term. Now, putting the given VALUE on it. → K[ x² - ( - 3 )x + ( 2 ) ] → K[ x² + 3x + 2 ] Therefore, the quadratic polynomial is x² + 3x + 2. $\rule{200}3$ VerificatioN : Taking Equation, x² + 3x + 2. → x² + 3x + 2. → x² + 2x + x + 2. → x( x + 2 ) + 1 ( x + 2 ) → ( x + 1 )( x + 2 ) ___________ → x + 1 = 0. → x = - 1. ___________ → x + 2 = 0. → x = - 2. Sum of the Zero → ( - 1 ) + ( - 2 ) = - b / a. → - 1 - 2 = - 3 / 1. → - 3 = - 3. Product Of Zeros → ( - 1 ) + ( - 2 ) = c / a. → - 1 - 2 = 2. → 2 = 2. Hence Verified.

28.

Find the quadrilateral polynomial with each the given number as the sum and product of its zeros -3 and -2 respectively

Answer»

AnsWer :

x² + 3x + 2.

Correct QUESTION :

Find the quadratic polynomial with each the given number as the SUM and PRODUCT of its zeros - 3 and 2 respectively.

To FinD :

The quadratic polynomial

SolutioN :

We have, zeros

★ Sum of Zero = - B / a = - 3.

★ Product of Zeros = c / a = 2.

We know,

K [ x² + Sx + P ]

where as,

S Sum of Zero.
P Product of Zero.
K content term.

Now, putting the given VALUE on it.

→ K[ x² - ( - 3 )x + ( 2 ) ]

→ K[ x² + 3x + 2 ]

Therefore, the quadratic polynomial is x² + 3x + 2.

$\rule{200}3$

VerificatioN :

Taking Equation,

x² + 3x + 2.

→ x² + 3x + 2.

→ x² + 2x + x + 2.

→ x( x + 2 ) + 1 ( x + 2 )

→ ( x + 1 )( x + 2 )

___________

→ x + 1 = 0.

→ x = - 1.

___________

→ x + 2 = 0.

→ x = - 2.

Sum of the Zero

→ ( - 1 ) + ( - 2 ) = - b / a.

→ - 1 - 2 = - 3 / 1.

→ - 3 = - 3.

Product Of Zeros

→ ( - 1 ) + ( - 2 ) = c / a.

→ - 1 - 2 = 2.

→ 2 = 2.

Hence Verified.

Discussion

29.	Solve the following equations using any methods x-y=2 and 3x+2y=16
Answer» Answer: X = 4 y = 2 Step-by-step explanation: x-y = 2 SO x = 2 + y -------------Equation 1 3x + 2y = 16 Replace x in above equation with Equation 1 ie 3(2+y) + 2y = 16 6 + 3Y + 2y = 16 6 + 5Y = 16 5y = 16-6 5y = 10 y = 10/5 = 2 Therefore x = 2 + y = 2 + 2 = 4

29.

Solve the following equations using any methods x-y=2 and 3x+2y=16

Answer»

Answer:

X = 4

y = 2

Step-by-step explanation:

x-y = 2

SO x = 2 + y -------------Equation 1

3x + 2y = 16

Replace x in above equation with Equation 1

ie 3(2+y) + 2y = 16

6 + 3Y + 2y = 16

6 + 5Y = 16

5y = 16-6

5y = 10

y = 10/5 = 2

Therefore x = 2 + y = 2 + 2 = 4

Discussion

30.	The product of (y² -5) and (y² +5) is *
Answer» ANSWER: (y(SQUARE)-5) (y(square)+5) ((y(square)) WHOLE square)-25 esay WAY (y²)²-25 y⁴-25

30.

The product of (y² -5) and (y² +5) is *

Answer»

ANSWER:

(y(SQUARE)-5) (y(square)+5)

((y(square)) WHOLE square)-25

esay WAY (y²)²-25

y⁴-25

Discussion

31.	Aquatic polynomial whose zeroes are 5 and -3 is
Answer» A quadratic polynomial whose ZEROES are 5 and -3 is [complete question] GIVEN: An equation has zeroes 5 and -3 To find: The quadratic equation Solution: Let the zeroes of the polynomial is a and B which are given in the question as 5 and -3: a = 5 b = -3 Sum of the zeroes = a+b 5+(-3) 5-3 2 Product of the zeroes = ab 5.(-3) -15 As we know that the quadratic equation is given by: x²+ (sum of the zeroes) x + product of the zeroes = 0 x²+2x+(-15) = 0 x²+2x-15 = 0 Hence the quadratic equation is x²+2x-15 = 0

31.

Aquatic polynomial whose zeroes are 5 and -3 is

Answer»

A quadratic polynomial whose ZEROES are 5 and -3 is [complete question]

GIVEN:

An equation has zeroes 5 and -3

To find:

The quadratic equation

Solution:

Let the zeroes of the polynomial is a and B which are given in the question as 5 and -3:

a = 5

b = -3

Sum of the zeroes = a+b

5+(-3)

5-3

2

Product of the zeroes = ab

5.(-3)

-15

As we know that the quadratic equation is given by:

x²+ (sum of the zeroes) x + product of the zeroes = 0
x²+2x+(-15) = 0
x²+2x-15 = 0

Hence the quadratic equation is x²+2x-15 = 0

Discussion

32.	If a =3/5 and b=11/15, find the value of a-b and b-a . State whether a-b and b-a are equal or not .
Answer» Answer: a-b=-2/15 and b-a=2/15 a-b and b-a are not equal Step-by-step explanation: HOPE you are SATISFIED with my answer mark my answer as brainliest PLZZZ plzzz

32.

If a =3/5 and b=11/15, find the value of a-b and b-a . State whether a-b and b-a are equal or not .

Answer»

Answer:

a-b=-2/15 and b-a=2/15

a-b and b-a are not equal

Step-by-step explanation:

HOPE you are SATISFIED with my answer

mark my answer as brainliest PLZZZ plzzz

Discussion

33.	-15, - 12,-9,-6 give the next four terms
Answer» ANSWER: ans = -3 , 0 , 3 , 6 Step-by-step explanation: PLEASE LIKE and follow please please thanks

33.

-15, - 12,-9,-6 give the next four terms

Answer»

ANSWER:

ans = -3 , 0 , 3 , 6

Step-by-step explanation:

PLEASE LIKE and follow

please

thanks

Discussion

34.	In n root a,n is calledsurdradicalorder of the surdnone
Answer» Step-by-step EXPLANATION: what what is your QUESTION it is not understood by me so MARK me as brainliest and follow me OK

34.

In n root a,n is calledsurdradicalorder of the surdnone

Answer»

Step-by-step EXPLANATION:

what what is your QUESTION it is not understood by me so MARK me as brainliest and follow me OK

Discussion

35.	In parallelogram PQRS, T is the mid-point of PQ and U is the mid point of SR. Prove that PTRU is a parallelogram.
Answer» GIVEN: T is the mid-point of PQ and U is the mid-point of SR. To prove: PTRU is a parallelogram Solution: As it is given that PQRS is the parallelogram so, PQ║RS 1/2PQ║1/2RS PT║RU and, PQ=RS 1/2PQ=1/2RS PT=RU As we KNOW that the line passing through the mid-points of any of the parallelograms is parallel to the opposite SIDES of the parallelogram. TU║RP TU=RP Hence the opposite PAIR of sides of the parallelogram are parallel and EQUAL to each other. PTRU is a parallelogram Hence Proved

35.

In parallelogram PQRS, T is the mid-point of PQ and U is the mid point of SR. Prove that PTRU is a parallelogram.

Answer»

GIVEN:

T is the mid-point of PQ and U is the mid-point of SR.

To prove:

PTRU is a parallelogram

Solution:

As it is given that PQRS is the parallelogram so,

PQ║RS
1/2PQ║1/2RS
PT║RU

and,

PQ=RS
1/2PQ=1/2RS
PT=RU

As we KNOW that the line passing through the mid-points of any of the parallelograms is parallel to the opposite SIDES of the parallelogram.

TU║RP
TU=RP

Hence the opposite PAIR of sides of the parallelogram are parallel and EQUAL to each other.

PTRU is a parallelogram

Hence Proved

Discussion

36.	Q6. Express 74.0 in p / q form where p & q are integers.
Answer» Answer: 74.0 in p/q FORM is 740/10 Step-by-step EXPLANATION: HOPE IT HELPS YOU.....!

36.

Q6. Express 74.0 in p / q form where p & q are integers.

Answer»

Answer:

74.0 in p/q FORM is 740/10

Step-by-step EXPLANATION:

HOPE IT HELPS YOU.....!

Discussion

37.	What is the face value 4 in 2418
Answer» ANSWER: $\textbf{4}$

37.

What is the face value 4 in 2418

Answer»

ANSWER:

$\textbf{4}$

Discussion

38.	Draw the graph of the equation 2x-y+3=0. Using the graph find the value of y when (a) x=2 (b) x=-3.
Answer» SOLUTION TO DETERMINE The graph of the EQUATION 2x-y+3=0 Using the graph find the value of y when (a) x=2 (b) x=-3. *EVALUATION* $\sf{An \: equation \: of \: the \: form \: \: ax + by + c = 0 \: }$ is a equation of the Straight line Now the given equation of the line $\sf{2x - y + 3 = 0 \: \: \: \: ....(1)}$ *GRAPH* The graph of the line is referred to the attachment WHEN (a) x = 2 From the graph we observe that OA = x = 2 Then AB = y = 7 Hence for x = 2 we GET y = 7 *WHEN (b) x = - 3 From the graph we observe that* OC = x = - 3 Then CD = y = - 3 Hence for x = *- 3 we get y =* - 3 ━━━━━━━━━━━━━━━━ LEARN MORE FROM BRAINLY** Find the area of triangle bounded by a line 4x+3y=48 with COORDINATE axes. brainly.in/question/22473306

38.

Draw the graph of the equation 2x-y+3=0. Using the graph find the value of y when (a) x=2 (b) x=-3.

Answer»

SOLUTION

TO DETERMINE

The graph of the EQUATION 2x-y+3=0

Using the graph find the value of y when (a) x=2 (b) x=-3.

EVALUATION

$\sf{An \: equation \: of \: the \: form \: \: ax + by + c = 0 \: }$

is a equation of the Straight line

Now the given equation of the line

$\sf{2x - y + 3 = 0 \: \: \: \: ....(1)}$

GRAPH

The graph of the line is referred to the attachment

WHEN (a) x = 2

From the graph we observe that

OA = x = 2

Then AB = y = 7

Hence for x = 2 we GET y = 7

WHEN (b) x = - 3

From the graph we observe that

OC = x = - 3

Then CD = y = - 3

Hence for x = - 3 we get y = - 3

━━━━━━━━━━━━━━━━

LEARN MORE FROM BRAINLY

Find the area of triangle bounded by a line 4x+3y=48 with COORDINATE axes.

brainly.in/question/22473306

Discussion

39.	If p(x)=x square -3√3x-1 then p(3√3) is equal to answer
Answer» Answer: A STEM cutting PRODUCES NEW ROOTS, and a root cutting produces new stems. Some plants can be grown from leaf pieces, called leaf cuttings, which produce both stems and roots. The scions used in grafting are also called cuttings. PROPAGATING plants from cuttings is an ancient form of cloning.ba7❤❤❤❤usjjwjwjwjqnjhzuauqq

39.

If p(x)=x square -3√3x-1 then p(3√3) is equal to answer

Answer»

Answer:

A STEM cutting PRODUCES NEW ROOTS, and a root cutting produces new stems. Some plants can be grown from leaf pieces, called leaf cuttings, which produce both stems and roots. The scions used in grafting are also called cuttings. PROPAGATING plants from cuttings is an ancient form of cloning.ba7❤❤❤❤usjjwjwjwjqnjhzuauqq

Discussion

40.	Travelled 5/6 of the distance of 30km between his house and shopping mall
Answer» ANSWER: njrhhfhcjejwjcjgjvkhgijgkdjdnd nnftnfnjrrjfitiitifufufufufffjjfjfjfjfjx

40.

Travelled 5/6 of the distance of 30km between his house and shopping mall

Answer»

ANSWER:

njrhhfhcjejwjcjgjvkhgijgkdjdnd nnftnfnjrrjfitiitifufufufufffjjfjfjfjfjx

Discussion

41.	Find consumer surplus and producer surplus at equilibrium pd= 15-x and ps=0.3x+2
Answer» ANSWER: don't KNOW the answer but MARK as BRAINLIST and FOLLOW me

41.

Find consumer surplus and producer surplus at equilibrium pd= 15-x and ps=0.3x+2

Answer»

ANSWER:

don't KNOW the answer but MARK as BRAINLIST and FOLLOW me

Discussion

42.	Measure of angles lies between
Answer» ANSWER: 0 to 180 degrees follow me and MARK my answer is as BRAINLIST

42.

Measure of angles lies between

Answer»

ANSWER:

0 to 180 degrees

follow me and MARK my answer is

as BRAINLIST

Discussion

43.	_______holds good for the probability of any event A.
Answer» ANSWER: who or he HOPE you LIKE it

43.

_______holds good for the probability of any event A.

Answer»

ANSWER:

who or he

HOPE you LIKE it

Discussion

44.	Express 45 min in cm and m
Answer» ANSWER: in CM- 4.5cm in m- 0.045m hope it HELPS U

44.

Express 45 min in cm and m

Answer»

ANSWER:

in CM- 4.5cm

in m- 0.045m

hope it HELPS U

Discussion

45.	1)The _______of a digit is the number itself *
Answer» ANSWER: SUM is he CORRECT answer HOPE you LIKE it

45.

1)The _______of a digit is the number itself *

Answer»

ANSWER:

SUM is he CORRECT answer

HOPE you LIKE it

Discussion

46.	Shivani counted 25 notes the first time. Second time she counted 1 more. To check, she counted again and found 1 note less than the second
Answer» Answer: she has 25 notes Step-by-step EXPLANATION: USKA dimag khrab ho gya HOGA

46.

Shivani counted 25 notes the first time. Second time she counted 1 more. To check, she counted again and found 1 note less than the second

Answer»

Answer:

she has 25 notes

Step-by-step EXPLANATION:

USKA dimag khrab ho gya HOGA

Discussion

47.	If A = [aij] is a 2 × 3 matrix, such that aij = [latex]\frac{(-i+2 j)^{2}}{5}[/latex].then a23 is
Answer» ANSWER: IDK K ........................

47.

If A = [aij] is a 2 × 3 matrix, such that aij = [latex]\frac{(-i+2 j)^{2}}{5}[/latex].then a23 is

Answer»

ANSWER:

IDK K ........................

Discussion

48.	third zero of the polynomial when sum and product of the zeros are - 3 and 2 respectively what is the third number
Answer» Answer: 0000000000000000000000000000000000000000

48.

third zero of the polynomial when sum and product of the zeros are - 3 and 2 respectively what is the third number

Answer»

Answer:

0000000000000000000000000000000000000000

Discussion

49.	The LCM and HCF of two numbers are 29 and 348 respectively. If one number is 87 , find the other number
Answer» Answer: Step-by-step explanation: FORMULA to be USED = HCFLCM =Product of Number 1 and Number 2 HCF=29 LCM =348 Number 1 =87 Number 2 = x 29348=87x 29348/87 =x 116=x Number 2 = 116

49.

The LCM and HCF of two numbers are 29 and 348 respectively. If one number is 87 , find the other number

Answer»

Answer:

Step-by-step explanation:

FORMULA to be USED = HCF*LCM =Product of Number 1 and Number 2

HCF=29

LCM =348

Number 1 =87

Number 2 = x

29*348=87*x

29*348/87 =x

116=x

Number 2 = 116

Discussion

50.	Insert seven rational number-3/8 -5/4
Answer» hope it will HELP ☺️ Answer: -7/16 , -8/16 , -9/16 , -10/16 , -11/16 , -12/16 , -13/16 are SEVEN rational NUMBER between -3/8 and -5/4 Step-by-step EXPLANATION: -3/8 and -5/4 LCM of 8 and 4 is 8 -3/8 and -10/8 therefore between -3/8 and -10/8 didn't consit 7 no. so we multiply both no. with 2 -32/82 = -6/16 -102/82 = -20/16 rational number between - 6/16 and - 20/16 are :- -7/16 , -8/16 , -9/16 , -10/16 , -11/16 , -12/16 , -13/16.

50.

Insert seven rational number-3/8 -5/4

Answer»

hope it will HELP ☺️

Answer:

-7/16 , -8/16 , -9/16 , -10/16 , -11/16 , -12/16 , -13/16 are SEVEN rational NUMBER between -3/8 and -5/4

Step-by-step EXPLANATION:

-3/8 and -5/4

LCM of 8 and 4 is 8

-3/8 and -10/8

therefore between -3/8 and -10/8 didn't consit 7 no. so we multiply both no. with 2

-3*2/8*2 = -6/16

-10*2/8*2 = -20/16

rational number between - 6/16 and - 20/16 are :-

-7/16 , -8/16 , -9/16 , -10/16 , -11/16 , -12/16 , -13/16.

Discussion

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TO DETERMINE

EVALUATION

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In the adjacent diagram,if AB||CD, 2BAO = 104°& ZDCO = 1329, then findthe value of ZAOC.

Find lcm and hcm of 144 and 296

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Hey!! photo is clear I know... plzz

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Hey!!4√3√32 WE GET_______PLZ ANSWER IRREVERENT ANSWER WILL BE REPORTED ❌❌❌

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