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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
In the given figure ab is parallel to de angle abc is equal to 110 degree and Angle CD is equal to 130 degree find angle BCD |
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Answer» where is the FIGURE PLEASE ASK the question clearly so that I can HELP you. |
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| 2. |
Can you answer this question? |
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Answer» Answer: this is very HARD .THATS why i DONT KNOW the answer .so, sorry |
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| 3. |
Find the smallest number which is exactly divisible by 15,20,30 |
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Answer» Answer: 5 = 3 * 5 20 = 2 * 2 * 5 30 = 2 * 3 * 5 two 2’s by ONE 3 by one 5 = 2 * 2 * 3 * 5 = 60 That is the answer. Step-by-step EXPLANATION: |
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| 5. |
For what value of a the number - 11/a is not a rational number.a) -1b) +1c)0d) 10 |
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Answer» Answer: c- 0 Step-by-step EXPLANATION: ANYTHING DIVIDED by zero is not defined as it is IRRATIONAL |
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| 6. |
How to do this?? please help |
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Answer» STEP-by-step EXPLANATION: |
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| 7. |
Pls solve this sum fast |
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Answer» it is written as the rupees are equal as the participants ....so,one participant EQUALS to one rupees.so,the students went FRO picnic are 4225 Step-by-step explanation: ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ .....╚(███)╝ ......╚(██)╝ .........(█) ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ .....╚(███)╝ ......╚(██)╝ .........(█) ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ .....╚(███)╝ ......╚(██)╝ .........(█) ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ .....╚(███)╝ ......╚(██)╝ .........(█) ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ .....╚(███)╝ ......╚(██)╝ .........(█) ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ .....╚(███)╝ ......╚(██)╝ .........(█) .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ .....╚(███)╝ ......╚(██)╝ .........(█) ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ .....╚(███)╝ ......╚(██)╝ .........(█) ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ .....╚(███)╝ ......╚(██)╝ .........(█). ╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ .....╚(███)╝ ......╚(██)╝ .........(█) ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ ..╚═(███)═╝ .╚═(███)═╝ ╚═(███)═╝ ╚═(███)═╝ .╚═(███)═╝ ..╚═(███)═╝ ...╚═(███)═╝ ...╚═(███)═╝ .....╚(███)╝ ......╚(██)╝ .........(█) (BTW thanks if you're GOING to like this answer, rate this answer,or going to mark me as brainleast....) ^_^ ^_^ |
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| 8. |
Round 128,902,540 to the underlined digit, the underlined digit is 8 |
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Answer» ROUND 128,902,540 to the UNDERLINED DIGIT, the underlined digit is 8. |
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| 9. |
Exe1. A submarine was situated 600 feetbelow sea level. If it ascends 250 feet,what is its new position? |
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Answer» Answer: It is 350 FEET below SEA level Step-by-step explanation: below sea level = - ascending=+ therefore the submarine is situated 350 metres below sea level |
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| 10. |
A ball is thrown from the top of a cliff. Path of a ball may be modelled by the equation y=- 0.05x^2 + 1.5x+ 82(x>0), where is x the horizontal distance from the foot of the cliff and y is the height above the foot of the cliff.a. find an expression for dx/dyb.Hence find the maximum height reached by the ball.c. Justify that the height you found in part b is maximum point |
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Answer» Step-by-step EXPLANATION: |
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| 11. |
2. Express the following number in standard form:45 78.08 |
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Answer» The STANDARD FORM of a NUMBER can be expressed in the form a*n^p in which a is an integer, n is the base which is not greater than ten and p is the power .4.57808*10^3 is the standard form Step-by-step explanation: |
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| 12. |
Find the heidht and area of an equilateral triangle with sides 10 cm using Heron's formula |
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Answer» TRY with this method Step-by-step explanation: |
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| 13. |
Find the area of triangle whose vertices are (0,3)(0,-3)and(0,7) |
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| 14. |
The approximate value of IT in fraction form is1 point7/2222/727/272/7 |
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| 15. |
In the given figure, on the sides the respective coordinates of points p and q respectively are: Explanation please |
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Answer» <P>Step-by-step EXPLANATION: p(-2,3) ................ |
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| 16. |
For what value of p are (2p-1), 13 and (5p-10) are three consecutive terms of an AP |
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| 17. |
Two circles, each of radius 7 cm,31"Āintersect eacheach other. The distancebetween their centres is 72 cm. Findthe area of the portion common to boththe circles. |
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Answer» Step-by-step explanation: TWO CIRCLES, each of radius 7 cm, 31" Ā intersect each each other. The distance between their centres is 72 cm. Find the area of the portion common to both the circles. |
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| 18. |
3(iii(22 +5)differentiate |
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Answer» Answer: 22+5=27 Step-by-step explanation: Just Info - on 7 August 1944, IBM introduced Automatic Sequence CONTROL CALCULATOR ( ASCC ), which was named as MARK -1. This machine was easily able to do long calculations AUTOMATICALLY. |
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| 19. |
Find the least number which is exactly divisible by 24 and 36 |
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Answer» This is the answer |
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| 20. |
Is √12 by √2 is a rational or irrational number? |
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Answer» ^12 and ^2 are both irrational This because for a NUMBER to be rational they have to be expressed in the FORM of p/q where p and q are INTEGERS and q is not equal to 0. Step-by-step explanation: |
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| 21. |
୧୩. କେତୋଟି ୫ ଟଙ୍କିଆ ନୋଟ୍ ହେଲେ ୪୦ ଟଙ୍କା ହେବ ? |
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Answer» Your ANSWER is 8 40/5 = 8 there are eight 5 notes Hope it's help you Mark as BRAINLIEST |
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| 22. |
In each case. 11. Find the smallest number which when divided by 28 and 32 leaves 8&12Findremainders 8 and 12 respective |
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Answer» Answer: would be 4 and 6 Step-by-step explanation: if i put you over and over again 4 and 6 is that i think is OK if you die remem ber me xddddd ok noy don know is ok the ANWER |
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| 23. |
Plz solve it....true or false |
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Answer» Answer: 1.False 2.False 4.False
5.True |
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| 24. |
Plzzzzz ans fasssst |
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Answer» utyffstssistsjigdggdkkxg58552587257528582 |
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| 25. |
How many seconds in one minute? |
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Answer» Answer: 60 seconds in ONE minute Step-by-step EXPLANATION: Hope it helps you mark as a brainlist |
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| 26. |
Hey!!answer fast!!!! |
Answer» An IRRATIONAL number.HOPE THIS HELPS UH...PLEASE MARK THIS ANSWER AS BRAINLIEST...THANK YOU...... |
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| 27. |
Pls send tgis.Dont spam I request50 point for them pls |
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Answer» ..........FOLLOW me ............ |
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| 28. |
mrs. gupta bought a medicine which was made on 5th august 2017. it will expire in 180 days. what will be its "expiry" date? |
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Answer» Step-by-step EXPLANATION: answer 2nd jaunary 2018 |
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| 29. |
Kindly prove it anybody!!! (Class:-11) |
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Answer» Answer: RHS 1/2 [cotA-tanA] = 1/2[cotA-1/cotA] = 1/2[COT^2A-1]/cot A = (cot^2A-1)/2cotA hence, LHS=RHS thus proved I hope it HELPS you Mark me as brainliest and follow me pls |
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| 30. |
Prove that any three points on a circle cannot be collinear |
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Answer» Answer: Step-by-step explanation: To prove: There is one and only one circle passing through the points P, Q and R. Construction: Join PQ and QR. Draw perpendicular bisectors AB of PQ and CD of QR. Let the perpendicular bisectors intersect at the point O. Now join OP, OQ and OR. A circle is obtained passing through the points P, Q and R. Proof: We KNOW that, each and every point on the perpendicular bisector of a LINE segment is equidistant from its ends points. Thus, OP = OQ [Since, O LIES on the perpendicular bisector of PQ] and OQ = OR. [Since, O lies on the perpendicular bisector of QR] So, OP = OQ = OR. Let OP = OQ = OR = r. Now, draw a circle C(O, r) with O as centre and r as radius. Then, circle C(O, r) passes through the points P, Q and R. Next, we prove this circle is the only circle passing through the points P, Q and R. If possible, suppose there is a another circle C(O′, t) which passes through the points P, Q, R. Then, O′ will lie on the perpendicular bisectors AB and CD. But O was the intersection point of the perpendicular bisectors AB and CD. So, O ′ must COINCIDE with the point O. [Since, two lines can not intersect at more than one point] As, O′P = t and OP = r; and O ′ coincides with O, we get t = r . Therefore, C(O, r) and C(O, t) are congruent. Thus, there is one and only one circle passing through three the given non-collinear points. hope u can UNDERSTAND thank you pls follow me |
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| 31. |
2/5 of total students in the class have opted for maths .Find the percentage of students opting maths |
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Answer» =2/5*1/100 =1/250% is RIGHT answer |
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| 32. |
Ereard Mountainslog crust that rise to great heights above theirh Mountains are massive areas of the earth'ssurroundings. They may have steep or gentlethe slopes and occur in long narrow chains calledcom ranges. There are three main types of mountains.(a) fold mountains (b) volcanic mountains, and Fcea (c) block mountains.o8.TOmoshichtheMountains |
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Answer» py89yf has a LOT to do about Step-by-step EXPLANATION: |
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| 33. |
In the given figure, fibd the value of x |
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Answer» Answer: x equals 50 degree(corresponding ANGLES) PLEASE mark me brainliest Step-by-step explanation: |
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| 34. |
Define Tense in two lines.............. |
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Answer» Answer: TENSE is a time DESCRIBED by a VERB , shown by its grammatical FORM. |
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| 35. |
2. The following table gives the weekly wages of workers in a factory.65 - 7070 - 7575 - 8060 - 6555 - 6080 - 85 85-90Weekly Wages (50 - 55No. of workers 520101096128Calculate the mean, by using :(1) Direct Method(ii) Short-Cut Method. |
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Answer» Step-by-step explanation: Given The following table gives the weekly wages of workers in a factory.65 - 70 70 - 75 75 - 80 60 - 65 55 - 60 80 - 85 85-90 Weekly Wages (50 - 55 No. of workers 5 20 10 10 9 6 8 Calculate the mean, by USING : (1) Direct Method (ii) Short-Cut Method. Weekly wages (RS) Number of workers(f) Cumulative frequency Class marks x f(x) 50 – 55 5 5 52.5 262.5 55 – 60 20 25 57.5 1150.0 60 – 65 10 35 62.5 625.0 65 – 70 10 45 67.5 675.0 70 – 75 9 54 72.5 652.0 75 – 80 6 60 77.5 465.085 80 – 85 12 72 82.5 990.0 85 – 90 8 80 87.5 700.0 Total 80 5520.0 Mean = ∑ f(x) / ∑ f = 5520 / 80 = 69 Weekly wages (Rs) Number of workers(f) x I di = Xi – A (67.5) fi di 50 – 55 5 52.5 - 15 - 75 55 – 60 20 57.5 - 10 - 200 60 – 65 10 62.5 - 5 - 50 65 – 70 10 67.5 0 0 70 – 75 9 72.5 5 45 75 – 80 6 77.5 10 60 80 – 85 12 82.5 15 180 85 – 90 8 87.5 20 160 Total 80 so fi di = 120 Mean = A + ∑ fi di / ∑ f i = 67.5 + 120 / 80 = 69 Reference link will be |
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| 36. |
In the adjacent diagram if x:y=3:4 and y:z=1:2 then find angle DCB. |
Answer» HI BUDDY HERE IS YOUR ANSWER WITH FULL EXPLANATION.I HOPE YOU WILL LIKE MY ANSWER.SO, PLEASE MARK ME AS BRAINLIEST IF YOU LIKED MY ANSWER:-)Answer:- x=36° and y=48° and z=96° Step-by-step explanation:- Given: x:y=3:4 and y:z=1:2 To find: Measure of ∠DCB Solution:x:y=3:4 [GIVEN] Which MEANS, x = 3 y 4 Now cross multiplying,we get, 4x=3y 4x =y ----(1 ST equation) 3 Now we put value of y in y:z=1:2, y:z=1:2 Which means, y = 1 z 2 Now cross multiplication, 2y=z Now we put value of y from 1st equation, 2× 4x =z 3 ∴z= 8X ----(2nd equation) 3 Now,x+y+z=180° [Angle sum property] Putting values of y and z from equation 1 and 2 x+ 4x + 8x =180° 3 3 3x + 4x + 8x =180° 3 15x =180° 3 15x=540° ∴x=540°/15 =36° Hence,x=36° y=4x/3=4×36/3=48° z=8x/3=8×36/3=96° THANK YOU HAVE A NICE DAY |
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| 37. |
Dustin is paid $9.80 per hour. He worked 12 hours. He gave his mother LaTeX: \frac{1}{5}1 5 of his earnings. How much did Dustin have left? Group of answer choices A) $588.00 B) $94.08 C) $23.52 D) $117.60 |
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Answer» Answer: 450.80 you MULTIPLY 40 x 9.80 ...equals 392. take 1/2 of 9.80...that equals 4.90. 4.90 PLUS 9.80 equals $14.70 x 4 = 58.80 $58.80 plus 392. equals $450.80 |
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| 38. |
Find a rational between -1and1/2 |
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Answer» Answer: so here's the explanation Step-by-step explanation: 1/2(-1+1/2) then SOLVE the BRACKET and then u will get your answer... PLS mark my answer as BRAINLIEST |
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| 39. |
The edges of a surface are 1 curves 2 points 3 lines 4 none of these |
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Answer» Step-by-step EXPLANATION: pls mark as BRAINLIST answer |
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| 40. |
2.5 L of a sample of a gas at 270 C and 1 bar pressure compressed to a volume of 0.5 L keeping the temperature constant, the increase in pressure(A)2 bar(B)4 bar(C)5 bar(D)6 bar |
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Answer» Step-by-step explanation:
dhvdcsgshhxubes hxhhebbdj
ujghjjj
sorry for this kind of answer plz MARK me as brainlist plz ur the GREAT person |
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| 41. |
What is standard form for 4/6 |
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Answer» Answer: Step-by-step explanation: 2/3 hope it helps if yes so PLZZ MARK me as BRAINLIEST |
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| 42. |
Express -136/17 in standard form |
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Answer» answer is -5 Step-by-step EXPLANATION: |
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| 43. |
In the quadratic equations if a=3 b=6 c=4 then find the value of alpha + bita |
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Answer» Answer: -2 Step-by-step EXPLANATION: ALPHA and beta are the roots of the quadratic equation the sum of roots of quadratic equation is given by (-b/a) alpha+beta = (- 6/3 )= -2 |
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| 44. |
HEY FREIND WHAT IS THE MEANING OF LUMINESCENT |
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Answer» emitting light not CAUSED by HEAT. "the TEAM is developing a TRANSPARENT luminescent solar concentrator" |
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| 45. |
48÷100×8kg please please explain karke bata dijiye |
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Answer» 3.84kilogram Isaka answer HAI |
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| 46. |
2/7 ÷ 5/9 rational number |
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Answer» Answer: 18/35 Step-by-step explanation: 2/7 ÷5/9 2/7 × 9/5 18/35 |
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| 47. |
Pls solve this and send 50points for them.Dont spam I request |
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Answer» |
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| 48. |
Factorise y^2-6y+5.....plzz answer |
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Answer» = y^2 - (5 + 1) y + 5 = y^2 - 5Y - y + 5 = y ( y - 5) - 1 ( y - 5) = ( y - 5 ) ( y - 1 ). (ANS) |
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| 49. |
Calculate the value of x in the given below figure. |
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Answer» Answer: 130 Step-by-step explanation: 55+45+30 |
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| 50. |
9.One-third of acertain journey wascovered at a rate of 25 km/hr, one-fourthat the rate of 30 km/hr and the rest at therate of 50 km/hr. Find the average speedper hour for the whole journey.11(1) 33 – km/hr3(2) 66 – km/hr31(3) 36 = km/hr (4)63 km/hr1 61 6 |
Answer» (4)63 km/hr is answer DEAR FRIEND |
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