332354 + Interview Questions in Secondary School in Math

1.	(i) 18 added to quotient of 16 and 8.
Answer» Answer: UR question isn't proper… From my understanding 18 + 16/8 [16/8 = 2] 18 + 2 = 20 If correct MARK ME BRAINLIEST

1.

(i) 18 added to quotient of 16 and 8.

Answer»

Answer:

UR question isn't proper…

From my understanding

18 + 16/8

[16/8 = 2]

18 + 2 = 20

If correct MARK ME BRAINLIEST

Discussion

2.	The ages, year, of four boys are 10, 12, 14 and 18. What is the average age of boys?
Answer» Answer: Given 10,12,14 And 18 Are the ages of four boys Average=? Average = sum of all observations / 2 10 + 12 + 14 + 18 / 2 54 / 2 = 17 Tʜᴇ ᴀᴠᴇʀᴀɢᴇ ᴀɢᴇ ᴏғ ʙᴏʏs ɪs 17 Hᴏᴏᴇ ɪᴛ ʰᵉˡᵖˢ ᵘ✅

2.

The ages, year, of four boys are 10, 12, 14 and 18. What is the average age of boys?

Answer»

Answer:

Given 10,12,14 And 18 Are the ages of four boys

Average=?

Average = sum of all observations / 2

10 + 12 + 14 + 18 / 2

54 / 2

= 17

Tʜᴇ ᴀᴠᴇʀᴀɢᴇ ᴀɢᴇ ᴏғ ʙᴏʏs ɪs

17

Hᴏᴏᴇ ɪᴛ ʰᵉˡᵖˢ ᵘ✅

Discussion

3.	65895÷150=(Q:__) R:__)
Answer» ANSWER: q:439 R:45 I HOPE you LIKE answer

3.

65895÷150=(Q:) R:)

Answer»

ANSWER:

q:439

R:45

I HOPE you LIKE answer

Discussion

4.	A shopkeeper sells 2 qualities of rice at the rates of 27.5 $ per kg and 42$ per kg respectively. gaining a profit of 10% and 20% respectively. If he mixes the 2 variants in the ratio 4:1 and sell it at 32$ per kg. What is his gain or loss %?
Answer» answer= 5kg=18.52% 1kg=3.70% HOPE you like the answer please MARK me as BRAINLIEST and please FOLLOW me so that I can answer any QUESTIONS quickly ☺️☺️

4.

A shopkeeper sells 2 qualities of rice at the rates of 27.5 $ per kg and 42$ per kg respectively. gaining a profit of 10% and 20% respectively. If he mixes the 2 variants in the ratio 4:1 and sell it at 32$ per kg. What is his gain or loss %?

Answer»

answer= *5kg=18.52%

*1kg=3.70%

HOPE you like the answer please MARK me as BRAINLIEST and please FOLLOW me so that I can answer any QUESTIONS quickly ☺️☺️

Discussion

5.	Calculate the circumference of a circle3.5= Radius10mm= Diameter
Answer» Answer: CIRCUMFERENCE of a circle whose R= 3.5 2πr = 2×22/7× 3.5 = 22cm circumference of a circle whose r= 10 mm 2πr= 2× 22/7× 10mm = 440/7mm

5.

Calculate the circumference of a circle3.5= Radius10mm= Diameter

Answer»

Answer:

CIRCUMFERENCE of a circle whose R= 3.5

2πr = 2×22/7× 3.5

= 22cm

circumference of a circle whose r= 10 mm

2πr= 2× 22/7× 10mm

= 440/7mm

Discussion

6.	icse class 10 question from quadratic equations , problem on geometrical figures . I want full answer please help ✨
Answer» QUESTION: The hypotenuse of a right angled triangle is 9 cm more than the shortest SIDE. The THIRD side is 8 cm less than the hypotenuse, find the SIDES of the triangle. ANSWER: The sides are Hypotenuse = 29 cm Shortest side = 20 cm Third side = 21 cm. GIVEN: The hypotenuse of a right angled triangle is 9 cm more than the shortest side. The third side is 8 cm less than the hypotenuse. EXPLANATION: Let the shortest side be x cm. Hypotenuse = x + 9 cm. Third side = Hypotenuse - 8 Third side = x + 9 - 8 Third side = x + 1 cm According to Pythagoras theorem: Square of hypotenuse is equal to the sum of the squares of the other two sides. (x + 9)² = x² + (x + 1)² (A + B)² = A² + 2AB + B² x² + 2(9x) + 9² = x² + x² + 2(x) + 1² x² + 18x + 81 = 2x² + 2x + 1 x² - 16x - 80 = 0 Splitting the middle term x² - 16x - 4x + 4x - 80 = 0 x² - 20 x + 4x - 80 = 0 x(x - 20) + 4(x - 20) (x + 4)(x - 20) = 0 x = 20 (Length cannot be negative so x ≠ - 4) Length of shortest side = 20 cm Hypotenuse = x + 9 = 20 + 9 = 29 cm Third side = x + 1 = 20 + 1 = 21 cm. VERIFICATION: (x + 9)² = x² + (x + 1)² (20 + 9)² = 20² + (20 + 1)² (29)² = 20² + (21)² 841 = 400 + 441 841 = 841 HENCE VERIFIED.

6.

icse class 10 question from quadratic equations , problem on geometrical figures . I want full answer please help ✨

Answer»

QUESTION:

The hypotenuse of a right angled triangle is 9 cm more than the shortest SIDE. The THIRD side is 8 cm less than the hypotenuse, find the SIDES of the triangle.

ANSWER:

The sides are

Hypotenuse = 29 cm
Shortest side = 20 cm
Third side = 21 cm.

GIVEN:

The hypotenuse of a right angled triangle is 9 cm more than the shortest side.

The third side is 8 cm less than the hypotenuse.

EXPLANATION:

Let the shortest side be x cm.

Hypotenuse = x + 9 cm.

Third side = Hypotenuse - 8

Third side = x + 9 - 8

Third side = x + 1 cm

According to Pythagoras theorem:

Square of hypotenuse is equal to the sum of the squares of the other two sides.

(x + 9)² = x² + (x + 1)²

(A + B)² = A² + 2AB + B²

x² + 2(9x) + 9² = x² + x² + 2(x) + 1²

x² + 18x + 81 = 2x² + 2x + 1

x² - 16x - 80 = 0

Splitting the middle term

x² - 16x - 4x + 4x - 80 = 0

x² - 20 x + 4x - 80 = 0

x(x - 20) + 4(x - 20)

(x + 4)(x - 20) = 0

x = 20 (Length cannot be negative so x ≠ - 4)

Length of shortest side = 20 cm

Hypotenuse = x + 9 = 20 + 9 = 29 cm

Third side = x + 1 = 20 + 1 = 21 cm.

VERIFICATION:

(x + 9)² = x² + (x + 1)²

(20 + 9)² = 20² + (20 + 1)²

(29)² = 20² + (21)²

841 = 400 + 441

841 = 841

HENCE VERIFIED.

Discussion

7.	O is the centre of circle R is external point to the circle from point R, seg RM and seg RN are tangent segments touching the circle at M and N.If OR=10 cm and radius of circle is 5 cm then,find length of each tangent segments O हे वर्तुळ केंद्र असून R हा वर्तुळाबाहेरील बिंदू आहे. रेख RM व रेख RN ह्या स्पर्शिका वर्तुळाला अनुक्रमे M व N बिंदूत छेदतात . जर OR=10 सेमी आणि वर्तुळाची त्रिज्या 5 सेमी असेल तर प्रत्येक स्पर्शिका खंडाची लांबी किती ? *15 cm10√3 cm5√3 cm25 cm
Answer» Step-by-step explanation: (1) It is given that line AB is tangent to the circle at A. ∴ ∠CAB = 90º (Tangent at any point of a circle is perpendicular to the radius throught the point of contact) Thus, the measure of ∠CAB is 90º. (2) Distance of point C from AB = 6 cm (Radius of the circle) (3) ∆ABC is a RIGHT triangle. CA = 6 cm and AB = 6 cm Using PYTHAGORAS theorem, we have BC2=AB2+CA2⇒BC=62+62−−−−−−√ ⇒BC=62–√ cm Thus, d(B, C) = 62–√ cm (4) In right ∆ABC, AB = CA = 6 cm ∴ ∠ACB = ∠ABC (Equal sides have equal angles opposite to them) Also, ∠ACB + ∠ABC = 90º (Using ANGLE sum PROPERTY of triangle) ∴ 2∠ABC = 90º ⇒ ∠ABC = 90°2 = 45º Thus, the measure of ∠ABC is 45º.

7.

O is the centre of circle R is external point to the circle from point R, seg RM and seg RN are tangent segments touching the circle at M and N.If OR=10 cm and radius of circle is 5 cm then,find length of each tangent segments O हे वर्तुळ केंद्र असून R हा वर्तुळाबाहेरील बिंदू आहे. रेख RM व रेख RN ह्या स्पर्शिका वर्तुळाला अनुक्रमे M व N बिंदूत छेदतात . जर OR=10 सेमी आणि वर्तुळाची त्रिज्या 5 सेमी असेल तर प्रत्येक स्पर्शिका खंडाची लांबी किती ? *15 cm10√3 cm5√3 cm25 cm

Answer»

Step-by-step explanation:

(1) It is given that line AB is tangent to the circle at A.

∴ ∠CAB = 90º (Tangent at any point of a circle is perpendicular to the radius throught the point of contact)

Thus, the measure of ∠CAB is 90º.

(2) Distance of point C from AB = 6 cm (Radius of the circle)

(3) ∆ABC is a RIGHT triangle.

CA = 6 cm and AB = 6 cm

Using PYTHAGORAS theorem, we have

BC2=AB2+CA2⇒BC=62+62−−−−−−√ ⇒BC=62–√ cm

Thus, d(B, C) = 62–√ cm

(4) In right ∆ABC, AB = CA = 6 cm

∴ ∠ACB = ∠ABC (Equal sides have equal angles opposite to them)

Also, ∠ACB + ∠ABC = 90º (Using ANGLE sum PROPERTY of triangle)

∴ 2∠ABC = 90º

⇒ ∠ABC = 90°2 = 45º

Thus, the measure of ∠ABC is 45º.

Discussion

8.	3. (25 x 10)/(5(6 - 4)2) = ?(A) 200(B) 50(C) 25/2(D) 25
Answer» ANSWER: MASS 67 Step-by-step EXPLANATION:

8.

3. (25 x 10)/(5(6 - 4)2) = ?(A) 200(B) 50(C) 25/2(D) 25

Answer»

ANSWER:

MASS 67

Step-by-step EXPLANATION:

Discussion

9.	A earns 60% of B’s salary, B earns 70% of C’s salary. If the total earnings for a month is Rs. 19080, then what is the earning for A ?
Answer» Step-by-step EXPLANATION: Let C's SALARY be Rs. x Then B's salary = 80x/100 => A's salary = (50/100) * (80x/100) = 40x/100 But GIVEN total earnings in a month = 22000 => x + 80x/100 + 40x/100 = 22000 => x + 120x/100 = 22000 => x = 10000 => A's salary = 40 x 10000/100 = Rs. 4000

9.

A earns 60% of B’s salary, B earns 70% of C’s salary. If the total earnings for a month is Rs. 19080, then what is the earning for A ?

Answer»

Step-by-step EXPLANATION:

Let C's SALARY be Rs. x

Then B's salary = 80x/100

=> A's salary = (50/100) * (80x/100) = 40x/100

But GIVEN total earnings in a month = 22000

=> x + 80x/100 + 40x/100 = 22000

=> x + 120x/100 = 22000

=> x = 10000

=> A's salary = 40 x 10000/100 = Rs. 4000

Discussion

10.	We should divide 32.292÷14.04
Answer» Answer: 2.3 is the RIGHT answer plz MARK me as BRAINLIEST

10.

We should divide 32.292÷14.04

Answer»

Answer:

2.3 is the RIGHT answer

plz MARK me as BRAINLIEST

Discussion

11.	Determine whether g(x) is a factor of f(x) 1); f(x) =3x^3+x^2-20x+12;g(x)=3x-3
Answer» Answer: 3x-3=0 3x=3 x=3/3 x=1 F(x)=3x³+x²-20x+12 f(1)=3(1)³+(1)²-20×1+12 =3+1-20+12 =16-20 =-4 g(x) is not a FACTOR of f(x)

11.

Determine whether g(x) is a factor of f(x) 1); f(x) =3x^3+x^2-20x+12;g(x)=3x-3

Answer»

Answer:

3x-3=0

3x=3

x=3/3

x=1

F(x)=3x³+x²-20x+12

f(1)=3(1)³+(1)²-20×1+12

=3+1-20+12

=16-20

=-4

g(x) is not a FACTOR of f(x)

Discussion

12.	Question 2 & 3 please help urgent. due in 5 mintues plz help
Answer» ANSWER: I'm police officer need help FORM all of you don't be NERVOUS about it

12.

Question 2 & 3 please help urgent. due in 5 mintues plz help

Answer»

ANSWER:

I'm police officer need help FORM all of you don't be NERVOUS about it

Discussion

13.	A box of 600 bulb contain 12 defective bulb.One bulb is taken out . At rendom from this box. Then the probability that it's is non defective bulb isa) 143/150b) 147/150c) 1/25d) 1/59please solve fast
Answer» Answer: TOTAL NUMBER of bulbs = 600 Total number of non-defective bulb = 600-12=588 P (non-defective bulbs) = 588/600 =0.98 Step-by-step explanation: Pls THANK my answers and Mark me as BRAINLIEST

13.

A box of 600 bulb contain 12 defective bulb.One bulb is taken out . At rendom from this box. Then the probability that it's is non defective bulb isa) 143/150b) 147/150c) 1/25d) 1/59please solve fast

Answer»

Answer:

TOTAL NUMBER of bulbs = 600

Total number of non-defective bulb = 600-12=588

P (non-defective bulbs) = 588/600

=0.98

Step-by-step explanation:

Pls THANK my answers and Mark me as BRAINLIEST

Discussion

14.	tell the correct answer don not leave the answer pls. if you know the answer, write it correctly....if u do not know then do not write plzzz....if u write the answer correctly, i will mark u as brainliest and give u a thanks and rate ur answer excellent....
Answer» Where is the QUESTION?

Discussion

15.	Pls anyone provide surface area and volume notes
Answer» ANSWER: where is QUESTIONS BRO

15.

Pls anyone provide surface area and volume notes

Answer»

ANSWER:

where is QUESTIONS BRO

Discussion

16.	A natural number that can be expressed as a product of two prime numbers is called semi prime numberFor example, 77 is semi-prime since it is a product of two prime numbers, 7and 11[Remember that I is not prime]Question 1. Find the smallest semi-prime number.
Answer» Answer: 4 is the SEMI PRIME number Step-by-step EXPLANATION: PLEASE MARK me as brainlist

16.

A natural number that can be expressed as a product of two prime numbers is called semi prime numberFor example, 77 is semi-prime since it is a product of two prime numbers, 7and 11[Remember that I is not prime]Question 1. Find the smallest semi-prime number.

Answer»

Answer:

4 is the SEMI PRIME number

Step-by-step EXPLANATION:

PLEASE MARK me as brainlist

Discussion

17.	5. If a and b are odd numbers, then which ofthe following is even?laat b(b) a + b + 1(c) ab(d) ab + 2 buonis
Answer» a) option is CORRECT like my answer if it help U BYE Bye

17.

5. If a and b are odd numbers, then which ofthe following is even?laat b(b) a + b + 1(c) ab(d) ab + 2 buonis

Answer»

a) option is CORRECT

like my answer if it help U

BYE Bye

Discussion

18.	Two circles having radii 4.5 cm and 5.2 cm touch each other internally .Find the distance between their centres. 10) दोन अंतर्स्पशी वर्तुळांच्या त्रिज्या 4.5 सेमी आणि 5.2 सेमी आहे तर त्याच्या केंद्रांमधील अंतर किती ?. *0.7 cm2.7 cm5.3 cm9.7 cm
Answer» Step-by-step EXPLANATION: i HOPE this will be HELP you.....

18.

Two circles having radii 4.5 cm and 5.2 cm touch each other internally .Find the distance between their centres. 10) दोन अंतर्स्पशी वर्तुळांच्या त्रिज्या 4.5 सेमी आणि 5.2 सेमी आहे तर त्याच्या केंद्रांमधील अंतर किती ?. *0.7 cm2.7 cm5.3 cm9.7 cm

Answer»

Step-by-step EXPLANATION:

i HOPE this will be HELP you.....

Discussion

19.	Find the value of (64/216)whole to the power of -2/3
Answer» ANSWER: $( \frac{216}{64} ) {}^{ \frac{2}{3} } = ( \frac{216}{64} ) {}^{2 \times \frac{1}{3} } = ( \frac{8}{4} ) {}^{2} = \frac{64}{16} = 4$ Hope this will HELP you and PLEASE MARK me Brainlist

19.

Find the value of (64/216)whole to the power of -2/3

Answer»

ANSWER:

$( \frac{216}{64} ) {}^{ \frac{2}{3} } = ( \frac{216}{64} ) {}^{2 \times \frac{1}{3} } = ( \frac{8}{4} ) {}^{2} = \frac{64}{16} = 4$

Hope this will HELP you and PLEASE MARK me Brainlist

Discussion

20.	What is the meaning of rational number
Answer» In mathematics, a RATIONAL number is a number that can be expressed as the QUOTIENT or fraction p/Q of two integers, a numerator p and a non-zero denominator q. Since q MAY be equal to 1, EVERY integer is a rational number.

Discussion

21.	Find the equation of the line passing through (2, -1) and parallel to the line 2x – y = 4
Answer» Answer: 2x-y-4=0 Step-by-step EXPLANATION: they have given that 2x-y=4, they told US to form the equation.. push the 4 to LHS...then change the SIGN to -

21.

Find the equation of the line passing through (2, -1) and parallel to the line 2x – y = 4

Answer»

Answer:

2x-y-4=0

Step-by-step EXPLANATION:

they have given that 2x-y=4,

they told US to form the equation..

push the 4 to LHS...then change the SIGN to -

Discussion

22.	15 by 18 +16 by 20 it's 15/18+16/20 I will ask next question next time
Answer» ANSWER: PLEASE WRITE the FULL QUESTION

22.

15 by 18 +16 by 20 it's 15/18+16/20 I will ask next question next time

Answer»

ANSWER:

PLEASE WRITE the FULL QUESTION

Discussion

23.	15. Find the measure of angle x in the following figures. Give reason also.601104047(a)(b)(c)
Answer» Step-by-step EXPLANATION: MATE the QUESTIN is not clear. where is the equation. put in linely. or take a PHOTO and post. plz

23.

15. Find the measure of angle x in the following figures. Give reason also.601104047(a)(b)(c)

Answer»

Step-by-step EXPLANATION:

MATE the QUESTIN is not clear.

where is the equation.

put in linely.

or

take a PHOTO and post.

plz

Discussion

24.	15. 1'x 22x 33 x 44 x 55 x 6°x77x 88 99 x 1010. find the consecutive zeros at the end(a) 25(b) 15(c) 10(d) 20
Answer» ANSWER: 25 is the answer PLZ MARK as BRAINLIEST and FOLLOW me

24.

15. 1'x 22x 33 x 44 x 55 x 6°x77x 88 99 x 1010. find the consecutive zeros at the end(a) 25(b) 15(c) 10(d) 20

Answer»

ANSWER:

25 is the answer

PLZ MARK as BRAINLIEST and FOLLOW me

Discussion

25.	Divide 3 x ² + 5x² + 7x².50 +8 by (x²+3
Answer» Answer: exponent CHANGES. =2(3)+8. =6 + 8. = 35 x 102 . = 3.5 x 10-1. 3.5 x 10". = 14 ... Solve when: X = -2; y = 3 ... =3(-2)²(3)+2(3)(-2)-5(3) ... Divide the numbers and ... L(7x² +5)– (4X' – 5x). =-\|( 7x² ... Step-by-step explanation: PLZ follow me

25.

Divide 3 x ² + 5x² + 7x².50 +8 by (x²+3

Answer»

Answer:

exponent CHANGES. =2(3)+8. =6 + 8. = 35 x 102 . = 3.5 x 10-1. 3.5 x 10". = 14 ... Solve when: X = -2; y = 3 ... =3(-2)²(3)+2(3)(-2)-5(3) ... Divide the numbers and ... L(7x² +5)– (4X' – 5x). =-|( 7x² ...

Step-by-step explanation:

PLZ follow me

Discussion

26.	M1 5kg and m2 8kg. find accerlation and tension.don't post irrelevant answer .I will give brainlist answer which give right answer
Answer» GIVEN M1= 5KG and M2= 8kg a= (m2-m1) /(m2+m1) (g) = 5-2/5+2 (g) a = 3g/7

26.

M1 5kg and m2 8kg. find accerlation and tension.don't post irrelevant answer .I will give brainlist answer which give right answer

Answer»

GIVEN M1= 5KG and M2= 8kg

a= (m2-m1) /(m2+m1) (g)

= 5-2/5+2 (g)

a = 3g/7

Discussion

27.	If 3 is a solution of 3x²-(k-1)x +18=0,Then the value of 'k' is
Answer» To Find : -- We need to find the VALUE of k. SOLUTION : -- 3 is a Solution of 3x²-(k-1)x +18 So, x = 3 ››➔ 3x² - (k - 1)x + 18 = 0 ››➔ 3 × 3² - (k - 1) × 3 + 18 = 0 ››➔ 3 × 9 - 3k + 3 + 18 = 0 ››➔ 27 - 3k + 21 = 0 ››➔ - 3k = -48 ››➔ k = -48/-3 ››➔ k = 16 Hence, Value of k = 16 Verification :- ›› 3x² - (k - 1)x + 18 ›› 3x² -(16 - 1)x + 18 ›› 3x² - 15x + 18 ›› 3x² - 9x - 6x + 18 ›› 3x(x - 3) - 6(x - 3) ›› (3x - 6) or (x - 3) ›› x = 2 or x = 3 Hence we get Solution (x = 3) of the given equation that is given in the Question . HENCE VERIFIED ━━━━━━━━━━━━━━━━━━━━━━━━━

27.

If 3 is a solution of 3x²-(k-1)x +18=0,Then the value of 'k' is

Answer»

To Find : --

We need to find the VALUE of k.

SOLUTION : --

3 is a Solution of 3x²-(k-1)x +18

So,

x = 3

››➔ 3x² - (k - 1)x + 18 = 0

››➔ 3 × 3² - (k - 1) × 3 + 18 = 0

››➔ 3 × 9 - 3k + 3 + 18 = 0

››➔ 27 - 3k + 21 = 0

››➔ - 3k = -48

››➔ k = -48/-3

››➔ k = 16

Hence,

Value of k = 16

Verification :-

›› 3x² - (k - 1)x + 18

›› 3x² -(16 - 1)x + 18

›› 3x² - 15x + 18

›› 3x² - 9x - 6x + 18

›› 3x(x - 3) - 6(x - 3)

›› (3x - 6) or (x - 3)

›› x = 2 or x = 3

Hence we get Solution (x = 3) of the given equation that is given in the Question .

HENCE VERIFIED

━━━━━━━━━━━━━━━━━━━━━━━━━

Discussion

28.	14.Two points of height 7m and 10m stand vertically on the ground such that the distance between themis 12mFind the distance between their tope
Answer» In ∆ABE, AB = 3 m. [ SIDE ] BE = 12 m. [ Side ] AE = ? [ HYPOTENUSE ] BY USING PYTHAGORAS theorem... ◼ (Hypotenuse)² = (Side)² + (Side)² ➡ (AE)² = (3)² + (12)² ➡ (AE)² = 9 + 144 ➡ (AE)² = 153 ➡ AE = √153 ➡ AE = 12.36 m Hence, the distance between thier tops is 12.36 m (or) √153 m.

28.

14.Two points of height 7m and 10m stand vertically on the ground such that the distance between themis 12mFind the distance between their tope

Answer»

In ∆ABE,

AB = 3 m. [ SIDE ]
BE = 12 m. [ Side ]
AE = ? [ HYPOTENUSE ]

BY USING PYTHAGORAS theorem...

◼ (Hypotenuse)² = (Side)² + (Side)²

➡ (AE)² = (3)² + (12)²

➡ (AE)² = 9 + 144

➡ (AE)² = 153

➡ AE = √153

➡ AE = 12.36 m

Hence, the distance between thier tops is 12.36 m (or) √153 m.

Discussion

29.	Please answer me this question.......?????
Answer» Which QUESTION didn't you GET ? I HOPE it's from TRIGONOMETRY ...

29.

Please answer me this question.......?????

Answer»

Which QUESTION didn't you GET ?

I HOPE it's from TRIGONOMETRY ...

Discussion

30.	Please someone help.....
Answer» Step-by-step EXPLANATION: x-2 = 7 =) X=9 2y+3=10=) Y=7 Z+2=6=)z=4 6x=12=)x=2 t/5=10=)t=50 2x/3=18=)x=27 1.6=y/1.5=)y=2.4 7x-9=16=)x=1

30.

Please someone help.....

Answer»

Step-by-step EXPLANATION:

x-2 = 7 =) X=9

2y+3=10=) Y=7

Z+2=6=)z=4

6x=12=)x=2

t/5=10=)t=50

2x/3=18=)x=27

1.6=y/1.5=)y=2.4

7x-9=16=)x=1

Discussion

31.	3.5and height 14cm2. If the diameter of abroad roller is 96cmand length is 100cm. It takes 300 completerevolutions to roll once over theplayground to level. Find the area of theplayground in m?
Answer» Answer: HOPE it helps you Step-by-step explanation: diameter = 96cm radius = 48 cm Curved SURFACE area of cylinder = 2πrh = 2×22÷7×48cm×100cm = 30171.430cm² (approx.) Area of PLAYGROUND = 30171.430cm²×300 = 9051.430cm² (approx.)

31.

3.5and height 14cm2. If the diameter of abroad roller is 96cmand length is 100cm. It takes 300 completerevolutions to roll once over theplayground to level. Find the area of theplayground in m?

Answer»

Answer:

HOPE it helps you

Step-by-step explanation:

diameter = 96cm

radius = 48 cm

Curved SURFACE area of cylinder = 2πrh

= 2×22÷7×48cm×100cm

= 30171.430cm² (approx.)

Area of PLAYGROUND = 30171.430cm²×300

= 9051.430cm² (approx.)

Discussion

32.	Find the value of X 5x = 12
Answer» ANSWER: 2.4 is the answer you have to DIVIDE 12 by 5

32.

Find the value of X 5x = 12

Answer»

ANSWER:

2.4 is the answer you have to DIVIDE 12 by 5

Discussion

33.	Express the following numbers in standard form.(a) 0.00000000000085(b) 0.0000000000004995(d) 813200000000(e) 13960000000
Answer» Answer: 8.5 X 10-¹³ 4.995 x 10-¹³ 8.132 x 10¹¹ 1.396 x 10^10

33.

Express the following numbers in standard form.(a) 0.00000000000085(b) 0.0000000000004995(d) 813200000000(e) 13960000000

Answer»

Answer:

8.5 X 10-¹³

4.995 x 10-¹³

8.132 x 10¹¹

1.396 x 10^10

Discussion

34.	Divide 3x+5+2-50 + 8 by +3)
Answer» ANSWER: $3 + 3x - 50 + 8 \div 3 \\ - 42 + 3 + 3x \div 3 \\ - 39 + 3x \div 3 \\ 3x = - 39 \div 3 \\ x = - 13$ Step-by-step EXPLANATION: MAYBE QUESTION is WRONG

34.

Divide 3x+5+2-50 + 8 by +3)

Answer»

ANSWER:

$3 + 3x - 50 + 8 \div 3 \\ - 42 + 3 + 3x \div 3 \\ - 39 + 3x \div 3 \\ 3x = - 39 \div 3 \\ x = - 13$

Step-by-step EXPLANATION:

MAYBE QUESTION is WRONG

Discussion

35.	Find the diagonal of rectangle whose length is 35 cm and breadth is 12 cm . 9) आयताची लांबी 35 सेमी आणि रुंदी 12 सेमी आहे. तर कर्णाची लांबी काढा . *33353739
Answer» Answer:37cm Step-by-step EXPLANATION: Here is yr answer ___________________________ Let US TAKE a rectangle ABCD in which AC is a diagonal AB=35 cm BC=12 cm AC=?? By pythagoras THEROM...... AC² =AB² + BC² AC² =35² + 12² AC² =1225 + 144 AC = √1369 AC = 37 cm Therefore, diagonal of the recatangle = 37 cm Hope it hlpzz...

35.

Find the diagonal of rectangle whose length is 35 cm and breadth is 12 cm . 9) आयताची लांबी 35 सेमी आणि रुंदी 12 सेमी आहे. तर कर्णाची लांबी काढा . *33353739

Answer»

Answer:37cm

Step-by-step EXPLANATION:

Here is yr answer ___________________________

Let US TAKE a rectangle ABCD

in which AC is a diagonal

AB=35 cm

BC=12 cm

AC=??

By pythagoras THEROM......

AC² =AB² + BC²

AC² =35² + 12²

AC² =1225 + 144

AC = √1369

AC = 37 cm

Therefore, diagonal of the recatangle = 37 cm

Hope it hlpzz...

Discussion

36.	3.If the volume of a cube is 216cm3 thenfind its T.S.A, C.S.A
Answer» ANSWER: TSA = 216 cm2 ; CSA = 144 cm2 Step-by-step explanation: VOLUME= 216 cm2 Volume of cube = a x a x a Therefore, a x a x a = 216 a3=216 a= cube ROOT of 216 a = 6 TSA = 6a2 TSA = 6 x (6)2 TSA = 6 x 36 TSA = 216 cm2 CSA = 4a2 CSA = 4 x (6)2 CSA = 4 x 36 CSA = 144 cm2

36.

3.If the volume of a cube is 216cm3 thenfind its T.S.A, C.S.A

Answer»

ANSWER:

TSA = 216 cm2 ; CSA = 144 cm2

Step-by-step explanation:

VOLUME= 216 cm2

Volume of cube = a x a x a

Therefore, a x a x a = 216

a3=216

a= cube ROOT of 216

a = 6

TSA = 6a2

TSA = 6 x (6)2

TSA = 6 x 36

TSA = 216 cm2

CSA = 4a2

CSA = 4 x (6)2

CSA = 4 x 36

CSA = 144 cm2

Discussion

37.	A 200m long train crosses a platform of double its in 36s . The speed of the train
Answer» ANSWER: 6.5m/s is the CORRECT answer.

37.

A 200m long train crosses a platform of double its in 36s . The speed of the train

Answer»

ANSWER:

6.5m/s is the CORRECT answer.

Discussion

38.	33. यदि किसी भिन्न के अंश में 25% वृद्धि कर दी जाये तथा इसके हर में 10% कमी कर दीजाये तो भिन्न का नया मान क्या होगा?1620
Answer» Step-by-step explanation: HOPE it HELPS you PLS MARK brainliest answer

38.

33. यदि किसी भिन्न के अंश में 25% वृद्धि कर दी जाये तथा इसके हर में 10% कमी कर दीजाये तो भिन्न का नया मान क्या होगा?1620

Answer»

Step-by-step explanation:

HOPE it HELPS you PLS MARK brainliest answer

Discussion

39.	Find Z , X, Y??? and state the properties???
Answer» ANSWER: x=110 y=40 z=30 is the answer

39.

Find Z , X, Y??? and state the properties???

Answer»

ANSWER:

x=110

y=40

z=30

is the answer

Discussion

40.	2. Fill in the blanks with appropriate articles and prepositions:-And there was claude, standing____ ____bit of cord____in hand, looking foolish.
Answer» ANSWER: And there was Claude, STANDING with a bit of CORD in his hand, looking FOOLISH.

40.

2. Fill in the blanks with appropriate articles and prepositions:-And there was claude, standing bit of cordin hand, looking foolish.

Answer»

ANSWER:

And there was Claude, STANDING with a bit of CORD in his hand, looking FOOLISH.

Discussion

41.	Gal 01 (x).COS XLet f (x)0
Answer» ANSWER: I don't KNOW answer of this QUESTION

41.

Gal 01 (x).COS XLet f (x)0

Answer»

ANSWER:

I don't KNOW answer of this QUESTION

Discussion

42.	Rewrite each of the following polynomial in its simplest form.1) (2a^2- 3a +1 ) + ( a^2- 4a- 2)
Answer» ANSWER: answer is 2 only ................. (2-1+1) + (2-1-1) = 1+1 + 1-1 = 2+0 =2

42.

Rewrite each of the following polynomial in its simplest form.1) (2a^2- 3a +1 ) + ( a^2- 4a- 2)

Answer»

ANSWER:

answer is 2 only ................. (2-1+1) + (2-1-1) = 1+1 + 1-1 = 2+0 =2

Discussion

43.	(d)Express the following numbers into normal form.(a) 3.96 X 106 (b) 7 X 10-8 (c) 3.02 x 10-6
Answer» Step-by-step explanation: ) Express the FOLLOWING numbers into normal form. (a) 3.96 X 106 (b) 7 X 10-8 (C) 3.02 x 10-6

43.

(d)Express the following numbers into normal form.(a) 3.96 X 106 (b) 7 X 10-8 (c) 3.02 x 10-6

Answer»

Step-by-step explanation:

)

Express the FOLLOWING numbers into normal form.

(a) 3.96 X 106 (b) 7 X 10-8 (C) 3.02 x 10-6

Discussion

44.	Complete the given series:2139,2295,2451,2607,2763,2919,?
Answer» ANSWER: this is the BEST answer to your PLEASE MAKE me as BRAINLEAST

44.

Complete the given series:2139,2295,2451,2607,2763,2919,?

Answer»

ANSWER:

this is the BEST answer to your

PLEASE MAKE me as BRAINLEAST

Discussion

45.	Determine whether g(x) is a factor of f(x) 1); f(x)=x^4-x^3+x^2-x+1 ;g(x)=x+1
Answer» Step-by-step explanation: Given : $f (x)=x^4-x^3+x^2-x+1$ $g (x)=x+1=>x+1=0=>x= -1$ $g (x)= (1)^4-(1)^3+(1)^2-(1)+1$ $g (x)=1-1+1-1+1=1$ $g (x)= 1,\ therefore\ it\ is\ not\ a\ factor\ of\ the\ given\ equation.$ $\text{[math]}$ HOPE it HELPS U ........ Mark me as BRAINLIEST PLZ : )

45.

Determine whether g(x) is a factor of f(x) 1); f(x)=x^4-x^3+x^2-x+1 ;g(x)=x+1

Answer»

Step-by-step explanation:

Given :

$f (x)=x^4-x^3+x^2-x+1$

$g (x)=x+1=>x+1=0=>x= -1$

$g (x)= (1)^4-(1)^3+(1)^2-(1)+1$

$g (x)=1-1+1-1+1=1$

$g (x)= 1,\ therefore\ it\ is\ not\ a\ factor\ of\ the\ given\ equation.$

$\text{[math]}$

HOPE it HELPS U ........

Mark me as BRAINLIEST PLZ

: )

Discussion

46.	Which one of the following is true( A). √2 € Q ( B) 2/3 € R (C). - 3 € W (D). 5 € R
Answer» $\blue{\underline{\bf\green{ \quad {}^{2} \!\!/\!_3 \: \in \: <klux>R</klux> \quad }}}$ and $\blue{\underline{\bf\green{ \quad 5 \: \in \: R \quad }}}$ are true. (A) √2 € Q (B) 2/3 € R ✅ (C) -3 € W (D) 5 € R ✅ $\mid \underline{\underline{\LARGE\bf\green{Brainliest \: Answer}}}\mid$ ❤ 50 ➕ føĺĺøw ♒ INBOX

Discussion

47.	Log[(sectheta +tan theta) (sectheta -tantheta)]=__a)1b)0c)sec^2theta - tan^2thetad)not defined
Answer» Answer: Answer: zero Formulae USED: Sec²x-tan²x=1 Solution: It is given that, ⟹ LOG[(sectheta+tan theta)(sectheta-tan theta)] ⟹ log[(sec² theta-tan² theta)] By *using* *the* *identity*, ⟹ log**[(1)] ⟹ 0

47.

Log[(sectheta +tan theta) (sectheta -tantheta)]=__a)1b)0c)sec^2theta - tan^2thetad)not defined

Answer»

Answer:

Answer:

zero

Formulae USED:

Sec²x-tan²x=1

Solution:

It is given that,

⟹ LOG[(sectheta+tan theta)(sectheta-tan theta)]

⟹ log[(sec² theta-tan² theta)]

By using the identity,

⟹ log[(1)]

⟹ 0

Discussion

48.	Q. The sum of first n terms 2of an AP is n?. Then sixthterm (an) of AP is: *11O121314
Answer» It means n TERMS are 1st n odd natural number. 1,3,5,7,9,11,13,....... So 6th odd natural number = 11. ANS

48.

Q. The sum of first n terms 2of an AP is n?. Then sixthterm (an) of AP is: *11O121314

Answer»

It means n TERMS are 1st n odd natural number.

1,3,5,7,9,11,13,.......

So 6th odd natural number = 11. ANS

Discussion

49.	Try to solve the following questions:(1)2a - 2/a + 1 = 0, calculate the value of a^3 - 1/a^3 +2 (ans):3/8. (2) if m+n = 5 and mn=6, find out the value of. (m^2 + n^2)(m^3 + n^3). (ans:455)
Answer» Answer: What would you LIKE to ASK? 10th Maths Pair of Linear Equations in TWO Variables Algebraic SOLUTION of a Pair of Linear Equations Determine the value of m &... MATHS avatar Asked on January 17, 2020 by Aaroohi Nagar Determine the value of m and N so that the pair of linear equations (2m+1)x+3y=5 3x+(n−1)y=2 have infinite number of solutions. MEDIUM Share Study later ANSWER (2m+1)x+3y−5=0 3x+(n−1)y−2 condition for a pair of linear equations to have infinite number of solutions a 2 a 1 = b 2 b 1 = c 2 c 1 3 2m+1 = n−1 3 = −2 −5 3 2m+1 = 2 5 4m+2=15 4m=13 m= 4 13 n−1 3 = 2 5 5n−5=6 5n=11 n= 5 11 my friend hope it will help u

49.

Try to solve the following questions:(1)2a - 2/a + 1 = 0, calculate the value of a^3 - 1/a^3 +2 (ans):3/8. (2) if m+n = 5 and mn=6, find out the value of. (m^2 + n^2)(m^3 + n^3). (ans:455)

Answer»

Answer:

What would you LIKE to ASK?

10th

Maths

Pair of Linear Equations in TWO Variables

Algebraic SOLUTION of a Pair of Linear Equations

Determine the value of m &...

MATHS

avatar

Asked on January 17, 2020 by

Aaroohi Nagar

Determine the value of m and N so that the pair of linear equations

(2m+1)x+3y=5

3x+(n−1)y=2

have infinite number of solutions.

MEDIUM

Share

Study later

ANSWER

(2m+1)x+3y−5=0

3x+(n−1)y−2

condition for a pair of linear equations to have infinite number of solutions

a

2

a

1

=

b

2

b

1

=

c

2

c

1

3

2m+1

=

n−1

3

=

−2

−5

3

2m+1

=

2

5

4m+2=15

4m=13

m=

4

13

n−1

3

=

2

5

5n−5=6

5n=11

n=

5

11

my friend

hope it will help u

Discussion

50.	Write the following complex number in the form of A+iB (-i) (-2i)
Answer» ANSWER: where are the COMPLEX NUMBERS??

50.

Write the following complex number in the form of A+iB (-i) (-2i)

Answer»

ANSWER:

where are the COMPLEX NUMBERS??

Discussion

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