Log[(sectheta +tan theta) (sectheta -tantheta)]=__a)1b)0c)sec^2theta -

1.	Log[(sectheta +tan theta) (sectheta -tantheta)]=__a)1b)0c)sec^2theta - tan^2thetad)not defined
Answer» Answer: Answer: zero Formulae USED: Sec²x-tan²x=1 Solution: It is given that, ⟹ LOG[(sectheta+tan theta)(sectheta-tan theta)] ⟹ log[(sec² theta-tan² theta)] By *using* *the* *identity*, ⟹ log**[(1)] ⟹ 0

Log[(sectheta +tan theta) (sectheta -tantheta)]=__a)1b)0c)sec^2theta - tan^2thetad)not defined

Answer»

Answer:

Answer:

zero

Formulae USED:

Sec²x-tan²x=1

Solution:

It is given that,

⟹ LOG[(sectheta+tan theta)(sectheta-tan theta)]

⟹ log[(sec² theta-tan² theta)]

By using the identity,

⟹ log[(1)]

⟹ 0

Discussion

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Log[(sectheta +tan theta) (sectheta -tantheta)]=__a)1b)0c)sec^2theta - tan^2thetad)not defined​