332354 + Interview Questions in Secondary School in Math

1.	Which of the following is the perfect cube ? 108,343 ,243,5324
Answer» Answer: 343 Step-by-step EXPLANATION: Because it the cube of 7, $343 = 7 \times 7 \times 7 = {7}^{3}$ Hope this will help you and PLEASE MARK me as brainliest......

1.

Which of the following is the perfect cube ? 108,343 ,243,5324

Answer»

Answer:

343

Step-by-step EXPLANATION:

Because it the cube of 7,

$343 = 7 \times 7 \times 7 = {7}^{3}$

Hope this will help you and PLEASE MARK me as brainliest......

Discussion

2.	The no. of tangents can be drawn to a circle atthe point on the circle is
Answer» ANSWER: one Hope it helps Plz MARK as BRAINLIEST and FLW me

2.

The no. of tangents can be drawn to a circle atthe point on the circle is

Answer»

ANSWER:

one

Hope it helps

Plz MARK as BRAINLIEST and FLW me

Discussion

3.	Perameter and area
Answer» ANSWER: of which NUMBER PLEASE TELL

3.

Perameter and area

Answer»

ANSWER:

of which NUMBER PLEASE TELL

Discussion

4.	If the sum and the product of two zeros of a quadratic polynomial is 2/3 and -5/4 respectively, determine the polynomial.
Answer» ANSWER: *The* *general* *EQUATION* *FORMING* is x^2-(A+B)x+Ab=0 *here* A=*alpha, B=beta. (A+B) =2/3, AB=-5/4 .: x^2-(2/3)x+(-5/4)=0 .:x^2 -2/3x -5/4=0 Step-by-step EXPLANATION:* *Therefore* *the* *polynomial* is x^2 -2/3x - 5/4=0

4.

If the sum and the product of two zeros of a quadratic polynomial is 2/3 and -5/4 respectively, determine the polynomial.

Answer»

ANSWER:

The general EQUATION FORMING is x^2-(A+B)x+Ab=0 here A=alpha, B=beta.

(A+B) =2/3, AB=-5/4

.: x^2-(2/3)x+(-5/4)=0

.:x^2 -2/3x -5/4=0

Step-by-step EXPLANATION:

Therefore the polynomial is x^2 -2/3x - 5/4=0

Discussion

5.	Perameter and area self practice 14f
Answer» Step-by-step EXPLANATION: OK sir thanks ........ ........

5.

Perameter and area self practice 14f

Answer»

Step-by-step EXPLANATION:

OK sir

thanks

........

Discussion

6.	find the coordinates of the point whose ordinate is 2 and abscissa is -7......................................................pls i will mark as brainliest
Answer» Step-by-step EXPLANATION: Co-ordinate is (-7,2) This is RIGHT ANSWER

6.

find the coordinates of the point whose ordinate is 2 and abscissa is -7......................................................pls i will mark as brainliest

Answer»

Step-by-step EXPLANATION:

Co-ordinate is (-7,2)

This is RIGHT ANSWER

Discussion

7.	X4 + x3 – 2x² + x - 3 find hcf by divison method
Answer» ANSWER: please mark me as BRAINLIEST answer

7.

X4 + x3 – 2x² + x - 3 find hcf by divison method

Answer»

ANSWER:

please

mark me as BRAINLIEST answer

Discussion

8.	If 0°≤ theta ≤ 90° ; costheta=_______ a)decreasing functionb)increasing functionc)constant functiond)identity function
Answer» ANSWER: OPTION C is CORRECT answer

8.

If 0°≤ theta ≤ 90° ; costheta=_______ a)decreasing functionb)increasing functionc)constant functiond)identity function

Answer»

ANSWER:

OPTION C is CORRECT answer

Discussion

9.	Prove this tanA/secA-1+tanA/secA+1=2cosecA plz make it if possible in photo form
Answer» Answer: Step-by-step explanation: Sorry can't be done by photo: HS = tanA/secA - 1 + tanA/secA + 1 = sinA/cosA / 1/cosA - 1 + sinA/cosA / 1/cosA + 1 [because tan A = sin A / cos A and sec A = 1 / cos A] = sinA/cosA / (1 - cosA) / cosA + sinA/cosA / (1 + cosA) / cos A = sin A / 1 - cos A + sin A / 1 + cos A, = [sin A (1 + cos A) + sin A (1 - cos A)] / (1 - cos A) (1 + cos A), = [sin A + sin A cos A + sin A - sin A cos A] / 1 - cos(sq) A, = 2 sin A / sin(sq) A [From IDENTITY: sin(sq) A + cos(sq) A = 1], = 2 / sin A, = 2 x 1 / sin A, =2 CO sec A. Hope it HELPS you.

9.

Prove this tanA/secA-1+tanA/secA+1=2cosecA plz make it if possible in photo form

Answer»

Answer:

Step-by-step explanation:

Sorry can't be done by photo:

HS = tanA/secA - 1 + tanA/secA + 1

= sinA/cosA / 1/cosA - 1 + sinA/cosA / 1/cosA + 1 [because tan A = sin A / cos A and sec A = 1 / cos A]

= sinA/cosA / (1 - cosA) / cosA + sinA/cosA / (1 + cosA) / cos A

= sin A / 1 - cos A + sin A / 1 + cos A,

= [sin A (1 + cos A) + sin A (1 - cos A)] / (1 - cos A) (1 + cos A),

= [sin A + sin A cos A + sin A - sin A cos A] / 1 - cos(sq) A,

= 2 sin A / sin(sq) A [From IDENTITY: sin(sq) A + cos(sq) A = 1],

= 2 / sin A,

= 2 x 1 / sin A,

=2 CO sec A.

Hope it HELPS you.

Discussion

10.	draw a dotted line to divide each picture given below into two similar mirror halves .put wrong below the picture that not show symmetry
Answer» ANSWER: Here is not any PICTURE. MENTIONED where is picture.

10.

draw a dotted line to divide each picture given below into two similar mirror halves .put wrong below the picture that not show symmetry

Answer»

ANSWER:

Here is not any PICTURE.

MENTIONED where is picture.

Discussion

11.	6. Three cubes each of sides 5 cm are joined end to end. Find the surface area of the resultingcuboid.
Answer» ANSWER: SUPPOSE the answer is 1.25

11.

6. Three cubes each of sides 5 cm are joined end to end. Find the surface area of the resultingcuboid.

Answer»

ANSWER:

SUPPOSE the answer

is 1.25

Discussion

12.	Prove that 2root5+3 is irrational
Answer» ANSWER: p,q are integers then (p²-7q²)/2Q is a rational NUMBER. Then √10 is also a rational number. But this contradicts the fact that √10 is an irrational number. √2+√5 is an irrational number. Step-by-step explanation: i HELPED you out so you can Subscribe My youtube channel.....It is FREE (Deepanshu Kumar Garg)

12.

Prove that 2root5+3 is irrational

Answer»

ANSWER:

p,q are integers then (p²-7q²)/2Q is a rational NUMBER. Then √10 is also a rational number. But this contradicts the fact that √10 is an irrational number. √2+√5 is an irrational number.

Step-by-step explanation:

i HELPED you out so you can Subscribe My youtube channel.....It is FREE

(Deepanshu Kumar Garg)

Discussion

13.	ACTIVITYConsider the data given in example 1 and calculate the arithmetic mean by deviationmethod by taking successive values ofx, i.e., 17.5,32.5,... as assumed means. Now discussthe following:1. Are the values of arithmetic mean in all the above cases equal?2. If we take the actual mean as the assumed mean, how much will f;dbe?3. Reason about taking any mid-value (class mark) as assumed mean?
Answer» Answer: MUJHE NAHI PATA google Se puch lo

13.

ACTIVITYConsider the data given in example 1 and calculate the arithmetic mean by deviationmethod by taking successive values ofx, i.e., 17.5,32.5,... as assumed means. Now discussthe following:1. Are the values of arithmetic mean in all the above cases equal?2. If we take the actual mean as the assumed mean, how much will f;dbe?3. Reason about taking any mid-value (class mark) as assumed mean?

Answer»

Answer:

MUJHE NAHI PATA google Se puch lo

Discussion

14.	Help me with this.
Answer» Answer: 7 meter and cm is your answer Step-by-step EXPLANATION: MARK me as BRILLIANT PLEASE please

14.

Help me with this.

Answer»

Answer:

7 meter and cm is your answer

Step-by-step EXPLANATION:

MARK me as BRILLIANT PLEASE please

Discussion

15.	Calculate the amount on ₹20,000 for 2 years when rates of interest for successive years are 6% and 8% respectively.
Answer» ANSWER: asdfgjklmmnvxzzs ...... Step-by-step EXPLANATION: ....../...................

15.

Calculate the amount on ₹20,000 for 2 years when rates of interest for successive years are 6% and 8% respectively.

Answer»

ANSWER:

asdfgjklmmnvxzzs ......

Step-by-step EXPLANATION:

....../...................

Discussion

16.	A shope keeper purchase a book at RS 40, a trader gains a profit of 25%. What is the cost price of rice per kg?
Answer» ANSWER: RS. 145 Step-by-step EXPLANATION:

16.

A shope keeper purchase a book at RS 40, a trader gains a profit of 25%. What is the cost price of rice per kg?

Answer»

ANSWER:

RS. 145

Step-by-step EXPLANATION:

Discussion

17.	Differentiate ((4x+3)/(2-x))^2 w.r.t x
Answer» ANSWER: $y = ( \frac{4x + 3}{2 - x} ) {}^{2}$ $\frac{dy}{dx} = 2 \times \frac{4x + 3}{2 - x} \times ( \frac{(2 - x)4 - (4x + 3)( - 1)}{(2 - x) {}^{2} } ) =$ $2 \times \frac{4x + 3}{2 - x} \times \frac{8 - 4x + 4x + 3}{(2 - x) {}^{2} } =$ $2 \times \frac{11(4x + 3)}{ {(2 - x)}^{3} } = 22 \times \frac{4x + 3}{ {(2 - x)}^{3} } \: ans.$

17.

Differentiate ((4x+3)/(2-x))^2 w.r.t x

Answer»

ANSWER:

$y = ( \frac{4x + 3}{2 - x} ) {}^{2}$

$\frac{dy}{dx} = 2 \times \frac{4x + 3}{2 - x} \times ( \frac{(2 - x)4 - (4x + 3)( - 1)}{(2 - x) {}^{2} } ) =$

$2 \times \frac{4x + 3}{2 - x} \times \frac{8 - 4x + 4x + 3}{(2 - x) {}^{2} } =$

$2 \times \frac{11(4x + 3)}{ {(2 - x)}^{3} } = 22 \times \frac{4x + 3}{ {(2 - x)}^{3} } \: ans.$

Discussion

18.	the radius and the height of a cylinder are in the ratio 2:3 if it's curved surface area is 300π cm² find its volume(take π=3.14)
Answer» GIVEN :- Ratio of radius and height = 2 : 3 CSA of cylinder = 300 π cm² Value of π = 3.14 To Find :- VOLUME of the cylinder Solution :- Let's :- Radius of cylinder = 2x Height of cylinder = 3x $\large \implies \boxed{ \sf CSA \: of \: cylinder = 2\pi rh} \\ \\ \implies \tt2 \times \pi \times 2x \times 3x = 300\pi \\ \\ \implies \tt12x^2 = 300 \\ \\ \implies \tt x^2 = \frac{300}{12} \\ \\ \implies \tt x = \sqrt{25} \\ \\ \implies \tt x =<klux>5</klux>$ Radius = 2x = 2 × 5 = 10 cm Height = 3x = 3 × 5 = 15 cm Now $\large \implies\boxed{\sf Volume \: of \: cylinder = {\pi r}^{2} h }\\ \\\implies \tt 3.14 \times {<klux>10</klux>}^{2} \times 15 \\ \\\implies \tt 3.14 \times 100 \times 15 \\ \\\implies \tt 314 \times 15 \\ \\\implies \tt 4710 \: {cm}^{3}$ ★ Volume of cylinder is 4710 cm³

18.

the radius and the height of a cylinder are in the ratio 2:3 if it's curved surface area is 300π cm² find its volume(take π=3.14)

Answer»

GIVEN :-

Ratio of radius and height = 2 : 3

CSA of cylinder = 300 π cm²

Value of π = 3.14

To Find :-

VOLUME of the cylinder

Solution :-

Let's :-

Radius of cylinder = 2x

Height of cylinder = 3x

$\large \implies \boxed{ \sf CSA \: of \: cylinder = 2\pi rh} \\ \\ \implies \tt2 \times \pi \times 2x \times 3x = 300\pi \\ \\ \implies \tt12x^2 = 300 \\ \\ \implies \tt x^2 = \frac{300}{12} \\ \\ \implies \tt x = \sqrt{25} \\ \\ \implies \tt x =<klux>5</klux>$

Radius = 2x = 2 × 5 = 10 cm

Height = 3x = 3 × 5 = 15 cm

Now

$\large \implies\boxed{\sf Volume \: of \: cylinder = {\pi r}^{2} h }\\ \\\implies \tt 3.14 \times {<klux>10</klux>}^{2} \times 15 \\ \\\implies \tt 3.14 \times 100 \times 15 \\ \\\implies \tt 314 \times 15 \\ \\\implies \tt 4710 \: {cm}^{3}$

★ Volume of cylinder is 4710 cm³

Discussion

19.	If a mixed fraction is converted into a fraction and its reciprocal is
Answer» ANSWER: then we will GET a PROPER FRACTION

19.

If a mixed fraction is converted into a fraction and its reciprocal is

Answer»

ANSWER:

then we will GET a PROPER FRACTION

Discussion

20.	Please.....can any one give me sinX graph....it's urgent!
Answer» here's your ANSWER FRIEND HOPE it HELPS U

20.

Please.....can any one give me sinX graph....it's urgent!

Answer»

here's your ANSWER FRIEND HOPE it HELPS U

Discussion

21.	Tick (✓) the correct answers.1. Which is longer?MileO Kilometre
Answer» ANSWER: A MILE is LONGER than a KILOMETER.

21.

Tick (✓) the correct answers.1. Which is longer?MileO Kilometre

Answer»

ANSWER:

A MILE is LONGER than a KILOMETER.

Discussion

22.	Please answer this question asap.
Answer» ANSWER: L.H.S= $\sqrt{\frac{1+sinx}{1-sinx }$ + $\sqrt[]{\frac{1-sinx}{1+sinx} }$ = $\frac{(\sqrt{1+sinx})^2 + (\sqrt{1-sinx})^2}{\sqrt{1-sin^2 x} }$ = $\frac{1+sinx+1-sinx}{cosx}$ = $\frac{2}{cosx}$ = $2 secx$ = R.H.S

22.

Please answer this question asap.

Answer»

ANSWER:

L.H.S= $\sqrt{\frac{1+sinx}{1-sinx }$ + $\sqrt[]{\frac{1-sinx}{1+sinx} }$

= $\frac{(\sqrt{1+sinx})^2 + (\sqrt{1-sinx})^2}{\sqrt{1-sin^2 x} }$

= $\frac{1+sinx+1-sinx}{cosx}$

= $\frac{2}{cosx}$ = $2 secx$ = R.H.S

Discussion

23.	Write different kinds of formulas for permutation of n objects
Answer» <P>ANSWER: The number of permutations of n objects taken r at a TIME is determined by the following FORMULA: P(n,r)=n! (n−r)! n! is read n factorial and means all NUMBERS from 1 to n multiplied e.g hope this will help you........❣️

23.

Write different kinds of formulas for permutation of n objects

Answer»

<P>ANSWER:

The number of permutations of n objects taken r at a TIME is determined by the following FORMULA: P(n,r)=n! (n−r)! n! is read n factorial and means all NUMBERS from 1 to n multiplied e.g

hope this will help you........❣️

Discussion

24.	If x is not equal to zero and X+1/X =2, find x4+1/x4
Answer» Answer: 2 Step-by-step EXPLANATION:

24.

If x is not equal to zero and X+1/X =2, find x4+1/x4

Answer»

Answer:

2

Step-by-step EXPLANATION:

Discussion

25.	6.x=1 is a root of quadraticequationX^2+4x-5=0TrueFalse
Answer» Yes , X = 1 is a root of QUADRATIC Equation x²+4x–5=0

Discussion

26.	if A(4,8) ,B(-2,6) are to vertices of a triangle and G(2,7) is the centroid of the triangle then find the vertex of triangle
Answer» ANSWER: third vertex=(4,0) Step-by-step explanation: 3G=A+B+C; where A,B,C are vertices of triangle

26.

if A(4,8) ,B(-2,6) are to vertices of a triangle and G(2,7) is the centroid of the triangle then find the vertex of triangle

Answer»

ANSWER:

third vertex=(4,0)

Step-by-step explanation:

3G=A+B+C;

where A,B,C are vertices of triangle

Discussion

27.	In an election contested by 2, the winner secures 60% of the valid votes and wins by a majorityof 684 votes. If 95% of the votes are valid, what was the number of votes which were invalid?
Answer» ANSWER: uftwffjk5ttascxub Step-by-step EXPLANATION: fysffurjsvdhuxgsdghui

27.

In an election contested by 2, the winner secures 60% of the valid votes and wins by a majorityof 684 votes. If 95% of the votes are valid, what was the number of votes which were invalid?

Answer»

ANSWER:

uftwffjk5ttascxub

Step-by-step EXPLANATION:

fysffurjsvdhuxgsdghui

Discussion

28.	Calculate the compound Intrest accrued on Rs 16000 in 3 years, when the rates of intrest for successive years are 10%,12% and 15% respectively
Answer» Step-by-step EXPLANATION: answer=22669 OK ok OKOK

28.

Calculate the compound Intrest accrued on Rs 16000 in 3 years, when the rates of intrest for successive years are 10%,12% and 15% respectively

Answer»

Step-by-step EXPLANATION:

answer=22669 OK ok OKOK

Discussion

29.	A train covers a distance of 31245.60 km in 31.02 hours.How much distance well it covers in one hour.
Answer» Answer: Step-by-step EXPLANATION: If the TRAIN covers a distance of 31245.60 KM in 31.02 hours so the distance covered by it in 1 hour will be 31245.60/31.02 =3124560/3102

29.

A train covers a distance of 31245.60 km in 31.02 hours.How much distance well it covers in one hour.

Answer»

Answer:

Step-by-step EXPLANATION:

If the TRAIN covers a distance of 31245.60 KM in 31.02 hours

so the distance covered by it in 1 hour will be

31245.60/31.02

=3124560/3102

Discussion

30.	2 hour 30 minute after 10:40pm?
Answer» ANSWER: don't know what U mean by that but plzz do FOLLOW me and MARK as brainliest

30.

2 hour 30 minute after 10:40pm?

Answer»

ANSWER:

don't know what U mean by that but plzz do FOLLOW me and MARK as brainliest

Discussion

31.	WHAT IS THE coefficient of x2 in the given polynomial 1,5,3
Answer» ANSWER: COMPLETE the QUESTION FIRST

31.

WHAT IS THE coefficient of x2 in the given polynomial 1,5,3

Answer»

ANSWER:

COMPLETE the QUESTION FIRST

Discussion

32.	Subtract the sum of 2,3upon5 and 1,2upon5 from 7,3upon5 ???
Answer» Answer: 30/5+7/5=23/5 37/5-23/5=14/5 Step-by-step EXPLANATION:If you FIND it helpful please mark me BRAINLIST

32.

Subtract the sum of 2,3upon5 and 1,2upon5 from 7,3upon5 ???

Answer»

Answer:

30/5+7/5=23/5

37/5-23/5=14/5

Step-by-step EXPLANATION:If you FIND it helpful please mark me BRAINLIST

Discussion

33.	1. Solve by formula method.2x2 - 3x + 1 = 0
Answer» Step-by-step EXPLANATION: मातृभाषा स्त्रोत स्त्रोत स्त्रोत स्त्रोत स्त्रोत और

33.

1. Solve by formula method.2x2 - 3x + 1 = 0

Answer»

Step-by-step EXPLANATION:

मातृभाषा स्त्रोत स्त्रोत स्त्रोत स्त्रोत स्त्रोत और

Discussion

34.	Find the remainder , when p(x) = x^31 + 31 is divided by x + 1.
Answer» $\huge\underline{\overline{\mid{\bold{\pink{ANSWER-}}\mid}}}$ <P> Let p(x) = x ^31 + 31. Divisor = x + 1 By remainder theorem, we have Remainder p(−1) = (−1)^ 31 + 31 = −1 + 31 = 30 Thus, the remainder when (x 31 + 31) is DIVIDED by (x + 1 )

34.

Find the remainder , when p(x) = x^31 + 31 is divided by x + 1.

Answer»

$\huge\underline{\overline{\mid{\bold{\pink{ANSWER-}}\mid}}}$

<P>

Let p(x) = x ^31 + 31.

Divisor = x + 1

By remainder theorem,

we have Remainder

p(−1) = (−1)^ 31 + 31 = −1 + 31 = 30

Thus, the remainder when (x 31 + 31) is DIVIDED by (x + 1 )

Discussion

35.	10. Draw a dotted line to divide each picture given below into two similarhalves. Put X below the picture that does not show symmetry :(4)(3)(1)(2)8Hw(8)(5)(7)(6)(9)(11)(12)(10)M
Answer» ANSWER: ........ Step-by-step EXPLANATION:

35.

10. Draw a dotted line to divide each picture given below into two similarhalves. Put X below the picture that does not show symmetry :(4)(3)(1)(2)8Hw(8)(5)(7)(6)(9)(11)(12)(10)M

Answer»

ANSWER:

........

Step-by-step EXPLANATION:

Discussion

36.	Check whether 9 can end with zero for any natural number
Answer» Answer: 9n cannot END with a zero. Step-by-step EXPLANATION: Because its FACTORS are (3*3).

36.

Check whether 9 can end with zero for any natural number

Answer»

Answer:

9n cannot END with a zero.

Step-by-step EXPLANATION:

Because its FACTORS are (3*3).

Discussion

37.	(a⁴- a³+ a² - a+ 1) divided by (a³ - 2)
Answer» ANSWER: I HOPE ITS HELPFUL. Step-by-step EXPLANATION:

37.

(a⁴- a³+ a² - a+ 1) divided by (a³ - 2)

Answer»

ANSWER:

I HOPE ITS HELPFUL.

Step-by-step EXPLANATION:

Discussion

38.	In the given figure, AB \|\| DC and AD \|\| BC, and AC is a diagonal. If∆BAC = 35°, ∆CAD = 40°, ∆ACB = xº and ∆ACD= yº find thevalues of x and y.40
Answer» ANSWER: buegfhfjxkz Step-by-step EXPLANATION: fff dufhfjflhdjf bgjcggjfhgjfhdhf

38.

In the given figure, AB || DC and AD || BC, and AC is a diagonal. If∆BAC = 35°, ∆CAD = 40°, ∆ACB = xº and ∆ACD= yº find thevalues of x and y.40

Answer»

ANSWER:

buegfhfjxkz

Step-by-step EXPLANATION:

fff

dufhfjflhdjf

bgjcggjfhgjfhdhf

Discussion

39.	Faster....andwe my question...I am in a hurry....plzzz
Answer» WHAT IS UR QUESTION? >:3

39.

Faster....andwe my question...I am in a hurry....plzzz

Answer»

WHAT IS UR QUESTION? >:3

Discussion

40.	Explain how option 4th is correct
Answer» I think OPTION (2) Trypsin is CORRECT , because out of these only trypsin is ENZYME, rest are hormones. edit : THANKS for BRAINLIEST

Discussion

41.	Please please please please please please ans me
Answer» Step-by-step explanation: Let the same factors be a x^2-cx+(81/16) =16x^2-16cx+81=0 Sum=(-b/a) a+a=[(-(-C)/16] 2a=(c/16) a=(c/32)---(EQUATION 1) Product=(c/a) a×a=(81/16) a^2=(81/16) a=(9/4) or 2.25--(equation 2) putting a=(9/4) in equation 1 (9/4)=(c/32) (9×32)/4=c (9×8)=c c=72

41.

Please please please please please please ans me

Answer»

Step-by-step explanation:

Let the same factors be a

x^2-cx+(81/16)

=16x^2-16cx+81=0

Sum=(-b/a)

a+a=[(-(-C)/16]

2a=(c/16)

a=(c/32)---(EQUATION 1)

Product=(c/a)

a×a=(81/16)

a^2=(81/16)

a=(9/4) or 2.25--(equation 2)

putting a=(9/4) in equation 1

(9/4)=(c/32)

(9×32)/4=c

(9×8)=c

c=72

Discussion

42.	Show that ax 3 x 4 xGxGx7+ in a compositenumberone
Answer» 55+gg just succeeds38 and you have RECEIVED this answear-

Discussion

43.	Find the longest possible length of the stick which can be used to measure exactly 48 cm , 56 cm and 72 cm.
Answer» ANSWER: Find the HCF of it.. Step-by-step explanation: i hope u will get the ANS right...please MARK me as abrainlist

43.

Find the longest possible length of the stick which can be used to measure exactly 48 cm , 56 cm and 72 cm.

Answer»

ANSWER:

Find the HCF of it..

Step-by-step explanation:

i hope u will get the ANS right...please MARK me as abrainlist

Discussion

44.	Is triangle cbd is congruent to bce ? Why or why not
Answer» Answer: there NOTHING to SAY YES or no Step-by-step explanation: figure is not ATTACHED PLEASE mark it as brainliest

44.

Is triangle cbd is congruent to bce ? Why or why not

Answer»

Answer:

there NOTHING to SAY YES or no

Step-by-step explanation:

figure is not ATTACHED

PLEASE mark it as brainliest

Discussion

45.	Calculate the Compound Interest on ₹4000 in 1 year at 10% p.a. compounded half-yearly.
Answer» ANSWER: Step-by-step EXPLANATION: CI- 840

45.

Calculate the Compound Interest on ₹4000 in 1 year at 10% p.a. compounded half-yearly.

Answer»

ANSWER:

Step-by-step EXPLANATION:

CI-

840

Discussion

46.	The roots of the quadratic equaltion x2-x-6=0
Answer» ANSWER: x = -2 & x = 3 Step-by-step explanation: The factors of -6 which sums to -1 are: ( -3 and 2) Now, (x+2)(x-3)=0 now, equate each FACTOR to 0 and solve for x x+2 = 0 [x=-2] x-3=0 [x=3] HOPE this answer will help u... best WISHES for ur future :)

46.

The roots of the quadratic equaltion x2-x-6=0

Answer»

ANSWER:

x = -2 & x = 3

Step-by-step explanation:

The factors of -6 which sums to -1 are:

( -3 and 2)

Now,

(x+2)(x-3)=0

now, equate each FACTOR to 0 and solve for x

x+2 = 0

[x=-2]

x-3=0

[x=3]

HOPE this answer will help u...

best WISHES for ur future :)

Discussion

47.	4500-50008.(a) Find the mean marks from the following daNo. of Students4MarksBelow 10Below 20Below 30Below 40Below 50Below 601018284070
Answer» Answer Here we have, cumulative frequency distribution less than type. First we convert it into an ordinary frequency distribution. We observe that the number of students getting marks less than 10 is 5 and 9 students have secured marks less than 20. Therefore, number of students getting marks between 10 and 20 ( inclusive 0 and exclusive 10) is 9−5=4. Similarly, the number of students getting marks between 20 and 30 is 17−9=8 and so on. Thus, we have the following distribution frequency distributionAnswer: Step-by-step explanation:Marks: 0−10 10−20 20−30 30−40 40−50 50−60 60−70 70−80 80−90 90−100 Number of students: 5 4 8 12 16 15 10 8 5 2 Let US Let us now compute arithmetic mean by taking 55 and the assumed mean. Computation of Mean Marks Mid-value Frequency ui10xi−55 fiui 0−10 5 5 −5 −25 10−20 10 4 −4 −16 20−30 25 8 −3 −24 30−40 35 12 −2 −24 40−50 45 16 −1 −16 50−60 55 15 0 0 60−70 65 10 1 10 70−80 75 8 2 16 80−90 85 5 3 15 90−100 95 2 4 8 Total N=∑fi=85 ∑fiui=−56 We have, N=N=∑fi=85,∑fiui=−56,h=10andA=55 ∴X=A+h(N1∑fiui) ⇒X=55+10×85−56=55−6.59=48.41Marks. Hence, mean marks scored by the students = 48.41.

47.

4500-50008.(a) Find the mean marks from the following daNo. of Students4MarksBelow 10Below 20Below 30Below 40Below 50Below 601018284070

Answer»

Answer

Here we have, cumulative frequency distribution less than type. First we convert it into an ordinary frequency distribution. We observe that the number of students getting marks less than 10 is 5 and 9 students have secured marks less than 20. Therefore, number of students getting marks between 10 and 20 ( inclusive 0 and exclusive 10) is 9−5=4. Similarly, the number of students getting marks between 20 and 30 is 17−9=8 and so on. Thus, we have the following distribution frequency distributionAnswer:

Step-by-step explanation:Marks: 0−10 10−20 20−30 30−40 40−50 50−60 60−70 70−80 80−90 90−100

Number of students: 5 4 8 12 16 15 10 8 5 2

Let US Let us now compute arithmetic mean by taking 55 and the assumed mean.

Computation of Mean

Marks Mid-value Frequency ui10xi−55 fiui

0−10 5 5 −5 −25

10−20 10 4 −4 −16

20−30 25 8 −3 −24

30−40 35 12 −2 −24

40−50 45 16 −1 −16

50−60 55 15 0 0

60−70 65 10 1 10

70−80 75 8 2 16

80−90 85 5 3 15

90−100 95 2 4 8

Total N=∑fi=85 ∑fiui=−56

We have,

N=N=∑fi=85,∑fiui=−56,h=10andA=55

∴X=A+h(N1∑fiui)

⇒X=55+10×85−56=55−6.59=48.41Marks.

Hence, mean marks scored by the students = 48.41.

Discussion

48.	3x=2p+qThen p=?Change the subject of the following equationThankyou
Answer» ANSWER: p=3x-q/2 Step-by-step EXPLANATION: GIVEN : 3x=2p+q 3x=2p+q 2p=3x-q p=3x-q/2

48.

3x=2p+qThen p=?Change the subject of the following equationThankyou

Answer»

ANSWER: p=3x-q/2

Step-by-step EXPLANATION:

GIVEN : 3x=2p+q

3x=2p+q

2p=3x-q

p=3x-q/2

Discussion

49.	Set of all real no. that lie between 1 and 2 is infinite or finite
Answer» ANSWER: that will be an INFINITE SET

49.

Set of all real no. that lie between 1 and 2 is infinite or finite

Answer»

ANSWER:

that will be an INFINITE SET

Discussion

50.	The mid value of class interval x-25 is 20 then x is
Answer» Answer: 15 Step-by-step EXPLANATION: because mid value MEANS UPPER limit plus LOWER limit divided by 2

50.

The mid value of class interval x-25 is 20 then x is

Answer»

Answer:

15

Step-by-step EXPLANATION:

because mid value MEANS UPPER limit plus LOWER limit divided by 2

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