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Prove this tanA/secA-1+tanA/secA+1=2cosecA plz make it if possible in photo form

Answer»

Answer:

Step-by-step explanation:

Sorry can't be done by photo:

HS = tanA/secA - 1 + tanA/secA + 1

= sinA/cosA / 1/cosA - 1 + sinA/cosA / 1/cosA + 1 [because tan A = sin A / cos A and sec A = 1 / cos A]

= sinA/cosA / (1 - cosA) / cosA + sinA/cosA / (1 + cosA) / cos A

= sin A / 1 - cos A + sin A / 1 + cos A,

= [sin A (1 + cos A) + sin A (1 - cos A)] / (1 - cos A) (1 + cos A),

= [sin A + sin A cos A + sin A - sin A cos A] / 1 - cos(sq) A,

= 2 sin A / sin(sq) A [From IDENTITY: sin(sq) A + cos(sq) A = 1],

= 2 / sin A,

= 2 x 1 / sin A,

=2 CO sec A.

Hope it HELPS you.


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