332354 + Interview Questions in Secondary School in Math

1.	Complete this pattern:1. 8-6 =8-5 =8-4=8-3 =8-2=8-1=8-0 =8-(-1)=8-(-2)=8-(-3)=8-(-4)=
Answer» ANSWER: INCREASING by 1 in each PATTERN

1.

Complete this pattern:1. 8-6 =8-5 =8-4=8-3 =8-2=8-1=8-0 =8-(-1)=8-(-2)=8-(-3)=8-(-4)=

Answer»

ANSWER:

INCREASING by 1 in each PATTERN

Discussion

2.	D The mean of 1/5 and 1/2 is 7/20 . Find the average of 1/5 and 7/20.
Answer» $( \frac{1}{5} + \frac{7}{20} ) \div 2 \\ = \frac{11}{20} \div 2 = 11 \div 10$ MARK me brainlinest if HELPFUL

2.

D The mean of 1/5 and 1/2 is 7/20 . Find the average of 1/5 and 7/20.

Answer»

$( \frac{1}{5} + \frac{7}{20} ) \div 2 \\ = \frac{11}{20} \div 2 = 11 \div 10$

MARK me brainlinest if HELPFUL

Discussion

3.	Solve both the parts and compare the answer . Are they the same 1)a) 4/13 +2/13 b)2/13+4/13
Answer» Answer: 4/13+2/13=6/13 2/13+4/13=6/13 YES they are same

3.

Solve both the parts and compare the answer . Are they the same 1)a) 4/13 +2/13 b)2/13+4/13

Answer»

Answer:

4/13+2/13=6/13

2/13+4/13=6/13 YES they are same

Discussion

4.	Can u telll me indo note me konsa correct hai
Answer» ANSWER: LEFT one is corret because the formula is x=-b+-underroot b2-4ac MARK AS BRAINLIEST IF IT HELP

4.

Can u telll me indo note me konsa correct hai

Answer»

ANSWER:

LEFT one is corret because the formula is x=-b+-underroot b2-4ac

MARK AS BRAINLIEST IF IT HELP

Discussion

5.	Find the value of trignometric functions of sin 765
Answer» There is no angle GREATER than 360 DEGREE than how it i s POSSIBLE to GET the value of sin 765.

Discussion

6.	What is the value of (-1)203?
Answer» *HEY* (-1)*203* = -*203* *because* - × + = -

6.

What is the value of (-1)203?

Answer»

HEY

(-1)203 = -203

because - × + = -

Discussion

7.	T^4=256 full sum pls
Answer» ANSWER: t^4-256 (t^2)^2-(16)^2 (t^2+16)(t^2-16)

7.

T^4=256 full sum pls

Answer»

ANSWER:

t^4-256

(t^2)^2-(16)^2

(t^2+16)(t^2-16)

Discussion

8.	1st one please answer
Answer» -15 is the ANSWER of this QUESTION

Discussion

9.	3.20 km-_________mm
Answer» Answer: 1 KM = 1000000 MM So, 3.20 km = 3.20 × 1000000 =3200000 mm

9.

3.20 km-_________mm

Answer»

Answer:

1 KM = 1000000 MM

So, 3.20 km = 3.20 × 1000000 =3200000 mm

Discussion

10.	17 Simplify the following by usingsuitable property 2/3×3/4+2/3×1/4
Answer» Answer: 2/3×3/4+2/3×1/4=6/12+2/12=8/12=2/3

10.

17 Simplify the following by usingsuitable property 2/3×3/4+2/3×1/4

Answer»

Answer:

2/3×3/4+2/3×1/4=6/12+2/12=8/12=2/3

Discussion

11.	If alpha and beta are zeroes of the polynomial 2x2+7x+5 , then find the value of 1/alpha+1/beta
Answer» Answer: 2x² + 7x +5 Step-by-step EXPLANATION: as we know 1/ALPHA+1/beta= (alpha+beta) / alphabeta (alpha+beta = SUM of roots = -b/a = -7/2 alphabeta =PRODUCT = c/a = 5/2 hence answer = -7/2

11.

If alpha and beta are zeroes of the polynomial 2x2+7x+5 , then find the value of 1/alpha+1/beta

Answer»

Answer:

2x² + 7x +5

Step-by-step EXPLANATION:

as we know 1/ALPHA+1/beta= (alpha+beta) / alpha*beta

(alpha+beta = SUM of roots = -b/a = -7/2

alpha*beta =PRODUCT = c/a = 5/2

hence answer = -7/2

Discussion

12.	Simplify 1/√3+√2-√5
Answer» $\dfrac{1}{ \sqrt{3} \: + \: \sqrt{2} \: - \: \sqrt{5} }$ _________ [GIVEN EQUATION] • We have to simply it. ______________________________ => $\dfrac{1}{ \sqrt{3} \: + \: \sqrt{2} \: - \: \sqrt{5} }$ • Rationalize it. => $\dfrac{1}{ (\sqrt{3} \: + \: \sqrt{2}) \: - \: \sqrt{5} }$ × $\dfrac{ (\sqrt{3} \: + \: \sqrt{2} ) \: + \sqrt{5} }{ (\sqrt{3} \: + \: \sqrt{2}) \: + \: \sqrt{5} }$ => $\dfrac{( \sqrt{3} \: + \: \sqrt{2}) \: + \: \sqrt{5} }{ {( \sqrt{3} \: + \: \sqrt{2} ) }^{2} \: + \: {( \sqrt{5} }^{2} )}$ (a + b)² = a² + b² + 2AB => $\dfrac{( \sqrt{3} \: + \: \sqrt{2}) \: + \: \sqrt{5} }{ 3 \: + \: 2\: + \: 2(3)(2) \: + \: {5}}$ => $\dfrac{( \sqrt{3} \: + \: \sqrt{2}) \: + \: \sqrt{5} }{ 3 \: + \: 2\: + \: 2(\sqrt{2)}\: (\sqrt{3)}\: - \: {5}}$ => $\dfrac{( \sqrt{3} \: + \: \sqrt{2}) \: + \: \sqrt{5} }{ 6 \:+\:2\sqrt{6}\: - \: {5}}$ => $\dfrac{( \sqrt{3} \: + \: \sqrt{2}) \: + \: \sqrt{5} }{2\sqrt{6}}$ => $\dfrac{( \sqrt{3} \: + \: \sqrt{2}) \: + \: \sqrt{5} }{2\sqrt{6}}$ × $\dfrac{\sqrt{6}}{\sqrt{6}}$ => √6 × $\dfrac{( \sqrt{3} \: + \: \sqrt{2}) \: +\: \sqrt{5} }{12}$ => $\dfrac{ \sqrt{18} \: + \: \sqrt{12} \: +\: \sqrt{30} }{12}$ _______________________________

12.

Simplify 1/√3+√2-√5

Answer»

$\dfrac{1}{ \sqrt{3} \: + \: \sqrt{2} \: - \: \sqrt{5} }$

_________ [GIVEN EQUATION]

• We have to simply it.

______________________________

=> $\dfrac{1}{ \sqrt{3} \: + \: \sqrt{2} \: - \: \sqrt{5} }$

• Rationalize it.

=> $\dfrac{1}{ (\sqrt{3} \: + \: \sqrt{2}) \: - \: \sqrt{5} }$ × $\dfrac{ (\sqrt{3} \: + \: \sqrt{2} ) \: + \sqrt{5} }{ (\sqrt{3} \: + \: \sqrt{2}) \: + \: \sqrt{5} }$

=> $\dfrac{( \sqrt{3} \: + \: \sqrt{2}) \: + \: \sqrt{5} }{ {( \sqrt{3} \: + \: \sqrt{2} ) }^{2} \: + \: {( \sqrt{5} }^{2} )}$

(a + b)² = a² + b² + 2AB

=> $\dfrac{( \sqrt{3} \: + \: \sqrt{2}) \: + \: \sqrt{5} }{ 3 \: + \: 2\: + \: 2(3)(2) \: + \: {5}}$

=> $\dfrac{( \sqrt{3} \: + \: \sqrt{2}) \: + \: \sqrt{5} }{ 3 \: + \: 2\: + \: 2(\sqrt{2)}\: (\sqrt{3)}\: - \: {5}}$

=> $\dfrac{( \sqrt{3} \: + \: \sqrt{2}) \: + \: \sqrt{5} }{ 6 \:+\:2\sqrt{6}\: - \: {5}}$

=> $\dfrac{( \sqrt{3} \: + \: \sqrt{2}) \: + \: \sqrt{5} }{2\sqrt{6}}$

=> $\dfrac{( \sqrt{3} \: + \: \sqrt{2}) \: + \: \sqrt{5} }{2\sqrt{6}}$ × $\dfrac{\sqrt{6}}{\sqrt{6}}$

=> √6 × $\dfrac{( \sqrt{3} \: + \: \sqrt{2}) \: +\: \sqrt{5} }{12}$

=> $\dfrac{ \sqrt{18} \: + \: \sqrt{12} \: +\: \sqrt{30} }{12}$

_______________________________

Discussion

13.	Question:- 2x+3/2=5-2(x-4)/30
Answer» Step-by-step EXPLANATION: (2X2+3)/2=(-3x+12)/30 (4x+3)/2=(-3x+12)/30 (4x+3)/230= (-3x+12) 60x+45=-3x+12 60x-3x=12-45 57x=33 X=33/57 X=11/19.

13.

Question:- 2x+3/2=5-2(x-4)/30

Answer»

Step-by-step EXPLANATION:

(2X*2+3)/2=(-3x+12)/30

(4x+3)/2=(-3x+12)/30

(4x+3)/2*30= (-3x+12)

60x+45=-3x+12

60x-3x=12-45

57x=33

X=33/57

X=11/19.

Discussion

14.	OLA!What r POLYNOMIALS??
Answer» Answer: an expression more than 2 algebric terms and have a variable Pn= PX3 +Px2............... Pxn Step-by-step explanation: hope you got it so plse say thanks and follow me alia joshi and Mark as BRAINLIST my friend and later then all the question I will definitely TRY to answer

14.

OLA!What r POLYNOMIALS??

Answer»

Answer:

an expression more than 2 algebric terms and have a variable

Pn= PX3 +Px2............... Pxn

Step-by-step explanation:

hope you got it so plse say thanks and follow me alia joshi and Mark as BRAINLIST my friend and later then all the question I will definitely TRY to answer

Discussion

15.	- What is the value of (-1)203.?
Answer» (-1) * 203 = -203 Hope it HELPS u....pls MARK it as the BRAINLIEST....

15.

- What is the value of (-1)203.?

Answer»

(-1) * 203

= -203

Hope it HELPS u....pls MARK it as the BRAINLIEST....

Discussion

16.	Write six rational number between -2 and -4 all step
Answer» Answer: Take the denominator 100 and multiply with 100 the NUMERATOR as well So it BECOMES -200/100 and -400/100 Choose any SIX RATIONAL numbers and write Hope it helps Step-by-step explanation:

16.

Write six rational number between -2 and -4 all step

Answer»

Answer:

Take the denominator 100 and multiply with 100 the NUMERATOR as well

So it BECOMES -200/100 and -400/100

Choose any SIX RATIONAL numbers and write

Hope it helps

Step-by-step explanation:

Discussion

17.	Plzz solve this fast factorise x^2+3x+9
Answer» Answer: $\large \text{$<klux>X</klux>=\dfrac{-3+3i\sqrt{3} }{2} \ or \ x=\dfrac{-3-3i\sqrt{3}}{2}$}$ Step-by-step explanation: Given : $\large \text{$p(x)= x^2+3x+9$}$ We have to factorise the p ( x ). By Sridharacharya method we have $\large \text{$x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a} $}$ Comparing from p ( x ) we have b = 3 a = 1 C = 9 Now PUTTING values in formula $\large \text{$x=\dfrac{-3\pm\sqrt{3^2-4\times1\times9} }{2\times1} $}\\\\\\\large \text{$x=\dfrac{-3\pm\sqrt{9-36} }{2} $}\\\\\\\large \text{$x=\dfrac{-3\pm\sqrt{-27} }{2} $}\\\\\\\large \text{$x=\dfrac{-3\pm3\sqrt{-3} }{2} $}\\\\\\\large \text{$x=\dfrac{-3+3\sqrt{-3} }{2} \ or \ x=\dfrac{-3-3\sqrt{-3}}{2}$}\\\\\\$ We KNOW that $i=\sqrt{-1}$ Take out VALUE of i we get $\large \text{$x=\dfrac{-3+3i\sqrt{3} }{2} \ or \ x=\dfrac{-3-3i\sqrt{3}}{2}$}$ Thus we get answer.

17.

Plzz solve this fast factorise x^2+3x+9

Answer»

Answer:

$\large \text{$<klux>X</klux>=\dfrac{-3+3i\sqrt{3} }{2} \ or \ x=\dfrac{-3-3i\sqrt{3}}{2}$}$

Step-by-step explanation:

Given :

$\large \text{$p(x)= x^2+3x+9$}$

We have to factorise the p ( x ).

By Sridharacharya method we have

$\large \text{$x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a} $}$

Comparing from p ( x ) we have

b = 3

a = 1

C = 9

Now PUTTING values in formula

$\large \text{$x=\dfrac{-3\pm\sqrt{3^2-4\times1\times9} }{2\times1} $}\\\\\\\large \text{$x=\dfrac{-3\pm\sqrt{9-36} }{2} $}\\\\\\\large \text{$x=\dfrac{-3\pm\sqrt{-27} }{2} $}\\\\\\\large \text{$x=\dfrac{-3\pm3\sqrt{-3} }{2} $}\\\\\\\large \text{$x=\dfrac{-3+3\sqrt{-3} }{2} \ or \ x=\dfrac{-3-3\sqrt{-3}}{2}$}\\\\\\$

We KNOW that $i=\sqrt{-1}$

Take out VALUE of i we get

$\large \text{$x=\dfrac{-3+3i\sqrt{3} }{2} \ or \ x=\dfrac{-3-3i\sqrt{3}}{2}$}$

Thus we get answer.

Discussion

18.	√2(√6-√8) + √3(√27-√6)
Answer» ANSWER: Step-by-step EXPLANATION:

18.

√2(√6-√8) + √3(√27-√6)

Answer»

ANSWER:

Step-by-step EXPLANATION:

Discussion

19.	if _5 is a root of quadratic equation 2x square +px_15=0 and the quadratic equation p(x square +x)k=0,has equal roots ,find the value of k
Answer» ANSWER: Step-by-step EXPLANATION:

19.

if _5 is a root of quadratic equation 2x square +px_15=0 and the quadratic equation p(x square +x)k=0,has equal roots ,find the value of k

Answer»

ANSWER:

Step-by-step EXPLANATION:

Discussion

20.	MathsSimplificationSimplify.(2x – 3y) + (5x - y) – (- 4x + 3y + 3)
Answer» ANSWER: $\left(2x-3y\right)+\left(5x-y\right)-\left(-4x+3y+3\right)=11x-7y-3$ Step-by-step EXPLANATION: $\left(2x-3y\right)+\left(5x-y\right)-\left(-4x+3y+3\right)$ $\gray{\mathrm{Remove\:parentheses}:\quad \left(a\right)=a}$ $=2x-3y+5x-y-\left(-4x+3y+3\right)$ $\black{-\left(-4x+3y+3\right)}$ $\gray{\mathrm{Distribute\:parentheses}}$ $=-\left(-4x\right)-\left(3y\right)-\left(3\right)$ $\gray{\mathrm{Apply\:minus-plus\:rules}}$ $\gray{-\left(-a\right)=a,\:\:\:-\left(a\right)=-a}$ $=4x-3y-3$ $=2x-3y+5x-y+4x-3y-3$ $\black{\mathrm{Simplify}\:2x-3y+5x-y+4x-3y-3}$ $2x-3y+5x-y+4x-3y-3$ $\gray{\mathrm{Group\:like\:terms}}$ $=2x+5x+4x-3y-y-3y-3$ $\gray{\mathrm{Add\:similar\:elements:}\:2x+5x+4x=11x}$ $=11x-3y-y-3y-3$ $\gray{\mathrm{Add\:similar\:elements:}\:-3y-y-3y=-7y}$ $=11x-7y-3$

20.

MathsSimplificationSimplify.(2x – 3y) + (5x - y) – (- 4x + 3y + 3)

Answer»

ANSWER:

$\left(2x-3y\right)+\left(5x-y\right)-\left(-4x+3y+3\right)=11x-7y-3$

Step-by-step EXPLANATION:

$\left(2x-3y\right)+\left(5x-y\right)-\left(-4x+3y+3\right)$

$\gray{\mathrm{Remove\:parentheses}:\quad \left(a\right)=a}$

$=2x-3y+5x-y-\left(-4x+3y+3\right)$

$\black{-\left(-4x+3y+3\right)}$

$\gray{\mathrm{Distribute\:parentheses}}$

$=-\left(-4x\right)-\left(3y\right)-\left(3\right)$

$\gray{\mathrm{Apply\:minus-plus\:rules}}$

$\gray{-\left(-a\right)=a,\:\:\:-\left(a\right)=-a}$

$=4x-3y-3$

$=2x-3y+5x-y+4x-3y-3$

$\black{\mathrm{Simplify}\:2x-3y+5x-y+4x-3y-3}$

$2x-3y+5x-y+4x-3y-3$

$\gray{\mathrm{Group\:like\:terms}}$

$=2x+5x+4x-3y-y-3y-3$

$\gray{\mathrm{Add\:similar\:elements:}\:2x+5x+4x=11x}$

$=11x-3y-y-3y-3$

$\gray{\mathrm{Add\:similar\:elements:}\:-3y-y-3y=-7y}$

$=11x-7y-3$

Discussion

21.	Find the missing numbers in prime factors tree
Answer» 1st box = 104 2nd box = 52 3RD Box = 26 MULTIPLY the factors of 3rd box => 13 × 2 => 26 Multiply 26 by 2 to GET 2nd box => 26 × 2 => 52 Multiply 52 by 2 => 52 × 2 => 104

21.

Find the missing numbers in prime factors tree

Answer»

1st box = 104

2nd box = 52

3RD Box = 26

MULTIPLY the factors of 3rd box

=> 13 × 2

=> 26

Multiply 26 by 2 to GET 2nd box

=> 26 × 2

=> 52

Multiply 52 by 2

=> 52 × 2

=> 104

Discussion

22.	If a = 9/8 b , then 3b/4a = ?
Answer» Answer: 1/b Step-by-step EXPLANATION:

22.

If a = 9/8 b , then 3b/4a = ?

Answer»

Answer:

1/b

Step-by-step EXPLANATION:

Discussion

23.	Simplify -11by 30 - 8 by 15 + 7 by 6 + -2 by 5
Answer» Answer: 0.13 Step-by-step EXPLANATION: $= > - \frac{11}{30} - \frac{8}{15} + \frac{7}{6} + ( - \frac{2}{5} ) \\ \\ = > - \frac{11}{30} - \frac{16}{30} + \frac{35}{30} - \frac{12}{30} \\ \\ = > \frac{ - 11 - 16 + 35 - 12}{30} \\ \\ = > \frac{35 - 39}{30} \\ \\ = > - \frac{4}{30} \\ \\ = > - \frac{2}{15} \\ \\ = > - 0.13$

23.

Simplify -11by 30 - 8 by 15 + 7 by 6 + -2 by 5

Answer»

Answer:

0.13

Step-by-step EXPLANATION:

$= > - \frac{11}{30} - \frac{8}{15} + \frac{7}{6} + ( - \frac{2}{5} ) \\ \\ = > - \frac{11}{30} - \frac{16}{30} + \frac{35}{30} - \frac{12}{30} \\ \\ = > \frac{ - 11 - 16 + 35 - 12}{30} \\ \\ = > \frac{35 - 39}{30} \\ \\ = > - \frac{4}{30} \\ \\ = > - \frac{2}{15} \\ \\ = > - 0.13$

Discussion

24.	6. Find a) 1/8 of a Rupee b) 11/25 of a litre c)4/5 of an hour d) 2/3 of an year
Answer» Answer: a) 12.5 paisa b) 440 ml c) 48 min d) 8 months Step-by-step EXPLANATION:

24.

6. Find a) 1/8 of a Rupee b) 11/25 of a litre c)4/5 of an hour d) 2/3 of an year

Answer»

Answer:

a) 12.5 paisa

b) 440 ml

c) 48 min

d) 8 months

Step-by-step EXPLANATION:

Discussion

25.	Hello ..... plzzz tell me whether it's correct or not
Answer» ANSWER: YESS it is TRULY CORRECT.......,

25.

Hello ..... plzzz tell me whether it's correct or not

Answer»

ANSWER:

YESS it is TRULY CORRECT.......,

Discussion

26.	How can you apply knowledge of. light phenomenon in our daily life
Answer» Answer: 1. Food: Photosynthesis is a concept in biology wherein food is synthesized by use of light. Light is the sole source of food generation for all living organisms on the earth. Except for a few chemotrophic bacteria? Almost all living beings depend on light for their food and energy. Plants and other autotrophs synthesize their own food materials by use of light. The light which falls on the LEAVES and other greenish surfaces on plants are trapped. This trapped energy is converted to RESERVE energy in the form of food by a process known as photosynthesis. Here the light energy is used to synthesize carbohydrates. The autotrophs like plants use carbon-dioxide and water {CO2 +H2O= C6H12O6} to form carbohydrates in the presence of sunlight. From these plants, animals get the required food materials and thereby needed energy for living. These carbohydrates inside the body, break down and convert back into carbon dioxide and water releasing the energy from within after digestion. So plants depend on sunlight for their food and animals depend on plants. Thus all the living beings are dependent on light for food. This phenomenon is present both on the earth surface and also the marine environments. Energy for bio-molecules synthesis: After food (carbohydrates) is consumed, it is broken down into energy. This energy is produced in the form of ATP (adenosine triphosphate). This ATP breaks down to ADP and AMP to release energy in cells and tissues. This ATP is to build up the body proteins and maintenance of physiology. The cell and nucleus transcription mechanism uses this energy to form messenger RNA (m-RNA). This m-RNA in the presence ATP again translates to produce desired hormones, enzymes, proteins and fats required for the body. Thus the light energy conserved in the food is used up to build and maintain the body. 2. For Vitamin D synthesis: Vitamin-D is a type of vitamin which is needed to be supplied from the external source. This is because it can be synthesized from ergosterol and cholesterol by irradiation with sunlight. When the light fall on the skin, the ergosterol below the skin converts to vitamin-D. So if someone stays away from sunlight for long, he tends to develop the vitamin-D deficiency. Also to get a regular dose of vitamin D, it is important to expose to sunlight EVERYDAY. The best time would be in the mornings and evenings (before dawn). 3. Vision: All animals, birds are able to see the objects around them due to presence of eyes. But without light, these eyes might be of no use. Because of light, the eyes can receive the image of the objects and SEND the information to the brain. From this visual information we comprehend the objects. Hence we can notice that in darkness we could see nothing. So light makes us able to see objects around. 4. Colors: This whole world looks beautiful due to colors. But in darkness we see no colors. This is because all the colors in this world are possible only due to light. The light has many spectra. Each spectra has a color and these are broadly referred as VIBGYOR. In full form it is Violet, Indigo Blue Green Yellow Orange Red All these color have different wavelengths and frequency. And when light falls on an object, it absorbs some spectra and reflects others. The reflected light falls on to our eyeball and passes the impression to brain making it look colorful. So it is the ability of the object to absorb some spectra of light and reflect the remaining makes it look colorful. We would not be able to see the color if the light is absent or our eyes are not functional. 5. Maintenance of temperature: Light is a form of energy. And sunlight has huge energy by which the temperature on the earth is maintained. Due to this, the life exists on the earth. If you think why? Just imaged those areas of the earth without proper light in the whole year. Those areas are icy and even have heavy snowfall. If the sunlight is absent, the temperature of the earth can drop drastically such that the whole water on the earth gets frozen. If this happens, the animals especially homeotherms die instantly due to low temperatures. Even the poikilothermic animals may find it difficult to survive. So light is essential to maintain temperature on the earth and thereby life.

26.

How can you apply knowledge of. light phenomenon in our daily life

Answer»

Answer:

1. Food: Photosynthesis is a concept in biology wherein food is synthesized by use of light. Light is the sole source of food generation for all living organisms on the earth. Except for a few chemotrophic bacteria? Almost all living beings depend on light for their food and energy.

Plants and other autotrophs synthesize their own food materials by use of light. The light which falls on the LEAVES and other greenish surfaces on plants are trapped. This trapped energy is converted to RESERVE energy in the form of food by a process known as photosynthesis. Here the light energy is used to synthesize carbohydrates. The autotrophs like plants use carbon-dioxide and water {CO2 +H2O= C6H12O6} to form carbohydrates in the presence of sunlight.

From these plants, animals get the required food materials and thereby needed energy for living.

These carbohydrates inside the body, break down and convert back into carbon dioxide and water releasing the energy from within after digestion.

So plants depend on sunlight for their food and animals depend on plants. Thus all the living beings are dependent on light for food.

This phenomenon is present both on the earth surface and also the marine environments.

Energy for bio-molecules synthesis: After food (carbohydrates) is consumed, it is broken down into energy. This energy is produced in the form of ATP (adenosine triphosphate). This ATP breaks down to ADP and AMP to release energy in cells and tissues.

This ATP is to build up the body proteins and maintenance of physiology. The cell and nucleus transcription mechanism uses this energy to form messenger RNA (m-RNA).

This m-RNA in the presence ATP again translates to produce desired hormones, enzymes, proteins and fats required for the body. Thus the light energy conserved in the food is used up to build and maintain the body.

2. For Vitamin D synthesis: Vitamin-D is a type of vitamin which is needed to be supplied from the external source. This is because it can be synthesized from ergosterol and cholesterol by irradiation with sunlight.

When the light fall on the skin, the ergosterol below the skin converts to vitamin-D. So if someone stays away from sunlight for long, he tends to develop the vitamin-D deficiency. Also to get a regular dose of vitamin D, it is important to expose to sunlight EVERYDAY. The best time would be in the mornings and evenings (before dawn).

3. Vision: All animals, birds are able to see the objects around them due to presence of eyes. But without light, these eyes might be of no use. Because of light, the eyes can receive the image of the objects and SEND the information to the brain. From this visual information we comprehend the objects. Hence we can notice that in darkness we could see nothing. So light makes us able to see objects around.

4. Colors: This whole world looks beautiful due to colors. But in darkness we see no colors. This is because all the colors in this world are possible only due to light. The light has many spectra. Each spectra has a color and these are broadly referred as VIBGYOR. In full form it is

Violet,

Indigo

Blue

Green

Yellow

Orange

Red

All these color have different wavelengths and frequency. And when light falls on an object, it absorbs some spectra and reflects others. The reflected light falls on to our eyeball and passes the impression to brain making it look colorful. So it is the ability of the object to absorb some spectra of light and reflect the remaining makes it look colorful. We would not be able to see the color if the light is absent or our eyes are not functional.

5. Maintenance of temperature: Light is a form of energy. And sunlight has huge energy by which the temperature on the earth is maintained. Due to this, the life exists on the earth.

If you think why? Just imaged those areas of the earth without proper light in the whole year. Those areas are icy and even have heavy snowfall. If the sunlight is absent, the temperature of the earth can drop drastically such that the whole water on the earth gets frozen. If this happens, the animals especially homeotherms die instantly due to low temperatures. Even the poikilothermic animals may find it difficult to survive. So light is essential to maintain temperature on the earth and thereby life.

Discussion

27.	Linear equation2x+1÷2=5÷8+x
Answer» are U SURE that the QUESTION is CORRECT?

Discussion

28.	Find 10 rational numbers between 2 and -1
Answer» Answer: 1/2 ,1/3,1/4,1/5,1/6,1/7,1,1/11,1/22,1/33. Step-by-step EXPLANATION:

28.

Find 10 rational numbers between 2 and -1

Answer»

Answer:

1/2 ,1/3,1/4,1/5,1/6,1/7,1,1/11,1/22,1/33.

Step-by-step EXPLANATION:

Discussion

29.	Q9. Expand using brackets and solve 17×109
Answer» Answer: ⇒1 7 × 109 =(20-3)× (100 +9) We will use FOLLOWING Identity (x+a)(x+b)=x²+(a+b)x+ab =20×(100 +9) -3×(100+9) =20×100 +20×9 -3×100-3×9 =2000+180-300-27 =2180 -327 = 1853

29.

Q9. Expand using brackets and solve 17×109

Answer»

Answer:

⇒1 7 × 109

=(20-3)× (100 +9)

We will use FOLLOWING Identity

(x+a)(x+b)=x²+(a+b)x+ab

=20×(100 +9) -3×(100+9)

=20×100 +20×9 -3×100-3×9

=2000+180-300-27

=2180 -327

= 1853

Discussion

30.	Simplify (3√3-2√5)^2Solve as fast as possible plz
Answer» Answer: 27+20-6√15 Step-by-step EXPLANATION:

30.

Simplify (3√3-2√5)^2Solve as fast as possible plz

Answer»

Answer:

27+20-6√15

Step-by-step EXPLANATION:

Discussion

31.	Prove that root 6 + root 7 is an irrational number
Answer» 6 + √7 is irrational NUMBER __________ [TO PROVE] Let us ASSUME that, 6 + √7 is a rational number => 6 + √7 = $\dfrac{a}{b}$ Here, a and b are co-prime NUMBERS. => √7 = $\dfrac{a}{b}$ - 6 => √7 = $\dfrac{a\:-\:6b}{b}$ Here.. $\dfrac{a\:-\:6b}{b}$ is rational number. So, √7 is also a rational number. But we know that √7 is irrational number. So, our ASSUMPTION is wrong. 6 + √7 is irrational number. ___________ [HENCE PROVED]

31.

Prove that root 6 + root 7 is an irrational number

Answer»

6 + √7 is irrational NUMBER

__________ [TO PROVE]

Let us ASSUME that, 6 + √7 is a rational number

=> 6 + √7 = $\dfrac{a}{b}$

Here, a and b are co-prime NUMBERS.

=> √7 = $\dfrac{a}{b}$ - 6

=> √7 = $\dfrac{a\:-\:6b}{b}$

Here..

$\dfrac{a\:-\:6b}{b}$ is rational number.

So, √7 is also a rational number.

But we know that √7 is irrational number.

So, our ASSUMPTION is wrong.

6 + √7 is irrational number.

___________ [HENCE PROVED]

Discussion

32.	Collect height in m and weight in kg of 4-5 member of family and find BMI
Answer» the ANSWER is GIVEN in PHOTO

32.

Collect height in m and weight in kg of 4-5 member of family and find BMI

Answer»

the ANSWER is GIVEN in PHOTO

Discussion

33.	Write the greatest and the smallest three digit number that can be made by using the digits a. 1 ,7,8
Answer» Answer: these are the two NUMBER GREATES and SMALLEST three DIGIT number which you given 1)871 2)178

33.

Write the greatest and the smallest three digit number that can be made by using the digits a. 1 ,7,8

Answer»

Answer:

these are the two NUMBER GREATES and SMALLEST three DIGIT number which you given

1)871

2)178

Discussion

34.	Represent -1, 2 upon 3 and 5 upon 9 on same number line
Answer» ANSWER: answer is in the image. Step-by-step explanation: just DARKEN the POINTS you NEED to show.

34.

Represent -1, 2 upon 3 and 5 upon 9 on same number line

Answer»

ANSWER:

answer is in the image.

Step-by-step explanation:

just DARKEN the POINTS you NEED to show.

Discussion

35.	True/False1. If a point C lies between two points A and Bsuch that AC=BC, then AC =1/2AB.2. If a transversal intersects two parallellines, then corresponding angles are notnecessarily equal.3. Only one line can pass through a single point.4. Two lines are said to be parallel, when the perpendicular distance between them is always constant 5.For every line l and for every point P not lying on l, there exists infinite line passing through p and parallel to l
Answer» ANSWER: true false false true false

35.

True/False1. If a point C lies between two points A and Bsuch that AC=BC, then AC =1/2AB.2. If a transversal intersects two parallellines, then corresponding angles are notnecessarily equal.3. Only one line can pass through a single point.4. Two lines are said to be parallel, when the perpendicular distance between them is always constant 5.For every line l and for every point P not lying on l, there exists infinite line passing through p and parallel to l

Answer»

ANSWER:

true

false

true

false

Discussion

36.	153381472 in Indian system
Answer» Answer: Step-by-step explanation: Fifteen CRORE thirty three lakh eighty ONE thousand four HUNDRED seventy two Hope U LIKE it

36.

153381472 in Indian system

Answer»

Answer:

Step-by-step explanation:

Fifteen CRORE thirty three lakh eighty ONE thousand four HUNDRED seventy two

Hope U LIKE it

Discussion

37.	Determine the integer whose product with (-1)is-54
Answer» Answer: 54 Step-by-step explanation: If you multiply any POSITIVE integer with -1 it results in negative integer with the same MOD.

37.

Determine the integer whose product with (-1)is-54

Answer»

Answer:

54

Step-by-step explanation:

If you multiply any POSITIVE integer with -1 it results in negative integer with the same MOD.

Discussion

38.	Diagonal of a rhombus are 4 cm and 6 cm find its area and perimeter
Answer» length of FIRST DIAGONAL = 4cm length of second diagonal = 6cm Area:- =(1/2 x 4 x6) cm =12cm^2

38.

Diagonal of a rhombus are 4 cm and 6 cm find its area and perimeter

Answer»

length of FIRST DIAGONAL = 4cm

length of second diagonal = 6cm

Area:-

=(1/2 x 4 x6) cm

=12cm^2

Discussion

39.	The greatest number of 5 digits which is divisible by 15 20 45 and 70 is
Answer» Answer: 99540 is that NUMBER..

39.

The greatest number of 5 digits which is divisible by 15 20 45 and 70 is

Answer»

Answer:

99540 is that NUMBER..

Discussion

40.	The length breadth and height of a room are in the ratio 3:2:1
Answer» Step-by-step EXPLANATION: what we NEED to FIND is not MENTIONED

40.

The length breadth and height of a room are in the ratio 3:2:1

Answer»

Step-by-step EXPLANATION:

what we NEED to FIND is not MENTIONED

Discussion

41.	Hey Friends!! solve this quest!______________________________________________Q) If f:R->R and g:R->R are defined by f(x)=2x+3 and g(x)=x²+7, then the values of x such that g(f(x))=8 are:Options are:i) 1,2ii) -1,2iii) -1,-2iv) 1,-2___________________________________________Please answer it accurately and BEWARE OF SPAMMING!!
Answer» $\red{\bold{ANSWER}}$ $\rm{-1\:\:,-2}$ $\mathbb{EXPLANATION}$ $\rm{F:R\rightarrow\:R}$ $\rm{F\left(x\right)=2x+3}$ $\boxed{\mathbb{AND}}$ $\rm{G:R\rightarrow\:R}$ $\rm{G\left(x\right)=x^2+7}$ $\underline{\mathbb{GIVEN}}$ $\rm{G\left(F\left(x\right)\right)=8}$ $\rm{G\left(2x+3\right)=8}$ $\rm{\left(\left(2x+3\right)^2+7\right)=8}$ $\rm{4x^2+9+12x+7-8=0}$ $\rm{4x^2+12x+8=0}$ $\rm{x^2+3x+2=0}$ $\rm{x^2+2x+x+2=0}$ $\rm{x\left(x+2\right)+1\left(x+2\right)=0}$ $\rm{\left(x+2\right)\times\left(x+1\right)=0}$ $\rm{x=-2\:\:OR\:\:x=-1}$ $\therefore$ $\rm{x=-2,-1}$ $\boxed{\rm{\mathbb{HENCE,\:OPTION\:THIRD\:IS\:CORRECT}}}$

41.

Hey Friends!! solve this quest!____Q) If f:R->R and g:R->R are defined by f(x)=2x+3 and g(x)=x²+7, then the values of x such that g(f(x))=8 are:Options are:i) 1,2ii) -1,2iii) -1,-2iv) 1,-2_Please answer it accurately and BEWARE OF SPAMMING!!

Answer»

$\red{\bold{ANSWER}}$

$\rm{-1\:\:,-2}$

$\mathbb{EXPLANATION}$

$\rm{F:R\rightarrow\:R}$

$\rm{F\left(x\right)=2x+3}$

$\boxed{\mathbb{AND}}$

$\rm{G:R\rightarrow\:R}$

$\rm{G\left(x\right)=x^2+7}$

$\underline{\mathbb{GIVEN}}$

$\rm{G\left(F\left(x\right)\right)=8}$

$\rm{G\left(2x+3\right)=8}$

$\rm{\left(\left(2x+3\right)^2+7\right)=8}$

$\rm{4x^2+9+12x+7-8=0}$

$\rm{4x^2+12x+8=0}$

$\rm{x^2+3x+2=0}$

$\rm{x^2+2x+x+2=0}$

$\rm{x\left(x+2\right)+1\left(x+2\right)=0}$

$\rm{\left(x+2\right)\times\left(x+1\right)=0}$

$\rm{x=-2\:\:OR\:\:x=-1}$

$\therefore$ $\rm{x=-2,-1}$

$\boxed{\rm{\mathbb{HENCE,\:OPTION\:THIRD\:IS\:CORRECT}}}$

Discussion

42.	Find a rational number between 2 and 3
Answer» Answer: First TAKE the DENOMINATOR as 10. Then it becomes 2/10 and 3/10 Hence U can CHOOSE any rational number between this and write Step-by-step explanation:

42.

Find a rational number between 2 and 3

Answer»

Answer:

First TAKE the DENOMINATOR as 10.

Then it becomes 2/10 and 3/10

Hence U can CHOOSE any rational number between this and write

Step-by-step explanation:

Discussion

43.	At what rate percent per annum of simple interest will you certain sum of money become 3times in 15 years?
Answer» Answer: 1. Method of growing two or more crops in a definite pattern simultaneously on the same field.(13words) 4. Crops grown in rainy season.(6words) 10. Plants that are grown prior to crop and plants and mulched into the soil. (two WORDS)(11words) 11. The preferred agronomic characteristic in cereals.(9words) 12. PROCESS of crossing two plants of different species belonging to thesame genus(13words) 13. We can also improve crop varietyby introducing a ___ to get the preferred CHARACTERISTICS(4words) 14. A biotic factor that can reduce thecrop produce(8words) 2. Term used in relation with the duration of sunlight.(11words) 3. Destroys soil fertility if used constantly(11words) 5. Process of crossing two genetically dissimilar plants.(13words) 6. Method to kill pests that destroy grains.10 words 7. System of farming which uses little or no chemicals. (two words)(14words) 8. A biotic factor that can reduce thecrop produce(9words) 9. Manure prepared by decomposition of farm waste using EARTHWORMS.(12words) please tell fast I would be THANKFUL to you

43.

At what rate percent per annum of simple interest will you certain sum of money become 3times in 15 years?

Answer»

Answer:

1. Method of growing two or

more crops in a definite pattern

simultaneously on the same field.(13words)

4. Crops grown in rainy season.(6words)

10. Plants that are grown prior to crop and plants and mulched into the soil.

(two WORDS)(11words)

11. The preferred agronomic

characteristic in cereals.(9words)

12. PROCESS of crossing two plants of different species belonging to thesame genus(13words)

13. We can also improve crop varietyby introducing a ___ to get the preferred CHARACTERISTICS(4words)

14. A biotic factor that can reduce thecrop produce(8words)

2. Term used in relation with the

duration of sunlight.(11words)

3. Destroys soil fertility if used

constantly(11words)

5. Process of crossing two genetically dissimilar plants.(13words)

6. Method to kill pests that destroy

grains.10 words

7. System of farming which uses little or no chemicals. (two words)(14words)

8. A biotic factor that can reduce thecrop produce(9words)

9. Manure prepared by decomposition of farm waste using EARTHWORMS.(12words)

please tell fast I would be THANKFUL to you

Discussion

44.	WRITE ANY TWO RATIONS NUMBERS EQUIVALENT TO 4/9.
Answer» Answer: 4/9 × 2/2 = 8/18 4/9 × 3/3 = 12/27 4/9 × 4/4 = 16/36 4/9 × 5/5 = 20/45

44.

WRITE ANY TWO RATIONS NUMBERS EQUIVALENT TO 4/9.

Answer»

Answer:

4/9 × 2/2 = 8/18

4/9 × 3/3 = 12/27

4/9 × 4/4 = 16/36

4/9 × 5/5 = 20/45

Discussion

45.	1Mega Joule = ? . ............
Answer» Answer: 10^6 JOULE Step-by-step EXPLANATION: MEGA is 10^6 1Mega Joule is 10^6 joule

45.

1Mega Joule = ? . ............

Answer»

Answer:

10^6 JOULE

Step-by-step EXPLANATION:

MEGA is 10^6

1Mega Joule is 10^6 joule

Discussion

46.	Solve this question 100009÷12×34556+120998-⅜
Answer» Answer: 288113581 Step-by-step EXPLANATION: PLEASE MARK me as BRAINLIEAST......

46.

Solve this question 100009÷12×34556+120998-⅜

Answer»

Answer:

288113581

Step-by-step EXPLANATION:

PLEASE MARK me as BRAINLIEAST......

Discussion

47.	Write two point lying on the X axis, which are at equal distances from the origin
Answer» Answer: (0,-2) & (0,2) Step-by-step explanation: As it is not MENTIONED in the question that the points are POSITIVE or negative but should be on X-Axis. ALSO, the x-axis is divided into two parts i.e, Positive and negative. So, for equal DISTANCES points could be on Positive or Negative side. HENCE, the points can be (0,-2) & (0,2). Many other points are possible. HOPE IT HELPS.

47.

Write two point lying on the X axis, which are at equal distances from the origin

Answer»

Answer:

(0,-2) & (0,2)

Step-by-step explanation:

As it is not MENTIONED in the question that the points are POSITIVE or negative but should be on X-Axis. ALSO, the x-axis is divided into two parts i.e, Positive and negative. So, for equal DISTANCES points could be on Positive or Negative side. HENCE, the points can be (0,-2) & (0,2).

Many other points are possible.

HOPE IT HELPS.

Discussion

48.	Convert (11.0133)° in
Answer» ANSWER:any NUMBER to the POWER 0 is 1. Step-by-step EXPLANATION:

48.

Convert (11.0133)° in

Answer»

ANSWER:any NUMBER to the POWER 0 is 1.

Step-by-step EXPLANATION:

Discussion

49.	Show that any positive odd integer is of the form 5q + 1, 5q + 3 where Q is some integer
Answer» Step-by-step explanation: let 'a' be any positive odd integer & a = 5 Then by Euclid's Division ALGORITHM, a = bq + r , ( 0 less than or equal to r less than B) a = 5q + r ( 0 less than or equal to r less than 5) So, r = 0,1,2,3,4 a = 5q + 0 a = 5q Here, 5q is EXACTLY DIVISIBLE by 2 , hence , it is an even positive number. a = 5q + 1 Here, 5q + 1 is not exactly divisible by 2 , hence , it is an odd positive number. a = 5q + 2 Here, 5q + 2 is exactly divisible by 2 , hence , it is an even positive number. a = 5q + 3 Here, 5q + 3 is not exactly divisible by 2 , hence , it is an odd positive number. The procedure continues. Hence , any positive integer will be of form 5q + 1, 5q + 3... where q is some integer. Hope it helps!

49.

Show that any positive odd integer is of the form 5q + 1, 5q + 3 where Q is some integer

Answer»

Step-by-step explanation:

let 'a' be any positive odd integer & a = 5

Then by Euclid's Division ALGORITHM,

a = bq + r ,

( 0 less than or equal to r less than B)

a = 5q + r

( 0 less than or equal to r less than 5)

So, r = 0,1,2,3,4

a = 5q + 0

a = 5q

Here, 5q is EXACTLY DIVISIBLE by 2 , hence , it is an even positive number.

a = 5q + 1

Here, 5q + 1 is not exactly divisible by 2 , hence , it is an odd positive number.

a = 5q + 2

Here, 5q + 2 is exactly divisible by 2 , hence , it is an even positive number.

a = 5q + 3

Here, 5q + 3 is not exactly divisible by 2 , hence , it is an odd positive number.

The procedure continues. Hence , any positive integer will be of form 5q + 1, 5q + 3... where q is some integer.

Hope it helps!

Discussion

50.	HOLLA❤what are polynomials ?FOLLOW ME ❤
Answer» Answer: an expression of more than two ALGEBRAIC TERMS, ESPECIALLY the sum of several terms that contain DIFFERENT POWERS of the same variables. hope it may helps you follow me please

50.

HOLLA❤what are polynomials ?FOLLOW ME ❤

Answer»

Answer:

an expression of more than two ALGEBRAIC TERMS, ESPECIALLY the sum of several terms that contain DIFFERENT POWERS of the same variables.

hope it may helps you

follow me please

Discussion

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