This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The formula for cost of living index number is ---- |
|
Answer» Answer: An index number is a FIGURE reflecting price or quantity compared with a base value. The base value always has an index number of 100. The index number is then expressed as 100 times the ratio to the base value.⇒ Cost of LIVING index = ∑w∑I. w=10010441. 5=104. Step-by-step explanation: |
|
| 2. |
Class 7 Give Chapter 13 Solutions |
|
Answer» The short notation 104 stands for the product 10×10×10×10. Here ‘10’ is called the base and ‘4’ the exponent. The number 104 is read as 10 raised to the power of 4 or simply as the fourth power of 10. 104 is called the exponential form of 10,000. The other portion of the chapter gives insight about Laws of exponents. This particular section is divided into several sub-sections: Multiplying Powers with the Same Base Dividing Powers with the Same Base Taking Power of a Power Multiplying Powers with the Same Exponents Dividing Powers with the Same Exponents Numbers with exponent zero Once the student has come across various laws of exponents miscellaneous examples using the laws of exponents can be studied. This is followed by Decimal Number System and expressing large numbers in the standard form. Any number can be expressed as a decimal number between 1.0 and 10.0 including 1.0 MULTIPLIED by a power of 10. Such a form of a number is called its standard form. The chapter includes 3 unsolved exercises and various solved examples. The chapter comprises a summary in which all the important concepts of the chapter- Exponents and Powers are mentioned. Page No 252:Question 1: Find the value of: (i) 26 (ii) 93 (iii) 112 (iv)54 ANSWER: (i) 26 = 2 × 2 × 2 × 2 × 2 × 2 = 64 (ii) 93 = 9 × 9 × 9 = 729 (iii) 112 = 11 × 11 = 121 (iv)54 = 5 × 5 × 5 × 5 = 625 Page No 252:Question 2: Express the following in exponential form: (i) 6 × 6 × 6 × 6 (ii) t × t (iii) b × b × b × b (iv) 5 × 5 × 7 ×7 × 7 (v) 2 × 2 × a × a (vi) a × a × a × c × c × c × c × d ANSWER: (i) 6 × 6 × 6 × 6 = 64 (ii) t × t= t2 (iii) b × b × b × b = b4 (iv) 5 × 5 × 7 × 7 × 7 = 52 × 73 (v) 2 × 2 × a × a = 22 × a2 (vi) a × a × a × c × c × c × c × d = a3 c4 d Page No 253:Question 3: Express the following numbers using exponential notation: (i) 512 (ii) 343 (iii) 729 (iv) 3125 ANSWER: (i) 512 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 29 (ii) 343 = 7 × 7 × 7 = 73 (iii) 729 = 3 × 3 × 3 × 3 × 3 × 3 = 36 (iv) 3125 = 5 × 5 × 5 × 5 × 5 = 55 Page No 253:Question 4: Identify the greater number, wherever possible, in each of the following? (i) 43 or 34 (ii) 53 or 35 (iii) 28 or 82 (iv) 1002 or 2100 (v) 210 or 102 ANSWER: (i) 43 = 4 × 4 × 4 = 64 34 = 3 × 3 × 3 × 3 = 81 Therefore, 34 > 43 (ii) 53 = 5 × 5 × 5 =125 35 = 3 × 3 × 3 × 3 × 3 = 243 Therefore, 35 > 53 (iii) 28 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 256 82 = 8 × 8 = 64 Therefore, 28 > 82 (iv)1002 or 2100 210 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 1024 2100 = 1024 × 1024 × 1024 × 1024 × 1024 × 1024 × 1024 × 1024 ×1024 × 1024 1002 = 100 × 100 = 10000 Therefore, 2100 > 1002 (v) 210 and 102 210 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 1024 102 = 10 × 10 = 100 Therefore, 210 > 102 Page No 253:Question 5: Express each of the following as product of powers of their prime factors: (i) 648 (ii) 405 (iii) 540 (iv) 3,600 ANSWER: (i) 648 = 2 × 2 × 2 × 3 × 3 × 3 × 3 = 23. 34 (ii) 405 = 3 × 3 × 3 × 3 × 5 = 34 . 5 (iii) 540 = 2 × 2 × 3 × 3 × 3 × 5 = 22. 33. 5 (iv) 3600 = 2 × 2 × 2 × 2 × 3 × 3 × 5 × 5 = 24. 32. 52 Page No 253:Question 6: Simplify: (i) 2 × 103 (ii) 72 × 22 (iii) 23 × 5 (iv) 3 × 44 (v) 0 × 102 (vi) 52 × 33 (vii) 24 × 32 (viii) 32 × 104 ANSWER: (i) 2 × 103 = 2 × 10 × 10 × 10 = 2 × 1000 = 2000 (ii) 72 × 22 = 7 × 7 × 2 × 2 = 49 × 4 = 196 (iii) 23 × 5 = 2 × 2 × 2 × 5 = 8 × 5 = 40 (iv) 3 × 44 = 3 × 4 × 4 × 4 × 4 = 3 × 256 = 768 (v) 0 × 102 = 0 × 10 × 10 = 0 (vi) 52 × 33 = 5 × 5 × 3 × 3 × 3 = 25 × 27 = 675 (vii) 24 × 32 = 2 × 2 × 2 × 2 × 3 × 3 = 16 × 9 = 144 (viii) 32 × 104 = 3 × 3 × 10 × 10 × 10 × 10 = 9 × 10000 = 90000 Page No 253:Question 7: Simplify: (i) (− 4)3 (ii) (− 3) × (− 2)3 (iii) (− 3)2 × (− 5)2 (iv)(− 2)3 × (−10)3 ANSWER: (i) (−4)3 = (−4) × (−4) × (−4) = −64 (ii) (−3) × (−2)3 = (−3) × (−2) × (−2) × (−2) = 24 (iii) (−3)2 × (−5)2 = (−3) × (−3) × (−5) × (−5) = 9 × 25 = 225 (iv) (−2)3 × (−10)3 = (−2) × (−2) × (−2) × (−10) × (−10) × (−10) = (−8) × (−1000) = 8000 Page No 253:Question 8: Compare the following numbers: (i) 2.7 × 1012; 1.5 × 108 (ii) 4 × 1014; 3 × 1017 ANSWER: (i) 2.7 × 1012; 1.5 × 108 2.7 × 1012 > 1.5 × 108 (ii) 4 × 1014; 3 × 1017 3 × 1017 > 4 × 1014 Page No 260:Question 1: Using laws of exponents, simplify and write the answer in exponential form: (i) 32 × 34 × 38 (ii) 615 ÷ 610 (iii) a3 × a2 (iv) 7X× 72 (v) (vi) 25 × 55 (vii) a4 × b4 (viii) (34)3 (ix) (x) 8t ÷ 82 ANSWER: (i) 32 × 34 × 38 = (3)2 + 4 + 8 (am × an = am+n) = 314 (ii) 615 ÷ 610 = (6)15 − 10 (am ÷ an = am−n) = 65 (iii) a3 × a2 = a(3 + 2) (am × an = am+n) = a5 (iv) 7x + 72 = 7x + 2 (am × an = am+n) (v) (52)3 ÷ 53 = 52 × 3 ÷ 53 (am)n = amn = 56 ÷ 53 = 5(6 − 3) (am ÷ an = am−n) = 53 (vi) 25 × 55 = (2 × 5)5 [am × bm = (a × b)m] = 105 (vii) a4 × b4 = (ab)4 [am × bm = (a × b)m] (viii) (34)3 = 34 × 3 = 312 (am)n = amn (ix) (220 ÷ 215) × 23 = (220 − 15) × 23 (am ÷ an = am−n) = 25 × 23 = (25 + 3) (am × an = am+n) = 28 (x) 8t ÷ 82 = 8(t − 2) (am ÷ an = am−n) |
|
| 3. |
If -4 is a root of the equation x² + pc - 4 = 0 and the quadratic equation x² + pc + q = 0 has equal roots, then find the values of p and q. |
|
Answer» Answer: 1/2 Step-by-step EXPLANATION: |
|
| 4. |
Whats is the reciprocal of 24300? |
|
Answer» 24300 |
|
| 5. |
5. 70% of the students in a school are boys and the number of girls is 504. Find the number ofboys in the school.An ore contains 12% copper. How many kilograms of the ore are required to get 69 kg |
|
Answer» Answer: 1176 Step-by-step explanation: Then, as per the QUESTION 70% of BOYS = 70 NUMBER of girls = 30 Now, total number of students when the number of girls is 30 = 100 Then, total number of students when the number of girls is 504 = (100/30) × 504 = 1680 Total number of boys = 1680 – 504 = 1176 |
|
| 6. |
Find the square root of 6+4√2 |
|
Answer» |
|
| 7. |
Write the test and the correspondence of vertices by which Triangles in a pair congruent |
|
Answer» Answer: Step-by-step EXPLANATION: pa brainleis po salamat po |
|
| 8. |
Find x if (√3 )^x-3 (4√3 )^x+1 |
|
Answer» Answer: |
|
| 9. |
If p=-2 ,find the value of of -3p^2+4p+7 |
|
Answer» IF P=-2 THEN -3(-2)²+4(-2)+7 -3(4)+(-8)+7 -12-8+7 -13 HOPE U LIKE IT |
|
| 10. |
For a=2 find the value of 5a+3a-2 |
|
Answer» Answer: we will start by replacing the value of a (5×2) + (3×2) -2 10 + 6 - 2 now we will FOLLOW the bodmas
(10 +6 ) -2 16 -2 =14 HOPE this might help you |
|
| 12. |
Please solve this pleaseChapter PROBABILITYif you don't know the answer then don't answer |
|
Answer» Step-by-step explanation: 35+25+40=100/2=50 means 50 FAMILY is |
|
| 13. |
Find the value of K ,if given equation has no solution:-(1)3x-4y+7=0 kx+3y-5=0 (2)2x-ky+3=0 3x+2y-1=0 |
| Answer» | |
| 14. |
+ 5 को संख्यामा रेखा ने लिखिर |
|
Answer» + panch Step-by-step EXPLANATION: |
|
| 15. |
Aryan bro Divya nahi diya |
|
Answer» PAGALO PADAHI KRO ssssssssssssssssssssssss |
|
| 16. |
. The sum of two integers is -226. If one of them is 36, Find out the otherinteger. |
|
Answer» X+36= -226 X= -226-36(PLUS CHANGES 2 MINUS WHILE CHANGING SIDES) X= -262 HAPPY 2 HELP :) MARK AS BRAINLIEST Step-by-step explanation: |
|
| 17. |
The areas of two similiar triangle are81 Sq cm and 36 sq.cm if one side of the firsttriangle is 3cm Long What is the length ofcorresponding side of the second triangle . |
| Answer» | |
| 19. |
I. What is the class size of the given data?a.20b.10c.30d.15ii.What is the classmark of the forthclass?a.70b.130c.20d.15iii.The number of oranges whose weight is more than 180g.a.1b.3c.2d.4iv.The number of oranges, whose weight is less than 100g.a.10b.3c.5d.13 |
| Answer» | |
| 20. |
17. At a Ramuan Mela, a stalkeeper in one of the food stallsaua ar financal vessel of base radius 15cm filled up to a height of 32 cm with orange juice. The juisted in small find causes of radius 3cmup to a heght of cm, and sold for 3 eachif u answer this rugby i Will mark u as thé brainliest |
|
Answer» Answer: i have made a NEW INTRO so PLZ check out the SHOWER and get a chance to get a polygon |
|
| 21. |
Simplify using suitable identities (x + y + z)2 – (x – y +z )2m pls don't cheat 5 m |
| Answer» | |
| 22. |
8. Find the n-th derivative for:(3 Points)y = e cosx sin^2 2x |
|
Answer» Answer: |
|
| 23. |
Given a = 4, b = -2. Find: ab + ba. |
|
Answer» Answer: 4×-2 + -2×4 -8+ -8 -16 this is your answer |
|
| 24. |
Explain the bisexual method |
|
Answer» Answer: The TERM “bisexual” is used to describe a person who experiences emotional, romantic and/or sexual attractions to, or engages in romantic or sexual RELATIONSHIPS with, more than one sex or gender. |
|
| 25. |
8a + 3b - 7a + 2b + 11a - b solve in steps |
|
Answer» 8+3+7+2+11- =9 Step-by-step EXPLANATION: the answer is=9 |
|
| 26. |
Add 2 mn, -4 mn, 8 mn, -6 mn |
|
Answer» Answer: 2MN+4MN+8MN+-6MN=SINCE ALL ARE LIKE TERMS WE CAN ADD THEM =8MN HAPPY 2 HELP :) MARK ME AS BRAINLIEST Step-by-step EXPLANATION: |
|
| 27. |
HCF and LCM two numbers are 12 and 396 respectively. If one of thenumbers is 36, then the other number is: |
|
Answer» 132 is the answer Step-by-step EXPLANATION: |
|
| 28. |
What are the roots of the quadratic equation x² = 16?Please answer this question. |
|
Answer» Answer: 4 Step-by-step EXPLANATION: PLEASE MARK me as BRAINLIEST |
|
| 30. |
Graphical representation of air pollution rate in kerala and himachal pradesh |
|
Answer» Answer: 55% is graphical REPRESENTATION of Air POLLUTION rate in Kerala and HIMACHAL PRADESH |
|
| 31. |
Express in power natation. -27÷125 |
|
Answer» Step-by-step EXPLANATION: |
|
| 32. |
16. Find the value of(-4) = (2/3) |
|
Answer» -6 mark me as BRAINLIEST PLSS |
|
| 33. |
Insert a rational number between 1/4 and -3/4 |
|
Answer» -1/4 is the Answer Step-by-step EXPLANATION: |
|
| 34. |
WRITTEN TEST NO.3A DIRECTIONS: ANALYZE EAOR YOUR SOLUTION.16% OF 10 = |
|
Answer» Step-by-step EXPLANATION:
|
|
| 35. |
If 9.5% of a number is 76 , find the number |
|
Answer» LET the number be x . SEE the image The number is 800 |
|
| 36. |
A hostel had rations for 150 students for 60 days. After 12 days, 30 students leave the hostel. How long theremaining ration last? |
|
Answer» Answer: for 150 students the RATION lasted for =60 days after 12 days the ratio would last for= 60-12 48 days now, for 150 students the ration LASTS for= 48days for ONE student the ration will last for= 48×150 if 30 more JOIN the ration would last for= 48×150/180 =40 days Step-by-step explanation: |
|
| 37. |
Find the inverse of the following matrix using Gauss-Jordan elimination1 2 32 3 43 4 5 |
|
Answer» MARK me as brillianst plz I don’t KNOW what the ANSWER of this QUESTION |
|
| 38. |
350 for 3 upon 1/2 years at 8 % p.a |
|
Answer» <P> years =7/2 years SI = P .R. T/ 100 350 × 8 ×7/100×2 R.S. 98 and amount =p+S.I RS. 350 +Rs.98 = Rs. 448 |
|
| 39. |
How many 3 upon 17 are there in 21 |
|
Answer» Answer: 3x7=21 BRUH Step-by-step explanation: 3x7=21 , bruh |
|
| 40. |
2.सहा या गलतफा पपागका(i) क्या पूर्ण संख्याओं के योग के लिए संवृतता गुणधर्म लागू होता है?(ii) क्या पूर्ण संख्याओं के व्यवकलन के लिए संवृतता गुणधर्म लागू होता है?(n) क्या पूर्ण संख्याओं के गुणन के लिए संवृतता गुणधर्म लागू होता है?(iv) क्या पूर्ण संख्याओं के भाजन के लिए संवृतता गुणधर्म लागू होता है?((() |
|
Answer» I don't know if you have any QUESTIONS ask me to Step-by-step explanation: .... |
|
| 41. |
(x+7y) (7x -y)Find the product |
|
Answer»
your ANSWER in this ATTACHMENT PLEASE SEE it
hope.u LIKE |
|
| 42. |
How much cm in 1 metre |
|
Answer» Answer: it is 100 cm = 1 METER please MARK it the BRAINLIEST |
|
| 43. |
(x-1/x)^+7(x-1/x)=51/4 |
|
Answer» Answer: PLEASE WRITE clearly . L don't understand Step-by-step explanation: please write in a CLEAR way . . |
|
| 44. |
नाव लिहा फुफुसांदवारे श्वसन करणारे मत्स्य |
| Answer» | |
| 45. |
Ba,b,c are in continued proportionIf a=3 c=12 ,b=? |
|
Answer» Why is distilled water USED in the BATTERIES and not the TAP water? |
|
| 46. |
Find the amount on Rs 24,000 at 7.5 per for four years |
|
Answer» Answer: Principal (P) = Rs. 24,000 Rate (R) = 7.5% P.A. Time (T) = 4 Years S.I. = (P × T × R)/100 = Rs. (24,000 × 4 × 7.5)/100 = Rs. 240 × 4 × 7.5 Amount needed to clear the debt at the end of 4th year. = Rs. 24000 + Rs. 7200 = Rs. 31200 Step-by-step explanation: |
|
| 47. |
Explain the ductile faiure of machine |
|
Answer» Answer: A ductile failure is a TYPE of failure SEEN in malleable materials characterized by extensive PLASTIC deformation or necking. This usually occurs PRIOR to the actual failure of the MATERIAL. The term ductile rupture refers to the failure of highly ductile materials. |
|
| 48. |
two adjacent sides of a parallelogram are 12 cm and 8 cm if the length of the altitude corresponding to the side 12 and 6 cm fine the length of the altitude corresponding to the sides 8 cm |
|
Answer» Area of parallelogram which altitude corresponding to the SIDE of 12cm =area of parallelogram which altitude corresponding to 8cm altitude x BASE = altitude x base 6cm x12cm = altitude x 8cm altitude =9CM Step-by-step EXPLANATION: |
|
| 49. |
Find hcf of number 235 and 1050 using euclids division algorithm |
|
Answer» Answer: By USING EDL a=bq+r where a is > b so a =867 and b=255 867=255×3+102 here r≠0 so a=255 and b=102 255=102×2+51 here r≠0 so a=102 and b=51 102=51×2+0 here r=0 so, Hcf of (867,255) is =51 Step-by-step EXPLANATION: |
|