Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The formula for cost of living index number is ----​

Answer»

Answer:

An index number is a FIGURE reflecting price or quantity compared with a base value. The base value always has an index number of 100. The index number is then expressed as 100 times the ratio to the base value.⇒ Cost of LIVING index = ∑w∑I. w=10010441. 5=104.

Step-by-step explanation:

HOPE it helps U and mark this answer as brainliest answer

2.

Class 7 Give Chapter 13 Solutions ​

Answer»

The short notation 104 stands for the product 10×10×10×10. Here ‘10’ is called the base and ‘4’ the exponent. The number 104 is read as 10 raised to the power of 4 or simply as the fourth power of 10. 104 is called the exponential form of 10,000.

The other portion of the chapter gives insight about Laws of exponents. This particular section is divided into several sub-sections:

Multiplying Powers with the Same Base

Dividing Powers with the Same Base

Taking Power of a Power

Multiplying Powers with the Same Exponents

Dividing Powers with the Same Exponents

Numbers with exponent zero

Once the student has come across various laws of exponents miscellaneous examples using the laws of exponents can be studied.

This is followed by Decimal Number System and expressing large numbers in the standard form.

Any number can be expressed as a decimal number between 1.0 and 10.0 including 1.0 MULTIPLIED by a power of 10. Such a form of a number is called its standard form.

The chapter includes 3 unsolved exercises and various solved examples.

The chapter comprises a summary in which all the important concepts of the chapter- Exponents and Powers are mentioned.

Page No 252:

Question 1:

Find the value of:

(i) 26 (ii) 93

(iii) 112 (iv)54

ANSWER:

(i) 26 = 2 × 2 × 2 × 2 × 2 × 2 = 64

(ii) 93 = 9 × 9 × 9 = 729

(iii) 112 = 11 × 11 = 121

(iv)54 = 5 × 5 × 5 × 5 = 625

Page No 252:

Question 2:

Express the following in exponential form:

(i) 6 × 6 × 6 × 6 (ii) t × t

(iii) b × b × b × b (iv) 5 × 5 × 7 ×7 × 7

(v) 2 × 2 × a × a (vi) a × a × a × c × c × c × c × d

ANSWER:

(i) 6 × 6 × 6 × 6 = 64

(ii) t × t= t2

(iii) b × b × b × b = b4

(iv) 5 × 5 × 7 × 7 × 7 = 52 × 73

(v) 2 × 2 × a × a = 22 × a2

(vi) a × a × a × c × c × c × c × d = a3 c4 d

Page No 253:

Question 3:

Express the following numbers using exponential notation:

(i) 512 (ii) 343

(iii) 729 (iv) 3125

ANSWER:

(i) 512 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 29

(ii) 343 = 7 × 7 × 7 = 73

(iii) 729 = 3 × 3 × 3 × 3 × 3 × 3 = 36

(iv) 3125 = 5 × 5 × 5 × 5 × 5 = 55

Page No 253:

Question 4:

Identify the greater number, wherever possible, in each of the following?

(i) 43 or 34 (ii) 53 or 35

(iii) 28 or 82 (iv) 1002 or 2100

(v) 210 or 102

ANSWER:

(i) 43 = 4 × 4 × 4 = 64

34 = 3 × 3 × 3 × 3 = 81

Therefore, 34 > 43

(ii) 53 = 5 × 5 × 5 =125

35 = 3 × 3 × 3 × 3 × 3 = 243

Therefore, 35 > 53

(iii) 28 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 256

82 = 8 × 8 = 64

Therefore, 28 > 82

(iv)1002 or 2100

210 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 1024

2100 = 1024 × 1024 × 1024 × 1024 × 1024 × 1024 × 1024 × 1024 ×1024 × 1024

1002 = 100 × 100 = 10000

Therefore, 2100 > 1002

(v) 210 and 102

210 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 1024

102 = 10 × 10 = 100

Therefore, 210 > 102

Page No 253:

Question 5:

Express each of the following as product of powers of their prime factors:

(i) 648 (ii) 405

(iii) 540 (iv) 3,600

ANSWER:

(i) 648 = 2 × 2 × 2 × 3 × 3 × 3 × 3 = 23. 34

(ii) 405 = 3 × 3 × 3 × 3 × 5 = 34 . 5

(iii) 540 = 2 × 2 × 3 × 3 × 3 × 5 = 22. 33. 5

(iv) 3600 = 2 × 2 × 2 × 2 × 3 × 3 × 5 × 5 = 24. 32. 52

Page No 253:

Question 6:

Simplify:

(i) 2 × 103 (ii) 72 × 22

(iii) 23 × 5 (iv) 3 × 44

(v) 0 × 102 ­­­­­ (vi) 52 × 33

(vii) 24 × 32 (viii) 32 × 104

ANSWER:

(i) 2 × 103 = 2 × 10 × 10 × 10 = 2 × 1000 = 2000

(ii) 72 × 22 = 7 × 7 × 2 × 2 = 49 × 4 = 196

(iii) 23 × 5 = 2 × 2 × 2 × 5 = 8 × 5 = 40

(iv) 3 × 44 = 3 × 4 × 4 × 4 × 4 = 3 × 256 = 768

(v) 0 × 102 = 0 × 10 × 10 = 0

(vi) 52 × 33 = 5 × 5 × 3 × 3 × 3 = 25 × 27 = 675

(vii) 24 × 32 = 2 × 2 × 2 × 2 × 3 × 3 = 16 × 9 = 144

(viii) 32 × 104 = 3 × 3 × 10 × 10 × 10 × 10 = 9 × 10000 = 90000

Page No 253:

Question 7:

Simplify:

(i) (− 4)3 (ii) (− 3) × (− 2)3

(iii) (− 3)2 × (− 5)2 (iv)(− 2)3 × (−10)3

ANSWER:

(i) (−4)3 = (−4) × (−4) × (−4) = −64

(ii) (−3) × (−2)3 = (−3) × (−2) × (−2) × (−2) = 24

(iii) (−3)2 × (−5)2 = (−3) × (−3) × (−5) × (−5) = 9 × 25 = 225

(iv) (−2)3 × (−10)3 = (−2) × (−2) × (−2) × (−10) × (−10) × (−10)

= (−8) × (−1000) = 8000

Page No 253:

Question 8:

Compare the following numbers:

(i) 2.7 × 1012; 1.5 × 108

(ii) 4 × 1014; 3 × 1017

ANSWER:

(i) 2.7 × 1012; 1.5 × 108

2.7 × 1012 > 1.5 × 108

(ii) 4 × 1014; 3 × 1017

3 × 1017 > 4 × 1014

Page No 260:

Question 1:

Using laws of exponents, simplify and write the answer in exponential form:

(i) 32 × 34 × 38 (ii) 615 ÷ 610 (iii) a3 × a2

(iv) 7X× 72 (v) (vi) 25 × 55

(vii) a4 × b4 (viii) (34)3

(ix) (x) 8t ÷ 82

ANSWER:

(i) 32 × 34 × 38 = (3)2 + 4 + 8 (am × an = am+n)

= 314

(ii) 615 ÷ 610 = (6)15 − 10 (am ÷ an = am−n)

= 65

(iii) a3 × a2 = a(3 + 2) (am × an = am+n)

= a5

(iv) 7x + 72 = 7x + 2 (am × an = am+n)

(v) (52)3 ÷ 53

= 52 × 3 ÷ 53 (am)n = amn

= 56 ÷ 53

= 5(6 − 3) (am ÷ an = am−n)

= 53

(vi) 25 × 55

= (2 × 5)5 [am × bm = (a × b)m]

= 105

(vii) a4 × b4

= (ab)4 [am × bm = (a × b)m]

(viii) (34)3 = 34 × 3 = 312 (am)n = amn

(ix) (220 ÷ 215) × 23

= (220 − 15) × 23 (am ÷ an = am−n)

= 25 × 23

= (25 + 3) (am × an = am+n)

= 28

(x) 8t ÷ 82 = 8(t − 2) (am ÷ an = am−n)

3.

If -4 is a root of the equation x² + pc - 4 = 0 and the quadratic equation x² + pc + q = 0 has equal roots, then find the values of p and q.​

Answer»

Answer:

1/2

Step-by-step EXPLANATION:

4.

Whats is the reciprocal of 24300?​

Answer»

ANSWER:

___1__ is the CORRECT answer

24300

hope it HELPS you❤ 66

5.

5. 70% of the students in a school are boys and the number of girls is 504. Find the number ofboys in the school.An ore contains 12% copper. How many kilograms of the ore are required to get 69 kg​

Answer»

Answer:

1176

Step-by-step explanation:

Then, as per the QUESTION 70% of BOYS = 70 NUMBER of girls = 30 Now, total number of students when the number of girls is 30 = 100 Then, total number of students when the number of girls is 504 = (100/30) × 504 = 1680 Total number of boys = 1680 – 504 = 1176

6.

Find the square root of 6+4√2​

Answer»

ANSWER:

\sqrt{6 + 4 \sqrt{2 } }  =  \sqrt{6 + 2 \sqrt{8} }  =  \sqrt{4 + 2 + 2 \sqrt{4 \times 2} }  =  \sqrt{4 }  +  \sqrt{2}  = 2 +  \sqrt{2}

7.

Write the test and the correspondence of vertices by which Triangles in a pair congruent ​

Answer»

Answer:

sorry PO hindi KO po ALAM eh

Step-by-step EXPLANATION:

pa brainleis po

salamat po

8.

Find x if (√3 )^x-3 (4√3 )^x+1

Answer»

Answer:

thank you for your name and ADDRESS of the soul of the DAY

9.

If p=-2 ,find the value of of -3p^2+4p+7

Answer»

ANSWER:

IF P=-2

THEN

-3(-2)²+4(-2)+7

-3(4)+(-8)+7

-12-8+7

-13

HOPE U LIKE IT

10.

For a=2 find the value of 5a+3a-2​

Answer»

Answer:

we will start by replacing the value of a

(5×2) + (3×2) -2

10 + 6 - 2

now we will FOLLOW the bodmas

(10 +6 ) -2

16 -2

=14

HOPE this might help you

11.

Find value of x° y° and z° ​

Answer»

ANSWER:

where is DIAGRAM to answer

12.

Please solve this pleaseChapter PROBABILITYif you don't know the answer then don't answer ​

Answer»

Step-by-step explanation:

35+25+40=100/2=50

means 50 FAMILY is

13.

Find the value of K ,if given equation has no solution:-(1)3x-4y+7=0 kx+3y-5=0 (2)2x-ky+3=0 3x+2y-1=0​

Answer»

ANSWER:

HOPE you GOT your answer ☺

14.

+ 5 को संख्यामा रेखा ने लिखिर​

Answer»

ANSWER:

+ panch

Step-by-step EXPLANATION:

THEREFORE HENCE prooved

15.

Aryan bro Divya nahi diya ​

Answer»

PAGALO PADAHI KRO

ssssssssssssssssssssssss

16.

. The sum of two integers is -226. If one of them is 36, Find out the otherinteger.​

Answer»

ANSWER:

X+36= -226

X= -226-36(PLUS CHANGES 2 MINUS WHILE CHANGING SIDES)

X= -262

HAPPY 2 HELP :)

MARK AS BRAINLIEST

Step-by-step explanation:

17.

The areas of two similiar triangle are81 Sq cm and 36 sq.cm if one side of the firsttriangle is 3cm Long What is the length ofcorresponding side of the second triangle .​

Answer»

ANSWER:

SIDE of the second TRIANGLE is equal to 2 CM

18.

Factorise 8ab2-12a2b​

Answer»

Step-by-step explanation:

8*a*B*2-12*a*2*b is your ANSWER

19.

I. What is the class size of the given data?a.20b.10c.30d.15ii.What is the classmark of the forthclass?a.70b.130c.20d.15iii.The number of oranges whose weight is more than 180g.a.1b.3c.2d.4iv.The number of oranges, whose weight is less than 100g.a.10b.3c.5d.13​

Answer»

ANSWER:

When X = 0 ,then Y = 3,When x=1, then y= 5+3=8

20.

17. At a Ramuan Mela, a stalkeeper in one of the food stallsaua ar financal vessel of base radius 15cm filled up to a height of 32 cm with orange juice. The juisted in small find causes of radius 3cmup to a heght of cm, and sold for 3 eachif u answer this rugby i Will mark u as thé brainliest ​

Answer»

Answer:

i have made a NEW INTRO so PLZ check out the SHOWER and get a chance to get a polygon

21.

Simplify using suitable identities (x + y + z)2  –  (x – y +z )2m pls don't cheat 5 m​

Answer»

ANSWER:

HEY MATE, I THINK this should be the CORRECT answer

22.

8. Find the n-th derivative for:(3 Points)y = e cosx sin^2 2x​

Answer»

Answer:

FOUGHT. God was a NICE way FOR1.

23.

Given a = 4, b = -2. Find: ab + ba.​

Answer»

Answer:

4×-2 + -2×4

-8+ -8

-16

this is your answer

please MARK me as BRAINLEST.

24.

Explain the bisexual method​

Answer»

Answer:

The TERM “bisexual” is used to describe a person who experiences emotional, romantic and/or sexual attractions to, or engages in romantic or sexual RELATIONSHIPS with, more than one sex or gender.

25.

8a + 3b - 7a + 2b + 11a - b solve in steps ​

Answer»

ANSWER:

8+3+7+2+11-

=9

Step-by-step EXPLANATION:

the answer is=9

26.

Add 2 mn, -4 mn, 8 mn, -6 mn

Answer»

Answer:

2MN+4MN+8MN+-6MN=SINCE ALL ARE LIKE TERMS

WE CAN ADD THEM

=8MN

HAPPY 2 HELP :)

MARK ME AS BRAINLIEST

Step-by-step EXPLANATION:

27.

HCF and LCM two numbers are 12 and 396 respectively. If one of thenumbers is 36, then the other number is:​

Answer»

ANSWER:

132 is the answer

HOPE you FOUND this helpful

Step-by-step EXPLANATION:

28.

What are the roots of the quadratic equation x² = 16?Please answer this question.

Answer»

Answer:

4

Step-by-step EXPLANATION:

PLEASE MARK me as BRAINLIEST

29.

Find the osiac rational number b/w.12 and}3​

Answer»

ANSWER:

SORRY don't KNOW the answer

30.

Graphical representation of air pollution rate in kerala and himachal pradesh​

Answer»

Answer:

55%

is graphical REPRESENTATION of Air POLLUTION rate in Kerala and HIMACHAL PRADESH

31.

Express in power natation. -27÷125​

Answer»

Step-by-step EXPLANATION:

27 \beta  \gamma e \gamma \pi \\

32.

16. Find the value of(-4) = (2/3)​

Answer»

ANSWER:

-6

mark me as BRAINLIEST PLSS

33.

Insert a rational number between 1/4 and -3/4​

Answer»

ANSWER:

-1/4 is the Answer

Step-by-step EXPLANATION:

pls MARK me as brainlist and FOLLOW me

34.

WRITTEN TEST NO.3A DIRECTIONS: ANALYZE EAOR YOUR SOLUTION.16% OF 10 =​

Answer»

Step-by-step EXPLANATION:

\huge\blue{Answer \:࿐ \:}

\huge\red{Brainliest \:Banado \:}

\huge\pink{Follow \:Kardo \:}

35.

If 9.5% of a number is 76 , find the number​

Answer»

ANSWER:

LET the number be x .

SEE the image

The number is 800

36.

A hostel had rations for 150 students for 60 days. After 12 days, 30 students leave the hostel. How long theremaining ration last?​

Answer»

Answer:

for 150 students the RATION lasted for =60 days

after 12 days the ratio would last for= 60-12

48 days

now, for 150 students the ration LASTS for= 48days

for ONE student the ration will last for= 48×150

if 30 more JOIN the ration would last for= 48×150/180

=40 days

Step-by-step explanation:

37.

Find the inverse of the following matrix using Gauss-Jordan elimination1 2 32 3 43 4 5​

Answer» MARK me as brillianst plz
I don’t KNOW what the ANSWER of this QUESTION
38.

350 for 3 upon 1/2 years at 8 % p.a​

Answer»

<P>

p= RS .350,R=8%p.a T=3 1/2

years =7/2 years

SI = P .R. T/ 100

350 × 8 ×7/100×2

R.S. 98

and amount =p+S.I

RS. 350 +Rs.98 = Rs. 448

39.

How many 3 upon 17 are there in 21​

Answer»

Answer:

3x7=21 BRUH

Step-by-step explanation:

3x7=21 , bruh

40.

2.सहा या गलतफा पपागका(i) क्या पूर्ण संख्याओं के योग के लिए संवृतता गुणधर्म लागू होता है?(ii) क्या पूर्ण संख्याओं के व्यवकलन के लिए संवृतता गुणधर्म लागू होता है?(n) क्या पूर्ण संख्याओं के गुणन के लिए संवृतता गुणधर्म लागू होता है?(iv) क्या पूर्ण संख्याओं के भाजन के लिए संवृतता गुणधर्म लागू होता है?((()​

Answer»

ANSWER:

I don't know if you have any QUESTIONS ask me to

Step-by-step explanation:

....

MARK me as BRAINLIST

41.

(x+7y) (7x -y)Find the product ​

Answer»

your ANSWER in this ATTACHMENT PLEASE SEE it

hope.u LIKE

42.

How much cm in 1 metre

Answer»

Answer:

it is 100 cm = 1 METER

please MARK it the BRAINLIEST

43.

(x-1/x)^+7(x-1/x)=51/4​

Answer»

Answer:

PLEASE WRITE clearly . L don't understand

Step-by-step explanation:

please write in a CLEAR way

.

.

44.

नाव लिहा फुफुसांदवारे श्वसन करणारे मत्स्य​

Answer»

I don’t KNOW how to READ HINDI MARK me as WELL

45.

Ba,b,c are in continued proportionIf a=3 c=12 ,b=?​

Answer»

ANSWER:

Why is distilled water USED in the BATTERIES and not the TAP water?

46.

Find the amount on Rs 24,000 at 7.5 per for four years​

Answer»

Answer:

Principal (P) = Rs. 24,000

Rate (R) = 7.5% P.A.

Time (T) = 4 Years

S.I. = (P × T × R)/100

= Rs. (24,000 × 4 × 7.5)/100

= Rs. 240 × 4 × 7.5

= 240 × 30 = Rs. 7200

Amount needed to clear the debt at the end of 4th year.

= Rs. 24000 + Rs. 7200 = Rs. 31200

Step-by-step explanation:

47.

Explain the ductile faiure of machine​

Answer»

Answer:

A ductile failure is a TYPE of failure SEEN in malleable materials characterized by extensive PLASTIC deformation or necking. This usually occurs PRIOR to the actual failure of the MATERIAL. The term ductile rupture refers to the failure of highly ductile materials.

48.

two adjacent sides of a parallelogram are 12 cm and 8 cm if the length of the altitude corresponding to the side 12 and 6 cm fine the length of the altitude corresponding to the sides 8 cm ​

Answer»

ANSWER:

Area of parallelogram which altitude corresponding to the SIDE of 12cm =area of parallelogram which altitude corresponding to 8cm  

altitude x BASE = altitude x base  

6cm x12cm = altitude x 8cm

altitude =9CM  

Step-by-step EXPLANATION:

49.

Find hcf of number 235 and 1050 using euclids division algorithm​

Answer»

Answer:

By USING EDL

a=bq+r

where a is > b

so a =867 and b=255

867=255×3+102

here r≠0 so a=255 and b=102

255=102×2+51

here r≠0 so a=102 and b=51

102=51×2+0

here r=0

so, Hcf of (867,255) is =51

Step-by-step EXPLANATION:

50.

Find the value of -11/30,-8/15+7/6+(-2/5)​

Answer»

ANSWER:

OPTION C is the CORRECT answer