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Find hcf of number 235 and 1050 using euclids division algorithm |
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Answer» Answer: By USING EDL a=bq+r where a is > b so a =867 and b=255 867=255×3+102 here r≠0 so a=255 and b=102 255=102×2+51 here r≠0 so a=102 and b=51 102=51×2+0 here r=0 so, Hcf of (867,255) is =51 Step-by-step EXPLANATION: |
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