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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
An expression to represent the sequence. 4, 7, 10, 13, 16 |
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Answer» Answer: 19 is the ANS Step-by-step EXPLANATION: HOPE it helps you make it BRAINLEIST |
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| 2. |
Work out the value of x if 9 to the power x =9/3 to the power x. |
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Answer» okkkkkkkkkkkkkkkkkkkkkkkkkkkk kkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk kkkkkkk |
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| 3. |
How many 25 paise coins are there in rupse |
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Answer» Answer: Step-by-step explanation: so 100/25 = 4 |
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| 4. |
What is the percentage of the youngest age group persons over those in theoldest age group?a) 400.56% b) 466.67%c) 500%d) 500.67% |
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| 5. |
A table is bought for Rs.1056 and sold at Rs.792. Find the loss percentage. |
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Answer» Answer: 2.64% Step-by-step EXPLANATION: LOSS PERCENTAGE= (1056-792)/100= 2.64% |
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| 6. |
Write 5 lines about pyramids |
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Answer» Step-by-step explanation: A pyramid is a structure, usually of stone, built in the shape of a pyramid. From ancient to MODERN times people in MANY different parts of the world have built such structures. The word "pyramid" comes from the Greek word pyramis which meant "wheat cake." The ancient EGYPTIAN word for them was something LIKE "MER". |
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| 7. |
ਜੋਕਰ ਘਣ ਦੀ ਭੁਜਾ ਦੀ ਲੰਬਾਈ 1 ਸਮ ਹੋਵੇ ਤਾਂ ਇਸਦੀ ਕੁੱਲ ਸਤਾ ਦਾ ਖੇਤਰਫਲ 1 ਸਮਾਂ ਹੋਵੇਗਾ . |
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Answer» Step-by-step EXPLANATION: షషచ బుచ్చిబాబు గోపీచంద్ పై గరం అయిన ఈ నెల థీమ్ ఇలా ఈ నెల తరువాత ఆ పార్టీ సీనియర్ నాయకుడు కూడా వైయస్ఆర్ జిల్లా ఆయన అన్నారు నేను నీకోసం నేను నీకోసం నేను ఇ sorry I can't UNDERSTAND your LANGUAGE |
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| 8. |
Least rationalizing factor of 2√125 |
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Answer» HOPE this is helpful Please MARK it as BRAINLIEST ANSWER |
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| 9. |
What is difference between Vertebrates and invertebrates?Thodi der pehle mai kitna khush tha par maine khud hi apni khusiyo ko aag laga dikya talent hai mere paas |
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Answer» Answer: Animals can be classified into two main groups: vertebrates and invertebrates. The main DIFFERENCE between vertebrates and invertebrates is that invertebrates, like INSECTS and FLATWORMS, do not have a backbone or a SPINAL column. Examples of vertebrates include HUMANS, birds, and snakes. |
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| 10. |
6. The distance between point A (5,- 3) and B (13, m) in 10 units. Calculate the value of m. |
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Answer» Step-by-step EXPLANATION: |
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| 11. |
5 is _______ %give answer of this question |
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Answer» the QUESTION is not APPROPRIATE |
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| 12. |
the area of a parallelogram and a square are the same if the perimeter of the square is 100 and height of the parallelogram is 15 find the length of the corresponding base of the parallelogram |
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Answer» Step-by-step EXPLANATION: GIVEN AREA of square and parallelogram are some. Area of square =S×S perimeter of square =4×S 160m=4×S ⇒ 4 160
=S ∴S=40cm Area =40×40=1600m
∴ Area of square =1600m 2
∴ Area of parallelogram=Base×height 1600=B×20 20 1600
=B B=80 ∴ corresponding base of the parallelogram is 80M. |
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| 14. |
728÷144÷12[88÷11 of 8 +(20-4×4-6) ] |
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Answer» Answer: the best of luck to you and your family and friends and family and friends and family and friends and family and friends and family and friends and family and friends and family and friends and family are well to the core proud of you are not the best of the factory se bolugi phir bhi MAINE use krti h kya HUA KHUSHI zukam ho gya hai dunia yha aik PAL and family and friends and colleagues at all of the DAY ☺️ to be your fan to the best regards |
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| 15. |
Write4upon1/8 indecimal form and find what kindof decimale expansions it has |
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Answer» Answer: 7ttcphcoycohctcnc vmjvhhhochohochohoogx8titcgicgcgcgcggxigctif8tx |
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| 16. |
Find the arithmetic mean of school wise savings in each mandal .Also find the arithmetic mean of saving of all school.Please don't spam.It is very urgent.please answer step by step explaination.. |
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Answer» The process by which the HEIGHT of the Earth Surface INCREASES is CALLED weathering. Flw_Me(Manam Manam OKATI) |
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| 17. |
3x,3x+1,,3x-1,3x+1 which is an even number ? |
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Answer» Answer: it depends on the condition, if we take x as odd NUMBER than,3x will be odd and the other will be even no. For EXAMPLE- (X=1 ),3×1=3 , 3×1+1=4 & 3×1-1=2 if we take x as even no. than the answer will be just opposite of FIRST condition . For example - (X=2) , 3×2=6 , 3×2 +1=7 , 3×2-1=5 . I hope it'll HELP you... |
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| 18. |
The speed of a car is 5 m/s, then thedistance covered in 2 hours and 30 min.is |
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Answer» DISTANCE travelled by card=15 km Time taken t=5minutes= 60 5
hr= 12 1
hr Speed of Arun v= t d
⟹ v= 1/12 15
=60 km/hr |
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| 19. |
5x+2y = 0(b) If a + b + c = 2, ab + bc + ca = -1 and abc = -2, find the value of a +b+2. |
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Answer» |
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| 20. |
Iv. ਬਹੁਪਦ 7 - 4x +5 ਵਿੱਚ x ਦਾ ਗੁਣਾਂਕ 4 ਹੈ ।( ਸਹੀ / ਗਲਤ)ਜੇਕਰ ਘਣ ਦੀ ਤੁਜਾ ਦੀ ਲੰਬਾਈ 1 ਸਮ ਹੋਵੇ ਤਾਂ ਇਸਦੀ ਕੁੱਲ ਸਤ੍ਹਾ ਦਾ ਖੇਤਰਫਲ 1 ਸਮੱਹੋਵੇਗਾ I ਸਹੀ/ ਗਲਤ). |
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Answer» pjCv(:V:vzohvbzxhNXPFNXPTMXPNRPRNDOR IDVRIBDORNDORBDORBDPN DIBIODHDLBRLXBNPRNXPRNXLNROCNRPNFPRNFLE DOBEODBPRBDR |
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| 21. |
If x minus one upon x equals to 4 then find the value of x plus one upon x |
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Answer» x-1/x=4 find the VALUE of x+1/x sorry I can't UNDERSTAND your QUESTION |
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| 22. |
If sin A = 3/4 find the value of tan A |
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Answer» Step-by-step explanation: Answer Given, sinA= 4 3
⇒ DC BC
= 4 3
⇒BC=3k and AC=4k where K is the constant of proportionality. By Pythagoras theorem, we have AB 2 =AC 2 −BC 2 =(4k) 2 −(3k) 2 =7k 2
⇒AB= 7
k So, COSA= AC AB
= 4k 7
k
= 4 7
And tanA= AB BC
= 7
k 3k
= 7
3
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| 23. |
Find the product : b¹¹×(-2b⁶) |
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Answer» Step-by-step EXPLANATION: tosttits godydtit jxykdy xkjgjggk gjugjg cgciug |
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| 24. |
7. A hostel spends 3200 on food for 20students for 30 days. If they spend 2400for 30 students, then for how many dayswill the food last? |
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Answer» Answer: 80 days Step-by-step EXPLANATION: okkkkkkkkkkkkkkkkk |
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| 25. |
* The distance between Bhopal andNagpur is 200 km. A car starts fromBhopal at 08.00 hours and reachesNagpur at 14.00 hours the same day. Ifthe car runs non-stop between Bhopaland Nagpur, the distance covered by carin one hour is....( )A) 63 km B) 59 km) 65 km D) 85 km |
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Answer» Step-by-step EXPLANATION: |
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| 26. |
A garrison if 1200 men has sufficient rations for 25 days at the rate of 2400g per man per day. If 300 men join them and the rations are reduced to 2000g per man per day, how long will the food last all of them? |
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Answer» Step-by-step explanation: 1500 men at 2Kg/man day ---> 3000 Kg NEEDED PER day 1200 *2.4 Kg/man day *25 days = 72,000 Kg availablee 3000 * NUMBER of days = 72,000 so days = 24 days |
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| 28. |
2.5 is ________%if you give the answer I will mark you as brainlist |
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Answer» Step-by-step explanation: Hr I am not sure if you are 56 or not YET but I am utkarsh Soni ROLL on 23 and girl for me RYT I am not sure what to do with my hair |
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| 29. |
Classify linear, quadratic and cubic : 3t |
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Answer» Step-by-step EXPLANATION: Question 5. Classify the FOLLOWING as LINEAR, quadratic and cubic polynomials: (i) X2 + x (ii) x – x3 (iii) y + y2 + 4 (iv) 1 + x (v) 3t (vi) r2 Solution: (i) x2 + x Highest power of x is 2 so it is a quadratic polynomials (ii) x – x3 Highest power of x is 3 so it is cubic polynomial (iii) y + y2 + 4 Highest power of y is 2 so it is quadratic polynomial (iv) 1 + x Highest power of x is 1 so it is linear polynomial (v) 3t Highest power of t is 1 so it is linear polynomial (vi) r2 Highest power of t is 2 so it is quadratic polynomial (vii) 7x3 Highest power of x is 3 so it is cubic polynomial |
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| 30. |
2. The length of a rectangular hall is 6 metres less than 4 times the breadth of the hall. What is the length, if the breadth is b meteres? |
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Answer» Here is the answer. Hope it helps Step-by-step explanation: |
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| 31. |
Using quotient rule, find the derivative of 'tan x' |
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Answer» DERIVATIVE PROOF of TAN(X) d/dx tan(x) = sec^2(x) |
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| 32. |
Construct a triangle ABC AB=5.4cm,BC=4.9cm,AC=4cm |
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Answer» this is the answer Step-by-step EXPLANATION: |
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| 33. |
Solve the linear equation2m/3-m/4=10 |
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Answer» m=24 Step-by-step EXPLANATION: 8m-3m=120 5m=120 m=120/5 m=24 |
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| 34. |
Help me in these questions pleeeeasssseeeeee guys |
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Answer» Answer: HEY, DEAR no need to say sorry right now I am a boy and I am from EUROPE |
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| 35. |
Find the marks scored on chemistry |
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Answer» Answer: Step-by-step explanation: because English & CHEMISTRY is vertcally opposite so marks in chemistry will be 75 |
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| 36. |
PRACTColour to show the given fraction:(a)4(b)10 |
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| 37. |
The length of arectangular field is greateritsbreadth by 10mlom. Its diagonalmore than the length Find theof the fieldthanis 5marea |
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Answer» Answer: Ha ha ha ha ☺️ Ha ha ha ha ha ha ha ha ha ha ha ha ha ha Ha ha ha ha YE the FOLLOWING the following cases FX is EQUAL to x cube 3 X square 3 X square 3 X square 3 X square 3 X square 3 X square 3 X square 3 X square 3 X square 3 X square 3 X square 3 X square 3 X |
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| 38. |
Solve for Maths (3x+45)° |
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Answer» Answer: 15 Step-by-step explanation: 3x+45 3x=45 x=45/3 x=15 |
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| 39. |
Divide :(a) 543.60 by 12 . |
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Answer» Step-by-step explanation: 543.60 by 12 = 45.3 |
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| 40. |
Please solve with photo and please solve with photo right ans will mark brainliest |
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Answer» Answer: See WHETHER it is correct . I have tried my BEST to WRITE a correct answerStep-by-step explanation: AREA of ROAD =100× area covered in 1 revoluation =100× lateral surface area of road =100×2 Area of road =100× area covered in 1 revoluation =100× lateral surface area of road =100×2πrh Given, d=140cm⇒L=2 m→ 100 h=1m =750×2× 140 × 100 2m ~ 1 = 100 1500×132 =1980m |
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| 41. |
4. Area of a triangle5. In AABC, AB = 5 cm, CE = 6 cm and AC4.8 cm. Find the length of BD and area of AABC.4.8ccSABCB12cm Find the length of perpendicular |
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| 43. |
1)Factorise the alegebraicexpressionsi 16xcube + 2xsquare + 44x+ 2x4 +64xsquare |
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Answer» 16x^3+66x^2+44x+8 is the answer |
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| 44. |
Find the length of the radius of a circular sector with an area of 1309 square meters and measure its central angle of 240 degrees, to the nearest meter |
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Answer» Step-by-step explanation: We have, Let the RADIUS of CIRCLE r=4cm. Angle θ=30 o
Area of SECTOR of circle = 360 o
θ
×πr 2
= 360 o
30 o
×π×4×4 = 12 π
×16 = 3 4π
= 3 4
×3.14 =4.186cm 2
Area of major sector = Area of circle-area of minor sector =πr 2 −4.186 =3.14×4×4−4.186 =3.14×16−4.186 =50.24cm. 2
Hence, this is the ANSWER. |
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| 45. |
Solve for Maths (8x-5)° |
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Answer» x=5/8° Step-by-step EXPLANATION: by EQUATING the EQUATION with 0,we get 8x-5=0 x=5/8 |
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| 46. |
What will be the area of an isosceles triangle with unequalside of 8 cm and each equal side 5cm?Seeds Sign |
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Answer» Answer: 12 cm² Step-by-step explanation: Given, TWO Equal Sides = 5cm Also, Third Side = 8cm So, Semi-Perimeter = (a + b + C)/2 = (10 + 8)/2 = 18/2 = 9 Now, Area of ∆ = √s(s - a)(s - b)(s - c) Area of ∆ = √9(9 - 5)(9 - 5)(9 - 8) Area of ∆ = √9(4)(4)(1) Area of ∆ = √144 Hence, Area of ∆ = 12 cm² |
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| 47. |
Verify Euler’s formula for the following solids and draw their nets.(i) Regular tetrahedron. (ii) Octahedron prism. |
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Answer» Euler's formula for solids ⇒ Faces+ Vertices− Edges =2 The given SOLID in the IMAGE is a Cuboid ∴ Faces of the cuboid =6 Vertices=8 Edges =12 putting these VALUES in Euler's formula ⇒6+8−12=2 Hence, Verified. |
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| 48. |
in the adjoining figure measures of angle BAC and angle ADC are indicated. calculate the measures of the remaining angles. is angle abc isosceles give reason |
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Answer» Answer: 80+ABC=130 ABC=50 80+ABC+ACB=180 80+50+ACB=180 ACB=60 |
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| 49. |
Sec20 – tan20 = ?la(b) 0(c)1÷2(d)Ź |
Answer» 0.21332657673Step-by-step EXPLANATION: here is your answer HOPE it will HELP you |
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| 50. |
أوجد طول نصف قطر قطاع دائري مساحته 1309 متر مربع وقياس زوايته المركزيه 240درجه لأقرب متر |
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Answer» Answer: yƒod½tñg„t_Œr„rf½Ugt (y) Œëltü fuU Wúth c„tRY | 1. fwUA vrGgtü fuU ltb c„tRY | s : fUtug˜, fUtiyt, fUcq„h, „tu„t, „e„h, vvent, btuh, cxuh, nkm YTR” | 2. I I mkde„ bltuhksl fUt YfU mtOl ni | I I Rm fuU cthu yvlu rJath c„tRY | s : mkde„ bltuhksl fUt ŒCtJNt˜e mtOl ni | Rmmu nbthe NtherhfU ytih btlrmfU ƒfUtl ”qh ntu st„e ni | Rmmu YfUtd½raút c·Z„e ni | RmfUtu meFlt YfU yåAe yt”„ ni | (yt) vtX vr·ZY | yÇgtm-fUtgo fUersY | * Jt¢gtü fUtu mne f½Ub ”ersY | :_ 3, 4, 2, 1, 5 * rfUmlu rfUmmu fUnt_ 1. „wb ˜tudtü lu fUCe bwSu dtlu Jt˜e rar·zgt fuU rJMg bü lné c„tgt |( htst lu muJfUtü MU fUnt ) 2. nbthu htst „wöntht bOwh mkde„ mwllt atn„u nî | (˜·zfUe lu rar·zgt mu fUnt ) 3. bwSu yvlt mkde„ bunl„ fUhlu Jt˜tü fUtu Ce mwltlt ni | ( vGe lu htst mu fUnt ) * ylwåAu” v·ZfUh Œëltü fuU Wúth ”ersY | 1. Cth„ mhfUth lu Jàg seJtü fuU mkhGK fuU r˜Y fUtilmt yrOrlgb cltgt ni ? s : Cth„ mhfUth lu Jàg seJtü fuU mkhGK fuU r˜Y mlT 1972 bü I Jàg ŒtKe mwhGt yrOrlgb 1972 I cltgt | 2. gntâ vh rfU„lu htíx±eg W”Tgtltü fUe mkÏgt c„tge dge ni ? s : gntâ vh 69 htíx±eg W”Tgtltü fUe mkÏgt c„tge dge nî | 3. ctDtü fUe mwhGt fuU r˜Y fUtilme gtuslt fUtgo fUh hne ni ? s : ctDtü fUe mwhGt fuU r˜Y I Œtusu¢x xtRdh I sime gtuslt fUtgo fUh hne ni |yƒod½tñg„t_Œr„rf½Ugt (y) 1. Cth„egtü fuU cthu bü fUrJ lu ¢gt fUnt ni ? (vtX fUt mthtkN) s : rsm ”uN bü vrJºt dkdt cn„e ni, Jimu vrJºt †”gJt˜u Cth„Jtme ni | rslfuU ntüXtü vh matRo ntu„e ni, bunbtltü fUtu ŒtKtü mu ßgt”t mbS„u nî, ƒtu·zu mu FwNe seJl RC„tlu Jt˜u nî, ôJtƒeo ntufUh seJl rc„tluJt˜u lné nî ytih rJëJ fUtu YfU„t mu hnlu fUt mk”uN ”uluJt˜u nî | 2. Cth„ bü CNLU Jt˜e fwUA lr”gtü fuU cthu bü c„tRY | s : dkdt, gbwlt, mhôJ„e, c½ñbvwºtt, dtu”tJhe, fÐUíKt ytr” | (yt) vtX vr·ZY | yÇgtm fUtgo fUersY | * fUrJ„t fuU ytOth vh Wra„ f½Ub ”ersY | s : 2, 1, 4, 3. yrCÔgr¢„ _ mÐsltÀbfU„t (y) Rl Œëltü fuU Wúth ”tu-„el Jt¢gtü bü ”ersY | 1. de„ bü fUrJ lu rb˜-sw˜ fUh hnlu fuU r˜Y ¢gtü fUnt ntudt ? s : rb˜sw˜fUh hnlu mu ylufU ˜tC ni | Rmmu ”uN fUe YfU„t c·Z„e ni | Rmmu CtRoatht c·Z„t ni | 2. nb yvlu bunbtl fuU mtƒ fUimt ÔgJnth fUhlt atrnY ? s : nb yvlu bunbtltü fUtu ŒtK mu Ce ßgt”t mbSlt atrnY | 3. I nh stl fUe ·fUeb„ stl„u nî | I RmfUt CtJ yvlu Nç”tü bü r˜rFY | s : nh Cth„Jtme mCe fUtu yvlt CtRo mbSfUh rb˜sw˜fUh hn„u nî | Rmr˜Y Ju I I nh stl fUe fUeb„ stl„u nî | I I 4. Rm de„ bü ytvfUtu fUtilme CT„ü cý„ yåAe ˜dé ? ¢gtü ? s : Rm de„ bü bwSu vn˜t v” yåAt ˜dt ¢gtü rfU nh Cth„Jtme ma ne ctu˜„t ni ytih WmfUt r”˜ NwÆ” ytih dkdt l”e fuU mbtl vrJºtJtl ni |2. તારાઓ સDી બનું છું ની ફરતે ભર કરે છે |
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