1.

What will be the area of an isosceles triangle with unequalside of 8 cm and each equal side 5cm?Seeds Sign​

Answer»

Answer:

12 cm²

Step-by-step explanation:

Given,

TWO Equal Sides = 5cm

Also,

Third Side = 8cm

So,

Semi-Perimeter

= (a + b + C)/2

= (5 + 5 + 8)/2

= (10 + 8)/2

= 18/2

= 9

Now,

Area of ∆ = √s(s - a)(s - b)(s - c)

Area of ∆ = √9(9 - 5)(9 - 5)(9 - 8)

Area of ∆ = √9(4)(4)(1)

Area of ∆ = √144

Hence,

Area of ∆ = 12 cm²


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