332354 + Interview Questions in Secondary School in Math

1.	5/12+3/4 -3 find the equation
Answer» ANSWER: -1.83333333333 this is the answer the QUESTION

1.

5/12+3/4 -3 find the equation

Answer»

ANSWER:

-1.83333333333 this is the answer the QUESTION

Discussion

2.	निम्नलिखित में से कौन-सी पूर्ण वर्ग संख्या नहीं है?(क)256(ख)562(ग)289
Answer» Answer: 562 i THING it is not any NUMBER SQAURE

2.

निम्नलिखित में से कौन-सी पूर्ण वर्ग संख्या नहीं है?(क)256(ख)562(ग)289

Answer»

Answer:

562 i THING it is not any NUMBER SQAURE

Discussion

3.	Points A B and c are collinear then area of triangle A B C will be
Answer» Step-by-step explanation: (a),(c),(d) are the CORRECT OPTIONS. Step-by-step explanation: (a) If three points are collinear, then they lie on the same line. The vertices of the TRIANGLE lie on the same line and hence, the area of TRIANGLEABC = 0 no need to mark 30 thanks

3.

Points A B and c are collinear then area of triangle A B C will be

Answer»

Step-by-step explanation:

(a),(c),(d) are the CORRECT OPTIONS. Step-by-step explanation: (a) If three points are collinear, then they lie on the same line. The vertices of the TRIANGLE lie on the same line and hence, the area of TRIANGLEABC = 0

no need to mark

30 thanks

Discussion

4.	Find the product - 1/10 × 2/3 × 5/8. please tell the solution step-by-step
Answer» Answer: 1/24 is the answer Step-by-step explanation: 10/240 0 GETS CANCELED so 1/24 will be REMAINED

4.

Find the product - 1/10 × 2/3 × 5/8. please tell the solution step-by-step

Answer»

Answer:

1/24 is the answer

Step-by-step explanation:

10/240

0 GETS CANCELED

so 1/24 will be REMAINED

Discussion

5.	Cube root of 4.34
Answer» ANSWER: don't KNOW PLEASE SEND me

5.

Cube root of 4.34

Answer»

ANSWER:

don't KNOW PLEASE SEND me

Discussion

6.	सम संख्या किन्हें कहते है ? 1 और 100 के बीच की सम संख्याएँ लिखिए ।
Answer» Answer: 2zyawyeyeyeywueyeyeeeu

6.

सम संख्या किन्हें कहते है ? 1 और 100 के बीच की सम संख्याएँ लिखिए ।

Answer»

Answer:

2zyawyeyeyeywueyeyeeeu

Discussion

7.	While checking the value of 20 observations, it was noted that 125 was wrongly noted as 25 while calculating the mean and then the mean was 60. Find the correct mean
Answer» $\huge\colorbox{pink}{Answer ✔}$ LET y be the sum of observation of 19 (20 - 1) numbers leaving 125, So, y + 25 = 20 * 60 = 1200 (Mean = sum of observations/ no. of observations) As we know ➠ x + 25 = 20 × 60 = 1200 Also ➠ x + 125 =20 × y = 20Y Next, Subtract 125 - 25 = 20y - 1200 ➠ 20y = 1300 ➠ y = 65 *Aur* *koi* *day* *yaad* *rhe* ya na *rhe* ye *wala* *toh* *yaad* HI *rhe* *ga!! HAPPY* *SLAP* *DAY!*! HOPE it helps ☺️☘️☺️

7.

While checking the value of 20 observations, it was noted that 125 was wrongly noted as 25 while calculating the mean and then the mean was 60. Find the correct mean

Answer»

$\huge\colorbox{pink}{Answer ✔}$

LET y be the sum of observation of 19 (20 - 1) numbers leaving 125,

So, y + 25 = 20 * 60 = 1200

(Mean = sum of observations/ no. of observations)

As we know

➠ x + 25 = 20 × 60 = 1200

Also

➠ x + 125 =20 × y = 20Y

Next, Subtract 125 - 25 = 20y - 1200

➠ 20y = 1300

➠ y = 65

Aur koi day yaad rhe ya na rhe ye wala toh yaad HI rhe ga!!

HAPPY SLAP DAY!!

HOPE it helps ☺️☘️☺️

Discussion

8.	What is force???ok ji mt bataiye hanji hm to bahut darpok hai pr hame pahle pta nahi tha tq batane ke liye
Answer» ANSWER: A force is a PUSH or pull UPON an object RESULTING from the object's interaction with another object. Whenever there is an interaction between TWO objects, there is a force upon each of the objects.

8.

What is force???ok ji mt bataiye hanji hm to bahut darpok hai pr hame pahle pta nahi tha tq batane ke liye

Answer»

ANSWER:

A force is a PUSH or pull UPON an object RESULTING from the object's interaction with another object. Whenever there is an interaction between TWO objects, there is a force upon each of the objects.

Discussion

9.	If the diameter of a sphere is 14m then find the volume of this sphere
Answer» ANSWER: 3,201.34 $m^{3}$ Step-by-step EXPLANATION: DIAMETER = 14m So, Radius (r) = 7m Volume of sphere = $\frac{4}{3}$ π $r^{3}$ = $\frac{4}{3}$ × 7 × 7 × 7 × 7 = $\frac{9604}{3}$ ≈ 3,201.34 $m^{3}$

9.

If the diameter of a sphere is 14m then find the volume of this sphere

Answer»

ANSWER: 3,201.34 $m^{3}$

Step-by-step EXPLANATION:

DIAMETER = 14m

So, Radius (r) = 7m

Volume of sphere = $\frac{4}{3}$ π $r^{3}$

= $\frac{4}{3}$ × 7 × 7 × 7 × 7

= $\frac{9604}{3}$

≈ 3,201.34 $m^{3}$

Discussion

10.	1) A flying disc has a diameter of 9 5/8 inches. find it circumference.2) a hamster wheel has a radius of 4 1/2 inches. how far will the wheel turn in one revolution ? show the steps please.thank you
Answer» 1). r=77/16 use it in formula 2πr you'll GET your answer 2). use same as in this you'll find your answers

10.

1) A flying disc has a diameter of 9 5/8 inches. find it circumference.2) a hamster wheel has a radius of 4 1/2 inches. how far will the wheel turn in one revolution ? show the steps please.thank you

Answer»

1). r=77/16 use it in formula

2πr

you'll GET your answer

2). use same as in this you'll find your answers

Discussion

11.	Find the ratio of the following5m to 10km
Answer» Answer: 5:10 RATIO of the FOLLOWING.

11.

Find the ratio of the following5m to 10km

Answer»

Answer:

5:10 RATIO of the FOLLOWING.

Discussion

12.	Find the value of x
Answer» Answer: the value of x is 1 OK so plz FOLLOW

12.

Find the value of x

Answer»

Answer:

the value of x is 1 OK

so plz FOLLOW

Discussion

13.	In PQR PQ=PR=y QR=10cm and area of PQR=60cm2
Answer» Step-by-step explanation: same format but U NEED to CHANGE na number and SOLVE

13.

In PQR PQ=PR=y QR=10cm and area of PQR=60cm2

Answer»

Step-by-step explanation:

same format but U NEED to CHANGE na number and SOLVE

Discussion

14.	If the marked price = 7990 and the percentage of discount is 10 thenfind the selling price.
Answer» ANSWER: the answer is 7191 PLEASE heoeiehcwg4

14.

If the marked price = 7990 and the percentage of discount is 10 thenfind the selling price.

Answer»

ANSWER:

the answer is 7191 PLEASE heoeiehcwg4

Discussion

15.	Write all other trigonometric ratios in terms of sec A
Answer» Step-by-step EXPLANATION: SinA = ✓(Sec^2 A-1) / SecA Cos A = 1/SecA TAN A = ✓(Sec^2 A-1) COTA = 1/√(Sec^2 A -1) COSECA = SecA/ √(Sec^2 A -1)

15.

Write all other trigonometric ratios in terms of sec A

Answer»

Step-by-step EXPLANATION:

SinA = ✓(Sec^2 A-1) / SecA

Cos A = 1/SecA

TAN A = ✓(Sec^2 A-1)

COTA = 1/√(Sec^2 A -1)

COSECA = SecA/ √(Sec^2 A -1)

Discussion

16.	20 कबूतरो को 7बारी में उड़ाना है लेकिन जोड़े मे नहीं उड़ाना है
Answer» Answer: pelhe 6 udha FIR 1 ko fir se niche la or fir WAPAS 2 ko lija

16.

20 कबूतरो को 7बारी में उड़ाना है लेकिन जोड़े मे नहीं उड़ाना है

Answer»

Answer:

pelhe 6 udha FIR 1 ko fir se niche la or fir WAPAS 2 ko lija

Discussion

17.	64. Represent 2x + 3y = 6 by a graph. Write the coordinates of the point where it meets: (a) x-axis (b)y-axis
Answer» ANSWER: (a) (3,0) (B) (0,2) Step-by-step EXPLANATION:

17.

64. Represent 2x + 3y = 6 by a graph. Write the coordinates of the point where it meets: (a) x-axis (b)y-axis

Answer»

ANSWER:

(a) (3,0)

(B) (0,2)

Step-by-step EXPLANATION:

Discussion

18.	Find x angle boc,cod and Aod
Answer» Answer: add all ANGLE and put it in equal ti 180° like x+10+x+x+20=180 3x=180-30 x=150/3 x=50° i HOPE you will find it helpful ❤️

18.

Find x angle boc,cod and Aod

Answer»

Answer:

add all ANGLE and put it in equal ti 180°

like

x+10+x+x+20=180

3x=180-30

x=150/3

x=50°

i HOPE you will find it helpful ❤️

Discussion

19.	(Ch. 8)(15) Make a list of places in Brazil you would like to visit. Discuss about the types of these touristplaces with your friends. Present the information in the classroom.(Ch. 9)
Answer» Step-by-step EXPLANATION: All explanation in IMAGES

19.

(Ch. 8)(15) Make a list of places in Brazil you would like to visit. Discuss about the types of these touristplaces with your friends. Present the information in the classroom.(Ch. 9)

Answer»

Step-by-step EXPLANATION:

All explanation in IMAGES

Discussion

20.	अति लघु उत्तरीय प्रश्नन 23.एक ऋणात्मक परिमेय संख्या का व्युत्क्रम क्या होता है?
Answer» ANSWER: please joi*N scf-pcvc-dki to TALK as FRIEND

20.

अति लघु उत्तरीय प्रश्नन 23.एक ऋणात्मक परिमेय संख्या का व्युत्क्रम क्या होता है?

Answer»

ANSWER:

please joi*N scf-pcvc-dki to TALK as FRIEND

Discussion

21.	दिए संख्या रेखा के आधार पर कौन-सा विकल्प सही है-!HDD-b.B--7C.A-6essment/2020-21/Class-7
Answer» ANSWER: N hchchchcchchc Step-by-step EXPLANATION: gkvjyvjjcigmvugjvhvnch

21.

दिए संख्या रेखा के आधार पर कौन-सा विकल्प सही है-!HDD-b.B--7C.A-6essment/2020-21/Class-7

Answer»

ANSWER:

N hchchchcchchc

Step-by-step EXPLANATION:

gkvjyvjjcigmvugjvhvnch

Discussion

22.	1) The point (3,-5) liesIa) On the x-axis b) on the y-axis c) in the 1st quadrant d) in the 4th quadrant
Answer» ANSWER: Answer- In the 4th QUADRANT. Step-by-step EXPLANATION: The points are ( 3, -5) and since one is POSITIVE and the other is negative and by this we can conclude that it lies in 4th quadrant.

22.

1) The point (3,-5) liesIa) On the x-axis b) on the y-axis c) in the 1st quadrant d) in the 4th quadrant

Answer»

ANSWER:

Answer- In the 4th QUADRANT.

Step-by-step EXPLANATION:

The points are ( 3, -5) and since one is POSITIVE and the other is negative and by this we can conclude that it lies in 4th quadrant.

Discussion

23.	Time management in professional and personal life introduction using the famous slogan or proverbs
Answer» Answer: JUN 2, 2013 - Explore PLAN My Day's board " Time MANAGEMENT Quotes" on ... your time right to spend it with the people that matter the most- your FAMILY ... Explore our collection of MOTIVATIONAL and famous quotes .

23.

Time management in professional and personal life introduction using the famous slogan or proverbs

Answer»

Answer:

JUN 2, 2013 - Explore PLAN My Day's board " Time MANAGEMENT Quotes" on ... your time right to spend it with the people that matter the most- your FAMILY ... Explore our collection of MOTIVATIONAL and famous quotes .

Discussion

24.	वितरकता के उपयोग से निम्नलिखित का मान ज्ञात किजिए{7/5×(-3/12)}+{7/5×5/12}
Answer» I HOPE this will HELP you FRIEND.

24.

वितरकता के उपयोग से निम्नलिखित का मान ज्ञात किजिए{7/5×(-3/12)}+{7/5×5/12}

Answer»

I HOPE this will HELP you FRIEND.

Discussion

25.	A ship sails from harbour H on a bearing of084° for 340 km until it reaches point P. Itthen sails on a bearing of 210° for 160 kmuntil it reaches point Q.a Calculate the distance between point Qb On what bearing must the ship sail toreturn directly to the harbour from Q?and the harbour.
Answer» Given: Distance from H to P = 340km Distance from P to Q = 160km Ship bearing angle H to P = 84° Then SAILS from P to Q bearing angle = 210° To find: a) Calculate the distance between point Q and the harbor. b) On what bearing must the ship sail to return directly to the harbor from Q? Solution: (b) Angle between 340km and 160km will be ∠HPQ ∠NPQ = 360° - 210° = 150° i.e total angle P - (1) Now ∠NPH = 180° - 84° = 96° - (2) As we can see HN ║ PN and HP is transversal so sum of interior angle is 180°. From (1) and (2) we get ∠HPQ = ∠NPQ - ∠NPH ∠HPQ = 150° - 96° ∠HPQ = 54° (a) To calculate distance between Q and harbor 'H' We will use COSINE formula as we have one angle and two sides of ΔHPQ ∠P = 54° , HP = 340km , PQ = 160km (QH)² = (PH)² + (PQ)² - 2(PH)(PQ)cos∠HPQ (QH)² = (340)² + (160)² - 2(340)(160)cos54° (QH)² = 519904.965 QH = 227.8km ≈ 228km

25.

A ship sails from harbour H on a bearing of084° for 340 km until it reaches point P. Itthen sails on a bearing of 210° for 160 kmuntil it reaches point Q.a Calculate the distance between point Qb On what bearing must the ship sail toreturn directly to the harbour from Q?and the harbour.

Answer»

Given:

Distance from H to P = 340km

Distance from P to Q = 160km

Ship bearing angle H to P = 84°

Then SAILS from P to Q bearing angle = 210°

To find:

a) Calculate the distance between point Q and the harbor.

b) On what bearing must the ship sail to return directly to the harbor from Q?

Solution:

(b) Angle between 340km and 160km will be ∠HPQ

∠NPQ = 360° - 210° = 150° i.e total angle P - (1)

Now ∠NPH = 180° - 84° = 96° - (2)

As we can see HN ║ PN and HP is transversal so sum of interior angle is 180°.

From (1) and (2) we get

∠HPQ = ∠NPQ - ∠NPH

∠HPQ = 150° - 96°

∠HPQ = 54°

(a) To calculate distance between Q and harbor 'H'

We will use COSINE formula as we have one angle and two sides of ΔHPQ

∠P = 54° , HP = 340km , PQ = 160km

(QH)² = (PH)² + (PQ)² - 2(PH)(PQ)cos∠HPQ

(QH)² = (340)² + (160)² - 2(340)(160)cos54°

(QH)² = 519904.965

QH = 227.8km ≈ 228km

Discussion

26.	Fill in the blanks please answer
Answer» ANSWER: SEE the UPPER IMAGE . OK there Is your answer

26.

Fill in the blanks please answer

Answer»

ANSWER:

SEE the UPPER IMAGE .

OK there Is your answer

Discussion

27.	If 5 tan teta = 4. Find5 sin teta- 3 cos teta/5 sin teta + 2 cos teta .
Answer» ANSWER: Dono KO cos TETA se divide KARDE answer aajayega dono ka

27.

If 5 tan teta = 4. Find5 sin teta- 3 cos teta/5 sin teta + 2 cos teta .

Answer»

ANSWER:

Dono KO cos TETA se divide KARDE answer aajayega dono ka

Discussion

28.	डाइस में शीर्षों की संख्या होती है -(A) 6(B) 8(C) 10(D)12
Answer» ANSWER: (ʙ) 8 ʜᴇʟᴘs ᴜ!! ᴍᴀʀᴋ ᴍᴇ ᴀs ʙʀᴀɪɴʟɪsᴛ!!

28.

डाइस में शीर्षों की संख्या होती है -(A) 6(B) 8(C) 10(D)12

Answer»

ANSWER:

(ʙ) 8

ʜᴇʟᴘs ᴜ!!

ᴍᴀʀᴋ ᴍᴇ ᴀs ʙʀᴀɪɴʟɪsᴛ!!

Discussion

29.	SQ. Represent-3by7,5by7,9by7 on number line
Answer» [FF0000][B]Kᴏɪ ❤Ꮯᴜᴛᴇ❤ Ꮪɪ❤ Ꮮᴀᴅᴋɪ ❤Ꮇᴇʀɪ❤ Fʀɪᴇɴᴅ ❤Ᏼᴀɴ❤Jᴀᴏ❤Nᴀ❤❤❤

29.

SQ. Represent-3by7,5by7,9by7 on number line

Answer»

[FF0000][B]Kᴏɪ ❤Ꮯᴜᴛᴇ❤ Ꮪɪ❤ Ꮮᴀᴅᴋɪ ❤Ꮇᴇʀɪ❤ Fʀɪᴇɴᴅ ❤Ᏼᴀɴ❤Jᴀᴏ❤Nᴀ❤❤❤

Discussion

30.	Cbse class 9 math Ch 14 ex14.3 (6 sum)
Answer» Step-by-step EXPLANATION: POTY is RIGHT ANSWER haaaaaaaa

30.

Cbse class 9 math Ch 14 ex14.3 (6 sum)

Answer»

Step-by-step EXPLANATION:

POTY is RIGHT ANSWER haaaaaaaa

Discussion

31.	rehana borrows rs.2500 from brinda at an intrest rate of 8% for 2 years . how much money will rehana have to pay to brinda after 2 years
Answer» Answer: Rs 2900 Step-by-step explanation: Given Principal amount=Rs 2500 Rate of interest =8 PERCENT Time =2 years(24 months) Interest =P×R×T÷100 =2500×8×2÷100 =Rs 400 Amt to be PAID after 2 yrs=Principal amount+Interest =2500+400 =Rs 2900

31.

rehana borrows rs.2500 from brinda at an intrest rate of 8% for 2 years . how much money will rehana have to pay to brinda after 2 years

Answer»

Answer:

Rs 2900

Step-by-step explanation:

Given Principal amount=Rs 2500

Rate of interest =8 PERCENT

Time =2 years(24 months)

Interest =P×R×T÷100

=2500×8×2÷100

=Rs 400

Amt to be PAID after 2 yrs=Principal amount+Interest

=2500+400

=Rs 2900

Discussion

32.	In an exam passing marks are 40%. Joy got 500 marks and failed by 20 marks. What is the total marks of the exam .
Answer» Answer: 2,600 Step-by-step explanation: FIRST you do 500+20= 520 Therefore 520= 20% 20/100=1/5 so you do 520 TIMES 5 520 times 5= 2,600 Hope that makes sense if not i can EXPLAIN it differently

32.

In an exam passing marks are 40%. Joy got 500 marks and failed by 20 marks. What is the total marks of the exam .

Answer»

Answer:

2,600

Step-by-step explanation:

FIRST you do 500+20= 520

Therefore 520= 20%

20/100=1/5 so you do 520 TIMES 5

520 times 5= 2,600

Hope that makes sense if not i can EXPLAIN it differently

Discussion

33.	प्रश्न2(अ)-सरल रूप दीजिये.(2a+b)2 -(2a-b)2
Answer» ANSWER: (2a+b) 2 -(2a-b) 2 4a+2b-(4a-2b) 4a+2b-4a+2b =0

33.

प्रश्न2(अ)-सरल रूप दीजिये.(2a+b)2 -(2a-b)2

Answer»

ANSWER:

(2a+b) 2 -(2a-b) 2

4a+2b-(4a-2b)

4a+2b-4a+2b

=0

Discussion

34.	63. On the graph paper draw the straight line 3x – 2y = 4 and x + y - 3 = 0. Also, find their point ofintersection on the graph.
Answer» Answer: 3x 2y=4 X+y-3=0 put X=(3-y) in1st ==>3(3-y)-2y=4 ==>9-5y=4 ==> -5y=5 ==>y=1 ==X=2 X 3x-2y=4x+y-3=0

34.

63. On the graph paper draw the straight line 3x – 2y = 4 and x + y - 3 = 0. Also, find their point ofintersection on the graph.

Answer»

Answer:

3x 2y=4

X+y-3=0

put X=(3-y) in1st

==>3(3-y)-2y=4

==>9-5y=4

==> -5y=5

==>y=1

==X=2

X 3x-2y=4x+y-3=0

Discussion

35.	If the diameter of a sphere is 14 then find the volume of this sphere
Answer» GIVEN :- The diammeter of a SPHERE = 14 cm Solution :- $\purple{\boxed{ \bf{\sf \: Surface \: Area \: of \: Sphere = 2\pi {r}^{2} }}}$ ${ \bf{\sf \: 4 × \frac{22}{7} × 7 × 7}}$ ${ \bf{\sf \: 4 × 22 × 7}}$ $\red{\boxed{ \bf{\sf \: 616 \: {cm}^{2} }}}$ ${ \bf{\sf \: Volume \: Of \: Sphere = \frac{4}{3} \pi {r}^{3} }}$ ${ \bf{ \sf \: \frac{4}{3} × \frac{22}{7} ×7×7×7}}$ $\green{\boxed{ \bf{\sf \: 1437 \: {cm}^{3} }}}$

35.

If the diameter of a sphere is 14 then find the volume of this sphere

Answer»

GIVEN :-

The diammeter of a SPHERE = 14 cm

Solution :-

$\purple{\boxed{ \bf{\sf \: Surface \: Area \: of \: Sphere = 2\pi {r}^{2} }}}$

${ \bf{\sf \: 4 × \frac{22}{7} × 7 × 7}}$

${ \bf{\sf \: 4 × 22 × 7}}$

$\red{\boxed{ \bf{\sf \: 616 \: {cm}^{2} }}}$

${ \bf{\sf \: Volume \: Of \: Sphere = \frac{4}{3} \pi {r}^{3} }}$

${ \bf{ \sf \: \frac{4}{3} × \frac{22}{7} ×7×7×7}}$

$\green{\boxed{ \bf{\sf \: 1437 \: {cm}^{3} }}}$

Discussion

36.	अंकित मूल्य १०काएक वैठाउसेएकपरन्त 38 में बेचा जाता है । इसकतापर कितने पच्चिात डिस्काउंट दिया जा रहा
Answer» good luck with the best PART for you to be in a world that I THINK is the only THING he can say is that you are not a GREAT deal of the other guys that are in your hands when they can do something to you that will help them out with their relationship but they are still not sure what is happening to him or something that they are just a BIT shy of the world of different cultures that are different things you are going

36.

अंकित मूल्य १०काएक वैठाउसेएकपरन्त 38 में बेचा जाता है । इसकतापर कितने पच्चिात डिस्काउंट दिया जा रहा

Answer»

good luck with the best PART for you to be in a world that I THINK is the only THING he can say is that you are not a GREAT deal of the other guys that are in your hands when they can do something to you that will help them out with their relationship but they are still not sure what is happening to him or something that they are just a BIT shy of the world of different cultures that are different things you are going

Discussion

37.	The sum of the measure of the angles of a triangle is 180
Answer» Answer: Yes, the SUM of the measure of the ANGLES of a TRIANGLE is 180.

37.

The sum of the measure of the angles of a triangle is 180

Answer»

Answer:

Yes, the SUM of the measure of the ANGLES of a TRIANGLE is 180.

Discussion

38.	23:13::42: ?answer is 20 How???
Answer» Step-by-step EXPLANATION: I don't KNOW sorry hope u will GET right answer from ANYONE

38.

23:13::42: ?answer is 20 How???

Answer»

Step-by-step EXPLANATION:

I don't KNOW sorry

hope u will GET right answer from ANYONE

Discussion

39.	Yes.. simplify the question
Answer» Step-by-step EXPLANATION: Given:- √32+√48/√8+√2 ≪━─━─━─━─◈─━─━─━─━≫ √(32)+{√(48)/√(8)}+√(2) => 9.52055755. This is your ANSWER..༎ຶ‿༎ຶ

39.

Yes.. simplify the question

Answer»

Step-by-step EXPLANATION:

Given:- √32+√48/√8+√2

≪━─━─━─━─◈─━─━─━─━≫

√(32)+{√(48)/√(8)}+√(2)

=> 9.52055755.

This is your ANSWER..༎ຶ‿༎ຶ

Discussion

40.	Evaluate the limits :-(i) lim x → 0 cosx/π - x(ii) lim x → 0 ax + b/cx + 1
Answer» Answer: LIM x → 0 cosx/π - x Step-by-step EXPLANATION: hope it helps you

40.

Evaluate the limits :-(i) lim x → 0 cosx/π - x(ii) lim x → 0 ax + b/cx + 1

Answer»

Answer:

LIM x → 0 cosx/π - x

Step-by-step EXPLANATION:

hope it helps you

Discussion

41.	10. If the cost price of 11 shirts is equal to the selling price of 10 shirts, find the percentage profit or loss.
Answer» Answer: The shopkeeper gets profit and the profit percent is 10%. Step-by-step EXPLANATION: Let cost price of one SHIRT be RS x. GIVEN The cost price of 11 shirts is equal to the selling price of 10 shirts. Then, Cost price of 11 shirts = Rs 11x Selling price of 10 shirts = Rs 11x Selling price of one shirt = Rs 11x/10 = Rs 1.1x WE HAVE Selling price of one shirt = Rs 1.1x Cost price of one shirt = Rs x HERE Selling price is greater than the cost price as Rs 1.1x is greater than x. THEREFORE, Profit FORMULA USED Profit = SP - CP Profit percent = (Profit × 100)/CP % Where, Selling price = SP Cost price = CP FINDING THE PROFIT Profit = SP - CP Profit = Rs (1.1x - x) Profit = Rs 0.1x FINDING THE PROFIT PERCENT Profit percent = (Loss × 100)/CP % Profit percent = (0.1x × 100)/x % Profit percent = 10x/x % Profit percent = 10%

41.

10. If the cost price of 11 shirts is equal to the selling price of 10 shirts, find the percentage profit or loss.

Answer»

Answer:

The shopkeeper gets profit and the profit percent is 10%.

Step-by-step EXPLANATION:

Let cost price of one SHIRT be RS x.

GIVEN

The cost price of 11 shirts is equal to the selling price of 10 shirts.

Then, Cost price of 11 shirts = Rs 11x
Selling price of 10 shirts = Rs 11x
Selling price of one shirt = Rs 11x/10 = Rs 1.1x

WE HAVE

Selling price of one shirt = Rs 1.1x
Cost price of one shirt = Rs x

HERE

Selling price is greater than the cost price as Rs 1.1x is greater than x.

THEREFORE, Profit

FORMULA USED

Profit = SP - CP
Profit percent = (Profit × 100)/CP %

Where,

Selling price = SP
Cost price = CP

FINDING THE PROFIT

Profit = SP - CP
Profit = Rs (1.1x - x)
Profit = Rs 0.1x

FINDING THE PROFIT PERCENT

Profit percent = (Loss × 100)/CP %
Profit percent = (0.1x × 100)/x %
Profit percent = 10x/x %
Profit percent = 10%

Discussion

42.	Solve the following by transposing z/6 = -3
Answer» ANSWER: Z/6= - 3 Z= - 3x6 Z=-36. I HOPE this answer is HELPFUL for U

42.

Solve the following by transposing z/6 = -3

Answer»

ANSWER:

Z/6= - 3

Z= - 3x6

Z=-36.

I HOPE this answer is HELPFUL for U

Discussion

43.	What is the measure of RUP
Answer» ANSWER: MEANING of RIP REST in PEICES

43.

What is the measure of RUP

Answer»

ANSWER:

MEANING of RIP

REST in PEICES

Discussion

44.	Draw the angles of the following measures and determine their quadrants -120,300
Answer» Answer 120° LIES in 2ND quadrant 300° lies in 4TH quadrant hope it HELPS you..

44.

Draw the angles of the following measures and determine their quadrants -120,300

Answer»

Answer

120° LIES in 2ND quadrant

300° lies in 4TH quadrant

hope it HELPS you..

Discussion

45.	Find the absolute value of 3/12
Answer» 0.25 Step-by-step explanation: just DIVIDE it on 3 table and LATER devide so is to ABSTAIN in decimal that is 0.25

45.

Find the absolute value of 3/12

Answer»

0.25

Step-by-step explanation:

just DIVIDE it on 3 table and LATER devide so is to ABSTAIN in decimal that is 0.25

Discussion

46.	कनिका एक दिन में 3/8 सोती है । कनिका एक दिन में कितने घंटे सोती होगी।
Answer» Answer: 24×3/8=6 it's SIMPLE

46.

कनिका एक दिन में 3/8 सोती है । कनिका एक दिन में कितने घंटे सोती होगी।

Answer»

Answer:

24×3/8=6 it's SIMPLE

Discussion

47.	30÷5=6.then the quotient is
Answer» Answer: 6 Step-by-step explanation: Divide 30 by 5 to GET 6 6=6 compare 6and 6.

47.

30÷5=6.then the quotient is

Answer»

Answer:

6

Step-by-step explanation:

Divide 30 by 5 to GET 6

6=6

compare 6and 6.

Discussion

48.	When 2 − 1 exactly divides the polynomial () = 14 + 23 + 32 + 4 + 5 then prove that 1 + 3 + 5 = 2 + 4 = 0
Answer» Your 2- 1 = 14+ 23+ 32+ 4+ 5+1+ 3+ 5= +4 =0 = 92

Discussion

49.	Sheela noted a number as 34.3 instead of 3.43. Find the error percentage
Answer» Answer: 34.3 is 343 UPON 10 WHEREAS 3.43 is 343 upon 100.

49.

Sheela noted a number as 34.3 instead of 3.43. Find the error percentage

Answer»

Answer:

34.3 is 343 UPON 10 WHEREAS

3.43 is 343 upon 100.

Discussion

50.	a company has 70 employees who are engineers if the engineers compress 35 percentage of all employees find the total number of employees in the company
Answer» Answer: 70+35% Step-by-step EXPLANATION: you should ADD them both i THINK

50.

a company has 70 employees who are engineers if the engineers compress 35 percentage of all employees find the total number of employees in the company

Answer»

Answer:

70+35%

Step-by-step EXPLANATION:

you should ADD them both i THINK

Discussion

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