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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
ProbabilityA person has 3 children with at least oneboy. Find the probability of having at least 2 boys amongthe children. |
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Answer» Answer: We are TOLD that the father has atleast one BOY. Therefore the possible scenarios for the genders of the 3 CHILDREN are: 3 boys, 2 boys and 1 girl 1 boy and 2 girls. The probability for all these 3 scenarios is the same i.e. 1/3. Therefore the probability that the father has 2 boys and one girl is 1/3 |
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| 2. |
दिलेल्या पंकतीचा सरळ अर्थ लिहा फणस सवीर्गो कांटवले। |
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| 3. |
A sells his goods 20% cheaper than B and 20% dearer than C. How much percentage is C‟sgoods cheaper / dearer than B |
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Answer» LET tha selling price of B be 100 RUPEES =>Then the selling price of GOODS by A =80 rupees =>Now, 120% of selling price of goods by C = 80 =>Selling price of goods by C = => So C goods are cheaper than B goods by Answer is 33.3% |
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| 4. |
if surcharge on a commodity is reduced by 40% by how much percent should consumption increase so that revenue may remain untered ? |
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Answer» Don't PUT IRRELEVANT QUESTIONS OKAY |
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| 5. |
-31. Express as a rational number with denominator5(i) 20(ii) -30(iii) 35 |
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Answer» Answer: 1. 20 = 100/5 2. -30 = -150/5 3. 35 = 175/5 please MARK me as BRAINLIEST. |
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| 6. |
Factorise the following.c-8+8ab-abc |
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Answer» Step-by-step explanation: Mathematics NCERT Grade 8, Chapter 14: Factorisation- The chapter LAYS emphasis on the concept of how to express algebraic expressions as the products of their factors. In the introduction part following topics are discussed: 1. Factors of natural numbers 2. Factors of algebraic expressions An irreducible factor is a factor that cannot be expressed further as a product of factors. The chapter gives detail about the following topics: What is Factorisation? When we factorise an algebraic expression, we write it as a product of factors. These factors may be numbers, algebraic variables or algebraic expressions. After this, the Method of Common Factors is explained. A systematic way of factorising an expression is the common factor method. It contains three steps. Another section deals with a method called Factorising by regrouping terms. To practice questions based on this method, unsolved exercise 14.1 is given. Now the question arises What is Regrouping? Rearranging the expression allows us to FORM groups leading to factorisation. This is called regrouping. Factorisation using identities and factors in the form of (x +a) (x+b) are explained. Division of Algebraic Expressions: This section is divided into the following sub-sections: a. Division of a monomial by another monomial b. Division of a polynomial by a monomial Division of algebraic expressions continued ( Polynomial ÷ Polynomial) Division is the inverse of multiplication. Can You Find the Error? Important statements mentioned in the section:
Remember to make use of brackets, while substituting a NEGATIVE value. Remember, when you multiply the expression enclosed in a bracket by a constant (or a variable) outside, each term of the expression has to be multiplied by the constant (or the variable). Coefficient 1 of a term is usually not shown. But while adding like terms, we include it in the sum. Remember, when you square a monomial, the numerical coefficient and each factor has to be squared. While dividing a polynomial by a monomial, we divide each term of the polynomial in the numerator by the monomial in the denominator. All the topics are supplemented with examples and some short questions. 4 unsolved exercises are also given which contains questions in different patterns so that students can do enough practice of the same. To make the content of the chapter- Factorisation more interesting some FUN facts are also discussed in the chapter. Recaptulisation of all important points is done at the end. |
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| 7. |
Find the co ordiantes of the center of the circle which is drawn through points A,B and O |
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Answer» {2,3} Step-by-step EXPLANATION: |
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| 8. |
(1)एक कार 1 लीटर पेट्रोल में (x+2) किमी चलती है तो वह y लीटर पेट्रोल मेंचलेगी।(ii) |
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Answer» Answer: In y LITERS car will TRAVEL (xy + 2Y )KM Step-by-step explanation: 1 liter = x + 2 km y liters = y x (x +2) = (xy + 2y) km |
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| 9. |
In the given figure, PQR is an equilateraltriangle of side 20 cm. AQSR is inscribed in it,ZQSR = 90°, QS = 16 cm. Find (i) SR, (ii) thearea of the shaded portion. [Take 13 = 1.732]. |
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Answer» Step-by-step EXPLANATION: |
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| 10. |
What is elasticityare yrr itni der baad online aayi thi delete kar diya chal gali ni de ri bach gya |
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Answer» In economics, elasticity is the MEASUREMENT of the percentage change of one economic variable in RESPONSE to a change in another. An ELASTIC variable is one which RESPONDS more than proportionally to changes in other VARIABLES |
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| 11. |
True or falsel and give me the reasona line segment goes on and on, without changing direction |
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Answer» Answer: TrueExplanation:- A line has an infinite NUMBER of points, (in a STRAIGHT row), that keeps extending in both the directions. PLZ MARK AS BRIANLIEST,FLW ME AND THX FOR THE SUPERB QUESTION
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| 14. |
By selling a DVD. for Rs 12,000; a profit of Rs 1,500 ismade. The profit% is |
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Answer» PROFIT PERCENTAGE is 12.5 Step-by-step explanation: 12000x = 150000 Si x = 150000 / 12000 = 12.5 % |
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| 15. |
1 से 100 तक के प्राकृतिक संख्या का माध्य क्या होगा ?(a) 51(b) 50.5(c)50 |
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| 16. |
I³+1/i³ =?please solve it |
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Answer» now, i³=i.i²=i×(-1)=-i -i+1/(-i) = -i-1/i = (-(i²)-1)/i = (-(-1)-1)/i= 0/i= 0 ANSWER |
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| 17. |
Any one answer for this math |
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| 18. |
. एक फर्श की माप 5 मी x 4 मी है। फर्श को ढकने के लिएकितनी टाइलों की आवश्यकता होगी, यदि एक टाइल कीमाप 80 सेमी x 50 सेमी हो? |
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Answer» he was the only THING he was a 6AM PERSON to me but he had to do this to himself to get a little bit better in hindi or in a different direction but it would have to do this to him but I have a great job for a good TIME to get a job at a time to be |
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| 19. |
On comparing the ratios, , find out whether the following pair of linear equations is consistent, or inconsistent. – = ; – = . |
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| 20. |
*Points (3,2), (-2,-3) and (2,3) will make which type of triangle*1️⃣ equilateral triangle2️⃣ scalene triangle3️⃣ isosceles triangle4️⃣ right angle triangle |
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Answer» Answer: |
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| 21. |
If x +1 equal 3 finthe value of x6 +1x. x6 |
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Answer» Answer: Step-by-step EXPLANATION: Since x+1 = 3 x= 3-1 = 2 x6+1 = 2*6 +1 = 12+1 = 13 |
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| 22. |
Change into like fractions 5/7 and 7/9 |
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Answer» Answer: 5/7x9/9 =45/63 7/9x7/7=49/63 =45/63+49/63= 1.492 |
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| 23. |
Ramesh deposited rupees 4000 in a bank at 4% per annum. What amount will be get back after 2 year 9 months |
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Answer» P= 4000 RS. R= 4% TIME= 33 months I= 4000×33×34×4/2400 I= 7480 rs. Now, A= Pn+I A= 4000×33+7480 A= 1,39,480 rs. |
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| 24. |
In a class, no:of girls is x and that of boys is y. also, no:of girls is 6 more than no:of boys. write the given data in the form of a linear eqn.also represent it graphically |
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Answer» its HELPFUL for you |
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| 25. |
In a college the ratio of the number of boys to girls is 8:5 if there are 160 girls the total number of students in the college is |
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Answer» Answer: 416 Step-by-step explanation: 9ugfiyfigcigxufxigcigcigcigcigcicicc |
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| 26. |
Draw any one triangle and measure its sides.Check if the sum of the lengths of any two sides is greater than the third side |
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Answer» Answer: AB = 4.5 cm BC = 3.5 cm CA = 6.5 cm AB + BC = 4.5 + 3.5 = 8 AB + BC > CA ∴ Sum of two sides > Third side Step-by-step explanation: Hope this HELPS you ✌️ |
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| 27. |
Find the median of the following observation:25,12,8,28,22,10,17,36,51,40If 22 is replaced by 42, find the new median. |
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Answer» Answer: median in the first observation = 22 + 10 ÷ 2 = 16 median in the SECOND observation = 42 + 10 ÷ 2 = 26 pls mark me as the brainliest |
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| 28. |
Sanjay and Vijay invested Rs. 22,500 and Rs.35,000 in a new car company. The total profit madeby themwasRs.13,800,thenwhatwasVijay’sshare in the profit? (5 marks) |
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Answer»
SANJAY INVEST ON CAR =22500+13800=36300 SO THE PROFIT OF SANJAY IS ₹36300 PROFIT OF VIJAY 36300-35000=1300 SO THE PROFIT OF VIJAY IS ₹1300 |
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| 29. |
What is the value of x for which value of the expression 3x-4 and 2x+1 |
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Answer» Answer: The VALUE of x is 4/3 for 3x-4 The value of x is -1/2 for 2x +1 Step-by-step explanation: 3x-4 = 0 3x = 4 x = 4/3 2x + 1 = 0 2x = -1 x = -1/2 |
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| 30. |
Write the following decimal numbers as a fraction ( make sure fraction is in its lowest term )a. 0.06b. 12.45c. 9.005d. 45.25 |
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Answer» Answer: 6/100 1245/100 9005/1000 4525/100 Step-by-step explanation: 0.06=6/100 as there are TWO PLACES after the DECIMAL 12.45=1245/100 as there are two places after the decimal 9.005=9005/1000 as there are THREE places after decimal 45.25=4525/100 as there are two places after decimal |
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| 31. |
373.09 ×10^-4 convert it into standard form |
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Answer» Step-by-step EXPLANATION: rek-ftib-tzp (why reproduction is important in animal and how we FIND VELANCY of electron and happy DAY |
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| 34. |
If the website gives ACs points following the weighted sum of (3 x E) + N+B + S, then the total score for Samurai, Vidyut and Versa models will be- |
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Answer» Answer: here is your answer Step-by-step EXPLANATION: option d) samurai =15 ,VIDYUT =15 ,versa=16 |
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| 35. |
A square frame has sides measuring 17 cm what is the distance of the picture frame |
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Answer» Answer: 4×17=68cm Step-by-step explanation: The PERIMETER of a square = 4×sides = 4×17 = 68 cm I assume that you meant Perimeter when you SAID distance |
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| 36. |
Which of these is not a property of multiples |
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| 37. |
If a1=2 and an= (an-1)^2 +5 the find the value of a3 |
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Answer» a1=2 and an= (an-1)^2 +5 a3= a1×2d = 2x2×2 =8 |
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| 38. |
If a bus can travel 40 km in 45 minutes then how much it can travel in 12 minutes? |
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Answer» Answer: 10.7 km Step-by-step EXPLANATION: Distance TRAVELLED in 45 min = 40 km Distance travelled in 1 min = 40/45 Distance travelled in 12 min = (40/45) × 12 = 10.7 ( approx. , correct to 2 decimal PLACE)
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| 39. |
A field of grass feeds 40 goats for 10 days. How many days would the same field feed 20 goats? |
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Answer» 20 goats for 5 days |
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| 40. |
If the propability of an even if p then the probility an compilimantry event |
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Answer» So, PROBABILITY of its complementary EVENT = (1 – Probability of an event) = 1 – P. Step-by-step explanation: here is your answers |
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| 41. |
Consider a grouped frequency distributions of marks obtained out of 100 by 53 students in certain examination as follows 0 -10 510 -20 320 -30 430 -40 340 -50 350 -60 460 -70 770 -80 980 -90 7 90 -100 8find median |
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| 42. |
Write any two linear equations, and convert it into word problem. |
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| 43. |
(1/sec x-tan x)+(1/sec x + tan x) = 2/cos x |
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Answer» Step-by-step EXPLANATION: |
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| 46. |
(i) Looking at the figure (plan) the relation between x and y isa. x + 2y + πy = 1000b. 2x + 2y + πy = 1000c. x + 2y + πy = 500d. x + y + πy = 1000(ii) Area of sports ground in terms of x isa.2/π+2 (1000x − 2x^2)m2b. 1/π (1000x − 2x^2)m2c. 2/π+2 (500x − 2x^2)m2d. 1/π (500x − 2x^2)m2 (iii) The maximum area of sports ground is for x equal toa. 500mb. 50mc. 100md. 250m(iv) The government wants to maximize the area including parking area for this tohappen, value of y isa.1000/4+π mb. 2000/4+π mc. 500/4+π m d. 750/4+π m |
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| 47. |
Find LCM and HCF of x2 y and x y2. |
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Answer» Answer: i have made a NEW intro so plz CHECK out the SHOWER and get a chance to get a POLYGON |
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| 48. |
NotesRecord the list of things you might want to do.Whichnumboy О areandwhichof the followingrationalleft of othe right of o?theon.4- are |
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Answer» Answer: it is a valentine's day so.... Step-by-step EXPLANATION: Need of Rational numbers: In Mathematics, we FREQUENTLY come across simple equations to be solved. For example, the equation X + 2 = 13 —–(1) is solved when x = 11, because this value of x satisfies the given equation. The solution 11 is a natural number. On the other hand, for the equation x + 5 = 5 —–(2) the solution gives the whole number 0 (zero). If we consider only natural numbers, equation (2) cannot be solved. To solve equations like (2), we ADDED the number zero to the collection of natural numbers and obtained the whole numbers. Even whole numbers will not be sufficient to solve equations of type x + 18 = 5—– (3) Do you see ‘why’? We REQUIRE the number –13 which is not a whole number. This led us to think of integers, (positive and negative). Note that the positive integers correspond to natural numbers. One may think that we have enough numbers to solve all simple equations with the available list of integers. Consider the equations |
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| 49. |
Twoליין ה} (فحم) -CalculateСс a conperpendicularsan is asceles trianglequadrilates at ABCD when length of thediagonal A - room and- room and lengths ofon AC be 5cmB and DRespectively.5 6cm |
| Answer» WHATS this ?! Which | |