332354 + Interview Questions in Secondary School in Math

1.	Simplify ( √3+1√3-1 + √2+1√2-1 + √3-1√3+1 + √2-1√2+1) solve
Answer» Step-by-step EXPLANATION: √3+1√3-1 + √2+1√2-1 + √3-1√3+1 + √2-1√2+1 =√3√3+1-1+√2√2+1-1+√3√3+1-1√2√2+1-1 =3+0+2+0+3+0+2+0 =10 mark as BRAINLIEST

1.

Simplify ( √3+1√3-1 + √2+1√2-1 + √3-1√3+1 + √2-1√2+1) solve

Answer»

Step-by-step EXPLANATION:

√3+1√3-1 + √2+1√2-1 + √3-1√3+1 + √2-1√2+1

=√3√3+1-1+√2√2+1-1+√3√3+1-1√2√2+1-1

=3+0+2+0+3+0+2+0

=10

mark as BRAINLIEST

Discussion

2.	The sum of 3 terms in Geometric Progression is 21 and sum of their squares is 189. Find thenumbers
Answer» Answer:3, 6, 12 Step-by-step EXPLANATION: Geometric PROGRESSION with COMMON ratio 2

2.

The sum of 3 terms in Geometric Progression is 21 and sum of their squares is 189. Find thenumbers

Answer»

Answer:3, 6, 12

Step-by-step EXPLANATION: Geometric PROGRESSION with COMMON ratio 2

Discussion

3.	Simplify 9÷(-3)+7×2
Answer» Step-by-step EXPLANATION: ACCORDING to BODMAS, $9 \div ( - 3) + 7 \times 2 \\ = - 3 + 14 \\ = 11$ !!Hope it HELPS you!!

3.

Simplify 9÷(-3)+7×2

Answer»

Step-by-step EXPLANATION:

ACCORDING to BODMAS,

$9 \div ( - 3) + 7 \times 2 \\ = - 3 + 14 \\ = 11$

!!Hope it HELPS you!!

Discussion

4.	Solve this questionjisa aata hai ohe toh Karna iss questions ko....
Answer» ____BULK MODULUS____ THE RELATIVE CHANGE IN THE VOLUME OF A BODY PRODUCED BY A UNIT COMPRESSIVE OR TENSIL STRESS ACTING UNIFORMLY OVER ITS SURFACE. NUMERICAL CPNSTANT THAT DESCRIBES THE ELASTIC PROPERTIES OF A SOLID OR FLUID WHEN IT IS UNDER PRESSURE ON ALL SURFACES. THE APPLIED PRESSURE REDUCES THE VOLUME OF A MATERIAL, WHICH RETURNS TO ITS ORIGINAL VOLUME WHEN THE PRESSURE IS REMOVED.., ________________________________ EXPLANATION.., STRAIN = dL/L = 0.3/250 = 0.0012 ❤_____________________________❤ ...., be *happy, and* *chill.... ❤ I have* *cheated* it from *net* ..., *jhoot* *nhi* *bolti* *mai...., bas* *spamm* *karti* *HOO.*., ☞☜

4.

Solve this questionjisa aata hai ohe toh Karna iss questions ko....

Answer»

____BULK MODULUS____

THE RELATIVE CHANGE IN THE VOLUME OF A BODY PRODUCED BY A UNIT COMPRESSIVE OR TENSIL STRESS ACTING UNIFORMLY OVER ITS SURFACE.

NUMERICAL CPNSTANT THAT DESCRIBES THE ELASTIC PROPERTIES OF A SOLID OR FLUID WHEN IT IS UNDER PRESSURE ON ALL SURFACES. THE APPLIED PRESSURE REDUCES THE VOLUME OF A MATERIAL, WHICH RETURNS TO ITS ORIGINAL VOLUME WHEN THE PRESSURE IS REMOVED..,

________________________________

EXPLANATION..,

STRAIN = dL/L

= 0.3/250

= 0.0012

❤_____________________________❤

...., be happy, and chill.... ❤

I have cheated it from net ..., jhoot nhi bolti mai...., bas spamm karti HOO.., ☞☜

Discussion

5.	121.121-121.121-211.211+211.11+110.965
Answer» ANSWER : 110.864 "HOPE IT HELPS YOU" "MARK ME AS BRAINLIST" ⭐⭐⭐⭐⭐

5.

121.121-121.121-211.211+211.11+110.965

Answer»

ANSWER : 110.864

"HOPE IT HELPS YOU"

"MARK ME AS BRAINLIST"

⭐⭐⭐⭐⭐

Discussion

6.	Cube root of 3xminus2is equal to 4
Answer» ANSWER: $\sqrt[3]{3x - 2} = 4 \\ \\ 3x - 2 = 64 \\ \\ 3x = 62 \\ \\ x = 62 \div 3$ MARK as BRAIN LIST PLEASE

6.

Cube root of 3xminus2is equal to 4

Answer»

ANSWER:

$\sqrt[3]{3x - 2} = 4 \\ \\ 3x - 2 = 64 \\ \\ 3x = 62 \\ \\ x = 62 \div 3$

MARK as BRAIN LIST PLEASE

Discussion

7.	50 play tennis,50 play basket ballExpress the number of students who play tennis as a percentage of that who play basketball
Answer» Answer: 50% students play tennis. Step-by-step explanation: TOTAL strength = 100 No of students play tennis = 50 No of students play basketball = 50 Percentage of students play tennis = 50/100×100 = *50% (answer).* *PLEASE SELECT MY ANSWER AS THE BRAINLIEST ANSWER.*

7.

50 play tennis,50 play basket ballExpress the number of students who play tennis as a percentage of that who play basketball

Answer»

Answer:

50% students play tennis.

Step-by-step explanation:

TOTAL strength = 100

No of students play tennis = 50

No of students play basketball = 50

Percentage of students play tennis = 50/100×100

= 50% (answer).

PLEASE SELECT MY ANSWER AS THE BRAINLIEST ANSWER.

Discussion

8.	-7/5×5/7 solve it and also represent on number line
Answer» Answer: -1 is the answer for the question but I have no POSSIBILITY to PICK it on a number LINE

8.

-7/5×5/7 solve it and also represent on number line

Answer»

Answer:

-1 is the answer for the question but I have no POSSIBILITY to PICK it on a number LINE

Discussion

9.	Kojo wants to be an author. to improve his writing skills, everyday after school he writes 3 pages a story he is working on. mojo has been writing his story for d days. he has total of 81 pages completed.
Answer» ANSWER: He has been writing his STORY for 27 DAYS. Step-by-step EXPLANATION: *PLEASE SELECT MY ANSWER AS THE BRAINLIEST ANSWER.*

9.

Kojo wants to be an author. to improve his writing skills, everyday after school he writes 3 pages a story he is working on. mojo has been writing his story for d days. he has total of 81 pages completed.

Answer»

ANSWER:

He has been writing his STORY for 27 DAYS.

Step-by-step EXPLANATION:

PLEASE SELECT MY ANSWER AS THE BRAINLIEST ANSWER.

Discussion

10.	The area of a rectangular plot is 582 m the length of the plot is one more than twice its breadth find the length and breadth of the plot
Answer» $\blue{\bold{\underline{\underline{Answer:}}}}$ $\green{\tt{\therefore{Length=34.6\:m}}}$ $\green{\tt{\therefore{Breadth=16.8\:m}}}$ $\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$ $\green{\underline \bold{<klux>GIVEN</klux> :}} \\ \tt: \implies Area \: of \: rectangle = 582 \: {m}^{2} \\ \\ \tt: \implies Length \: of \: plot \: is \: one \: more \: that \: twice \: its \: Breadth \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Length = ? \\ \\ \tt: \implies Breadth = ?$ • ACCORDING to given QUESTION : $\circ \: \text{Let \: Breadth \: be \: x} \\ \\ \circ \: \text{Length = 1 + 2x} \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies Area \: of \: rectangle = Length \times Breadth \\ \\ \tt: \implies 582 = (1 + 2x) \times x \\ \\ \tt: \implies 582 = x + 2 {x}^{2} \\ \\ \tt: \implies {2x}^{2} + x - 582 = 0 \\ \\ \tt: \implies x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ \tt: \implies x = \frac{ - 1 \pm \sqrt{ {1}^{2} - 4 \times 2 \times 582 } }{2 \times 2} \\ \\ \tt: \implies x = \frac{ - 1 \pm \sqrt{1 + 4656} }{4} \\ \\ \tt: \implies x = \frac{ - 1 \pm \sqrt{4657} }{4} \\ \\ \tt: \implies x = \frac{ - 1 \pm68.2}{4} \\ \\ \tt: \implies x = \frac{67.2}{4} \\ \\ \green{\tt: \implies x = 16.8 \: m} \\ \\ \bold{Note-} \: \tt{ Length \: and \:Breadth \: cannot \: be \: in \: negative} \\ \\ \green{\tt \therefore Length = 1 + 2 \times 16.8 = 34.6 \: m} \\ \\ \green{\tt \therefore Breadth = x = 16.8 \: m}$

10.

The area of a rectangular plot is 582 m the length of the plot is one more than twice its breadth find the length and breadth of the plot

Answer»

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Length=34.6\:m}}}$

$\green{\tt{\therefore{Breadth=16.8\:m}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{<klux>GIVEN</klux> :}} \\ \tt: \implies Area \: of \: rectangle = 582 \: {m}^{2} \\ \\ \tt: \implies Length \: of \: plot \: is \: one \: more \: that \: twice \: its \: Breadth \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Length = ? \\ \\ \tt: \implies Breadth = ?$

• ACCORDING to given QUESTION :

$\circ \: \text{Let \: Breadth \: be \: x} \\ \\ \circ \: \text{Length = 1 + 2x} \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies Area \: of \: rectangle = Length \times Breadth \\ \\ \tt: \implies 582 = (1 + 2x) \times x \\ \\ \tt: \implies 582 = x + 2 {x}^{2} \\ \\ \tt: \implies {2x}^{2} + x - 582 = 0 \\ \\ \tt: \implies x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ \tt: \implies x = \frac{ - 1 \pm \sqrt{ {1}^{2} - 4 \times 2 \times 582 } }{2 \times 2} \\ \\ \tt: \implies x = \frac{ - 1 \pm \sqrt{1 + 4656} }{4} \\ \\ \tt: \implies x = \frac{ - 1 \pm \sqrt{4657} }{4} \\ \\ \tt: \implies x = \frac{ - 1 \pm68.2}{4} \\ \\ \tt: \implies x = \frac{67.2}{4} \\ \\ \green{\tt: \implies x = 16.8 \: m} \\ \\ \bold{Note-} \: \tt{ Length \: and \:Breadth \: cannot \: be \: in \: negative} \\ \\ \green{\tt \therefore Length = 1 + 2 \times 16.8 = 34.6 \: m} \\ \\ \green{\tt \therefore Breadth = x = 16.8 \: m}$

Discussion

11.	Solve 2x + y = 5 and 3x - 2y = 11 by substitution.
Answer» ANSWER: Step-by-step EXPLANATION: y=5-2x 3x-2(5-2x)=11 3x-10+4x=11 7x=11+10 7x=21 x=21/7=3 2(3)+y=5 6+y=5 y=5-6 y=-1 therefore, x=3, y=-1 ur WELCOME BABY

11.

Solve 2x + y = 5 and 3x - 2y = 11 by substitution.

Answer»

ANSWER:

Step-by-step EXPLANATION:

y=5-2x

3x-2(5-2x)=11

3x-10+4x=11

7x=11+10

7x=21

x=21/7=3

2(3)+y=5

6+y=5

y=5-6

y=-1

therefore, x=3, y=-1

ur WELCOME BABY

Discussion

12.	The multiplicative inverse of minus 8 /7
Answer» Answer: 7/8 Step-by-step EXPLANATION:

12.

The multiplicative inverse of minus 8 /7

Answer»

Answer:

7/8

Step-by-step EXPLANATION:

Discussion

13.	Find the sum of two consecutive square odd number
Answer» ANSWER: I HOPE it is CORRECT answer

13.

Find the sum of two consecutive square odd number

Answer»

ANSWER:

I HOPE it is CORRECT answer

Discussion

14.	ONE FOURTH OF A STRAIGHT ANGLE IS.
Answer» One fourth of a straight ANGLE is CALLED as acute angle

Discussion

15.	Find the product using suitable properties:- (-17)×(-29)
Answer» ANSWER: (-17)×(-29) =493 please MAKE me BRAINLEIST

15.

Find the product using suitable properties:- (-17)×(-29)

Answer»

ANSWER:

(-17)×(-29)

=493

please MAKE me BRAINLEIST

Discussion

16.	2x2 +x–4=0 By completeing the square
Answer» x=0 Step-by-step explanation: 2×2=4+x-4=0 4-4=0+x x=0

16.

2x2 +x–4=0 By completeing the square

Answer»

x=0

Step-by-step explanation:

2×2=4+x-4=0

4-4=0+x

x=0

Discussion

17.	1 2 3 = 475 9 9 = 1096 3 6 = 4329 25 4 = ?
Answer» Answer: 3one is the answer Step-by-step EXPLANATION: HOPE it HELPS PLZ FOLLOW me

17.

1 2 3 = 475 9 9 = 1096 3 6 = 4329 25 4 = ?

Answer»

Answer:

3one is the answer

Step-by-step EXPLANATION:

HOPE it HELPS PLZ FOLLOW me

Discussion

18.	Find the square of :3a/2b-2b/3a
Answer» ANSWER: {(3A + 4b)(3a-4b)}/6AB Step-by-step explanation: 3a/2B - 2b/3a =( 3a×3a-2b×2b)/2b×3a ={(3a)^2 - (2b)^2}/6ab =={(3a + 4b)(3a-4b)}/6ab

18.

Find the square of :3a/2b-2b/3a

Answer»

ANSWER:

{(3A + 4b)(3a-4b)}/6AB

Step-by-step explanation:

3a/2B - 2b/3a

=( 3a×3a-2b×2b)/2b×3a

={(3a)^2 - (2b)^2}/6ab

=={(3a + 4b)(3a-4b)}/6ab

Discussion

19.	If x=2 is a zero of p(x)=xsquare+2x+2k then what is the value of k
Answer» ANSWER: this is the answer. I HOPE it HELP you

19.

If x=2 is a zero of p(x)=xsquare+2x+2k then what is the value of k

Answer»

ANSWER:

this is the answer. I HOPE it HELP you

Discussion

20.	(cos+ cos y)2 + (sin x + sin y)2 = 4 cos^2x-y/2.
Answer» Answer: ("2cos (" (X + y)/2 ") Step-by-step explanation: (2) Using (1) & (2),we OBTAIN, (cosx+cosy) ^2+ (sinx+siny) ... =2+COS(x+y)+cos(x-y)+cos(x-y)-cos(x+y) . (D^2-4) y= e^x + sin2x + cos^2x?

20.

(cos+ cos y)2 + (sin x + sin y)2 = 4 cos^2x-y/2.

Answer»

Answer:

("2cos (" (X + y)/2 ")

Step-by-step explanation:

(2) Using (1) & (2),we OBTAIN, (cosx+cosy) ^2+ (sinx+siny) ... =2+COS(x+y)+cos(x-y)+cos(x-y)-cos(x+y) . (D^2-4) y= e^x + sin2x + cos^2x?

Discussion

21.	A hall is 13 meters 53 cm. long and 8 meters 61cm. broad is to be paved with minimum number of square tiles. the number of tiles required is?
Answer» Length of the hall = 13m 53cm = 13053m Width of the hall = 8m 61CM = 8061m Area of the hall = (13053×8061)m^2 = 105,220,233m^2 Let side be s ATP (s)^2 = 105,220,233 s = 10,257.6914 Area of the square TILES = (side)^2 = (10,257.6914×10,257.6914) = 105,220,233m^2 Number of tiles = 105,220,233/105,220,233 = 1 TILE

21.

A hall is 13 meters 53 cm. long and 8 meters 61cm. broad is to be paved with minimum number of square tiles. the number of tiles required is?

Answer»

Length of the hall = 13m 53cm = 13053m

Width of the hall = 8m 61CM = 8061m

Area of the hall = (13053×8061)m^2

= 105,220,233m^2

Let side be s

ATP

(s)^2 = 105,220,233

s = 10,257.6914

Area of the square TILES = (side)^2

= (10,257.6914×10,257.6914)

= 105,220,233m^2

Number of tiles

= 105,220,233/105,220,233

= 1 TILE

Discussion

22.	2/4x +1/3x=x_8.solve for x
Answer» ANSWER: PLEASE POST the QUESTION CORRECTLY

22.

2/4x +1/3x=x_8.solve for x

Answer»

ANSWER:

PLEASE POST the QUESTION CORRECTLY

Discussion

23.	एका आंधळ्या माणसाकडे एका डबीत औषधाच्या 4 गोळ्या आहेत 2 निळ्या आणि 2 लाल त्याला 1 निळी आणि 1 लाल गोळी घ्यायची आहेत जर कॉम्बिनेशन चुकले तर तो मरेल कोणाची मदत नं घेता तो गोळ्या कश्या घेणार
Answer» ANSWER: एका आंधळ्या माणसाकडे एका डबीत औषधाच्या 4 गोळ्या आहेत 2 निळ्या आणि 2 लाल त्याला 1 निळी आणि 1 लाल गोळी घ्यायची आहेत जर कॉम्बिनेशन चुकले तर तो मरेल कोणाची मदत नं घेता तो गोळ्या कश्या घेणार Step-by-step EXPLANATION:

23.

एका आंधळ्या माणसाकडे एका डबीत औषधाच्या 4 गोळ्या आहेत 2 निळ्या आणि 2 लाल त्याला 1 निळी आणि 1 लाल गोळी घ्यायची आहेत जर कॉम्बिनेशन चुकले तर तो मरेल कोणाची मदत नं घेता तो गोळ्या कश्या घेणार

Answer»

ANSWER:

एका आंधळ्या माणसाकडे एका डबीत औषधाच्या 4 गोळ्या आहेत 2 निळ्या आणि 2 लाल त्याला 1 निळी आणि 1 लाल गोळी घ्यायची आहेत जर कॉम्बिनेशन चुकले तर तो मरेल कोणाची मदत नं घेता तो गोळ्या कश्या घेणार

Step-by-step EXPLANATION:

Discussion

24.	How many number lie between 205 and 206
Answer» ANSWER: There is no any no. between 205 and 206

24.

How many number lie between 205 and 206

Answer»

ANSWER:

There is no any no. between 205 and 206

Discussion

25.	2=6,3=12,4=20,5=30,6=42,9=
Answer» Step-by-step explanation: 2=6 This only OCCURS when 2×3 3=12 This only occurs when 3×4 4=20 This only occurs when 4×5 5=30 This only occurs when 5×6 6=42 This only occurs when 6×7 Hence, 7=56 This only occurs when 7×8 By FOLLOWING the above PATTERN 8=72 This only occurs when 8×9 By following the above pattern 9=90 This only occurs when 9×10 By following the above pattern THANK You.

25.

2=6,3=12,4=20,5=30,6=42,9=

Answer»

Step-by-step explanation:

2=6

This only OCCURS when 2×3

3=12

This only occurs when 3×4

4=20

This only occurs when 4×5

5=30

This only occurs when 5×6

6=42

This only occurs when 6×7

Hence,

7=56

This only occurs when 7×8

By FOLLOWING the above PATTERN

8=72

This only occurs when 8×9

By following the above pattern

9=90

This only occurs when 9×10

By following the above pattern

THANK You.

Discussion

26.	Rationalize the denominator of 1 upon 7 + 3 root 2
Answer» ANSWER: Step-by-step explanation: 1/7+3√2 (1)(7-3√2) / (7+3√2)(7-3√2) 7-3√2 / (7∧2)-[(3√2)∧2] 7-3√2 / 49-18 7-3√2 /31

26.

Rationalize the denominator of 1 upon 7 + 3 root 2

Answer»

ANSWER:

Step-by-step explanation:

1/7+3√2

(1)(7-3√2) / (7+3√2)(7-3√2)

7-3√2 / (7∧2)-[(3√2)∧2]

7-3√2 / 49-18

7-3√2 /31

Discussion

27.	A School collected 2601 rupees as fee from it's students.if fee paid by Each student and number ofStudents in school were equal. How manyStudents were there in school?
Answer» underroot2601........

Discussion

28.	Insert root 5 on number line
Answer» ROOT 5 on NUMBER LINE SEE above

Discussion

29.	difference in lenth and breadth of a rectangle is 8 and its area is 468.represent this with a quadratic equation
Answer» ANSWER: Look at the explanation Step-by-step explanation: LET length=l breadth = b 1st CASE: l-b=8 (1) 2ND case: lxb=468. (l-b) + (lxb) = 468-+8

29.

difference in lenth and breadth of a rectangle is 8 and its area is 468.represent this with a quadratic equation

Answer»

ANSWER:

Look at the explanation

Step-by-step explanation:

LET length=l

breadth = b

1st CASE: l-b=8 (1)

2ND case: lxb=468.

(l-b) + (lxb) = 468-+8

Discussion

30.	8,2347,192 number name in International system of Numerationt
Answer» Answer: 82,347,192 this is the INTERNATIONAL system please FOLLOW me

30.

8,2347,192 number name in International system of Numerationt

Answer»

Answer:

82,347,192

this is the INTERNATIONAL system

please FOLLOW me

Discussion

31.	How to do power questions?
Answer» ANSWER: Some basic formulas used to solve QUESTIONS on (a^m)^N = (an)^m = a.^mn a^m.a^n = a.^m+n a-^m = 1/a.^m a^m/a^n = a^m-^n = 1/a. ^n-m (ab)^n = a^nb.^n (a/b)^n = a^n/b.^n a^0 = 1.

31.

How to do power questions?

Answer»

ANSWER:

Some basic formulas used to solve QUESTIONS on

(a^m)^N = (an)^m = a.^mn
a^m.a^n = a.^m+n
a-^m = 1/a.^m
a^m/a^n = a^m-^n = 1/a. ^n-m
(ab)^n = a^nb.^n
(a/b)^n = a^n/b.^n
a^0 = 1.

Discussion

32.	Q. Name thon guadrilateral
Answer» ANSWER: FIRST QUESTION properly Step-by-step EXPLANATION:

32.

Q. Name thon guadrilateral

Answer»

ANSWER:

FIRST QUESTION properly

Step-by-step EXPLANATION:

Discussion

33.	(a) 9 comes before(b) 189 comes before(c) 15 comes after
Answer» ANSWER: These are the ANSWERS fir your QUESTIONS (a) 10 (b) 190 (C) 16

33.

(a) 9 comes before(b) 189 comes before(c) 15 comes after

Answer»

ANSWER:

These are the ANSWERS fir your QUESTIONS

(a) 10

(b) 190

(C) 16

Discussion

34.	Please divide 140 ÷1.2756
Answer» ANSWER: 141.12 Step-by-step explanation: 1 4 0 1.2756 1 4 0 × 10000 12756 by DIVIDING above 10000 70.86 10000 × 100 7086 by dividing above 10000 × 50 3543 500000 3543 141.12 ANSWER

34.

Please divide 140 ÷1.2756

Answer»

ANSWER:

141.12

Step-by-step explanation:

1 4 0

1.2756

1 4 0 × 10000

12756

by DIVIDING above

10000

70.86

10000 × 100

7086

by dividing above

10000 × 50

3543

500000

3543

141.12 ANSWER

Discussion

35.	B^2 - a^2 + 2bc + c ^2
Answer» ANSWER: 2bc-a2+b2+c2 Step-by-step EXPLANATION: The answer in just the same but it should be arranged in a perfect ORDER by increasing POWER order

35.

B^2 - a^2 + 2bc + c ^2

Answer»

ANSWER:

2bc-a2+b2+c2

Step-by-step EXPLANATION:

The answer in just the same but it should be arranged in a perfect ORDER by increasing POWER order

Discussion

36.	Verify euler's theorem for function Z=e^x/y
Answer» ANSWER: PLEASE please please please please please please please please please please please please please please please please MARK as BRAINLEIST

36.

Verify euler's theorem for function Z=e^x/y

Answer»

ANSWER:

PLEASE please please please please please please please please please please please please please please please please MARK as BRAINLEIST

Discussion

37.	Please answer this this is very imporatnt
Answer» ANSWER:One POINT two eight FOUR

37.

Please answer this this is very imporatnt

Answer»

ANSWER:One POINT two eight FOUR

Discussion

38.	A factory produces electric bulbs if one out of every 10 bulbs is defective and the factory produced 6:30 bulbs per day find the number of defective bulbs produced each day.plz answer in detail .
Answer» Correct QUESTION A factory produces electric bulbs if ONE out of every 10 bulbs is defective and the factory produced 630 bulbs per day. Find the number of defective bulbs produced each day. Solution Let the number of defective bulbs produced per day be x. Number of defective bulbs out of 10 bulbs is 1. Total number of bulbs produced by factory = 630 Now, The ratio of number of defective bulbs to the total number of bulbs = 1/10 Similarly, The ratio of the assumed number of defective bulbs to the total number of bulbs produces every day = x/630 According to question, ⇒ 1/10 = x/630 Cross-multiply them ⇒ x(10) = 1(630) ⇒ 10x = 630 ⇒ x = 630/10 ⇒ x = 63 Therefore, 63 defective bulbs produced each day.

38.

A factory produces electric bulbs if one out of every 10 bulbs is defective and the factory produced 6:30 bulbs per day find the number of defective bulbs produced each day.plz answer in detail .

Answer»

Correct QUESTION

A factory produces electric bulbs if ONE out of every 10 bulbs is defective and the factory produced 630 bulbs per day. Find the number of defective bulbs produced each day.

Solution

Let the number of defective bulbs produced per day be x.

Number of defective bulbs out of 10 bulbs is 1.

Total number of bulbs produced by factory = 630

Now,

The ratio of number of defective bulbs to the total number of bulbs = 1/10

Similarly,

The ratio of the assumed number of defective bulbs to the total number of bulbs produces every day = x/630

According to question,

⇒ 1/10 = x/630

Cross-multiply them

⇒ x(10) = 1(630)

⇒ 10x = 630

⇒ x = 630/10

⇒ x = 63

Therefore,

63 defective bulbs produced each day.

Discussion

39.	In the rectnagle PQRS shown below if angle PSM = 70 degree then find ANgle QRM , angle PMQ and angle MRS
Answer» $\huge{\bf{\underline{\red{Solution :}}}}$ ⇒We KNOW that the diagonals of a rectangle bisect each other and both diagonal are equal in length . In ΔSPM , MS = MP $\implies \bold{ \angle PSM = \angle SPM = 70^{\circ}}$ Therefore , $\implies \bold{\angle PMS = 180^{\circ} - ( \angle PSM + \angle SPM)}$ $\implies \bold{ \angle PMS = 180^{\circ} - (70^{\circ} + 70^{\circ})}$ $\implies \bold{\angle PMS = 180^{\circ} - 140^{\circ}}$ $\implies \bold{\angle PMS = 40^{\circ}}$ Now ∠PMQ and ∠PMS from a linear pair :- $\implies \bold{\angle PMQ = 180^{\circ} - 40^{\circ}}$ $\implies \boxed{\bold{\angle PMQ = 140^{\circ}}}$ $\implies \bold{\angle PSR = \angle PSM + \angle MSR}$ $\implies \bold{90^{\circ} = 70^{\circ} + \angle MSR}$ $\implies \bold{\angle MSR = 90^{\circ} - 70^{\circ}}$ $\implies \bold{\angle MSR = 20^{\circ}}$ In ΔMSR , MS = MR $\implies \bold{\angle MSR = \angle MRS}$ $\implies \boxed{\bold{\angle MRS = 20^{\circ}}}$ Now FIND ∠QRM :- $\implies \bold{\angle QRS = \angle QRM + \angle MRS}}$ $\implies \bold{90^{\circ} = \angle QRM + \angle 20^{\circ}}$ $\implies \boxed{\bold{\angle QRM = 70^{\circ}}}$ $\rule{200}2$

39.

In the rectnagle PQRS shown below if angle PSM = 70 degree then find ANgle QRM , angle PMQ and angle MRS

Answer»

$\huge{\bf{\underline{\red{Solution :}}}}$

⇒We KNOW that the diagonals of a rectangle bisect each other and both diagonal are equal in length .

In ΔSPM , MS = MP

$\implies \bold{ \angle PSM = \angle SPM = 70^{\circ}}$

Therefore ,

$\implies \bold{\angle PMS = 180^{\circ} - ( \angle PSM + \angle SPM)}$

$\implies \bold{ \angle PMS = 180^{\circ} - (70^{\circ} + 70^{\circ})}$

$\implies \bold{\angle PMS = 180^{\circ} - 140^{\circ}}$

$\implies \bold{\angle PMS = 40^{\circ}}$

Now ∠PMQ and ∠PMS from a linear pair :-

$\implies \bold{\angle PMQ = 180^{\circ} - 40^{\circ}}$

$\implies \boxed{\bold{\angle PMQ = 140^{\circ}}}$

$\implies \bold{\angle PSR = \angle PSM + \angle MSR}$

$\implies \bold{90^{\circ} = 70^{\circ} + \angle MSR}$

$\implies \bold{\angle MSR = 90^{\circ} - 70^{\circ}}$

$\implies \bold{\angle MSR = 20^{\circ}}$

In ΔMSR , MS = MR

$\implies \bold{\angle MSR = \angle MRS}$

$\implies \boxed{\bold{\angle MRS = 20^{\circ}}}$

Now FIND ∠QRM :-

$\implies \bold{\angle QRS = \angle QRM + \angle MRS}}$

$\implies \bold{90^{\circ} = \angle QRM + \angle 20^{\circ}}$

$\implies \boxed{\bold{\angle QRM = 70^{\circ}}}$

$\rule{200}2$

Discussion

40.	Simply ansswer get 20 points
Answer» LCM is 180. 162/180,80/180,99/180 Greater NUMBER is 18/20 HOPE THIS MAY HELP..

40.

Simply ansswer get 20 points

Answer»

LCM is 180.

162/180,80/180,99/180

Greater NUMBER is 18/20

HOPE THIS MAY HELP..

Discussion

41.	6. The sum of the digits of a two-digit number is 11. If we interchangethe digits then the new number formed is 45 less than the original. Findthe original number.
Answer» AnswEr:- Two digit number = 83 $\rule{250}{1}$ Let the digit at UNIT's place be m & digit at ten's place be n ⇒ ORIGINAL number = m + 10n Case 1:- ⇒ m + n = 11 [Eq.1] Case 2:- ★ Interchanged number :- ⇒ New number = n + 10m According to question:- ⇒ Original number - New number = 45 ⇒ m + 10n - (n + 10m) = 45 ⇒ m + 10n - n - 10m = 45 ⇒ 9n - 9m = 45 ⇒ 9(n - m) = 45 ⇒ n - m = 45/9 ⇒ n - m = 5 [Eq.2] Now ADDING both equations:- $\qquad\sf{n \: + \: \cancel{m} = 11}$ $\qquad\sf{n \: - \: \cancel{m} = 5}$ $\quad\sf{\: (+) \: \: (-) \: \: (+)}$ $\: \: \rule{100}{1}$ $\qquad\sf{\: 2n = \:\: 16}$ $\twoheadrightarrow\sf {\: \: \: \: \: n = 16/2}$ $\twoheadrightarrow\sf{\: \: \: \: \: n =\large {\boxed{\sf\green{<klux>8</klux>}}}}$ So, digit at ten's place = 8 Put this value in (Eq.2) ⇒ 8 - m = 5 ⇒ m = 8 - 5 ⇒ m = 3 So, digit at unit's place = 3 Now number:- ⇒ Original number = 3 + 10(8) ⇒ Original number = 3 + 80 ⇒ Original number = 83 Therefore, $\therefore{\underline{\boxed{\textsf{Original number = {\textbf{83 }}}}}}$

41.

6. The sum of the digits of a two-digit number is 11. If we interchangethe digits then the new number formed is 45 less than the original. Findthe original number.

Answer»

AnswEr:-

Two digit number = 83

$\rule{250}{1}$

Let the digit at UNIT's place be m & digit at ten's place be n

⇒ ORIGINAL number = m + 10n

Case 1:-

⇒ m + n = 11 [Eq.1]

Case 2:-

★ Interchanged number :-

⇒ New number = n + 10m

According to question:-

⇒ Original number - New number = 45

⇒ m + 10n - (n + 10m) = 45

⇒ m + 10n - n - 10m = 45

⇒ 9n - 9m = 45

⇒ 9(n - m) = 45

⇒ n - m = 45/9

⇒ n - m = 5 [Eq.2]

Now ADDING both equations:-

$\qquad\sf{n \: + \: \cancel{m} = 11}$

$\qquad\sf{n \: - \: \cancel{m} = 5}$

$\quad\sf{\: (+) \: \: (-) \: \: (+)}$

$\: \: \rule{100}{1}$

$\qquad\sf{\: 2n = \:\: 16}$

$\twoheadrightarrow\sf {\: \: \: \: \: n = 16/2}$

$\twoheadrightarrow\sf{\: \: \: \: \: n =\large {\boxed{\sf\green{<klux>8</klux>}}}}$

So, digit at ten's place = 8

Put this value in (Eq.2)

⇒ 8 - m = 5

⇒ m = 8 - 5

⇒ m = 3

So, digit at unit's place = 3

Now number:-

⇒ Original number = 3 + 10(8)

⇒ Original number = 3 + 80

⇒ Original number = 83

Therefore,

$\therefore{\underline{\boxed{\textsf{Original number = {\textbf{83 }}}}}}$

Discussion

42.	The 7th term of an A.P. whose 1st term is 6 and common difference is -1 is .........
Answer» Answer: CLEARLY a=6 d=-1 then A7 = a(n-1)d = 6(7-1)(-1) =6×-6 =-36

42.

The 7th term of an A.P. whose 1st term is 6 and common difference is -1 is .........

Answer»

Answer:

CLEARLY

a=6

d=-1

then A7 = a(n-1)d

= 6(7-1)(-1)

=6×-6

=-36

Discussion

43.	On subtracting 6 from five times x gives 4
Answer» Answer: *5x-6=4* is the CORRECT answer. *HOPE IT HELPS YOU...........*

43.

On subtracting 6 from five times x gives 4

Answer»

Answer:

5x-6=4 is the CORRECT answer.

HOPE IT HELPS YOU...........

Discussion

44.	Cosπ/7+cos 2π/7+cos3π/7+cos 4π/7+cos5π/7+ cos6π/7=
Answer» Answer: 0 Step-by-step explanation: 0

44.

Cosπ/7+cos 2π/7+cos3π/7+cos 4π/7+cos5π/7+ cos6π/7=

Answer»

Answer:

0

Step-by-step explanation:

0

Discussion

45.	Set builder for B={1,4,9,16,25}
Answer» Answer: A=(1,4,9,16,25,....) A=(1sq,2sq,3sq,4sq,5sq,.....) Here, 1,2,3,4,5 are all NATURAL numbers and 1,4,9,16,25 are their square hence, we MAY write the set A as A=(x:x is the square of a natural numbers) (or) A=(x;x=n SQ, where n € N

45.

Set builder for B={1,4,9,16,25}

Answer»

Answer:

A=(1,4,9,16,25,....)

A=(1sq,2sq,3sq,4sq,5sq,.....)

Here,

1,2,3,4,5 are all NATURAL numbers

and 1,4,9,16,25 are their square

hence, we MAY write the set A as

A=(x:x is the square of a natural numbers)

(or)

A=(x;x=n SQ, where n € N

Discussion

46.	0.57 in the form of p/q form
Answer» ANSWER: 57/100 is the REQUIRED answer

46.

0.57 in the form of p/q form

Answer»

ANSWER:

57/100 is the REQUIRED answer

Discussion

47.	The three angles of a triangleare in the ratio 2:3:5 . Findthe measure of each angle classify.the triangle (36, 54,90). (rightengled triangled).
Answer» RATIO of TRIANGLES 2:3:5 let the ratio be X 2x,3x,5x EQUATION 1 sum of all angles =180° 2x+3x+5x=180° 10x=180 x=180/10 x=18 put value of x in equation 1 2x=2×18= 36° 3x=3×18=54° 4x=5×18=90° so measure of all angles are 36°,54°,90°

47.

The three angles of a triangleare in the ratio 2:3:5 . Findthe measure of each angle classify.the triangle (36, 54,90). (rightengled triangled).

Answer»

RATIO of TRIANGLES 2:3:5

let the ratio be X

2x,3x,5x EQUATION 1

sum of all angles =180°

2x+3x+5x=180°

10x=180

x=180/10

x=18

put value of x in equation 1

2x=2×18= 36°

3x=3×18=54°

4x=5×18=90°

so measure of all angles are 36°,54°,90°

Discussion

48.	A+b+c=12a^2 +b^2+ c^2 = 70ab+bc+ca= 37Find value a, b and c?
Answer» Given : a² + b² + c² = 70, a + b + C = 12, ab + bc + ca = 37 To find : a, b and c Solution: (a + b + c)² = a² + b² + c² + 2(ab + bc + ca) => 12² = 70 + 2(37) => 144 = 70 + 74 => 144 = 144 Hence 3rd Equation can be found if 2 Equations are given Hence these 3 Equations are basically 2 Equations and 3 Variable a , b & c We can not solve 3 variables with 2 Equations There can be MANY possible solutions few are below : a = √37 i b = -√37 i c = 12 a = -√37 i b = √37 i c = 12 c= √37 i b = -√37 i a = 12 c = -√37 i b = √37 i a = 12 a = √37 i c = -√37 i b = 12 a = -√37 i c = √37 i b = 12 Verification a² + b² + c² = -37 - 37 + 144 = 70 (i² = -1) a + b + c = √37 i -√37 i + 12 = 12 ab + bc + ca = (√37 i) * (-√37 i) + (√37 i) 12 + (-√37 i) 12 = 37 Not Enough Details to find Unique Solutions we can choose any value then find others let SAY a = 0 => b + c = 12 bc = 37 => x² - 12x + 37 = 0 => b & c = ( 12 ± √144 - 4 * 37 ) / 2 = 6 ± i a = 0 , b = 6 + i , c = 6 - i a + b + c = 12 a² + b² + c² = 0 + 36 - 1 + 12i + 36 - 1 - 12i = 72 ab + bc + ca = (6 + i)(6 - i) = 36 - i² = 36 -(-1) = 37 Hence if we assume one value we can get others a = 1 => b + c = 11 & bc = 26 x² - 11x + 26 = 0 b & c = (11 ± √17)/2 a = 2 => b + c = 10 & bc = 17 x² - 10x + 17 = 0 b & c = (10 ± √32)/2 = 5 ± 2√2 and so on limit less solution Learn more: if x+y+z=0 then the square of the value of (x+y)^2/xy+(y+z)^2/yz+(z+x) brainly.in/question/12858114 Find x,y,z using cramers rule, if x-y+z=4, 2x+y-3z=0 and x+y+z=2 brainly.in/question/9052437 brainly.in/question/16359658

48.

A+b+c=12a^2 +b^2+ c^2 = 70ab+bc+ca= 37Find value a, b and c?

Answer»

Given : a² + b² + c² = 70, a + b + C = 12, ab + bc + ca = 37

To find : a, b and c

Solution:

(a + b + c)² = a² + b² + c² + 2(ab + bc + ca)

=> 12² = 70 + 2(37)

=> 144 = 70 + 74

=> 144 = 144

Hence 3rd Equation can be found if 2 Equations are given

Hence these 3 Equations are basically 2 Equations

and 3 Variable a , b & c

We can not solve 3 variables with 2 Equations

There can be MANY possible solutions

few are below :

a = √37 i b = -√37 i c = 12

a = -√37 i b = √37 i c = 12

c= √37 i b = -√37 i a = 12

c = -√37 i b = √37 i a = 12

a = √37 i c = -√37 i b = 12

a = -√37 i c = √37 i b = 12

Verification

a² + b² + c² = -37 - 37 + 144 = 70 (i² = -1)

a + b + c = √37 i -√37 i + 12 = 12

ab + bc + ca = (√37 i) * (-√37 i) + (√37 i) 12 + (-√37 i) 12 = 37

Not Enough Details to find Unique Solutions

we can choose any value then find others

let SAY a = 0

=> b + c = 12 bc = 37

=> x² - 12x + 37 = 0

=> b & c = ( 12 ± √144 - 4 * 37 ) / 2 = 6 ± i

a = 0 , b = 6 + i , c = 6 - i

a + b + c = 12

a² + b² + c² = 0 + 36 - 1 + 12i + 36 - 1 - 12i = 72

ab + bc + ca = (6 + i)(6 - i) = 36 - i² = 36 -(-1) = 37

Hence if we assume one value we can get others

a = 1 => b + c = 11 & bc = 26

x² - 11x + 26 = 0

b & c = (11 ± √17)/2

a = 2 => b + c = 10 & bc = 17

x² - 10x + 17 = 0

b & c = (10 ± √32)/2 = 5 ± 2√2

and so on limit less solution

Learn more:

if x+y+z=0 then the square of the value of (x+y)^2/xy+(y+z)^2/yz+(z+x)

brainly.in/question/12858114

Find x,y,z using cramers rule, if x-y+z=4, 2x+y-3z=0 and x+y+z=2

brainly.in/question/9052437

brainly.in/question/16359658

Discussion

49.	_×_×_is 156 the numbers consists of 1to 9
Answer» SORRY BROTHER I don't KNOW the ANSWER

Discussion

50.	in a cricket match,Gaurav faces 30 balls. he hits 8 fours, 5 sixes and remaining singles in his score of 70 runs.Find probability that on playing next ball,Gaurav will (1)hit a sixer (2) make a single run (3) not be able to score
Answer» ANSWER: 1/6 4/15 3/10 Step-by-step explanation: SCORE by fours= 84= 32 score by SIXES= 56= 30 score by singles= 70-30-32=8 no of dots = 30-8-5-8=9 probability of six=5/30=1/6 probability of single=8/30=4/15 probability of DOT = 9/30=3/10 Hope this HELPS you Mark as Brainliest answer please

50.

in a cricket match,Gaurav faces 30 balls. he hits 8 fours, 5 sixes and remaining singles in his score of 70 runs.Find probability that on playing next ball,Gaurav will (1)hit a sixer (2) make a single run (3) not be able to score

Answer»

ANSWER:

1/6

4/15

3/10

Step-by-step explanation:

SCORE by fours= 8*4= 32

score by SIXES= 5*6= 30

score by singles= 70-30-32=8

no of dots = 30-8-5-8=9

probability of six=5/30=1/6

probability of single=8/30=4/15

probability of DOT = 9/30=3/10

Hope this HELPS you

Mark as Brainliest answer please

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Simply ansswer get 20 points ​

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AnswEr:-

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