332354 + Interview Questions in Secondary School in Math

1.	(_१)५ मान ज्ञात करो
Answer» ANSWER: -15=-5 Step-by-step EXPLANATION:* (-1)5 (-1)*5=-5

1.

(_१)५ मान ज्ञात करो

Answer»

ANSWER:

-1*5=-5

Step-by-step EXPLANATION:

(-1)5

(-1)*5=-5

Discussion

2.	-1 Write the decimal part in 30.65.
Answer» Answer: 0.65 is your answer. it can ALSO be WRITTEN as 65/100 or 13/20

2.

-1 Write the decimal part in 30.65.

Answer»

Answer:

0.65 is your answer.

it can ALSO be WRITTEN as 65/100 or 13/20

Discussion

3.	7. Find curved surface area of cone having radius 7cm and slant height 26 cm
Answer» ANSWER: CSA of cone = πrl = 3.175 X 7 X 26 = 577.85 CM

3.

7. Find curved surface area of cone having radius 7cm and slant height 26 cm

Answer»

ANSWER:

CSA of cone = πrl

= 3.175 X 7 X 26

= 577.85 CM

Discussion

4.	Find the square of (4a-5).
Answer» ANSWER: the answer is 1.9a is the answer

4.

Find the square of (4a-5).

Answer»

ANSWER:

the answer is 1.9a is the answer

Discussion

5.	.If Angle A=Angle P, AB=PQ and Angle B =Angle Q then triangle ABC and triangle PQR by which criteria
Answer» ANSWER: A-S-A please MARK me as a BRAINLIEST......

5.

.If Angle A=Angle P, AB=PQ and Angle B =Angle Q then triangle ABC and triangle PQR by which criteria

Answer»

ANSWER:

A-S-A

please MARK me as a BRAINLIEST......

Discussion

6.	Plz tell this plz questionsfind 3 1/2 ÷ 1 2/3
Answer» Answer: 3 1/2 DIVIDED by 1 2/3 Convert mixed fraction into improper fraction =6/2 + 6/3 Do L. C. M for 2&3 =18+12/6 =30/6 =5

6.

Plz tell this plz questionsfind 3 1/2 ÷ 1 2/3

Answer»

Answer:

3 1/2 DIVIDED by 1 2/3

Convert mixed fraction into improper fraction

=6/2 + 6/3

Do L. C. M for 2&3

=18+12/6

=30/6

=5

Discussion

7.	The perpendicular distance of the point (3, 6) from x-axis is 6.
Answer» Answer: The ⊥ DISTANCE from x- axis to the point(-3,-6) is 6 units

Discussion

8.	A396543 169é 19604e square root by prime factorization.6276 676 k. 396 900116.6490.25*0.00090.0144
Answer» ANSWER: ↑10 THANX =30 thanx + FOLLOW+ inbox↓ ↓till JANUARY 2021↓ Step-by-step explanation:

8.

A396543 169é 19604e square root by prime factorization.6276 676 k. 396 900116.6490.25*0.00090.0144

Answer»

ANSWER:

↑10 THANX =30 thanx + FOLLOW+ inbox↓

↓till JANUARY 2021↓

Step-by-step explanation:

Discussion

9.	Point whose abscissa and ordinate are -2 and +3 lies in _______quadrant
Answer» Answer: 2nd QUADRANT . In this Quadrant, POINT LIES. HOPE it HELPS you

9.

Point whose abscissa and ordinate are -2 and +3 lies in _______quadrant

Answer»

Answer:

2nd QUADRANT .

In this Quadrant, POINT LIES.

HOPE it HELPS you

Discussion

10.	Evalute the followingplease give me my answerI will mark as brainlesst answer
Answer» ANSWER: this is my answer PLZZ MARK me BRAINLIST PLZ plz plz

10.

Evalute the followingplease give me my answerI will mark as brainlesst answer

Answer»

ANSWER:

this is my answer

PLZZ MARK me BRAINLIST PLZ plz plz

Discussion

11.	ip tp and tq are tangent drawm from con external point t with the circle centre o if tp=4cm,op=3cm,find ot
Answer» Answer: As op is PERPENDICULAR to tp. So TRIANGLE OPT is RIGHT angke triangle. Using PYTHAGORAS theorem ${ot}^{2} = {op}^{2} + {tp}^{2} \\ = {3}^{2} + {4}^{2} \\ = 9 + 16 \\ = 25 \\ = {5}^{2} \\ = > ot = 5 \: cm$

11.

ip tp and tq are tangent drawm from con external point t with the circle centre o if tp=4cm,op=3cm,find ot

Answer»

Answer:

As op is PERPENDICULAR to tp.

So TRIANGLE OPT is RIGHT angke triangle.

Using PYTHAGORAS theorem

${ot}^{2} = {op}^{2} + {tp}^{2} \\ = {3}^{2} + {4}^{2} \\ = 9 + 16 \\ = 25 \\ = {5}^{2} \\ = > ot = 5 \: cm$

Discussion

12.	What is sunset......
Answer» ANSWER: The TIME when the SUN GOES down in the EVENING...

12.

What is sunset......

Answer»

ANSWER:

The TIME when the SUN GOES down in the EVENING...

Discussion

13.	Write the 435.023 in expanded from
Answer» Answer: 400 + 30 + 5 . 0 + 2 + 3 100 1000 Step-by-step explanation: PLACE value of 4 = 4 × 100 = 400 Place value of 3 = 3 × 10 = 30 Place value of 5 = 5 × 1 = 5 Place value of 0 = 0 × 1 = 0 10 Place value of 2 = 2 × 1 = 2 = 0.05 100 100 Place value of 3 = 3 × 1 = 3 = 0.004 1000 1000

13.

Write the 435.023 in expanded from

Answer»

Answer:

400 + 30 + 5 . 0 + 2 + 3

100 1000

Step-by-step explanation:

PLACE value of 4 = 4 × 100 = 400

Place value of 3 = 3 × 10 = 30

Place value of 5 = 5 × 1 = 5

Place value of 0 = 0 × 1 = 0

10

Place value of 2 = 2 × 1 = 2 = 0.05

100 100

Place value of 3 = 3 × 1 = 3 = 0.004

1000 1000

Discussion

14.	Δ ABC and Δ DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC. If AD is extended to intersect BC at P, show that; i) Δ ABD ≅ Δ ACD ii) Δ ABP ≅ Δ ACP iii) AP is the perpendicular bisector of BC
Answer» ANSWER: sahooooooooooooooooooooooooooooooooooo

14.

Δ ABC and Δ DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC. If AD is extended to intersect BC at P, show that; i) Δ ABD ≅ Δ ACD ii) Δ ABP ≅ Δ ACP iii) AP is the perpendicular bisector of BC

Answer»

ANSWER:

sahooooooooooooooooooooooooooooooooooo

Discussion

15.	Find the value of (2xy+5y)² by using the identity (a+b)²
Answer» Answer: USING identity - ( a + b) 2 = a sq. + b sq. + 2ab solution = here a = 2xy , b = 5Y = ( 2xy) sq. + (5y) sq. + 2 × 2xy ×5y 4XY sq. + 25 y 2 + 20 x y*2

15.

Find the value of (2xy+5y)² by using the identity (a+b)²

Answer»

Answer:

USING identity - ( a + b) *2 = a sq. + b sq. + 2ab

solution = here a = 2xy , b = 5Y

= ( 2xy) sq. + (5y) sq. + 2 × 2xy ×5y

4XY sq. + 25 y *2 + 20 x y*2

Discussion

16.	Is 78.0.5 Which term of the AP 3,8,13,18 .OrCheck whether-150 is term of AP 11.8.5.22.........Q.6 Find the zero's: 4x2-3x-1Or3x2+4x40.7 Solve 8x + 5y = 9,3x + 2y = 4 by substitution method.OrSolvex + y = 5, 2x - 3y 4 by elimination method.0.8 Solve 2x - 3* - 5 by formula method.OrSolve X-2.9 Solve ! + 1 and x-3OrSolvey 2x + 3y = 0, 3x - Voy = 0,2.10 Find the 31" term of an AP whose 11 term is 38 and the 16"term isOr
Answer» ANSWER: the QUESTIONS are very DIFFERENT

16.

Is 78.0.5 Which term of the AP 3,8,13,18 .OrCheck whether-150 is term of AP 11.8.5.22.........Q.6 Find the zero's: 4x2-3x-1Or3x2+4x40.7 Solve 8x + 5y = 9,3x + 2y = 4 by substitution method.OrSolvex + y = 5, 2x - 3y 4 by elimination method.0.8 Solve 2x - 3* - 5 by formula method.OrSolve X-2.9 Solve ! + 1 and x-3OrSolvey 2x + 3y = 0, 3x - Voy = 0,2.10 Find the 31" term of an AP whose 11 term is 38 and the 16"term isOr

Answer»

ANSWER:

the QUESTIONS are very DIFFERENT

Discussion

17.	AABCD ésand sidesquarCDA line BHBM entersecte diagonal AC at oif LA013 - TO then find LOMD
Answer» ANSWER: *through* a *CONSTANT* *rate then* *we SAY it* *had* *uniform acceleration* *trap* on *the* *mom* *and* *2nd* *the* *mom* *and* *nom angry but so still have* *to play FAST bowling in over* *the* *4km* *and* *nom* *angry* *but* so *still have to play fast bowling* in *over cover the human eye on* *the mom and nom angry but* so *far more SUCCESSFUL in the mom* *and* *nom angry but so still have* *to play fast bowling in over* *cover* *the human eye on the mom* *and* *nom angry but so still have* *to play fast bowling in over* *cover*

17.

AABCD ésand sidesquarCDA line BHBM entersecte diagonal AC at oif LA013 - TO then find LOMD

Answer»

ANSWER:

through a CONSTANT rate then we SAY it had uniform acceleration trap on the mom and 2nd the mom and nom angry but so still have to play FAST bowling in over the 4km and nom angry but so still have to play fast bowling in over cover the human eye on the mom and nom angry but so far more SUCCESSFUL in the mom and nom angry but so still have to play fast bowling in over cover the human eye on the mom and nom angry but so still have to play fast bowling in over cover

Discussion

18.	Simplify Tan ( pi/4+a) Tan(pi/4-a)
Answer» Answer: Valida r ur done it do you want to be your friend pritisruti I am a GIRL join US for a while AGO and I don't know how to CLIMB the steps to be y you and mother and I don't know

18.

Simplify Tan ( pi/4+a) Tan(pi/4-a)

Answer»

Answer:

Valida r ur done it do you want to be your friend pritisruti I am a GIRL join US for a while AGO and I don't know how to CLIMB the steps to be y you and mother and I don't know

Discussion

19.	The sum of three consecutive odd number is 21. Find the middle number.A. 11B. 5C. 9 D. 7
Answer» ANSWER: ANS is 7 REFER the ATTACHMENT .................

19.

The sum of three consecutive odd number is 21. Find the middle number.A. 11B. 5C. 9 D. 7

Answer»

ANSWER:

ANS is 7

REFER the ATTACHMENT

.................

Discussion

20.	In the figure AB = 12 cm BC = 7 cm CD = 8 cm, AD = 10 cm, find [3]i. The length of AE ii. The length of CFiii. The length of EF
Answer» ANSWER: In the given figure, let CE=CF=x It is also given that AB=12 cm, BC=8 cm and AC=10 cm, therefore, AF=AD=10−x BE=BD=8−x Now consider, AB=AD+BD ⇒12=10−x+8−x ⇒12=18−2x ⇒2x=18−12 ⇒2x=6 ⇒x= 2 6 =3 Therefore, CE=x=3 cm, AF=10−3=7 cm and BD=8−3=5 cm Hence, CE=3 cm, AF=7 cm and BD=5 cm. Step-by-step EXPLANATION: Do FOLLOW please

20.

In the figure AB = 12 cm BC = 7 cm CD = 8 cm, AD = 10 cm, find [3]i. The length of AE ii. The length of CFiii. The length of EF

Answer»

ANSWER:

In the given figure, let CE=CF=x

It is also given that AB=12 cm, BC=8 cm and AC=10 cm, therefore,

AF=AD=10−x

BE=BD=8−x

Now consider,

AB=AD+BD

⇒12=10−x+8−x

⇒12=18−2x

⇒2x=18−12

⇒2x=6

⇒x=

2

6

=3

Therefore, CE=x=3 cm, AF=10−3=7 cm and BD=8−3=5 cm

Hence, CE=3 cm, AF=7 cm and BD=5 cm.

Step-by-step EXPLANATION:

Do FOLLOW please

Discussion

21.	Find the area area of parallelogram
Answer» Answer: A = B * H where B is the BASE, H is the height, and * means multiply. Step-by-step explanation:

21.

Find the area area of parallelogram

Answer»

Answer:

A = B * H where B is the BASE, H is the height, and * means multiply.

Step-by-step explanation:

Discussion

22.	998 covert to roman numeral
Answer» ANSWER: CMXCVIII ╔┓┏╦━━╦┓╔┓╔━━╗╔╗ ║┗┛║┗━╣┃║┃║╯╰║║║ ║┏┓║┏━╣┗╣┗╣╰╯║╠╣ ╚┛┗╩━━╩━╩━╩━━╝╚╝

22.

998 covert to roman numeral

Answer»

ANSWER:

CMXCVIII

╔┓┏╦━━╦┓╔┓╔━━╗╔╗

║┗┛║┗━╣┃║┃║╯╰║║║

║┏┓║┏━╣┗╣┗╣╰╯║╠╣

╚┛┗╩━━╩━╩━╩━━╝╚╝

Discussion

23.	Find the sum of successor of (-5) and predecessor of 1.we
Answer» Step-by-step explanation: SUCCESSOR of -5 is -4 and predecessor of 1 is 0

23.

Find the sum of successor of (-5) and predecessor of 1.we

Answer»

Step-by-step explanation:

SUCCESSOR of -5 is -4 and predecessor of 1 is 0

Discussion

24.	The sum of two angles is 90othen the angles are referred to as ________angles.(a)linear (b)adjacent (c)Complementary (d)Supplementary
Answer» ANSWER: (d) Supplementary is the answer... Step-by-step explanation: PLS MARK me BRAINLIEST

24.

The sum of two angles is 90othen the angles are referred to as ________angles.(a)linear (b)adjacent (c)Complementary (d)Supplementary

Answer»

ANSWER:

(d) Supplementary is the answer...

Step-by-step explanation:

PLS MARK me BRAINLIEST

Discussion

25.	2. Find the domain of *√X-5
Answer» ANSWER: DOMAIN is [5,INFINITY)

25.

2. Find the domain of *√X-5

Answer»

ANSWER:

DOMAIN is [5,INFINITY)

Discussion

26.	Commen difference 'd' of an AP is
Answer» ANSWER: d(COMMON DIFFERENCE) Step-by-step EXPLANATION: t2-t1=t3-t2

26.

Commen difference 'd' of an AP is

Answer»

ANSWER:

d(COMMON DIFFERENCE)

Step-by-step EXPLANATION:

t2-t1=t3-t2

Discussion

27.	In triangle , seg aB is perpendicular Bc, angle c= 45° ac = 8√2 find aB
Answer» AD = 8 and BC = 13 Step-by-step explanation: given AD is perpendicular to BC => ∠D = 90° now consider Δle ADC here ∠D is 90° and ∠C is 45° sum of angles equals to 180° so, ∠A = 45° when TWO angles are EQUAL it is a ISOSCELES TRIANGLE in which two sides are also equal so AD = DC hypotenuse theorem, AC² = DC² + AD² => (8√2)² = 2DC² => 128/2 = DC² => DC = 8 =AD so AD = 8 then BC = BD + DC => BC = 13

27.

In triangle , seg aB is perpendicular Bc, angle c= 45° ac = 8√2 find aB

Answer»

AD = 8 and BC = 13

Step-by-step explanation:

given AD is perpendicular to BC

=> ∠D = 90°

now consider Δle ADC

here ∠D is 90° and ∠C is 45°

sum of angles equals to 180° so, ∠A = 45°

when TWO angles are EQUAL it is a ISOSCELES TRIANGLE in which two sides are also equal

so AD = DC

hypotenuse theorem, AC² = DC² + AD²

=> (8√2)² = 2DC²

=> 128/2 = DC²

=> DC = 8 =AD

so AD = 8 then

BC = BD + DC

=> BC = 13

Discussion

28.	Tons Carry Equal Marks1224Find the rank of the matrix by reducing it to normal form263561022Prove that the
Answer» ANSWER: VALLA valla valla valla valla

28.

Tons Carry Equal Marks1224Find the rank of the matrix by reducing it to normal form263561022Prove that the

Answer»

ANSWER:

VALLA valla valla valla valla

Discussion

29.	12girls can finish a piece of work in 6days 8girls can do the same work in how many days math
Answer» ANSWER: 10 DAYS I THINK if correct PLS mark as brainliest answer

29.

12girls can finish a piece of work in 6days 8girls can do the same work in how many days math

Answer»

ANSWER:

10 DAYS I THINK

if correct PLS mark as brainliest answer

Discussion

30.	Write the discrimation of the equation 2x²-3x+5=o
Answer» X= 1 and 5/2 Step-by-step explanation: 2x²-5x+2x+5 = 0 x(2x-5)-1(2x-5) = 0 (x-1)(2x-5) = 0 x-1 = 0 and 2x-5=0 x=1 and x= 5/2

30.

Write the discrimation of the equation 2x²-3x+5=o

Answer»

X= 1 and 5/2

Step-by-step explanation:

2x²-5x+2x+5 = 0

x(2x-5)-1(2x-5) = 0

(x-1)(2x-5) = 0

x-1 = 0 and 2x-5=0

x=1 and x= 5/2

Discussion

31.	Find LCM by prime factorization method a) 14,20
Answer» Least COMMON multiple can be found by multiplying the highest exponent prime factors of 14 and 20. First we will CALCULATE the prime factors of 14 and 20. Prime Factorization of 14 2 14 7 7 1 Prime factors of 14 are 2,7. Prime factorization of 14 in exponential form is: 14 = 21×71 Prime Factorization of 20 2 20 2 10 5 5 1 Prime factors of 20 are 2,5. Prime factorization of 20 in exponential form is: 20 = 22×51 Now multiplying the highest exponent prime factors to calculate the LCM of 14 and 20. LCM(14,20) = 22×51×71 LCM(14,20) = 140

31.

Find LCM by prime factorization method a) 14,20

Answer»

Least COMMON multiple can be found by multiplying the highest exponent prime factors of 14 and 20. First we will CALCULATE the prime factors of 14 and 20.

Prime Factorization of 14

2 14

7 7

1

Prime factors of 14 are 2,7. Prime factorization of 14 in exponential form is:

14 = 21×71

Prime Factorization of 20

2 20

2 10

5 5

1

Prime factors of 20 are 2,5. Prime factorization of 20 in exponential form is:

20 = 22×51

Now multiplying the highest exponent prime factors to calculate the LCM of 14 and 20.

LCM(14,20) = 22×51×71

LCM(14,20) = 140

Discussion

32.	Simplify 2√45 -5√20+ √80
Answer» Answer: 0 Step-by-step EXPLANATION: √45 = 3√5 2√45 = 2 ( 3√5 ) 2√45 = 6√5 √20 = 2√5 5√20 = 5 ( 2√5 ) 5√20 = 10√5 √80 = 4√5 2√45 - 5√20 + √80 = 6√5 - 10√5 + 4√5 = 6√5 + 4√5 - 10√5 = 10√5 - 10√5 = 0

32.

Simplify 2√45 -5√20+ √80

Answer»

Answer:

0

Step-by-step EXPLANATION:

√45 = 3√5

2√45 = 2 ( 3√5 )

2√45 = 6√5

√20 = 2√5

5√20 = 5 ( 2√5 )

5√20 = 10√5

√80 = 4√5

2√45 - 5√20 + √80

= 6√5 - 10√5 + 4√5

= 6√5 + 4√5 - 10√5

= 10√5 - 10√5

= 0

Discussion

33.	In a rectangle ABCD, E is a point which bisects BC. Prove that AE = ED.
Answer» ANSWER: ↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑ ←Here is your answer DEAR..→ ↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓ ♦♦♦Mark my answer as BRAINLIEST answer♦♦♦ follow me plz✌️ saranghae ♥

33.

In a rectangle ABCD, E is a point which bisects BC. Prove that AE = ED.

Answer»

ANSWER:

↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑

←Here is your answer DEAR..→

↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓

♦♦♦Mark my answer as BRAINLIEST answer♦♦♦

follow me plz✌️

saranghae ♥

Discussion

34.	সরলরেখার উপর লম্ব অঙ্কন করাে।খ) স্কেল ও পেনসিল কম্পাসের সাহায্যে60° কোন একেঁ, ওই কোণের সমদ্বিখন্ডকঅংকন করাে।
Answer» ANSWER: hdidis jhsjdnd osge.nakdb KWBE kdhd sna.bbkdbs lajs lbe sld. LNA s d Step-by-step explanation: bdjxl. K ks.s.hd kn.bmbnngbj jghddbhf hdxd.hhdjjd.hd

34.

সরলরেখার উপর লম্ব অঙ্কন করাে।খ) স্কেল ও পেনসিল কম্পাসের সাহায্যে60° কোন একেঁ, ওই কোণের সমদ্বিখন্ডকঅংকন করাে।

Answer»

ANSWER:

hdidis jhsjdnd osge.nakdb KWBE kdhd sna.bbkdbs lajs lbe sld. LNA s d

Step-by-step explanation:

bdjxl. K ks.s.hd kn.bmbnngbj jghddbhf hdxd.hhdjjd.hd

Discussion

35.	What is 1+80000000000000000000
Answer» Answer: 80000000000000000001

35.

What is 1+80000000000000000000

Answer»

Answer:

80000000000000000001

Discussion

36.	A rectangular box is completely filled with dice. Each dice has a volume of 1 cm³. The length of the box is 3 cm greater than its width and its height is 5 cm. Suppose the box holds at most 140 dice. What are the possible dimensions of the box?
Answer» ANSWER: Dimensions, W+3, w, 5 Volume, 140 CUBIC centimeters 5w%28w%2B3%29=140 w%28w%2B3%29=28 Factors for 28 may be 1&28, 2&14, 4&7. The 4 & 7 factorization looks LIKE the right one. system%28w=4%2Cw%2B3=7%29 --------------------------- Width, 4 cm Length, 7 cm Height, 5 cm -------------------------- Step-by-step explanation:

36.

A rectangular box is completely filled with dice. Each dice has a volume of 1 cm³. The length of the box is 3 cm greater than its width and its height is 5 cm. Suppose the box holds at most 140 dice. What are the possible dimensions of the box?

Answer»

ANSWER:

Dimensions, W+3, w, 5

Volume, 140 CUBIC centimeters

5w%28w%2B3%29=140

w%28w%2B3%29=28

Factors for 28 may be 1&28, 2&14, 4&7.

The 4 & 7 factorization looks LIKE the right one.

system%28w=4%2Cw%2B3=7%29

---------------------------

Width, 4 cm

Length, 7 cm

Height, 5 cm

--------------------------

Step-by-step explanation:

Discussion

37.	Asap fast no spammingtwo dice are thrown simultaneously find the probability of getting the sum of two numbers on the dice is greater than 6 but less than 9
Answer» Sample space for total NUMBER of possible outcomes (1,1),(1,2),(1,3),(1,4),(1,5),(1,6), (2,1),(2,2),(2,3),(2,4),(2,5),(2,6), (3,1),(3,2),(3,3),(3,4),(3,5),(3,6), (4,1),(4,2),(4,3),(4,4),(4,5),(4,6), (5,1),(5,2),(5,3),(5,4),(5,5),(5,6), (6,1),(6,2),(6,3),(6,4),(6,5),(6,6) Total number of outcomes =36 (i) Favorable outcomes for sum as prime are (1,1),(1,2),(1,4),(1,6),(2,3),(2,3),(2,5),(3,2),(3,4),(4,1),(4,3),(5,2),(5,6),(6,1),(6,5) Number of favorable outcomes =15 Hence, the probability of getting the sum as a prime number. = 36 15 = 12 5 (ii) Favorable outcomes for total of atleast 10 are (4,6),(5,5),(5,6),(6,4),(6,5),(6,6) Number of favorable outcomes =6 Hence, the probability of getting a total of atleast 10 = 36 6 = 6 1 (iii) Favorable outcomes for a doublet of even number are (2,2),(4,4),(6,6) Number of favorable outcomes =3 Hence, the probability of getting a doublet of even number = 36 3 = 13 1 (IV) Favorable outcomes for a multiple of 2 on one dice and a multiple of 3 on the other dice are (2,3),(2,6),(3,2),(3,4),(3,6),(4,3),(4,6),(6,2),(6,3),(6,4),(6,6) Number of favorable outcomes =11 Hence, the probability of getting a multiple of 2 on one dice and a multiple of 3 on the other dice = 36 11 (v) Favorable outcomes for getting a multiple of 3 as the sum (1,2),(1,5),(2,1),(2,4),(3,3),(3,6),(4,2),(4,5),(5,1),(5,4),(6,3)(6,6) Number of favorable outcomes =12 Hence, the probability of getting a multiple of 3 as the sum = 36 12 = Sample space for total number of possible outcomes (1,1),(1,2),(1,3),(1,4),(1,5),(1,6), (2,1),(2,2),(2,3),(2,4),(2,5),(2,6), (3,1),(3,2),(3,3),(3,4),(3,5),(3,6), (4,1),(4,2),(4,3),(4,4),(4,5),(4,6), (5,1),(5,2),(5,3),(5,4),(5,5),(5,6), (6,1),(6,2),(6,3),(6,4),(6,5),(6,6) Total number of outcomes =36 (i) Favorable outcomes for sum as prime are (1,1),(1,2),(1,4),(1,6),(2,3),(2,3),(2,5),(3,2),(3,4),(4,1),(4,3),(5,2),(5,6),(6,1),(6,5) Number of favorable outcomes =15 Hence, the probability of getting the sum as a prime number. = 36 15 = 12 5 (ii) Favorable outcomes for total of atleast 10 are (4,6),(5,5),(5,6),(6,4),(6,5),(6,6) Number of favorable outcomes =6 Hence, the probability of getting a total of atleast 10 = 36 6 = 6 1 (iii) Favorable outcomes for a doublet of even number are (2,2),(4,4),(6,6) Number of favorable outcomes =3 Hence, the probability of getting a doublet of even number = 36 3 = 13 1 (iv) Favorable outcomes for a multiple of 2 on one dice and a multiple of 3 on the other dice are (2,3),(2,6),(3,2),(3,4),(3,6),(4,3),(4,6),(6,2),(6,3),(6,4),(6,6) Number of favorable outcomes =11 Hence, the probability of getting a multiple of 2 on one dice and a multiple of 3 on the other dice = 36 11 (v) Favorable outcomes for getting a multiple of 3 as the sum (1,2),(1,5),(2,1),(2,4),(3,3),(3,6),(4,2),(4,5),(5,1),(5,4),(6,3) = 36 12 = 3 1 mark me as genius

37.

Asap fast no spammingtwo dice are thrown simultaneously find the probability of getting the sum of two numbers on the dice is greater than 6 but less than 9

Answer»

Sample space for total NUMBER of possible outcomes

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

Total number of outcomes =36

(i)

Favorable outcomes for sum as prime are

(1,1),(1,2),(1,4),(1,6),(2,3),(2,3),(2,5),(3,2),(3,4),(4,1),(4,3),(5,2),(5,6),(6,1),(6,5)

Number of favorable outcomes =15

Hence, the probability of getting the sum as a prime number. =

36

15

=

12

5

(ii)

Favorable outcomes for total of atleast 10 are

(4,6),(5,5),(5,6),(6,4),(6,5),(6,6)

Number of favorable outcomes =6

Hence, the probability of getting a total of atleast 10 =

36

6

=

6

1

(iii)

Favorable outcomes for a doublet of even number are

(2,2),(4,4),(6,6)

Number of favorable outcomes =3

Hence, the probability of getting a doublet of even number =

36

3

=

13

1

(IV)

Favorable outcomes for a multiple of 2 on one dice and a multiple of 3 on the other dice are

(2,3),(2,6),(3,2),(3,4),(3,6),(4,3),(4,6),(6,2),(6,3),(6,4),(6,6)

Number of favorable outcomes =11

Hence, the probability of getting a multiple of 2 on one dice and a multiple of 3 on the other dice =

36

11

(v)

Favorable outcomes for getting a multiple of 3 as the sum

(1,2),(1,5),(2,1),(2,4),(3,3),(3,6),(4,2),(4,5),(5,1),(5,4),(6,3)(6,6)

Number of favorable outcomes =12

Hence, the probability of getting a multiple of 3 as the sum =

36

12

= Sample space for total number of possible outcomes

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

Total number of outcomes =36

(i)

Favorable outcomes for sum as prime are

(1,1),(1,2),(1,4),(1,6),(2,3),(2,3),(2,5),(3,2),(3,4),(4,1),(4,3),(5,2),(5,6),(6,1),(6,5)

Number of favorable outcomes =15

Hence, the probability of getting the sum as a prime number. =

36

15

=

12

5

(ii)

Favorable outcomes for total of atleast 10 are

(4,6),(5,5),(5,6),(6,4),(6,5),(6,6)

Number of favorable outcomes =6

Hence, the probability of getting a total of atleast 10 =

36

6

=

6

1

(iii)

Favorable outcomes for a doublet of even number are

(2,2),(4,4),(6,6)

Number of favorable outcomes =3

Hence, the probability of getting a doublet of even number =

36

3

=

13

1

(iv)

Favorable outcomes for a multiple of 2 on one dice and a multiple of 3 on the other dice are

(2,3),(2,6),(3,2),(3,4),(3,6),(4,3),(4,6),(6,2),(6,3),(6,4),(6,6)

Number of favorable outcomes =11

Hence, the probability of getting a multiple of 2 on one dice and a multiple of 3 on the other dice =

36

11

(v)

Favorable outcomes for getting a multiple of 3 as the sum

(1,2),(1,5),(2,1),(2,4),(3,3),(3,6),(4,2),(4,5),(5,1),(5,4),(6,3) =

36

12

=

3

1

mark me as genius

Discussion

38.	(4) Evaluate:(a). (2° + 3-1 ) X 32
Answer» ANSWER: =(1+3-1)×32 =(1+2)×32 =(3)×32 =3×32 =96

38.

(4) Evaluate:(a). (2° + 3-1 ) X 32

Answer»

ANSWER:

=(1+3-1)×32

=(1+2)×32

=(3)×32

=3×32

=96

Discussion

39.	Find the product of:fast and answer
Answer» Answer: 21/8a^2b^3c^3 Step-by-step EXPLANATION: MARK as BRAINIEST HOPE IT HELPS YOU!!!

39.

Find the product of:fast and answer

Answer»

Answer:

21/8a^2b^3c^3

Step-by-step EXPLANATION:

MARK as BRAINIEST

HOPE IT HELPS YOU!!!

Discussion

40.	The law of reflection states that when a ray of light reflects off a surface, theangle of incidence is equal to the angle of reflection.Ramesh placesa mirror on levelground to determine the height of a pole (with traffic light fired on it). He stands at acertain distance so that he can see the top of the pole reflected from the mirror.Ramesh’s eye level is 1.5 m above the ground. The distance of Ramesh and thepole from the mirror are 1.8 m and 6 m respectively.On the basis of the above information, answer any four of the followingquestions:(i) Which criterion of similarity is applicable to similar triangles?(a) SSA(b) ASA(c) SSS(d) AA(ii) What is the height of the pole?(a) 6 metres(b) 8 metres(c) 5 metres(d) 4 metres(iii) If angle of incidence is i , which of the following is correct relation?(a) tan i=5/6(b) tan i= 6/5(c) tan i= 3/5(d) tan i= 5/3(iv) Now Ramesh move behind such that distance between pole and Ramesh is13 meters. He places mirror between him and pole to see the reflection of lightin right position. What is the distance between mirror and Ramesh ?(a) 7 metres(b) 3 metres (c) 5 metres(d) 4 metres(v) What is the distance between mirror and pole?(a) 9 metres(b) 8 metres(c) 12 metres(d) 10 metre
Answer» Answer: (i) Which CRITERION of similarity is applicable to similar triangles? (d) AA (ii) What is the HEIGHT of the pole? (c) 5 METRES (iii) If angle of INCIDENCE is i , which of the following is CORRECT relation? (a) tan i=5/6

40.

The law of reflection states that when a ray of light reflects off a surface, theangle of incidence is equal to the angle of reflection.Ramesh placesa mirror on levelground to determine the height of a pole (with traffic light fired on it). He stands at acertain distance so that he can see the top of the pole reflected from the mirror.Ramesh’s eye level is 1.5 m above the ground. The distance of Ramesh and thepole from the mirror are 1.8 m and 6 m respectively.On the basis of the above information, answer any four of the followingquestions:(i) Which criterion of similarity is applicable to similar triangles?(a) SSA(b) ASA(c) SSS(d) AA(ii) What is the height of the pole?(a) 6 metres(b) 8 metres(c) 5 metres(d) 4 metres(iii) If angle of incidence is i , which of the following is correct relation?(a) tan i=5/6(b) tan i= 6/5(c) tan i= 3/5(d) tan i= 5/3(iv) Now Ramesh move behind such that distance between pole and Ramesh is13 meters. He places mirror between him and pole to see the reflection of lightin right position. What is the distance between mirror and Ramesh ?(a) 7 metres(b) 3 metres (c) 5 metres(d) 4 metres(v) What is the distance between mirror and pole?(a) 9 metres(b) 8 metres(c) 12 metres(d) 10 metre

Answer»

Answer:

(i) Which CRITERION of similarity is applicable to similar triangles?

(d) AA

(ii) What is the HEIGHT of the pole?

(c) 5 METRES

(iii) If angle of INCIDENCE is i , which of the following is CORRECT relation?

(a) tan i=5/6

Discussion

41.	Give possible expression for length, breadth and height of a cuboid whosevolume is 2ky^2 − 14ky + 20k.
Answer» Step-by-step EXPLANATION: $\sf \large \blue{ \star \: GIVEN}$ $\displaystyle \sf \: Volume \: of \: cubiod \: = 2k {y}^{2} - 14ky + 20$ $\sf \large \blue{\star TO \: FIND}$ $\sf \: Possible \: dimensions \: of \: cubiod$ $\sf \large \blue{ \star SOLUTION}$ $\displaystyle \sf \: Volume \: of \: cubiod \: = 2k {y}^{2} - 14ky + 20 \\ \sf common \: the \: \: same \: term \\ \sf \: = 2k( {y}^{2} - 7y + 10) \\ = \sf \: 2 \times k \times ( {y}^{2} - y7 + 10)$ $\sf \: volume \: of \: cubiod \: =( length) \times (breadth) \times (height) \\ \sf \: compare \: it \: \: with \: the \: volume \: given \: we \: get \\$ $\sf \: dimensions \: of \: cubiod \: is \: \\ \sf\: 2 \: and \: \: k \: \: and \: ( {y}^{2} - 7x + 10)$

41.

Give possible expression for length, breadth and height of a cuboid whosevolume is 2ky^2 − 14ky + 20k.

Answer»

Step-by-step EXPLANATION:

$\sf \large \blue{ \star \: GIVEN}$

$\displaystyle \sf \: Volume \: of \: cubiod \: = 2k {y}^{2} - 14ky + 20$

$\sf \large \blue{\star TO \: FIND}$

$\sf \: Possible \: dimensions \: of \: cubiod$

$\sf \large \blue{ \star SOLUTION}$

$\displaystyle \sf \: Volume \: of \: cubiod \: = 2k {y}^{2} - 14ky + 20 \\ \sf common \: the \: \: same \: term \\ \sf \: = 2k( {y}^{2} - 7y + 10) \\ = \sf \: 2 \times k \times ( {y}^{2} - y7 + 10)$

$\sf \: volume \: of \: cubiod \: =( length) \times (breadth) \times (height) \\ \sf \: compare \: it \: \: with \: the \: volume \: given \: we \: get \\$

$\sf \: dimensions \: of \: cubiod \: is \: \\ \sf\: 2 \: and \: \: k \: \: and \: ( {y}^{2} - 7x + 10)$

Discussion

42.	Three alarm clocks ring alarm at regular intervals of 25sec ,35sec and 45 sec, if they firstbeep together at 11.40 am., at what time will they beep again together?
Answer» ANSWER: LCM of 25sec ,35sec and 45 SEC = 1575 time will they BEEP again together = 11.40 am+ 1575 = 11.40 am+ 1575/60 HR calculate it to get the required ans..... i hope it helps

42.

Three alarm clocks ring alarm at regular intervals of 25sec ,35sec and 45 sec, if they firstbeep together at 11.40 am., at what time will they beep again together?

Answer»

ANSWER:

LCM of 25sec ,35sec and 45 SEC = 1575

time will they BEEP again together = 11.40 am+ 1575

= 11.40 am+ 1575/60 HR

calculate it to get the required ans.....

i hope it helps

Discussion

43.	What are the first common multuples of 4&8
Answer» Answer: 8..................................

43.

What are the first common multuples of 4&8

Answer»

Answer:

8..................................

Discussion

44.	மரங்களின் சிறப்புகளாக மு.மேத்தா கூறுவனவற்றை தொகுத்துரைக்க
Answer» ANSWER: SORRY I'm not UNDERSTANDING this LANGUAGE

44.

மரங்களின் சிறப்புகளாக மு.மேத்தா கூறுவனவற்றை தொகுத்துரைக்க

Answer»

ANSWER:

SORRY I'm not UNDERSTANDING this LANGUAGE

Discussion

45.	If a random variable x assumes the values 1,2,4,5,6 withprobabilities 0.15,0.25, 0.20,0.30, 0.10 respectively, then theP(X
Answer» Answer: What are the THREE STATES of WATER? How did they convert from ONE state to another 2 Step-by-step explanation:

45.

If a random variable x assumes the values 1,2,4,5,6 withprobabilities 0.15,0.25, 0.20,0.30, 0.10 respectively, then theP(X

Answer»

Answer:

What are the THREE STATES of WATER? How did they convert from ONE state to another

2

Step-by-step explanation:

Discussion

46.	Metallic spheres of radii 6cm, 8cm and 10cm respectively are melted to form a solid sphere.Find the radius of the resulting sphere.
Answer» ANSWER: here is ur answer SISO plz MARK me brainiest

46.

Metallic spheres of radii 6cm, 8cm and 10cm respectively are melted to form a solid sphere.Find the radius of the resulting sphere.

Answer»

ANSWER:

here is ur answer SISO plz MARK me brainiest

Discussion

47.	A parabola is the graph that results from p(x)=ax2+bx+c Parabolas are symmetric about a vertical line known as the Axis of Symmetry. The Axis of Symmetry runs through the maximum or minimum point of the parabola which is called the VERTEX Q1 If the high overpass is given by x2-2x-8. Then its zeroes are(A) (2,-4)(B) (-2,4)(C) (-2,-4)(D) (-4,-2)
Answer» Answer: 378₹! 843_66422589! _";?? _#&() /;:@%°=¢€√{

47.

A parabola is the graph that results from p(x)=ax2+bx+c Parabolas are symmetric about a vertical line known as the Axis of Symmetry. The Axis of Symmetry runs through the maximum or minimum point of the parabola which is called the VERTEX Q1 If the high overpass is given by x2-2x-8. Then its zeroes are(A) (2,-4)(B) (-2,4)(C) (-2,-4)(D) (-4,-2)

Answer»

Answer:

378₹! 843_66422589! _";?? _#*&() /;:*@%°=¢€√{

Discussion

48.	Numbers.2: Find the angle of depression from the top of 12 m high tower of an object lying at a point 12 maway from the base of the tower.
Answer» Answer: TAN 45DEGREE [email protected]=12/12 [email protected]=1 [email protected]=tan45degree @=45degree

48.

Numbers.2: Find the angle of depression from the top of 12 m high tower of an object lying at a point 12 maway from the base of the tower.

Answer»

Answer:

TAN 45DEGREE

[email protected]=12/12

[email protected]=1

[email protected]=tan45degree

@=45degree

Discussion

49.	Find a relation between x and y such that the point (x,y) is equidistant from the points (-2,6) and (3,5).
Answer» ∴PA=PB By using the distance formula = (x 2 −x 1 ) 2 +(y 2 −y 1 ) 2 we have ⇒ (x−3) 2 +(y−6) 2 = (x+3) 2 +(y−4) 2 ⇒(x−3) 2 +(y−6) 2 =(x+3) 2 +(y−4) 2 ⇒x 2 −6x+9+y 2 −12y+36=x 2 +6x+9+y 2 −8y+16 ⇒−6x−6x−12y+8y+36−16=0 ⇒−12x−4y+20=0 ⇒3x+y−5=0 Hence this is a RELATION between x and y.

49.

Find a relation between x and y such that the point (x,y) is equidistant from the points (-2,6) and (3,5).

Answer»

∴PA=PB

By using the distance formula

=

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

we have

⇒

(x−3)

2

+(y−6)

2

=

(x+3)

2

+(y−4)

2

⇒(x−3)

2

+(y−6)

2

=(x+3)

2

+(y−4)

2

⇒x

2

−6x+9+y

2

−12y+36=x

2

+6x+9+y

2

−8y+16

⇒−6x−6x−12y+8y+36−16=0

⇒−12x−4y+20=0

⇒3x+y−5=0

Hence this is a RELATION between x and y.

Discussion

50.	Sum of first 65 terms in an AP is 3300 find its 28 th term
Answer» Correct Question : The sum of first 55 terms in an AP is 3300 find its 28TH term Answer : 28th term = 60 Step-by-step explanation : Given, The sum of first 55 terms in an AP is 3300 In an AP, sum of n terms is given by $\boxed{\bf S_n=\frac{n}{2}[2a+(n-<klux>1</klux>)d]}$ where Sₙ - sum of n terms n - number of terms a - first term d - common difference Put Sₙ = 3300 and n = 55, $\sf 3300=\frac{65}{2} [2a+(55-1)d]$ 3300 × 2 = 55 [2a + 54d] 6600 = 55 [2a + 54d] 6600/55 = 2a + 54d 120 = 2a + 54d 120 = 2(a + 27D) 120/2 = a + 27d 60 = a + 27d We have to find the 28th term. i.e., a₂₈ = ? NTH term of an AP is given by, $\boxed{\bf a_n=a+(n-1)d}$ Put n = 28, a₂₈ = a + (28 - 1)d a₂₈ = a + 27d a₂₈ = 60 Therefore, 28th term is 60

50.

Sum of first 65 terms in an AP is 3300 find its 28 th term

Answer»

Correct Question :

The sum of first 55 terms in an AP is 3300 find its 28TH term

Answer :

28th term = 60

Step-by-step explanation :

Given,

The sum of first 55 terms in an AP is 3300

In an AP, sum of n terms is given by

$\boxed{\bf S_n=\frac{n}{2}[2a+(n-<klux>1</klux>)d]}$

where

Sₙ - sum of n terms

n - number of terms

a - first term

d - common difference

Put Sₙ = 3300 and n = 55,

$\sf 3300=\frac{65}{2} [2a+(55-1)d]$

3300 × 2 = 55 [2a + 54d]

6600 = 55 [2a + 54d]

6600/55 = 2a + 54d

120 = 2a + 54d

120 = 2(a + 27D)

120/2 = a + 27d

60 = a + 27d

We have to find the 28th term.

i.e., a₂₈ = ?

NTH term of an AP is given by,

$\boxed{\bf a_n=a+(n-1)d}$

Put n = 28,

a₂₈ = a + (28 - 1)d

a₂₈ = a + 27d

a₂₈ = 60

Therefore, 28th term is 60

Discussion

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மரங்களின் சிறப்புகளாக மு.மேத்தா கூறுவனவற்றை தொகுத்துரைக்க ​

If a random variable x assumes the values 1,2,4,5,6 withprobabilities 0.15,0.25, 0.20,0.30, 0.10 respectively, then theP(X

Metallic spheres of radii 6cm, 8cm and 10cm respectively are melted to form a solid sphere.Find the radius of the resulting sphere.​

Numbers.2: Find the angle of depression from the top of 12 m high tower of an object lying at a point 12 maway from the base of the tower.​

Find a relation between x and y such that the point (x,y) is equidistant from the points (-2,6) and (3,5).​

Sum of first 65 terms in an AP is 3300 find its 28 th term​

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-1 Write the decimal part in 30.65.

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.If Angle A=Angle P, AB=PQ and Angle B =Angle Q then triangle ABC and triangle PQR by which criteria

Plz tell this plz questionsfind 3 1/2 ÷ 1 2/3

A396543 169é 19604e square root by prime factorization.6276 676 k. 396 900116.6490.25*0.00090.0144

Point whose abscissa and ordinate are -2 and +3 lies in _______quadrant

Evalute the followingplease give me my answerI will mark as brainlesst answer

ip tp and tq are tangent drawm from con external point t with the circle centre o if tp=4cm,op=3cm,find ot

What is sunset......

Write the 435.023 in expanded from

Δ ABC and Δ DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC. If AD is extended to intersect BC at P, show that; i) Δ ABD ≅ Δ ACD ii) Δ ABP ≅ Δ ACP iii) AP is the perpendicular bisector of BC

Find the value of (2xy+5y)² by using the identity (a+b)²

AABCD ésand sidesquarCDA line BHBM entersecte diagonal AC at oif LA013 - TO then find LOMD

Simplify Tan ( pi/4+a) Tan(pi/4-a)

The sum of three consecutive odd number is 21. Find the middle number.A. 11B. 5C. 9 D. 7

In the figure AB = 12 cm BC = 7 cm CD = 8 cm, AD = 10 cm, find [3]i. The length of AE ii. The length of CFiii. The length of EF

Find the area area of parallelogram

998 covert to roman numeral

Find the sum of successor of (-5) and predecessor of 1.we

The sum of two angles is 90othen the angles are referred to as ________angles.(a)linear (b)adjacent (c)Complementary (d)Supplementary

2. Find the domain of *√X-5

Commen difference 'd' of an AP is

In triangle , seg aB is perpendicular Bc, angle c= 45° ac = 8√2 find aB

Tons Carry Equal Marks1224Find the rank of the matrix by reducing it to normal form263561022Prove that the

12girls can finish a piece of work in 6days 8girls can do the same work in how many days math

Write the discrimation of the equation 2x²-3x+5=o

Find LCM by prime factorization method a) 14,20

Simplify 2√45 -5√20+ √80

In a rectangle ABCD, E is a point which bisects BC. Prove that AE = ED.

সরলরেখার উপর লম্ব অঙ্কন করাে।খ) স্কেল ও পেনসিল কম্পাসের সাহায্যে60° কোন একেঁ, ওই কোণের সমদ্বিখন্ডকঅংকন করাে।

A rectangular box is completely filled with dice. Each dice has a volume of 1 cm³. The length of the box is 3 cm greater than its width and its height is 5 cm. Suppose the box holds at most 140 dice. What are the possible dimensions of the box?

Asap fast no spammingtwo dice are thrown simultaneously find the probability of getting the sum of two numbers on the dice is greater than 6 but less than 9

(4) Evaluate:(a). (2° + 3-1 ) X 32

Find the product of:fast and answer

Give possible expression for length, breadth and height of a cuboid whosevolume is 2ky^2 − 14ky + 20k.

Three alarm clocks ring alarm at regular intervals of 25sec ,35sec and 45 sec, if they firstbeep together at 11.40 am., at what time will they beep again together?

What are the first common multuples of 4&8

மரங்களின் சிறப்புகளாக மு.மேத்தா கூறுவனவற்றை தொகுத்துரைக்க

Metallic spheres of radii 6cm, 8cm and 10cm respectively are melted to form a solid sphere.Find the radius of the resulting sphere.

Numbers.2: Find the angle of depression from the top of 12 m high tower of an object lying at a point 12 maway from the base of the tower.

Find a relation between x and y such that the point (x,y) is equidistant from the points (-2,6) and (3,5).

Sum of first 65 terms in an AP is 3300 find its 28 th term